Search Results

Search found 25747 results on 1030 pages for 'tree view'.

Page 26/1030 | < Previous Page | 22 23 24 25 26 27 28 29 30 31 32 33  | Next Page >

  • How can I save a directory tree to an array in PHP?

    - by Greg
    I'm trying to take a directory with the structure: top folder1 file1 folder2 file1 file2 And save it into an array like: array ( 'folder1' => array('file1'), 'folder2' => array('file1', 'file2') ) This way, I can easily resuse the tree throughout my site. I've been playing around with this code but it's still not doing what I want: private function get_tree() { $uploads = __RELPATH__ . DS . 'public' . DS . 'uploads'; $iterator = new RecursiveIteratorIterator(new RecursiveDirectoryIterator($uploads), RecursiveIteratorIterator::SELF_FIRST); $output = array(); foreach($iterator as $file) { $relativePath = str_replace($uploads . DS, '', $file); if ($file->isDir()) { if (!in_array($relativePath, $output)) $output[$relativePath] = array(); } } return $output; }

    Read the article

  • How do I output the preorder traversal of a tree given the inorder and postorder tranversal?

    - by user342580
    Given the code for outputing the postorder traversal of a tree when I have the preorder and the inorder traversal in an interger array. How do I similarily get the preorder with the inorder and postorder array given? void postorder( int preorder[], int prestart, int inorder[], int inostart, int length) { if(length==0) return; //terminating condition int i; for(i=inostart; i<inostart+length; i++) if(preorder[prestart]==inorder[i])//break when found root in inorder array break; postorder(preorder, prestart+1, inorder, inostart, i-inostart); postorder(preorder, prestart+i-inostart+1, inorder, i+1, length-i+inostart-1); cout<<preorder[prestart]<<" "; } Here is the prototype for preorder() void preorder( int inorderorder[], int inostart, int postorder[], int poststart, int length)

    Read the article

  • How can I do block-oriented disk I/O with Java? Or similar for a B+ tree

    - by Sanoj
    I would like to implement an B+ tree in Java and try to optimize it for disk based I/O. Is there an API for accessing individual disk blocks from Java? or is there an API that can do similar block-oriented access that fits my purpose? I would like to create something like Tokyo Cabinet in 100% Java. Is there anyone that knows what Java only databases like JavaDB is using in the back-end for this? I know that there are probably other languages than Java that can do this better, but I do this in a learning purpose only.

    Read the article

  • How to change the sorting of a view using hook_views_pre_view()?

    - by RD
    I've got the following: function view_sorter_views_pre_view(&$view) { // don't need $items if ($view->name == 'MOST_RECENT') { $insert = array(); $insert[order] = 'DESC'; //SORT ORDER $insert[id] = 'title'; $insert[table] = 'node'; $insert[field] = 'title'; $insert[override] = array(); $insert[override][button] = 'Override'; $insert[relationship] = 'none'; unset ($view->display['default']->display_options['sorts']['title']); $view->display['default']->display_options['sorts']['title'] = $insert; } } Basically, I'm just changing the sort order... but this does not appear on the view when opening it. Any idea why?

    Read the article

  • How will you register a custom view engine where in the Areas will not be affected?

    - by Fleents
    I made a custom view engine for my application. ~/Themes/Default/Views.. And I have an Area called Admin. Area/Admin/Views.. I register my custom view engine in Global.asax : RegisterViewEngines(ViewEngines.Engines); AreaRegistration.RegisterAllAreas(); RegisterRoutes(RouteTable.Routes); When I browsed my admin site, it cant find the views.. I know its because of my custom view engine.. But how can you register new custom view engine without affecting the view engine of areas?

    Read the article

  • HTML Markup in einem APEX Tree - ganz einfach per Plugin!

