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  • ASP.NET MVC UpdateModel - fields vs properties??

    - by mrjoltcola
    I refactored some common properties into a base class and immediately my model updates started failing. UpdateModel() and TryUpdateModel() did not seem to update inherited public properties. I cannot find detailed info on MSDN nor Google as to the rules or semantics of these methods. The docs are terse (http://msdn.microsoft.com/en-us/library/dd470933.aspx), simply stating: Updates the specified model instance using values from the controller's current value provider. SOLVED: MVC.NET does indeed handle inherited properties just fine. This turned out to have nothing to do with inheritance. My base class was implemented with public fields, not properties. Switching them to formal properties (adding {get; set; }) was all I needed. This has bitten me before, I keep wanting to use simple, public fields. I would argue that fields and properties are syntactically identical, and could be argued to be semantically equivalent, for the user of the class.

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  • Is there a recommended way to use the Observer pattern in MVP using GWT?

    - by Tomislav Nakic-Alfirevic
    I am thinking about implementing a user interface according to the MVP pattern using GWT, but have doubts about how to proceed. These are (some of) my goals: - the presenter knows nothing about the UI technology (i.e. uses nothing from com.google.*) - the view knows nothing about the model or the presenter - the model knows nothing of the view or the presenter (...obviously) I would place an interface between the view and the presenter and use the Observer pattern to decouple the two: the view generates events and the presenter gets notified. What confuses me is that java.util.Observer and java.util.Observable are not supported in GWT. This suggests that what I'm doing is not the recommended way to do it, as far as GWT is concerned, which leads me to my questions: what is the recommended way to implement MVP using GWT, specifically with the above goals in mind? How would you do it?

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  • Solving the water jug problem

    - by Amit
    While reading through some lecture notes on preliminary number theory, I came across the solution to water jug problem (with two jugs) which is summed as thus: Using the property of the G.C.D of two numbers that GCD(a,b) is the smallest possible linear combination of a and b, and hence a certain quantity Q is only measurable by the 2 jugs, iff Q is a n*GCD(a,b), since Q=sA + tB, where: n = a positive integer A = capacity of jug A B= capacity of jug B And, then the method to the solution is discussed Another model of the solution is to model the various states as a state-space search problem as often resorted to in Artificial Intelligence. My question is: What other known methods exist which models the solution, and how? Google didn't throw up much.

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  • Rest API Web Service - iOS

    - by zeekerg
    Its my first time to use web service in iOS. REST was my first choice and I use code igniter to form it. I have my Controller: require APPPATH.'/libraries/REST_Controller.php'; class Sample extends REST_Controller { function example_get() { $this->load->helper('arh'); $this->load->model('users'); $users_array = array(); $users = $this->users->get_all_users(); foreach($users as $user){ $new_array = array( 'id'=>$user->id , 'name'=>$user->name, 'age'=>$user->age, ); array_push( $users_array, $new_array); } $data['users'] = $users_array; if($data) { $this->response($data, 200); } } function user_put() { $this->load->model('users'); $this->users->insertAUser(); $message = array('message' => 'ADDED!'); $this->response($message, 200); } } , using my web browser, accessing the URL http://localhost:8888/restApi/index.php/sample/example/format/json really works fine and gives this output: {"users":[{"id":"1","name":"Porcopio","age":"99"},{"id":"2","name":"Name1","age":"24"},{"id":"3","name":"Porcopio","age":"99"},{"id":"4","name":"Porcopio","age":"99"},{"id":"5","name":"Luna","age":"99"}]} , this gives me a great output using RKRequest by RestKit in my app. The problem goes with the put method. This URL : http://localhost:8888/restApi/index.php/sample/user always give me an error like this: This XML file does not appear to have any style information associated with it. The document tree is shown below. <xml> <status/> <error>Unknown method.</error> This is my Users model <?php class Users extends CI_Model { function __construct() { parent::__construct(); } function get_all_users() { $this->load->database(); $query = $this->db->get('users'); return $query->result(); } function insertAUser(){ $this->load->database(); $data = array('name'=> "Sample Name", 'age'=>"99"); $this->db->insert('users', $data); } } ?> What is the work around for my _put method why am I not inserting anything? Thanks all!

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  • The Utilization of Software Engineering Development Principles

    - by Chance
    Being a CS student I've had to take a course in basic software engineering. I was a little curious to find such elaborate "software development processes", like the spiral model, the waterfall model, et cetera. Some of these methodologies seem a little antiquated to me and, after speaking with several employed developers, I can't seem to find anyone who actually adheres to these models. Does anyone here have experience working under the guidance of these models? Were they useful to you and your team during the development of your product? Or are these models just some way to communicate a sense of progression to interested parties outside of the development team?

