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  • MySQL escape string help

    - by gAMBOOKa
    I have a pretty large insert statement something like INSERT INTO multimedia (filename, regex, flag) VALUES (('adsfavr.jpg', '<div id="title">', 0), (...), (...)); How do I prepare the query for MySQL.It's too long to do it manually. It includes double quotes so I can't use the php function mysql_real_escape_string()

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  • Select random row from MySQL (with probability)

    - by James Simpson
    I have a MySQL table that has a row called cur_odds which is a percent number with the percent probability that that row will get selected. How do I make a query that will actually select the rows in approximately that frequency when you run through 100 queries for example? I tried the following, but a row that has a probability of 0.35 ends up getting selected around 60-70% of the time. SELECT * FROM table ORDER BY RAND()*cur_odds DESC

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  • Create a Cumulative Sum Column in MySQL

    - by Kirk
    I have a table that looks like this: id count 1 100 2 50 3 10 I want to add a new column called cumulative_sum, so the table would look like this: id count cumulative_sum 1 100 100 2 50 150 3 10 160 Is there a MySQL update statement that can do this easily? What's the best way to accomplish this?

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  • Advice on how to complete specific MySQL JOIN

    - by Tim
    Hello, I have a mysql table jobs. This is the basic structure of jobs. id booked_user_id assigned_user_id I then also have another table, meta. Meta has the structure: id user_id first_name last_name How can I join these tables so that both booked_user_id and assigned_user_id can access meta.first_name? Thanks for your advice Tim

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  • mysql query for getting all messages that belong to user's contacts

    - by aharon
    So I have a database that is setup sort of like this (simplified, and in terms of the tables, all are InnoDBs): Users: contains based user authentication information (uid, username, encrypted password, et cetera) Contacts: contains two rows per relationship that exists between users as (uid1, uid2), (uid2, uid1) to allow for a good 1:1 relationship (must be mutual) between users Messages: has messages that consist of a blob, owner-id, message-id (auto_increment) So my question is, what's the best MySQL query to get all messages that belong to all the contacts of a specific user? Is there an efficient way to do this?

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  • Optimize MYSQL Query with Order by

    - by Victor
    Hello, I have seen mysql queries with order by runs slow. Is there any specific way to optimize queries which use order by ? Queries without order by run very fast but with order by its always runs slow. if any one suggest any thing on this as general solutions. Thank You

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  • Saving commands for later re-use in MySQL?

    - by Zombies
    What would be the equivalant in MySQL for: Saving a command for later reuse. eg: alias command1='select count(*) from sometable;' Where then I simply type command 1 to get the count for SomeTable. Saving just a string, or rather part of a command. eg: select * from sometable where $complex_where_logic$ order by attr1 desc; WHere $complex_where_logic$ is something I wish to save and not have to keep writing out

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  • MySQL Workbench - How to synchronize the EER Diagram

    - by Tiago Alves
    I am creating a visual representation of my existing database with MySQL Workbench and I am able to synchronize the models with the "Database - Synchronize Model..." menu. However, every time I synchronize (update) my model, I have to recreate the EER Diagram and rearrange all the tables. Is there a way to update or synchronize the EER Diagram as well? Thanks.

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  • regenerate the ID row in a MySQL Table with a Mysql's Script or PHP

    - by DomingoSL
    Hello, i have a database fill with information of the users who use my webpage. The table as many MySql tables have the ID parameters who is autoincrement. The issue is that when somebody eliminate his account from the site, in the database remain a jump in the sequence that i dont want cuz i have a script who fail if find some jump in the ID. Ex. ID Name PASS 1 Jhon 1234 2 Max 2233 3 Jorge 2232 If Max get out and a new user go in, this is what will happend. ID Name PASS 1 Jhon 1234 4 NewU 1133 3 Jorge 2232 So what is the best way to erase some body from the data base in order to avoid this isuue, or if is not a way, its posible to do a PHP or MySql script who eliminate all the contents in the ID row and regenerate it in order? Thanks A lot! sorry for my english

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  • multi word query in mysql

    - by salmane
    Hi there , in order to make things easier for users i want to add multiple keyword search to my site. so that in the input the user would do something like : " keyword1 keyword 2" ( similar to google for example. would i need to write a code that would parse that string and do queries based on that or is there something built in mysql that could do it?

