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  • Multi-client C# ODBC (Sybase/Oracle/MSSQL) table access question.

    - by Hamish Grubijan
    I am working on a feature that would allow clients pick a unique identifier (ci_name). The code below is a generic version that gets expanded to the right sql depending on the vendor. Hopefully it makes sense. #include "sql.h" create table client_identification ( ci_id TYPE_ID IDENTITY, ci_name varchar(64) not null, constraint ci_pk primary key (ci_name) ); go CREATE_SEQUENCE(ci_id) There will be simple stored procedures for adding, retrieving, and deleting these user records. This will be used by several admins. This will not happen very frequently, but there is still a possibility that something will be added or deleted since the list was initially retrieved. I have not yet decided if I need to detect the case of a double delete, but the user name cannot be created twice - primary key constraint will object. I want to be able to detect this particular case and display something like: "you snooze - you loose." :) I would like to leverage the pk constraint instead of doing some extra sql gymnastics. So, how can I detect this case cleanly, so that it works in MS SQL 2008, Sybase, and Oracle? I hope to do better than catch a general ODBC exception and parse out the text and look for what Sybase, Oracle, and MSSQL would give me back. Oracle is a little different. We actually prepend these variables to the Oracle version of stored procedures because they are not available otherwise: Vret_val out number, Vtran_count in out number, Vmessage_count in out number, Thanks. General helpful tips and comments are welcome, except for naming convention ones ( I do not have a choice here, plus I mangled the actual names a bit).

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  • How can I use rows in a lookup table as columns in a MySQL query?

    - by TomH
    I'm trying to build a MySQL query that uses the rows in a lookup table as the columns in my result set. LookupTable id | AnalysisString 1 | color 2 | size 3 | weight 4 | speed ScoreTable id | lookupID | score | customerID 1 | 1 | A | 1 2 | 2 | C | 1 3 | 4 | B | 1 4 | 2 | A | 2 5 | 3 | A | 2 6 | 1 | A | 3 7 | 2 | F | 3 I'd like a query that would use the relevant lookupTable rows as columns in a query so that I can get a result like this: customerID | color | size | weight | speed 1 A C D 2 A A 3 A F The kicker of the problem is that there may be additional rows added to the LookupTable and the query should be dynamic and not have the Lookup IDs hardcoded. That is, this will work: SELECT st.customerID, (SELECT st1.score FROM ScoreTable st1 WHERE lookupID=1 AND st.customerID = st1.customerID) AS color, (SELECT st1.score FROM ScoreTable st1 WHERE lookupID=2 AND st.customerID = st1.customerID) AS size, (SELECT st1.score FROM ScoreTable st1 WHERE lookupID=3 AND st.customerID = st1.customerID) AS weight, (SELECT st1.score FROM ScoreTable st1 WHERE lookupID=4 AND st.customerID = st1.customerID) AS speed FROM ScoreTable st GROUP BY st.customerID Until there is a fifth row added to the LookupTable . . . Perhaps I'm breaking the whole relational model and will have to resolve this in the backend PHP code? Thanks for pointers/guidance. tom

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  • Is it reasonable to make a RAID-1 array with a ram disk and a physical disk to maximize read performance and protect data?

    - by Petr Pudlák
    In one of the answers on SO (I forgot which one) I've seen a suggestion to make a RAID-1 array composed of a RAM disk and a physical partition. By adding the physical partition with --write-mostly and enabling --write-behind the system should read everything instantly from the RAM disk but still save all data to the physical partition so that the data are preserved and the RAID array can be assembled again after reboot. Is such a setup reasonable? Will it perform any better in some scenario than having just the physical partition and perhaps tweaking the kernel to favor disk cache (swappiness and vfs_cache_pressure)?

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  • how to diffrentiate between same field names of two tables in a select query??

    - by developer
    i have more than two tables in my database and all of them contains same field names like table A table B table C field1 field1 field1 field2 field2 field2 field3 field3 field3 . . . . . . . . . . . . I have to write a SELECT query which gets almost all same fields from these 3 tables.Iam using something like this :- select a.field1,a.field2,a.field3,b.field1,b.field2,b.field3,c.field1,c.field2,c.field3 from table A as a, table B as b,table C as c where so and so. but when i print field1's value it gives me the last table values. How can i get all the values of three tables with the same field names??? do i have to write individual query for every table OR there is any ways of fetching them all in a single query????

