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  • comparision of strings

    - by EmiLazE
    i am writing a program, that simulates game mastermind. but i am struggling on how to compare guessed pattern to key pattern. the game conditions are a little bit changed: patterns consist of letters. if an element of guessed pattern is equal to element of key pattern, and also index is equal, then print b. if an element of guessed pattern is equal to element of key pattern, but index is not, then print w. if an element of guessed pattern is not equal to element of key pattern, print dot. in feedback about guessed pattern, 'b's come first, 'w's second, '.'s last. my problem is that i cannot think of a way totally satisfies the answer. for (i=0; i<patternlength; i++) { for (x=0; x<patternlength; x++) { if (guess[i]==key[x] && i==x) printf("b"); if (guess[i]==key[x] && i!=x) printf("w"); if (guess[i]!=key[x]) printf("."); } }

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  • Reading a text file, and performing actions based on strings read

    - by user1691766
    Let me start off by saying that I really am quite new to C. So basically I have a text file (contains around 30 assembly instructions, separated by new lines), and I am successfully reading them into my program. From here I need to perform certain actions based off each instruction. I would assume the best way to do this would be via a switch-case statement. However I am encountering a lot of problems due to me trying to compare strings that are 33 characters long. Can anyone please offer me advice on what I am doing wrong, or offer an alternative? Thanks in advance. Here is what I have so far: char instruction[29][ 33 ]; int i,run; i = 0; run = 1; FILE *instPtr; /* LOADING INSTRUCTIONS FROM FILE INTO "instruction" ARRAY*/ if ( ( instPtr = fopen("MIPSinstructions.txt", "r") ) == NULL ) { printf("File could not be opened\n"); } // end if else { fscanf( instPtr, "%s", instruction[0]); printf("%s\n", instruction[0]); while (!feof( instPtr ) ){ i++; fscanf( instPtr, "%s", instruction[i]); printf("%s\n", instruction[i]); } fclose( instPtr ); i = 0; // Reset the counter } //end else return 0; }

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  • DOS "pause" in Linux?

    - by user2930466
    Firstly, I'm REALLY new to programming. I've just started my first programming class two weeks ago, and I apologize if I sound newbish. My professor wants me to implement a "press any key to continue..." thing in my program. Basically when I run a program, he wants one line to come up [like printf("jfdskaljlfja");] then what would come up is "press any key to continue," before the next line runs. he told us that the DOS equivalent is system("pause"), but he wants us to do it linux. This is what my code looks like: #include <stdio.h> int main() { printf("This is the first line of this program); system("pause"); printf("This is the second line); } Except he wants us to do this in Linux, so system("pause") won't work in this case. Is there a way to have it do exactly what pause does, but in linux terms? again, sorry if i sound newbish. thank you so much! Also, he doesn't really care if the code is efficient or anything, as long as it runs. Again, i'm really new to programming, so the simplest answer would be much appreciated :)

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  • Need help finding a unique value in array

    - by bardockyo
    My code is complete minus one little flaw. It searches the array and prints out which values are unique, however it always counts the first entry as unique even if it is followed by the same value. Can anyone look at my code and tell me which part is messing this up because it is driving me crazy. #include <stdio.h> #define size 7 int main(void) { int array1[size], target, answer, found, x, k, prev, count =1, i; printf("Please input %d integers: ", size); scanf("%d", &target); for(x = 0; x < size; x++) { scanf("%d", &array1[x]); } prev = array1[0]; for (i = 1; i < size; i++) { if (array1[i] == prev) { count++; } else { if (count < 2) printf("%d=%d\n", prev, count); prev = array1[i]; count = 1; } } if (count < 2) { printf("%d=%d\n", prev, count); } return 0; }

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  • How is the MTU is 65535 in UDP but ethernet does not allow frame size more than 1500 bytes

    - by nikku
    I am using a fast ethernet of 100 Mbps, whose frame size is less than 1500 bytes (1472 bytes for payload as per my textbook). In that, I was able to send and receive a UDP packet of message size 65507 bytes, which means the packet size was 65507 + 20 (IP Header) + 8 (UDP Header) = 65535. If the frame's payload size itself is maximum of 1472 bytes (as per my textbook), how can the packet size of IP be greater than that which here is 65535? I used sender code as char buffer[100000]; for (int i = 1; i < 100000; i++) { int len = send (socket_id, buffer, i); printf("%d\n", len); } Receiver code as while (len = recv (socket_id, buffer, 100000)) { printf("%d\n". len); } I observed that send returns -1 on i > 65507 and recv prints or receives a packet of maximum of length 65507.

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  • Nagios - NagWin - Send notification with gmail

    - by Attila Bujáki
    I would like to send Nagios notifications using my gmail account. I have already set up my hosts I want to monitor and services also. What is the most simple way to accomplish this using NagWin on a Windows Server 2012 installation? As far as I know I must change some of these configuration settings: # 'notify-host-by-email' command definition define command{ command_name notify-host-by-email command_line /usr/bin/printf "%b" "***** Nagios *****\n\nNotification Type: $NOTIFICATIONTYPE$\nHost: $HOSTNAME$\nState: $HOSTSTATE$\nAddress: $HOSTADDRESS$\nInfo: $HOSTOUTPUT$\n\nDate/Time: $LONGDATETIME$\n" | /bin/blat - -to $CONTACTEMAIL$ -f nagios@localhost -subject "** $NOTIFICATIONTYPE$ Host Alert: $HOSTNAME$ is $HOSTSTATE$ **" -server ??? } # 'notify-service-by-email' command definition define command{ command_name notify-service-by-email command_line /usr/bin/printf "%b" "***** Nagios *****\n\nNotification Type: $NOTIFICATIONTYPE$\n\nService: $SERVICEDESC$\nHost: $HOSTALIAS$\nAddress: $HOSTADDRESS$\nState: $SERVICESTATE$\n\nDate/Time: $LONGDATETIME$\n\nAdditional Info:\n\n$SERVICEOUTPUT$\n" | /bin/blat - -to $CONTACTEMAIL$ -f nagios@localhost -subject "** $NOTIFICATIONTYPE$ Service Alert: $HOSTALIAS$/$SERVICEDESC$ is $SERVICESTATE$ **" -server ??? } What should I use for smtp server? Is it possible to directly send my notifications to the Gmail server?

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  • How is the MTU is 65535 in UDP but ethernet does not allow frame size more than 1500 bytes

    - by nikku
    I am using a fast ethernet of 100 Mbps, whose frame size is less than 1500 bytes (1472 bytes for payload as per my textbook). In that, I was able to send and receive a UDP packet of message size 65507 bytes, which means the packet size was 65507 + 20 (IP Header) + 8 (UDP Header) = 65535. If the frame's payload size itself is maximum of 1472 bytes (as per my textbook), how can the packet size of IP be greater than that which here is 65535? I used sender code as char buffer[100000]; for (int i = 1; i < 100000; i++) { int len = send (socket_id, buffer, i); printf("%d\n", len); } Receiver code as while (len = recv (socket_id, buffer, 100000)) { printf("%d\n". len); } I observed that send returns -1 on i > 65507 and recv prints or receives a packet of maximum of length 65507.

