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• Want to show file association icon and skype like progress bar c#

  - by Thomas

  whenever user drag any file onto skype chat textbox then skype show right icon for that file and one custom progress bar rounded corner. i have 4 questions 1) i am working with win application not WPF. i like to know how to develop skype like corner progressbar. i search lot google to find out skype like progressbar. so if anyone knows how to develop that kind of progress bar then please share that knowledge or give me any url from where i can download similar look progressbar. 2) when i drag any file onto my richtextbox then how could i show right icon for that file on my richtextbox. anyone can give me idea. 3) what kind of richtextbox skype use? is there any advance richtextbox library which i can use for showing picture or button etc. 4) skype shows button on chat textbox called Cancel......is it button or any image. when user click on that button then button respond accordingly. so just tell me how could place any button on my rich textbox and when i will click on that button then a event should fire at my end. any idea. here i attach a picture from where you can see the image of progressbar that i am looking for. how i want to show the progress button and file associated icon on richtextbox. the object behind attaching the image is other person can understand what is my requirement and what i want to know. please anyone give me the idea for my above 4 points. thanks

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• Show last 4 table entries mysql php

  - by user272899

  I have a movie database Kind of like a blog and I want to display the last 4 created entries. I have a column in my table for timestamp called 'dateadded'. Using this code how would I only display the 4 most recent entries to table <?php //connect to database mysql_connect($mysql_hostname,$mysql_user,$mysql_password); @mysql_select_db($mysql_database) or die("<b>Unable to connect to specified database</b>"); //query databae $query = "SELECT * FROM movielist"; $result=mysql_query($query) or die('Error, insert query failed'); $row=0; $numrows=mysql_num_rows($result); while($row<$numrows) { $id=mysql_result($result,$row,"id"); $imgurl=mysql_result($result,$row,"imgurl"); $imdburl=mysql_result($result,$row,"imdburl"); ?> <div class="moviebox rounded"><a href="http://<?php echo $domain; ?>/viewmovie?movieid=<?php echo $id; ?>" rel="facebox"> <img src="<?php echo $imgurl; ?>" /> <form method="get" action=""> <input type="text" name="link" class="link" style="display:none" value="http://us.imdb.com/Title?<?php echo $imdburl; ?>"/> </form> </a></div> <?php $row++; } ?>

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• jQuery slideDown: Parent element doesn't expand?

  - by bobsoap

  Hi, This issue occurs in our beloved Internet Explorer 7: I have a list of items, each with a hidden child div. When user clicks the "expand" button in any list item, the hidden div will expand downwards and push all content beneith it lower. This works just as it should in FF, Chrome, IE8 - but IE7 will not expand the parent element along with its children. This is noticeable because the top-most parent container has an absolutely positioned image at the very bottom (yea... rounded corners) - that doesn't get pushed down when the content expands. I'm guessing that's because of the absolute positioning... Just wondering whether I should attempt to code up some huge workaround in jQuery just for that (assuming I'm able to), or if this is a known issue of some sort. My HTML: <div id="container"> <ul> <li>Click here to expand <div class="hide"></div> </li> <li>Click here to expand <div class="hide"></div> </li> <li>Click here to expand <div class="hide"></div> </li> </ul> <div id="containerbottom"></div> </div> The CSS: #container { position:relative; } #container #containerbottom { position:absolute; bottom:0px; left:0px; } The jQuery is pretty much your everyday slide function: $('ul li').click(function() { $(this).children('.hide').slideDown(200); }); Any ideas?

