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  • Linux: shell builtin string matching

    - by gmatt
    I am trying to become more familiar with using the builtin string matching stuff available in shells in linux. I came across this guys posting, and he showed an example a="abc|def" echo ${a#*|} # will yield "def" echo ${a%|*} # will yield "abc" I tried it out and it does what its advertised to do, but I don't understand what the $,{},#,*,| are doing, I tried looking for some reference online or in the manuals but I couldn't find anything. Can anyone explain to me what's going on here?

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  • Running shell scripts with sudo through my web app

    - by nfm
    I have some functionality that interfaces with the server's OS in my web application. I've written a bash script and am able to run it from within my app. However, some functionality of the script requires superuser privileges. What is the most sane way to run this script securely? It is being passed arguments from a web form, but should only be able to be called by authenticated users that I trust not to haxxor it.

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  • An agenda in Korn Shell: New / Edit / Delete / View appointment

    - by Abaco
    As stated in the title, I have to write a simple script which should perform some typical agenda's functions. The script must use crontab. The functions are: Creating a new appointment Edit an existent appointment Delete an appointment List the appointment I really don't have a clue how to do this, can you help me with some hint? Maybe a bit of sweet code? Thank you very much, Abaco EDIT: To be more specific on my question Point 1: how can I edit a crontab thorugh ksh? How can I insert a new line? Can you link me some documentation or a bit of code about this?

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  • How to: Simulating keystroke inputs in shell to an app running in an embedded target

    - by fzkl
    I am writing an automation script that runs on an embedded linux target. A part of the script involves running an app on the target and obtaining some data from the stdout. Stdout here is the ssh terminal connection I have to the target. However, this data is available on the stdout only if certain keys are pressed and the key press has to be done on the keyboard connected to the embedded target and not on the host system from which I have ssh'd into the target. Is there any way to simulate this? Edit: Elaborating on what I need - I have an OpenGL app that I run on the embedded linux (works like regular linux) target. This displays some graphics on the embedded system's display device. Pressing f on the keyboard connected to the target outputs the fps data onto the ssh terminal from which I control the target. Since I am automating the process of running this OpenGL app and obtaining the fps scores, I can't expect a keyboard to be connected to the target let alone expect a user to input a keystroke on the embedded target keyboard. How do I go about this? Thanks.

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  • Telnet SMTP with expect or shell script

    - by Fendrix
    Want to build up a Auth Smtp Connection with expect script... just to test I wanted to get ehlo parameters but expect is not working like this #!/usr/bin/expect set timeout -1 set smtp [lindex $argv 0] set port [lindex $argv 1] spawn telnet $smtp $port expect "[2]{2,}[0]{1,}" send "ehlo" I expect the code 220 to come from mailserver to continue to send ehlo ... just like ..../...:telnet smtp.mail.yahoo.de 25 Trying 77.238.184.85... Connected to smtp2-de.mail.vip.ukl.yahoo.com. Escape character is '^]'. 220 smtp116.mail.ukl.yahoo.com ESMTP ehlo 250-smtp116.mail.ukl.yahoo.com 250-AUTH LOGIN PLAIN XYMCOOKIE 250-PIPELINING 250-SIZE 41697280 250 8BITMIME

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  • Korn Shell SegFault

    - by C. Ross
    I have found the following script causes a segmentation fault and core in kshell on AIX. Can anyone explain why I get the following results? Seg Fault doOutput(){ Echo "Something" } doOutput() >&1 OR doOutput(){ Echo "Something" } echo `doOutput()` No Output doOutput(){ Echo "Something" } doOutput() Correct doOutput(){ Echo "Something" } doOutput OR doOutput(){ Echo "Something" } doOutput >&1

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  • Function behaviour on shell(ksh) script

    - by footy
    Here are 2 different versions of a program: this Program: #!/usr/bin/ksh printmsg() { i=1 print "hello function :)"; } i=0; echo I printed `printmsg`; printmsg echo $i Output: # ksh e I printed hello function :) hello function :) 1 and Program: #!/usr/bin/ksh printmsg() { i=1 print "hello function :)"; } i=0; echo I printed `printmsg`; echo $i Output: # ksh e I printed hello function :) 0 The only difference between the above 2 programs is that printmsg is 2times in the above program while printmsg is called once in the below program. My Doubt arises here: To quote Be warned: Functions act almost just like external scripts... except that by default, all variables are SHARED between the same ksh process! If you change a variable name inside a function.... that variable's value will still be changed after you have left the function!! But we can clearly see in the 2nd program's output that the value of i remains unchanged. But we are sure that the function is called as the print statement gets the the output of the function and prints it. So why is the output different in both?

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  • Explained shell statement

    - by Mats Stijlaart
    The following statement will remove line numbers in a txt file: cat withLineNumbers.txt | sed 's/^.......//' >> withoutLineNumbers.txt The input file is created with the following statement (this one i understand): nl -ba input.txt >> withLineNumbers.txt I know the functionality of cat and i know the output is written to the 'withoutLineNumbers.txt' file. But the part of '| sed 's/^.......//'' is not really clear to me. Thanks for your time.