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  • Nagios shell script cannot be executed

    - by MeinAccount
    I'm trying to monitor GitLab with nagios. I've created the following command definition and shell script but when checking the service I'm receiving the following e-mail. How can I solve this? The file is executable. [...] nagios : 3 incorrect password attempts ; TTY=unknown ; PWD=/ ; USER=git ; COMMAND=/bin/bash -c /var/lib/nagios/custom_plugins/check_gitlab.sh Command definition: define command { command_name custom_check_gitlab command_line /var/lib/nagios/custom_plugins/check_gitlab.sh } Shell script: #! /bin/sh # [...] RAILS_ENV="production" # Script variable names should be lower-case not to conflict with internal /bin/sh variables such as PATH, EDITOR or SHELL. app_root="/home/git/gitlab" app_user="git" unicorn_conf="$app_root/config/unicorn.rb" pid_path="$app_root/tmp/pids" socket_path="$app_root/tmp/sockets" web_server_pid_path="$pid_path/unicorn.pid" sidekiq_pid_path="$pid_path/sidekiq.pid" ### Here ends user configuration ### # Switch to the app_user if it is not he/she who is running the script. if [ "$USER" != "$app_user" ]; then sudo -u "$app_user" -H -i $0 "$@"; exit; fi # Switch to the gitlab path, if it fails exit with an error. if ! cd "$app_root" ; then echo "Failed to cd into $app_root, exiting!"; exit 1 fi ### Init Script functions check_pids(){ if ! mkdir -p "$pid_path"; then echo "Could not create the path $pid_path needed to store the pids." exit 1 fi # If there exists a file which should hold the value of the Unicorn pid: read it. if [ -f "$web_server_pid_path" ]; then wpid=$(cat "$web_server_pid_path") else wpid=0 fi if [ -f "$sidekiq_pid_path" ]; then spid=$(cat "$sidekiq_pid_path") else spid=0 fi } # Checks whether the different parts of the service are already running or not. check_status(){ check_pids # If the web server is running kill -0 $wpid returns true, or rather 0. # Checks of *_status should only check for == 0 or != 0, never anything else. if [ $wpid -ne 0 ]; then kill -0 "$wpid" 2>/dev/null web_status="$?" else web_status="-1" fi if [ $spid -ne 0 ]; then kill -0 "$spid" 2>/dev/null sidekiq_status="$?" else sidekiq_status="-1" fi } check_pids check_status if [ "$web_status" != "0" -a "$sidekiq_status" != "0" ]; then echo "GitLab is not running." exit 2 fi if [ "$web_status" != "0" ]; then printf "The GitLab Unicorn webserver is \033[31mnot running\033[0m.\n" exit 1 fi if [ "$sidekiq_status" != "0" ]; then printf "The GitLab Sidekiq job dispatcher is \033[31mnot running\033[0m.\n" exit 1 fi if [ "$web_status" = "0" -a "$sidekiq_status" = "0" ]; then printf "GitLab and all it's components are \033[32mup and running\033[0m.\n" exit 0 fi

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  • Bash: Quotes getting stripped when a command is passed as argument to a function

    - by Shoaibi
    I am trying to implement a dry run kind of mechanism for my script and facing the issue of quotes getting stripped off when a command is passed as an argument to a function and resulting in unexpected behavior. dry_run () { echo "$@" #printf '%q ' "$@" if [ "$DRY_RUN" ]; then return 0 fi "$@" } email_admin() { echo " Emailing admin" dry_run su - $target_username -c "cd $GIT_WORK_TREE && git log -1 -p|mail -s '$mail_subject' $admin_email" echo " Emailed" } Output is: su - webuser1 -c cd /home/webuser1/public_html && git log -1 -p|mail -s 'Git deployment on webuser1' [email protected] Expected: su - webuser1 -c "cd /home/webuser1/public_html && git log -1 -p|mail -s 'Git deployment on webuser1' [email protected]" With printf enabled instead of echo: su - webuser1 -c cd\ /home/webuser1/public_html\ \&\&\ git\ log\ -1\ -p\|mail\ -s\ \'Git\ deployment\ on\ webuser1\'\ [email protected] Result: su: invalid option -- 1 That shouldn't be the case if quotes remained where they were inserted. I have also tried using "eval", not much difference. If i remove the dry_run call in email_admin and then run script, it work great.

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  • Does a successful exit of rsync -acvvv s d guarantee identical directory trees?

    - by user259774
    I have two volumes, one xfs, and another ntfs - ntfs was empty, and xfs had 10 subitems. I needed to sync them. I initially copied a few of the subitems by dragging them over in a gui fm. Several of the direct descendants which i had dragged finished, apparently. One I stopped before it was done, and the rest I cancelled while it still appeared to be gathering information about the files. Then I ran rsync -acvvv xmp/ nmp/, where xmp and nmp are the volumes' respective mountpoints, which exited with a 0 status. find xmp -printf x | wc -c and find nmp -printf x | wc -c both return 372926. My question is: Am I guaranteed that the two drives' contents are identical?

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  • 5x5 matrix multiplication in C

    - by Rick
    I am stuck on this problem in my homework. I've made it this far and am sure the problem is in my three for loops. The question directly says to use 3 for loops so I know this is probably just a logic error. #include<stdio.h> void matMult(int A[][5],int B[][5],int C[][5]); int printMat_5x5(int A[5][5]); int main() { int A[5][5] = {{1,2,3,4,6}, {6,1,5,3,8}, {2,6,4,9,9}, {1,3,8,3,4}, {5,7,8,2,5}}; int B[5][5] = {{3,5,0,8,7}, {2,2,4,8,3}, {0,2,5,1,2}, {1,4,0,5,1}, {3,4,8,2,3}}; int C[5][5] = {0}; matMult(A,B,C); printMat_5x5(A); printf("\n"); printMat_5x5(B); printf("\n"); printMat_5x5(C); return 0; } void matMult(int A[][5], int B[][5], int C[][5]) { int i; int j; int k; for(i = 0; i <= 2; i++) { for(j = 0; j <= 4; j++) { for(k = 0; k <= 3; k++) { C[i][j] += A[i][k] * B[k][j]; } } } } int printMat_5x5(int A[5][5]){ int i; int j; for (i = 0;i < 5;i++) { for(j = 0;j < 5;j++) { printf("%2d",A[i][j]); } printf("\n"); } } EDIT: Here is the question, sorry for not posting it the first time. (2) Write a C function to multiply two five by five matrices. The prototype should read void matMult(int a[][5],int b[][5],int c[][5]); The resulting matrix product (a times b) is returned in the two dimensional array c (the third parameter of the function). Program your solution using three nested for loops (each generating the counter values 0, 1, 2, 3, 4) That is, DO NOT code specific formulas for the 5 by 5 case in the problem, but make your code general so it can be easily changed to compute the product of larger square matrices. Write a main program to test your function using the arrays a: 1 2 3 4 6 6 1 5 3 8 2 6 4 9 9 1 3 8 3 4 5 7 8 2 5 b: 3 5 0 8 7 2 2 4 8 3 0 2 5 1 2 1 4 0 5 1 3 4 8 2 3 Print your matrices in a neat format using a C function created for printing five by five matrices. Print all three matrices. Generate your test arrays in your main program using the C array initialization feature. enter code here

