Search Results

Search found 8232 results on 330 pages for 'position'.

Page 27/330 | < Previous Page | 23 24 25 26 27 28 29 30 31 32 33 34  | Next Page >

  • CALayer rotation on Y axis ignores z position

    - by Rafa
    Hi, i have some CALayers one on top of the other with different z-values. the z-values are sequential (1,2,3 ...). i wrote some code that changes the y-rotation of a CALayer when i click on it. the y-rotations changes to -30.f the problem is that when i click on a CALayer it rotates and goes behind the CALayers that are actually beneath it (by z-value ordering). i understand that changing the y-rotation by -30.f actually takes the CALayer back in a sense. but shouldn't it consider the z-value as the index of the CALayer in the container and make sure it stays on top of lower z-values ?

    Read the article

  • Android: How to find the position clicked from the context menu

    - by Josemalive
    Hi, I have a list view filled with data. I set up a context menu for the listview using the following code: list.setOnCreateContextMenuListener ( new View.OnCreateContextMenuListener() { public void onCreateContextMenu(ContextMenu menu, View view, ContextMenu.ContextMenuInfo menuInfo) { AdapterContextMenuInfo mi =(AdapterContextMenuInfo) menuInfo; menu.add(0, 0, 0, "Delete item"); } } ); I have the following method override to control de contextmenu menuitem selected: @Override public boolean onContextItemSelected(MenuItem item) { switch(item.getItemId()) { case 0: ShowAlert("hello from delete item"); break; default: return super.onContextItemSelected(item); } return true; } In this overrided method, how could i find the item of the list view that was clicked? Thanks in advance. Best Regards. Jose

    Read the article

  • Jquery Slide to position on click

    - by Andy
    Here's a scenario... I have a column. In the column i have multiple divs with text inside each one. A bit like a list of categories. Which ever one is SELECTED gains a different background colour. What i would like to be able to do is use jquery so that when a different div is clicked on the background colour appears to slide behind the rest of the items until it reaches the one you selected. Does anyone have any idea if this can be done? And if so any idea on Markup? Any help is greatly appreciated.

    Read the article

  • Django: How do I position a page when using Django templates

    - by swisstony
    I have a web page where the user enters some data and then clicks a submit button. I process the data and then use the same Django template to display the original data, the submit button, and the results. When I am using the Django template to display results, I would like the page to be automatically scrolled down to the part of the page where the results begin. This allows the user to scroll back up the page if she wants to change her original data and click submit again. Hopefully, there's some simple way of doing this that I can't see at the moment.

    Read the article

  • Relative Position in PHP between 2 points (Lat/Long)

    - by Brian H
    I have a database of airports with Latitude and Longitude for each point. I want to run a PHP script to find all airports that are nearby a given airport, with their distance and relative direction. I.e. for Airport KLDJ (40-37-02.810N 074-14-40.539W) Airport Nearby KJFK - John F Kennedy Airport (21.2 nm NE) (40-38-23.104N 073-46-44.132W) I have used code from http://www.movable-type.co.uk/scripts/latlong.html to find distance, and tried to use it to find bearing, which might not be right. //BEARING RHUMB LINE $phi = log(tan($lat2/2+pi/4)/tan($lat1/2+pi/4)); $distance['bearing'] = (rad2deg(atan2($theta, $phi)) +180) % 360; I basically want to run all points through this script and find the distance, which I have already, but then the direction. (i.e. N, S, W, E, NW, SW, NE, SE)

    Read the article

  • How to Change TabPage Position in C#.NET?

    - by user327387
    I have six tabs on my Windows application. I need to put tab #6 after tab #2, how can i do it? I couldn't drag the tab to the location i want! The 5 tabs are full of controls that took long time to name and design. Any idea how to move last tab and place it after 3rd tab?