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  • MySQL foreign key creation with alter table command

    - by user313338
    I created some tables using MySQL Workbench, and then did forward ‘forward engineer’ to create scripts to create these tables. BUT, the scripts lead me to a number of problems. One of which involves the foreign keys. So I tried creating separate foreign key additions using alter table and I am still getting problems. The code is below (the set statements, drop/create statements I left in … though I don’t think they should matter for this): SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL'; DROP SCHEMA IF EXISTS `mydb` ; CREATE SCHEMA IF NOT EXISTS `mydb` DEFAULT CHARACTER SET latin1 COLLATE latin1_swedish_ci ; -- ----------------------------------------------------- -- Table `mydb`.`User` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User` ; CREATE TABLE IF NOT EXISTS `mydb`.`User` ( `UserName` VARCHAR(35) NOT NULL , `Num_Accts` INT NOT NULL , `Password` VARCHAR(45) NULL , `Email` VARCHAR(45) NULL , `User_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_ID`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `mydb`.`User_Space` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User_Space` ; CREATE TABLE IF NOT EXISTS `mydb`.`User_Space` ( `User_UserName` VARCHAR(35) NOT NULL , `User_Space_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_Space_ID`), FOREIGN KEY (`User_UserName`) REFERENCES `mydb`.`User` (`UserName`) ON UPDATE CASCADE ON DELETE CASCADE) ENGINE = InnoDB; SET SQL_MODE=@OLD_SQL_MODE; SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS; SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS; The error this produces is: Error Code: 1005 Can't create table 'mydb.user_space' (errno: 150) Anybody know what the heck I’m doing wrong?? And anybody else have problems with the script generation done by mysql workbench? It’s a nice tool, but annoying that it pumps out scripts that don’t work for me. [As an fyi here’s the script it auto-generates: SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL'; DROP SCHEMA IF EXISTS `mydb` ; CREATE SCHEMA IF NOT EXISTS `mydb` DEFAULT CHARACTER SET latin1 COLLATE latin1_swedish_ci ; -- ----------------------------------------------------- -- Table `mydb`.`User` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User` ; CREATE TABLE IF NOT EXISTS `mydb`.`User` ( `UserName` VARCHAR(35) NOT NULL , `Num_Accts` INT NOT NULL , `Password` VARCHAR(45) NULL , `Email` VARCHAR(45) NULL , `User_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_ID`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `mydb`.`User_Space` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User_Space` ; CREATE TABLE IF NOT EXISTS `mydb`.`User_Space` ( `User_Space_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_Space_ID`) , INDEX `User_ID` () , CONSTRAINT `User_ID` FOREIGN KEY () REFERENCES `mydb`.`User` () ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; SET SQL_MODE=@OLD_SQL_MODE; SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS; SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS; ** Thanks!]