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  • Fluent NHibernate: Example of a one-to-many relationship on an abstract class of a table-per-subclas

    - by BigTommy79
    Hi All, I've been trying for ages to find an example (because I can't get it to work myself) of the correct mapping for a one-to-many relationship on an abstract class of a table-per-subclass implementation, in fluent nHibernate. An example below: I'm looking to map the list of Fines on the Debt abstract base class to the Fine class. if anyone knows of any tutorial or example they've come across before please let me know. Thanks, Tim public abstract class Entity { public int Id { get; set; } } public abstract class Debt : Entity { public decimal Balance { get; set; } public IList<Fine> Fines { get; set; } public Debt() { Fines = new List<Fine>(); } } public class CarLoan : Debt { } public class CreditCard : Debt { } public class LoanApplication : Entity { public IList<Debt> ExistingDebts { get; set; } public LoanApplication() { ExistingDebts = new List<Debt>(); } } public class Fine { public Int64 Cash { get; set; } }

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  • Take a regular Windows 7 clone with clonezilla (device-to-image)

    - by Mario De Schaepmeester
    I am unexperienced with cloning software and I've decided to use Clonezilla as it seemed best as freeware. I chose device image and left most options standard. I chose expert mode anyway to see what I could configure, and decided to try the lzop algorithm instead of the default one for compression. The rest was left at default. When Clonezilla asked me which partitions to clone (I chose parts to image), I chose the C:\ drive but Windows 7 also creates a 100MB partition on setup for system files (the actual boot partition?). I copied that into the image as well. The reason I didn't choose disk to image is that I also have a data partition that needs to stay intact. Now I'm simply not sure that this is the way to go, should I ever need to restore my disk image. Will Clonezilla know what to do with both partitions and will Windows 7 work perfectly after restoring? Edit: apparantly a similar question has been asked before. The link to the first article in the answer is not relevant to me since it covers a device-to-device clone. It appears the windows installation disk can repair the 100MB partition. As for Clonezilla, it copies "hidden data after the MBR" by default too. I don't know, I feel I'll be allright whether by restoring the partition with Clonezilla or repairing it with the Windows 7 disk.

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  • Rendering partial for table row with form_tag is getting crazy!

    - by xopht
    I have 23(column)x6(row) table and change the row with link_to_remote function. each tr tag has its own id attribute. change link call change action and change action changes the row using render function wit partial. _change.html.erb <td id="row_1">1</td> . . omitted . . <td id="row_23">23</td> link_to_remote function <%= link_to_remote 'Change', :update => 'row_1', :url => change_path %> change action def change logger.debug render :partial => 'change' end If I coded like above, everything work okay. This means all changed-columns are in one row. But, if I wrap partial code with *form_for* function like below... <% form_for 'change' do %> <td id="row_1">1</td> . . omitted . . <td id="row_23">23</td> <% end %> Then, one column located in one row and that column is the first column. I've looked up the log file, but it was normal html tags. What's wrong?

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  • How to alter Postgres table data based on its contents?

    - by williamjones
    This is probably a super simple question, but I'm struggling to come up with the right keywords to find it on Google. I have a Postgres table that has among its contents a column of type text named content_type. That stores what type of entry is stored in that row. There are only about 5 different types, and I decided I want to change one of them to display as something else in my application (I had been directly displaying these). It struck me that it's funny that my view is being dictated by my database model, and I decided I would convert the types being stored in my database as strings into integers, and enumerate the possible types in my application with constants that convert them into their display names. That way, if I ever got the urge to change any category names again, I could just change it with one alteration of a constant. I also have the hunch that storing integers might be somewhat more efficient than storing text in the database. First, a quick threshold question of, is this a good idea? Any feedback or anything I missed? Second, and my main question, what's the Postgres command I could enter to make an alteration like this? I'm thinking I could start by renaming the old content_type column to old_content_type and then creating a new integer column content_type. However, what command would look at a row's old_content_type and fill in the new content_type column based off of that?