    - by carstenczarski
    Die APEX Tree Region kennt sicherlich jeder APEX-Entwickler. Und vielfach besteht der Bedarf, das Aussehen des APEX Tree mit Hilfe von HTML Markup zu beeinflussen. Leider ist es seit APEX 4.0 nicht mehr möglich, eigenes HTML-Markup in einen APEX-Tree aufzunehmen - aus Sicherheitsgründen (Schutz vor Cross-Site-Scripting) werden alle HTML Sonderzeichen maskiert. Wenn kein XSS-Risiko besteht (die vom Tree dargestellten Inhalte basieren nicht auf Benutzereingaben und werden komplett vom Entwickler bestimmt), kann dies mit wenigen Zeilen JavaScript und jQuery-Code erreicht werden. Damit es noch einfacher wird,  haben wir die Funktionalität für Sie in einem APEX-Plugin gekapselt. Und so funktioniert es: APEX Plugin "HTML Markup for APEX Tree Region" herunterladenhttp://apex-plugin.com/oracle-apex-plugins/dynamic-action-plugin/html-markup-for-apex-tree_174.html APEX Plugin in die Anwendung importieren APEX Tree Region erzeugen und eigene Ersetzungen für HTML-Sonderzeichen verwenden, also bspw."[" für "<", "]" für ">" und "§" für "&". Eine neue dynamische Aktion erzeugen, die beim Laden der Seite ausgeführt wird und mit Hilfe des Plugins die Ersetzungen im Tree durch die "richtigen" HTML-Sonderzeichen ersetzt. Fertig. Wie das Plugin wirkt, können Sie sich auf einer Demo-Seite ansehen.

    Read the article

  • Tool to compute SHA256 Tree Hash

    - by Benjamin
    I've started using AWS Glacier, and noticed that it hashes the files using an algorithm called SHA-256 Tree Hash. To my surprise, this algorithm is different from SHA-256, so I can't use the tools I'm used to, to compare hashes and verify file integrity. Do you know a Windows tool, if possible integrated in the context menu, to compute the SHA-256 Tree Hash of a file? I'd also accept a Linux command-line tool, as a second choice :-)

    Read the article

  • Hierarchical View/ViewModel/Presenters in MVPVM

    - by Brian Flynn
    I've been working with MVVM for a while, but I've recently started using MVPVM and I want to know how to create hierarchial View/ViewModel/Presenter app using this pattern. In MVVM I would typically build my application using a hierarchy of Views and corresponding ViewModels e.g. I might define 3 views as follows: The View Models for these views would be as follows: public class AViewModel { public string Text { get { return "This is A!"; } } public object Child1 { get; set; } public object Child2 { get; set; } } public class BViewModel { public string Text { get { return "This is B!"; } } } public class CViewModel { public string Text { get { return "This is C!"; } } } In would then have some data templates to say that BViewModel and CViewModel should be presented using View B and View C: <DataTemplate DataType="{StaticResource local:BViewModel}"> <local:BView/> </DataTemplate> <DataTemplate DataType="{StaticResource local:CViewModel}"> <local:CView/> </DataTemplate> The final step would be to put some code in AViewModel that would assign values to Child1 and Child2: public AViewModel() { this.Child1 = new AViewModel(); this.Child2 = new BViewModel(); } The result of all this would be a screen that looks something like: Doing this in MVPVM would be fairly simple - simply moving the code in AViewModel's constructor to APresenter: public class APresenter { .... public void WireUp() { ViewModel.Child1 = new BViewModel(); ViewModel.Child2 = new CViewModel(); } } But If I want to have business logic for BViewModel and CViewModel I would need to have a BPresenter and a CPresenter - the problem is, Im not sure where the best place to put these are. I could store references to the presenter for AViewModel.Child1 and AViewModel.Child2 in APresenter i.e.: public class APresenter : IPresenter { private IPresenter child1Presenter; private IPresenter child2Presenter; public void WireUp() { child1Presenter = new BPresenter(); child1Presenter.WireUp(); child2Presenter = new CPresenter(); child2Presenter.WireUp(); ViewModel.Child1 = child1Presenter.ViewModel; ViewModel.Child2 = child2Presenter.ViewModel; } } But this solution seems inelegant compared to the MVVM approach. I have to keep track of both the presenter and the view model and ensure they stay in sync. If, for example, I wanted a button on View A, which, when clicked swapped the View's in Child1 and Child2, I might have a command that did the following: var temp = ViewModel.Child1; ViewModel.Child1 = ViewModel.Child2; ViewModel.Child2 = temp; This would work as far as swapping the view's on screen (assuming the correct Property Change notification code is in place), but now my APresenter.child1Presenter is pointing to the presenter for AViewModel.Child2, and APresenter.child2Presenter is pointing to the presenter for AViewModel.Child1. If something accesses APresenter.child1Presenter, any changes will actually happen to AViewModel.Child2. I can imagine this leading to all sorts of debugging fun. I know that I may be misunderstanding the pattern, and if this is the case a clarification of what Im doing wrong would be appreciated.

