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  • Implementation of a distance matrix of a binary tree that is given in the adjacency-list representation

    - by Denise Giubilei
    Given this problem I need an O(n²) implementation of this algorithm: "Let v be an arbitrary leaf in a binary tree T, and w be the only vertex connected to v. If we remove v, we are left with a smaller tree T'. The distance between v and any vertex u in T' is 1 plus the distance between w and u." This is a problem and solution of a Manber's exercise (Exercise 5.12 from U. Manber, Algorithms: A Creative Approach, Addison-Wesley (1989).). The thing is that I can't deal properly with the adjacency-list representation so that the implementation of this algorithm results in a real O(n²) complexity. Any ideas of how the implementation should be? Thanks.

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  • make a tree based on the key of each element in list.

    - by cocobear
    >>> s [{'000000': [['apple', 'pear']]}, {'100000': ['good', 'bad']}, {'200000': ['yeah', 'ogg']}, {'300000': [['foo', 'foo']]}, {'310000': [['#'], ['#']]}, {'320000': ['$', ['1']]}, {'321000': [['abc', 'abc']]}, {'322000': [['#'], ['#']]}, {'400000': [['yeah', 'baby']]}] >>> for i in s: ... print i ... {'000000': [['apple', 'pear']]} {'100000': ['good', 'bad']} {'200000': ['yeah', 'ogg']} {'300000': [['foo', 'foo']]} {'310000': [['#'], ['#']]} {'320000': ['$', ['1']]} {'321000': [['abc', 'abc']]} {'322000': [['#'], ['#']]} {'400000': [['yeah', 'baby']]} i want to make a tree based on the key of each element in list. result in logic will be: {'000000': [['apple', 'pear']]} {'100000': ['good', 'bad']} {'200000': ['yeah', 'ogg']} {'300000': [['foo', 'foo']]} {'310000': [['#'], ['#']]} {'320000': ['$', ['1']]} {'321000': [['abc', 'abc']]} {'322000': [['#'], ['#']]} {'400000': [['yeah', 'baby']]} perhaps a nested list can implement this or I need a tree type?

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  • Manage more Images to move in View

    - by David Pollak
    hi everyone, I'm creating an app which has more UIImageView on a View, they should move normally from a side to the other. I have an issue: after entering the second image, the two UIImageView start to behave crazy (!) because they don' move freely, but they are like restricted in two different areas not touching each other even if I said different things the first thing that I want to do, is to let them move normally; this is the code I am using: `- (void)viewDidLoad { [super viewDidLoad]; pos = CGPointMake(14.0, 7.0); [NSTimer scheduledTimerWithTimeInterval:0.05 target:self selector:@selector(onTimer) userInfo:nil repeats:YES]; }` - (void) onTimer { pallone.center = CGPointMake(pallone.center.x+pos.x, pallone.center.y+pos.y); if(pallone.center.x > 320 || pallone.center.x < 0) pos.x = -pos.x; if(pallone.center.y > 480 || pallone.center.y < 0) pos.y = -pos.y; } and for the other image that has to enter after: - (IBAction)spara{ cos = CGPointMake(8.0, 4.0); [NSTimer scheduledTimerWithTimeInterval:0.05 target:self selector:@selector(inTimer) userInfo:nil repeats:YES]; } - (void)inTimer{ bomba.center = CGPointMake(bomba.center.x+pos.x, bomba.center.y+pos.y); if(bomba.center.x > 50 || bomba.center.x < 0) pos.x = -pos.x; if(bomba.center.y > 480 || bomba.center.y < 0) pos.y = -pos.y; } what should I change ? and if I'd like the images to move only in one way (y) ? how do I do this ? I know, I'm a newbie thanks in advance

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  • What do I do with a Concrete Syntax Tree?

    - by Cap
    I'm using pyPEG to create a parse tree for a simple grammar. The tree is represented using lists and tuples. Here's an example: [('command', [('directives', [('directive', [('name', 'retrieve')]), ('directive', [('name', 'commit')])]), ('filename', [('name', 'f30502')])])] My question is what do I do with it at this point? I know a lot depends on what I am trying to do, but I haven't been able to find much about consuming/using parse trees, only creating them. Does anyone have any pointers to references I might use? Thanks for your help.