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  • Why would using a Temp table be faster than a nested query?

    - by Mongus Pong
    We are trying to optimise some of our queries. One query is doing the following: SELECT t.TaskID, t.Name as Task, '' as Tracker, t.ClientID, (<complex subquery>) Date, INTO [#Gadget] FROM task t SELECT TOP 500 TaskID, Task, Tracker, ClientID, dbo.GetClientDisplayName(ClientID) as Client FROM [#Gadget] order by CASE WHEN Date IS NULL THEN 1 ELSE 0 END , Date ASC DROP TABLE [#Gadget] (I have removed the complex subquery, cos I dont think its relevant other than to explain why this query has been done as a two stage process.) Now I would have thought it would be far more efficient to merge this down into a single query using subqueries as : SELECT TOP 500 TaskID, Task, Tracker, ClientID, dbo.GetClientDisplayName(ClientID) FROM ( SELECT t.TaskID, t.Name as Task, '' as Tracker, t.ClientID, (<complex subquery>) Date, FROM task t ) as sub order by CASE WHEN Date IS NULL THEN 1 ELSE 0 END , Date ASC This would give the optimiser better information to work out what was going on and avoid any temporary tables. It should be faster. But it turns out it is a lot slower. 8 seconds vs under 5 seconds. I cant work out why this would be the case as all my knowledge of databases imply that subqueries would always be faster than using temporary tables. Can anyone explain what could be going on!?!?

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  • Modeling many-to-one with constraints?

    - by Greg Beech
    I'm attempting to create a database model for movie classifications, where each movie could have a single classification from each of one of multiple rating systems (e.g. BBFC, MPAA). This is the current design, with all implied PKs and FKs: TABLE Movie ( MovieId INT ) TABLE ClassificationSystem ( ClassificationSystemId TINYINT ) TABLE Classification ( ClassificationId INT, ClassificationSystemId TINYINT ) TABLE MovieClassification ( MovieId INT, ClassificationId INT, Advice NVARCHAR(250) -- description of why the classification was given ) The problem is with the MovieClassification table whose constraints would allow multiple classifications from the same system, whereas it should ideally only permit either zero or one classifications from a given system. Is there any reasonable way to restructure this so that a movie having exactly zero or one classifications from any given system is enforced by database constraints, given the following requirements? Do not duplicate information that could be looked up (i.e. duplicating ClassificationSystemId in the MovieClassification table is not a good solution because this could get out of sync with the value in the Classification table) Remain extensible to multiple classification systems (i.e. a new classification system does not require any changes to the table structure)? Note also the Advice column - each mapping of a movie to a classification needs to have a textual description of why that classification was given to that movie. Any design would need to support this.

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  • Adding a footer to a table in another view?

    - by cannyboy
    The app I'm making has a settings view which I want to show on the first run of the app. Normally (after the first run) this view will be pushed onto the screen and there will be a "Back" button in the nav bar. However, on first launch I don't want there to be a back button. Instead, I want to add a 'Done' button at the footer of the table... and then the view can be popped. Here's my code (in my initial view's viewDidLoad). I have removed the back button, but don't know how to add the footer and button. NSUserDefaults *prefs = [NSUserDefaults standardUserDefaults]; if ([prefs stringForKey:@"firstRun"] == nil) { SettingsViewController *settingsView = [[SettingsViewController alloc] initWithNibName:@"SettingsView" bundle:nil]; settingsView.hidesBottomBarWhenPushed = YES; settingsView.navigationItem.hidesBackButton = TRUE; // add footer button here? [[self navigationController] pushViewController:settingsView animated:YES]; [settingsView release]; [prefs setObject:@"OK" forKey:@"firstRun"]; } else { //something }

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  • Procedure for dual booting (2 copies of Win-7) off 2 partitions on same disk

    - by Sam Holder
    What procedure should I follow to set a dual boot (both Win-7 x64) on a machine where (ideally): Both operating systems will be installed on the same physical disk in different partitions When booting into either operating system the contents of the other OS partition disk will not be seen (this just seems safer) Other hard drives in the system will be visible by both OS's 1 copy of Win7 is already installed. Is it as simple as shrinking the existing volume and creating the partition, then sticking the CD in and booting off it and formatting the new partition and then installing another copy of windows onto the new partition? Or will that not work? Or are there gotchas?

