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  • php exec and shell_exec not working

    - by chris
    I want to run an exe file on my server and return the output to the browser screen. The exe file takes a input file and then returns data on the screen. Why is this code not working? $output = shell_exec('myprogram < INP.DAT'); echo "<pre>" . var_export($output, TRUE) ."</pre>\\n"; It displays "NULL" on the browser screen. I have also tried exec(). There it returns "Array()".

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  • Why isn't this message subject encoded properly? (php mail)

    - by Camran
    I use this code to send an email: $headers="MIME-Version: 1.0"."\n"; $headers.="Content-type: text/plain; charset=UTF-8"."\n"; $headers.="From: $name <$email>"."\n"; mail($to, '=?UTF-8?B?'.base64_encode($subject).'?=', $text, $headers, '[email protected]'); If I use special characters Å Ä Ö from the swedish alphabet, they are not encoded properly, so they turn up like ö for ö. However, this doesn't happen if I change the $to variable to a gmail account email, then they are shown correctly. Anybody got any idea? Thanks UPDATE: When I echo $name, the name is displayed correctly, in utf8, with all special chars nicely shown.

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  • Getting id of row just inserted into MySQL database

    - by James P
    I have my table columns set like this: likes(id, like_message, timestamp) id is the primary key that is auto incrementing. This is the SQL that I use to add a row: $sql = "INSERT INTO `likes` (like_message, timestamp) VALUES ('$likeMsg', $timeStamp)"; Everything works, but now I need to throw back the id attribute of the newly inserted row. For example, if I insert a row and the id of that row is 13, I need to echo out 13 so my AJAX request can pick that up and use it. Any help would be appreciated, as well as related code samples. Thanks :)

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  • Can I expand macro JUST ONE TIME in specific target?

    - by naive231
    A = "demo" %.o:%.cpp $(CC) -c $^ $(A) -o $@ default:$(all_objs) game:A = $(shell read -p 'Enter game version: ' gv && echo $$gv) game:$(all_objs) Just a snippet makefile above. If I make game, main problem is each compilation of sources will expand $(A) and it will request user to input game version over and over. $(A) has default content "demo" only if user doesn't make game target. So, is there any way to set $(A) to be expanded && ?

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  • php/ssh2 script does not display the stdout to $stream

    - by kamal
    The following php script works for simple linux commands, like ps -ef , but when i use ./dstat -t -a , it seems to hang and i dont get the prompt back on my local machine. Kep in mind that all commands are executed over ssh on a remote host: <?php $target = time() . '_' . 'txt'; if($ssh = ssh2_connect('10.1.0.174', 22)) { if(ssh2_auth_password($ssh, 'root', 'kmoon77')) { //$stream = ssh2_exec($ssh, 'whoami'); $sCommand = 'dstat -a'; //$sCommand = 'ps -ef'; $stream = ssh2_exec($ssh, $sCommand); //$stream = ssh2_exec($ssh, 'pwd'); stream_set_blocking($stream, true); $data = ''; while($buffer = fread($stream, 4096)) { $data .= $buffer; } //fclose($stream); echo $data; // user } } ?>

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  • Why is it inserting 0's instead of blank spaces into my DB using php?

    - by zeckdude
    I have an insert: $sql = 'INSERT into orders SET fax_int_prefix = "'.$_SESSION['fax_int_prefix'].'", fax_prefix = "'.$_SESSION['fax_prefix'].'", fax_first = "'.$_SESSION['fax_first'].'", fax_last = "'.$_SESSION['fax_last']; The value of all of these fields is that they are blank right before the insert. Here is an example of one of them I echo'd out just before the insert: $_SESSION[fax_prefix] = For some reason it inserts the integer 0, instead of a blank value or null, as it should. Why is it inserting 0's instead of blank spaces into my DB?

