Search Results

Search found 1765 results on 71 pages for 'z sorting'.

Page 26/71 | < Previous Page | 22 23 24 25 26 27 28 29 30 31 32 33  | Next Page >

  • Sorting Custom Objects with Parameter in VB.Net/C#

    - by Jeffrey Kern
    Let's say I have a custom object of Foo Is there anyway I can sort through a list of these objects, like list<of foo>.sort() and also be able to sort this list with a passable parameter. which will influence the sort? list<of foo>.sort(pValue) I'm guessing I'll need to define two separate sorts, but I am not sure. Thanks!

    Read the article

  • C++ struct sorting error

    - by Betamoo
    I am trying to sort a vector of custom struct in C++ struct Book{ public:int H,W,V,i; }; with a simple functor class CompareHeight { public: int operator() (Book lhs,Book rhs) { return lhs.H-rhs.H; } }; when trying : vector<Book> books(X); ..... sort(books.begin(),books.end(), CompareHeight()); it gives me exception "invalid operator <" What is the meaning of this error? Thanks

    Read the article

  • Sorting an array of strings in reverse alphabetical order in Java

    - by Quacky
    I've been tasked with turning this code into a reverse sort, but for the life of me cannot figure out how to do it. These are my sort, findlargest and swap methods. I have a feeling I am missing something glaringly obvious here, any help would be really appreciated. public static void sort(String[] arr) { for (int pass = 1; pass < arr.length; pass++) { int largestPos = findLargest(arr, arr.length - pass); if (largestPos != arr.length - pass) { swap(arr, largestPos, arr.length - pass); } } } public static int findLargest(String[] arr, int num) { int largestPos = 0; for (int i = 1; i <= num; i++) { if (arr[i].compareToIgnoreCase(arr[largestPos]) > 0) { largestPos = i; } } return largestPos; } public static void swap(String[] arr, int first, int second) { String temp = arr[first]; arr[first] = arr[second]; arr[second] = temp; } }

    Read the article

  • Sorting multidimensional array on inner value php [duplicate]

    - by Silver89
    This question already has an answer here: Reference: all basic ways to sort arrays and data in PHP 4 answers Say I have the following array, how can I sort it on sort_by? Array ( [10] => Array ( [Masthead_slide] => Array ( [id] => 1456464564 [sort_by] => 1 ) ) [6] => Array ( [Masthead_slide] => Array ( [id] => 645454 [sort_by] => 10 ) ) [7] => Array ( [Masthead_slide] => Array ( [id] => 4547 [sort_by] => 5 ) ) )

    Read the article

  • sqlalchemy natural sorting

    - by teggy
    Currently, i am querying with this code: meta.Session.query(Label).order_by(Label.name).all() and it returns me objects sorted by Label.name in this manner ['1','7','1a','5c']. Is there a way i can have the objects returned in the order with their Label.name sorted like this ['1','1a','5c','7'] Thanks!

    Read the article

  • Python: Sorting array with custom pattern

    - by Binka
    In my little project here I have sorted a list in decending order, however, my goal is to sort it in this custom pattern. (largest - smallest - next largest - next smallest -)etc. In java I was able to do this like this... My goal is to do the same thing but in python, except backwards. Any ideas on how to convert that last for loop that does the wackysort into python and make it go backwards? public static void wackySort(int[] nums){ //first, this simply sorts the array by ascending order. int sign = 0; int temp = 0; int temp2 = 0; for (int i = 0; i < nums.length; i++){ for (int j = 0; j < nums.length -1; j++){ if (nums[j] > nums[j+1]){ temp = nums[j]; nums[j] = nums[j+1]; nums[j+1] = temp; } } } //prepare for new array to actually do the wacky sort. System.out.println(); int firstPointer = 0; int secondPointer = nums.length -1; int[] newarray = new int[nums.length]; int size = nums.length; //for loop that increments by two taking second slot replacing the last (n-1) term for (int i = 0; i < nums.length -1; i+=2){ newarray[i] = nums[firstPointer++]; newarray[i+1] = nums[secondPointer--]; } //storing those values back in the nums array for (int i = 0; i < nums.length; i++){ nums[i] = newarray[i]; } }

    Read the article

  • Sorting an object?

