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  • How to enable mysqli extension on redhat?

    - by nuthan
    My php.ini says: Additional .ini files parsed /etc/php53/php.d/curl.ini, /etc/php53/php.d/fileinfo.ini, /etc/php53/php.d/json.ini, /etc/php53/php.d/mysqli.ini, /etc/php53/php.d/mysql.ini, /etc/php53/php.d/pdo_mysql.ini, /etc/php53/php.d/phar.ini, /etc/php53/php.d/zip.ini mysqli.ini is loaded.. But still i get this, PHP Fatal error: Class 'mysqli' not found i tried enabling dynamic loading and initialize php scripts with dl("mysqli.so"); i also tried recompiling the php source: ./configure --with-mysql=/usr/lib64/mysql --with- mysqli=/usr/lib64/mysql/mysql_config even this didn't work. Can anybody help me solve my problem? Red Hat Enterprise Linux Server release 5 (Tikanga). x86_64 GNU/Linux. No access to RHN. Thanks.

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  • Very simply, how can check if a user exists against my MySQL database?

    - by Sergio Tapia
    Here's what I have but nothing is output to the screen. :\ <html> <head> </head> <body> <? mysql_connect(localhost, "sergio", "123"); @mysql_select_db("multas") or die( "Unable to select database"); $query="SELECT * FROM usuario"; $result=mysql_query($query); $num=mysql_numrows($result); $i=0; $username=GET["u"]; $password=GET["p"]; while ($i < $num) { $dbusername=mysql_result($result,$i,"username"); $dbpassword=mysql_result($result,$i,"password"); if(($username == $dbusername) && ($password == $dbpassword)){ echo "si"; } $i++; } ?> </body> </html> I'm iterating through all users and seeing if there is a match for user && password. Any guidance?

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  • Possible to open a text file in a MYSQL stored procedure?

    - by futureelite7
    Is it possible to open and read from a text file in a MYSQL stored procedure? I have a text file with a list of about 50k telephone numbers, and want to write a stored procedure that will open the file, read the 50k lines and store it as rows in a table. I cannot load the file directly using LOAD IN FILE as the table has additional columns that I have to set. Thanks!

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  • cPanel web server redundancy advice?

    - by crgnz
    At present I operate a (reasonably low volume) web-hosting service with a Centos 5.3 server running cPanel/WHM. I would like to implement a level of redundancy such that in the event of server failure, I can restore service with a minimum of effort in less than 60 minutes. I also want to setup a secondary DNS that cPanel will replicate with. My current idea is to kill two birds with one stone by: My current server is called "www1" Purchase an identical server (HP DL360 G4) with mirrored disks. Call this server "www2" Install Centos 5.4 (or perhaps I should install 5.3 to be identical with www1) Install cPanel/WHM on this server and fully license it Setup www1 and www2 cPanel to replicate DNS with each other Setup a nightly replication script that does the following: a) rsync's the /home directory from www1 to www2 b) dumps all MySQL databases on www1 and copies them to a temp folder (with root access only) on www2 c) triggers a script to run on www2 that restores the MySQL dumps Thus each night a fully working copy of all the websites and MySQL databases is copied to www2. I do not have enough knowledge of MySQL replication to understand if it works safely and transparently with cPanel. Thus I propose the mysql dump/copy/restore due to not knowing any better! In the event that www1 dies a horrible death, I envisage that I could login to www2, change the IP addresses to those that www1 had, and presto, the websites are available again. The advantage of this idea is that it is fairly simple and "low tech" and thus does not require an expert sysadmin to setup and monitor (I am NOT an expert sysadmin) The disadvantage of this idea is that up to a full days worth of data changes would be lost. I think this would be acceptable to the sorts of customers I host at the moment. The other disadvantage would be having to pay for a full cPanel license, but I am comfortable with that cost, so for now all I want to discuss are technical considerations. Is this a sound scheme?

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  • How do I Handle Ties When Ranking Results in MySQL?