    Read the article

  • Binary Search Tree in C

    - by heapzero
    Hi, I'm a Python guy. Learning C language and I've been trying to implement Binary Search Tree in C. I wrote down the code, and I've been trying from few hours but, not able to get the output as expected. Please help! Please correct me. #include<stdlib.h> #include<stdio.h> typedef int ElementType; typedef struct TreeNode { ElementType element; struct TreeNode *left, *right; } TreeNode; TreeNode *createTree(){ //Create the root of tree TreeNode *tempNode; tempNode = malloc(sizeof(TreeNode)); tempNode->element = 0; tempNode->left = NULL; tempNode->right = NULL; return tempNode; } TreeNode *createNode(ElementType X){ //Create a new leaf node and return the pointer TreeNode *tempNode; tempNode = malloc(sizeof(TreeNode)); tempNode->element = X; tempNode->left = NULL; tempNode->right = NULL; return tempNode; } TreeNode *insertElement(TreeNode *node, ElementType X){ //insert element to Tree if(node==NULL){ return createNode(X); } else{ if(X < node->element){ node->left = insertElement(node->left, X); } else if(X > node->element){ node->right = insertElement(node->right, X); } else if(X == node->element){ printf("Oops! the element is already present in the tree."); } } } TreeNode *displayTree(TreeNode *node){ //display the full tree if(node==NULL){ return; } displayTree(node->left); printf("| %d ", node->element); displayTree(node->right); } main(){ //pointer to root of tree #2 TreeNode *TreePtr; TreeNode *TreeRoot; TreeNode *TreeChild; //Create the root of tree TreePtr = createTree(); TreeRoot = TreePtr; TreeRoot->element = 32; printf("%d\n",TreeRoot->element); insertElement(TreeRoot, 8); TreeChild = TreeRoot->left; printf("%d\n",TreeChild->element); insertElement(TreeRoot, 2); insertElement(TreeRoot, 7); insertElement(TreeRoot, 42); insertElement(TreeRoot, 28); insertElement(TreeRoot, 1); insertElement(TreeRoot, 4); insertElement(TreeRoot, 5); // the output is not as expected :( displayTree(TreeRoot); }

    Read the article

  • Pull Request Changes, Multi-Selection in Advanced View, and Advertisement Changes

    [Do you tweet? Follow us on Twitter @matthawley and @adacole_msft] We deployed a new version of the CodePlex website today. Pull Request Changes In this release, we have begun to re-focus on Pull Requests to ensure a productive experience between the project users and developers. We feel we made significant progress in this area for this release and look forward to using your feedback to drive future iterations. One of the biggest hurdles people have indicated is the inability to see what a pull request includes without pulling the source down from a Mercurial client. With today’s changes, any user has the ability to view a pull request, the changesets / changes included, and perform an inline diff of the file. When a pull request is made, the CodePlex website will query for all outgoing changes from the fork to the main repository for a point-in-time comparison. Because of this point-in-time comparison… All existing pull requests created prior to this release will not have changesets associated with them. If new commits are pushed to the fork while a pull request is active, they will not appear associated with the pull request. The pull request will need to be re-submitted for them to appear. Once a pull request is created, you can “View the Pull Request” which takes you to a page that looks like As you may notice, we now display a lot more detailed information regarding that pull request including who it was requested by and when, the associated changesets, the description, who it’s assigned to (we’ll come back to this) and the listing of summarized file changes. What you’ll also notice, is that each modified file has the ability to view a diff of all changes made. When you click “(view diff)” for a file, an inline diff experience appears. This new experience allows you to quickly navigate through all of the modified files as well as viewing the various change blocks for each file. You’ll also notice as you browse through each file’s changes, we update the URL to include the file path so you can quickly send a direct link to a pull request’s file. Clicking “(close diff)” will bring you back to the original pull request view. View this pull request live on WikiPlex. Pull Request Review Assignment Another new feature we added for pull requests is the ability for project members to assign pull requests for review. Any project member has the ability to assign (and re-assign if needed) a pull request to a project member. Once the assignment has been made, that project member will be notified via email of the assignment. Once they complete the review of the pull request, they can either accept or deny it similarly to the previous process. Multi-Selection in Advanced View Filters One of the more recent requests we have heard from users is the ability multi-select advanced view filters for work items. We are happy to announce this is now possible. Simply control-click the multiple options for each filter item and your work item query will be refined as such. Should you happen to unselect all options for a given filter, it will automatically reset to the default option for that filter. Furthermore, the “Direct Link” URL will be updated to include the multi-selected options for each filter. Note: The “Direct Link” feature was released in our previous deployment, just never written about. It allows you to capture the current state of your query and send it to other individuals. Advertisement Changes Very recently, the advertiser (The Lounge) we partnered to provide advertising revenue for projects, or donated to charity, was acquired by Lake Quincy Media. There has been no change in the advertising platform offering, and all projects have been converted over to using the new infrastructure. Project owners should note the new contact information for getting paid. The CodePlex team values your feedback, and is frequently monitoring Twitter, our Discussions and Issue Tracker for new features or problems. If you’ve not visited the Issue Tracker recently, please take a few moments to log an idea or vote for the features you would most like to see implemented on CodePlex.

