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  • Django: Determining if a user has voted or not

    - by TheLizardKing
    I have a long list of links that I spit out using the below code, total votes, submitted by, the usual stuff but I am not 100% on how to determine if the currently logged in user has voted on a link or not. I know how to do this from within my view but do I need to alter my below view code or can I make use of the way templates work to determine it? I have read http://stackoverflow.com/questions/1528583/django-vote-up-down-method but I don't quite understand what's going on ( and don't need any ofjavascriptery). Models (snippet): class Link(models.Model): category = models.ForeignKey(Category, blank=False, default=1) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) url = models.URLField(max_length=1024, unique=True, verify_exists=True) name = models.CharField(max_length=512) def __unicode__(self): return u'%s (%s)' % (self.name, self.url) class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) def __unicode__(self): return u'%s vote for %s' % (self.user, self.link) Views (snippet): links = Link.objects.select_related().annotate(votes=Count('vote')).order_by('-created')

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  • Calling UITableViews delegate methods directly.

    - by RickiG
    Hi I was looking for a way to call the edit method directly. - (void)tableView:(UITableView *)theTableView commitEditingStyle:(UITableViewCellEditingStyle)editingStyle forRowAtIndexPath:(NSIndexPath *)indexPath I have all my logic for animating manipulated cells, removing from my model array etc. in this method. It is getting called when a user swipes, adds or rearranges, but I would like to call it manually/directly as a background thread changes my model. I have constructed an NSIndexPath like so: NSIndexPath *path = [NSIndexPath indexPathForRow:i inSection:1]; I just can't figure out how to call something like: [self.tableview commitEditingStyle:UITableViewCellEditingStyleDelete forRowAtIndexPath:path]; Do I need to gain access to the methods of this plain style UITableView in another way? Thanks:)

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  • How safe is the quicken encryption of files?

    - by jmvidal
    Quicken has a password-protection option where you type in a password and your file is encrypted. How good is this encryption and how does it depend on the length or complexity of my password? A google search reveals a lot of "quicken password recovery" programs, like this one, which make me feel like the password is just for keeping the really dumb criminals away, not the ones with large computers.

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  • Repository vs Data Access

    - by vdh_ant
    Hi guys In the context of the n-tier application, is there a difference between what you would consider your data access classes to be and your repositories? I tend to think yes but I just wanted to see what other thought. My thinking is that the job of the repository is just to contain and execute the raw query itself, where as the data access class would create the context, execute the repository (passing in the context), handle mapping the data model to the domain model and return the result back up... What do you guys think? Also do you see any of this changing in a Linq to XML scenario (assuming that you change the context for the relevant XDocument)? Cheers Anthony

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  • how to pass in dynamic data to decorators

    - by steve
    Hi, I am trying to write a base crud controller class that does the following: class BaseCrudController: model = "" field_validation = {} template_dir = "" @expose(self.template_dir) def new(self, *args, **kwargs) .... @validate(self.field_validation, error_handler=new) @expose() def post(self, *args, **kwargs): ... My intent is to have my controllers extend this base class, set the model, field_validation, and template locations, and am ready to go. Unfortunately, decorators (to my understanding), are interpreted when the function is defined. Hence it won't have access to instance's value. Is there a way to pass in dynamic data or values from the sub class? If not, I guess I could use override_template as a workaround to expose and set the template within the controller action. How would I go about validating the form within the controller action? Thanks, Steve

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  • Why would the first call to a KVC setter have an NSTextField instance as the argument?

    - by Stephen
    If I have a NSTextField bound through an NSObjectController to a model object, I would expect the setter of the model object to be called with an NSString as the argument, but instead, I receive the instance of the control that I am bound too the first time I am called. - (NSString *)property { NSLog(@"returning property"); return property; } - (void)setProperty:(NSString *)string { NSLog(@"recieved %@", string) } - (id) init { if (self = [super init]) { property = [[NSString alloc] initWithString:@"value"]; } NSLog(@"property is %@",property"); return self; } (The program doesn't run if you try anything in setProperty, because it tries to send NSString messages to string - which might be an NSTextField.) Console Output: 2010-05-12 14:19:14.096 Trouble[13108:10b] property is enter value 2010-05-12 14:19:14.100 Trouble[13108:10b] recieved <NSTextField: 0x1025210> 2010-05-12 14:19:14.106 Trouble[13108:10b] returning property

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  • Trying to understand MVC Models, Advice?