    - by Laxmidi
    Hi, How does one handle ties when ranking results in a mysql query? I've simplified the table names and columns in this example, but it should illustrate my problem: SET @rank=0; SELECT student_names.students, @rank := @rank +1 AS rank, scores.grades FROM student_names LEFT JOIN scores ON student_names.students = scores.students ORDER BY scores.grades DESC So imagine the the above query produces: Students Rank Grades Al 1 90 Amy 2 90 George 3 78 Bob 4 73 Mary 5 NULL William 6 NULL Even though Al and Amy have the same grade, one is ranked higher than the other. Amy got ripped-off. How can I make it so that Amy and Al have the same ranking, so that they both have a rank of 1. Also, William and Mary didn't take the test. They bagged class and were smoking in the boy's room. They should be tied for last place. The correct ranking should be: Students Rank Grades Al 1 90 Amy 1 90 George 3 78 Bob 4 73 Mary 5 NULL William 5 NULL If anyone has any advice, please let me know. Thank you! -Laxmidi

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  • Why does this pdo::mysql code crash on windows??

    - by user154107
    Why does this pdo::mysql code crash on windows??? <?php $username = "root"; $password = ""; try { $dsn = "mysql:host=localhost;dbname=employees"; $dbh = new PDO($dsn, $username, $password); $dbh->setAttribute(PDO::ATTR_EMULATE_PREPARES, FALSE); $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); echo "Connected to database<br />" ; $dbh->exec("DROP TABLE IF EXISTS vCard;"); $dbh->exec("DROP TABLE IF EXISTS emp;"); $table = "CREATE TABLE vCard( id INT(4) NOT NULL PRIMARY KEY, firstName VARCHAR (255), lastName VARCHAR (255), office VARCHAR (255), homePh VARCHAR (13), mobilePh VARCHAR (13))"; $dbh->exec($table); $dbh->beginTransaction(); $dbh->exec("INSERT INTO vCard(id, firstName, lastName, office, homePh, mobilePh) VALUES (4834, 'Randy', 'Lewis', 'SR. Front End Developer', '631-842-3375', '917-435-2245');"); $dbh->exec("INSERT INTO vCard(id, firstName, lastName, office, homePh, mobilePh) VALUES (0766, 'Frank', 'LaGuy', 'Graphic Designer', '631-789-8244', '917-324-9897');"); $dbh->exec("INSERT INTO vCard(id, firstName, lastName, office, homePh, mobilePh) VALUES (6684, 'Donnie', 'Dolemite', 'COO', '631-789-9482', '917-234-1222');"); $dbh->exec("INSERT INTO vCard(id, firstName, lastName, office, homePh, mobilePh) VALUES (8569, '', 'McLovin', 'Actor', '631-842-9786', '917-987-8944');"); $dbh->commit(); echo "Data entered successfully<br/><br/>"; $sql = "SELECT * FROM vCard"; // WHERE firstName = 'Donnie'"; $results = $dbh->query($sql); foreach ($results as $id){ echo "SSN: ". $id['id']." "; echo "First Name: ". $id['firstName']." "; echo "Last Name: ". $id['lastName']."<br/>"; } } catch (PDOException $e) { echo "Failed: " . $e->getMessage(); $dbh->rollback(); } ?> basically this line of code is what triggers Apache to crash.. $sql = "SELECT * FROM vCard"; If I try to select one value like 'id' it'll ... when I try to select more than one value "*" it crashes??????

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  • Can you notice what's wrong with my PHP or MYSQL code?

