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  • bash script to find/grep particular string in xml files in particular folders

    - by user3702188
    i have a problem at work, where i need to simplify the process how i searrh for logs. I would like to ask for help from experts here. We have different services for every channel. The structure is following: - root/channel_1/service_1/2014-05-21/file_54544654541.xml - root/channel_1/server2_2/2014-05-20/file_74272172.xml - root/channel_1/service_3/2014-05-22/file_45456546.xml - root/channel_2/service_4/2014-05-23/file_78754456.xml - root/channel_2/service_5/2014-05-24/file_546546546.xml my main problem is to find particular string in these xml files. Lets say, i know the channel name but i dont know the service name under which my particular string should be present. Also i know the date. So in search i want to enter the channel name the date and string. The search would be going via all service folders and looking for string only in all xml files under particular date folder and particular channel. any ideas for quickest and easiest solution to achieve this? Either by bash or perl? Any help would be appreciated thanks

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  • There is an error in XML document... When calling to web service

    - by Sigurjón Guðbergsson
    I have created a web service and a function in it that should return a list of 11thousand records retreived from a pervasive database Here is my function in the web service. [WebService(Namespace = "http://tempuri.org/")] [WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)] [System.ComponentModel.ToolboxItem(false)] public class BBI : System.Web.Services.WebService { [WebMethod] public List<myObject> getAll() { List<myObject> result = new List<myObject>(); PsqlConnection conn = new PsqlConnection("Host=soemthing;Port=something;Database=something;Encoding=IBM861"); conn.Open(); string strSql = "select 0, 1, 2, 3, 4, 5 from something"; PsqlCommand DBCmd = new PsqlCommand(strSql, conn); PsqlDataReader myDataReader; myDataReader = DBCmd.ExecuteReader(); while (myDataReader.Read()) { myObject b = new myObject(); b.0 = Convert.ToInt32(myDataReader[0].ToString()); b.1 = myDataReader[1].ToString(); b.2 = myDataReader[2].ToString(); b.3 = myDataReader[3].ToString(); b.4 = myDataReader[4].ToString(); b.5 = myDataReader[5].ToString(); result.Add(b); } conn.Close(); myDataReader.Close(); return result; } } Then i add web reference to this web service in my client program and call the reference BBI. Then i call to the getAll function and get the error : There is an error in XML document (1, 63432). public List<BBI.myObject> getAll() { BBI.BBI bbi = new BBI.BBI(); List<BBI.myObject> allBooks = bbi.getAll().OfType<BBI.myObject>().ToList(); return allBooks; } Here is the total exception detail System.InvalidOperationException was unhandled by user code Message=There is an error in XML document (1, 71897). Source=System.Xml StackTrace: at System.Xml.Serialization.XmlSerializer.Deserialize(XmlReader xmlReader, String encodingStyle, XmlDeserializationEvents events) at System.Xml.Serialization.XmlSerializer.Deserialize(XmlReader xmlReader, String encodingStyle) at System.Web.Services.Protocols.SoapHttpClientProtocol.ReadResponse(SoapClientMessage message, WebResponse response, Stream responseStream, Boolean asyncCall) at System.Web.Services.Protocols.SoapHttpClientProtocol.Invoke(String methodName, Object[] parameters) at BBI.BBI.getAllBooks() in c:\WINDOWS\Microsoft.NET\Framework\v4.0.30319\Temporary ASP.NET Files\vefur\73db60db\a4ee31dd\App_WebReferences.jl1r8jv6.0.cs:line 252 at webServiceFuncions.getAllBooks() in c:\Documents and Settings\forritari\Desktop\Vefur - Nýr\BBI\trunk\Vefur\App_Code\webServiceFuncions.cs:line 59 InnerException: System.Xml.XmlException Message='', hexadecimal value 0x01, is an invalid character. Line 1, position 71897. Source=System.Xml LineNumber=1 LinePosition=71897 SourceUri="" StackTrace: at System.Xml.XmlTextReaderImpl.Throw(Exception e) at System.Xml.XmlTextReaderImpl.Throw(String res, String[] args) at System.Xml.XmlTextReaderImpl.Throw(Int32 pos, String res, String[] args) at System.Xml.XmlTextReaderImpl.ParseNumericCharRefInline(Int32 startPos, Boolean expand, StringBuilder internalSubsetBuilder, Int32& charCount, EntityType& entityType) at System.Xml.XmlTextReaderImpl.ParseCharRefInline(Int32 startPos, Int32& charCount, EntityType& entityType) at System.Xml.XmlTextReaderImpl.ParseText(Int32& startPos, Int32& endPos, Int32& outOrChars) at System.Xml.XmlTextReaderImpl.ParseText() at System.Xml.XmlTextReaderImpl.ParseElementContent() at System.Xml.XmlTextReaderImpl.Read() at System.Xml.XmlTextReader.Read() at System.Xml.XmlReader.ReadElementString() at Microsoft.Xml.Serialization.GeneratedAssembly.XmlSerializationReaderBBI.Read2_Book(Boolean isNullable, Boolean checkType) at Microsoft.Xml.Serialization.GeneratedAssembly.XmlSerializationReaderBBI.Read20_getAllBooksResponse() at Microsoft.Xml.Serialization.GeneratedAssembly.ArrayOfObjectSerializer35.Deserialize(XmlSerializationReader reader) at System.Xml.Serialization.XmlSerializer.Deserialize(XmlReader xmlReader, String encodingStyle, XmlDeserializationEvents events) InnerException: The database records are containing all kind of strange symbols, for example ¤rmann Kr. Einarsson and Tv” ‘fint˜ri Can someone see what im doing wrong here?

