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  • How to get the content of two xml tags even when they have another xml tags inside them (PHP-XML)

    - by Harry
    In simple terms, let's suppose you have the following xml structure: <TEXT>Well, I need some help as you <CUSTOMTAG>can</CUSTOMTAG> see.</TEXT> When extracting the text of this node in PHP with strip_tags(), I am not getting the content of tags. First step: What I want to do, is to extract and thus have the following string: "Well, I need some help as you can see." Second step: I would also like to convert the <CUSTOMTAG> and </CUSTOMTAG> to something else, like <e> and </e> for example, and finally have the following string: "Well, I need some help as you <e>can</e> see." I would appreciate only tested and working code. Thanks in advance! Kind Regards

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  • How to spread XML Sitemaps over several webservers behind AWS loadbalancer?

    - by Jurik
    We have a web portal with almost a million products and way more other urls. I wrote a script that checks database. If there is a new url needed or an old one update, this script will update/create the XML Sitemaps. But we have several servers behind the load balancer at our rented AWS space. Further this script checks database for each url if there was an update so that it updates the appropriate xml file too. My question is how to spread those XML Sitemaps over all webservers behind this AWS load balancer? Our approaches/ideas: we could just generate them on one server with a cron job and copy them to the other servers, but this could be difficult because of automatic raising numbers of servers and so on. we put them on our S3 - but this one is not avaible thru our domain, so I guess google will have a problem with it I let my script run on every webserver but change it in a way that it will generate each time all xml files if they do not exist. But then I would have conflicts with updated URLs in my database, where I saved timestamp of last changed value of every url Is there another - better - solution that I do not know? Are there any special services by amazon for such cases?

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  • Register Schema Master in Active Directory

    In order to view the complete schema in AD, I have to register the schmmgmt.dll and then open a snap in in MMC, the steps can be summarized as: Go to CMD> Windows System Folder > System32 folder Type in "regsvr32 schmmgmt.dll" Open MMC > File > Add/Remove Snap-In > Active Directory Schema Then I can browser all available attributes in this AD Schema  ...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Using Sql Server Change Data Capture with a frequently changing schema

    - by Pete
    We are looking into enabling Sql Server Change Data Capture for a new subsystem we are building. It's not really because we need it, but we are being pushed for having a complete history traceability, and CDC would nicely solve this requirement with minimum effort on our parts. We are following an agile development process, which in this case means that we frequently make changes to the database schema, e.g. adding new columns, moving data to other columns, etc. We did a small test where we created a table, enabled CDC for that table, and then added a new column to the table. Changes to the new column is not registered in the CDC table. Is there a mechanism to update the CDC table to the new schema, and are there any best practices to how you deal with captured data when migrating the database schema?

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  • Register Schema Master in Active Directory

    In order to view the complete schema in AD, I have to register the schmmgmt.dll and then open a snap in in MMC, the steps can be summarized as: Go to CMD> Windows System Folder > System32 folder Type in "regsvr32 schmmgmt.dll" Open MMC > File > Add/Remove Snap-In > Active Directory Schema Then I can browser all available attributes in this AD Schema  ...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • schema.org 'reviewRating' tag not recognized by google snippet testing tool

    - by saravanak
    I'm trying to add more structural information to my webpages by using the microdata format suggested in www.schema.org. The procedure seems straight forward but I'm having issues validating my results in the Google Rich Snippets Testing Tool. Check out this review page, here I'm using the 'reviewRating' property item to specify rating values for that particular review. I followed the same format as defined in schema.org/Rating but this markup fails validation in Google's rich snippet testing tool with the following error info. Item Type: http://schema.org/rating reviewrating = 5 ratingvalue = 5 Warning: Property "reviewrating" was not found.

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  • How would you represent an object that can be of multiple types, when storing it as a document in MongoDB?