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• Raphael SVG VML Implement Multi Pivot Points for Rotation

  - by Cody N

  Over the last two days I've effectively figured out how NOT to rotate Raphael Elements. Basically I am trying to implement a multiple pivot points on element to rotate it by mouse. When a user enters rotation mode 5 pivots are created. One for each corner of the bounding box and one in the center of the box. When the mouse is down and moving it is simple enough to rotate around the pivot using Raphael elements.rotate(degrees, x, y) and calculating the degrees based on the mouse positions and atan2 to the pivot point. The problem arises after I've rotated the element, bbox, and the other pivots. There x,y position in the same only there viewport is different. In an SVG enabled browser I can create new pivot points based on matrixTransformation and getCTM. However after creating the first set of new pivots, every rotation after the pivots get further away from the transformed bbox due to rounding errors. The above is not even an option in IE since in is VML based and cannot account for transformation. Is the only effective way to implement element rotation is by using rotate absolute or rotating around the center of the bounding box? Is it possible at all the create multi pivot points for an object and update them after mouseup to remain in the corners and center of the transformed bbox?

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• Custom back button click event on pushed view controller

  - by TechFusion

  Hello, I have pushed view controller and load WebView and Custom rectangular rounded button on right down left corner into view using programmatic way. -(void)loadView { CGRect frame = CGRectMake(0.0, 0.0, 480, 320); WebView = [[[UIWebView alloc] initWithFrame:frame] autorelease]; WebView.backgroundColor = [UIColor whiteColor]; WebView.scalesPageToFit = YES; WebView.autoresizingMask = (UIViewAutoresizingFlexibleWidth | UIViewAutoresizingFlexibleHeight | UIViewAutoresizingFlexibleLeftMargin | UIViewAutoresizingFlexibleTopMargin); WebView.autoresizesSubviews = YES; WebView.exclusiveTouch = YES; WebView.clearsContextBeforeDrawing = YES; self.roundedButtonType = [[UIButton buttonWithType:UIButtonTypeRoundedRect] retain]; self.roundedButtonType.frame = CGRectMake(416.0, 270.0, 44, 19); [self.roundedButtonType setTitle:@"Back" forState:UIControlStateNormal]; self.roundedButtonType.backgroundColor = [UIColor grayColor]; [self.roundedButtonType addTarget:self action:@selector(back:) forControlEvents:UIControlEventTouchUpInside]; self.view = WebView; [self.view addSubview: self.roundedButtonType ]; [WebView release]; } This is action that I have added as back button of navigation. -(void)back:(id)sender{ [self.navigationController popViewControllerAnimated:YES]; } -(void)viewDidUnload{ self.WebView = nil; self.roundedButtonType = nil; } -(void)dealloc{ [roundedButtonType release]; [super dealloc]; } Here, When Back button click then it is showing previous view but application got stuck in that view and GDB shows Program received signal :EXC_BAD_ACCESS message. how resolve this issue? Thanks,

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• How can I apply a style to existing tikz node on specific slides

  - by Eugene Pimenov

  This is what I'm trying to do \begin{tikzpicture} [node distance = 1cm, auto,font=\footnotesize, % STYLES every node/.style={node distance=1.3cm}, comment/.style={rectangle, inner sep= 5pt, text width=4cm, node distance=0.25cm, font=}, module/.style={rectangle, drop shadow, draw, fill=black!10, inner sep=5pt, text width=3cm, text badly centered, minimum height=0.8cm, font=\bfseries\footnotesize\sffamily,rounded corners}, selected/.style={fill=red!40}] \node [module] (nodeA) {node A}; \node [module, below of=nodeA] (nodeA) {node B}; \only<1>{ \node [comment, text width=6cm, right=0.25 of nodeA] {short description of Node A}; \node [comment, text width=6cm, right=0.25 of nodeB] {short description of Node B}; } \only<2>{ \node [selected] (nodeA) {}; \node [comment, text width=6cm, right=0.25 of nodeA] {long description of node A}; } \only<3>{ \node [selected] (nodeB) {}; \node [comment, text width=6cm, right=0.25 of nodeA] {long description of node B}; } \end{tikzpicture} The problem is \node [selected] (nodeB) {}; creates a new node, but I want it to apply the style for the existing node. Is there any way to do so? Of course I could have copies of every node in selected state and not-selected state, but I really want to have a normal solution.

