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  • mysql query for getting all messages that belong to user's contacts

    - by aharon
    So I have a database that is setup sort of like this (simplified, and in terms of the tables, all are InnoDBs): Users: contains based user authentication information (uid, username, encrypted password, et cetera) Contacts: contains two rows per relationship that exists between users as (uid1, uid2), (uid2, uid1) to allow for a good 1:1 relationship (must be mutual) between users Messages: has messages that consist of a blob, owner-id, message-id (auto_increment) So my question is, what's the best MySQL query to get all messages that belong to all the contacts of a specific user? Is there an efficient way to do this?

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  • MySQL Workbench - How to synchronize the EER Diagram

    - by Tiago Alves
    I am creating a visual representation of my existing database with MySQL Workbench and I am able to synchronize the models with the "Database - Synchronize Model..." menu. However, every time I synchronize (update) my model, I have to recreate the EER Diagram and rearrange all the tables. Is there a way to update or synchronize the EER Diagram as well? Thanks.

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  • Optimize MYSQL Query with Order by

    - by Victor
    Hello, I have seen mysql queries with order by runs slow. Is there any specific way to optimize queries which use order by ? Queries without order by run very fast but with order by its always runs slow. if any one suggest any thing on this as general solutions. Thank You

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  • Saving commands for later re-use in MySQL?

    - by Zombies
    What would be the equivalant in MySQL for: Saving a command for later reuse. eg: alias command1='select count(*) from sometable;' Where then I simply type command 1 to get the count for SomeTable. Saving just a string, or rather part of a command. eg: select * from sometable where $complex_where_logic$ order by attr1 desc; WHere $complex_where_logic$ is something I wish to save and not have to keep writing out

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  • regenerate the ID row in a MySQL Table with a Mysql's Script or PHP

    - by DomingoSL
    Hello, i have a database fill with information of the users who use my webpage. The table as many MySql tables have the ID parameters who is autoincrement. The issue is that when somebody eliminate his account from the site, in the database remain a jump in the sequence that i dont want cuz i have a script who fail if find some jump in the ID. Ex. ID Name PASS 1 Jhon 1234 2 Max 2233 3 Jorge 2232 If Max get out and a new user go in, this is what will happend. ID Name PASS 1 Jhon 1234 4 NewU 1133 3 Jorge 2232 So what is the best way to erase some body from the data base in order to avoid this isuue, or if is not a way, its posible to do a PHP or MySql script who eliminate all the contents in the ID row and regenerate it in order? Thanks A lot! sorry for my english

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  • multi word query in mysql

    - by salmane
    Hi there , in order to make things easier for users i want to add multiple keyword search to my site. so that in the input the user would do something like : " keyword1 keyword 2" ( similar to google for example. would i need to write a code that would parse that string and do queries based on that or is there something built in mysql that could do it?

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  • php MySQL snytax error

    - by Jacksta
    my scrip is supposed to look up contacts in a table and present thm on the screen to then be edited. however this is not this case. I am getting the error Parse error: syntax error, unexpected $end in /home/admin/domains/domain.com.au/public_html/pick_modcontact.php on line 50 NOTE: this is the last line in this script. <? session_start(); if ($_SESSION[valid] != "yes") { header( "Location: contact_menu.php"); exit; } $db_name = "testDB"; $table_name = "my_contacts"; $connection = @mysql_connect("localhost", "user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT id, f_name, l_name FROM $table_name ORDER BY f_name"; $result = @mysql_query($sql, $connection) or die(mysql_error()); $num = @mysql_num_rows($result); if ($num < 1) { $display_block = "<p><em>Sorry No Results!</em></p>"; } else { while ($row = mysql_fetch_array($result)) { $id = $row['id']; $f_name = $row['f_name']; $l_name = $row['l_name']; $option_block .= "<option value\"$id\">$l_name, $f_name</option>"; } $display_block = "<form method=\"POST\" action=\"show_modcontact.php\"> <p><strong>Contact:</strong> <select name=\"id\">$option_block</select> <input type=\"submit\" name=\"submit\" value=\"Select This Contact\"></p> </form>"; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Modify A Contact</title> </head> <body> <h1>My Contact Management System</h1> <h2><em>Modify a Contact</em></h2> <p>Select a contact from the list below, to modify the contact's record.</p> <? echo "$display_block"; ?> <br> <p><a href="contact_menu.php">Return to Main Menu</a></p> </body> </html>

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  • MySQL foreign key creation with alter table command