    - by blueberryfields
    Somewhat related to this question, say that I have an object category which, depending on which type of object I have, has different restrictions on what it contains. (if you can reword the previous sentence to make more sense I'd appreciate it) For example var SomeSchema = new Schema({ _id: ObjectID, [... large number of common fields ...] type: //Restricted somehow to members of a fixed array data: //depending on type, this might be restricted - sometimes an integer, sometimes array, etc... }); What's the idiosyncratic method for defining this type of schema? Is it appropriate to define a single schema, and handle the types inside of it's members, or am I better off with separate schema for each type?

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  • XMl to XHTML using XSL with namespace

    - by user256007
    How to handle XML Elements with namespace in an XSL. Here goes my XML Document <?xml version="1.0" encoding="UTF-8"?> <?xml-stylesheet type="text/xml" href="wpanel.xsl" ?> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:bong="http://bong/glob/wpanel" xml:lang="en" lang="en"> <head> <title> Transitional DTD XHTML Example </title> <link rel="stylesheet" type="text/css" href="wpanel.css" /> </head> <body> <bong:QButton text="Submit"></bong:QButton> <bong:QButton text="Reset"></bong:QButton> </body> </html> and My XSL goes here <?xml version="1.0" ?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:bong="http://bong/glob/wpanel" xmlns:fn="http://www.w3.org/2005/xpath-functions" > <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" /> <xsl:template match="*|@*"> <xsl:copy> <xsl:apply-templates select="@*"/> <xsl:apply-templates/> </xsl:copy> </xsl:template> <xsl:template match="processing-instruction()|comment()"> <xsl:copy>.</xsl:copy> </xsl:template> I want to copy the elements without bong namespace as it is But transform those using the bong namespace. I think there will be an xsl element or attribute for that.I've serched the net. but haven't found yet. Thank You.

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  • Parsing XML via jQuery, nested loops

    - by Coughlin
    I am using jQuery to parse XML on my page using $.ajax(). My code block is below and I can get this working to display say each result on the XML file, but I am having trouble because each section can have MORE THAN ONE and im trying to print ALL grades that belong to ONE STUDENT. Here is an example of the XML. <student num="505"> <name gender="male">Al Einstein</name> <course cid="1">60</course> <course cid="2">60</course> <course cid="3">40</course> <course cid="4">55</course> <comments>Lucky if he makes it to lab, hopeless.</comments> </student> Where you see the I am trying to get the results to print the grades for EACH student in each course. Any ideas on what I would do? Thanks, Ryan $.ajax({ type: "GET", url: "final_exam.xml", dataType: "xml", success: function(xml) { var student_list = $('#student-list'); $(xml).find('student').each(function(){ $(xml).find('course').each(function(){ gradeArray = $(this).text(); console.log(gradeArray); }); var name = $(this).find("name").text(); var grade = $(this).find("course").text(); var cid = $(this).find("course").attr("cid"); //console.log(cid); student_list.append("<tr><td>"+name+"</td><td>"+cid+"</td><td>"+grade+"</td></tr>"); }); } });

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  • PHP XML Validation

    - by efritz
    What's the best way to validate an XML file (or a portion of it) against multiple XSD files? For example, I have the following schema for a configuration loader: <xsd:schema xmlns="http://www.kauriproject.org/schema/configuration" xmlns:xsd="http://www.w3.org/2001/XMLSchema" targetNamespace="http://www.kauriproject.org/schema/configuration" elementFormDefault="qualified"> <xsd:element name="configuration" type="configuration" /> <xsd:complexType name="configuration"> <xsd:choice maxOccurs="unbounded"> <xsd:element name="import" type="import" minOccurs="0" maxOccurs="unbounded" /> <xsd:element name="section" type="section" /> </xsd:choice> </xsd:complexType> <xsd:complexType name="section"> <xsd:sequence> <xsd:any minOccurs="0" maxOccurs="unbounded" processContents="lax" /> </xsd:sequence> <xsd:attribute name="name" type="xsd:string" use="required" /> <xsd:attribute name="type" type="xsd:string" use="required" /> </xsd:complexType> <xsd:complexType name="import" mixed="true"> <xsd:attribute name="resource" type="xsd:string" /> </xsd:complexType> </xsd:schema> As the Configuration class exists now, it lets one add a <section> tag with a define concrete parser class (much like custom configuration sections in ASP.NET). However, I'm unsure of how to validate the section being parsed. If it possible to validate just this section of code with an XSD file/string without writing it back to a file?