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  • trying to use PHP extract() within a function

    - by samuelf
    Hi, I have the two following files: main.php include("functions.php") __EXTRACT(); echo $testvar; functions.php function __EXTRACT(){ extract($_POST, EXTR_SKIP); } However, having a form with a textbox called testvar I can't get the extract function to extract the data.. if I remove the function call and insert it the extract statement directly into main.php it works. The include is not a problem as other functions in it works. Any ideas? Cheers

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  • cant get ajax response (JSON) to call 'success' function?

    - by Haroldo
    for some reason the success function isnt being called? javscript: $.ajax({ type: 'POST', url: 'http://localhost/hf_latest_desktop/st_pages/user_area/acc_buttons/pass_change/pass_change_ajax.php', data: data, dataType: 'json', success: function(e){ console.log(e); if(e.status == 'success'){ alert('your password has been changed!'); } if(e.status == 'error1'){ alert('please fill in all inputs!'); } if(e.status == 'error2'){ alert('password incorrect!'); } if(e.status == 'error3'){ alert('change failed!'); } } }); php file ajax is calling to: <?php session_start(); session_cache_limiter('nocache'); header('Expires: ' . gmdate('r', 0)); header('Content-type: application/json'); $status = 'error1'; //for sake of example ?> {'status':'<?php echo $status; ?>'}

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  • Paginator (Migration from Cake 1.3 to 2.0

    - by Christian Waschke
    i am struggling with the paginator in cakephp 2.0. While i am trying to migrate my application to 2.0 i cant find any solution to jump directly to the last page. In 1.3 it was quiet to do that from outside like this: echo $this->Html->link(__('Flights'), array('controller' => 'flights', 'action' => 'index','page' => 'last')); but this little trick putting 'page:last' in does not work anymore in 2.0. Of course there is a Paginator function called last, but this would only help if i would be already inside the app. My Problem is to access from an outside link directly the last page of the paginator. Thank you for reading, cdjw

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  • Is it possible to auto generate Getter/Setter from Array Values in PHP?

    - by Phill Pafford
    So I have a couple of arrays $array_1 = Array('one','two','three'); $array_2 = Array('red','blue','green'); Is there a dynamic way to create the Setters and Getters for an array with single value entries? So the class would be something like: class xFromArray() { } So the above if I passed $array_1 it would generate something like this: private $one; setOne($x) { $one = $x; } getOne() { return $one; } if I passed $array_2 it would generate something like this: private $red; setRed($x) { $red = $x; } getRed() { return $red; } So I would call it somehow like this? (My best guess but doesn't seem that this would work) $xFromArray = new xFromArray; foreach($array_1 as $key=>$data) { $xFromArray->create_function(set.ucfirst($data)($data)); echo $xFromArray->create_function(get.ucfirst($data)); }

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  • jQuery Fade a div off the screen

    - by Scott B
    In my app, I have a temporary div that is shown each time the app is saved (see markup below). I'm using jQuery 1.4.2 and would like to know the command that will fade this div off the screen after 3 seconds... <script src="../wp-content/themes/mytheme/jquery-1.4.2.min.js" type="text/javascript"></script> if ($_REQUEST['saved']) echo '<div id="message" class="updated fade"><p>'.$themename.' settings saved.</strong></p></div>';

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  • php/mysql question, retrieving information

    - by chance
    Hey SO, I have a question, pretty new at PHP and MySql but was curious is it possible to display only the most recent column to a table, from a database? I know it is possible to display a list of all information, or if you have just one column of information in your table to display that using the Here is my code for my basic script (just loads 1 column of information) I would like it to only print out the recent column i added to the table $con = mysql_connect ("localhost","username","password"); if (!$con) { die ('Could not connect:' . mysql_error()0; } mysql_select_db("db_name", $con); $result = mysql_query(Select column FROM table"); while($row = mysql_fetch_array($result)) { echo $row['column']; } mysql_close($con); * keep in mind, im not looking for someone to shoot me my code with it completed, though it would be handy, however just giving me the options of what I have to do, or what the script is called would be plentiful enough for my research, thanks!