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  • What is the reason partitioning is usually a step in installing multiple OS's?

    - by P.S.
    What is the reason partitioning is usually a step in installing multiple (2) operating systems on the same computer? Does an operating system have to have it's own partition to run or can it run in the same partition as another operating system? (i.e. -can two of the same flavor run in the same partition but if you have one Linux and one windows it needs to be partitioned?) Is it necessary to make disk partitions to run multiple operating systems?

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  • How to setup RAID partitions with parted?

    - by psycketom
    I'm going through the https://wiki.archlinux.org/index.php/RAID guide in here, but I'm stuck on Partition Tables. Since my drives are 3TB, fdisk and cfdisk won't cut it due to their 2GB limit, but they are straight forward when managing partitions - adding da or fd as types. But, there is not that straight forward guide for RAID partition setup with parted. So, how do I make Non-FS or RAID partition with parted?

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  • Creating bootable Fedora USB with persistent storage

    - by dooffas
    I am attempting to burn the full Fedora 19 x86_64 DVD iso to a USB drive and have a separate partition on it for a kickstart file / other media that will be installed in the kickstart process. With the Ubuntu server 12 iso, you can simply dd the iso to the usb drive: dd if=/path/to/iso of=/dev/sdb Once the iso has been burnt, open gparted and create a ext2 parition in the allocated space. However, this does not seem to work with the Fedora ISO. When loading the USB drive in gparted I get a warning and an error: Warning: The driver descriptor says the physical block size is 2048 bytes, but Linux says it is 512 bytes. Error: The partition's data region doesn't occupy the entire partition. Ignoring both of these errors allows gparted to load the usb drive, however it shows a blank drive with no partition table. Has anyone come across this before? From what I have found, it may have something to do with the fact that Fedora use isohybrid.

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  • Windows 7 boot manager not localized on UEFI systems

    - by Massimo
    I originally posted this on SuperUser because I discovered this behaviour on my home computer, but this seems to be a general issue on UEFI systems, thus I'm posting here too; I also hope someone here can shed some light on what's going on. Italian version of Windows 7 x64 SP1, same installation media used for both situations. When running on BIOS systems, the boot manager is fully localized, both for the loading screen and for the F8 boot menu. When running on UEFI systems, the boot manager always runs in English, even if it's correctly configured to use the it-IT locale, as BCDEDIT clearly shows: Windows Boot Manager -------------------- identificatore {bootmgr} device partition=\Device\HarddiskVolume1 path \EFI\Microsoft\Boot\bootmgfw.efi description Windows Boot Manager locale it-IT inherit {globalsettings} default {current} resumeobject {9ef36aa6-4188-11e3-909d-d32f0c3871c8} displayorder {current} toolsdisplayorder {memdiag} timeout 30 Caricatore di avvio di Windows ------------------- identificatore {current} device partition=C: path \Windows\system32\winload.efi description Windows 7 locale it-IT inherit {bootloadersettings} recoverysequence {9ef36aa8-4188-11e3-909d-d32f0c3871c8} recoveryenabled Yes osdevice partition=C: systemroot \Windows resumeobject {9ef36aa6-4188-11e3-909d-d32f0c3871c8} nx OptIn I also noticed something strange here; the motherboard setup shows "Windows Boot Manager" as the main boot option, while the actual boot disk is listed as the second one. Looks like the Windows Boot Manager is actually being loaded from somewhere else than the first partition of the first disk... what's going on here? Update I've also checked the EFI boot manager using bcdedit /enum FIRMWARE. That one looks correctly localized, too: Boot Manager per firmware --------------------- identificatore {fwbootmgr} displayorder {bootmgr} {9ef36aa4-4188-11e3-909d-d32f0c3871c8} {a30e8550-47e4-11e3-9ad1-806e6f6e6963} timeout 1 Windows Boot Manager -------------------- identificatore {bootmgr} device partition=\Device\HarddiskVolume1 path \EFI\Microsoft\Boot\bootmgfw.efi description Windows Boot Manager locale it-IT inherit {globalsettings} default {current} resumeobject {9ef36aa6-4188-11e3-909d-d32f0c3871c8} displayorder {current} toolsdisplayorder {memdiag} timeout 30 Applicazione firmware (101fffff) ------------------------------- identificatore {9ef36aa4-4188-11e3-909d-d32f0c3871c8} description CD/DVD Drive Applicazione firmware (101fffff) ------------------------------- identificatore {a30e8550-47e4-11e3-9ad1-806e6f6e6963} description Hard Drive