    Read the article

  • Algorithm to Render a Horizontal Binary-ish Tree in Text/ASCII form

    - by Justin L.
    It's a pretty normal binary tree, except for the fact that one of the nodes may be empty. I'd like to find a way to output it in a horizontal way (that is, the root node is on the left and expands to the right). I've had some experience expanding trees vertically (root node at the top, expanding downwards), but I'm not sure where to start, in this case. Preferably, it would follow these couple of rules: If a node has only one child, it can be skipped as redundant (an "end node", with no children, is always displayed) All nodes of the same depth must be aligned vertically; all nodes must be to the right of all less-deep nodes and to the left of all deeper nodes. Nodes have a string representation which includes their depth. Each "end node" has its own unique line; that is, the number of lines is the number of end nodes in the tree, and when an end node is on a line, there may be nothing else on that line after that end node. As a consequence of the last rule, the root node should be in either the top left or the bottom left corner; top left is preferred. For example, this is a valid tree, with six end nodes (node is represented by a name, and its depth): [a0]------------[b3]------[c5]------[d8] \ \ \----------[e9] \ \----[f5] \--[g1]--------[h4]------[i6] \ \--------------------[j10] \-[k3] Which represents the horizontal, explicit binary tree: 0 a / \ 1 g * / \ \ 2 * * * / \ \ 3 k * b / / \ 4 h * * / \ \ \ 5 * * f c / \ / \ 6 * i * * / / \ 7 * * * / / \ 8 * * d / / 9 * e / 10 j (branches folded for compactness; * representing redundant, one-child nodes; note that *'s are actual nodes, storing one child each, just with names omitted here for presentation sake) (also, to clarify, I'd like to generate the first, horizontal tree; not this vertical tree) I say language-agnostic because I'm just looking for an algorithm; I say ruby because I'm eventually going to have to implement it in ruby anyway. Assume that each Node data structure stores only its id, a left node, and a right node. A master Tree class keeps tracks of all nodes and has adequate algorithms to find: A node's nth ancestor A node's nth descendant The generation of a node The lowest common ancestor of two given nodes Anyone have any ideas of where I could start? Should I go for the recursive approach? Iterative?

    Read the article

  • What is the difference (if any) between Html.Partial(view, model) and Html.RenderPartial(view,model)

