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  • Segmentation Fault (C) occur on the server, but works on local machine

    - by menachem-almog
    As stated in the title, the program is working on my local machine (ubuntu 9.10) but not on the server (linux). It's a grid hosting hosting package of godaddy. Please help.. Here is the code: #include <stdio.h> #include <stdlib.h> int main(int argc, char **argv) { long offset; FILE *io; unsigned char found; unsigned long loc; if (argc != 2) { printf("syntax: find 0000000\n"); return 255; } offset = atol(argv[1]) * (sizeof(unsigned char)+sizeof(unsigned long)); io = fopen("index.dat","rb"); fseek(io,offset,SEEK_SET); fread(&found,sizeof(unsigned char),1,io); fread(&loc,sizeof(unsigned long),1,io); if (found == 1) printf("%d\n",loc); else printf("-1\n"); fclose(io); return 0; }

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  • How to prevent buffer overflow in C/C++?

    - by alexpov
    Hello, i am using the following code to redirect stdout to a pipe, then read all the data from the pipe to a buffer. I have 2 problems: first problem: when i send a string (after redirection) bigger then the pipe's BUFF_SIZE, the program stops responding (deadlock or something). second problem: when i try to read from a pipe before something was sent to stdout. I get the same response, the program stops responding - _read command stuck's ... The issue is that i don't know the amount of data that will be sent to the pipe after the redirection. The first problem, i don't know how to handle and i'll be glad for help. The second problem i solved by a simple workaround, right after the redirection i print space character to stdout. but i guess that this solution is not the correct one ... #include <fcntl.h> #include <io.h> #include <iostream> #define READ 0 #define WRITE 1 #define BUFF_SIZE 5 using namespace std; int main() { int stdout_pipe[2]; int saved_stdout; saved_stdout = _dup(_fileno(stdout)); // save stdout if(_pipe(stdout_pipe,BUFF_SIZE, O_TEXT) != 0 ) // make a pipe { exit(1); } fflush( stdout ); if(_dup2(stdout_pipe[1], _fileno(stdout)) != 0 ) //redirect stdout to the pipe { exit(1); } ios::sync_with_stdio(); setvbuf( stdout, NULL, _IONBF, 0 ); //anything sent to stdout goes now to the pipe //printf(" ");//workaround for the second problem printf("123456");//first problem char buffer[BUFF_SIZE] = {0}; int nOutRead = 0; nOutRead = _read(stdout_pipe[READ], buffer, BUFF_SIZE); //second problem buffer[nOutRead] = '\0'; // reconnect stdout if (_dup2(saved_stdout, _fileno(stdout)) != 0 ) { exit(1); } ios::sync_with_stdio(); printf("buffer: %s\n", buffer); } Thanks, Alex

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  • SUA + Visual Studio + pthreads

    - by vasek7
    Hi, I cannot compile this code under SUA: #include <unistd.h> #include <stdio.h> #include <stdlib.h> #include <pthread.h> void * thread_function(void *arg) { printf("thread_function started. Arg was %s\n", (char *)arg); // pause for 3 seconds sleep(3); // exit and return a message to another thread // that may be waiting for us to finish pthread_exit ("thread one all done"); } int main() { int res; pthread_t a_thread; void *thread_result; // create a thread that starts to run ‘thread_function’ pthread_create (&a_thread, NULL, thread_function, (void*)"thread one"); printf("Waiting for thread to finish...\n"); // now wait for new thread to finish // and get any returned message in ‘thread_result’ pthread_join(a_thread, &thread_result); printf("Thread joined, it returned %s\n", (char *)thread_result); exit(0); } I'm running on Windows 7 Ultimate x64 with Visual Studio 2008 and 2010 and I have installed: Windows Subsystem for UNIX Utilities and SDK for Subsystem for UNIX-based Applications in Microsoft Windows 7 and Windows Server 2008 R2 Include directories property of Visual Studio project is set to "C:\Windows\SUA\usr\include" What I have to configure in order to compile and run (and possibly debug) pthreads programs in Visual Studio 2010 (or 2008)?