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  • OSX: How to get a volume name (or bsd name) from a IOUSBDeviceInterface or location id

    - by LG
    Hi, I'm trying to write an app that associates a particular USB string descriptor (of a USB mass storage device) with its volume or bsd name. So the code goes through all the connected USB devices, gets the string descriptors and extracts information from one of them. I would like to get the volume name of those USB devices. I can't find the right API to do that. I have tried to do that: DASessionRef session = DASessionCreate(kCFAllocatorDefault); DADiskRef disk_ref = DADiskCreateFromIOMedia(kCFAllocatorDefault, session, usb_device_ref); const char* name = DADiskGetBSDName(disk_ref); But the DADiskCreateFromIOMedia function returned nil, I assume the usb_device_ref that I passed was not compatible with the io_service_t that the function is expecting. So how can I get the volume name of a USB device? Could I use the location id to do that? Thanks for reading. -L FOO_Result result = FOO_SUCCESS; mach_port_t master_port; kern_return_t k_result; io_iterator_t iterator = 0; io_service_t usb_device_ref; CFMutableDictionaryRef matching_dictionary = NULL; // first create a master_port if (FOO_FAILED(k_result = IOMasterPort(MACH_PORT_NULL, &master_port))) { fprintf(stderr, "could not create master port, err = %d\n", k_result); goto cleanup; } if ((matching_dictionary = IOServiceMatching(kIOUSBDeviceClassName)) == NULL) { fprintf(stderr, "could not create matching dictionary, err = %d\n", k_result); goto cleanup; } if (FOO_FAILED(k_result = IOServiceGetMatchingServices(master_port, matching_dictionary, &iterator))) { fprintf(stderr, "could not find any matching services, err = %d\n", k_result); goto cleanup; } while (usb_device_ref = IOIteratorNext(iterator)) { IOReturn err; IOCFPlugInInterface **iodev; // requires <IOKit/IOCFPlugIn.h> IOUSBDeviceInterface **dev; SInt32 score; err = IOCreatePlugInInterfaceForService(usb_device_ref, kIOUSBDeviceUserClientTypeID, kIOCFPlugInInterfaceID, &iodev, &score); if (err || !iodev) { printf("dealWithDevice: unable to create plugin. ret = %08x, iodev = %p\n", err, iodev); return; } err = (*iodev)->QueryInterface(iodev, CFUUIDGetUUIDBytes(kIOUSBDeviceInterfaceID), (LPVOID*)&dev); (*iodev)->Release(iodev); // done with this FOO_String string_value; UInt8 string_index = 0x1; FOO_Result result = FOO_SUCCESS; CFStringRef device_name_as_cf_string; do { if (FOO_SUCCEEDED(result = FOO_GetStringDescriptor(dev, string_index, 0, string_value))) { printf("String at index %i is %s\n", string_index, string_value.GetChars()); // extract the command code if it is the FOO string if (string_value.CompareN("FOO:", 4) == 0) { FOO_Byte code = 0; FOO_HexToByte(string_value.GetChars() + 4, code); // Get other relevant information from the device io_name_t device_name; UInt32 location_id = 0; // Get the USB device's name. err = IORegistryEntryGetName(usb_device_ref, device_name); device_name_as_cf_string = CFStringCreateWithCString(kCFAllocatorDefault, device_name, kCFStringEncodingASCII); err = (*dev)->GetLocationID(dev, &location_id); // TODO: get volume or BSD name // add the device to the list break; } } string_index++; } while (FOO_SUCCEEDED(result)); err = (*dev)->USBDeviceClose(dev); if (err) { printf("dealWithDevice: error closing device - %08x\n", err); (*dev)->Release(dev); return; } err = (*dev)->Release(dev); if (err) { printf("dealWithDevice: error releasing device - %08x\n", err); return; } IOObjectRelease(usb_device_ref); // no longer need this reference }

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  • how to get vendor id and product id of a plugged usb device on windows

    - by new
    Hello all, I am using Qt on windows platform. i want to get and display vendor id and product id of a plugged usb device from my local system. Below is my full source code to get the vendor id and product id from the usb device. when i run the my qt application it does not throw me any errors . so i plug the usb device into the system. but my print statement displays the result as below qDebug ()<DevicePath; i get the result as 0x4 Whether i have any implementation mistakes in my source code ? if so please guide me what i am doing wrong.. Have i missed out any other functions ? Is it possible to get the vendor id and product id from the usb device based on my source code .( my implementation of the code ) ? kindly find my source code below static GUID GUID_DEVINTERFACE_USB_DEVICE = { 0xA5DCBF10L, 0x6530, 0x11D2, { 0x90, 0x1F, 0x00, 0xC0, 0x4F, 0xB9, 0x51, 0xED } }; HANDLE hInfo = SetupDiGetClassDevs(&GUID_DEVINTERFACE_USB_DEVICE,NULL,NULL,DIGCF_PRESENT | DIGCF_INTERFACEDEVICE); if ( hInfo == INVALID_HANDLE_VALUE ) { qDebug ()<<"invalid"; } else { qDebug ()<<"valid handle"; SP_DEVINFO_DATA DeviceInfoData; DeviceInfoData.cbSize = sizeof(SP_DEVINFO_DATA); SP_INTERFACE_DEVICE_DATA Interface_Info; Interface_Info.cbSize = sizeof(Interface_Info); BYTE Buf[1024]; DWORD i; DWORD InterfaceNumber= 0; PSP_DEVICE_INTERFACE_DETAIL_DATA pspdidd = (PSP_DEVICE_INTERFACE_DETAIL_DATA)Buf; for (i=0;SetupDiEnumDeviceInfo(hInfo,i,&DeviceInfoData);i++) { DWORD DataT; LPTSTR buffer = NULL; DWORD buffersize = 0; while (!SetupDiGetDeviceRegistryProperty( hInfo,&DeviceInfoData,SPDRP_DEVICEDESC,&DataT,(PBYTE)buffer,buffersize,&buffersize)) { if (GetLastError() == ERROR_INSUFFICIENT_BUFFER) { // Change the buffer size. if (buffer) LocalFree(buffer); buffer = (LPTSTR)LocalAlloc(LPTR,buffersize); } else { // Insert error handling here. break; } qDebug ()<<(TEXT("Device Number %i is: %s\n"),i, buffer); if (buffer) LocalFree(buffer); if ( GetLastError()!=NO_ERROR && GetLastError()!=ERROR_NO_MORE_ITEMS ) { // Insert error handling here. qDebug ()<<"return false"; } InterfaceNumber = 0; // this just returns the first one, you can iterate on this if (SetupDiEnumDeviceInterfaces(hInfo,NULL,&GUID_DEVINTERFACE_USB_DEVICE,InterfaceNumber,&Interface_Info)) { printf("Got interface"); DWORD needed; pspdidd->cbSize = sizeof(*pspdidd); SP_DEVICE_INTERFACE_DETAIL_DATA *pDetData = NULL; DWORD dwDetDataSize = sizeof (SP_DEVICE_INTERFACE_DETAIL_DATA) + 256; SetupDiGetDeviceInterfaceDetail(hInfo, &Interface_Info, pDetData,dwDetDataSize, NULL,&DeviceInfoData); qDebug ()<<pDetData->DevicePath; //qDebug ()<<QString::fromWCharArray(pDetData->DevicePath); } else { printf("\nNo interface"); //ErrorExit((LPTSTR) "SetupDiEnumDeviceInterfaces"); if ( GetLastError() == ERROR_NO_MORE_ITEMS) printf(", since there are no more items found."); else printf(", unknown reason."); } // Cleanup SetupDiDestroyDeviceInfoList(hInfo); qDebug ()<<"return true"; } } }