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  • Set bounds for markers generated by jQuery table loop?

    - by abemonkey
    I have some jQuery code that goes through a table of location results and puts corresponding pins on a map. I am having trouble figuring out how to set the bounds so that when it goes through the loop and generates the markers on the map that it zooms and pans to fit the markers in the view. I've tried implementing code from some similar questions on this site but nothing seems to be working. Please let me know what code I should be using and where the heck I should put it in my script: $(function() { var latlng = new google.maps.LatLng(44, 44); var settings = { zoom: 15, center: latlng, disableDefaultUI: false, mapTypeId: google.maps.MapTypeId.ROADMAP }; var map = new google.maps.Map(document.getElementById("map_canvas"), settings); $('tr').each(function(i) { var the_marker = new google.maps.Marker({ title: $(this).find('.views-field-title').text(), map: map, clickable: true, position: new google.maps.LatLng( parseFloat($(this).find('.views-field-latitude').text()), parseFloat($(this).find('.views-field-longitude').text()) ) }); var infowindow = new google.maps.InfoWindow({ content: $(this).find('.views-field-title').text() + $(this).find('.adr').text() }); new google.maps.event.addListener(the_marker, 'click', function() { infowindow.open(map, the_marker); }); }); }); `

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  • Hibernate CreateSQL Query Problem

    - by Shaded
    Hello All I'm trying to use hibernates built in createsql function but it seems that it doesn't like the following query. List =hibernateSession.createSQLQuery("SELECT number, location FROM table WHERE other_number IN (SELECT f.number FROM table2 AS f JOIN table3 AS g on f.number = g.number WHERE g.other_number = " + var + ") ORDER BY number").addEntity(Table.class).list(); I have a feeling it's from the nested select statement, but I'm not sure. The inner select is used elsewhere in the code and it returns results fine. This is my mapping for the first table: <hibernate-mapping> <class name="org.efs.openreports.objects.Table" table="table"> <id name="id" column="other_number" type="java.lang.Integer"> <generator class="native"/> </id> <property name="number" column="number" not-null="true" unique="true"/> <property name="location" column="location" not-null="true" unique="true"/> </class> </hibernate-mapping> And the .java public class Table implements Serializable { private Integer id;//panel_facility private Integer number; private String location; public Table() { } public void setId(Integer id) { this.id = id; } public Integer getId() { return id; } public void setNumber(Integer number) { this.number = number; } public Integer number() { return number; } public String location() { return location; } public void setLocation(String location) { this.location = location; } } Any suggestions? Edit (Added mapping)

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  • After creating a mysql user with all privileges, the user cannot create databases in phpMyAdmin and only sees information_schema table

    - by GHarping
    This is a recurring problem for some reason... Using mysql 5.5, I am simply trying to create a user that can connect to the database remotely, have access to all databases, and create databases. I have created a user using: create user 'dev'@'%' identified by 'abcdefg'; then granted all permissions using: GRANT ALL ON *.* to 'dev'@'192.168.%' IDENTIFIED BY 'abcdefg' WITH GRANT OPTION; and the result is that the user cannot create databases, and can only see information_schema database for some reason. Databases Create database: Documentation No Privileges Database Ascending information_schema Total: 1 Does anyone know why this might be happening?