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  • Black Screen: How to set Projection/View Matrix

    - by Lisa
    I have a Windows Phone 8 C#/XAML with DirectX component project. I'm rendering some particles, but each particle is a rectangle versus a square (as I've set the vertices to be positions equally offset from each other). I used an Identity matrix in the view and projection matrix. I decided to add the windows aspect ratio to prevent the rectangles. But now I get a black screen. None of the particles are rendered now. I don't know what's wrong with my matrices. Can anyone see the problem? These are the default matrices in Microsoft's project example. View Matrix: XMVECTOR eye = XMVectorSet(0.0f, 0.7f, 1.5f, 0.0f); XMVECTOR at = XMVectorSet(0.0f, -0.1f, 0.0f, 0.0f); XMVECTOR up = XMVectorSet(0.0f, 1.0f, 0.0f, 0.0f); XMStoreFloat4x4(&m_constantBufferData.view, XMMatrixTranspose(XMMatrixLookAtRH(eye, at, up))); Projection Matrix: void CubeRenderer::CreateWindowSizeDependentResources() { Direct3DBase::CreateWindowSizeDependentResources(); float aspectRatio = m_windowBounds.Width / m_windowBounds.Height; float fovAngleY = 70.0f * XM_PI / 180.0f; if (aspectRatio < 1.0f) { fovAngleY /= aspectRatio; } XMStoreFloat4x4(&m_constantBufferData.projection, XMMatrixTranspose(XMMatrixPerspectiveFovRH(fovAngleY, aspectRatio, 0.01f, 100.0f))); } I've tried modifying them to use cocos2dx's WP8 example. XMMATRIX identityMatrix = XMMatrixIdentity(); float fovy = 60.0f; float aspect = m_windowBounds.Width / m_windowBounds.Height; float zNear = 0.1f; float zFar = 100.0f; float xmin, xmax, ymin, ymax; ymax = zNear * tanf(fovy * XM_PI / 360); ymin = -ymax; xmin = ymin * aspect; xmax = ymax * aspect; XMMATRIX tmpMatrix = XMMatrixPerspectiveOffCenterRH(xmin, xmax, ymin, ymax, zNear, zFar); XMMATRIX projectionMatrix = XMMatrixMultiply(tmpMatrix, identityMatrix); // View Matrix float fEyeX = m_windowBounds.Width * 0.5f; float fEyeY = m_windowBounds.Height * 0.5f; float fEyeZ = m_windowBounds.Height / 1.1566f; float fLookAtX = m_windowBounds.Width * 0.5f; float fLookAtY = m_windowBounds.Height * 0.5f; float fLookAtZ = 0.0f; float fUpX = 0.0f; float fUpY = 1.0f; float fUpZ = 0.0f; XMMATRIX tmpMatrix2 = XMMatrixLookAtRH(XMVectorSet(fEyeX,fEyeY,fEyeZ,0.f), XMVectorSet(fLookAtX,fLookAtY,fLookAtZ,0.f), XMVectorSet(fUpX,fUpY,fUpZ,0.f)); XMMATRIX viewMatrix = XMMatrixMultiply(tmpMatrix2, identityMatrix); XMStoreFloat4x4(&m_constantBufferData.view, viewMatrix); Vertex Shader cbuffer ModelViewProjectionConstantBuffer : register(b0) { //matrix model; matrix view; matrix projection; }; struct VertexInputType { float4 position : POSITION; float2 tex : TEXCOORD0; float4 color : COLOR; }; struct PixelInputType { float4 position : SV_POSITION; float2 tex : TEXCOORD0; float4 color : COLOR; }; PixelInputType main(VertexInputType input) { PixelInputType output; // Change the position vector to be 4 units for proper matrix calculations. input.position.w = 1.0f; //===================================== // TODO: ADDED for testing input.position.z = 0.0f; //===================================== // Calculate the position of the vertex against the world, view, and projection matrices. //output.position = mul(input.position, model); output.position = mul(input.position, view); output.position = mul(output.position, projection); // Store the texture coordinates for the pixel shader. output.tex = input.tex; // Store the particle color for the pixel shader. output.color = input.color; return output; } Before I render the shader, I set the view/projection matrices into the constant buffer void ParticleRenderer::SetShaderParameters() { ViewProjectionConstantBuffer* dataPtr; D3D11_MAPPED_SUBRESOURCE mappedResource; DX::ThrowIfFailed(m_d3dContext->Map(m_constantBuffer.Get(), 0, D3D11_MAP_WRITE_DISCARD, 0, &mappedResource)); dataPtr = (ViewProjectionConstantBuffer*)mappedResource.pData; dataPtr->view = m_constantBufferData.view; dataPtr->projection = m_constantBufferData.projection; m_d3dContext->Unmap(m_constantBuffer.Get(), 0); // Now set the constant buffer in the vertex shader with the updated values. m_d3dContext->VSSetConstantBuffers(0, 1, m_constantBuffer.GetAddressOf() ); // Set shader texture resource in the pixel shader. m_d3dContext->PSSetShaderResources(0, 1, &m_textureView); } Nothing, black screen... I tried so many different look at, eye, and up vectors. I tried transposing the matrices. I've set the particle center position to always be (0, 0, 0), I tried different positions too, just to make sure they're not being rendered offscreen.

