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• MySQL Query, limit output display according/only to associated ID!

  - by Jess

  So here's my situation. I have a books table and authors table. An author can have many books... In my authors page view, the user (logged in) can click an author in a tabled row and be directed to a page displaying the author's books (collected like this URI format: viewauthorbooks.php?author_id=23), very straight forward... However, in my query, I need to display the books for the author only, and not all books stored in the books table (as i currently have!) As I am a complete novice, I used the most simple query of: SELECT * FROM tasks_tb :)....this returns the books for me, but returns every single value (book) in the database, and not ones associated with the selected author. And when I click a different author the same books are displayed for them...I think everyone gets what I'm trying to achieve, I just don't know how to perform the query. I'm guessing that I need to start using more advanced query clauses like INNER JOIN etc. Anyone care to help me out :)

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• Searching a keyword in a long string in mysql?

  - by user187580

  Hello keyword = house SELECT * FROM products WHERE description LIKE '%house%' This query also returns records having keyword, for example, courthouse, but I want to look for house only. How do I search anywhere in the description for "house" only? Thanks. UPDATE just for more clarification .. actually house, can be at - the start of the description .. "House for sale..", - can be quoted -- "house", 'house' - can have exclamation .. house!!!, house! - others - house? etc .. this is why I used %house%

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• MySQL searching using many 'like' operators: is there a better way?

  - by DrAgonmoray

  I have a page that gets all rows from a table in a database, then displays the rows in an HTML table. That works great, but now I want to implement a 'search' feature. There is a searchbox, and search-terms are separated by a space. I am going to make it search three fields for the search terms, 'make' 'model' and 'type.' These three fields are VARCHAR(30). Currently if I wanted to search using 3 terms (say 'cool' 'abc' and '123') my query would look something like this. SELECT * FROM table WHERE make LIKE '%cool%' OR make LIKE '%abc%' OR make LIKE '%123%' OR model LIKE '%cool%' OR model LIKE '%abc%' OR model LIKE '%123%' OR type LIKE '%cool%' OR type LIKE '%abc%' OR type LIKE '%123%' That looks really bad, and it will get even worse if there are more search terms or more fields to search. My question to you: is there a better way to search? If so, what?

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• MySQL Query, how to group and count in one row ?

  - by Akarun

  Hi All, To simplify, I have tree tables: products, products-vs-orders, orders products fields : 'ProductID', 'Name', 'isGratis', ... products-vs-orders fields : 'ProductID', 'OrderID' orders fields : 'OrderID', 'Title', ... Actually, I have a query like this: SELECT orders.OrderID, orders.Title, COUNT(`products`.`isGratis`) AS "Quantity", `products`.`isGratis` FROM `orders`, `products-vs-orders`, `products` WHERE `orders`.`OrderID` = `products-vs-orders`.`OrderID` AND `products-vs-orders`.`ProductID` = `products`.`ProductID` GROUP BY `products`.`PackID`, `products`.`isGratis` This query works and return this surch of result: OrderID, Title, Quantity, isGratis 1 My Order 20 0 1 My Order 3 1 2 An other 8 0 2 An other 1 1 How can I retrieve the count of products 'gratis' and 'paid' in to separate cols ? OrderID, Title, Qt Paid, Qt Gratis 1 My Order 20 3 2 An other 8 1 Thanks for your help

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• Having trouble comparing a range of dates entered in a form with records in a mySQL database