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  • Setting XSL-FO XML Schema in Visual Studio

    - by Lukasz Kurylo
    I'm playing lately with an XSL-FO for generating a pdf documents. XSL-FO has a long list of available tags and attributes, which for a new guy who want to create a simple document is a nightmare to find a proper one. Fortunatelly we can set an schema for XSL-FO, so will result in acquire a full intellisense in VS. For a simple *.fo file, we can set the path to the schema directly in file: <?xml version="1.0" encoding="utf-8"?> <fo:root       xmlns:fo="http://www.w3.org/1999/XSL/Format"       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"       xsi:schemaLocation=" http://www.w3.org/1999/XSL/Format http://www.xmlblueprint.com/documents/fop.xsd"> ...   We can of course use the build in VS XML Schemas selector. To use it, we must copy the schema file to the Schemas catalog (defaut path for VS2012 is C:\Program Files (x86)\Microsoft Visual Studio 11.0\Xml\Schemas). Then we can go to Properties of the opened xml/xslt file and set the new added schema to file:                 From now, we should have an enable intellisense as shown below: .

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  • How to visualize an XML schema ?

    - by matt
    I have made an XML Schema - all the code basically - and was wondering if there is a way that the code can generate something like this: http://www.novell.com/documentation/extend52/Docs/help/Director/books/PGImages/novell_portlet_xml_schema.gif If so how can I do it?

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  • Where to locate the unattend.xml schema

    - by Adam Driscoll
    I'm in need of a way to modify an unattend.xml file programmatically. It would be great if I could just serialize to and from an object. But to do so I would need to get a hold of the schema so that I can run it through XSD. The referenced link provides all the possible settings but it would be nice to have it in XSD format. Any ideas?

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  • xml schema ........

    - by matt
    ive made an xml schema all the code basically and was wonder is there a way that the code genarates something like this http://www.novell.com/documentation/extend52/Docs/help/Director/books/PGImages/novell_portlet_xml_schema.gif and if i can then how do you do it?