    - by dfjhdfjhdf
    How to sort this object lexicographically by its keys: var obj = {'somekey_B' : 'itsvalue', 'somekey_A' : 'itsvalue'); so that it outputs like this: for (k in obj) { alert(k + ' : ' + obj[k]); //first "somekey_A : itsvalue"; then "somekey_B : itsvalue" }

    Read the article

  • question about permut-by-sorting

    - by davit-datuashvili
    hi i have following question from book introduction in algorithms second edition there is such problem suppose we have some array A int a[]={1,2,3,4} and we have some random priorities array P={36,3,97,19} we shoud permut array a randomly using this priorities array here is pseudo code P ERMUTE -B Y-S ORTING ( A) 1 n ? length[A] 2 for i ? 1 to n do P[i] = R ANDOM(1, n 3 ) 3 4 sort A, using P as sort keys 5 return A and result will be permuted array B={2, 4, 1, 3}; please help any ideas i have done this code and need aideas how continue import java.util.*; public class Permut { public static void main(String[]args){ Random r=new Random(); int a[]=new int[]{1,2,3,4}; int n=a.length; int b[]=new int[a.length]; int p[]=new int[a.length]; for (int i=0;i<p.length;i++){ p[i]=r.nextInt(n*n*n)+1; } // for (int i=0;i<p.length;i++){ // System.out.println(p[i]); //} } } please help

    Read the article

  • Sorting results by a char(1) column

    - by Brandon
    I have a stored procedure which basically does something like select top 1 expiryDate, flag, (bunch of other columns) from someTable (bunch of joins) order by expiryDate desc So this will grab the record that expires last. This works for most cases, except some records have a flag that are just a char(1). Most of the time it's just Y or N. So it'll return something like 2010-12-31 N 2010-10-05 Y 2010-08-05 N 2010-03-01 F 2010-01-31 N This works, most of the time, but is there any way to order it by the Flag column as well? So I'd want to group the results by Y, then N, and F and any other flags can go last in any order. I thought this would just be an order by, but since the flags are not weighted by the alphabetic value, I'm a little stumped. (Note: These are not my tables, I don't know if using the characters like this was a good idea or not, but it's not something I can change).

    Read the article

  • Sorting MySQL table by next due date

    - by Zagga
    Hi folks, I have a MySQL table that stores (amongst other things) a persons date of birth. Is there any way to sort the table so the next due birthday is at the top? I have the date stored in standard yyyy-mm-dd DATE format and seperate year, month and day fields so I can sort it by the first birthday of the year (ORDER BY month, day) but I can't seem to get any further. Any help would be greatly appreciated. Zagga

    Read the article

  • Java Sorting "queue" list based on DateTime and Z Position (part of school project)