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  • Saving jQuery UI Sortable's order to Backbone.js Collection

    - by VirtuosiMedia
    I have a Backbone.js collection that I would like to be able to sort using jQuery UI's Sortable. Nothing fancy, I just have a list that I would like to be able to sort. The problem is that I'm not sure how to get the current order of items after being sorted and communicate that to the collection. Sortable can serialize itself, but that won't give me the model data I need to give to the collection. Ideally, I'd like to be able to just get an array of the current order of the models in the collection and use the reset method for the collection, but I'm not sure how to get the current order. Please share any ideas or examples for getting an array with the current model order.

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  • Execution Plan Optimization when where clause is removed then added back

    - by nmushov
    I have a stored procedure that uses a table valued function which executes in 9 seconds. If I alter the table valued function and remove the where clause, the stored procedure executes in 3 seconds. If I add the where clause back, the query still executes in 3 seconds. I took a look at the execution plans and it appears that after I remove the where clause, the execution plan includes parallelism and the scan count for 2 of my tables drops for 50000 and 65000 down to 5 and 3. After I add the where clause back, the optimized execution plan still runs unless I run DBCC FREEPROCCACHE. Questions 1. Why would SQL Server start using the optimized execution plan for both queries only when I first remove the where clause? Is there a way to force SQL Server to use this execution plan? Also, this is a paramaterized all-in-one query that uses the (Parameter is null or Parameter) in the where clause, which I believe is bad for performance. RETURNS TABLE AS RETURN ( SELECT TOP (@PageNumber * @PageSize) CASE WHEN @SortOrder = 'Expensive' THEN ROW_NUMBER() OVER (ORDER BY SellingPrice DESC) WHEN @SortOrder = 'Inexpensive' THEN ROW_NUMBER() OVER (ORDER BY SellingPrice ASC) WHEN @SortOrder = 'LowMiles' THEN ROW_NUMBER() OVER (ORDER BY Mileage ASC) WHEN @SortOrder = 'HighMiles' THEN ROW_NUMBER() OVER (ORDER BY Mileage DESC) WHEN @SortOrder = 'Closest' THEN ROW_NUMBER() OVER (ORDER BY P1.Distance ASC) WHEN @SortOrder = 'Newest' THEN ROW_NUMBER() OVER (ORDER BY [Year] DESC) WHEN @SortOrder = 'Oldest' THEN ROW_NUMBER() OVER (ORDER BY [Year] ASC) ELSE ROW_NUMBER() OVER (ORDER BY InventoryID ASC) END as rn, P1.InventoryID, P1.SellingPrice, P1.Distance, P1.Mileage, Count(*) OVER () RESULT_COUNT, dimCarStatus.[year] FROM (SELECT InventoryID, SellingPrice, Zip.Distance, Mileage, ColorKey, CarStatusKey, CarKey FROM facInventory JOIN @ZipCodes Zip ON Zip.DealerKey = facInventory.DealerKey) as P1 JOIN dimColor ON dimColor.ColorKey = P1.ColorKey JOIN dimCarStatus ON dimCarStatus.CarStatusKey = P1.CarStatusKey JOIN dimCar ON dimCar.CarKey = P1.CarKey WHERE (@ExteriorColor is NULL OR dimColor.ExteriorColor like @ExteriorColor) AND (@InteriorColor is NULL OR dimColor.InteriorColor like @InteriorColor) AND (@Condition is NULL OR dimCarStatus.Condition like @Condition) AND (@Year is NULL OR dimCarStatus.[Year] like @Year) AND (@Certified is NULL OR dimCarStatus.Certified like @Certified) AND (@Make is NULL OR dimCar.Make like @Make) AND (@ModelCategory is NULL OR dimCar.ModelCategory like @ModelCategory) AND (@Model is NULL OR dimCar.Model like @Model) AND (@Trim is NULL OR dimCar.Trim like @Trim) AND (@BodyType is NULL OR dimCar.BodyType like @BodyType) AND (@VehicleTypeCode is NULL OR dimCar.VehicleTypeCode like @VehicleTypeCode) AND (@MinPrice is NULL OR P1.SellingPrice >= @MinPrice) AND (@MaxPrice is NULL OR P1.SellingPrice < @MaxPrice) AND (@Mileage is NULL OR P1.Mileage < @Mileage) ORDER BY CASE WHEN @SortOrder = 'Expensive' THEN -SellingPrice WHEN @SortOrder = 'Inexpensive' THEN SellingPrice WHEN @SortOrder = 'LowMiles' THEN Mileage WHEN @SortOrder = 'HighMiles' THEN -Mileage WHEN @SortOrder = 'Closest' THEN P1.Distance WHEN @SortOrder = 'Newest' THEN -[YEAR] WHEN @SortOrder = 'Oldest' THEN [YEAR] ELSE InventoryID END )