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  • JAXB adding namespace to parent but not to the child elements contained

    - by Nishant
    I put together an XSD and used JAXB to generate classes out of it. Here are my XSDs- myDoc.xsd : <?xml version="1.0" encoding="UTF-8"?> <xs:schema xmlns="http://www.mydoc.org" targetNamespace="http://www.mydoc.org" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:mtp="http://www.mytypes.com" elementFormDefault="qualified"> <xs:import namespace="http://www.mytypes.com" schemaLocation="mytypes.xsd" /> <xs:element name="myDoc"> <xs:complexType> <xs:sequence> <xs:element name="crap" type="xs:string"/> <xs:element ref="mtp:foo"/> <xs:element ref="mtp:bar"/> </xs:sequence> </xs:complexType> </xs:element> mytypes.xsd <?xml version="1.0" encoding="UTF-8"?> <xs:schema targetNamespace="http://www.mytypes.com" xmlns="http://www.mytypes.com" xmlns:tns="http://www.mytypes.com" xmlns:xs="http://www.w3.org/2001/XMLSchema" attributeFormDefault="qualified" elementFormDefault="qualified"> <xs:element name="foo" type="tns:Foo"/> <xs:element name="bar" type="tns:Bar"/> <xs:element name="spam" type="tns:Spam"/> <xs:simpleType name="Foo"> <xs:restriction base="xs:string"></xs:restriction> </xs:simpleType> <xs:complexType name="Bar"> <xs:sequence> <xs:element ref="spam"/> </xs:sequence> </xs:complexType> <xs:simpleType name="Spam"> <xs:restriction base="xs:string" /> </xs:simpleType> </xs:schema> The document marshalled is- <?xml version="1.0" encoding="UTF-8" standalone="yes"?> <myDoc xmlns:ns2="http://www.mytypes.com"> <crap>real crap</crap> <ns2:foo>bleh</ns2:foo> <ns2:bar> <spam>blah</spam> </ns2:bar> </myDoc> Note that the <spam> element uses the default namespace. I would like it to use the ns2 namespace. The schema (mytypes.xsd) expresses the fact that <spam> is contained within <bar> which in the XML instance is bound to the ns2 namespace. I've broken my head over this for over a week and I would like ns2 prefix to appear in <spam>. What should I do? Required : <?xml version="1.0" encoding="UTF-8" standalone="yes"?> <myDoc xmlns:ns2="http://www.mytypes.com"> <crap>real crap</crap> <ns2:foo>bleh</ns2:foo> <ns2:bar> <ns2:spam>blah</ns2:spam><!--NS NS NS--> </ns2:bar> </myDoc>

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  • Subsonic - How to use SQL Schema / Owner name as part of the namespace?

    - by CResults
    Hi there, I've just started using Subsonic 2.2 and so far very impressed - think it'll save me some serious coding time. Before I dive into using it full time though there is something bugging me that I'd like to sort out. In my current database (a SQL2008 db) I have split the tables, views, sps etc. up into separate chunks by schema/owner name, so all the customer tables are in the customer. schema, products in the product. schema etc., so a to select from the customers address table i'd do a select * from customer.address Unfortunately, Subsonic ignores the schema/owner name and just gives me the base table name. This is fine as I've no duplicates between schemas (e.g Customer.Address and Supplier.Address don't both exist) but I just feel the code could be clearer if I could split by schema. Ideally I'd like to be able to alter the namespace by schema/owner - I think this would have least impact on SubSonic yet make the resulting code easier to read. Problem is, I've crawled all over the Subsonic source and don't have a clue how to do this (doesn't help that I code in VB not C# = yes I know, blame the ZX Spectrum!!) If anyone has tackled this before or has an idea on how to solve it, I'd be really grateful, Thanks in advance. Ed