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• The best way to implement drawing features like Keynote

  - by Shamseddine

  Hi all, I'm trying to make a little iPad tool's for drawing simple geometrical objects (rect, rounded rect, ellipse, star, ...). My goal is to make something very close to Keynote (drawing feature), i.e. let the user add a rect (for instance), resizing it and moving it. I want too the user can select many objects and move them together. I've thought about at least 3 differents ways to do that : Extends UIView for each object type, a class for Rect, another for Ellipse, ... With custom drawing method. Then add this view as subview of the global view. Extends CALayer for each object type, a class for Rect, another for Ellipse, ... With custom drawing method. Then add this layer as sublayer of the global view layer's. Extends NSObject for each object type, a class for Rect, another for Ellipse, ... With just a drawing method which will get as argument a CGContext and a Rect and draw directly the form in it. Those methods will be called by the drawing method of the global view. I'm aware that the two first ways come with functions to detect touch on each object, to add easily shadows,... but I'm afraid that they are a little too heavy ? That's why I thought about the last way, which it seems to be straight forward. Which way will be the more efficient ??? Or maybe I didn't thought another way ? Any help will be appreciated ;-) Thanks.

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• Question regarding ip checksum code

  - by looktt

  unsigned short /* this function generates header checksums */ csum (unsigned short *buf, int nwords) { unsigned long sum; for (sum = 0; nwords > 0; nwords--) // add words(16bits) together sum += *buf++; sum = (sum >> 16) + (sum & 0xffff); //add carry over sum += (sum >> 16); //what does this step do??? add possible left-over //byte? But isn't it already added in the loop (if //any)? return ((unsigned short) ~sum); } I assume nwords in the number of 16bits word, not 8bits byte (if there are odd byte, nword is rounded to next large), is it correct? The line sum = (sum 16) + (sum & 0xffff) is to add carry over to make 16bit complement sum += (sum 16); What's the purpose of this step? Add left-over byte? How? Thanks!

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• Does android maps support ground overlay?

  - by wmh1108

  I have a weather image I would like to use as an overlay in the google maps android api. I would like to achieve the same result that I get from using GroundOverlay in KML files, such as <GroundOverlay> <name>myimage</name> <Icon> <href>myimage.png</href> <viewBoundScale>0.75</viewBoundScale> </Icon> <LatLonBox> <north>75.6088</north> <south>5.0121</south> <east>182.2805</east> <west>120.6795</west> </LatLonBox> </GroundOverlay> The above will ensure that the 4 corners of my image stay anchored to the 4 lat/long points listed, regardless of scrolling, zooming etc.. Is there a way to accomplish this using the google api/maps provided for android?

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• Simulating 3D 'cards' with just orthographic rendering

  - by meds

  I am rendering textured quads from an orthographic perspective and would like to simulate 'depth' by modifying UVs and the vertex positions of the quads four points (top left, top right, bottom left, bottom right). I've found if I make the top left and bottom right corners y position be the same I don't get a linear 'skew' but rather a warped one where the texture covering the top triangle (which makes up the quad) seems to get squashed while the bottom triangles texture looks normal. I can change UVs, any of the four points on the quad (but only in 2D space, it's orthographic projection anyway so 3D space won't matter much). So basically I'm trying to simulate perspective on a two dimensional quad in orthographic projection, any ideas? Is it even mathematically possible/feasible? ideally what I'd like is a situation where I can set an x/y rotation as well as a virtual z 'position' (which simulates z depth) through a function and see it internally calclate the positions/uvs to create the 3D effect. It seems like this should all be mathematical where a set of 2D transforms can be applied to each corner of the quad to simulate depth, I just don't know how to make it happen. I'd guess it requires trigonometry or something, I'm trying to crunch the math but not making much progress. here's what I mean: Top left is just the card, center is the card with a y rotation of X degrees and right most is a card with an x and y rotation of different degrees.

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• "Outward" border-radius in css?