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  • XML::LibXML::XPathContext - Question

    - by sid_com
    This script works with and without XPathContext. Why should I use it with XPathContext? #!/usr/bin/env perl use warnings; use strict; use XML::LibXML; use 5.012; my $parser = XML::LibXML->new; my $doc = $parser->parse_string(<<EOT); <?xml version="1.0"?> <xml> Text im Dokument <element id="myID" name="myname" style="old" /> <object objid="001" objname="Object1" /> <element id="002" name="myname" /> </xml> EOT #/ # without XPathContext my $nodes = $doc->findnodes( '/xml/element[@id=002]' ); # with XPathContext #my $root = $doc->documentElement; #my $xc = XML::LibXML::XPathContext->new( $root ); #my $nodes = $xc->findnodes( '/xml/element[@id=002]' ); for my $node ( $nodes->get_nodelist ) { say "Node: ", $node->nodeName; print "Attribute: "; print $_->getName, '=', $_->getValue, ' ' for $node->attributes; say ""; }

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  • Update element values using xml.dom.minidom

    - by amnesia-55
    Hello, I have an XML structure which looks similar to: <Store> <foo> <book> <isbn>123456</isbn> </book> <title>XYZ</title> <checkout>no</checkout> </foo> <bar> <book> <isbn>7890</isbn> </book> <title>XYZ2</title> <checkout>yes</checkout> </bar> </Store> Using xml.dom.minidom only (restrictions) i would like to 1)traverse through the XML file 2)Search/Get for particular element, depending on its parent Example: checkout element for author1, isbn for author2 3)Change/Set that element's value 4)Write the new XML structure to a file Can anyone help here? Thank you! UPDATE: This is what i have done till now import xml.dom.minidom checkout = "yes" def getLoneChild(node, tagname): assert ((node is not None) and (tagname is not None)) elem = node.getElementsByTagName(tagname) if ((elem is None) or (len(elem) != 1)): return None return elem def getLoneLeaf(node, tagname): assert ((node is not None) and (tagname is not None)) elem = node.getElementsByTagName(tagname) if ((elem is None) or (len(elem) != 1)): return None leaf = elem[0].firstChild if (leaf is None): return None return leaf.data def setcheckout(node, tagname): assert ((node is not None) and (tagname is not None)) child = getLoneChild(node, 'foo') Check = getLoneLeaf(child[0],'checkout') Check = tagname return Check doc = xml.dom.minidom.parse('test.xml') root = doc.getElementsByTagName('Store')[0] output = setcheckout(root, checkout) tmp_config = '/tmp/tmp_config.xml' fw = open(tmp_config, 'w') fw.write(doc.toxml()) fw.close()

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  • Problem with XML encoding of database contents with Latin characters

    - by user89691
    I have an ASP Access database that contains strings in various European languages. The database was populated prior by agents in the respective countries. It contains entries with accented etc characters as you would expect. If I open the database with MS Access these characters show up fine. For example the the German equivalent of "Open" shows as "Öffnen" (hopefully you can see an "O" with 2 dots above it!). I have ASP code that reads the database and returns records in XML. The text is passed to XMLEncode to construct the XML, but that only seems to deal with the 5 specials like "<", "&", etc. If I dump the XML the accented characters are unchanged. <English>Open</English> <German>Öffnen</German> If I look at the raw packets with Wireshark I see that the "Ö" byte is hex D6, which appears to be it's decimal Unicode and ISO 8859-1 value. The problem starts when I try to parse the XML in client-side JS. I get: "An invalid character was found in text content" from IE. FF and Chrome happily accept the XML without hiccup but the browser shows the "Ö" character as a diamond with a question mark inside. http://www.validome.org/xml/validate/ reports "encoding error." http://www.w3schools.com/dom/dom_validate.asp thinks it is fine. The XML is UTF-8 encoded. What do I need to do to have IE accept my XML without complaint? What do I need to do to have browsers display the stuff correctly?