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  • C# Windows Service XML

    - by Goober
    Scenario I have a windows service written in C# that performs some processing based on parsing an XML file and use that data to carry out various tasks. The service also does various bits of logging - which uses settings from an APP.Config file. The Problem When the service is compiled, installed and run, the XML file seems to disappear. I'm getting the impression that it is just ignored or something like that. So far I've tried using TWO App.Config files, one named App.Config that contains settings for the service, and the other called MyService.exe.config that contains all of the data that was used in the XML file (the idea being that I can parse the XML from a config file that actually gets compiled and appears in my installation directory. However When I do this, all that happens is that ONE config file appears (with the name MyService.exe.config), but it contains the contents of the App.Config file and not the XML data that I want to parse. What I need All I want is to have a config file for my settings, and an XML file for my data. Question Is this possible? I know the application works as it was originally built as a console application that ran fine. Other The application has to be designed this way (as in, I need my data stored as XML, and my settings stored in a config file). Thoughts If I could somehow combine the contents of the two files into ONE config file, that would be one way of solving the problem. However, I have tried this and of course I get a "Type Initialisation Exception", as the config file cannot interprate the XML data (probably because the tags are custom and do not form any part of the config schema - or something like that). Ideas Please could someone explain to me if it is possible for me to have an XML file AND a config file that will actually be compiled and stored in my installation directory for the service when it is run? CODE Custom XML/Data Config File <?xml version="1.0" encoding="utf-8" ?> <configuration> <servers> <SV066930> <add name="Name" value = "SV066930" /> <processes> <SimonTest1> <add name="ProcessName" value="notepad.exe" /> <add name="CommandLine" value="C:\\WINDOWS\\system32\\notepad.exe C:\\WINDOWS\\Profiles\\TA2TOF1\\Desktop\\SimonTest1.txt" /> </SimonTest1> </processes> </SV066930> </servers> </configuration> APP.Config Settings File <?xml version="1.0" encoding="utf-8" ?> <configuration> <configSections> <section name="dataConfiguration" type="Microsoft.Practices.EnterpriseLibrary.Data.Configuration.DatabaseSettings, Microsoft.Practices.EnterpriseLibrary.Data, Version=4.0.0.0, Culture=neutral, PublicKeyToken=xxxxxxxxxxx" /> </configSections> <connectionStrings> <add name="DB" connectionString="Data Source=etc......" /> </connectionStrings> </configuration> Help greatly appreciated.

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  • Converting XML to RSS

    - by hkw
    I've got an xml feed that will be published in one location of our website, and would like to repurpose that for an RSS feed. A few different pages on the website will also be referencing the same xml - all of those transformations are set up and working. The base xml file (XMLTEST.xml) is using this structure: <POST> <item> <POST_ID>80000852</POST_ID> <POST_TITLE>title</POST_TITLE> <POST_CHANNEL>I</POST_CHANNEL> <POST_DESC>description</POST_DESC> <LINK>http://www...</LINK> <STOC>N</STOC> </item> </POST> I'm trying to transform the xml into an RSS feed using the following setup (feed.xml + rss.xsl) feed.xml: <?xml-stylesheet href="rss.xsl" type="text/xsl"?> <RSSChannels> <RSSChannel src="XMLTEST.xml"/> </RSSChannels> rss.xsl: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" omit-xml-declaration="yes" /> <xsl:template match="RSSChannels"> <rss version="2.0"> <channel> <title>site title</title> <link></link> <description>Site description...</description> <xsl:apply-templates /> </channel> </rss> </xsl:template> <xsl:template match="RSSChannel"> <xsl:apply-templates select="document(@src)" /> </xsl:template> <xsl:template match="item"> <xsl:choose> <xsl:when test="STOC = 'Y'"></xsl:when> <xsl:when test="POST_CHANNEL = 'I'"></xsl:when> <xsl:otherwise> <item> <title> <xsl:value-of select="*[local-name()='POST_TITLE']" /> </title> <link> <xsl:value-of select="*[local-name()='LINK']" /> </link> <description> <xsl:value-of select="*[local-name()='POST_DESC']" /> </description> </item> </xsl:otherwise> </xsl:choose> </xsl:template> </xsl:stylesheet> When I try to view the output of feed.xml in Firefox, all of the filtering is applied correctly (sorting out items that shouldn't be published in that channel), but the page outputs as plain text, rather than the usual feed-detection that takes place in Firefox. Any ideas on what I'm missing? Thanks for any suggestions you can provide.

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  • What is the correct high level schema.org microdata itemtype for a retail brand/company homepage?