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  • ubuntu: sem_timedwait not waking (C)

    - by gillez
    I have 3 processes which need to be synchronized. Process one does something then wakes process two and sleeps, which does something then wakes process three and sleeps, which does something and wakes process one and sleeps. The whole loop is timed to run around 25hz (caused by an external sync into process one before it triggers process two in my "real" application). I use sem_post to trigger (wake) each process, and sem_timedwait() to wait for the trigger. This all works successfully for several hours. However at some random time (usually after somewhere between two and four hours), one of the processes starts timing out in sem_timedwait(), even though I am sure the semaphore is being triggered with sem_post(). To prove this I even use sem_getvalue() immediately after the timeout, and the value is 1, so the timedwait should have been triggered. Please see following code: #include <stdio.h> #include <time.h> #include <string.h> #include <errno.h> #include <semaphore.h> sem_t trigger_sem1, trigger_sem2, trigger_sem3; // The main thread process. Called three times with a different num arg - 1, 2 or 3. void *thread(void *arg) { int num = (int) arg; sem_t *wait, *trigger; int val, retval; struct timespec ts; struct timeval tv; switch (num) { case 1: wait = &trigger_sem1; trigger = &trigger_sem2; break; case 2: wait = &trigger_sem2; trigger = &trigger_sem3; break; case 3: wait = &trigger_sem3; trigger = &trigger_sem1; break; } while (1) { // The first thread delays by 40ms to time the whole loop. // This is an external sync in the real app. if (num == 1) usleep(40000); // print sem value before we wait. If this is 1, sem_timedwait() will // return immediately, otherwise it will block until sem_post() is called on this sem. sem_getvalue(wait, &val); printf("sem%d wait sync sem%d. val before %d\n", num, num, val); // get current time and add half a second for timeout. gettimeofday(&tv, NULL); ts.tv_sec = tv.tv_sec; ts.tv_nsec = (tv.tv_usec + 500000); // add half a second if (ts.tv_nsec > 1000000) { ts.tv_sec++; ts.tv_nsec -= 1000000; } ts.tv_nsec *= 1000; /* convert to nanosecs */ retval = sem_timedwait(wait, &ts); if (retval == -1) { // timed out. Print value of sem now. This should be 0, otherwise sem_timedwait // would have woken before timeout (unless the sem_post happened between the // timeout and this call to sem_getvalue). sem_getvalue(wait, &val); printf("!!!!!! sem%d sem_timedwait failed: %s, val now %d\n", num, strerror(errno), val); } else printf("sem%d wakeup.\n", num); // get value of semaphore to trigger. If it's 1, don't post as it has already been // triggered and sem_timedwait on this sem *should* not block. sem_getvalue(trigger, &val); if (val <= 0) { printf("sem%d send sync sem%d. val before %d\n", num, (num == 3 ? 1 : num+1), val); sem_post(trigger); } else printf("!! sem%d not sending sync, val %d\n", num, val); } } int main(int argc, char *argv[]) { pthread_t t1, t2, t3; // create semaphores. val of sem1 is 1 to trigger straight away and start the whole ball rolling. if (sem_init(&trigger_sem1, 0, 1) == -1) perror("Error creating trigger_listman semaphore"); if (sem_init(&trigger_sem2, 0, 0) == -1) perror("Error creating trigger_comms semaphore"); if (sem_init(&trigger_sem3, 0, 0) == -1) perror("Error creating trigger_vws semaphore"); pthread_create(&t1, NULL, thread, (void *) 1); pthread_create(&t2, NULL, thread, (void *) 2); pthread_create(&t3, NULL, thread, (void *) 3); pthread_join(t1, NULL); pthread_join(t2, NULL); pthread_join(t3, NULL); } The following output is printed when the program is running correctly (at the start and for a random but long time after). The value of sem1 is always 1 before thread1 waits as it sleeps for 40ms, by which time sem3 has triggered it, so it wakes straight away. The other two threads wait until the semaphore is received from the previous thread. [...] sem1 wait sync sem1. val before 1 sem1 wakeup. sem1 send sync sem2. val before 0 sem2 wakeup. sem2 send sync sem3. val before 0 sem2 wait sync sem2. val before 0 sem3 wakeup. sem3 send sync sem1. val before 0 sem3 wait sync sem3. val before 0 sem1 wait sync sem1. val before 1 sem1 wakeup. sem1 send sync sem2. val before 0 [...] However, after a few hours, one of the threads begins to timeout. I can see from the output that the semaphore is being triggered, and when I print the value after the timeout is is 1. So sem_timedwait should have woken up well before the timeout. I would never expect the value of the semaphore to be 1 after the timeout, save for the very rare occasion (almost certainly never but it's possible) when the trigger happens after the timeout but before I call sem_getvalue. Also, once it begins to fail, every sem_timedwait() on that semaphore also fails in the same way. See the following output, which I've line-numbered: 01 sem3 wait sync sem3. val before 0 02 sem1 wakeup. 03 sem1 send sync sem2. val before 0 04 sem2 wakeup. 05 sem2 send sync sem3. val before 0 06 sem2 wait sync sem2. val before 0 07 sem1 wait sync sem1. val before 0 08 !!!!!! sem3 sem_timedwait failed: Connection timed out, val now 1 09 sem3 send sync sem1. val before 0 10 sem3 wait sync sem3. val before 1 11 sem3 wakeup. 12 !! sem3 not sending sync, val 1 13 sem3 wait sync sem3. val before 0 14 sem1 wakeup. [...] On line 1, thread 3 (which I have confusingly called sem1 in the printf) waits for sem3 to be triggered. On line 5, sem2 calls sem_post for sem3. However, line 8 shows sem3 timing out, but the value of the semaphore is 1. thread3 then triggers sem1 and waits again (10). However, because the value is already 1, it wakes straight away. It doesn't send sem1 again as this has all happened before control is given to thread1, however it then waits again (val is now 0) and sem1 wakes up. This now repeats for ever, sem3 always timing out and showing that the value is 1. So, my question is why does sem3 timeout, even though the semaphore has been triggered and the value is clearly 1? I would never expect to see line 08 in the output. If it times out (because, say thread 2 has crashed or is taking too long), the value should be 0. And why does it work fine for 3 or 4 hours first before getting into this state? This is using Ubuntu 9.4 with kernel 2.6.28. The same procedure has been working properly on Redhat and Fedora. But I'm now trying to port to ubuntu! Thanks for any advice, Giles