  - by MaxMackie

  Currently, the links at the top of my website look like this: However, I am trying to "round" the bottom edges of the buttons to make it look like they are coming out of the page and into the ribbon at the top. I am aware that you can hack it and add a "separator" div with rounded corners between each entry, but this would be difficult to do seeing at the borders used are not all from the same div. Also, it wouldn't be easy seeing as my buttons are very close to each other. The css for the "button": .button { border-top: 3px solid #A1C1BE; border-left: 3px solid #A1C1BE; border-right: 3px solid #A1C1BE; border-bottom: 0px; padding: 5px 8px 5px 8px; margin: 0 0 -9px 0; border-radius: 5px 5px 0 0; font-size: 12px; font-family: 'PT Sans', sans-serif; background-color: #f8f8ff; color: #484848; } css for the "ribbon": #top-wrapper { border-bottom: 5px solid #A1C1BE; width: 100%; background-color: #59554E; padding: 10px 0 0 0; color: #C0C0A8; } As you can see, the thicker border belongs to the ribbon which stretches the length of the webpage, whereas the thinner blue border is part of the button.

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• [jQuery 1.4] move one div over another

  - by Tomasz Zielinski

  I have two div elements that are twins (i.e. their dimensions and contents are identical). I want to move of those div-s over another, so that their corners are at exactly the same coordinates. What I try to do is: var offset = $('div#placeholder').offset(); $('div#overlay').css('position', 'absolute').css('left', offset.left + 'px').css('top', offset.top + 'px') -- but this causes the overlay to be exactly (or almost exactly, taking subpixel accuracy into account) 16px below the placeholder (below, i.e. overlay_top = placeholder_top + 16px). I'm aware that offset() gives position relative to the document, and position: absolute sets position relative to body element, but compensating for body offset() doesn't help much (I'm getting 8px offset, equal to margins): offset.top -= $('body').offset().top; offset.left -= $('body').offset().left; Also, compensating for body margins (in case they were different that offset() didn't help, as they were set to 8px). Does somebody know what I'm doing wrong here? UPDATE: Take a look at here - I'm getting the same result in FireFox 3.6.3 and Opera 10.10.

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• What do you do when your boss doesn't care about code quality?

  - by Chad Johnson

  My boss (a proprietor) is a developer like me. He comes, however, from a C background and severely lacks knowledge of the benefits of proper object-oriented design. That, or he simply ignores them. So my co-worker developed this feature prototype in a week, and it's not release-ready--at least not from a good code standpoint. It works; it does the job--but it'sa freaking prototype. It's totally not scalable. My boss wants to wow clients and "just get the feature out." I understand that. But, we could take two weeks and finish this shit up, or we could take three and finish this shit up AND do it so that it's scalable. I just KNOW we are going to want to add onto this feature in the coming months, and then, a customer is going to "need it in a week," and so even though we've agreed to refactor when we want to add onto the feature, IT WILL NEVER HAPPEN! This ALWAYS happens. I'm the code quality assurance guy, but my boss seems to see me as a radical and thinks I just waste time, whereas I actually am trying to follow good, known solid design patterns. He just wants his stinking feature though, and he doesn't want to spend the time or money to do things well. He pretty much listens to what I have to say, and then he ultimately just makes the decision to take the shortest path (which cuts corners a lot). I often develop large, important features for our software. THOSE THINGS TAKE TIME! They're not happy with the time it's taken with past projects, though, but the features I've put in all work really damn well and are very scalable. How do you all deal with this kind of situation?

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• Projective transformation

  - by mcwehner

  Given two image buffers (assume it's an array of ints of size width * height, with each element a color value), how can I map an area defined by a quadrilateral from one image buffer into the other (always square) image buffer? I'm led to understand this is called "projective transformation". I'm also looking for a general (not language- or library-specific) way of doing this, such that it could be reasonably applied in any language without relying on "magic function X that does all the work for me". An example: I've written a short program in Java using the Processing library (processing.org) that captures video from a camera. During an initial "calibrating" step, the captured video is output directly into a window. The user then clicks on four points to define an area of the video that will be transformed, then mapped into the square window during subsequent operation of the program. If the user were to click on the four points defining the corners of a door visible at an angle in the camera's output, then this transformation would cause the subsequent video to map the transformed image of the door to the entire area of the window, albeit somewhat distorted.