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  • Writing Russian in XML

    - by zavié
    Hi, I am writing a Xml Tag Renamer class with Java which reads in a XML, renames the tags and write them back into another XML file using DocumentBuilderFactory and TransformerFactory (text nodes are preserved). It worked fine before with German and English texts, until today, when I tried to rename a XML file with russian text. Instead of the source texts I got ????? in the newly created XML file. I've tried setting Encoding Any idea how to correct this? Thanks! PS. Strings were correct before entering TransformerFactory, as I checked in the debugger. I've tried setting OutputKeys.ENCODING to UTF-8 and ISO-8859-5. None of them helped. The Transformer part: // Output the XML // Set up a transformer TransformerFactory transFactory = TransformerFactory.newInstance(); Transformer transformer = transFactory.newTransformer(); transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "no"); // Fix to a bug about indent in transformer transformer.setOutputProperty ("{http://xml.apache.org/xslt}indent-amount", "4"); transformer.setOutputProperty(OutputKeys.INDENT, "yes"); // TODO encoding parameter transformer.setOutputProperty(OutputKeys.ENCODING, "UTF-8"); // Create string from xml tree StringWriter sw = new StringWriter(); StreamResult result = new StreamResult(sw); DOMSource source = new DOMSource(doc); transformer.transform(source, result); String xmlString = sw.toString(); xmlString.replaceAll("\n", System.getProperty("line.separator")); // Write to file BufferedWriter output = new BufferedWriter(new FileWriter(outputPath)); output.write(xmlString); output.close();

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  • Xsd recursion of complexTypes

    - by Hatch
    I am just learning XML/XSD and am struggling with the implementation of an XML-schema which models a folder structure. What I had in mind was defining a complexType for the folder which can have additional folder instances that represent subfolders. Using the xsd schema validator here always returns that the schema is invalid. I tried defining the complexType up front and then using the ref keyword for subfolders: <xs:complexType name="tFolder"> <xs:sequence> <xs:element name="Path" type="tFolderType" msdata:Ordinal="0" /> <xs:element ref="Folder" minOccurs="0" maxOccurs="unbounded" /> <xs:element name="File" nillable="true" minOccurs="0" maxOccurs="unbounded"> <xs:complexType> <xs:simpleContent msdata:ColumnName="File_Text" msdata:Ordinal="0"> <xs:extension base="xs:string"> </xs:extension> </xs:simpleContent> </xs:complexType> </xs:element> </xs:sequence> <xs:attribute name="Type" type="tFolderType" /> As for the element itself: <xs:element name="Folder" type="tFolder" /> The error returned by the validator is: "Cannot resolve the name 'Folder' to a(n) 'element declaration' component." and the error occurs at the line <xs:element ref="Folder" minOccurs="0" maxOccurs="unbounded" /\> Defining the complexType within the element itself yields the exact same error: <xs:element name="Folder"> <xs:complexType> <xs:sequence> <xs:element name="Path" type="tFolderType" msdata:Ordinal="0" /> <xs:element ref="Folder" minOccurs="0" maxOccurs="unbounded" /> <xs:element name="File" nillable="true" minOccurs="0" maxOccurs="unbounded"> <xs:complexType> <xs:simpleContent msdata:ColumnName="File_Text" msdata:Ordinal="0"> <xs:extension base="xs:string"> </xs:extension> </xs:simpleContent> </xs:complexType> </xs:element> </xs:sequence> <xs:attribute name="Type" type="tFolderType" /> </xs:complexType> </xs:element> What I've read, this kind of recursion should work using ref. Can anyone tell me what I've done wrong? Maybe the xsd validator is just faulty? If so, does anyone know a better alternative? I've tried using the one from w3.org as well, but it seems to be taken offline...