    - by kpowz
    I'd like to hear which schema.org itemtype others would recommend using or have used in the case of completing a retail brand's company homepage microdata. Take for example TOMS's shoes: Example #1 - Using /Corporation as the high-level itemtype one can include a lot of great /Organization microdata, but nothing about the retail store. <html itemscope='itemscope' itemtype="http://schema.org/Website> <head></head> <body itemscope='itemscope' itemtype="http://schema.org/Corporation> various microdata here probably including Product microdata </body> </html> NOTE: the only schema.org property specific to /Corporation is tickerSymbol & TOMS doesn't have one. Example #2 - This code would work if TOMS started their own channel of physical retail stores & each location had it's own homepage. However, for TOMS's.com, although accurate schematically & more descriptive at the face, this is incorrect microdata markup for TOMS.com, because /ShoeStore derives from /LocalBusiness - which must represent a physical place. <html itemscope='itemscope' itemtype='http://schema.org/Website'> <head></head> <body itemscope='itemscope' itemtype='http://schema.org/ShoeStore'> a whole bunch of jabber here </body> </html> NOTE: Since TOMS is virtual & thus can't be a /Store this means you lose really cool properties like 'currenciesAccepted', 'paymentAccepted' & 'priceRange'. Is this just a 'sit and wait' situation until more schemas are approved for 'virtual places' or is there a validation-passing way to get the best of both worlds?

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  • JAXB adding namespace to parent but not to the child elements contained

    - by Nishant
    I put together an XSD and used JAXB to generate classes out of it. Here are my XSDs- myDoc.xsd : <?xml version="1.0" encoding="UTF-8"?> <xs:schema xmlns="http://www.mydoc.org" targetNamespace="http://www.mydoc.org" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:mtp="http://www.mytypes.com" elementFormDefault="qualified"> <xs:import namespace="http://www.mytypes.com" schemaLocation="mytypes.xsd" /> <xs:element name="myDoc"> <xs:complexType> <xs:sequence> <xs:element name="crap" type="xs:string"/> <xs:element ref="mtp:foo"/> <xs:element ref="mtp:bar"/> </xs:sequence> </xs:complexType> </xs:element> mytypes.xsd <?xml version="1.0" encoding="UTF-8"?> <xs:schema targetNamespace="http://www.mytypes.com" xmlns="http://www.mytypes.com" xmlns:tns="http://www.mytypes.com" xmlns:xs="http://www.w3.org/2001/XMLSchema" attributeFormDefault="qualified" elementFormDefault="qualified"> <xs:element name="foo" type="tns:Foo"/> <xs:element name="bar" type="tns:Bar"/> <xs:element name="spam" type="tns:Spam"/> <xs:simpleType name="Foo"> <xs:restriction base="xs:string"></xs:restriction> </xs:simpleType> <xs:complexType name="Bar"> <xs:sequence> <xs:element ref="spam"/> </xs:sequence> </xs:complexType> <xs:simpleType name="Spam"> <xs:restriction base="xs:string" /> </xs:simpleType> </xs:schema> The document marshalled is- <?xml version="1.0" encoding="UTF-8" standalone="yes"?> <myDoc xmlns:ns2="http://www.mytypes.com"> <crap>real crap</crap> <ns2:foo>bleh</ns2:foo> <ns2:bar> <spam>blah</spam> </ns2:bar> </myDoc> Note that the <spam> element uses the default namespace. I would like it to use the ns2 namespace. The schema (mytypes.xsd) expresses the fact that <spam> is contained within <bar> which in the XML instance is bound to the ns2 namespace. I've broken my head over this for over a week and I would like ns2 prefix to appear in <spam>. What should I do? Required : <?xml version="1.0" encoding="UTF-8" standalone="yes"?> <myDoc xmlns:ns2="http://www.mytypes.com"> <crap>real crap</crap> <ns2:foo>bleh</ns2:foo> <ns2:bar> <ns2:spam>blah</ns2:spam><!--NS NS NS--> </ns2:bar> </myDoc>

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  • Replacing innertext of XML node using PHP DOMDocument