    - by Kuchinawa
    For a school project i have a list of 50k containers that arrive on a boat. These containers need to be sorted in a list in such a way that the earliest departure DateTimes are at the top and the containers above those above them. This list then gets used for a crane that picks them up in order. I started out with 2 Collection.sort() methods: 1st one to get them in the right XYZ order Collections.sort(containers, new Comparator<ContainerData>() { @Override public int compare(ContainerData contData1, ContainerData contData2) { return positionSort(contData1.getLocation(),contData2.getLocation()); } }); Then another one to reorder the dates while keeping the position in mind: Collections.sort(containers, new Comparator<ContainerData>() { @Override public int compare(ContainerData contData1, ContainerData contData2) { int c = contData1.getLeaveDateTimeFrom().compareTo(contData2.getLeaveDateTimeFrom()); int p = positionSort2(contData1.getLocation(), contData2.getLocation()); if(p != 0) c = p; return c; } }); But i never got this method to work.. What i got working now is rather quick and dirty and takes a long time to process (50seconds for all 50k): First a sort on DateTime: Collections.sort(containers, new Comparator<ContainerData>() { @Override public int compare(ContainerData contData1, ContainerData contData2) { return contData1.getLeaveDateTimeFrom().compareTo(contData2.getLeaveDateTimeFrom()); } }); Then a correction function that bumps top containers up: containers = stackCorrection(containers); private static List<ContainerData> stackCorrection(List<ContainerData> sortedContainerList) { for(int i = 0; i < sortedContainerList.size(); i++) { ContainerData current = sortedContainerList.get(i); // 5 = Max Stack (0 index) if(current.getLocation().getZ() < 5) { //Loop through possible containers above current for(int j = 5; j > current.getLocation().getZ(); --j) { //Search for container above for(int k = i + 1; k < sortedContainerList.size(); ++k) if(sortedContainerList.get(k).getLocation().getX() == current.getLocation().getX()) { if(sortedContainerList.get(k).getLocation().getY() == current.getLocation().getY()) { if(sortedContainerList.get(k).getLocation().getZ() == j) { //Found -> move container above current sortedContainerList.add(i, sortedContainerList.remove(k)); k = sortedContainerList.size(); i++; } } } } } } return sortedContainerList; } I would like to implement this in a better/faster way. So any hints are appreciated. :)

    Read the article

  • Can't compile std::map sorting, why?

    - by Vincenzo
    This is my code: map<string, int> errs; struct Compare { bool operator() (map<string, int>::const_iterator l, map<string, int>::const_iterator r) { return ((*l).second < (*r).second); } } comp; sort(errs.begin(), errs.end(), comp); Can't compile. This is what I'm getting: no matching function for call to ‘sort(..’ Why so? Can anyone help? Thanks!

    Read the article

  • mysql ORDER BY date_time field not sorting as expected

    - by undefined
    I have a field in my database that stores the datetime that an item was added to the database. If I want to sort the items in reverse chronological order I would expect that doing ORDER by date_added DESC would do the trick. But this seems not to work. I also tried ORDER by UNIX_TIMESTAMP(date_added) but this still did not sort the results as I would expect. I also have an auto-increment field that I can use to sort items so I will use this, but I am curious as to why ORDER by datetime was not behaving as expected. any ideas?

    Read the article

  • Sorting a table based on which header cell was clicked

    - by cf_PhillipSenn
    If I have the following: <table> <thead> <tr> <th><a href="Index.cfm?Sort=0">First</a></th> <th><a href="Index.cfm?Sort=1">Second</a></th> <th><a href="Index.cfm?Sort=2">Third</a></th> </tr> </thead> <tbody> <tr> <td>A</td> <td class="num">123</td> <td>XYZ</td> </tr> </tbody> </table> Q: How do I sort the table body based upon which table header cell was clicked? <script> $('th a').click(function() { var $this = $(this).closest('th'); console.log($this.index()); return false; }); </script> (I made each of the table header cells hyperlinks so that if the user has JavaScript turned off, it will follow the link and be sorted on the server side).

    Read the article

  • Sorting by value with ORDER BY?

    - by Kevin
    For clarification, are you able to use MySQL this way to sort? ORDER BY CompanyID = XXX DESC What I am trying to do is use one sql query to sort everything where X = Y, in this case, where CompanyID = XXX. All values where CompanyID is not XXX should come after all the results where CompanyID = XXX. I don't want to limit my query but I do want to sort a particular company above other listings.