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  • Unknown error in the memory in C

    - by Sergey Gavruk
    I have a 2D dynamic array. I enter a line of 0's after line which has a biggest number: void InsertZero(int **a, int pos){ int i, j; a = (int**)realloc(a, n * sizeof(*a)); a[n-1] = (int*)calloc(n, sizeof(**a)); d = 0; for(i = n-1; i > pos; i--){ for(j = 0; j < n; j++){ a[i][j] = a[i-1][j]; printf("%d ", a[i][j]); } } for(i = 0; i < n; i++){ a[pos][i] = 0; } } If i make a size of array 3, 5, 7, 9, ... it works correctly. But if a number of lines is 2, 4, 6, ... , it is an access violation error, when i try to print my array: void Print(void){ int i, j; for(i = 0; i < (n-d); i++){ for(j = 0; j < n; j++){ printf("%d\t", arr[i][j]); } printf("\n"); } } code: http://codepad.org/JcUis6W4

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  • going reverse in a for loop?

    - by sil3nt
    Hello there, Basically i got this for loop and i want the number inputed (eg. 123) to be printed out in reverse, so "321". so far it works fine and prints out the correct order when the for loop is for(i = 0; i<len ; i++) but i get an error when i try to print it in reverse?. Whats going wrong? #include <stdio.h> #include <string.h> void cnvrter(char *number); int main(){ char number[80]; printf("enter a number "); gets(number); cnvrter(number); return 0; } void cnvrter(char *number){ char tmp[80]; int i = 0,len = 0; int cnvrtd_digit = 0; len = strlen(number); printf("\nsize of input %d\n",len); for(i = len; i>len ; i--){ if ( ( number[i] >= '0' ) && ( number[i]<='9' ) ){ tmp[0] = number[i]; sscanf(tmp,"%d",&cnvrtd_digit); } printf("%d\n",cnvrtd_digit); } }

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  • program that writes the even and odd numbers

    - by user292489
    enter code herei was writting a program that can read a set of numbers file called dog.txt; and also writes to two file separating odd and even. i was able to compile my program however, the output expected is not the same which was supposed to be even numbers in one file called EVEN, odd numbers in file odd. #include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { int i; int even,odd; int num; if (argc != 4) { printf("Usage: executable in_file output_file\n"); exit(0); } FILE *dog = fopen(argv[1], "r"); FILE *feven= fopen(argv[2], "w"); FILE *fodd= fopen (argv[3], "w"); while (fscanf(dog, "%d", &num) != EOF) { if (0==i%2){ i++; printf("even= %d\n", num); } else if(i!=0){ i++; printf("odd= %d\n", num); } } fclose(feven); fclose(fodd); fclose(dog); return 0; } output: even= 1 odd= 2 even= 34 odd= 44 even= 66 odd= 78 even= 94 odd= 21 even= 23 odd= 54 even= 44 odd= 65 even= 78 odd= 68 even= 92

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  • Code Explanation (MPICH)