    - by Jenna
    I am trying to create a category menu with sub categories. I have the following MySQL table: -- -- Table structure for table `categories` -- CREATE TABLE IF NOT EXISTS `categories` ( `ID` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(1000) NOT NULL, `slug` varchar(1000) NOT NULL, `parent` int(11) NOT NULL, `type` varchar(255) NOT NULL, PRIMARY KEY (`ID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=66 ; -- -- Dumping data for table `categories` -- INSERT INTO `categories` (`ID`, `name`, `slug`, `parent`, `type`) VALUES (63, 'Party', '/category/party/', 0, ''), (62, 'Kitchen', '/category/kitchen/', 61, 'sub'), (59, 'Animals', '/category/animals/', 0, ''), (64, 'Pets', '/category/pets/', 59, 'sub'), (61, 'Rooms', '/category/rooms/', 0, ''), (65, 'Zoo Creatures', '/category/zoo-creatures/', 59, 'sub'); And the following PHP: <?php include("connect.php"); echo "<ul>"; $query = mysql_query("SELECT * FROM categories"); while ($row = mysql_fetch_assoc($query)) { $catId = $row['id']; $catName = $row['name']; $catSlug = $row['slug']; $parent = $row['parent']; $type = $row['type']; if ($type == "sub") { $select = mysql_query("SELECT name FROM categories WHERE ID = $parent"); while ($row = mysql_fetch_assoc($select)) { $parentName = $row['name']; } echo "<li>$parentName >> $catName</li>"; } else if ($type == "") { echo "<li>$catName</li>"; } } echo "</ul>"; ?> Now Here's the Problem, It displays this: * Party * Rooms >> Kitchen * Animals * Animals >> Pets * Rooms * Animals >> Zoo Creatures I want it to display this: * Party * Rooms >> Kitchen * Animals >> Pets >> Zoo Creatures Is there something wrong with my loop? I just can't figure it out.

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  • Query by datetime in JDOQL / Java / GAE

    - by Jan Kuboschek
    I'm working on a GAE app. I want to query datastore and retrieve all records between startDate and endDate. Each record has a datetime field. I'm using a query similar to this (the below code is something I quickly grabbed - I'm not near my developer machine.): Query query = pm.newQuery(Employee.class); query.setFilter("lastName == lastNameParam"); query.setOrdering("hireDate desc"); query.declareParameters("String lastNameParam"); try { List results = (List) query.execute("Smith"); if (results.iterator().hasNext()) { for (Employee e : results) { // ... } } else { // ... no results ... } } finally { query.closeAll(); } How do I have to format the date to form a correctly working query? How is the datetime stamp stored in datastore? As timestamp? Fully formatted? I can't find ANY information on this. Please help.

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  • What's the best way to store a MySQL database in source control?

    - by Marplesoft
    I am working on an application with a few other people and we'd like to store our MySQL database in source control. My thoughts are two have two files: one would be the create script for the tables, etc, and the other would be the inserts for our sample data. Is this a good approach? Also, what's the best way to export this information? Also, any suggestions for workflow in terms of ways to speed up the process of making changes, exporting, updating, etc.

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  • Help with mysql sum and group query and managing jquery graph results.

    - by Scarface
    Hey guys, I have a system I am trying to design that will retrieve information from a database, so that it can be plotted in a jquery graph. I need to retrieve the information and somehow put it in the necessary format (for example two coordinates var d = [[1269417600000, 10],[1269504000000, 15]];). My table that I am selecting from is a table that stores user votes with fields: points_id (1=vote up ,2=vote down), user_id, timestamp, and topic_id. What I need to do is select all the votes and somehow group them into respective days and then sum the difference between 1 votes and 2 votes for each day. I then need to somehow display the data in the appropriate plotting format shown earlier. For example April 1, 4 votes. The data needs to be separated by commas, except the last plot entry, so I am not sure how to approach that. I showed an example below of the kind of thing I need but it is not correct, echo "var d=["; $query=mysql_query("SELECT *, SUM(IF(points_id = \"1\", 1,0))-SUM(IF([points_id = \"2\", 1,0)) AS 'total' FROM points LEFT JOIN topic on topic.topic_id=points.topic_id WHERE topic.creator='$user' GROUP by timestamp HAVING certain time interval"); while ($row=mysql_fetch_assoc($query)){ $timestamp=$row['timestamp']; $votes=$row['total']; echo "[$timestamp,$vote],"; } echo "];";

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  • How to query two tables based on whether or not record exists in a third?