  - by Andrew Fox

  I have a table called schedule and a column called Date where the column type is date. In that column I have a range of dates, which is currently from 2012-11-01 to 2012-11-30. I have a small form where the user can enter a range of dates (input names from and to) and I want to be able to compare the range of dates with the dates currently in the database. This is what I have: //////////////////////////////////////////////////////// //////First set the date range that we want to use////// //////////////////////////////////////////////////////// if(isset($_POST['from']) && ($_POST['from'] != NULL)) { $startDate = $_POST['from']; } else { //Default date is Today $startDate = date("Y-m-d"); } if(isset($_POST['to']) && ($_POST['to'] != NULL)) { $endDate = $_POST['to']; } else { //Default day is one month from today $endDate = date("Y-m-d", strtotime("+1 month")); } ////////////////////////////////////////////////////////////////////////////////////// //////Next calculate the total amount of days selected above to use as a limiter////// ////////////////////////////////////////////////////////////////////////////////////// $dayStart = strtotime($startDate); $dayEnd = strtotime($endDate); $total_days = abs($dayEnd - $dayStart) / 86400 +1; echo "Start Date: " . $startDate . "<br>End Date: " . $endDate . "<br>"; echo "Day Start: " . $dayStart . "<br>Day End: " . $dayEnd . "<br>"; echo "Total Days: " . $total_days . "<br>"; //////////////////////////////////////////////////////////////////////////////////// //////Then we're going to see if the dates selected are in the schedule table////// //////////////////////////////////////////////////////////////////////////////////// //Select all of the dates currently in the schedule table between the range selected. $sql = ("SELECT Date FROM schedule WHERE Date BETWEEN '$startDate' AND '$endDate' LIMIT $total_days"); //Run a check on the query to make sure it worked. If it failed then print the error. if(!$result_date_query = $mysqli->query($sql)) { die('There was an error getting the dates from the schedule table [' . $mysqli->error . ']'); } //Set the dates to an array for future use. // $current_dates = $result_date_query->fetch_assoc(); //Loop through the results while a result is being returned. while($row = $result_date_query->fetch_assoc()) { echo "Row: " . $row['Date'] . "<br>"; echo "Start day: " . date('Y-m-d', $dayStart) . "<br>"; //Set this loop to add 1 day to the Start Date until it reaches the End Date for($i = $dayStart; $i <= $dayEnd; $i = strtotime('+1 day', $i)) { $date = date('Y-m-d',$i); echo "Loop Start day: " . date('Y-m-d', $dayStart) . "<br>"; //Run a check to see if any of the dates selected are in the schedule table. if($row['Date'] != $date) { echo "Current Date: " . $row['Date'] . "<br>"; echo "Date: " . $date . "<br>"; echo "It appears as though you've selected some dates that are not in the schedule database.<br>Please correct the issue and try again."; return; } } } //Free the result so something else can use it. $result_date_query->free(); As you can see I've added in some echo statements so I can see what is being produced. From what I can see it looks like my $row['Date'] is not incrementing and staying at the same date. I originally had it set to a variable (currently commented out) but I thought that could be causing problems. I have created the table with dates ranging from 2012-11-01 to 2012-11-15 for testing and entered all of this php code onto phpfiddle.org but I can't get the username provided to connect. Here is the link: PHP Fiddle I'll be reading through the documentation to try and figure out the user connection problem in the meantime, I would really appreciate any direction or advice you can give me.

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• MySQL ORDER BY returns things in (apparently) random order !?

  - by Luke H

  The following query: SELECT DISTINCT ClassName FROM SiteTree ORDER BY ClassName is returning things in no apparent order! I get the same result whether I quote column/table names, or use DISTINCT or not, or add ASC or DESC. I assumed the indexes might be broken, or something like this, so tried dropping and recreating. Also tried REPAIR TABLE and CHECK TABLE. The table collation is set to latin1_swedish_ci. All the textual columns are set to use UTF-8 and collation is set to utf8_general_ci What could be causing this?

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• Drawing up a session value within SQL query? PHP and MySQL

  - by Derek

  Hi, on one of my web pages I want my manager user to view all activities assigned to them (personally). In order to do this, I need something like this: $sql = "SELECT * FROM activities WHERE manager = $_SESSION['SESS_FULLNAME']"; Now obviously this syntax is all wrong, but because I am new to this stuff, is there a way I can call up the full name from the user's session within a query? This is so that when I call up the database values to be displayed within the web page, only the activities for the manager who is logged in is displayed. For example, the activities table has a manager column of a full name entry. Any help is much appreciated. Thanks.

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• Can anyone help me with a complex sum, 3 table join mysql query?

  - by Scarface

  Hey guys I have a query and it works fine, but I want to add another table to the mix. The invite table I want to add has two fields: username and user_invite. Much like this site, I am using a point system to encourage diligent users. The current query which is displayed below adds the up votes and down votes based on the user in question: $creator. I want to count the number of entries for that same user from the invite table, and add 50 for each row it finds to the current output/sum of my query. Is this possible with one query, or do I need two? "SELECT *, SUM(IF(points_id = \"1\", 1,0))-SUM(IF(points_id = \"2\", 1,0)) AS 'total' FROM points LEFT JOIN post ON post.post_id=points.points_id WHERE post.creator='$creator'"

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• MySQL - accessing a table sum and compare to another table?