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  • How to redirect user to another page from view after it was loaded is ASP .NET MVC?

    - by Dmytro Tsiniavsky
    For example I have some view with action link: @Html.ActionLink("Action", "Controller") Action action returns some view: public ActionResult Action() { string someModelForView = "some url i need to redirect after view was fully loaded"; return View("SomeView", someModelForView); } What I need is to redirect user to url, defined in someModelForView model after view was fully loaded, and all javascripts on this page were executed. This view might be empty, without any content, I just need to execute some javascript, and after that redirect user to external page. How can accomplish that?

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  • View Your Google Calendar in Outlook 2010

    - by Mysticgeek
    Google Calendar is a great way to share appointments, and synchronize your schedule with others. Here we show you how to view your Google Calendar in Outlook 2010 too. Google Calendar Log into the Google Calendar and under My Calendars click on Settings. Now click on the calendar you want to view in Outlook. Scroll down the page and click on the ICAL button from the Private Address section, or Calendar Address if it’s a public calendar…then copy the address to your clipboard. Outlook 2010 Open up your Outlook calendar, click the Home tab on the Ribbon, and under Manage Calendars click on Open Calendar \ From Internet… Now enter the link location into the New Internet Calendar field then click OK. Click Yes to the dialog box that comes up verifying you want to subscribe to it.   If you want more subscription options click on the Advanced button. Here you can name the folder, type in a description, and choose if you want to download attachments. That is all there is to it! Now you will be able to view your Google Calendar in Outlook 2010. You’ll also be able to view your local computer and the Google Calendar side by side… Keep in mind that this only gives you the ability to view the Google Calendar…it’s read-only. Any changes you make on the Google Calendar site will show up when you do a send/receive. If live out of Outlook during the day, you might want the ability to view what is going on with your Google Calendar(s) as well. If you’re an Outlook 2007 user, check out our article on how to view your Google Calendar in Outlook 2007. Similar Articles Productive Geek Tips View Your Google Calendar in Outlook 2007Overlay Calendars in Outlook 2007 (like Google Calendar does)Sync Your Outlook and Google Calendar with Google Calendar SyncDisplay your Google Calendar in Windows CalendarEasily Add All Holidays To The Calendar in Outlook 2003 TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Xobni Plus for Outlook All My Movies 5.9 CloudBerry Online Backup 1.5 for Windows Home Server Snagit 10 Create More Bookmark Toolbars in Firefox Easily Filevo is a Cool File Hosting & Sharing Site Get a free copy of WinUtilities Pro 2010 World Cup Schedule Boot Snooze – Reboot and then Standby or Hibernate Customize Everything Related to Dates, Times, Currency and Measurement in Windows 7

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  • Routing to a Controller with no View in Angular

    - by Rick Strahl
    Angular provides a nice routing, and controller to view model that makes it easy to create sophisticated JavaScript views fairly easily. But Angular's views are destroyed and re-rendered each time they are activated - what if you need to work with a persisted view that's too expensive to re-render? Here's how to build a headless controller that doesn't render a view through Angular, but rather manages the the view or markup manually.

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  • minimax depth first search game tree

    - by Arvind
    Hi I want to build a game tree for nine men's morris game. I want to apply minimax algorithm on the tree for doing node evaluations. Minimax uses DFS to evaluate nodes. So should I build the tree first upto a given depth and then apply minimax or can the process of building the tree and evaluation occur together in recursive minimax DFS? Thank you Arvind

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  • How do you display a binary search tree?

    - by fakeit
    I'm being asked to display a binary search tree in sorted order. The nodes of the tree contain strings. I'm not exactly sure what the best way is to attack this problem. Should I be traversing the tree and displaying as I go? Should I flatten the tree into an array and then use a sorting algorithm before I display? I'm not looking for the actual code, just a guide where to go next.