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  • shell script filter du and find by a string inside a file in a subfolder

    - by Jason
    I have the following command that I run on cygwin: find /cygdrive/d/tmp/* -maxdepth 0 -mtime -150 -type d | xargs du --max-depth=0 > foldersizesreport.csv I intended to do the following with this command: for each folder under /d/tmp/ that was modified in last 150 days, check its total size including files within it and report it to file foldersizesreport.csv however that is now not good enough for me, as it turns out inside each /d/tmp/subfolder1/somefile.properties /d/tmp/subfolder2/somefile.properties /d/tmp/subfolder3/somefile.properties /d/tmp/subfolder4/somefile.properties so as you see inside each subfolderX there is a file named somefile.properties inside it there is a property SOMEPROPKEY=3808612800100 (among other properties) this is the time in millisecond, i need to change the command so that instead of -mtime -150 it will include in the whole calculation only subfolderX that has a file inside them somefile.properties where the SOMEPROPKEY=3808612800100 is the time in millisecond in future, if the value SOMEPROPKEY=23948948 is in past then dont at all include the folder in the foldersizesreport.csv because its not relevant to me. so the result report should be looking like: /d/tmp/,subfolder1,<itssizein KB> /d/tmp/,subfolder2,<itssizein KB> and if subfolder3 had a SOMEPROPKEY=34243234 (time in ms in past) then it would not be in that csv file. so basically I'm looking for: find /cygdrive/d/tmp/* -maxdepth 0 -mtime -150 -type d | <only subfolders that have in them property in file SOMEPROPKEY=28374874827 - time in ms in future and not in past | xargs du --max-depth=0 > foldersizesreport.csv

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  • Sum in shell script

    - by Dinis Monteiro
    Why can't I create a sum of total words in this script? I get the result something like: 120+130 but it isn't 250 (as I expected)! Is there any reason? #!/bin/bash while [ -z "$count" ] ; do echo -e "request :: please enter file name " echo -e "\n\tfile one : \c" read count itself=counter.sh countWords=`wc -w $count |cut -d ' ' -f 1` countLines=`wc -l $count |cut -d ' ' -f 1` countWords_=`wc -w $itself |cut -d ' ' -f 1` echo "Number of lines: " $countLines echo "Number of words: " $countWords echo "Number of words -script: " $countWords_ echo "Number of words -total " $countWords+$countWords_ done if [ ! -e $count ] ; then echo -e "error :: file one $count doesn't exist. can't proceed." read empty exit 1 fi

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  • BASH SHELL IF ELSE run command in background

    - by bikerben
    I have used the & command before to make a script run another script in the background like so: #!/bin/bash echo "Hello World" script1.sh & script2.sh & echo "Please wait..." But lets say I have another script with an IF ELSE statment and I would like to set an ELIF statement mid flow as a background task witht the & and then carry on with processing the rest of my script knowing that while rest of the ELIF will carry running in the back ground: #!/bin/bash if cond1; then stuff sleep 10 & stuff stuff elif cond2; then something else else echo "foo" fi stuff echo "Hello World" I really hope this makes sense any help would be greatly appreciated.

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  • Shell Script - print selected columns

    - by teepusink
    Hi, I have a txt file with columns separated by tabs and based on that file, I want to create a new file that only contains information from some of the columns. This is what I have now awk '{ print $1, $5 }' filename newfilename That works except that when column 5 contains spaces e.g 123 Street, only 123 shows up and the street is considered as another column. How can I achieve what I'm trying to do? Thanks, Tee

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  • Shell Script- each unique user

    - by Dinis Monteiro
    Hi guys I need "for each unique user, report which group they are a member of and when they last logged in" so i have: #!/bin/sh echo "Your initial login:" who | cut -d' ' -f1 | sort | uniq echo "Now is logged:" whoami echo "Group ID:" id -G $whoami case $1 in "-l") last -Fn 10 | tr -s " " ;; *) last -Fn 10 | tr -s " " | egrep -v '(^reboot)|(^$)|(^wtmp a)|(^ftp)' | cut -d" " -f1,5,7 | sort -uM | uniq -c esac My question is: how i can show the each unique user? the script above only show the more recent user logged in the system, but i need all unique users. anyone can help? thanks

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  • How to use a string as a delimiter shell script

    - by Dan
    I am reading a line and am using regex to match it in my script. (/bin/bash) echo $line | grep -E '[Ss][Uu][Bb][Jj][Ee][Cc][Tt]: [Hh][Ee][Ll][Pp]' > /dev/null 2>&1 if [[ $? = "0" && -z $subject ]]; then subject=`echo $line | cut -d: -f2` > /dev/null echo "Was able to grab a SUBJECT $line and the actual subject is -> $subject" >> $logfile fi now my problem is that i use the colon as the delimiter. but sometimes the email will have multiple colons in the subject and so I am not able to grab the whole subject because of that. I am looking for a way to grab everything after the colon following subject. even is there is a way to loop through and check for a colon or what. maybe cut allows you to cut with a string as delimiter? Not sure...any ideas? Thanks!