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  • Using sed with html data

    - by StackedCrooked
    I'm having some problems using sed in combination with html. The following sample illustrates the problem: HTML="<html><body>ENTRY</body><html>" TABLE="<table></table>" echo $HTML | sed -e s/ENTRY/$TABLE/ This outputs: sed: -e expression #1, char 18: unknown option to `s' If I leave out the / from $TABLE so that it becomes <table><table> it works ok. Any ideas on how to fix it?

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  • Can I insert a style tag and contents from a view with CakePHP?

    - by Richard
    From what I can see, CakePHP makes it easy to link to a CSS file in a view with the following: echo $html->css('my-css-filename',null,array(),FALSE); But what if I don't want to exclusively use hardcoded files? How can I get it to create a style tag with some dynamically generated rules in e.g. <style type="text/css" media="all">p {font-size:1.5em}</style> I am trying to do this in a view file, I'd like the CSS to be placed in the head tag, and I'm using CakePHP 1.2.7

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  • how to force drupal function to not use DB cache?

    - by Alaa
    Hi All, i have a module and i am using node_load(array('nid' = arg(1))); now the problem is that this function keep getting its data for node_load from DB cache. how can i force this function to not use DB cache? Example my link is http://mydomain.com/node/344983 now: $node=node_load(array('nid'=arg(1)),null,true); echo $node-nid; output 435632 which is a randomly node id (available on the system) and everytime i ctrl+F5 my browser i get new nid!! Thanks for your help

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  • PHP: reusing database class

    - by citricsquid
    Hi, I built a class that allows me to do: $db->query($query); and it works perfectly, although if I want to do: $db->query($query); while($row = $db->fetch_assoc()){ $db->query($anotherquery); echo $db->result(); } it "breaks" the class. I don't want to constantly have to redeclare my class (eg: $seconddb = new database()), is there a way to get around this? I want to be able to reuse $db within $db, without overwriting the "outside" db. currently I'm create an array of data (from db-fetch_assoc() then doing a foreach and then doing the db call inside that: $db->query('SELECT * FROM table'); while($row = $db->fetch_assoc()){ $arr[] = $row; } foreach($arr as $a){ $db->query(); // query and processing here } Is this the best method or am I missing the obvious? Should I consider passing a connection link ID with the database connection?

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  • update in codeigniter works but displays an error message

    - by Charmie
    i was just wondering what could be the problem with a working code yet displays an error message such as this: A PHP Error was encountered Severity: Notice Message: Array to string conversion Filename: database/DB_active_rec.php Line Number: 1407 im trying to update fields in my database. I have this code and every tutorial are just the same for batch upload. It works anyway but the thing is it display such an error. this what i have in my model: function update2($data){ $this->db->update_batch('users',$data, "id"); } This what i have in my controller: public function updateValues(){ $this->load->model('get_db'); $newRow = array( array( 'id' => '3', 'firstname' => 'Rapphie' ), array( 'id' => '2', 'firstname' => 'Charmie' ) ); $this->get_db->update2($newRow); echo "it has been updated"; } please help.

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  • Unable to return/process JSON in JQuery $.get()

    - by shyam
    I have a problem returning/processing JSON data while calling $.get() function. Here's the code: JQuery: $.get("script.php?", function(data) { if (data.status) { alert('ok'); } else { alert(data.error); } },'json'); PHP if ($r) { $ret = array("status"=>true); } else { $ret = array("status"=>false,"error"=>$error); } echo json_encode( $ret ); So this is the code. But the response is always taken as string in the jquery. data.status and data.error is undefined.

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  • Accessing array elements in PHP

    - by Elliot B.
    I have an array $aMethods whose print_r output is this: Array ( [0] => Array ( [pattern] => [return_media] => 1 [return_name] => ) ) I'm trying to access 'return_media' with this code: $iReturnMedia = $aMethods[0]->return_media; echo $iReturnMedia; Also, when I tried this: $iReturnMedia = $aMethods[0]['return_media']; I get an error stating: Cannot use string offset as an array in... But it's not working, $iReturnMedia comes back as blank. Could someone tell me what I'm doing wrong here?