    - by Rohan Kumar
    I want to replace innertext of a XML node my XML file named test.xml is <?xml version="1.0" encoding="utf-8"?> <ads> <loop>no</loop> <item> <description>Description 1</description> </item> <item> <description>Text in item2</description> </item> <item> <description>Let play with this XML</description> </item> </ads> I want to change the value of loop and description tag both, and it should be saved in test.xml like: <?xml version="1.0" encoding="utf-8"?> <ads> <loop>yes</loop> <item> <description>Description Changing Here</description> </item> <item> <description>Changing text in item2</description> </item> <item> <description>We will play later</description> </item> </ads> I tried code in PHP: <? $file = "test.xml"; $fp = fopen($file, "rb") or die("cannot open file"); $str = fread($fp, filesize($file)); $dom=new DOMDocument(); $dom->formatOutput = true; $dom->preserveWhiteSpace = false; $dom->loadXML($str) or die("Error"); //$dom->load("items.xml"); $root=$dom->documentElement; // This can differ (I am not sure, it can be only documentElement or documentElement->firstChild or only firstChild) $loop=$root->getElementsByTagName('loop')->item(0);//->textContent; //echo $loop; if(trim($loop->textContent)=='no') { echo 'ok'; $root->getElementsByTagName('loop')->item(0)->nodeValue ='yes'; } echo "<xmp>NEW:\n". $dom->saveXML() ."</xmp>"; ?> I tried only for loop tag.I don't know how to replace nodevalue in description tag. When I run this page it shows output like: ok NEW: <?xml version="1.0" encoding="utf-8"?> <ads> <loop>yes</loop> <item> <description>Description 1</description> </item> <item> <description>Changing text in item2</description> </item> <item> <description>Let play with this XML</description> </item> </ads> It gives the value yes in browser but don't save it in test.xml any reason?

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  • Why is the XML DTD not found by the browser

    - by hyperuser
    When I load my XML file in a browser, it complains there is 'no style information': "This XML file does not appear to have any style information associated with it. The document tree is shown below." So I wrote an external DTD, then an internal DTD, but keep getting the same 'no style information' error. It doesn't even show the DTD! What am I doing wrong? <?xml version="1.0"?> <!DOCTYPE fotos [ <!ELEMENT fotos (titel,auteur)> <!ELEMENT titel (#PCDATA)> <!ELEMENT auteur (#PCDATA)> ]> <fotos> <titel>titel1</titel> <auteur>jan</auteur> </fotos>

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  • wmic output well formed xml on remote queries

    - by Mervin
    I want to use the WMI command line tool (wmic) to get information about windows computers on the network and output it as valid xml. However, I can't seem to find the right way to do this as the outputted xml currently contains invalid tokens for which I think I should use the /TRANSLATE:basicxml switch. The command: wmic /NODE:"tech-demo" /IMPLEVEL:Impersonate /USER:MyUser /PASSWORD:MyPassword /PRIVILEGES:DISABLE /AUTHLEVEL:Pkt /AUTHORITY:"ntlmdomain:companydomain.local" PATH Win32_LogicalDisk GET * /FORMAT:rawxml This command runs but returns invalid xml tokens ('<' and '' I think? edit: it appears to fail parsing at ‹) When I add the translate switch I get the message: Can not use credentials for local connections a bit strange that it tries to query the local pc when I add the switch.. Help would be greatly appreciated.

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  • Consume an XML Feed with PowerPoint 2010

    - by Matt Schweers
    Hi there. I'm looking for a way to consume an XML feed from a web-service directly into PowerPoint 2010. I found the LiveWeb plugin (http://skp.mvps.org/liveweb.htm) for PowerPoint that, while pretty cool, really only pulls in actual web content in a way that feels more like an iframe. Ideally, I would like to consume raw XML web service/feed with PowerPoint, parse it, and stylize the results. Is this possible? Even reading from a static XML file would be a good start.

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  • How to Read XML and Generate SQL Insert

    - by hackerkatt
    I am trying to write a VB Script to read a XML file (downloaded daily) and insert the information into a MSSQL DB. The content of the XML is a list if CDRs (Call Data Records). I need to parse the file and insert the cdr's into a table. I'm a Ruby,Perl,PHP,Javascript,SQL,... programer. But I've really never written any VB Script. I've done some googling and find a number of examples on how to generate XML from a SQL Query, but not the reverse. Any help/suggestions would be greatly appreciated. Thank you!