    - by user243680
    #include "mpi.h" #include <stdio.h> #include <math.h> double f(double a) { return (4.0 / (1.0 + a*a)); } void main(int argc, char *argv[]) { int done = 0, n, myid, numprocs,i; double PI25DT = 3.141592653589793238462643; double mypi, pi, h, sum, x; double startwtime, endwtime; int namelen; char processor_name[MPI_MAX_PROCESSOR_NAME]; MPI_Init(&argc,&argv); MPI_Comm_size(MPI_COMM_WORLD,&numprocs); MPI_Comm_rank(MPI_COMM_WORLD,&myid); MPI_Get_processor_name(processor_name,&namelen); fprintf(stderr,"Process %d on %s\n", myid, processor_name); fflush(stderr); n = 0; while (!done) { if (myid == 0) { printf("Enter the number of intervals: (0 quits) ");fflush(stdout); scanf("%d",&n); startwtime = MPI_Wtime(); } MPI_Bcast(&n, 1, MPI_INT, 0, MPI_COMM_WORLD); if (n == 0) done = 1; else { h = 1.0 / (double) n; sum = 0.0; for (i = myid + 1; i <= n; i += numprocs) { x = h * ((double)i - 0.5); sum += f(x); } mypi = h * sum; MPI_Reduce(&mypi, &pi, 1, MPI_DOUBLE, MPI_SUM, 0, MPI_COMM_WORLD); if (myid == 0) { printf("pi is approximately %.16f, Error is %.16f\n", pi, fabs(pi - PI25DT)); endwtime = MPI_Wtime(); printf("wall clock time = %f\n", endwtime-startwtime); } } } MPI_Finalize(); } Can anyone explain me the above code what it does??I am in lab and my miss has asked me to explain and i dont know what it is.please help

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  • How do I fork a maximum of 5 child processes of the parent at any one time?

    - by bstullkid
    I have the following code, which I'm trying to only allow a maximum of 5 children to run at a time, but I can't figure out how to decrement the child count when a child exits. struct { char *s1; char *s2; } s[] = { {"one", "oneB"}, {"two", "twoB"}, {"three", "thr4eeB"}, {"asdf", "3th43reeB"}, {"asdfasdf", "thr33eeB"}, {"asdfasdfasdf", "thdfdreeB"}, {"af3c3", "thrasdfeeB"}, {"fec33", "threfdeB"}, {NULL, NULL} }; int main(int argc, char *argv[]) { int i, im5, children = 0; int pid = fork(); for (i = 0; s[i].s2; i++) { im5 = 0; switch (pid) { case -1: { printf("Error\n"); exit(255); } case 0: { printf("%s -> %s\n", s[i].s1, s[i].s2); if (i==5) im5 = 1; printf("%d\n", im5); sleep(i); exit(1); } default: { // Here is where I need to sleep the parent until chilren < 5 // so where do i decrement children so that it gets modified in the parent process? while(children > 5) sleep(1); children++; pid = fork(); } } } return 1; }

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  • EVP_PKEY from char buffer in x509 (PKCS7)

    - by sid
    Hi All, I have a DER certificate from which I am retrieving the Public key in unsigned char buffer as following, is it the right way of getting? pStoredPublicKey = X509_get_pubkey(x509); if(pStoredPublicKey == NULL) { printf(": publicKey is NULL\n"); } if(pStoredPublicKey->type == EVP_PKEY_RSA) { RSA *x = pStoredPublicKey->pkey.rsa; bn = x->n; } else if(pStoredPublicKey->type == EVP_PKEY_DSA) { } else if(pStoredPublicKey->type == EVP_PKEY_EC) { } else { printf(" : Unkown publicKey\n"); } //extracts the bytes from public key & convert into unsigned char buffer buf_len = (size_t) BN_num_bytes (bn); key = (unsigned char *)malloc (buf_len); n = BN_bn2bin (bn, (unsigned char *) key); for (i = 0; i < n; i++) { printf("%02x\n", (unsigned char) key[i]); } keyLen = EVP_PKEY_size(pStoredPublicKey); EVP_PKEY_free(pStoredPublicKey); And, With this unsigned char buffer, How do I get back the EVP_PKEY for RSA? OR Can I use following ???, EVP_PKEY *d2i_PublicKey(int type, EVP_PKEY **a, unsigned char **pp, long length); int i2d_PublicKey(EVP_PKEY *a, unsigned char **pp);

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  • What is the point of the logical operators in C?