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  • php MySQL snytax error

    - by Jacksta
    my scrip is supposed to look up contacts in a table and present thm on the screen to then be edited. however this is not this case. I am getting the error Parse error: syntax error, unexpected $end in /home/admin/domains/domain.com.au/public_html/pick_modcontact.php on line 50 NOTE: this is the last line in this script. <? session_start(); if ($_SESSION[valid] != "yes") { header( "Location: contact_menu.php"); exit; } $db_name = "testDB"; $table_name = "my_contacts"; $connection = @mysql_connect("localhost", "user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT id, f_name, l_name FROM $table_name ORDER BY f_name"; $result = @mysql_query($sql, $connection) or die(mysql_error()); $num = @mysql_num_rows($result); if ($num < 1) { $display_block = "<p><em>Sorry No Results!</em></p>"; } else { while ($row = mysql_fetch_array($result)) { $id = $row['id']; $f_name = $row['f_name']; $l_name = $row['l_name']; $option_block .= "<option value\"$id\">$l_name, $f_name</option>"; } $display_block = "<form method=\"POST\" action=\"show_modcontact.php\"> <p><strong>Contact:</strong> <select name=\"id\">$option_block</select> <input type=\"submit\" name=\"submit\" value=\"Select This Contact\"></p> </form>"; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Modify A Contact</title> </head> <body> <h1>My Contact Management System</h1> <h2><em>Modify a Contact</em></h2> <p>Select a contact from the list below, to modify the contact's record.</p> <? echo "$display_block"; ?> <br> <p><a href="contact_menu.php">Return to Main Menu</a></p> </body> </html>

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  • MySQL - Order results by relevancy, LEFT JOINS and more

    - by XaviEsteve
    Hi guys, I am trying to get some results ordered by total votes (where client votes count 2 points and other people votes are 1 point). tab_names: +-----------+ | Name | id | +------+----+ | John | 1 | | Paul | 2 | +------+----+ tab_votes: +--------+-----------+ | idname | ip | +--------+-----------+ | 2 | 127.0.0.1 | | 2 | 127.0.0.1 | | 2 | 82.23.5.1 | | 1 | 127.0.0.1 | +--------+-----------+ This is the MySQL query I've got but doesn't work: SELECT * COUNT(v.idname) AS totalvotes, (SELECT COUNT(v.ip) FROM tab_votes WHERE v.ip LIKE '$ip') AS uservotes FROM tab_names n LEFT JOIN tab_votes v ON n.id = v.idname GROUP BY n.name ORDER BY uservotes DESC, totalvotes DESC LIMIT 40

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  • How to create sql insert query dynamically in mysql

    - by nectar
    I am creating an application where I am generating pins dynamically based on user's input and storing them into mySql database. $sql = "INSERT INTO tblpin ('pinId', 'ownerId', 'usedby', 'status') VALUES for($i=0;$i<$npin;$i++) { ('$pin[$i]','$ownerid', 'Free', '1'); } ;"; how can I do that?

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  • MySQL - Using an alias in a subquery with WHERE clause

    - by gaoshan88
    I have a feeling I am completely borking this MySQL query but I'll ask anyway. I am wondering why I get the warning Unknown column 'FOO', and how I can get this query to work properly, in 'where clause' when I run the following: SELECT sample_id as FOO FROM tbl_test WHERE sample_id = 521 AND sample_id IN ( Select sample_id FROM tbl_test WHERE sample_id = FOO GROUP BY sample_id )

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  • Timeout error occurred trying to start MySQL Daemon. CentOS 5

    - by epema
    I ran into troubles with MySQL on my CentOS. I had some problems and backed up my database and removed mysql with all dependencies. After that I ran reinstalled: yum groupinstall "MySQL Database" Installed without errors. Running the mysql daemon: service mysqld start Timeout error occurred trying to start MySQL Daemon. Starting MySQL: [FAILED] I also ran # /usr/bin/mysql_install_db --user=mysql Installing MySQL system tables... 120112 1:49:44 [ERROR] Error message file '/usr/share/mysql/english/errmsg.sys' had only 480 error messages, but it should contain at least 481 error messages. Check that the above file is the right version for this program! 120112 1:49:44 [ERROR] Aborting Installation of system tables failed! Examine the logs in /var/lib/mysql for more information. You can try to start the mysqld daemon with: /usr/libexec/mysqld --skip-grant & and use the command line tool /usr/bin/mysql to connect to the mysql database and look at the grant tables: shell> /usr/bin/mysql -u root mysql mysql> show tables Try 'mysqld --help' if you have problems with paths. Using --log gives you a log in /var/lib/mysql that may be helpful. The latest information about MySQL is available on the web at http://www.mysql.com Please consult the MySQL manual section: 'Problems running mysql_install_db', and the manual section that describes problems on your OS. Another information source is the MySQL email archive. Please check all of the above before mailing us! And if you do mail us, you MUST use the /usr/bin/mysqlbug script! Checking the logs: less /var/log/mysqld.log Log file is empty. I don't even know how to debug it and not sure what to do. Any recommendations? Thank you