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  • shell script stopped working --- need to rewrite?

    - by OopsForgotMyOtherUserName
    The script below worked on my Mac OS X. I'm now using Ubuntu OS, and the script is no longer working. I'm wondering if there's something that I need to change here? I did change the first line from #!/bin/bash to #!/bin/sh, but it's still throwing up an error.... Essentially, I get an error when I try to run it: Syntax error: end of file unexpected (expecting ")") #!/bin/sh REMOTE='ftp.example.com' USER='USERNAME' PASSWORD='PASSWORD' CMDFILE='/jtmp/rc.ftp' FTPLOG='/jtmp/ftplog' PATTERN='SampFile*' date > $FTPLOG rm $CMDFILE 2>/dev/null LISTING=$(ftp -in $REMOTE <<EOF user $USER $PASSWORD cd download ls $PATTERN quit EOF ) echo "open $REMOTE" >> $CMDFILE echo "user $USER $PASSWORD" >> $CMDFILE echo "verbose" >> $CMDFILE echo "bin" >> $CMDFILE echo "cd download" >> $CMDFILE for FILE in $LISTING do echo "get $FILE" >> $CMDFILE done echo "quit" >> $CMDFILE ftp -in < $CMDFILE >> $FTPLOG 2>&1 rm $CMDFILE

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  • Skipping a line and reading another line in shell script while loop

    - by parameswar
    i have a code which reads a file line by line using a while loop. Inside the while loop, i have certain conditions. Is there a way using which i can skip the current line and read the next line based upon the condition ? Let me be precise: while read Line do //some sample conditions a=$Line if [ "a" == "b" ] //i want to go to the next line from this point. done < **inputfile** Any help would be appreciated.

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  • Shell complains 'cannot execute binary file'

    - by Negai
    Hi everyone, I've playing around with linux and noticed that for some mysterious reason commands like '/bin/sh ' just will not work. Each time I'm trying to start a process it yields 'cannot execute binary file' error message. m@sanctuary:~$ sh sed /bin/sed: /bin/sed: cannot execute binary file When I first launch sh and try to execute sed, it succeeds. I'm starting to loose my wits. It would be just great, if somebody could help me. Thank you.

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  • Shell Screen -X Stuff problems

    - by user1621988
    OPTIONS="java -Xms1024M -Xmx1024M -jar craftbukkit.jar" PROCESS=server01 screen -dmS $PROCESS $OPTIONS nogui # Starting the application screen -x $PROCESS -X stuff `printf "stop\r"` # Closing the application screen -x $PROCESS # Attaching to the terminal of the application Starting the application work fine, however I got problems with stuff 'printf "stop/r"' It seems not to work when I just start up, wait some time and then try to Stop it with command above. But the strange thing is, that IF I did screen -x $PROCESS and detach (ctrl-A & ctrl-D) and then I use the Stop command it does work. So is there a way around to stuff printf without -screen -x the $PROCESS? Thank You in Advance

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  • Can a shell loop do this?

    - by helpwithshell
    Ive seen loops to unzip all zip files in a directory, however, before I run this, I would rather make sure what Im about to run will work right: for i in dir; do cd $i; unzip '*.zip'; rm -rf *.zip; cd ..; done Basically I want it to look at the output of "dir" see all the folders, for each directory cd into it, unzip all the zip archives, then remove them, then cd back and do it again until theres no more. Is this something I should do in a single command or should I consider doing this in perl?

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  • Shell script for generating HTML out put

    - by user1638016
    The following script is generating the desired out put but not redirecting the result to /home/myuser/slavedelay.html #!/bin/bash host=<ip> echo $host user=usr1 password=mypass threshold=300 statusok=OK statuscritical=CRITICAL for i in ert7 ert9 do echo "<html>" > /home/myuser/slavedelay.html if [ "$i" == "ert7" ]; then slvdelay=`mysql -u$user -p$password -h<ip> -S /backup/mysql/mysql.sock -e 'show slave status\G' | grep Seconds_Behind_Master | sed -e 's/ *Seconds_Behind_Master: //'` if [ $slvdelay -ge $threshold ]; then echo "<tr><td>$i</td><td>CRITICAL</td>" >> /home/myuser/slavedelay.html echo "<tr><td>$i</td><td>CRITICAL</td>" else echo "<tr><td>$i</td><td>OK</td>" >> /home/myuser/slavedelay.html echo "<tr><td>$i</td><td>OK</td>" fi fi done echo "</html>" >> /home/myuser/slavedelay.html If I cat the output file /home/myuser/slavedelay.html it gives. <html> </html> Execution result : sh slave_delay.sh <tr><td>sdb7</td><td>OK</td>

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