    - by reubensammut
    I was just wondering if there is an XOR logical operator in C (something like && for AND but for XOR). I know I can split an XOR into ANDs, NOTs and ORs but a simple XOR would be much better. Then it occurred to me that if I use the normal XOR bitwise operator between two conditions, it might just work. And for my tests it did. Consider: int i = 3; int j = 7; int k = 8; Just for the sake of this rather stupid example, if I need k to be either greater than i or greater than j but not both, XOR would be quite handy. if ((k > i) XOR (k > j)) printf("Valid"); else printf("Invalid"); or printf("%s",((k > i) XOR (k > j)) ? "Valid" : "Invalid"); I put the bitwise XOR ^ and it produced "Invalid". Putting the results of the two comparisons in two integers resulted in the 2 integers to contain a 1, hence the XOR produced a false. I've then tried it with the & and | bitwise operators and both gave the expected results. All this makes sense knowing that true conditions have a non zero value, whilst false conditions have zero values. I was wondering, is there a reason to use the logical && and || when the bitwise operators &, | and ^ work just the same? Thanks Reuben

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  • GDB not breaking on breakpoints set on object creation in C++

    - by Drew
    Hi all, I've got a c++ app, with the following main.cpp: 1: #include <stdio.h> 2: #include "HeatMap.h" 3: #include <iostream> 4: 5: int main (int argc, char * const argv[]) 6: { 7: HeatMap heatMap(); 8: printf("message"); 9: return 0; 10: } Everything compiles without errors, I'm using gdb (GNU gdb 6.3.50-20050815 (Apple version gdb-1346) (Fri Sep 18 20:40:51 UTC 2009)), and compiled the app with gcc (gcc version 4.2.1 (Apple Inc. build 5646) (dot 1)) with the commands "-c -g". When I add breakpoints to lines 7, 8, and 9, and run gdb, I get the following... (gdb) break main.cpp:7 Breakpoint 1 at 0x10000177f: file src/main.cpp, line 8. (gdb) break main.cpp:8 Note: breakpoint 1 also set at pc 0x10000177f. Breakpoint 2 at 0x10000177f: file src/main.cpp, line 8. (gdb) break main.cpp:9 Breakpoint 3 at 0x100001790: file src/main.cpp, line 9. (gdb) run Starting program: /DevProjects/DataManager/build/DataManager Reading symbols for shared libraries ++. done Breakpoint 1, main (argc=1, argv=0x7fff5fbff960) at src/main.cpp:8 8 printf("message"); (gdb) So, why of why, does anyone know, why my app does not break on the breakpoints for the object creation, but does break on the printf line? Drew J. Sonne.

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  • The dealloc method is not called in the present modal view contrller.

    - by Madan Mohan
    It is in My view controller -(void)doctorsListAction { if(isFirst == YES) { [self getDoctorsListController]; [[self navigationController] presentModalViewController:doctorListViewNavigationController animated:YES]; [doctorListViewController release]; } } -(void)getDoctorsListController { //DoctorListViewController *doctorListViewController=[[[DoctorListViewController alloc]initWithNibName:nil bundle:nil]autorelease]; doctorListViewController=[[DoctorListViewController alloc]init]; doctorListViewNavigationController=[[UINavigationController alloc]initWithRootViewController:doctorListViewController]; doctorListViewController.doctorList=doctorList; doctorListViewNavigationController.navigationBar.barStyle= UIBarStyleBlackOpaque; [doctorListViewController release]; } It is in DoctorListViewContrller -(void)closeAction { printf("\n hai i am in close action*******************************"); //[doctorList release]; //[myTableView release]; //myTableView=nil; printf("\n myTableView retainCount :%d",[myTableView retainCount]); [[self navigationController] dismissModalViewControllerAnimated:YES]; } //this method is not called I don't know why if it not called i will get memory issues - (void)dealloc { printf("\n hai i am in dealloc of Doctor list view contrller"); [doctorList release]; [myTableView release]; myTableView=nil; [super dealloc]; }

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  • Malloc inside another function (ANSI C)

    - by Casper
    Hi I'll go straight to it. I'm working on an assignment, where I suddenly ran into trouble. I have to allocate a struct from within another function, obviously using pointers. I've been staring at this problem for hours and tried in a million different ways to solve it. This is some sample code (very simplified): ... some_struct s; printf("Before: %d\n", &s"); allocate(&s); printf("After: %d\n", &s"); ... /* The allocation function */ int allocate(some_struct *arg) { arg = malloc(sizeof(some_struct)); printf("In function: %d\n", &arg"); return 0; } This does give me the same address before and after the allocate-call: Before: -1079752900 In function: -1079752928 After: -1079752900 I know it's probably because it makes a copy in the function, but I don't know how to actually work on the pointer I gave as argument. I tried defining some_struct *s instead of some_struct s, but no luck. I tried with: int allocate(some_struct **arg) which works just fine (the allocate-function needs to be changed as well), BUT according to the assignment I may NOT change the declaration, and it HAS to be *arg.. And it would be most correct if I just have to declare some_struct s.. Not some_struct *s. I hope I make sense and some of you out there can help me :P Thanks in advice

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  • How to Implement Grep into CGI script Please?