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  • c - dereferencing issue

    - by Joe
    Hi, I have simplified an issue that I've been having trying to isolate the problem, but it is not helping. I have a 2 dimensional char array to represent memory. I want to pass a reference to that simulation of memory to a function. In the function to test the contents of the memory I just want to iterate through the memory and print out the contents on each row. The program prints out the first row and then I get seg fault. My program is as follows: #include <stdio.h> #include <stdlib.h> #include <ctype.h> #include <string.h> void test_memory(char*** memory_ref) { int i; for(i = 0; i < 3; i++) { printf("%s\n", *memory_ref[i]); } } int main() { char** memory; int i; memory = calloc(sizeof(char*), 20); for(i = 0; i < 20; i++) { memory[i] = calloc(sizeof(char), 33); } memory[0] = "Mem 0"; memory[1] = "Mem 1"; memory[2] = "Mem 2"; printf("memory[1] = %s\n", memory[1]); test_memory(&memory); return 0; } This gives me the output: memory[1] = Mem 1 Mem 0 Segmentation fault If I change the program and create a local version of the memory in the function by dereferencing the memory_ref, then I get the right output: So: #include <stdio.h> #include <stdlib.h> #include <ctype.h> #include <string.h> void test_memory(char*** memory_ref) { char** memory = *memory_ref; int i; for(i = 0; i < 3; i++) { printf("%s\n", memory[i]); } } int main() { char** memory; int i; memory = calloc(sizeof(char*), 20); for(i = 0; i < 20; i++) { memory[i] = calloc(sizeof(char), 33); } memory[0] = "Mem 0"; memory[1] = "Mem 1"; memory[2] = "Mem 2"; printf("memory[1] = %s\n", memory[1]); test_memory(&memory); return 0; } gives me the following output: memory[1] = Mem 1 Mem 0 Mem 1 Mem 2 which is what I want, but making a local version of the memory is useless because I need to be able to change the values of the original memory from the function which I can only do by dereferencing the pointer to the original 2d char array. I don't understand why I should get a seg fault on the second time round, and I'd be grateful for any advice. Many thanks Joe

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  • push_back of STL list got bad performance?

    - by Leon Zhang
    I wrote a simple program to test STL list performance against a simple C list-like data structure. It shows bad performance at "push_back()" line. Any comments on it? $ ./test2 Build the type list : time consumed -> 0.311465 Iterate over all items: time consumed -> 0.00898 Build the simple C List: time consumed -> 0.020275 Iterate over all items: time consumed -> 0.008755 The source code is: #include <stdexcept> #include "high_resolution_timer.hpp" #include <list> #include <algorithm> #include <iostream> #define TESTNUM 1000000 /* The test struct */ struct MyType { int num; }; /* * C++ STL::list Test */ typedef struct MyType* mytype_t; void myfunction(mytype_t t) { } int test_stl_list() { std::list<mytype_t> mylist; util::high_resolution_timer t; /* * Build the type list */ t.restart(); for(int i = 0; i < TESTNUM; i++) { mytype_t aItem = (mytype_t) malloc(sizeof(struct MyType)); if(aItem == NULL) { printf("Error: while malloc\n"); return -1; } aItem->num = i; mylist.push_back(aItem); } std::cout << " Build the type list : time consumed -> " << t.elapsed() << std::endl; /* * Iterate over all item */ t.restart(); std::for_each(mylist.begin(), mylist.end(), myfunction); std::cout << " Iterate over all items: time consumed -> " << t.elapsed() << std::endl; return 0; } /* * a simple C list */ struct MyCList; struct MyCList{ struct MyType m; struct MyCList* p_next; }; int test_simple_c_list() { struct MyCList* p_list_head = NULL; util::high_resolution_timer t; /* * Build it */ t.restart(); struct MyCList* p_new_item = NULL; for(int i = 0; i < TESTNUM; i++) { p_new_item = (struct MyCList*) malloc(sizeof(struct MyCList)); if(p_new_item == NULL) { printf("ERROR : while malloc\n"); return -1; } p_new_item->m.num = i; p_new_item->p_next = p_list_head; p_list_head = p_new_item; } std::cout << " Build the simple C List: time consumed -> " << t.elapsed() << std::endl; /* * Iterate all items */ t.restart(); p_new_item = p_list_head; while(p_new_item->p_next != NULL) { p_new_item = p_new_item->p_next; } std::cout << " Iterate over all items: time consumed -> " << t.elapsed() << std::endl; return 0; } int main(int argc, char** argv) { if(test_stl_list() != 0) { printf("ERROR: error at testcase1\n"); return -1; } if(test_simple_c_list() != 0) { printf("ERROR: error at testcase2\n"); return -1; } return 0; }

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  • Trying to sentinel loop this program.

    - by roger34
    Okay, I spent all this time making this for class but I have one thing that I can't quite get: I need this to sentinel loop continuously (exiting upon entering x) so that the System.out.println("What type of Employee? Enter 'o' for Office " + "Clerical, 'f' for Factory, or 's' for Saleperson. Enter 'x' to exit." ); line comes back up after they enter the first round of information. Also, I can't leave this up long on the (very) off chance a classmate might see this and steal the code. Full code following: import java.util.Scanner; public class Project1 { public static void main (String args[]){ Scanner inp = new Scanner( System.in ); double totalPay; System.out.println("What type of Employee? Enter 'o' for Office " + "Clerical, 'f' for Factory, or 's' for Saleperson. Enter 'x' to exit." ); String response= inp.nextLine(); while (!response.toLowerCase().equals("o")&&!response.toLowerCase().equals("f") &&!response.toLowerCase().equals("s")&&!response.toLowerCase().equals("x")){ System.out.print("\nInvalid selection,please enter your choice again:\n"); response=inp.nextLine(); } char choice = response.toLowerCase().charAt( 0 ); switch (choice){ case 'o': System.out.println("Enter your hourly rate:"); double officeRate=inp.nextDouble(); System.out.println("Enter the number of hours worked:"); double officeHours=inp.nextDouble(); totalPay = officeCalc(officeRate,officeHours); taxCalc(totalPay); break; case 'f': System.out.println("How many Widgets did you produce during the week?"); double widgets=inp.nextDouble(); totalPay=factoryCalc(widgets); taxCalc(totalPay); break; case 's': System.out.println("What were your total sales for the week?"); double totalSales=inp.nextDouble(); totalPay=salesCalc(totalSales); taxCalc(totalPay); break; } } public static double taxCalc(double totalPay){ double federal=totalPay*.22; double state =totalPay*.055; double netPay = totalPay - federal - state; federal =federal*Math.pow(10,2); federal =Math.round(federal); federal= federal/Math.pow(10,2); state =state*Math.pow(10,2); state =Math.round(state); state= state/Math.pow(10,2); totalPay =totalPay*Math.pow(10,2); totalPay =Math.round(totalPay); totalPay= totalPay/Math.pow(10,2); netPay =netPay*Math.pow(10,2); netPay =Math.round(netPay); netPay= netPay/Math.pow(10,2); System.out.printf("\nTotal Pay \t: %1$.2f.\n", totalPay); System.out.printf("State W/H \t: %1$.2f.\n", state); System.out.printf("Federal W/H : %1$.2f.\n", federal); System.out.printf("Net Pay \t: %1$.2f.\n", netPay); return totalPay; } public static double officeCalc(double officeRate,double officeHours){ double overtime=0; if (officeHours>=40) overtime = officeHours-40; else overtime = 0; if (officeHours >= 40) officeHours = 40; double otRate = officeRate * 1.5; double totalPay= (officeRate * officeHours) + (otRate*overtime); return totalPay; } public static double factoryCalc(double widgets){ double totalPay=widgets*.35 +300; return totalPay; } public static double salesCalc(double totalSales){ double totalPay = totalSales * .05 + 500; return totalPay; } }