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• CIE XYZ colorspace: do I have RGBA or XYZA?

  - by Tronic

  I plan to write a painting program based on linear combinations of xy plane points (0,1), (1,0) and (0,0). Such system works identically to RGB, except that the primaries are not within the gamut but at the corners of a triangle that encloses the entire gamut. I have seen the three points being referred to as X, Y and Z (upper case) somewhere, but I cannot find the page anymore (I marked them to the picture myself). My pixel format stores the intensity of each of those three components the same way as RGB does, together with alpha value. This allows using pretty much any image manipulation operation designed for RGBA without modifying the code. What is my format called? Is it XYZA, RGBA or something else? Google doesn't seem to know of XYZA. RGBA will get confused with sRGB + alpha (which I also need to use in the same program). Notice that the primaries X, Y and Z and their intensities have little to do with the x, y and z coordinates (lower case) that are more commonly used.

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• Silverlight: How can I built an overview display block for any XAML?

  - by Ryan Bates

  Hi all, I am trying to create a generic "overview" control for any XAML. A good example of the desired effect would be on Google Maps or Bing maps: The main map zooms into some content, while a small "overview" block is docked to one of the map corners, showing the user where he/she is zoomed into. My content is all placed inside a <Canvas>, which can then be scaled and zoomed with transforms. While the user does this kind of navigation, I would like to give them a visual indication of where they are in the larger context of the content. I have tried to take a 'screenshot' of the XAML before the user starts navigating, i.e. create a WriteableBitmap wbImageData = new WriteableBitmap(TheCanvas, null); and then displaying it in an Image. Based on the user's scrolling and zooming activity, a Rectangle displays which part of the content is currently visible in the display area. This works OK-ish (still clunky), but the image has to be redone everytime the content changes. Is there a simple way to create this kind of preview, or does anyone know of a component that does it? Thanks!

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• Javascript and rendering pauses and stays paused on scroll in the android browser

  - by user357303

  Hi. I've found some wierd behaviour related to scrolling and rendering and javascript. How to make it happen: On any webpage that is long enough to scroll on. Start to scroll pretty fast (fling the page). then release the touch. No while the page is still scrolling because of the momentum. Tap the screen to stop the scroll. This make the browser enter a wierd mode. On the nexus one it behaves like this: The updating of what's shown on the screen stops, you can still click on links and the go to where they are supposed to but what's shown on the screen stays the same. If you then scroll the screen a bit the update of the screen kicks in again and what you you where suppsed to see all the time is shown. On all phones with HTC Sense I've tried (Hero, Desire, Legend) this happens: The updating of the screen is stopped just like on the nexus one, but also the execution of any javascript is stopped. If you click on a link that takes you to another page however things return to normal again. The way I tested this was I created a page like this: http://pastebin.ca/1881620 The changeColor function simply changed the background color of 'container' to a few different colors. So before the error what happens is that when you click any link the color changes. after the error this happens: Nexus one: when you click on the links nothing happens (except the "orange link selected rounded corner box thing" is shown as if the link is clicked). Then when you scroll abit. You can see the color has changed (and equal amount of times to the number of times I clicked the link). On Sense: The links take me to google.com Has anyone else noticed this problem? Is there anyway to work around it? Thanks.