    - by Stephane
    Other than the type it returns and the fact that you call it differently of course <% Html.RenderPartial(...); %> <%= Html.Partial(...) %> If they are different, why would you call one rather than the other one? The definitions: // Type: System.Web.Mvc.Html.RenderPartialExtensions // Assembly: System.Web.Mvc, Version=2.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35 // Assembly location: C:\Program Files (x86)\Microsoft ASP.NET\ASP.NET MVC 2\Assemblies\System.Web.Mvc.dll using System.Web.Mvc; namespace System.Web.Mvc.Html { public static class RenderPartialExtensions { public static void RenderPartial(this HtmlHelper htmlHelper, string partialViewName); public static void RenderPartial(this HtmlHelper htmlHelper, string partialViewName, ViewDataDictionary viewData); public static void RenderPartial(this HtmlHelper htmlHelper, string partialViewName, object model); public static void RenderPartial(this HtmlHelper htmlHelper, string partialViewName, object model, ViewDataDictionary viewData); } } // Type: System.Web.Mvc.Html.PartialExtensions // Assembly: System.Web.Mvc, Version=2.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35 // Assembly location: C:\Program Files (x86)\Microsoft ASP.NET\ASP.NET MVC 2\Assemblies\System.Web.Mvc.dll using System.Web.Mvc; namespace System.Web.Mvc.Html { public static class PartialExtensions { public static MvcHtmlString Partial(this HtmlHelper htmlHelper, string partialViewName); public static MvcHtmlString Partial(this HtmlHelper htmlHelper, string partialViewName, ViewDataDictionary viewData); public static MvcHtmlString Partial(this HtmlHelper htmlHelper, string partialViewName, object model); public static MvcHtmlString Partial(this HtmlHelper htmlHelper, string partialViewName, object model, ViewDataDictionary viewData); } }

    Read the article

  • Switch from a View (Login) to another View with a TabBarController

    - by Raphael
    Hi, i'm new at Iphone SDK Developing and now i need some help. I have a LoginView where the User have to authentificate his legitimacy. After he enter his Username and Passwort he click on the "Sign In" Button. Then i want to load my "Real-App". Here is the Problem because i can't switch from the LoginScreen to the TabBarController. I found many solutions but only for switching to other views. Is there a way to do it ?

    Read the article

  • Capture one view and output to an other view

    - by killerapfel
    Hi, looking for an impulse, how to get that done. I know that it is possible to capture the iSight but I have no Idea how to capture the screen and output it in realtime to an other... there will be no recording, just output... would be nice if someone could give me an hint. thx in advance

    Read the article

  • Asp.net mvc getting partial view inside another view folder

    - by Shawn Mclean
    I have inside a controller PostLogicController.cs public ActionResult GetCreateNormalPost() { return PartialView("CreateNormalPost", null); } CreateNormalPost is inside the folder Post (which belongs to another post controller). How do I go about returning the CreateNormalPost.ascx? My folders are structured as follows: Controllers PostController.cs PostLogicController.cs Views Post Index.aspx CreateNormalPost.ascx There is no folder for PostLogicController.

    Read the article

  • How to display recently view items in iphone

    - by Pugal Devan
    Hi friends, I have created tab bar and have three views. Tab-1 --> table view and it navigates to detail table view. Tab-2 --> map view. Tab-3 --> table view.(Recent view for Tab-1 items). Now i have displayed the names in the table view in tab-1. The names are changed dynamically and displayed using XML parsing. In tab-3 is the recent view. Now i want to display the details in recent view those who visit recently in tab-1 view. I want to display only 10 items in the recent view. So i have used NSMutableArray and i have set deleagtes due to get the items in recent view from tab-1 view. How to avoid the duplicate recent items and how to remove the older items and inserts the new recent items in recent view. Here my sample code, In Recent view class, stories = [[NSMutableArray alloc] initWithCapacity:10]; items = [[NSMutableDictionary alloc] init]; NSString *preferName = [devDelegate getCurrentAuthor]; //(get name dynamically) [items setObject:preferName forKey:@"preferName"]; [stories addObject:[items copy]]; cell.textLabel.text = [[stories objectAtIndex:storyIndex] objectForKey:@"preferName"]; So please guide me to how to achieve this. Thanks.

    Read the article

  • how do I set a delegate in a view that is not my main view

    - by orangecl4now
    I have a xib. the xib has a button that swaps another xib. the second xib has a uitextfield and a uilabel. how do I make the keyboard go away when I'm done typing? what do I need to wire or code? the second xib has it's own class (called CustomSign.m) Inside CustomSign.m, I've implemented the following method -(void)textFieldDidEndEditing:(UITextField *)textField { [customText resignFirstResponder]; signedLabel.text = customText.text; } - (void)awakeFromNib { //assume textField is an ivar that is connected to the textfield in IB [customText setDelegate:self]; } I get the following warning Class "CustomSign" does not implement the UITextFieldDelegate protocol

    Read the article

  • List View Selected Index Changed in a multi-selectable list view

    - by Anton Indrawan
    I have a windows form with a listview control. I set the MultiSelect property to true and I added a selected_index changed event. I get the event fired when I click the same index as the current selected index. My expectation is that I will not get the event fired. The strange thing is that the event fired 1 second after I click the index. I appreciate for any reply to explain why this is happening.