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  • Maintaing list order in binary tree.

    - by TheBigO
    Given a sequence of numbers, I want to insert the numbers into a balanced binary tree such that when I do a preorder traversal on the tree, it gives me the sequence back. How can I construct the insert method corresponding to this requirement? Remember that the tree must be balanced, so there isn't a completely trivial solution. I was trying to do this with a modified version of an AVL tree, but I'm not sure if this can work out.

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  • Convert a post-order binary tree traversal index to an level-order (breadth-first) index

    - by strfry
    Assuming a complete binary tree, each node can be adressed with the position it appears in a given tree traversal algorithm. For example, the node indices of a simple complete tree with height 3 would look like this: breadth first (aka level-order): 0 / \ 1 2 / \ / \ 3 4 5 6 post-order dept first: 6 / \ 2 5 / \ / \ 0 1 3 4 The height of the tree and an index in the post-order traversal is given. How can i calculate the breadth first index from this information?

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  • Cladogram, tree of life, cladistics, taxonomy in JS or canvas?

    - by boblet
    Good people - I need some help to find a way to create an interactive cladogram or phylogenetic tree (yes, I have read all related posts, and do not find what I am looking for). The thing is, I need the nodes to be name-able. An example would be something like this Most scripts I find are either applets, flash, or simply do not show the node classification, ie it would skip "feliformia" in this example. This is useless to me, as I would then end up with carnivore - anonymous node - anonymous node - anonymous node - tiger, and that is not good. This tree will in theory cover all life, so it could get rather large, and get links and names in english and latin from database. So: no flash, no applets. It must be horizontal, no supertrees (circular). I have gone through this http://bioinfo.unice.fr/biodiv/Tree_editors.html but most of them seems to be either old, not displaying sub-node levels, applets, or way too complex. I imagine this would be a delightful job for canvas/jQuery..? And chances are, someone got there before me? Any pointers much appreciated. Note: if anyone out there would like to do something like this as a project, I will be happy to help, even though it would not benefit me for this project.This type of taxonomy is not as simple as it may seem, and I would be happy see this happen.

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  • How can you get the call tree with python profilers?

    - by Oliver
    I used to use a nice Apple profiler that is built into the System Monitor application. As long as your C++ code was compiled with debug information, you could sample your running application and it would print out an indented tree telling you what percent of the parent function's time was spent in this function (and the body vs. other function calls). For instance, if main called function_1 and function_2, function_2 calls function_3, and then main calls function_3: main (100%, 1% in function body): function_1 (9%, 9% in function body): function_2 (90%, 85% in function body): function_3 (100%, 100% in function body) function_3 (1%, 1% in function body) I would see this and think, "Something is taking a long time in the code in the body of function_2. If I want my program to be faster, that's where I should start." Does anyone know how I can most easily get this exact profiling output for a python program? I've seen people say to do this: import cProfile, pstats prof = cProfile.Profile() prof = prof.runctx("real_main(argv)", globals(), locals()) stats = pstats.Stats(prof) stats.sort_stats("time") # Or cumulative stats.print_stats(80) # 80 = how many to print but it's quite messy compared to that elegant call tree. Please let me know if you can easily do this, it would help quite a bit. Cheers!

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  • Two view App with root template view

    - by Tieman
    Hi I was wanted to do Application witch have a root template view with a nice logo on top or something adn load other views just below (here is what I have right now: Test App ) But I have a little problem. If I'll remove a comment in file TestAppDelegate.m on line 58 //[currentView release]; Application will crash with bunch of errors when I try to switch views. But if I comment this line Project analyzer is telling me that I have a potential leak with currentView variable. Can somebody spare some time and see in that code what I did wrong?

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  • A data structure based on the R-Tree: creating new child nodes when a node is full, but what if I ha

    - by Tom
    I realize my title is not very clear, but I am having trouble thinking of a better one. If anyone wants to correct it, please do. I'm developing a data structure for my 2 dimensional game with an infinite universe. The data structure is based on a simple (!) node/leaf system, like the R-Tree. This is the basic concept: you set howmany childs you want a node (a container) to have maximum. If you want to add a leaf, but the node the leaf should be in is full, then it will create a new set of nodes within this node and move all current leafs to their new (more exact) node. This way, very populated areas will have a lot more subdivisions than a very big but rarely visited area. This works for normal objects. The only problem arises when I have more than maxChildsPerNode objects with the exact same X,Y location: because the node is full, it will create more exact subnodes, but the old leafs will all be put in the exact same node again because they have the exact same position -- resulting in an infinite loop of creating more nodes and more nodes. So, what should I do when I want to add more leafs than maxChildsPerNode with the exact same position to my tree? PS. if I failed to explain my problem, please tell me, so I can try to improve the explanation.