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• problems selecting a mutliple select value from database in Rails

  - by Ramy

  From inside of a form_for in rails, I'm inserting multiple select values into the database, like this: <div class="new-partner-form"> <%= form_for [:admin, matching_profile.partner, matching_profile], :html => {:id => "edit_profile", :multipart => true} do |f| %> <%= f.submit "Submit", :class => "hidden" %> <div class="rounded-block quarter-wide radio-group"> <h4>Exclude customers from source:</h4> <%= f.select :source, User.select(:source).group(:source).order(:source).map {|u| [u.source,u.source]}, {:include_blank => false}, {:multiple => true} %> <%= f.error_message_on :source %> </div> I'm then trying to pull the value from the database like this: def does_not_contain_source(matching_profiles) Expression.select(matching_profiles, :source) do |keyword| Rails.logger.info("Keyword is : " + keyword) @customer_source_tokenizer ||= Tokenizer.new(User.select(:source).where("id = ?", self.owner_id).map {|u| u.source}[0]) #User.select("source").where("id = ?", self.owner_id).to_s) @customer_source_tokenizer.divergent?(keyword) end end but getting this: ExpressionErrors: Bad syntax: --- - "" - B - "" this is what the value is in the database but it seems to choke when i access it this way. What's the right way to do this?

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• why is css not being applied to this jquery anchor button?

  - by Tim

  I must be missing something very basic in the CSS. My jQuery anchor button is functional, but it's rendering as a simple underlined label, not asa rounded-corner UI button. I would be grateful if someone could point out the error in this simple example. Thanks !DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <HTML LANG="en-US"> <HEAD> <TITLE>button test</TITLE> <META http-equiv="Content-Type" content="text/html; charset=UTF-8"> <meta http-equiv="Expires" content="Sat, 22 May 2010 00:00:11 GMT"> <link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.1/jquery-ui.min.js"></script> <SCRIPT type="text/javascript"> $(document).ready( function() { $('a','.test').click(function(){showIntro();return false;}); }); function showIntro() { document.location.href="intro.htm"; } </script> <body> <div class='test'><a href="#">Button</a></div> </body> </html>

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• How to Use border as an image in android xml

  - by Ethan Hunt

  I have a popup to show in my xml. It should have a border. Following is the code:- <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/rl_parent" android:layout_width="wrap_content" android:layout_height="wrap_content" android:paddingBottom="20dp" > <RelativeLayout android:id="@+id/rl_startpopup" android:layout_width="340dp" android:layout_height="320dp" android:layout_marginLeft="10dp" android:layout_marginRight="10dp" android:background="@drawable/popup_outline" android:orientation="vertical" /> </RelativeLayout> The popup_outline is a shape <?xml version="1.0" encoding="utf-8"?> <shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle" > <gradient android:angle="270" android:endColor="#192423" android:startColor="#4a7669" android:type="linear" /> <corners android:radius="8dp" /> <stroke android:width="2dp" android:color="#e4f4d3" /> </shape> here is the image of the popup:- This "popup_outline" is the white border shown. I want to use a repeatable pattern image instead of one color as the border. I have to do this in xml. Please help

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• How do I send an email with HTML with an address the user inputs?

  - by MeganSime

  I have an app i am designing and there is a page for emails. The user inputs their name, email address and message and then clicks 'submit'. this works, but i don't know how to make the user's input be on the email. this is the code so far; <form id="contacts-form" action="mailto:[email protected]"> <ul class = "rounded"> <li style = "color: #FFFFFF">Full Name:<input type="text" placeholder = "J. Doe" name = "signature" id = 'signature' /></li> <li style = "color: #FFFFFF">E-mail:<input type="text" placeholder = "[email protected]" name = "address" id = 'address' /></li> <li style = "color: #FFFFFF">Message:<input type = "text" placeholder = "Message" name = "message" id = 'message' /></li> <a href="mailto:address?subject=subject&body=message" class="button">Submit</a> </ul> </form> does anyone know how to change the code to allow the user input to go onto the email? Thanks a lot in advance x

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• Making a Javascript game, Having a little problem with scrolling.