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  • Problem on getting the vendor id and product id of a usb device

    - by new
    Hi... my application comes and prints this "\?\usb#vid_04f2&pid_0111#5&1ba5a77f&0&2#{a5dcbf1 0-6530-11d2-901f-00c04fb951ed}" again it goes to while loop .... here it gets breaked in the else statement... Qt Code: if (GetLastError() == ERROR_INSUFFICIENT_BUFFER) { // Change the buffer size. if (buffer) LocalFree(buffer); buffer = (LPTSTR)LocalAlloc(LPTR,buffersize); } else { qDebug ()<<"Here it quits the application"; // Insert error handling here. break; } Any ideas in this.... full source code comes here static GUID GUID_DEVINTERFACE_USB_DEVICE = { 0xA5DCBF10L, 0x6530, 0x11D2, { 0x90, 0x1F, 0x00, 0xC0, 0x4F, 0xB9, 0x51, 0xED } }; HANDLE hInfo = SetupDiGetClassDevs(&GUID_DEVINTERFACE_USB_DEVICE,NULL,NULL, DIGCF_PRESENT | DIGCF_INTERFACEDEVICE); if ( hInfo == INVALID_HANDLE_VALUE ) { qDebug ()<<"invalid"; } else { qDebug ()<<"valid handle"; SP_DEVINFO_DATA DeviceInfoData; DeviceInfoData.cbSize = sizeof(SP_DEVINFO_DATA); SP_INTERFACE_DEVICE_DATA Interface_Info; Interface_Info.cbSize = sizeof(Interface_Info); BYTE Buf[1024]; DWORD i; DWORD InterfaceNumber= 0; PSP_DEVICE_INTERFACE_DETAIL_DATA pspdidd = (PSP_DEVICE_INTERFACE_DETAIL_DATA) Buf; for (i=0;SetupDiEnumDeviceInfo(hInfo,i,&DeviceInfoData);i++) { DWORD DataT; LPTSTR buffer = NULL; DWORD buffersize = 0; while (!SetupDiGetDeviceRegistryProperty( hInfo, &DeviceInfoData,SPDRP_DEVICEDESC, &DataT,(PBYTE)buffer,buffersize, &buffersize)) { if (GetLastError() == ERROR_INSUFFICIENT_BUFFER) { // Change the buffer size. if (buffer) LocalFree(buffer); buffer = (LPTSTR)LocalAlloc(LPTR,buffersize); } else { // Insert error handling here. break; } qDebug ()<<(TEXT("Device Number %i is: %s\n"),i, buffer); if (buffer) LocalFree(buffer); if ( GetLastError() != NO_ERROR && GetLastError() != ERROR_NO_MORE_ITEMS ) { // Insert error handling here. qDebug ()<<"return false"; } InterfaceNumber = 0; // this just returns the first one, you can iterate on this if (SetupDiEnumDeviceInterfaces(hInfo, NULL, &GUID_DEVINTERFACE_USB_DEVICE, InterfaceNumber, &Interface_Info)) { printf("Got interface"); DWORD needed; pspdidd->cbSize = sizeof(*pspdidd); SP_DEVICE_INTERFACE_DETAIL_DATA *pDetData = NULL; DWORD dwDetDataSize = sizeof (SP_DEVICE_INTERFACE_DETAIL_DATA) + 256; pDetData = (SP_DEVICE_INTERFACE_DETAIL_DATA*) malloc (dwDetDataSize); pDetData->cbSize = sizeof (SP_DEVICE_INTERFACE_DETAIL_DATA); SetupDiGetDeviceInterfaceDetail(hInfo,&Interface_Info, pDetData,dwDetDataSize, NULL,&DeviceInfoData); qDebug ()<<pDetData->DevicePath; qDebug ()<<QString::fromWCharArray(pDetData->DevicePath); free(pDetData); } else { printf("\nNo interface"); //ErrorExit((LPTSTR) "SetupDiEnumDeviceInterfaces"); if ( GetLastError() == ERROR_NO_MORE_ITEMS) printf(", since there are no more items found."); else printf(", unknown reason."); } // Cleanup SetupDiDestroyDeviceInfoList(hInfo); } } }

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  • Doxygen for C++ template class member specialization

    - by Ziv
    When I write class templates, and need to fully-specialize members of those classes, Doxygen doesn't recognize the specialization - it documents only the generic definition, or (if there are only specializations) the last definition. Here's a simple example: ===MyClass.hpp=== #ifndef MYCLASS_HPP #define MYCLASS_HPP template<class T> class MyClass{ public: static void foo(); static const int INT_CONST; static const T TTYPE_CONST; }; /* generic definitions */ template<class T> void MyClass<T>::foo(){ printf("Generic foo\n"); } template<class T> const int MyClass<T>::INT_CONST = 5; /* specialization declarations */ template<> void MyClass<double>::foo(); template<> const int MyClass<double>::INT_CONST; template<> const double MyClass<double>::TTYPE_CONST; template<> const char MyClass<char>::TTYPE_CONST; #endif === MyClass.cpp === #include "MyClass.hpp" /* specialization definitions */ template<> void MyClass<double>::foo(){ printf("Specialized double foo\n"); } template<> const int MyClass<double>::INT_CONST = 10; template<> const double MyClass<double>::TTYPE_CONST = 3.141; template<> const char MyClass<char>::TTYPE_CONST = 'a'; So in this case, foo() will be documented as printing "Generic foo," INT_CONST will be documented as set to 5, with no mention of the specializations, and TTYPE_CONST will be documented as set to 'a', with no mention of 3.141 and no indication that 'a' is a specialized case. I need to be able to document the specializations - either within the documentation for MyClass<T>, or on new pages for MyClass<double>, MyClass<char>. How do I do this? Can Doxygen even handle this? Am I possibly doing something wrong in the declarations/code structure that's keeping Doxygen from understanding what I want? I should note two related cases: A) For templated functions, specialization works fine, e.g.: /* functions that are global/in a namespace */ template<class T> void foo(){ printf("Generic foo\n"); } template<> void foo<double>(){ printf("Specialized double foo\n"); } This will document both foo() and foo(). B) If I redeclare the entire template, i.e. template<> class MyClass<double>{...};, then MyClass<double> will get its own documentation page, as a seperate class. But this means actually declaring an entirely new class - there is no relation between MyClass<T> and MyClass<double> if MyClass<double> itself is declared. So I'd have to redeclare the class and all its members, and repeat all the definitions of class members, specialized for MyClass<double>, all to make it appear as though they're using the same template. Very awkward, feels like a kludge solution. Suggestions? Thanks much :) --Ziv

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  • Why does this Quicksort work?