    Read the article

  • Custom Geo Tagging. Name to position and position to name

    - by Toni Michel Caubet
    Hello there i am implementing a custom geo tagging system, ok Array where i store the cordenades of each place /* ******Opciones del etiquetado del mapa*** */ var TagSpeed = 800; //el tiempo de la animacion var animate = true; //false = fadeIn / true = animate var paises = { "isora": { leftX: '275', topY: '60', name: 'Gran Melia Palacio de Isora' }, "pepe": { leftX: '275', topY: '60', name: 'Gran Melia de Don Pepe' }, "australia": { leftX: '565', topY: '220', name: 'Gran Melia Uluru' }, "otro": { // ejemplo leftX: '565', // cordenada x topY: '220', // cordenada y name: 'soy otro' // nombre a mostrar } /* <==> <span class="otro mPointer">isora</span> */ } /**/ this is how i check with js function escucharMapa(){ /*fOpciones*/ $('.mPointer').bind('mouseover',function(){ var clase = $(this).attr('class').replace(" mPointer", ""); var left_ = paises[clase].leftX; var top_ = paises[clase].topY; var name_ = paises[clase].name; $('.arrow .text').html(name_); /*Esta linea centra la etiqueta del hotel con la flecha. Si cambia el tamaño de fuente o la typo, habrá que cambiar el 3.3*/ $('.arrow .text').css({'marginLeft':'-'+$('.arrow .text').html().length*3.3+'px'}); $('.arrow').css({top:'-60px',left:left_+'px'}); if(animate) $('.arrow').show().stop().animate({'top':top_},TagSpeed,'easeInOutBack'); else $('.arrow').css({'top':top_+'px'}).fadeIn(500); }); $('.mPointer').bind('mouseleave',function(){ if(animate) $('.arrow').stop().animate({'top':'0px'},100,function(){ $('.arrow').hide() }); else $('.arrow').hide(); }); } /*Inicio gestion geoEtiquetado*/ $(document).ready(function(){ escucharMapa(); }); HTML <div style="float:left;height:500px;"> <div class="map"> <div class="arrow"> <div class="text"></div> <img src="img/flecha.png"/> </div> <!--mapa--> <img src="http://www.freepik.es/foto-gratis/mapa-del-mundo_17-903095345.jpg" id="img1"/> <br/> <br/> <span class="isora mPointer">isora</span> <span class="pepe mPointer">Pepe</span> <span class="australia mPointer">Australia</span> </div> </div> OK so you have vew items and when you hover one, it gets the classname, it checks the cordinades in the object and displays a cursor in those cordinades of the image, right? ok so how can i do the opposite? lets say if user hovers +-30px error margin (top and left) an area in the map the item is highlighted??? i was considering -on map image mouse over - get the offset of the mouse - if is in the margin error area -show else -no show But that does not look really efficient as long as it would have to caculate each pixel movement, no?

    Read the article

  • Swap CSS class on the basis of Scroll Position with Javascript

    - by Alan
    I have followed answer given by CMS in relation to getting a menu to stay in one place on the page whilst you scroll the page as per this original question and it works very well but I also have a number of images on the page where I'm using the jquery fancylink plugin to show an enlarged image on click. The problem is when you then close the fancylink popup and scroll to the top of the page the static DIV then decides to stick to the very top of the page. Any ideas or help would this would be greatly appreciated.

    Read the article

  • SEO google keyword position tools?

    - by Peterl86
    Hi guys, I want to check our google postions for several keywords every day and make a note in a spreadseet. At the moment, we have a student doing it but it's a rubbish job and it doesn't seem fair on them! Are there any tools available to automate this process? I have tried rankchecker by seobook.com, but although that should be exactly what im looking for when i set scheduled tasks in that, it doesnt work. Any tips would be appreciated, thanks! peter EDIT: Liam has suggested a Python script to do this, which unfortunately isnt something I'm very familiar with! If anyone knows of a good tutorial or something to help us with this, that would be brilliant. Update: Found a php script at seoscript.net which looks like a step in the right direction. But I cant get it to work! I get this error. Anyone more knowledgabe than me know how to fix that? I have PEAR installed. thanks again, Peter

    Read the article

  • position of options in HTML select element

    - by frenchie
    I have a element that contains options. The element is 150px wide but some of the options are wider. So when rendering, the browser shows the overflow to the right. How can I make the options list overflow to the left? JSFiddle Thanks. <select id="MySelect"> <option value="60" selected="selected"></option><option value="-60">(UTC-01:00) Azores</option> <option value="-60">(UTC-01:00) Cape Verde Is.</option><option value="0">(UTC) Casablanca</option> <option value="0">(UTC) Dublin, Edinburgh, Lisbon, London</option><option value="0">(UTC) Monrovia, Reykjavik</option> <option value="60">(UTC+01:00) Belgrade, Bratislava, Budapest, Ljubljana, Prague</option> <option value="60">(UTC+01:00) Brussels, Copenhagen, Madrid, Paris</option> <option value="60">(UTC+01:00) Sarajevo, Skopje, Warsaw, Zagreb</option> <option value="60">(UTC+01:00) West Central Africa</option> <option value="120">(UTC+01:00) Windhoek</option> </select>?????????????????????????????????????????????? ?#MySelect{ margin-top:20px; margin-left:200px; width:150px;}