  - by RobertWHurst

  I have a #wrapper div and a #grid div nested inside. currently I can scroll around with this function below. getCursorPos : function(){ // set the empty cursor object var cursor = {}; //get the offset from the left of the grid container var grid //offset loop $(function getCursorPos(){ grid = $('#grid').offset(); setTimeout(getCursorPos, game.loopSpeed); }); //continuosly get the position var that = this; $(document).mousemove(function(e){ //if game mode is menu exit if(game.mode === 'menu'){ return; } // NOTE: this looks a litle over done but don't remove anything // its like this because javascript uses floating points // and so in order to line up to the nearest hunderedth I // had to make the cursor and div position intergers by // muliplying by ten. one the two are added I reduced them // and rounded them. that.x = Math.round(((e.pageX * 10) - (grid.left * 10)) / 10); that.y = Math.round(((e.pageY * 10) - (grid.top * 10)) / 10); }); }, the problem is that the mouse coordinates only update when the mouse moves. is there any way to get the coordinates with out moving the mouse?

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• Convert long/lat to pixel x/y on a given picure.

  - by Kalinin

  I have a city "map" (for example - Moscow). She in accuracy repeats the contours the given city in google maps (that is it is copied from google maps and it is a little processed, but the sense remained the same). Also I have object co-ordinates in a city (in co-ordinates of google). Problem: how to convert google co-ordinates to the co-ordinates of my picture (that is in pixels on OX and OY on a picture). That is I receive google-co-ordinates and it is necessary for me to draw this point on my picture. The most desired variant of the answer - is based on javascript, but it is possible and on php. I know that on small scales (for example on city scales) it to make simply enough (it is necessary to learn what google-co-ordinates has one of picture corners, then to learn "price" of one pixel in google-co-ordinates on a picture on axes OX and OY separately). But on the big scales (country scale) "price" of one pixel will be not a constant, and will vary strongly enough and the method described above cannot be applied. How to solve a problem on country scales?

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• How to draw shadows that don't suck?

  - by mystify

  A CAShapeLayer uses a CGPathRef to draw it's stuff. So I have a star path, and I want a smooth drop shadow with a radius of about 15 units. Probably there is some nice functionality in some new iPhone OS versions, but I need to do it myself for a old aged version of 3.0 (which most people still use). I tried to do some REALLY nasty stuff: I created a for-loop and sequentially created like 15 of those paths, transform-scaling them step by step to become bigger. Then assigning them to a new created CAShapeLayer and decreasing it's alpha a little bit on every iteration. Not only that this scaling is mathematically incorrect and sucks (it should happen relative to the outline!), the shadow is not rounded and looks really ugly. That's why nice soft shadows have a radius. The tips of a star shouldn't appear totally sharp after a shadow size of 15 units. They should be soft like cream. But in my ugly solution they're just as s harp as the star itself, since all I do is scale the star 15 times and decrease it's alpha 15 times. Ugly. I wonder how the big guys do it? If you had an arbitrary path, and that path must throw a shadow, how does the algorithm to do that work? Probably the path would have to be expanded like 30 times, point-by-point relative to the tangent of the outline away from the filled part, and just by 0.5 units to have a nice blending. Before I re-invent the wheel, maybe someone has a handy example or link?

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• Is there bug in the Matrix.RotateAt method for certain angles? .Net Winforms

  - by Jules

  Here's the code i'm using to rotate: Dim m As New System.Drawing.Drawing2D.Matrix Dim size = image.Size m.RotateAt(degreeAngle, New PointF(CSng(size.Width / 2), CSng(size.Height / 2))) Dim temp As New Bitmap(600, 600, Imaging.PixelFormat.Format32bppPArgb) Dim g As Graphics = Graphics.FromImage(temp) g.Transform = m g.DrawImage(image, 0, 0) (1) Disposals removed for brevity. (2) I test the code with a 200 x 200 rectangle. (3) Size 600,600 it just an arbitrary large value that I know will fit the right and bottom sides of the rotated image for testing purposes. (4) I know, with this code, the top and left edges will be clipped because I'm not transforming the orgin after the rotate. The problem only occurs at certain angles: (1) At 90, the right hand edge disappears completely. (2) At 180, the right and bottom edges are there, but very faded. (3) At 270, the bottom edge disappears completely. Is this a known bug? If I manually rotate the corners an draw the image by specifying an output rectangle, I don't get the same problem - though it is slightly slower than using RotateAt.

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