    - by IVlad
    I find this Quicksort partitioning approach confusing and wrong, yet it seems to work. I am referring to this pseudocode. Note: they also have a C implementation at the end of the article, but it's very different from their pseudocode, so I don't care about that. I have also written it in C like this, trying to stay true to the pseudocode as much as possible, even if that means doing some weird C stuff: #include <stdio.h> int partition(int a[], int p, int r) { int x = a[p]; int i = p - 1; int j = r + 1; while (1) { do j = j - 1; while (!(a[j] <= x)); do i = i + 1; while (!(a[i] >= x)); if (i < j) { int t = a[i]; a[i] = a[j]; a[j] = t; } else { for (i = 1; i <= a[0]; ++i) printf("%d ", a[i]); printf("- %d\n", j); return j; } } } int main() { int a[100] = //{8, 6,10,13,15,8,3,2,12}; {7, 7, 6, 2, 3, 8, 4, 1}; partition(a, 1, a[0]); return 0; } If you run this, you'll get the following output: 1 6 2 3 4 8 7 - 5 However, this is wrong, isn't it? Clearly a[5] does not have all the values before it lower than it, since a[2] = 6 > a[5] = 4. Not to mention that 7 is supposed to be the pivot (the initial a[p]) and yet its position is both incorrect and lost. The following partition algorithm is taken from wikipedia: int partition2(int a[], int p, int r) { int x = a[r]; int store = p; for (int i = p; i < r; ++i) { if (a[i] <= x) { int t = a[i]; a[i] = a[store]; a[store] = t; ++store; } } int t = a[r]; a[r] = a[store]; a[store] = t; for (int i = 1; i <= a[0]; ++i) printf("%d ", a[i]); printf("- %d\n", store); return store; } And produces this output: 1 6 2 3 8 4 7 - 1 Which is a correct result in my opinion: the pivot (a[r] = a[7]) has reached its final position. However, if I use the initial partitioning function in the following algorithm: void Quicksort(int a[], int p, int r) { if (p < r) { int q = partition(a, p, r); // initial partitioning function Quicksort(a, p, q); Quicksort(a, q + 1, r); // I'm pretty sure q + r was a typo, it doesn't work with q + r. } } ... it seems to be a correct sorting algorithm. I tested it out on a lot of random inputs, including all 0-1 arrays of length 20. I have also tried using this partition function for a selection algorithm, in which it failed to produce correct results. It seems to work and it's even very fast as part of the quicksort algorithm however. So my questions are: Can anyone post an example on which the algorithm DOESN'T work? If not, why does it work, since the partitioning part seems to be wrong? Is this another partitioning approach that I don't know about?

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  • How Can I Improve/SpeedUp This FrequentFunction in C?

    - by Peter Lee
    Hi folks, How can I improve / speed up this frequent function? #include <math.h> #include <stdio.h> #include <stdlib.h> #include <time.h> // Assumptions: x, y, z, a, b and c are all array of 10. // Requirement: return the value of ret; // get all elements of array c float fnFrequentFunction(const float* x, const float* y, const float* z, const float *a, const float *b, float *c, int M) { register float tmp; register float sum; register float ret = 0; int i; for (i = 0; i < M; i++) // M == 1, 2, 4, or 8 { sum = 0; tmp = x[0] - y[0]; sum += tmp * tmp * z[0]; tmp = x[1] - y[1]; sum += tmp * tmp * z[1]; tmp = x[2] - y[2]; sum += tmp * tmp * z[2]; tmp = x[3] - y[3]; sum += tmp * tmp * z[3]; tmp = x[4] - y[4]; sum += tmp * tmp * z[4]; tmp = x[5] - y[5]; sum += tmp * tmp * z[5]; tmp = x[6] - y[6]; sum += tmp * tmp * z[6]; tmp = x[7] - y[7]; sum += tmp * tmp * z[7]; tmp = x[8] - y[8]; sum += tmp * tmp * z[8]; tmp = x[9] - y[9]; sum += tmp * tmp * z[9]; ret += (c[i] = log(a[i] * b[i]) + sum); } return ret; } int main() { float x[10] = {0.001251f, 0.563585f, 0.193304f, 0.808741f, 0.585009f, 0.479873f, 0.350291f, 0.895962f, 0.622840f, 0.746605f}; float y[10] = {0.864406f, 0.709006f, 0.091433f, 0.995727f, 0.227180f, 0.902585f, 0.659047f, 0.865627f, 0.846767f, 0.514359f}; float z[10] = {0.866817f, 0.581347f, 0.175542f, 0.620197f, 0.781823f, 0.778588f, 0.938688f, 0.721610f, 0.940214f, 0.811353f}; float a[10] = {0.870205f, 0.733879f, 0.711386f, 0.588244f, 0.484176f, 0.852962f, 0.168126f, 0.684286f, 0.072573f, 0.632160f}; float b[10] = {0.871487f, 0.998108f, 0.798608f, 0.134831f, 0.576281f, 0.410779f, 0.402936f, 0.522935f, 0.623218f, 0.193030f}; float c[8]; int i; int n = 10000000; long start; // Speed test here: start = clock(); while(--n) fnFrequentFunction(x, y, z, a, b, c, 8); printf("Time used: %ld\n", clock() - start); printf("fnFrequentFunction == %f\n", fnFrequentFunction(x, y, z, a, b, c, 8)); for(i = 0; i < 8; ++i) printf(" c[%d] == %f\n", i, c[i]); printf("\n"); return 0; } Any suggestions are welcome :-)

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  • how to add a function to that program, and call that function from the command line in the function