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  • Map problem when passing it as model to view in grails

    - by xain
    Hi, In a controller, I have populated a map that has a string as key and a list as value; in the gsp, I try to show them like this: <g:each in="${sector}" var="entry" > <br/>${entry.key}<br/> <g:each in="${entry.value}" var="item" > ${item.name}<br/> </g:each> </g:each> The problem is that item is considered as string, so I get the exception Error 500: Error evaluating expression [item.name] on line [11]: groovy.lang.MissingPropertyException: No such property: nombre for class: java.lang.String Any hints on how to fix it other than doing the find for the item explicitly in the gsp ?

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  • Eclipse Outline View - Visible JavaScript Categories in Eclipse?

    - by leeand00
    I just found an option in the little white down arrow in Eclipse that reads "Visible Categories..." How can I use this? It seems to me that it could be used to only show functions that have an @category in their comments, but I haven't been able to make that work. If it did work it would be incredibly useful for separating out Unit Tests from their common-functions and separating them from the setUp and tearDown methods, so what is it really for? By the way I'm editing a Javascript file in the Eclipse "Javascript Editor", I don't know if that makes any difference or not.

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  • Android Custom View Constructor

    - by Mitch
    I'm learning about using Custom Views from the following: http://developer.android.com/guide/topics/ui/custom-components.html#modifying The description says: Class Initialization As always, the super is called first. Furthermore, this is not a default constructor, but a parameterized one. The EditText is created with these parameters when it is inflated from an XML layout file, thus, our constructor needs to both take them and pass them to the superclass constructor as well. Is there a better description? I've been trying to figure out what the constructor(s) should look like and I've come up with 4 possible choices (see example at end of post). I'm not sure what these 4 choices do (or don't do), why I should implement them, or what the parameters mean. Is there a description of these? Thanks. Mitch public MyCustomView() { super(); } public MyCustomView(Context context) { super(context); } public MyCustomView(Context context, AttributeSet attrs) { super(context, attrs); } public MyCustomView(Context context, AttributeSet attrs, Map params) { super(context, attrs, params); }

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  • Integrate IPhone Safari like view in Android?

    - by sunil
    The main concept goes like this. I have four listviews with its own data loaded at the same time. Only one listview will be visible to the user. Now, when the user presses a button, not only the current listview but also other three listviews should be minimized and then user can just scroll just as in Gallery and select the listview that one wants to open. I hope you all have understood what I want. Let me know if someone have some idea of implementing such a User Interface in Android. Thanks & Regards Sunil

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  • ASP.NET MVC Newbie: why isn't my model available when creating a strongly-typed view?

    - by Rax Olgud
    I'm starting with ASP.NET MVC, and working with NerdDinner as reference. I did the following: Created a new project Added a couple of tables Created LINQ to SQL for them Created a new controller My Models directory now contains MyModel.dbml, under which I have MyModel.designer.cs, that contains classes for models relating to both of my tables (let's call them Categories and Products). Now, under my new controller, I would like to create a strongly typed view. So for example I have the following code in my controller (for my application I must work by name, and the "Name" field is unique): public ActionResult Details(string name) { MyModelDataContext db = new MyModelDataContext(); Product user = db.Products.Single(t => t.Name == name); return View(user); } I would like to create a strongly-typed view. So I right-click the line "return View(user)", and choose "Add View...". I click "Create a strongly-typed view". When I click the dropdown of "View data class", I don't see my models, but only: MyProject.Controllers.AccountMembershipService MyProject.Controllers.FormsAuthenticationService What am I missing?

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  • avoid preselection of a view when focus is gained android

    - by Sephy
    Hi all, I don't know if the title is very clear, but my issue is as follows : I have an activity with a listview, and on top of this listview, i have a searchfield (edittext). The issue is that when i try debugging on a phone, the virtual keyboard gets out straight after the screen displays the activity... And of course, it's hidding half of the list... So, is there an attribute or something I can use to prevent this from happening?(I still want to keybord to appear when i click the edittext though...) thank you

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