    Read the article

  • Sorting a Singly Linked List With Pointers

    - by Mark Simson
    I am trying to sort a singly linked list using bubble sort by manipulating ONLY the pointers, no keys. The following gets stuck in the for loop and loops infinitely. I don't understand why this is. Can anybody explain to me why the end of the list is not being found? Node* sort_list(Node* head) { Node * temp; Node * curr; for(bool didSwap = true; didSwap; ) { didSwap = false; for(curr = head; curr->next != NULL; curr = curr->next) { if(curr->key > curr->next->key) { temp = curr; curr = curr->next; curr->next = temp; didSwap = true; } cout << curr->next->key << endl; } } return head; } If I change the code so that the keys (data) are swapped, then the function works properly but for some reason I am not able make it work by manipulating only pointers.

    Read the article

  • RadGrid nestedview sort makes nestedview disappear?

    - by lance
    When I click on the header of my detail table, it disappears entirely, leaving empty white space in the browser where it used to be. The Ajax postback caused by my clicking on the header does fire FooGridNeedDataSource and FooGridItemCommand, but I've used the debugger to skip the code inside those handlers (after clicking the header of the column I'm trying to sort, in the detail table), and I still get the same behavior. I'm hoping someone can tell me what I'm doing wrong? The MasterTableView sorts just fine (my real markup enables that with AllowSorting="true" on MasterTableView). <telerik:RadGrid ID="FooGrid" runat="server" AutoGenerateColumns="false" OnNeedDataSource="FooGridNeedDataSource" OnItemCommand="FooGridItemCommand" > <MasterTableView ClientDataKeyNames="FooData" DataKeyNames="FooData"> <Columns> <telerik:GridBoundColumn DataField="FooData" HeaderText="Foo"></telerik:GridBoundColumn> </Columns> <DetailTables> <telerik:GridTableView AllowSorting="true"> <Columns> <telerik:GridBoundColumn DataField="FooDetailData" HeaderText="Foo Detail" ></telerik:GridBoundColumn> </Columns> </telerik:GridTableView> </DetailTables> </MasterTableView> </telerik:RadGrid>

    Read the article

  • Disk Search / Sort Algorithm

    - by AlgoMan
    Given a Range of numbers say 1 to 10,000, Input is in random order. Constraint: At any point only 1000 numbers can be loaded to memory. Assumption: Assuming unique numbers. I propose the following efficient , "When-Required-sort Algorithm". We write the numbers into files which are designated to hold particular range of numbers. For example, File1 will have 0 - 999 , File2 will have 1000 - 1999 and so on in random order. If a particular number which is say "2535" is being searched for then we know that the number is in the file3 (Binary search over range to find the file). Then file3 is loaded to memory and sorted using say Quick sort (which is optimized to add insertion sort when the array size is small ) and then we search the number in this sorted array using Binary search. And when search is done we write back the sorted file. So in long run all the numbers will be sorted. Please comment on this proposal.