    - by Tyler
    I am writing my own MVC for the purpose of learning it. I have pretty much everything "down-pat" and my main stuff written besides models due to some trouble understanding them and lack of viable examples. Now, I've been told a model should reprecent a single row, someone told me, your model class should on update/insert and delete rows, anything that involves fetching a single or multiple rows - a "finder" class should be used. So... a) what is a finder class, b) how do I implement it in a useage example, c) Is what I've been told about models correct or is there a better way than "finders"? Advice is much appricated :)

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  • How to customize BsGridView to show links instead of BsButtonColumn?

    - by felipe.zkn
    Given the code below, I need to customize the third column to show two links instead of that BsButtonColumn. I didn't find any related documentation to get the answer. <?php $this->widget( 'bootstrap.widgets.BsGridView', array( 'id' => 'activity-translation-grid', 'dataProvider' => $model->search(), 'filter' => $model, 'columns' => array( 'id', 'name', array( 'class' => 'BsButtonColumn', ), ), ) ); ?>

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  • How do I fix "error 1004, 0, Unable to find property" in an Entity Framework 4 WinForms application?

    - by Ivan
    I've designed an EF4 model (quite complex inheritance, lots of small tables incl. multiple self-referencing), generated (table-per-type) a database and inserted some basic data manually. It works fine in an ASP.Net Dynamic Data Entities web application with full automatic scaffolding. But when in a WinForms application using the same model (I share it as a part of a class library) I construct a query and bind a combo box to it (the way it's shown here), I get an InnerException {"Internal .NET Framework Data Provider error 1004, 0, Unable to find property... I've found a question about the same problem here (incl. a sample to reproduce the error) but no answer. I use final Visual Studio 2010, no beta.

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  • How to create a test environnement on the production FTP

    - by Clement Herreman
    Hello, I'm currently working on a symfony webapp, which is already on production. To develop and add/delete/modify functionnality of the model, I work on my laptop, using symfony 'dev' environnemment. I test if everything work fine, then I pray a little and deploy it on the prod server (with all the risk of data error, like when I add new not null attributes on the model, prod server configuration special stuff, version of php/apache etc.). The problem is that I would like to setup a "staging" server, which would be a copy of the production server (same database, same configuration apache/php), so that, if the deployment goes bad, the production user stay untouched and working, only the staging server is down. But my client has only 1 FTP available. So, the question is : can I run 2 symfony project, with different models, on the same FTP ? Or is there another way to do what I want to do ? Thank you !

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  • How do I write a spec to verify the rendering of partials?

    - by TheDeeno
    I'm using rr and rspec. Also, I'm using the collection short hand for partial rendering. My question: How do I correctly fill out the the following spec? before(:each) do assigns[:models] = Array.new(10, stub(Model)) end it "should render the 'listing' partial for each model" do # help me write something that actually verifies this end I've tried a few examples from the rspec book, rspec docs, and rr docs. Everything I try seems to leave me with runtime errors in the test - not failed assertions. Rather than show all the transformations I've tried, I figured all I'd need if someone showed me one that actually worked. I'd be good to go from there.

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  • where should i encode this html data in an asp.net mvc site

    - by ooo
    here is my view code: <%=Model.HtmlData %> here is my controller code: public ActionResult GetPage() { ContentPageViewModel vm = new ContentPageViewModel(); vm.HtmlData = _htmlPageRepository.Get("key"); return View(vm); } my repository class basically queries a database table that has the fields: id, pageName, htmlContent the .Get() method passes in a pageName (or key) and returns the htmlContent value. Right now i have just started this (haven't persisted anything to the db yet) so i am not doing any explicit encoding in my code now. What is the best practice for where i need to do encoding (in the model, the controller, the view ??)

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  • Django admin output extra HTML in ModelSite

    - by VoteyDisciple
    Ultimately, I want to add an <iframe> to the display of a particular model on Django's admin page. Django is already rendering the form for this model correctly, but I want to add this <iframe> in addition to Django's form. The src attribute needs to involve the primary key for the currently-displayed record. I've learned how to properly override the change_form.html template through Django's documentation, and I can add markup to the right block, but I can't figure out how to access the primary key value. (No amount of determined Googling has helped at all.) Alternatively, is there a direct way to specify that I want to produce extra output in my ModelSite definition?

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  • Is Django's manage.py syncdb or South used to create the test database?