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  • Multiprogramming in Django, writing to the Database

    - by Marcus Whybrow
    Introduction I have the following code which checks to see if a similar model exists in the database, and if it does not it creates the new model: class BookProfile(): # ... def save(self, *args, **kwargs): uniqueConstraint = {'book_instance': self.book_instance, 'collection': self.collection} # Test for other objects with identical values profiles = BookProfile.objects.filter(Q(**uniqueConstraint) & ~Q(pk=self.pk)) # If none are found create the object, else fail. if len(profiles) == 0: super(BookProfile, self).save(*args, **kwargs) else: raise ValidationError('A Book Profile for that book instance in that collection already exists') I first build my constraints, then search for a model with those values which I am enforcing must be unique Q(**uniqueConstraint). In addition I ensure that if the save method is updating and not inserting, that we do not find this object when looking for other similar objects ~Q(pk=self.pk). I should mention that I ham implementing soft delete (with a modified objects manager which only shows non-deleted objects) which is why I must check for myself rather then relying on unique_together errors. Problem Right thats the introduction out of the way. My problem is that when multiple identical objects are saved in quick (or as near as simultaneous) succession, sometimes both get added even though the first being added should prevent the second. I have tested the code in the shell and it succeeds every time I run it. Thus my assumption is if say we have two objects being added Object A and Object B. Object A runs its check upon save() being called. Then the process saving Object B gets some time on the processor. Object B runs that same test, but Object A has not yet been added so Object B is added to the database. Then Object A regains control of the processor, and has allready run its test, even though identical Object B is in the database, it adds it regardless. My Thoughts The reason I fear multiprogramming could be involved is that each Object A and Object is being added through an API save view, so a request to the view is made for each save, thus not a single request with multiple sequential saves on objects. It might be the case that Apache is creating a process for each request, and thus causing the problems I think I am seeing. As you would expect, the problem only occurs sometimes, which is characteristic of multiprogramming or multiprocessing errors. If this is the case, is there a way to make the test and set parts of the save() method a critical section, so that a process switch cannot happen between the test and the set?

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  • Adding an IList item to a particular index number

    - by Dr. Zim
    Our Client's database returns a set of prices in an array, but they sometimes don't include all prices, i.e., they have missing elements in their array. We return what we find as an IList, which works great when we retrieve content from the database. However, we are having difficulties setting the elements in the proper position in the array. Is it possible to create an IList then add an element at a particular position in the IList? var myList = new List<Model>(); var myModel = new Model(); myList[3] = myModel; // Something like what we would want to do

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  • Backing up data stored on Amazon S3

    - by Fiver
    I have an EC2 instance running a web server that stores users' uploaded files to S3. The files are written once and never change, but are retrieved occasionally by the users. We will likely accumulate somewhere around 200-500GB of data per year. We would like to ensure this data is safe, particularly from accidental deletions and would like to be able to restore files that were deleted regardless of the reason. I have read about the versioning feature for S3 buckets, but I cannot seem to find if recovery is possible for files with no modification history. See the AWS docs here on versioning: http://docs.aws.amazon.com/AmazonS3/latest/dev/ObjectVersioning.html In those examples, they don't show the scenario where data is uploaded, but never modified, and then deleted. Are files deleted in this scenario recoverable? Then, we thought we may just backup the S3 files to Glacier using object lifecycle management: http://docs.aws.amazon.com/AmazonS3/latest/dev/object-lifecycle-mgmt.html But, it seems this will not work for us, as the file object is not copied to Glacier but moved to Glacier (more accurately it seems it is an object attribute that is changed, but anyway...). So it seems there is no direct way to backup S3 data, and transferring the data from S3 to local servers may be time-consuming and may incur significant transfer costs over time. Finally, we thought we would create a new bucket every month to serve as a monthly full backup, and copy the original bucket's data to the new one on Day 1. Then using something like duplicity (http://duplicity.nongnu.org/) we would synchronize the backup bucket every night. At the end of the month we would put the backup bucket's contents in Glacier storage, and create a new backup bucket using a new, current copy of the original bucket...and repeat this process. This seems like it would work and minimize the storage / transfer costs, but I'm not sure if duplicity allows bucket-to-bucket transfers directly without bringing data down to the controlling client first. So, I guess there are a couple questions here. First, does S3 versioning allow recovery of files that were never modified? Is there some way to "copy" files from S3 to Glacier that I have missed? Can duplicity or any other tool transfer files between S3 buckets directly to avoid transfer costs? Finally, am I way off the mark in my approach to backing up S3 data? Thanks in advance for any insight you could provide!