    Read the article

  • Android - Issue with View when set above another View while scrolling

    - by KevinM
    I've created a ScrollView with a RelativeLayout inside of it. I have a TextView aligned at the bottom of the RelativeLayout using layout_alignParentBottom="true" and a ImageView above the TextView using "layout_above". The layout works perfect when I am on a device where the display is large enough to not have to scroll up and down. When I test it on devices where you need to scroll to see the ImageView and TextView the ImageView doesn't line up above the TextView. Actually I haven't a clue where it goes because I can't see it anywhere. It might be behind the TextView. This also happens when I'm editing an EditText with the Soft Keyboard up, which causes the RelativeLayout to scroll. Anyone knows what's going on here?

    Read the article

  • iPhone loading view from nib only works once

    - by The Swissdude
    Hi Forum I'm trying to add a «loader-view» to my app which shows a spinner while doing stuff. This works fine the first time, but it doesn't work a second time. here's what I do: I have a viewController for the spinner (spinnerViewController) and a nib-file which I made in IB (spinner.xib). I load the nib in the viewDidLoad-event: spinnerView = [[spinnerViewController alloc] initWithNibName:@"spinner" bundle:nil]; [spinnerView retain]; spinnerView is declared in the .h-file (spinnerViewController *spinnerView;) next, I show the spinner-view: [self.view addSubview:spinnerView.view]; [self.view bringSubviewToFront:spinnerView.view]; which works fine... And now the trouble starts. No matter what I do, I can't show the spinner view again. I tried just hiding it (self.view sendSubViewToBack: spinnerView.view) which works for hiding, but when I try to bring it to the front again (self.view bringSubViewToFront: spinnerView.view) it doesn't work. I also tried removing the spinner-view and add it again with no success (within the spinnerViewController: [self.view removeFromSuperview] and to show it again [self.view addSubview... ) Any ideas what I'm doing wrong??? ;) Thanks for the help!

    Read the article

  • How can I convert this PHP script to Ruby? (build tree from tabbed string)

    - by Jon Sunrays
    I found this script below online, and I'm wondering how I can do the same thing with a Ruby on Rails setup. So, first off, I ran this command: rails g model Node node_id:integer title:string Given this set up, how can I make a tree from a tabbed string like the following? <?php // Make sure to have "Academia" be root node with nodeID of 1 $data = " Social sciences Anthropology Biological anthropology Forensic anthropology Gene-culture coevolution Human behavioral ecology Human evolution Medical anthropology Paleoanthropology Population genetics Primatology Anthropological linguistics Synchronic linguistics (or Descriptive linguistics) Diachronic linguistics (or Historical linguistics) Ethnolinguistics Sociolinguistics Cultural anthropology Anthropology of religion Economic anthropology Ethnography Ethnohistory Ethnology Ethnomusicology Folklore Mythology Political anthropology Psychological anthropology Archaeology ...(goes on for a long time) "; //echo "Checkpoint 2\n"; $lines = preg_split("/\n/", $data); $parentids = array(0 => null); $db = new PDO("host", 'username', 'pass'); $sql = 'INSERT INTO `TreeNode` SET ParentID = ?, Title = ?'; $stmt = $db->prepare($sql); foreach ($lines as $line) { if (!preg_match('/^([\s]*)(.*)$/', $line, $m)) { continue; } $spaces = strlen($m[1]); //$level = intval($spaces / 4); //assumes four spaces per indent $level = strlen($m[1]); // if data is tab indented $title = $m[2]; $parentid = ($level > 0 ? $parentids[$level - 1] : 1); //All "roots" are children of "Academia" which has an ID of "1"; $rv = $stmt->execute(array($parentid, $title)); $parentids[$level] = $db->lastInsertId(); echo "inserted $parentid - " . $parentid . " title: " . $title . "\n"; } ?>

    Read the article

< Previous Page | 22 23 24 25 26 27 28 29 30 31 32 33  | Next Page >