    - by Joey jie
    Hi all! I am having difficulty figuring out how to implement grep into my CGI script. Basically I will receive a value of eg. 1500 from a HTML page. The CGI script then runs and compares 1500 to a text file. When it finds 1500 it prints the entire line and displays it on the webpage. I would like some tips and pointers on how to do this please. I understand that this involves grep but I don't really know how to put it in. #include <stdio.h> #include <stdlib.h> int main(void) { char *data; long m,n; printf("%s%c%c\n", "Content-Type:text/html;charset=iso-8859-1",13,10); printf("<TITLE>Webpage of Results</TITLE>\n"); printf("<H1>Temperatures</H1>\n"); data = getenv("QUERY_STRING"); The HTML passes the variable time=1500. I understand (correct me if I am wrong) that QUERY_STRING will contain 1500?

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  • Unit testing opaque structure based C API

    - by Nicolas Goy
    I have a library I wrote with API based on opaque structures. Using opaque structures has a lot of benefits and I am very happy with it. Now that my API are stable in term of specifications, I'd like to write a complete battery of unit test to ensure a solid base before releasing it. My concern is simple, how do you unit test API based on opaque structures where the main goal is to hide the internal logic? For example, let's take a very simple object, an array with a very simple test: WSArray a = WSArrayCreate(); int foo = 5; WSArrayAppendValue(a, &foo); int *bar = WSArrayGetValueAtIndex(a, 0); if(&foo != bar) printf("Eroneous value returned\n"); else printf("Good value returned\n"); WSRelease(a); Of course, this tests some facts, like the array actually acts as wanted with 1 value, but when I write unit tests, at least in C, I usualy compare the memory footprint of my datastructures with a known state. In my example, I don't know if some internal state of the array is broken. How would you handle that? I'd really like to avoid adding codes in the implementation files only for unit testings, I really emphasis loose coupling of modules, and injecting unit tests into the implementation would seem rather invasive to me. My first thought was to include the implementation file into my unit test, linking my unit test statically to my library. For example: #include <WS/WS.h> #include <WS/Collection/Array.c> static void TestArray(void) { WSArray a = WSArrayCreate(); /* Structure members are available because we included Array.c */ printf("%d\n", a->count); } Is that a good idea? Of course, the unit tests won't benefit from encapsulation, but they are here to ensure it's actually working.

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  • Pointer problem in C for char*

    - by egebilmuh
    Hi guys, i use pointer for holding name and research lab property. But when i print the existing Vertex ,when i print the vertex, i cant see so -called attributes properly. For example though real value of name is "lancelot" , i see it as wrong such as "asdasdasdasd" struct vertex { int value; char*name; char* researchLab; struct vertex *next; struct edge *list; }; void GRAPHinsertV(Graph G, int value,char*name,char*researchLab) { //create new Vertex. Vertex newV = malloc(sizeof newV); // set value of new variable to which belongs the person. newV->value = value; newV->name=name; newV->researchLab=researchLab; newV->next = G->head; newV->list = NULL; G->head = newV; G->V++; } /*** The method creates new person. **/ void createNewPerson(Graph G) { int id; char name[30]; char researchLab[30]; // get requeired variables. printf("Enter id of the person to be added.\n"); scanf("%d",&id); printf("Enter name of the person to be added.\n"); scanf("%s",name); printf("Enter researc lab of the person to be added\n"); scanf("%s",researchLab); // insert the people to the social network. GRAPHinsertV(G,id,name,researchLab); } void ListAllPeople(Graph G) { Vertex tmp; Edge list; for(tmp = G->head;tmp!=NULL;tmp=tmp->next) { fprintf(stdout,"V:%d\t%s\t%s\n",tmp->value,tmp->name,tmp->researchLab); } system("pause"); }

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  • getchar does not stop when using scanf

    - by Oz123
    I am have a difficulty understanding getchar(). In the following program getchar works as expected: #include <stdio.h> int main() { printf("Type Enter to continue..."); getchar(); return 0; } However, in the following program, getchar does not create a delay and the program ends: #include <stdio.h> int main() { char command[100]; scanf("%s", command ); printf("Type Enter to continue..."); getchar(); return 0; } I have the following weired workaround, which works, but I understand why: #include <stdio.h> int main() { char command[100]; int i; scanf("%s", command ); printf("Type Enter to continue..."); while ( getchar() != '\n') { i=0; } getchar(); return 0; } So my questions are: 1. What is scanf doing? Why does scanf do this ? 2. Why is my work around working? 3. What is a good way to emulate the following Python code: raw_input("Type Enter to continue")

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  • Why is this exception thrown in the visual studio C compiler?