  - by assignment_operator

  This is for a homework assignment. I just plain don't understand how to do it. The instructions for this particular question is: List the branch name for all branches that have at least one book that has at least 4 copies on hand. Where the tables in question are: Branch: BranchName | BranchId Henry Downtown | 1 16 Riverview | 2 Henry On The Hill | 3 Inventory: BookId | BranchId | OnHand 1 | 1 | 2 2 | 3 | 4 3 | 1 | 8 4 | 3 | 1 5 | 1 | 2 6 | 2 | 3 From what I understand, I can get the number of OnHand per branch name with: SELECT BranchName, SUM(OnHand) FROM Branch B, Inventory I WHERE B.BranchId = I.BranchId GROUP BY BranchName; but I don't get how I'd do the comparison between the sum of OnHand per branch and 4. Any help would be appreciated, guys!

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• mysql phpmyadmin, how to save date of birth that was attained through a form with the input type "se

  - by newbie-25

  Hello, I have a form which asks the user his or her date of birth. Its a drop down box since I use the select input type. The first drop down has Months, second has Days, the third has the Years. So the format should be Month(October), Day(25), Year(1990). In other words the months spell out the actual month and not simply the number representation of the month. However, I would like to save the Day and Year in their respective formats. How can I do this in phpMyAdmin? Should I use the DATE type? what should the value be? I just need to know how to correlate all of this in phpmyadmin, so I can save it properly. Thank you.

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• "Remember" last three MySql queries; Cookie, passed variable or other method?

  - by Camran

  I have a classified website, with pretty sophisticated searching, and I am about to implement a function where the last three queries is displayed for the user, so that the user can go back easier through the queries. This because for each query the user has to provide a lot of input. I have four questions for you: I wonder, how can I save the actual query (SELECT * FROM etc etc)...? Do I need to add some form of encryption to be on the safe side? How will this affect performance? (I don't like the fact that cookies slow websites down) Anything else to think about? If you need more input, let me know... Btw, the website is PHP based. Thanks

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• Recursive MySQL function call eats up too much memory and dies.

  - by kylex

  I have the following recursive function which works... up until a point. Then the script asks for more memory once the queries exceed about 100, and when I add more memory, the script typically just dies (I end up with a white screen on my browser). public function returnPArray($parent=0,$depth=0,$orderBy = 'showOrder ASC'){ $query = mysql_query("SELECT *, UNIX_TIMESTAMP(lastDate) AS whenTime FROM these_pages WHERE parent = '".$parent."' AND deleted = 'N' ORDER BY ".$orderBy.""); $rows = mysql_num_rows($query); while($row = mysql_fetch_assoc($query)){ // This uses my class and places the content in an array. MyClass::$_navArray[] = array( 'id' => $row['id'], 'parent' => $row['parent'] ); MyClass::returnPArray($row['id'],($depth+1)); } $i++; } Can anyone help me make this query less resource intensive?

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• MySQL query to find the most popular value in a column joined by another value in a second table

  - by Budove

  I have two tables: users: user_id, user_zip settings: user_id, pref_ex_loc I need to find the single most popular 'pref_ex_loc' from the settings table based on a particular user_zip, which will be specified as the variable $userzip. Here is the query that I have now and obviously it doesn't work. $popularexloc = "SELECT pref_ex_loc, user_id COUNT(pref_ex_loc) AS countloc FROM settings FULL OUTER JOIN users ON settings.user_id = users.user_id WHERE users.user_zip='$userzip' GROUP BY settings.pref_ex_loc ORDER BY countloc LIMIT 1"; $popexloc = mysql_query($popularexloc) or die('SQL Error :: '.mysql_error()); $exlocrow = mysql_fetch_array($popexloc); $mostpopexloc=$exlocrow[0]; echo '<option value="'.$mostpopexloc.'">'.$mostpopexloc.'</option>'; What am I doing wrong here? I'm not getting any kind of error from this either.