    - by user336291
    a#include "smallsh.h" /*include file for example*/ /*program buffers and work pointers*/ static char inpbuf[MAXBUF], tokbuf[2*MAXBUF], *ptr = inpbuf, *tok = tokbuf; userin(p) /*print prompt and read a line*/ char *p; { int c, count; /*initialization for later routines*/ ptr = inpbuf; tok = tokbuf; /*display prompt*/ printf("%s ",p); for(count = 0;;) { if((c = getchar()) == EOF) return(EOF); if(count<MAXBUF) inpbuf[count++] = c; if(c == '\n' && count <MAXBUF) { inpbuf[count] = '\0'; return(count); } /*if line too long restart*/ if(c == '\n') { printf("smallsh:input line too long\n"); count = 0; printf("%s",p); } } } gettok(outptr) /*get token and place into tokbuf*/ char **outptr; { int type; *outptr = tok; /*strip white space*/ for(;*ptr == ' ' || *ptr == '\t'; ptr++) ; *tok++ = *ptr; switch(*ptr++) { case '\n': type = EOL; break; case '&': type = AMPERSAND; break; case ';': type = SEMICOLON; break; case '#': type = POUND; break; default: type = ARG; while(inarg(*ptr)) *tok++ = *ptr++; } *tok++ = '\0'; return(type); } static char special[]= {' ', '\t', '&', ':', '\n', '\0'}; inarg(c) /*are we in an ordinary argument*/ char c; { char *wrk; for(wrk = special;*wrk != '\0';wrk++) if(c == *wrk) return(0); return(1); } #include "smallsh.h" procline() /*process input line*/ { char *arg[MAXARG+1]; /*pointer array for runcommand*/ int toktype; /*type of token in command*/ int narg; /*number of arguments so far*/ int type; /*FOREGROUND or BACKGROUND*/ for(narg = 0;;) { /*loop FOREVER*/ /*take action according to token type*/ switch(toktype = gettok(&arg[narg])) { case ARG: if(narg<MAXARG) narg++; break; case EOL: case SEMICOLON: case AMPERSAND: case POUND: type = (toktype == AMPERSAND) ? BACKGROUND : FOREGROUND; if(narg!=0) { arg[narg] = NULL; runcommand(arg, type); } if((toktype == EOL)||(toktype=POUND)) return; narg = 0; break; } } } #include "smallsh.h" /*execute a command with optional wait*/ runcommand(cline,where) char **cline; int where; { int pid, exitstat, ret; if((pid = fork()) <0) { perror("smallsh"); return(-1); } if(pid == 0) { /*child*/ execvp(*cline, cline); perror(*cline); exit(127); } /*code for parent*/ /*if background process print pid and exit*/ if(where == BACKGROUND) { printf("[Process id %d]\n", pid); return(0); } /*wait until process pid exists*/ while( (ret=wait(&exitstat)) != pid && ret != -1) ; return(ret == -1 ? -1 : exitstat); } #include "smallsh.h" char *prompt = "Command>"; /*prompt*/ main() { while(userin(prompt) != EOF) procline(); }

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  • Trying to sentinel loop this program. [java]

    - by roger34
    Okay, I spent all this time making this for class but I have one thing that I can't quite get: I need this to sentinel loop continuously (exiting upon entering x) so that the System.out.println("What type of Employee? Enter 'o' for Office " + "Clerical, 'f' for Factory, or 's' for Saleperson. Enter 'x' to exit." ); line comes back up after they enter the first round of information. Also, I can't leave this up long on the (very) off chance a classmate might see this and steal the code. Full code following: import java.util.Scanner; public class Project1 { public static void main (String args[]){ Scanner inp = new Scanner( System.in ); double totalPay; System.out.println("What type of Employee? Enter 'o' for Office " + "Clerical, 'f' for Factory, or 's' for Saleperson. Enter 'x' to exit." ); String response= inp.nextLine(); while (!response.toLowerCase().equals("o")&&!response.toLowerCase().equals("f") &&!response.toLowerCase().equals("s")&&!response.toLowerCase().equals("x")){ System.out.print("\nInvalid selection,please enter your choice again:\n"); response=inp.nextLine(); } char choice = response.toLowerCase().charAt( 0 ); switch (choice){ case 'o': System.out.println("Enter your hourly rate:"); double officeRate=inp.nextDouble(); System.out.println("Enter the number of hours worked:"); double officeHours=inp.nextDouble(); totalPay = officeCalc(officeRate,officeHours); taxCalc(totalPay); break; case 'f': System.out.println("How many Widgets did you produce during the week?"); double widgets=inp.nextDouble(); totalPay=factoryCalc(widgets); taxCalc(totalPay); break; case 's': System.out.println("What were your total sales for the week?"); double totalSales=inp.nextDouble(); totalPay=salesCalc(totalSales); taxCalc(totalPay); break; } } public static double taxCalc(double totalPay){ double federal=totalPay*.22; double state =totalPay*.055; double netPay = totalPay - federal - state; federal =federal*Math.pow(10,2); federal =Math.round(federal); federal= federal/Math.pow(10,2); state =state*Math.pow(10,2); state =Math.round(state); state= state/Math.pow(10,2); totalPay =totalPay*Math.pow(10,2); totalPay =Math.round(totalPay); totalPay= totalPay/Math.pow(10,2); netPay =netPay*Math.pow(10,2); netPay =Math.round(netPay); netPay= netPay/Math.pow(10,2); System.out.printf("\nTotal Pay \t: %1$.2f.\n", totalPay); System.out.printf("State W/H \t: %1$.2f.\n", state); System.out.printf("Federal W/H : %1$.2f.\n", federal); System.out.printf("Net Pay \t: %1$.2f.\n", netPay); return totalPay; } public static double officeCalc(double officeRate,double officeHours){ double overtime=0; if (officeHours>=40) overtime = officeHours-40; else overtime = 0; if (officeHours >= 40) officeHours = 40; double otRate = officeRate * 1.5; double totalPay= (officeRate * officeHours) + (otRate*overtime); return totalPay; } public static double factoryCalc(double widgets){ double totalPay=widgets*.35 +300; return totalPay; } public static double salesCalc(double totalSales){ double totalPay = totalSales * .05 + 500; return totalPay; } }

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  • Question about unions and heap allocated memory

    - by Dennis Miller
    I was trying to use a union to so I could update the fields in one thread and then read allfields in another thread. In the actual system, I have mutexes to make sure everything is safe. The problem is with fieldB, before I had to change it fieldB was declared like field A and C. However, due to a third party driver, fieldB must be alligned with page boundary. When I changed field B to be allocated with valloc, I run into problems. Questions: 1) Is there a way to statically declare fieldB alligned on page boundary. Basically do the same thing as valloc, but on the stack? 2) Is it possible to do a union when field B, or any field is being allocated on the heap?. Not sure if that is even legal. Here's a simple Test program I was experimenting with. This doesn't work unless you declare fieldB like field A and C, and make the obvious changes in the public methods. #include <iostream> #include <stdlib.h> #include <string.h> #include <stdio.h> class Test { public: Test(void) { // field B must be alligned to page boundary // Is there a way to do this on the stack??? this->field.fieldB = (unsigned char*) valloc(10); }; //I know this is bad, this class is being treated like //a global structure. Its self contained in another class. unsigned char* PointerToFieldA(void) { return &this->field.fieldA[0]; } unsigned char* PointerToFieldB(void) { return this->field.fieldB; } unsigned char* PointerToFieldC(void) { return &this->field.fieldC[0]; } unsigned char* PointerToAllFields(void) { return &this->allFields[0]; } private: // Is this union possible with field B being // allocated on the heap? union { struct { unsigned char fieldA[10]; //This field has to be alligned to page boundary //Is there way to be declared on the stack unsigned char* fieldB; unsigned char fieldC[10]; } field; unsigned char allFields[30]; }; }; int main() { Test test; strncpy((char*) test.PointerToFieldA(), "0123456789", 10); strncpy((char*) test.PointerToFieldB(), "1234567890", 10); strncpy((char*) test.PointerToFieldC(), "2345678901", 10); char dummy[11]; dummy[10] = '\0'; strncpy(dummy, (char*) test.PointerToFieldA(), 10); printf("%s\n", dummy); strncpy(dummy, (char*) test.PointerToFieldB(), 10); printf("%s\n", dummy); strncpy(dummy, (char*) test.PointerToFieldC(), 10); printf("%s\n", dummy); char allFields[31]; allFields[30] = '\0'; strncpy(allFields, (char*) test.PointerToAllFields(), 30); printf("%s\n", allFields); return 0; }

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  • First time using select(), maybe a basic question?