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  • mySQL - One large query vs Ajax indivdual queries

    - by Mark
    Hi guys, I guess no one will have a definative answer to this but considered predictions would be appriciated. I am in the process of developing a mySQL database for a web application and my question is: Is it more efficient to make a single query that returns a single row using AJAX or To request 100 - 700 rows when the user will likely only ever use the results of two or three? Really I am asking what is heavier for the server 2-3 requests with one result or 1 request with 100 - 700 results? Thanks, Mark

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  • Best way to check for NULL value in MySql query

    - by PHP-Prabhu
    Can any one please let me know the best way to use IF statement in mysql query to show if the "email" field is NULL then it should show as "no email"... Postcode Telephone Email ---------------------------------------------------------- BS20 0QN 1275373088 no email BS20 0QN 1275373088 no email PO9 4HG 023 92474208 [email protected] SO43 7DS 07801 715200 [email protected] ----------------------------------------------------------

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  • MySQL 5.1.41 leading zero is deleted

    - by iggnition
    Hello, I have a MySQL database where i want to store phonenumbers among other things. The fieldtype is INT(10) When I try to insert a number starting with a 0, like 0504042858 it's stored like 504042858. This only happens with zeros when the number start with any other number it's stored correctly. What am I doing wrong?

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  • Mysql timestamp query

    - by Hulk
    In mysql a result of a query is say select timestamp from newbie; | 2010-03-12 14:50:46 | | 2010-03-12 14:50:46 | | 2010-03-12 14:50:51 | | 2010-03-12 14:50:52 | | 2010-03-12 14:50:54 | | 2010-03-12 14:51:04 | | 2010-03-12 14:51:07 | | 2010-03-12 14:51:08 | Is there a way to subquery the above and sum up the i.e, the final result should be the delta of each row in hh:mm:ss format

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  • Search number entries on a mysql database with COUNT

    - by skiria
    I have a mysql database which allocate: iid, name, description, url, namecategory, idcategory, nametopic, idtopic How can i know the number of entries that has categoryid=1 and topicid=1? I've try $result = mysql_query("SELECT COUNT(id) FROM videos WHERE categoryid=1 AND topicid=1") But it hasn't worked!

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  • Error on SQL insert statement

    - by Ashley Stewart
    I exported a recordset from one database into a csv file, and when I try to import it into another using mysql workbench I keep this this error message: Executing SQL script in server ERROR: Error 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' 'Lord it Over', 'Ben', '1993-03-01', 'TRC', NULL, 1983, '1999-09-01', 'NULL', '' at line 1 INSERT INTO `TRC`.`horse` (`horse_id`, `registered_name`, `stable_name`, `arrival_date`, `last_known_location`, `is_ex_racer`, `birth_year`, `death_date`, `horse_comments`, `sex`, `referral_date`, `horse_height`, `arrival_weight`, `passport_no`, `microchip_no`, `is_on_waiting_list`) VALUES (, 'Lord it Over', 'Ben', '1993-03-01', 'TRC', NULL, 1983, '1999-09-01', 'NULL', 'NULL', 'NULL', NULL, NULL, 'NULL', 'NULL', 0) SQL script execution finished: statements: 29 succeeded, 1 failed Fetching back view definitions in final form. Nothing to fetch Any help would be appreciated as their appears to be no errors as far as I can see.

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