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• Juju stuck in "pending" state when using LXC

  - by Andre

  So I'm trying to get started with Juju, and tried to do this locally using LXC. I followed the instructions here: How do I configure juju for local usage? Unfortunately this doesn't seem to work for me. status shows the following: $ juju status machines: 0: agent-state: running dns-name: localhost instance-id: local instance-state: running services: mysql: charm: cs:precise/mysql-1 relations: db: - wordpress units: mysql/0: agent-state: pending machine: 0 public-address: null wordpress: charm: cs:precise/wordpress-0 exposed: true relations: db: - mysql units: wordpress/0: agent-state: pending machine: 0 open-ports: [] public-address: null 2012-05-10 14:09:38,155 INFO 'status' command finished successfully As you can see the agent-state is 'pending' and there is no public address where I'm able to access the newly created site. Am I missing something here? UPDATE: Tried destroying the environment an doing everything again (multiple times). This is the output for debug-log: ~$ juju debug-log 2012-05-11 08:50:23,790 INFO Enabling distributed debug log. 2012-05-11 08:50:23,806 INFO Tailing logs - Ctrl-C to stop. 2012-05-11 08:50:42,338 Machine:0: juju.agents.machine DEBUG: Units changed old:set([]) new:set(['mysql/0']) 2012-05-11 08:50:42,339 Machine:0: juju.agents.machine DEBUG: Starting service unit: mysql/0 ... 2012-05-11 08:50:42,459 Machine:0: unit.deploy DEBUG: Downloading charm cs:precise/mysql-1 to /home/andre/.juju/data/andre-local/charms 2012-05-11 08:50:42,620 Machine:0: unit.deploy DEBUG: Using <juju.machine.unit.UnitContainerDeployment object at 0x9c54b6c> for mysql/0 in /home/andre/.juju/data/andre-local 2012-05-11 08:50:42,648 Machine:0: unit.deploy DEBUG: Starting service unit mysql/0... 2012-05-11 08:50:42,649 Machine:0: unit.deploy DEBUG: Creating master container... 2012-05-11 08:54:33,992 Machine:0: unit.deploy DEBUG: Created master container andre-local-0-template 2012-05-11 08:54:33,993 Machine:0: unit.deploy INFO: Creating container mysql-0... 2012-05-11 08:56:18,760 Machine:0: unit.deploy INFO: Container created for mysql/0 2012-05-11 08:56:19,466 Machine:0: unit.deploy DEBUG: Charm extracted into container 2012-05-11 08:56:19,569 Machine:0: unit.deploy DEBUG: Starting container... 2012-05-11 08:56:22,707 Machine:0: unit.deploy INFO: Started container for mysql/0 2012-05-11 08:56:22,707 Machine:0: unit.deploy INFO: Started service unit mysql/0 2012-05-11 08:56:23,012 Machine:0: juju.agents.machine DEBUG: Units changed old:set(['mysql/0']) new:set(['wordpress/0', 'mysql/0']) 2012-05-11 08:56:23,039 Machine:0: juju.agents.machine DEBUG: Starting service unit: wordpress/0 ... 2012-05-11 08:56:23,154 Machine:0: unit.deploy DEBUG: Downloading charm cs:precise/wordpress-0 to /home/andre/.juju/data/andre-local/charms 2012-05-11 08:56:23,396 Machine:0: unit.deploy DEBUG: Using <juju.machine.unit.UnitContainerDeployment object at 0x9c519cc> for wordpress/0 in /home/andre/.juju/data/andre-local 2012-05-11 08:56:23,620 Machine:0: unit.deploy DEBUG: Starting service unit wordpress/0... 2012-05-11 08:56:23,621 Machine:0: unit.deploy INFO: Creating container wordpress-0... 2012-05-11 08:58:24,739 Machine:0: unit.deploy INFO: Container created for wordpress/0 2012-05-11 08:58:25,163 Machine:0: unit.deploy DEBUG: Charm extracted into container 2012-05-11 08:58:25,397 Machine:0: unit.deploy DEBUG: Starting container... 2012-05-11 08:58:27,982 Machine:0: unit.deploy INFO: Started container for wordpress/0 2012-05-11 08:58:27,983 Machine:0: unit.deploy INFO: Started service unit wordpress/0 This is the result for the status command (with verbose flag): ~$ juju -v status 2012-05-11 08:51:53,464 DEBUG Initializing juju status runtime 2012-05-11 08:51:53,625:4030(0xb7345b00):ZOO_INFO@log_env@658: Client environment:zookeeper.version=zookeeper C client 3.3.5 2012-05-11 08:51:53,625:4030(0xb7345b00):ZOO_INFO@log_env@662: Client environment:host.name=andre-ufo 2012-05-11 08:51:53,625:4030(0xb7345b00):ZOO_INFO@log_env@669: Client environment:os.name=Linux 2012-05-11 08:51:53,625:4030(0xb7345b00):ZOO_INFO@log_env@670: Client environment:os.arch=3.2.0-24-generic-pae 2012-05-11 08:51:53,625:4030(0xb7345b00):ZOO_INFO@log_env@671: Client environment:os.version=#37-Ubuntu SMP Wed Apr 25 10:47:59 UTC 2012 2012-05-11 08:51:53,626:4030(0xb7345b00):ZOO_INFO@log_env@679: Client environment:user.name=andre 2012-05-11 08:51:53,626:4030(0xb7345b00):ZOO_INFO@log_env@687: Client environment:user.home=/home/andre 2012-05-11 08:51:53,626:4030(0xb7345b00):ZOO_INFO@log_env@699: Client environment:user.dir=/home/andre 2012-05-11 08:51:53,626:4030(0xb7345b00):ZOO_INFO@zookeeper_init@727: Initiating client connection, host=192.168.122.1:41779 sessionTimeout=10000 watcher=0xb7780620 sessionId=0 sessionPasswd=<null> context=0x9242ee8 flags=0 2012-05-11 08:51:53,627:4030(0xb6b90b40):ZOO_INFO@check_events@1585: initiated connection to server [192.168.122.1:41779] 2012-05-11 08:51:53,649:4030(0xb6b90b40):ZOO_INFO@check_events@1632: session establishment complete on server [192.168.122.1:41779], sessionId=0x1373ae057d90007, negotiated timeout=10000 2012-05-11 08:51:53,651 DEBUG Environment is initialized. machines: 0: agent-state: running dns-name: localhost instance-id: local instance-state: running services: mysql: charm: cs:precise/mysql-1 relations: db: - wordpress units: mysql/0: agent-state: pending machine: 0 public-address: null wordpress: charm: cs:precise/wordpress-0 relations: db: - mysql units: wordpress/0: agent-state: pending machine: 0 public-address: null