    - by user313338
    I created some tables using MySQL Workbench, and then did forward ‘forward engineer’ to create scripts to create these tables. BUT, the scripts lead me to a number of problems. One of which involves the foreign keys. So I tried creating separate foreign key additions using alter table and I am still getting problems. The code is below (the set statements, drop/create statements I left in … though I don’t think they should matter for this): SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL'; DROP SCHEMA IF EXISTS `mydb` ; CREATE SCHEMA IF NOT EXISTS `mydb` DEFAULT CHARACTER SET latin1 COLLATE latin1_swedish_ci ; -- ----------------------------------------------------- -- Table `mydb`.`User` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User` ; CREATE TABLE IF NOT EXISTS `mydb`.`User` ( `UserName` VARCHAR(35) NOT NULL , `Num_Accts` INT NOT NULL , `Password` VARCHAR(45) NULL , `Email` VARCHAR(45) NULL , `User_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_ID`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `mydb`.`User_Space` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User_Space` ; CREATE TABLE IF NOT EXISTS `mydb`.`User_Space` ( `User_UserName` VARCHAR(35) NOT NULL , `User_Space_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_Space_ID`), FOREIGN KEY (`User_UserName`) REFERENCES `mydb`.`User` (`UserName`) ON UPDATE CASCADE ON DELETE CASCADE) ENGINE = InnoDB; SET SQL_MODE=@OLD_SQL_MODE; SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS; SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS; The error this produces is: Error Code: 1005 Can't create table 'mydb.user_space' (errno: 150) Anybody know what the heck I’m doing wrong?? And anybody else have problems with the script generation done by mysql workbench? It’s a nice tool, but annoying that it pumps out scripts that don’t work for me. [As an fyi here’s the script it auto-generates: SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL'; DROP SCHEMA IF EXISTS `mydb` ; CREATE SCHEMA IF NOT EXISTS `mydb` DEFAULT CHARACTER SET latin1 COLLATE latin1_swedish_ci ; -- ----------------------------------------------------- -- Table `mydb`.`User` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User` ; CREATE TABLE IF NOT EXISTS `mydb`.`User` ( `UserName` VARCHAR(35) NOT NULL , `Num_Accts` INT NOT NULL , `Password` VARCHAR(45) NULL , `Email` VARCHAR(45) NULL , `User_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_ID`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `mydb`.`User_Space` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User_Space` ; CREATE TABLE IF NOT EXISTS `mydb`.`User_Space` ( `User_Space_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_Space_ID`) , INDEX `User_ID` () , CONSTRAINT `User_ID` FOREIGN KEY () REFERENCES `mydb`.`User` () ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; SET SQL_MODE=@OLD_SQL_MODE; SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS; SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS; ** Thanks!]

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  • How to create sql insert query dynamically in mysql

    - by nectar
    I am creating an application where I am generating pins dynamically based on user's input and storing them into mySql database. $sql = "INSERT INTO tblpin ('pinId', 'ownerId', 'usedby', 'status') VALUES for($i=0;$i<$npin;$i++) { ('$pin[$i]','$ownerid', 'Free', '1'); } ;"; how can I do that?

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  • MySQL - Order results by relevancy, LEFT JOINS and more

    - by XaviEsteve
    Hi guys, I am trying to get some results ordered by total votes (where client votes count 2 points and other people votes are 1 point). tab_names: +-----------+ | Name | id | +------+----+ | John | 1 | | Paul | 2 | +------+----+ tab_votes: +--------+-----------+ | idname | ip | +--------+-----------+ | 2 | 127.0.0.1 | | 2 | 127.0.0.1 | | 2 | 82.23.5.1 | | 1 | 127.0.0.1 | +--------+-----------+ This is the MySQL query I've got but doesn't work: SELECT * COUNT(v.idname) AS totalvotes, (SELECT COUNT(v.ip) FROM tab_votes WHERE v.ip LIKE '$ip') AS uservotes FROM tab_names n LEFT JOIN tab_votes v ON n.id = v.idname GROUP BY n.name ORDER BY uservotes DESC, totalvotes DESC LIMIT 40

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  • MySQL - Using an alias in a subquery with WHERE clause

    - by gaoshan88
    I have a feeling I am completely borking this MySQL query but I'll ask anyway. I am wondering why I get the warning Unknown column 'FOO', and how I can get this query to work properly, in 'where clause' when I run the following: SELECT sample_id as FOO FROM tbl_test WHERE sample_id = 521 AND sample_id IN ( Select sample_id FROM tbl_test WHERE sample_id = FOO GROUP BY sample_id )

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  • mySQL - One large query vs Ajax indivdual queries

    - by Mark
    Hi guys, I guess no one will have a definative answer to this but considered predictions would be appriciated. I am in the process of developing a mySQL database for a web application and my question is: Is it more efficient to make a single query that returns a single row using AJAX or To request 100 - 700 rows when the user will likely only ever use the results of two or three? Really I am asking what is heavier for the server 2-3 requests with one result or 1 request with 100 - 700 results? Thanks, Mark

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  • Timeout error occurred trying to start MySQL Daemon. CentOS 5