    - by Shane Larson
    Hello. I am trying to get more adept and my C programming and I was attempting to test out displaying a character from the input stream while inside of the loop that is getting the character. I am using the getchar() method. I am getting an exception thrown at the time that the printf statement in my code is present. (If I comment out the printf line in this function, the exception is not thrown). Exception: Unhandled exception at 0x611c91ad (msvcr90d.dll) in firstOS.exe: 0xC0000005: Access violation reading location 0x00002573. Here is the code... Any thoughts? Thank you. PS. I am using the stdio.h library. /*getCommandPromptNew - obtains a string command prompt.*/ void getCommandPromptNew(char s[], int lim){ int i, c; for(i=0; i < lim-1 && (c=getchar())!=EOF && c!='\n'; ++i){ s[i] = c; printf('%s', c); } }

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  • c multithreading

    - by coubeatczech
    hi, there's a weird behaviour in my threads: void * foo(void * nic){ printf("foo"); } void * threadF(void * ukazatel){ printf("1\n"); pthread_t threadT; pthread_attr_t attr; pthread_attr_init (&attr); pthread_attr_setdetachstate(&attr, PTHREAD_CREATE_JOINABLE); pthread_create(&threadT,NULL,&foo,(void*)NULL); printf("2\n"); while (!feof(stdin)){ int id, in, out; fscanf(stdin,"%d:%d:%d",&id,&in,&out); } } int main(){ pthread_attr_t attr; pthread_attr_init (&attr); pthread_attr_setdetachstate(&attr, PTHREAD_CREATE_JOINABLE); pthread_t threadT; pthread_create(&vlaknoVstupu,&attr,&threadF,(void*)&data); pthread_join(threadT,NULL); pthread_attr_destroy (&attr); } // I skipped irelevant parts of code... the thing is, that sometimes, the output is 12foo, but usually just 12. Then the function waits for input. I would expect it to be always 12foo. Do anybody know why are my expectations wrong?

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  • C Run-Time library part 2

    - by b-gen-jack-o-neill
    Hi, I was suggested when I have some further questions on my older ones, to create newer Question and reffer to old one. So, this is the original question: What is the C runtime library? OK, from your answers, I now get thet statically linked libraries are Microsoft implementation of C standart functions. Now: If I get it right, the scheme would be as follow: I want to use printf(), so I must include which just tels compiler there us functio printf() with these parameters. Now, when I compile code, becouse printf() is defined in C Standart Library, and becouse Microsoft decided to name it C Run Time library, it gets automatically statically linked from libcmt.lib (if libcmt.lib is set in compiler) at compile time. I ask, becouse on wikipedia, in article about runtime library there is that runtime library is linked in runtime, but .lib files are linked at compile time, am I right? Now, what confuses me. There is .dll version of C standart library. But I thought that to link .dll file, you must actually call winapi program to load that library. So, how can be these functions dynamically linked, if there is no static library to provide code to tell Windows to load desired functions from dll? And really last question on this subject - are C Standart library functions also calls to winapi even they are not .dll files like more advanced WinAPI functions? I mean, in the end to access framebuffer and print something you must tell Windows to do it, since OS cannot let you directly manipulate HW. I think of it like the OS must be written to support all C standart library functions same way across similiar versions, since they are statically linked, and can differently support more complex WinAPI calls becouse new version of OS can have adjustements in the .dll file.