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  • How to get paperclip to delete files

    - by webdestroya
    I have a model that is using Paperclip to manage the file. After I delete the model, I obviously would like the file to be deleted as well, but I cannot seem to find out how to get the file deleted using Paperclip. I have tried self.sourcefile = nil if !sourcefile.dirty? in the before_destroy def, but that had no effect. (I want to be able to have it delete the file locally when I test, and then on S3 when I use that - So i need a pure paperclip solution) Any ideas?

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  • Django Multi-Table Inheritance VS Specifying Explicit OneToOne Relationship in Models

    - by chefsmart
    Hope all this makes sense :) I'll clarify via comments if necessary. Also, I am experimenting using bold text in this question, and will edit it out if I (or you) find it distracting. With that out of the way... Using django.contrib.auth gives us User and Group, among other useful things that I can't do without (like basic messaging). In my app I have several different types of users. A user can be of only one type. That would easily be handled by groups, with a little extra care. However, these different users are related to each other in hierarchies / relationships. Let's take a look at these users: - Principals - "top level" users Administrators - each administrator reports to a Principal Coordinators - each coordinator reports to an Administrator Apart from these there are other user types that are not directly related, but may get related later on. For example, "Company" is another type of user, and can have various "Products", and products may be supervised by a "Coordinator". "Buyer" is another kind of user that may buy products. Now all these users have various other attributes, some of which are common to all types of users and some of which are distinct only to one user type. For example, all types of users have to have an address. On the other hand, only the Principal user belongs to a "BranchOffice". Another point, which was stated above, is that a User can only ever be of one type. The app also needs to keep track of who created and/or modified Principals, Administrators, Coordinators, Companies, Products etc. (So that's two more links to the User model.) In this scenario, is it a good idea to use Django's multi-table inheritance as follows: - from django.contrib.auth.models import User class Principal(User): # # # branchoffice = models.ForeignKey(BranchOffice) landline = models.CharField(blank=True, max_length=20) mobile = models.CharField(blank=True, max_length=20) created_by = models.ForeignKey(User, editable=False, blank=True, related_name="principalcreator") modified_by = models.ForeignKey(User, editable=False, blank=True, related_name="principalmodifier") # # # Or should I go about doing it like this: - class Principal(models.Model): # # # user = models.OneToOneField(User, blank=True) branchoffice = models.ForeignKey(BranchOffice) landline = models.CharField(blank=True, max_length=20) mobile = models.CharField(blank=True, max_length=20) created_by = models.ForeignKey(User, editable=False, blank=True, related_name="principalcreator") modified_by = models.ForeignKey(User, editable=False, blank=True, related_name="principalmodifier") # # # Please keep in mind that there are other user types that are related via foreign keys, for example: - class Administrator(models.Model): # # # principal = models.ForeignKey(Principal, help_text="The supervising principal for this Administrator") user = models.OneToOneField(User, blank=True) province = models.ForeignKey( Province) landline = models.CharField(blank=True, max_length=20) mobile = models.CharField(blank=True, max_length=20) created_by = models.ForeignKey(User, editable=False, blank=True, related_name="administratorcreator") modified_by = models.ForeignKey(User, editable=False, blank=True, related_name="administratormodifier") I am aware that Django does use a one-to-one relationship for multi-table inheritance behind the scenes. I am just not qualified enough to decide which is a more sound approach.

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  • How to instanciate a class when its property members are not of primitive types?