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  • Flash AS3 load file xml

    - by Elias
    Hello, I'm just trying to load an xml file witch can be anywere in the hdd, this is what I have done to browse it, but later when I'm trying to load the file it would only look in the same path of the swf file here is the code package { import flash.display.Sprite; import flash.events.; import flash.net.; public class cargadorXML extends Sprite { public var cuadro:Sprite = new Sprite(); public var file:FileReference; public var req:URLRequest; public var xml:XML; public var xmlLoader:URLLoader = new URLLoader(); public function cargadorXML() { cuadro.graphics.beginFill(0xFF0000); cuadro.graphics.drawRoundRect(0,0,100,100,10); cuadro.graphics.endFill(); cuadro.addEventListener(MouseEvent.CLICK,browser); addChild(cuadro); } public function browser(e:Event) { file = new FileReference(); file.addEventListener(Event.SELECT,bien); file.browse(); } public function bien(e:Event) { xmlLoader.addEventListener(Event.COMPLETE, loadXML); req=new URLRequest(file.name); xmlLoader.load(req); } public function loadXML(e:Event) { xml=new XML(e.target.data); //xml.name=file.name; trace(xml); } } } when I open a xml file that isnt it the same directory as the swf, it gives me an unfound file error. is there anything I can do? cause for example for mp3 there is an especial class for loading the file, see http://www.flexiblefactory.co.uk/flexible/?p=46 thanks

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  • Flex through Flash Builder 4; Connecting to a dynamic XML feed: "The response is not a valid XML or

    - by jtromans
    I am learning how to use Flex with Adobe Flash Builder 4 standalone. I am working my through the Adobe Flash Build 4 Bible by David Gassner. This has led me to create my own micro problems to try and solve. I am trying to connect to a dynamix XML feed created by the following aspx page: generate_xml.aspx When I create the data connection through the Data/Service panel, I can pick between XML and HTTP. I figured because the generate_xml.aspx has to generate the XML file first, I should use the HTTP service as opposed to the XML. The HTTP service offers GET, which seems to be the kinda thing I want. However, I am really struggling to do this. I keep getting: "The response is not a valid XML or a JSON string" The actual STATIC generated XML file that is created by this page works perfectly when I save it and manually connect with the XML service. Therefore I know my XML code is properly formatted and contains no other HTML of JavaScript. I figure my problem occurs because the page itself is .aspx, but I cannot work out how to successfully ask Flex to request the output of this page, rather than the page itself.

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  • built-in schema datatype for html / xhtml

    - by John Clements
    Is there a built-in schema datatype for xhtml data? Suppose I want to specify a "boozle" element that contains two "woozles", each of which is arbitrary xhtml. I want to write something like this, using the relax NG compact syntax: namespace nifty = "http://brinckerhoff.org/nifty/" start = element nifty:boozle {woozle, woozle} woozle = element nifty:woozle {xhtml} Unfortunately, xmllint then signals this error: ./lab.rng:43: element ref: Relax-NG parser error : Reference xhtml has no matching definition ./lab.rng:43: element ref: Relax-NG parser error : Internal found no define for ref xhtml So my question is this: is there something sensible that I should put in place of "xhtml" above?

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  • faster way to change xml to array(grails to flex)

    - by Anthony Umpad
    I have a large xml passed from grails to flex. When flex receives the xml, it converts the xml into an associative array object. Given the large xml file, it takes too long to complete the loop, is there any way in flex to make conversion faster? Below is my sample code. <xml> <car> <model>Vios</model> <type>Sedan</type> <color>Blue</color> </car> <car> <model>Camry</model> <type>Luxury</type> <color>Black</color> </car> </xml> *converted to the flex associative array below.* [Vios].type = Sedan .color = Blue [Camry].type = Luxury .color = Black *Below is a code I used in flex to convert the xml to the associative array object* var tempXML=xml.children() var tempArray:Array= new Array() for(var i:int=0;i<tempXML.length();i++) { tempArray[tempXML[i].@model]= new Object(); tempArray[tempXML[i].@model].color = tempXML[i][email protected](); tempArray[tempXML[i].@model].type = tempXML[i][email protected](); }

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  • PHP4: Send XML over HTTPS/POST via cURL?