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  • Android app crashes when I change the default xml layout file to another

    - by mib1413456
    I am currently just starting to learn android development and have created a basic "Hello world" app that uses "activity_main.xml" for the default layout. I tried to create a new layout xml file called "new_layout.xml" with a text view, a text field and a button and did the following changes in the MainActivity.java file: setContentView(R.layout.new_layout); I did nothing else expect for adding a new_layout.xml in the res/layout folder, I have tried restarting and cleaning the project but nothing. Below is my activity_main.xml file, new_layout.xml file and MainActivity.java activity_main.xml: <FrameLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:tools="http://schemas.android.com/tools" android:id="@+id/container" android:layout_width="match_parent" android:layout_height="match_parent" tools:context="org.example.androidsdk.demo.MainActivity" tools:ignore="MergeRootFrame" /> new_layout.xml: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="match_parent" android:layout_height="match_parent" android:orientation="horizontal" > <TextView android:id="@+id/textView1" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="TextView" /> <EditText android:id="@+id/editText1" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_weight="1" android:ems="10" > <requestFocus /> </EditText> <Button android:id="@+id/button1" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="Button" /> MainActivity.java file package org.example.androidsdk.demo; import android.app.Activity; import android.app.ActionBar; import android.app.Fragment; import android.os.Bundle; import android.view.LayoutInflater; import android.view.Menu; import android.view.MenuItem; import android.view.View; import android.view.ViewGroup; import android.os.Build; public class MainActivity extends Activity { @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.new_layout); if (savedInstanceState == null) { getFragmentManager().beginTransaction() .add(R.id.container, new PlaceholderFragment()) .commit(); } } @Override public boolean onCreateOptionsMenu(Menu menu) { // Inflate the menu; this adds items to the action bar if it is present. getMenuInflater().inflate(R.menu.main, menu); return true; } @Override public boolean onOptionsItemSelected(MenuItem item) { // Handle action bar item clicks here. The action bar will // automatically handle clicks on the Home/Up button, so long // as you specify a parent activity in AndroidManifest.xml. int id = item.getItemId(); if (id == R.id.action_settings) { return true; } return super.onOptionsItemSelected(item); } /** * A placeholder fragment containing a simple view. */ public static class PlaceholderFragment extends Fragment { public PlaceholderFragment() { } @Override public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) { View rootView = inflater.inflate(R.layout.fragment_main, container, false); return rootView; } } }

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  • Is it possible to use .properties files in web.xml in conjunction with contextConfigLocation paramet

    - by Vladimir
    Here is part of my web.xml: <context-param> <param-name>contextConfigLocation</param-name> <param-value> classpath:application-config.xml </param-value> </context-param> application-config.xml uses property placeholder: <context:property-placeholder location="classpath:properties/db.properties"/> Is it possible somehow to define which properties file to use in web.xml rather than in application-config.xml?

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  • How to select visibility of specific worksheet at the opening of Excel using Spreadsheet XML

    - by user211607
    Hi, I am getting spreadsheet xml from a code logic (Flex Grids to spreadsheet xml). I have 3 worksheets (A, B, C) in that spreadsheet xml. I am opening this spreadsheet xml in Excel. I want to view worksheet B when I am opening the spreadhseet xml in Excel. Is there any tag/code, I need to add so that worksheet B will be visible at initial? I can add that code in code logic Thanks ... Atul

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  • Print XML file and download it

    - by Pankaj
    I am create xml using serialization and trying to print them using this code string xmlDate = xml.GetXML(); string name = string.Format("{0}_HighEST", ProjectName); Response.AddHeader("Content-disposition", "attachment; filename=\"" + name + "_HighEST.xml\""); Response.ContentType = string.Format("application/.xml", name); how can assign my xmldata to Response so that data will write on downloaded xml?