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  • How to speed up a slow UPDATE query

    - by Mike Christensen
    I have the following UPDATE query: UPDATE Indexer.Pages SET LastError=NULL where LastError is not null; Right now, this query takes about 93 minutes to complete. I'd like to find ways to make this a bit faster. The Indexer.Pages table has around 506,000 rows, and about 490,000 of them contain a value for LastError, so I doubt I can take advantage of any indexes here. The table (when uncompressed) has about 46 gigs of data in it, however the majority of that data is in a text field called html. I believe simply loading and unloading that many pages is causing the slowdown. One idea would be to make a new table with just the Id and the html field, and keep Indexer.Pages as small as possible. However, testing this theory would be a decent amount of work since I actually don't have the hard disk space to create a copy of the table. I'd have to copy it over to another machine, drop the table, then copy the data back which would probably take all evening. Ideas? I'm using Postgres 9.0.0. UPDATE: Here's the schema: CREATE TABLE indexer.pages ( id uuid NOT NULL, url character varying(1024) NOT NULL, firstcrawled timestamp with time zone NOT NULL, lastcrawled timestamp with time zone NOT NULL, recipeid uuid, html text NOT NULL, lasterror character varying(1024), missingings smallint, CONSTRAINT pages_pkey PRIMARY KEY (id ), CONSTRAINT indexer_pages_uniqueurl UNIQUE (url ) ); I also have two indexes: CREATE INDEX idx_indexer_pages_missingings ON indexer.pages USING btree (missingings ) WHERE missingings > 0; and CREATE INDEX idx_indexer_pages_null ON indexer.pages USING btree (recipeid ) WHERE NULL::boolean; There are no triggers on this table, and there is one other table that has a FK constraint on Pages.PageId.

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  • Fetching only the first record in the table (via the view) without changing controller?

    - by bgadoci
    I am trying to only fetch the first record in my table for display. I am creating a site where a user can upload multiple images and attach to a post but I only want to display the first image view for each post. For further clarification posts belong_to projects. So when you are on the projects show page you see multiple posts. In this view I only want to display the first image for each post. Is there a way to do this in the view without affecting the controller (as later I want to allow users to browse all photos through the addition of a lightbox). Here is my /views/posts/_post.html.erb code: <% div_for post do %> <% post.photos.each do | photo | %> <%= image_tag(photo.data.url(:large), :alt => '') %> <%= photo.description %> <% end unless post.photos.first.new_record? rescue nil %> <%= link_to h(post.link_title), post.link %> <%= h(post.description) %> <%= link_to 'Manage this post', edit_post_path(post) %> <% end %> UPDATE: I am using a photos model to attach multiple photos to each post and using paperclip here.

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  • Which rdisk value in boot.ini maps to which disk?

    - by MA1
    Following are the contents of a sample boot.ini: [boot loader] timeout=30 default=multi(0)disk(0)rdisk(0)partition(1)\WINDOWS [operating systems] multi(0)disk(0)rdisk(0)partition(1)\WINDOWS="Microsoft Windows XP Professional" /NOEXECUTE=OPTIN /FASTDETECT multi(0)disk(0)rdisk(0)partition(2)\WINNT="Windows 2000 Professional" /fastdetect multi(0)disk(0)rdisk(1)partition(1)\WINDOWS="Microsoft Windows XP Home Edition" /NOEXECUTE=OPTIN /FASTDETECT The rdisk value tells the physical disk number. So, if I have three hard disks say: /dev/sda /dev/sdb /dev/sdc Then how to know which disk (/dev/sda or /dev/sdb or /dev/sdc) is rdisk(0) and which disk is rdisk(1), etc.?

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  • Function to extract data in insert into satement for a table.