    - by epema
    I ran into troubles with MySQL on my CentOS. I had some problems and backed up my database and removed mysql with all dependencies. After that I ran reinstalled: yum groupinstall "MySQL Database" Installed without errors. Running the mysql daemon: service mysqld start Timeout error occurred trying to start MySQL Daemon. Starting MySQL: [FAILED] I also ran # /usr/bin/mysql_install_db --user=mysql Installing MySQL system tables... 120112 1:49:44 [ERROR] Error message file '/usr/share/mysql/english/errmsg.sys' had only 480 error messages, but it should contain at least 481 error messages. Check that the above file is the right version for this program! 120112 1:49:44 [ERROR] Aborting Installation of system tables failed! Examine the logs in /var/lib/mysql for more information. You can try to start the mysqld daemon with: /usr/libexec/mysqld --skip-grant & and use the command line tool /usr/bin/mysql to connect to the mysql database and look at the grant tables: shell> /usr/bin/mysql -u root mysql mysql> show tables Try 'mysqld --help' if you have problems with paths. Using --log gives you a log in /var/lib/mysql that may be helpful. The latest information about MySQL is available on the web at http://www.mysql.com Please consult the MySQL manual section: 'Problems running mysql_install_db', and the manual section that describes problems on your OS. Another information source is the MySQL email archive. Please check all of the above before mailing us! And if you do mail us, you MUST use the /usr/bin/mysqlbug script! Checking the logs: less /var/log/mysqld.log Log file is empty. I don't even know how to debug it and not sure what to do. Any recommendations? Thank you

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  • Best way to check for NULL value in MySql query

    - by PHP-Prabhu
    Can any one please let me know the best way to use IF statement in mysql query to show if the "email" field is NULL then it should show as "no email"... Postcode Telephone Email ---------------------------------------------------------- BS20 0QN 1275373088 no email BS20 0QN 1275373088 no email PO9 4HG 023 92474208 [email protected] SO43 7DS 07801 715200 [email protected] ----------------------------------------------------------

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  • MySQL 5.1.41 leading zero is deleted

    - by iggnition
    Hello, I have a MySQL database where i want to store phonenumbers among other things. The fieldtype is INT(10) When I try to insert a number starting with a 0, like 0504042858 it's stored like 504042858. This only happens with zeros when the number start with any other number it's stored correctly. What am I doing wrong?

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  • Mysql timestamp query

    - by Hulk
    In mysql a result of a query is say select timestamp from newbie; | 2010-03-12 14:50:46 | | 2010-03-12 14:50:46 | | 2010-03-12 14:50:51 | | 2010-03-12 14:50:52 | | 2010-03-12 14:50:54 | | 2010-03-12 14:51:04 | | 2010-03-12 14:51:07 | | 2010-03-12 14:51:08 | Is there a way to subquery the above and sum up the i.e, the final result should be the delta of each row in hh:mm:ss format

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  • Search number entries on a mysql database with COUNT

    - by skiria
    I have a mysql database which allocate: iid, name, description, url, namecategory, idcategory, nametopic, idtopic How can i know the number of entries that has categoryid=1 and topicid=1? I've try $result = mysql_query("SELECT COUNT(id) FROM videos WHERE categoryid=1 AND topicid=1") But it hasn't worked!

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  • Error on SQL insert statement

    - by Ashley Stewart
    I exported a recordset from one database into a csv file, and when I try to import it into another using mysql workbench I keep this this error message: Executing SQL script in server ERROR: Error 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' 'Lord it Over', 'Ben', '1993-03-01', 'TRC', NULL, 1983, '1999-09-01', 'NULL', '' at line 1 INSERT INTO `TRC`.`horse` (`horse_id`, `registered_name`, `stable_name`, `arrival_date`, `last_known_location`, `is_ex_racer`, `birth_year`, `death_date`, `horse_comments`, `sex`, `referral_date`, `horse_height`, `arrival_weight`, `passport_no`, `microchip_no`, `is_on_waiting_list`) VALUES (, 'Lord it Over', 'Ben', '1993-03-01', 'TRC', NULL, 1983, '1999-09-01', 'NULL', 'NULL', 'NULL', NULL, NULL, 'NULL', 'NULL', 0) SQL script execution finished: statements: 29 succeeded, 1 failed Fetching back view definitions in final form. Nothing to fetch Any help would be appreciated as their appears to be no errors as far as I can see.

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  • MySQL: Check if first character is _not_ A-Z

    - by dbemerlin
    I have to create an SQL Query to get all rows starting with a specific character, except if the parameter passed to the (PHP) function is 0, in that case it should get every row that does not start with A - Z (like #0-9.,$ etc). What is the easiest and fastest way to get those rows? DB: MySQL 5.1 Column: title

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  • mySQL query: How to insert with UNION?

    - by Industrial
    Hi everybody, I am kind of new to mySQL:s union functions, at least when doing inserts with them. I have gotten the following to work based upon a example found on the net: INSERT INTO tableOne(a, b) SELECT a, $var FROM tableOne WHERE b = $var2 UNION ALL SELECT $var,$var Ok, nothing strange about that. But what happens when I want to insert a third value into the database that has nothing to do with the logic of the Select being done? Like : INSERT INTO tableOne(a, b, c ) How could that be done?

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  • A SELECT statement for Mysql

    - by Hossein
    I have this table: id,bookmarkID,tagID I want to fetch the top N bookmarkIDs for a given list of tags. Does anyone know a very fast solution for this? the table is quite large(12 million records) I am using MySql

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