    - by Thierry Lam
    With Django 1.1.1 and South 0.62, running a test from the CLI usually have the following output: Creating table some_model Installing index for my_app.SomeModel model . ----- Ran 1 test in 1s OK After upgrading to South 0.7, the output is invoking South's migration: Creating table some_model Installing index for my_app.SomeModel model Migrating... Running migrations for my_app: - Migrating forwards to 0001_initial > my_app:0001_initial - Loading initial data for my_app Migrated: - my_app . ----- Ran 1 test in 1s OK To create the test DB, has the test always used South migration in the past(before South 0.7) even if the output is not explicitly being shown?

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  • binding to arraycollection does not work

    - by ron
    Hi, I am using flex SDK 3.5. I have model.as and in it i have an ArrayCollection (name it arr_mod) which is Bindable. From my mxml i link to this arr_mod in two ways: 1) in DataGrid i set dataprovider={arr_mode} ... 2) in Button i add new item to the arr_mod this way: 3) in textBox i want to add mx:TextBox text="{mySpecialCounterFunc(arr_mod)}" note that in the Script of mxml arr_mod is Bindable as well as in the class definition in model.as The problem is, that when clicking on button, mySpecialCounterFunc is not called! it should be called, since i use {} and this should listen to changes in arr_mod (a change that was made in the button should cause a new item to be added.. and than the listener to respond). While The DataGrid is updated correctly! Why??

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  • SelfReferenceProperty vs. ListProperty Google App Engine

    - by John
    Hi All, I am experimenting with the Google App Engine and have a question. For the sake of simplicity, let's say my app is modeling a computer network (a fairly large corporate network with 10,000 nodes). I am trying to model my Node class as follows: class Node(db.Model): name = db.StringProperty() neighbors = db.SelfReferenceProperty() Let's suppose, for a minute, that I cannot use a ListProperty(). Based on my experiments to date, I can assign only a single entity to 'neighbors' - and I cannot use the "virtual" collection (node_set) to access the list of Node neighbors. So... my questions are: Does SelfReferenceProperty limit you to a single entity that you can reference? If I instead use a ListProperty, I believe I am limited to 5,000 keys, which I need to exceed. Thoughts? Thanks, John

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  • which Server I have to buy?

    - by sri
    Hello, Recently i have registered startup (home office). My intension is to have virtual(company) server for LAMP website development(virtual). Initially thinking, 2-5 people will be logging virtually to the server. a. but not sure where to shop or what to shop. b. Should I go for my own Server or i have to share some server. c. If i have to go My Server, should I go with rack or tower model. d. which brand and model i have to buy. d. If I have to go with shared(cloud), not sure which is the best place It will be great help, if some one provide in site. Thanks in advance. Sri

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  • Grails: Property Null error

    - by richardhell
    I've a domain called Modulo with some properties and a Controller with a method that create a object from model and save it, when execute save the shell show this error: La propiedad [{0}] de la clase [{1}] no puede ser nulo But if i set the constraint nullable to true, the error show again. I think that i should not set this cosntraint. The model is linked to a mysql table with all properties except id allow null. I think I am not doing something wrong here. Any advice?? Domain: Modulo class Modulo { String nombre String icon String url //static constraint = { // url(nullable:true) //} } Controller: Example class ExampleController { def index = { def modulo = new Modulo( nombre:'xxx', icon:'xxx' ) if (modulo.save()){ println 'ok' }else{ modulo.errors.allErrors.each { println it.defaultMessage} } } } Thanks. José

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  • Windows partition and double operation system

    - by metdos
    I bought a notebook, Sony Vaio VPC-EB1M1E and I want to make partition and use both windows-7 and Linux(Ubuntu). Should I make partition from inside windows, or should make partition using recovery discs? There is windows-installer version of Ubuntu, should I use it, or should I install it separately? Thanks.

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  • Entity Framework How to specify paramter type in generated SQL (SQLServer 2005) Nvarchar vs Varchar

    - by Gratzy
    In entity framework I have an Entity 'Client' that was generated from a database. There is a property called 'Account' it is defined in the storage model as: <Property Name="Account" Type="char" Nullable="false" MaxLength="6" /> And in the Conceptual Model as: <Property Name="Account" Type="String" Nullable="false" /> When select statements are generated using a variable for Account i.e. where m.Account == myAccount... Entity Framework generates a paramaterized query with a paramater of type NVarchar(6). The problem is that the column in the table is data type of char(6). When this is executed there is a large performance hit because of the data type difference. Account is an index on the table and instead of using the index I believe an Index scan is done. Anyone know how to force EF to not use Unicode for the paramater and use Varchar(6) instead?