    - by user269484
    Hi...I m using this Function to extract the data but unable to extract LONG datatype. Can anyone help me? create or replace Function ExtractData(v_table_name varchar2) return varchar2 As b_found boolean:=false; v_tempa varchar2(8000); v_tempb varchar2(8000); v_tempc varchar2(255); begin for tab_rec in (select table_name from user_tables where table_name=upper(v_table_name)) loop b_found:=true; v_tempa:='select ''insert into '||tab_rec.table_name||' ('; for col_rec in (select * from user_tab_columns where table_name=tab_rec.table_name order by column_id) loop if col_rec.column_id=1 then v_tempa:=v_tempa||'''||chr(10)||'''; else v_tempa:=v_tempa||',''||chr(10)||'''; v_tempb:=v_tempb||',''||chr(10)||'''; end if; v_tempa:=v_tempa||col_rec.column_name; if instr(col_rec.data_type,'CHAR') 0 then v_tempc:='''''''''||'||col_rec.column_name||'||'''''''''; elsif instr(col_rec.data_type,'DATE') 0 then v_tempc:='''to_date(''''''||to_char('||col_rec.column_name||',''mm/dd/yyyy hh24:mi'')||'''''',''''mm/dd/yyyy hh24:mi'''')'''; else v_tempc:=col_rec.column_name; end if; v_tempb:=v_tempb||'''||decode('||col_rec.column_name||',Null,''Null'','||v_tempc||')||'''; end loop; v_tempa:=v_tempa||') values ('||v_tempb||');'' from '||tab_rec.table_name||';'; end loop; if Not b_found then v_tempa:='-- Table '||v_table_name||' not found'; else v_tempa:=v_tempa||chr(10)||'select ''-- commit;'' from dual;'; end if; return v_tempa; end; /

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  • How can I undo what I did when I accidentally booted linux host inside itself with VMware?

    - by ThomasGHenry
    Hello, I'm dual booting XP and Kubuntu. I wanted to boot to my existing raw scsi XP partition inside Kubuntu, not a virtual XP instance. I accidentally booted Kubuntu inside itself. I know this is a big mistake, so I interrupted the VM, which saved the state and closed. I rebooted the host and now I can't load the Kubuntu partition at boot time. I get a maintenance shell and the Kubuntu partition is read-only. I am able to boot XP as usual. I removed the HDD and tried to mount it on another computer as an external drive and neither partition (XP or Kubuntu) will be recognized, it just appears to be one device that still mounts and appears empty. From the maintenance shell I can see all the files are still on the Kubuntu partition. How can I undo what I did when I accidentally booted Kubuntu inside itself? Is it a matter of unlocking some files somewhere? how can I do that on a RO filesystem? Thanks!

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  • What is preferred method for searching table data using stored procedure?

    - by Mourya
    I have a customer table with Cust_Id, Name, City and search is based upon any or all of the above three. Which one Should I go for ? Dynamic SQL: declare @str varchar(1000) set @str = 'Select [Sno],[Cust_Id],[Name],[City],[Country],[State] from Customer where 1 = 1' if (@Cust_Id != '') set @str = @str + ' and Cust_Id = ''' + @Cust_Id + '''' if (@Name != '') set @str = @str + ' and Name like ''' + @Name + '%''' if (@City != '') set @str = @str + ' and City like ''' + @City + '%''' exec (@str) Simple query: select [Sno],[Cust_Id],[Name],[City],[Country],[State] from Customer where (@Cust_Id = '' or Cust_Id = @Cust_Id) and (@Name = '' or Name like @Name + '%') and (@City = '' or City like @City + '%') Which one should I prefer (1 or 2) and what are advantages? After going through everyone's suggestion , here is what i finally got. DECLARE @str NVARCHAR(1000) DECLARE @ParametersDefinition NVARCHAR(500) SET @ParametersDefinition = N'@InnerCust_Id varchar(10), @InnerName varchar(30),@InnerCity varchar(30)' SET @str = 'Select [Sno],[Cust_Id],[Name],[City],[Country],[State] from Customer where 1 = 1' IF(@Cust_Id != '') SET @str = @str + ' and Cust_Id = @InnerCust_Id' IF(@Name != '') SET @str = @str + ' and Name like @InnerName' IF(@City != '') SET @str = @str + ' and City like @InnerCity' -- ADD the % symbol for search based upon the LIKE keyword SELECT @Name = @Name + '%', @City = @City+ '%' EXEC sp_executesql @str, @ParametersDefinition, @InnerCust_Id = @Cust_Id, @InnerName = @Name, @InnerCity = @City; References : http://blogs.lessthandot.com/index.php/DataMgmt/DataDesign/changing-exec-to-sp_executesql-doesn-t-p http://msdn.microsoft.com/en-us/library/ms175170.aspx

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