    Read the article

  • How to fix the position of the button in applet

    - by user1609804
    I'm trying to make an applet that has a buttons in the right, where each button is corresponding to a certain pokemon. I already did it, but the buttons isn't fixed.they keep following the mouse. please help. This is my code: import javax.swing.*; import java.awt.image.BufferedImage; import java.io.*; import javax.imageio.ImageIO; import java.applet.*; import java.awt.event.*; import java.awt.*; public class choosePokemon extends Applet implements ActionListener { private int countPokemon; private int[] storePokemon; private int x,y; //this will be the x and y coordinate of the button BufferedImage Picture; public int getCountPokemon(){ //for other class that needs how many pokemon return countPokemon; } public int[] getStoredPokemon(){ //for other class that needs the pokemon return storePokemon; } public void init(){ x=0;y=0; try{ Picture = ImageIO.read(new File("pokeball.png")); } catch( IOException ex ){ } } public void paint( Graphics g ){ pokemon display = new pokemon(); // to access the pokemon attributes in class pokemon ButtonGroup group = new ButtonGroup(); //create a button group for( int a=0;a<16;a++ ){ // for loop in displaying the buttons of every pokemon(one pokemon, one button) display.choose( a ); //calls the method choose in which accepts an integer from 0-15 and saves the attributes of the pokemon corresponding to the integer JButton pokemonButton = new JButton( display.getName() ); // creates the button pokemonButton.setActionCommand( display.getName() ); // isasave sa actioncommand yung name ng kung ano mang pokemon pokemonButton.addActionListener(this); //isasama yung bagong gawang button sa listener para malaman kung na-click yung button pokemonButton.setBounds( x,y,50,23 ); group.add( pokemonButton ); //eto naman yung mag-aadd sa bagong gawang button sa isang group na puro buttons(button ng mga pokemon) y+=23; if( a==7 ){ x+=50; y=0; } add( pokemonButton ); //will add the button to the applet } g.drawImage( Picture, 120, 20, null ); } public void actionPerformed(ActionEvent e) { try{ //displays the picture of the selected pokemon Picture = ImageIO.read(new File( "pokemon/" + e.getActionCommand() + ".png" )); } catch( IOException ex ){ } } public boolean chosen( int PChoice ){ //this will check if the chosen pokemon is already the player's pokemon boolean flag = false; for( int x=0; x<countPokemon && !flag ;x++ ){ if( storePokemon[x]==PChoice ){ flag = true; } } return flag; }

    Read the article

  • Determining a location's side of the road position with MapKit

    - by idStar
    Is there a way to use MapKit in iOS7 to not only get geocoding for an address, but determine what side of the road it is on? I'm not trying to build a full function navigation app, but similar to navigation apps that tell you things like "Your destination is in 100 feet on the right", I'd like to be able to obtain this information. Does MapKit give one a way to do this? Do I need to adopt routing privileges to access such, or is this just not available in the SDK period? If not available in the iOS7 SDK, knowing what options exist as services, would be a helpful pointer.

    Read the article

  • get element position

    - by hopes
    how can i know that a specific is on another specific after dragging the first and drop it I am using this code in the head of my document to enable drag and drop of my divs var dragapproved=false var z,x,y function move(){ if (event.button==1&&dragapproved){ z.style.pixelLeft=temp1+event.clientX-x z.style.pixelTop=temp2+event.clientY-y return false } } function drags() { if (!document.all) return if (event.srcElement.className=="drag") { dragapproved=true z=event.srcElement temp1=z.style.pixelLeft temp2=z.style.pixelTop x=event.clientX y=event.clientY document.onmousemove=move } } document.onmousedown=drags document.onmouseup=new Function('dragapproved=false')

    Read the article

  • Easiest way to position camera in XNA?

    - by DMan
    Everytime I load my model into XNA, I can usually see it far off in the distance. When I change some parameters and make it zoom up close, 10/10 times it's rotated funny and I'm set with the task of rotating it. Is there any easy way to do it except by experimenting? Or am I exporting it wrong (using Blender)? Is there any value I should set the objects in my 3d scene to be before exporting it so they appear 'upright'?

    Read the article

  • How to position some text?

    - by Faery
    Sorry for the noobie and stupid question, but I know only a bit about css and I don't know how to style my site. Here is my code: HTML (Twig) : <div class="wrap"> <div> <img class="birthday" src="http://www.clker.com/cliparts/1/d/a/6/11970917161615154558carlitos_Balloons.svg.med.png"> <div class="try"> This friends have brithday today: {% for bd in birthdays %} <p> <a href="{{ path('friend_id', {'id': bd.id}) }}">{{ bd.name }}</a> <span class="years"> ({{ bd.years }} years) </span> </p> {% endfor %} </div> </div> </div> CSS: body { background-color: #FFFFF1; text-align: center; font-size: 17px; font-family: Tahoma, Geneva, sans-serif; } p { margin: 10px; } a { text-decoration: none; color: #6a9211; } a:hover { text-decoration: underline; } .wrap { width: 700px; margin: auto; } .birthday { width: 49px; height: 80px; float: left; margin-left: 150px; display: block; } .try { display: block; margin-right: 150px; margin-bottom: 50px; } .years { font-size: 12px; } And this is what I get. The thing I want to fix is Maria and Peter to be display under Anna and John, all of them 4 centered under the label This friends have birthday today:. I know that it's because of the image, but I don't know how to make it look fine. :( Please help! Thanks in advance!