    - by starmonkey
    I wrote a class/function to send xml over https via PHP4/cURL, just wondering if this is the correct approach, or if there's a better one. Note that PHP5 is not an option at present. /** * Send XML via http(s) post * * curl --header "Content-Type: text/xml" --data "<?xml version="1.0"?>...." http://www.foo.com/ * */ function sendXmlOverPost($url, $xml) { $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); // For xml, change the content-type. curl_setopt ($ch, CURLOPT_HTTPHEADER, Array("Content-Type: text/xml")); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $xml); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); // ask for results to be returned if(CurlHelper::checkHttpsURL($url)) { curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0); } // Send to remote and return data to caller. $result = curl_exec($ch); curl_close($ch); return $result; } cheers!

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  • Save a form in an XML file using Ajax and JSP

    - by novellino
    Hello, I want to create a simple form with a name and an email and save these data in an XML file. So far I found that using Ajax with jQuery is quite easy. So I used the usual code: //dataString have the values taken from the form var dataString = 'name='+ name + '&email=' + email; $.ajax({ type: "POST", url: "users.xml", data: dataString, dataType: "xml", success: function() { .... } }); If I understood well, in the url I should add the name of the XML file that will be created. When the user clicks a button I call the function with the Ajax request, and then I should call somewhere a function for generating the xml. I am using also two beans. One is for setting the elements of the user and the other is for saving the data in the XML. I am using the XStream library for the xml although I don't know if is the best solution. The problem now it that I can not connect all these together in order to save the data in the XML. Does anyone know what should I do? Thanks a lot!

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  • LINQ to XML contents of child records.

    - by Fossaw
    I have this LINQ to XML enquiry... var Records = from Item in XDoc.Root.Elements("Item") where (string)Item.Element("ItemNumber") == item.ID.ToString select Item; ... where ItemNumber is a reference number used in the XML, (originally written by this program but manually edited by "others"), and item.ID is the database version of the same thing. The query executes, and I can test for the number of entries in the result fine... if (Records.Count() < 1) ... you get the idea. I have established that there is only one record. Each Item has several child fields. I want to test the values of the child fields are reasonable before passing them on to the database update sub-system. The XML is produced by the program, but edited by users, so I need to really check what is coming back. So I tried... if (DB_English.ToString() != Records.Elements("English").ToString()) ... DB_English is from the database, but the XML in Records, does not contain the contents of that field, it contains... System.Xml.Linq.Extensions+<GetElements>d__29`1[System.Xml.Linq.XElement] ... so, how do I get the value of this element in the XML file? I need to check the field in the XML has not been altered, (the manual editors of this data file are not potentially 100% reliable).

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  • How to find/extract data from xml with jQuery

    - by darryl
    I'm trying to extract the StateLongName and StateShortName values from the xml below. I know there has to be a simple elegant way to do this with jQuery. <NewDataSet> <Table> <StateLongName>Alabama</StateLongName> <StateShortName>AL</StateShortName> </Table> <Table> <StateLongName>Alaska</StateLongName> <StateShortName>AK</StateShortName> </Table> ...elments removed for brevity </NewDataSet> Here's what I've tried. Load the xml from above into a Javascript variable name xml. Try #1 $(xml).find("TABLE").each(function() { var stateName = $(this).find("StateLongName").innerText; var stateCode = $(this).find("StateShortName").innerText; }); Try #1 doesn't find anything and never goes inside to load the stateName and stateCode variables. Try #2 $(xml).find("StateLongName").each(function() { var stateName = $(this).find("StateLongName").innerText; var stateCode = $(this).find("StateShortName").innerText; }); Try #2 does find matches, however the stateName and stateCode are left undefined. Try #3 $(xml).find("StateLongName").each(function() { var stateName = $($(xml).find('StateLongName').parent()[0].innerHTML)[1].data; var stateCode = $($(xml).find('StateLongName').parent()[0].innerHTML)[5].data; }); Try #3 works but there has to be a better way. Please enlighten me. Thanks for you time!

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