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  • jQuery autocomplete works with a local string but not when the same String is called off the server

    - by Ankur
    This is related to the question I asked at http://stackoverflow.com/questions/2802948/how-to-make-an-ajax-call-immediately-on-document-loading My code is: $(document).ready(function(){ $.ajax({ type: "GET", url: "../AutoComplete", success: function(data) { var dataArray = data; alert(dataArray); $("#example").autocomplete(dataArray); } }); }); The value that is printed in the alert is: "Manuscript|Text|Information Object|Basketball|Ball|Sporting Equipment|Tarantula|Spider|Australian Spider|Cricket Player|Medieval Artefact|Person|Sportsperson|Leonardo Da Vinci|Country|Language|Inventor|Priest|Electronics Manufacturer|Object|letter|Artefact|governance model|Organism|Animal".split("|"); If instead I do this: $(document).ready(function(){ $.ajax({ type: "GET", url: "../AutoComplete", success: function(data) { var dataArray = "Manuscript|Text|Information Object|Basketball|Ball|Sporting Equipment|Tarantula|Spider|Australian Spider|Cricket Player|Medieval Artefact|Person|Sportsperson|Leonardo Da Vinci|Country|Language|Inventor|Priest|Electronics Manufacturer|Object|letter|Artefact|governance model|Organism|Animal".split("|"); alert(dataArray); $("#example").autocomplete(dataArray); } }); }); It works fine?

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  • How does Rails find models and controllers? How can I get it to load more models?

    - by David
    I'm trying to create a non-ActiveRecord model in app/models/gamestate.rb. Then inside my controller (PlayController) I should be able to do GameState.new, right? No go: NameError (uninitialized constant PlayController::GameState): app/controllers/play_controller.rb:23:in `play' (at least in the development environment) But! If I do have a model called app/models/play.rb, then it's automatically loaded and I can do Play.new. So my question is: how does Rails know which classes to load? What sort of name mangling does it do to get from play#action to PlayController to app/controllers/play_controller.rb to app/models/play.rb? It seems awfully fragile, but maybe a better understanding of how this works would help. And finally, how can I get it to load app/models/gamestate.rb?

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  • How to allow users to customize a DAL

    - by rsteckly
    Hi, I'm working in ASP.NET in an application where often users want to add fields or change field names. I'd like to be able to have an xml schema in place that is parsed and a dynamic object model created from it that can be accessed throughout the application. My initial reaction is that this is not realistic. I think there is flexibility about the dynamic nature of it. I think the people I'm trying to build this for wouldn't mind recompiling. Even if the app recompiled, I don't know how to abstract away enough in my code access the data to allow for users changing property names, etc. How can you write LINQ when the properties might change? In short, there's two questions here: 1) is there a way to dynamically generate an object model of the database and 2) is there a way to abstract away enough so that code accessing the database doesn't break when properties change?

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  • undefined local variable or method 'acts_as_gmappable'

    - by MRJ
    I attempted to install the gmaps4rails gem. I added gem 'gmaps4rails' to my Gemfile, and ran 'bundle install. It said that my bundle installed successfully. I can find "Using gmaps4rails (0.8.8)" with 'gem list'. I added the specified columns to my users table with rake db:migrate and added acts_as_gmappable and the gmaps4rails_address method to my User model. Visiting pages that involve the user model gives me "undefined local variable or method 'acts_as_gmappable'"error. Is there something that I am missing? For greater context, the code I am using is from the Rails 3 Tutorial. OS X 10.6.6 ruby 1.8.7 rails 3.0.7 passenger 3.0.7

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  • adding hobby to a user

    - by rookieRailer
    I'm trying to write a rails application. I'm a ruby-on-rails newbie. I have a User model and a Hobby model. class User < ActiveRecord::Base has_many :hobbies end class Hobby < ActiveRecord::Base belongs_to :user end During the new user registration, I have used a text box where I enter a value for hobby. Then, when I press a button 'Add hobby', a method in UsersController add_hobby is to be called where I intend to append the value entered for hobby by user to the user i.e @user.hobbies << hobby However, my problem is that the user object has not been saved yet, so there is no way to access a particular user object. How do I get around this problem ?

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