    Read the article

  • Flexslider position of previous and next slides

    - by TJ15
    I am using the basic flexslider, I wantto display some of the previous and next , so if slide 2 is showing you will see part of slide 1 to the left and part of slide 3 to the right. <!DOCTYPE html> <head> <link rel="stylesheet" href="flexslider.css" type="text/css"> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.2/jquery.min.js"></script> <style> .container {overflow: hidden; width: 100%} .flexslider {max-width: 500px; width: 500px; margin: 0 auto} .content {background: #f2f2f2; max-width: 500px; display: block; margin: 0 auto} .flex-viewport {overflow: visible !important} </style> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <div class="container"> <div class="flexslider"> <ul class="slides"> <li><img src="785.jpg" /></li> <li><img src="785.jpg" /></li> <li><img src="785.jpg" /></li> <li><img src="785.jpg" /></li> </ul> </div> </div> <script src="jquery.flexslider.js"></script> <script> jQuery(document).ready(function($) { // You can use the locally-scoped $ in here as an alias to jQuery. $(window).load(function() { $('.flexslider').flexslider(); }); }); </script> </body> </html> I have reduced the image to 70% and positioned it in the middle of the page. I want to have the next and previous slides visible on either side of the main pic but no idea where to make the appropriate changes (I assume in the js file). I thought this was a margin issue but setting this to 0 in styles makes no difference. Has anyone done this and can provide some advice?

    Read the article

  • Android return to the original position of the view after MotionEvent

    - by Kurty
    My application currently changes to another random int (View) when I let go of it (ACTION_UP) but the view stays in the same spot where I dropped it. I want it to return to the original location (the middle of the screen) when I drop it so I can repeat the process. // OnTouch and MotionEvent OnTouchListener dragt = new OnTouchListener() { public boolean onTouch(View v, MotionEvent me) { FrameLayout.LayoutParams par = (FrameLayout.LayoutParams) v.getLayoutParams(); switch (v.getId()) { case R.id.randomView: } switch(me.getAction()) { case MotionEvent.ACTION_MOVE: par.gravity = 0; par.setMargins((int)me.getRawX() - (v.getWidth())/2, (int)me.getRawY() - (v.getHeight())/2, 0, 0); v.setLayoutParams(par); break; case MotionEvent.ACTION_UP: // tallies score. score++; textScore.setText(String.valueOf(score)); // this generates the new view but the location is still the same color.setImageResource(mImageIds[rgenerator.nextInt(mImageIds.length)]); break; } return true; } };

    Read the article

  • Type Declaration - Pointer Asterisk Position

    - by sahs
    Hello, in C++, the following means "allocate memory for an int pointer": int* number; So, the asterisk is part of the variable type; without it, that would mean something else (that's why I usually don't separate the asterisk from the variable type). Then what is the reason the asterisk is considered something else, instead of being part of the type? For example, it seems better, if the following meant "allocate memory for two int pointers": int* number1, number2; Am I wrong?

    Read the article

  • Java return to position N in call stack.

    - by Finbarr
    Using the return keyword in Java code will return execution to the last piece of calling code in the call stack. If object foo calls baz.bar(), the return keyword in the bar method will continue code execution in foo. Let's say I have object foo that calls foofoo that calls foofoofoo in the above scenario, and foofoofoo calls baz.bar(). Is there anyway in Java to use the return keyword, or something else, so that the code in the bar method can return all the way back up to foo? (WITHOUT THROWING AN EXCEPTION)

    Read the article

  • jQuery - Ajax post result in html displaying in wrong position

    - by Sev
    I have a site with user posted threads that get voted on (up or down), and a vote count is displayed next to each thread. The voting up and down process is being done through jQuery/Ajax, and using something like this: $.ajax({ url: 'vote.php', success: function(data) { $('.result').html(data); } }); the html of the vote count is being updated (.result being the class of the div that holds the vote count number) Also, the threads are being sorted first by vote count descending, and then alphabetically. I'm having a problem with the ajax updating the HTML vote count in real time, i have a hunch that the issue is due to the fact that the order of the threads are changing when the vote count is being updated, but I'm not certain. I know the database is being updated, and when I refresh the page, it's also being updated correctly, but I'm not seeing the real-time behavior that I expect from jQuery/Ajax. What might be the problem?

    Read the article

< Previous Page | 23 24 25 26 27 28 29 30 31 32 33 34  | Next Page >