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  • Parsing secure entries XML file with jquery

    - by user573131
    Apologies if this is elementary. I'm primarily a front end designer/dev. I have webform through a form service called wufoo. Wufoo generates a lovely XML (or json) file that can be grabed and parsed. I'm trying to grab the entries xml feed that is associated with the form and parse it via jquery to show who has entered. Im using the following code (which works with a local xml file). http://bostonwebsitemakeover.com/2/test <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.js"></script> <script> $(document).ready(function () { $.ajax({ type: "GET", url: "people.xml", dataType: "xml", success: xmlParser }); }); function xmlParser(xml) { $('#load').fadeOut(); $(xml).find("Entry").each(function () { $(".main").append('<div class="entry">' + $(this).find("Field1").text() + ' ' + $(this).find("Field2").text() + ' http://twitter.com/' + $(this).find("Field17").text() + '</div>'); $(".entry").fadeIn(1000); }); } </script> My XML file contains the following: <?xml version="1.0"?> <Entries> <Entry> <EntryId>1</EntryId> <Field1>Meaghan</Field1> <Field2>Severson</Field2> <Field17/> </Entry> <Entry> <EntryId>2</EntryId> <Field1>Michael</Field1> <Field2>Flint</Field2> <Field17>michaelflint</Field17> </Entry> <Entry> <EntryId>3</EntryId> <Field1>Niki</Field1> <Field2>Brown</Field2> <Field17>nikibrown</Field17> </Entry> <Entry> <EntryId>4</EntryId> <Field1>Niki</Field1> <Field2>Brown</Field2> <Field17>nikibrown</Field17> </Entry> </Entries> I'm wondering how I would do this with the xml file hosted on the wufoo (which is https) So I guess Im asking how do I authenticate the feed via jquery? Or do i need to do this via json? Could someone explain how?

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  • Which XML library for what purposes?

    - by John Mee
    A search for "python" and "xml" returns a variety of libraries for combining the two. This list probably faulty: xml.dom xml.etree xml.sax xml.parsers.expat PyXML beautifulsoup? HTMLParser htmllib sgmllib Be nice if someone can offer a quick summary of when to use which, and why.

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  • who convert flat file xml in biztalk server?

    - by Anish
    Hi, I am new to BizTalk server. So if this question is so obvious, plz forgive :( I have a flat file from one application, which i have to send to a biztalk server. In that case which component in my biztalk server converts my flat file to xml. Also I heard that I have to create an input schema(.xsd file), why i need an input message schema? Thanks in advance!

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  • How to replace invalid characters in XML using Javascript or PhP

    - by Raind
    Hi, Need help here for the following: Running PhP, javascript, MySQL, XML. 1) Retrieving file from MySQL and stored it onto XML file. 2) Use javascript function to load XML file (that stored those data). 3) It produces invalid characters in XML file. STEP 1 : Sample of the code in PhP - Loading MySQL DB to store data onto XML file $file= fopen("MapDeals2.xml", "w"); $_xml ="\n"; $_xml .="\n"; while($row1_ThisWeek = mysql_fetch_array($result1_ThisWeek)) { $rRName = $row1_ThisWeek['Retailer_Name']; $rRAddress = $row1_ThisWeek['Retailer_Address1']; $rRAddressPostCode = $row1_ThisWeek['Retailer_AddressPostCode1']; } $_xml .= "<DEAL>\n"; $_xml .= "<DealDescription>" . $d_Description . "</DealDescription>\n"; $_xml .= "<DealURL>" . $d_URL . "</DealURL>\n"; $_xml .= "<DealRName>" . $rRName . "</DealRName>\n"; $_xml .= "<DealRAddress>" . $rRAddress . "</DealRAddress>\n"; $_xml .= "<DealRPostCode>" . $rRAddressPostCode . "</DealRPostCode>\n"; $_xml .= "</DEAL>\n"; } } $_xml .="\n"; fwrite($file, $_xml); fclose($file); STEP 2 : Sample of the code in Javscript - Loading XML file xhttp.open("GET","Test2.xml", false); xhttp.send(""); xmlDoc=xhttp.responseXML; var x=xmlDoc.getElementsByTagName("Employee"); parser = new DOMParser(); xmlDoc = parser.parseFromString("MapDeals2.xml", "text/xml"); for (i=0;i"; . . . } Is there a solution for the above? Looking forward to hear from you soon. Cheers

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