    - by Richard77
    Hello, 1) Let's say I've a class MyDataInfo public class MyDataInfo { public int MyDataInfoID { get; set; } public string Name { get; set; } } For the purpose of the fuctionality I'm after, I've created another class (MyData) whose property members are of MyDataInfo type. 2) Here's myData public class MyData { public MyDataInfo Prop1 { get; set; } public MyDataInfo Prop2 { get; set; } } 3) And, here's my action method public ActionResult MyAction() { MyData myObject = new MyData(); return View(myObject); } 4) Finally, this in my View template (which is strongly typed and inherits from MyData) <% = Html.Encode (Model.Prop1.Name)%> <% = Html.Encode (Model.Prop2.Name)%> Unfortunately, I got an error "Object not set to an instance of an object." Am I missing something or is there a different way of obtaining the same result? Thanks for helping

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  • MacRuby + Interface Builder: How to display, then close, then display a window again

    - by Derick Bailey
    I'm a complete n00b with MacRuby and Cocoa, though I've got more than a year of Ruby experience, so keep that in mind when answering - I need lots of details and explanation. :) I've set up a simple project that has 2 windows in it, both of which are built with Interface Builder. The first window is a simple list of accounts using a table view. It has a "+" button below the table. When I click the + button, I want to show an "Add New Account" window. I also have an AccountsController < NSWindowController and a AddNewAccountController class, set up as the delegates for these windows, with the appropriate button click methods wired up, and outlets to reference the needed windows. When I click the "+" button in the Accounts window, I have this code fire: @add_account.center @add_account.display @add_account.makeKeyAndOrderFront(nil) @add_account.orderFrontRegardless this works great the first time I click the + button. Everything shows up, I'm able to enter my data and have it bind to my model. however, when I close the add new account form, things start going bad. if I set the add new account window to release on close, then the second time I click the + button, the window will still pop up but it's frozen. i can't click any buttons, enter any data, or even close the form. i assume this is because the form's code has been released, so there is no message loop processing the form... but i'm not entirely sure about this. if i set the add new account window to not release on close, then the second time i click the + button, the window shows up fine and it is usable - but it still has all the data that i had previously entered... it's still bound to my previous Account class instance. what am I doing wrong? what's the correct way to create a new instance of the Add New Account form, create a new Account model, bind that model to the form and show the form, when I click the + button on the Accounts form? ... this is all being done on OSX 10.6.6, 64bit, with XCode 3.2.4

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  • Windows 7 boot problem

    - by nijikunai
    My system doesn't boot at all, upon starting it takes me to the Windows Error Recovery screen saying "Windows failed to start, a recent software or hardware change might be the cause" and gives two options Launch System Repair (Recommended) Start Windows normally But neither options work, upon clicking either of them, some progress bars get displayed and the screen just freezes on "Starting Windows". I tried booting from the Windows 7 disk but it too freezes on the "Starting Windows" screen. I even tried booting from ubuntu, slax linux, but they don't work too.

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  • Reading Ontology with Jena, feeding it with RDF triples, and producing correct RDF string output.

    - by JonB
    Hi, I have an ontology, which I read in with Jena to help me scrape some RDFa triples from a website. I don't currently store these triples in a Jena model, but that is fairly straight forward to do, its on my to do next list. The area I am struggling with, though, is to get Jena to output correct RDF for the ontology I have. The ontology uses Owl and RDFS definitions, but when I pass some example triples into the model, they don't appear correctly. Almost as if it doesn't know anything about the ontology. The output is, however, still valid RDF, just it's not coming out in the form I was hoping for. Am I correct in thinking that Jena should be able to produce well written RDF (not just valid) about the triples I have collected, based on the ontology or does this out stretch what it is capable of? Many thanks for any input.

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  • How to validate a ComboBox programatically?

    - by PhOeNiX
    How can i validate a ComboBox for null entry? My combobox is in a model as i am generating it dynamically. Now what i want is that when the the columns are generated dynamically, the border of combobox should be red as no value is selected and once the value is selected the border shud become normal. The following is my combobox in model : DataGridTemplateColumn dataGridComboBoxTemplateColumnObj = new DataGridTemplateColumn(); dataGridComboBoxTemplateColumnObj.Header = column.Header; FrameworkElementFactory comboBoxFactory = new FrameworkElementFactory(typeof(ComboBox)); Binding bindingItemSourceObj = new Binding(column.ItemsSourcePropertyName); comboBoxFactory.SetValue(ComboBox.HorizontalAlignmentProperty, HorizontalAlignment.Stretch); comboBoxFactory.SetValue(ComboBox.ItemsSourceProperty, bindingItemSourceObj); comboBoxFactory.SetValue(ComboBox.SelectedValuePathProperty, column.ValuePropertyName); dataGridComboBoxTemplateColumnObj.CellTemplate = new DataTemplate(); dataGridComboBoxTemplateColumnObj.CellTemplate.VisualTree = comboBoxFactory;

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  • django generic view not recieving an object (template issue?)