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  • How to make gcc on SUN calculate floating points the same way as in Linux

    - by Marina
    I have a project where I have to perform some mathematics calculations with double variables. The problem is that I get different results on SUN Solaris 9 and Linux. There are a lot of ways (explained here and other forums) how to make Linux work as Sun, but not the other way around. I cannot touch the Linux code, so it is only SUN I can change. Is there any way to make SUN to behave as Linux? The code I run(compile with gcc on both systems): int hash_func(char *long_id) { double product, lnum, gold; while (*long_id) lnum = lnum * 10.0 + (*long_id++ - '0'); printf("lnum => %20.20f\n", lnum); lnum = lnum * 10.0E-8; printf("lnum => %20.20f\n", lnum); gold = 0.6125423371582974; product = lnum * gold; printf("product => %20.20f\n", product); ... } if the input is 339886769243483 the output in Linux: lnum => 339886769243**483**.00000000000000000000 lnum => 33988676.9243**4829473495483398** product => 20819503.600158**59827399253845** When on SUN: lnum => 339886769243483.00000000000000000000 lnum => 33988676.92434830218553543091 product = 20819503.600158**60199928283691** Note: The result is not always different, moreover most of the times it is the same. Just 10 15-digit numbers out of 60000 have this problem. Please help!!!

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  • Should i enforce realloc check if the new block size is smaller than the initial ?

    - by nomemory
    Can realloc fail in this case ? int *a = NULL; a = calloc(100, sizeof(*a)); printf("1.ptr: %d \n", a); a = realloc(a, 50 * sizeof(*a)); printf("2.ptr: %d \n", a); if(a == NULL){ printf("Is it possible?"); } return (0); } The output in my case is: 1.ptr: 4072560 2.ptr: 4072560 So 'a' points to the same adress. So should i enforce realloc check ? Later edit: Using MinGW compiler under Windows XP. Is the behaviour similar with gcc on Linux ? Later edit 2: Is it OK to check this way ? int *a = NULL, *b = NULL; a = calloc(100, sizeof(*a)); b = realloc(a, 50 * sizeof(*a)); if(b == NULL){ return a; } a = b; return a;

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  • Is it possible to declare multiple static variable with same name in a single C file?

    - by Mohammed Khalid Kherani
    Hi Experts, Is it possible to declare multiple static variables of same name in a single C file with different scopes? I wrote a simple programme to check this and in gcc it got compiled and worked fine. code: static int sVar = 44; void myPrint2() { printf("sVar = %d\n", sVar++); } void myPrint() { static int sVar =88; printf("sVar = %d\n", sVar++); } int main(void) { static int sVar = 55; int i = 0; for (i = 0; i < 5; i++) myPrint(); printf("sVar = %d\n", sVar); myPrint2(); return(0); } Now my question is since all "static" variable will reside in same section (.data) then how we can have multiple variable with same name in one section? I used objdump to check the different section and found that all Static variables (sVar) were in .data section but with different names 0804960c l O .data 00000004 sVar 08049610 l O .data 00000004 sVar.1785 08049614 l O .data 00000004 sVar.1792 Why compiler is changing the name of variables (since C doesnt support name mangling)? Thanks in advance.

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  • Compiling Objective-C project on Linux (Ubuntu)

    - by Alex
    How to make an Objective-C project work on Ubuntu? My files are: Fraction.h #import <Foundation/NSObject.h> @interface Fraction: NSObject { int numerator; int denominator; } -(void) print; -(void) setNumerator: (int) n; -(void) setDenominator: (int) d; -(int) numerator; -(int) denominator; @end Fraction.m #import "Fraction.h" #import <stdio.h> @implementation Fraction -(void) print { printf( "%i/%i", numerator, denominator ); } -(void) setNumerator: (int) n { numerator = n; } -(void) setDenominator: (int) d { denominator = d; } -(int) denominator { return denominator; } -(int) numerator { return numerator; } @end main.m #import <stdio.h> #import "Fraction.h" int main( int argc, const char *argv[] ) { // create a new instance Fraction *frac = [[Fraction alloc] init]; // set the values [frac setNumerator: 1]; [frac setDenominator: 3]; // print it printf( "The fraction is: " ); [frac print]; printf( "\n" ); // free memory [frac release]; return 0; } I've tried two approaches to compile it: Pure gcc: $ sudo apt-get install gobjc gnustep gnustep-devel $ gcc `gnustep-config --objc-flags` -o main main.m -lobjc -lgnustep-base /tmp/ccIQKhfH.o:(.data.rel+0x0): undefined reference to `__objc_class_name_Fraction' I created a GNUmakefile Makefile: include ${GNUSTEP_MAKEFILES}/common.make TOOL_NAME = main main_OBJC_FILES = main.m include ${GNUSTEP_MAKEFILES}/tool.make ... and ran: $ source /usr/share/GNUstep/Makefiles/GNUstep.sh $ make Making all for tool main... Linking tool main ... ./obj/main.o:(.data.rel+0x0): undefined reference to `__objc_class_name_Fraction' So in both cases compiler gets stuck at undefined reference to `__objc_class_name_Fraction' Do you have and idea how to resolve this issue?

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