    Read the article

  • jqGrid: sort by index

    - by David__
    I am having trouble getting a column to sort by an index other than the 'name' value. In this case I am trying to sort the aggregation type column (values are days of the week) by the week order, rather than alphanumeric order. To do this I added an index column ('Aggregation type-index') that has the days of week an integers. However with this configuration, it fails to sort that column by index or name. Can someone point me the err in my ways? I posted all the js and css that is on the page, because I am also having two other issues, that if you notice the problem great, otherwise I'll keep hunting. I want to be able to enable the column reodering and be able to resize the grid (Both shown at http://trirand.com/blog/jqgrid/jqgrid.html under the new in 3.6 tab). Both options are not working either. <link rel="stylesheet" type="text/css" href="/static/latest_ui/themes/base/jquery.ui.all.css"/> <link rel="stylesheet" type="text/css" media="print" href="/static/css/print.css"/> <script src="/static/js/jquery-1.7.2.min.js" type="text/javascript"></script> <script src="/static/latest_ui/ui/jquery.ui.core.js"></script> <script src="/static/latest_ui/ui/jquery.ui.widget.js"></script> <script src="/static/latest_ui/ui/jquery.ui.position.js"></script> <script src="/static/latest_ui/ui/jquery.ui.button.js"></script> <script src="/static/latest_ui/ui/jquery.ui.menu.js"></script> <script src="/static/latest_ui/ui/jquery.ui.menubar.js"></script> <script src="/static/latest_ui/ui/jquery.ui.tabs.js"></script> <script src="/static/latest_ui/ui/jquery.ui.datepicker.js"></script> <script src="/static/js/custom.js"></script> <link rel="stylesheet" type="text/css" media="all" href="/static/css/custom_style.css" /> <link rel="stylesheet" type="text/css" media="all" href="/static/css/custom_colors.css" /> <link rel="stylesheet" type="text/css" media="screen" href="/static/css/ui.jqgrid.css" /> <body> <table id="grid_reports"></table> <div id='pager'></div> </body> <script src="/static/latest_ui/ui/jquery.ui.resizable.js"></script> <script src="/static/latest_ui/ui/jquery.ui.sortable.js"></script> <script src="/static/js/grid.locale-en.js" type="text/javascript"></script> <script src="/static/js/jquery.jqGrid.min.js" type="text/javascript"></script> <script src="/static/js/jqGrid_src/grid.jqueryui.js"></script> <script> $(function() { jQuery("#grid_reports").jqGrid({ sortable: true, datatype: "local", height: 500, width: 300, colNames:['Series', 'Agg Type', 'Days'], colModel:[{'index': 'By series', 'align': 'left', 'sorttype': 'text', 'name': 'By series', 'width': 65}, {'index': 'Aggregation type-index', 'align': 'left', 'sorttype': 'int', 'name': 'Aggregation type', 'width': 75}, {'index': 'Days since event', 'align': 'center', 'sorttype': 'text', 'name': 'Days since event', 'width': 50}], rowNum:50, pager: '#pager', sortname: 'Aggregation type', sortorder: 'desc', altRows: true, rowList:[20,50,100,500,10000], viewrecords: true, gridview: true, caption: "Report for 6/19/12" }); jQuery("#grid_reports").navGrid("#pager",{edit:false,add:false,del:false}); jQuery("#grid_reports").jqGrid('gridResize',{minWidth:60,maxWidth:2500,minHeight:80, maxHeight:2500}); var mydata = [{'Days since event': 132, 'Aggregation type': 'Date=Fri', 'By series': 'mean', 'Aggregation type-index': 5}, {'DIM at event': 178, 'Aggregation type': 'Date=Thu', 'By series': 'mean', 'Aggregation type-index': 4}, {'DIM at event': 172, 'Aggregation type': 'Date=Wed', 'By series': 'mean', 'Aggregation type-index': 3}, {'DIM at event': 146, 'Aggregation type': 'Date=Tue', 'By series': 'mean', 'Aggregation type-index': 2}, {'DIM at event': 132, 'Aggregation type': 'Date=Sat', 'By series': 'mean', 'Aggregation type-index': 6}, {'DIM at event': 162, 'Aggregation type': 'Date=Mon', 'By series': 'mean', 'Aggregation type-index': 1}, {'DIM at event': 139, 'Aggregation type': 'Date=Sun', 'By series': 'mean', 'Aggregation type-index': 0}]; for(var i=0;i<=mydata.length;i++) jQuery("#grid_reports").jqGrid('addRowData',i+1,mydata[i]); }); </script>

    Read the article

  • How is counting sort a stable sort?

    - by eSKay
    Suppose my input is (a,b and c to distinguish between equal keys) 1 6a 8 3 6b 0 6c 4 My counting sort will save as (discarding the a,b and c info!!) 0(1) 1(1) 3(1) 4(1) 6(3) 8(1) which will give me the result 0 1 3 4 6 6 6 8 So, how is this stable sort? I am not sure how it is "maintaining the relative order of records with equal keys." Please explain.

    Read the article

< Previous Page | 22 23 24 25 26 27 28 29 30 31 32 33  | Next Page >