    - by Katherine
    I have three tables, the first two fairly standard: 1) PRODUCTS table: pid pname, etc 2) CART table: cart_id cart_pid cart_orderid etc The third is designed to let people save products they buy and keep notes on them. 3) MYPRODUCTS table: myprod_id myprod_pid PRODUCTS.prod_id = CART.cart_prodid = MYPRODUCTS.myprod_pid When a user orders, they are presented with a list of products on their order, and can optionally add that product to myproducts. I am getting the info necessary for them to do this, with a query something like this for each order: SELECT cart.pid, products.pname, products.pid FROM products, cart WHERE products.pid = cart_prodid AND cart_orderid=orderid This is fine the first time they order. However, if they subsequently reorder a product which they have already added to myproducts, then it should NOT be possible for them to add it to myproducts again - basically instead of 'Add to MyProducts' they need to see 'View in MyProducts'. I am thinking I can separate the products using two queries: Products never added to MyProducts By somehow identifying whether the user has the product in MyProducts already, and if so excluding it from the query above. Products already in MyProducts By reversing the process above. I need some pointers on how to do this though.

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  • What's the different between these 2 mysql queries? one using left join

    - by Lyon
    Hi, I see people using LEFT JOIN in their mysql queries to fetch data from two tables. But I normally do it without left join. Is there any differences besides the syntax, e.g. performance? Here's my normal query style: SELECT * FROM table1 as tbl1, table2 as tbl2 WHERE tbl1.id=tbl2.table_id as compared to SELECT * FROM table1 as tbl1 LEFT JOIN table2 as tbl2 on tbl1.id=tbl2.id Personally I prefer the first style...hmm..

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  • NHibernate Query object collection issue

    - by Mahesh
    Hi, I am new to NHibernate and need some information regarding the internal working of the engine: I have a table called Student and the design is as follows: RollNo Name City Postcode and there are 5 more columns like this. I have School class and mappings associated with it. I am querying RollNo and Name using session as given below: IQuery query = session.CreateQuery("SELECT RollNo,Name FROM Student); Executing query.List resulting in error because the query is returning object[][]. Now, I changed the query as given below: IQuery query = session.CreateQuery("FROM Student); Executing query.List on this query yeilds the desired results. But, the results contain more data than I want. Could you please let me know the query to which I can get RollNo and Name from Student and castable as Student collection. Thanks, Mahesh

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  • What should a Django user know when moving from MySQL to PostgreSQL?

    - by tmitchell
    Most of my experience with Django thus far has been with MySQL and mysqldb. For a new app I'm writing, I'm dipping my toe in the PostgreSQL water, now that I have seen the light. While writing a data import script, I stumbled upon an issue with the default autocommit behavior. I would guess there are other "gotchas" that might crop up. What else should I be on the lookout for?

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  • why this left join query failed to load all the data in left table ?

    - by lzyy
    users table +-----+-----------+ | id | username | +-----+-----------+ | 1 | tom | | 2 | jelly | | 3 | foo | | 4 | bar | +-----+-----------+ groups table +----+---------+-----------------------------+ | id | user_id | title | +----+---------+-----------------------------+ | 2 | 1 | title 1 | | 4 | 1 | title 2 | +----+---------+-----------------------------+ the query SELECT users.username,users.id,count(groups.title) as group_count FROM users LEFT JOIN groups ON users.id = groups.user_id result +----------+----+-------------+ | username | id | group_count | +----------+----+-------------+ | tom | 1 | 2 | +----------+----+-------------+ where is the rest users' info? the result is the same as inner join , shouldn't left join return all left table's data? PS:I'm using mysql

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  • PHP next MySQL row - how to move pointer until function checks true?

    - by ropbhardgood
    I have a PHP script which takes a value from a row in my MySQL database, runs it through a function, and if it determines it's true returns one value, and if it's false, it needs to go to the next value in the database and check that one until eventually one returns true. I think I need to use mysql_fetch_assoc, but I'm not really sure in what way to use it... I wish I could post my code to be more specific, but it's a lot of code and most of it has no bearing on this issue...

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