    - by Kirby
    My Model class Player(models.Model): player_name = models.CharField(max_length=50) player_email = models.CharField(max_length=50) def __unicode__(self): return self.player_name My Root urls.py urlpatterns = patterns('', (r'^kroster/', include('djangosite.kroster.urls')), (r'^admin/(.*)', admin.site.root), ) My kroster urls.py from djangosite.kroster.models import Player info_dict = { 'queryset': Player.objects.all(), } urlpatterns = patterns('', (r'^$', 'django.views.generic.list_detail.object_list', info_dict), (r'^(?P<object_id>\d+)/$', 'django.views.generic.list_detail.object_detail', info_dict), ) My player_list.html template <h1>Player List</h1> {% if error_message %}<p><strong>{{ error_message }}</strong></p>{% endif %} <ul> {% for player in object.player_set.all %} <li id="{{ player.id }}">{{ forloop.counter }} .)&nbsp;&nbsp;{{ player }}</li> {% endfor %} </ul> Sadly my template output is this. <h1>Player List</h1> <ul> </ul> Apologies if this is a stupid mistake. It has to be something wrong w/ my template.

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  • ASP.Net MVC Outbound Route Matching Problem When Using ActionLink

    - by Godders
    Hi there, Hoping for some help after reading into MVC routing and not coming up with the answer myself. I have the following routes registered: public static void RegisterRoutes(RouteCollection routes) { routes.IgnoreRoute("{resource}.axd/{*pathInfo}"); routes.MapRoute( null, "YourFeedback/Article/{resourceId}", new { controller = "YourFeedback", action = "Index", contentTypeId = new Guid(ConfigurationManager.AppSettings["ArticleLibraryId"]) }); routes.MapRoute( "Default", // Route name "{controller}/{action}/{id}", // URL with parameters new { controller = "Home", action = "Index", id = "" } // Parameter defaults ); } I have the following ActionLink in an aspx view: <%=Html.ActionLink("Your Feedback", "Article", "YourFeedback", new { resourceId = Model.ContentId.ResourceId }, new { @class = "yourFeedback" })%> My understanding of MVC routing is that this would render a anchor link with href of "/YourFeedback/Article/101" where 101 comes from Model.ContentId.ResourceId. Yet the anchor link href is rendered as "YourFeedback/Article/resourceId=101". Any ideas where I'm going wrong? Thanks in advance.

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  • Can I assign the value like this?

    - by kumar
    Exactly I ned to do something like this is this possible? <% var Controller = null; if (Model.ID== "ABC") { Controller = "Name"; } else { Controller = "Detail"; } %> <% using (Html.BeginForm("edit", Controller, FormMethod.Post, new { @id="exc-" + Model.SID})) {%> <%= Html.Summary(true)%> is this possible? if i do I am getting exception... ERROR: Cannot assign to an implicitly-typed local variable

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  • nested form & habtm

    - by brewster
    so i am trying to save to a join table in a habtm relationship, but i am having problems. from my view, i pass in a group id with: = link_to "Create New User", new_user_url(:group => 1) User model (user.rb) class User < ActiveRecord::Base has_and_belongs_to_many :user_groups accepts_nested_attributes_for :user_groups end UserGroups model (user_groups.rb) class UserGroup < ActiveRecord::Base has_and_belongs_to_many :users end users_controller.rb def new @user = User.new(:user_group_ids => params[:group]) end in the new user view, i have access to the User.user_groups object, however when i submit the form, not only does it not save into my join table (user_groups_users), but the object is no longer there. all the other objects & attributes of my User object are persistent except for the user group. i just started learning rails, so maybe i am missing something conceptually here, but i have been really struggling with this.

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  • How do I get the position of a result in the list after an order_by?

    - by Bob Bob
    I'm trying to find an efficient way to find the rank of an object in the database related to it's score. My naive solution looks like this: rank = 0 for q in Model.objects.all().order_by('score'): if q.name == 'searching_for_this' return rank rank += 1 It should be possible to get the database to do the filtering, using order_by: Model.objects.all().order_by('score').filter(name='searching_for_this') But there doesn't seem to be a way to retrieve the index for the order_by step after the filter. Is there a better way to do this? (Using python/django and/or raw SQL.) My next thought is to pre-compute ranks on insert but that seems messy.

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