    - by darkletter
    Hello people, i've been working for a few days with this server using select(). What it does, is that, i have two arrays of clients (one is "suppliers", and the other is "consumers"), and the mission of the server is to check whether the suppliers have something to send to the consumers, and in case affirmative, send it. The second part of the server is that, when the consumers have received the suppliers' info, they send a confirmation message to the same suppliers that sent the info. When a client connects, it gets recognized as "undefined", until it sends a message with the word "supplier" or "consumer" (in Spanish, as i'm from there), when the server puts it in the correct clients array. Well, what the server does is not very important here. What's important is that, i'm doing both parts with two different "for" loops, and that's where i'm getting the problems. When the first user connects to the server (be it a supplier or a consumer), the server gets stuck in the first or second loop, instead of just continuing its execution. As it's the first time i'm using select(), i may be missing something. Could you guys give me any sort of help? Thanks a lot in advance. for(;;) { rset=allset; nready=select(maxfd+1,&rset,NULL,NULL,NULL); if (FD_ISSET(sockfd, &rset)){ clilen=sizeof(cliente); if((connfd=accept(sockfd,(struct sockaddr *)&cliente,&clilen))<0) printf("Error"); IP=inet_ntoa(cliente.sin_addr); for(i=0;i<COLA;i++){if(indef[i]<0){indef[i]=connfd;IPind[i]=IP;break;}} FD_SET(connfd,&allset); if(connfd > maxfd) maxfd=connfd; if(i>maxii) maxii=i; if(--nready<=0) continue; }// Fin ISSET(sockfd) for(i=0;i<=maxii;i++){ if((sockfd1=indef[i])<0){ continue;} //! if(FD_ISSET(sockfd1,&rset)){ if((n=read(sockfd1,comp,MAXLINE))==0){close(sockfd1);FD_CLR(sockfd1,&allset);indef[i]=-1;printf("Cliente indefinido desconectado \n");} else{ comp[n]='\0'; if(strcmp(comp,"suministrador")==0){ for(j=0;j<=limite;j++){if(sumi[j]<0){IPsum[j]=IPind[i];sumi[j]=indef[i]; indef[i]=-1;if(j>maxis) {maxis=j;}break; } } } else if(strcmp(comp,"consumidor")==0){ for(o=0;j<=limite;j++){if(consum[o]<0){IPcons[o]=IPind[i];consum[o]=indef[i]; indef[o]=-1;if(o>maxic) {maxic=o;}break; } } } if(--nready <=0)break; } } }//fin bucle for maxii for(i=0;i<=maxis;i++){ if((sockfd2=sumi[i])<0){continue;} if(FD_ISSET(sockfd2,&rset)){ if((n=read(sockfd2,buffer2,MAXLINE))==0){close(sockfd2);FD_CLR(sockfd2,&allset);sumi[i]=-1;printf("Suministrador desconectado \n");} else{ buffer2[n]='\0'; for(j=0;j<=maxic;j++){ if((sockfd3=consum[j])<0){ continue;} else {strcpy(final,IPsum[i]);strcat(final,":");strcat(final,buffer2);write(sockfd3,final,sizeof(final));respuesta[i]=1;} } break; // ? } } }//fin for maxis for(i=miniic;i<=maxic;i++){ if((sockfd4=consum[i])<0){continue;} if(FD_ISSET(sockfd4,&rset)){ if((n=read(sockfd4,buffer3,MAXLINE))==0){close(sockfd4);FD_CLR(sockfd4,&allset);consum[i]=-1;printf("Consumidor desconectado \n");} else{ buffer3[n]='\0'; IP2=strtok(buffer3,":"); obj=strtok(NULL,":"); for(j=0;j<100;j++){ if((strcmp(IPsum[j],IP2)==0) && (respuesta[j]==1)) {write(sumi[j],obj,sizeof(obj)); miniic=i+1; respuesta[j]=0; break; } } } } }

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  • How to find an element in an array in C

    - by gkaykck
    I am trying to find the location of an element in the array. I have tried to use this code i generated for(i=0;i<10;i++) { if (strcmp(temp[0],varptr[i])==0) j=i; } varptr is a pointer which points to array var[11][10] and it is by the definition *varptr[11][10]. I have assigned strings to var[i] and i want to get the "i" number of my element NOT THE ADRESS. Thanks for any comment. EDit: temp is also a pointer which points to the string that i want to check. Also i am using the 2D array for keeping variable names and their address. So yes i want to keep it inside a 2D array. The question is this code is not working at all, it does not assigns i to j, so i wonder where is the problem with this idea? writing a "break" does not change if the code works or not, it just optimizes the code a little. Full Code: #include <stdio.h> #include <string.h> #include <ctype.h> double atof(char*); int main(void) { char in[100], *temp[10],var[11][10],*varptr[11][10]; int i,j, n = 0,fullval=0; double val[11]; strcpy(var[11], "ans"); for(i=0;i<11;i++) { for(j=0;j<10;j++) varptr[i][j]=&var[i][j]; } START: printf("Enter the expression: "); fflush(stdout); for(i=0;i<10;i++) temp[i]=NULL; if (fgets(in, sizeof in, stdin) != NULL) { temp[0] = strtok(in, " "); if (temp[0] != NULL) { for (n = 1; n < 10 && (temp[n] = strtok(NULL," ")) != NULL; n++) ; } if (*temp[0]=="quit") { goto FINISH;} if (isdigit(*temp[0])) { if (*temp[1]=='+') val[0] = atof(temp[0])+atof(temp[2]); else if (*temp[1]=='-') val[0] = atof(temp[0])-atof(temp[2]); else if (*temp[1]=='*') val[0] = atof(temp[0])*atof(temp[2]); else if (*temp[1]=='/') val[0] = atof(temp[0])/atof(temp[2]); printf("%s = %f\n",var[11],val[0]); goto START; } else if (temp[1]==NULL) //asking the value of a variable { for(i=0;i<10;i++) { if (strcmp(temp[0],varptr[i])==0) j=i; } printf("%s = %d\n",var[j],val[j]); goto START; } if (*temp[1]==61) { strcpy(var[fullval], temp[0]); if ((temp[3])!=NULL) { } val[fullval]=atof(temp[2]); printf("%s = %f\n",var[fullval],val[fullval]); fullval++; goto START; } if (*temp[1]!=61) { } } getch(); FINISH: return 0; }

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