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  • Problem with fetching table to array

    - by jasmine
    I have writed this function: function news_array() { $sql = "SELECT * FROM content WHERE home=1"; $query = mysql_query($sql); $i = 0; while($row = mysql_fetch_array($query)){ $row_array[$i] = array( TITLE => $row['title'], ABSTRACTT => $row['abstract'], BODY => $row['body'], ID => $row['conID'] ); $i++; } return $row_array; } When using this function like this: <?php $row_array = news_array(); for($i = 0 ; $i < count($row_array) ; $i++){ echo $row_array[$i][TITLE]; } ?> There no output in html. What is wrong in my function? Thanks in advance

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  • Removing rows from MySQL table where the timestamp is over one day old?

    - by Rob
    I found the exact same question here. But it isn't working for me. I've modified it a bit, manipulated it, and I can't figure it out. I'm trying to remove rows that are over a day old. Here is my code: if (isset($_POST['prune'])) { $sql = "DELETE FROM logs WHERE time < date('now', '-1 days')"; mysql_query($sql); echo 'Logs older than one day removed.'; } Fairly simple question I suppose, but its bugging the hell out of me. I would appreciate any help. In case it makes a difference, the column is a TIMESTAMP type.

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  • How to insert data in mysql data base table

    - by user1289538
    I am inserting data in MySQL data base but in field it does not insert data. I am using following code $providernpi=$_POST['ProviderNPI']; $patienid=$_POST['PatientID']; $fileurl=$_POST['FileURL']; $filetype=$_POST['FileTYPE']; $datasynid=$_POST['DataSynID']; $appointmentlistingsid=$_POST ['AppointmentListingsID']; $query=("INSERT INTO AppointmentDataSync (ProviderNPI,PatientID, FileURL,FileType,DataSyncID,AppointmentListingsID) VALUES ('$providernpi', '$patientid','$fileurl','$filetype','$datasynid','$appointmentlistingid')"); mysql_query($query,$con); printf("Records inserted: %d\n", mysql_affected_rows()); echo($patienid) ?>

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  • How to assign variable dynamically to php list function

    - by ravisoni
    What I am doing that I want to generate a list based on how many items are in an array, so I have counted the items and loop over them, create a number based var and construct a string $var which contains $a1,$a2.... and assigns the $var to list list($var) and tried to access $a1 but it gives me the error "Undefined variable: a1" Is there any other way to do it? Here is my code: $arr = array('1','2','3'); $listsize = count($arr); $var=''; for($i=1;$i<=$listsize;$i++){ $var.='$a'.$i; if($i!=$listsize){ $var.=','; } } list($var) = $arr; echo $a1;

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  • How do I link to another action in Magento whilst passing a parameter to the controller?

    - by desbest
    I need to pass a parameter, because I would like to redirect back to the module and query string of the current page. So I can get from showdown/index?id=35 --click--- showdown/vote?id=1 showdown/vote?id=1 --redirect-- showdown/index?id=35 The vote action is not seen. (The redirect method doesn't work as it takes the index.php url only and no actions, and I cannot find a helper in Magento for creating hyperlinks.) Does Magneto have a link helper for this? Example of stuff I want: <a href="<?php echo Mage::Helper->Link->($url, $array); ?> then $array or whatever variables gets sent to the controller.

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  • PHP export to excel

    - by user1865240
    I'm having a trouble that I can't export japanese texts to excel (xls). I used the following codes: header('Content-type: application/ms-excel;charset=UTF-8'); header('Content-Disposition: attachment; filename='.$filename); header("Pragma: no-cache"); echo $contents; But in the excel file, the text changed to funny characters like this: é™?定ç‰? ã?¨ã??ã?¯ã??ã?£ã?†ã?ªã?¢å??犬ã?®ã?Œæ??ã? ’è??ã??ã?Ÿã?†ã?£ã??ã??ã??ã?? ï?? Currently, I'm using hostingmanager and I tried on the different server using the same codes and there's no problem. What could be the problem. Because of the PHP version?? Please help me. Thank you, Aino

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