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• Better way to search for text in two columns

  - by David

  Here is the scenario. I am making a custom blogging software for my site. I am implementing a search feature. It's not very sophisticated - basically it just takes the search phrase entered and runs this query: $query="SELECT * FROM `blog` WHERE `title` LIKE '%$q%' OR `post` LIKE '%$q%'"; Which is meant to simply search the title and post body for the phrase entered. Is there a better way to do that, keeping in mind how long it would take to run the query on up to 100 rows, each with a post length of up to 1500 characters? I have considered using a LIMIT statement to (sometimes) restrict the number of rows that the query would examine. Good idea?

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• PHP MYSQL FPDF retrieving pdf string stored as blob.

  - by jj.amonit

  Using the above technologies, I want to create a PDF, store it in my db, and email it. All with the click of one button. I also want to call it up and have it be able to display with a hyperlink. I am very new to FPDF. Therefore, I am trying to start off very slowly. I began with this link stackoverflow Q I put both parts of his code into the same page and tried with separate pages. I made the suggested changes/additions and even did a line by line comparison. I still get the message, "format error: not a PDF or corrupted" If I just $pdf-Output(); I get the pdf to display. It's either the way the string is being Output, or it's the header() function. It's not the storage method, unless my column setup is incorrect. BUt a blob is a blob, right? If you want, I can upload the sanitized code. Just let me know what would help answer this. Thanks JJ

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• How do I break down MySQL query results into categories, each with a specific number of rows?

  - by Mel

  Hello, Problem: I want to list n number of games from each genre (order not important) The following MySQL query resides inside a ColdFusion function. It is meant to list all games under a platform (for example, list all PS3 games; list all Xbox 360 games; etc...). The variable for PlatformID is passed through the URL. I have 9 genres, and I would like to list 10 games from each genre. SELECT games.GameID AS GameID, games.GameReleaseDate AS rDate, titles.TitleName AS tName, titles.TitleShortDescription AS sDesc, genres.GenreName AS gName, platforms.PlatformID, platforms.PlatformName AS pName, platforms.PlatformAbbreviation AS pAbbr FROM (((games join titles on((games.TitleID = titles.TitleID))) join genres on((genres.GenreID = games.GenreID))) join platforms on((platforms.PlatformID = games.PlatformID))) WHERE (games.PlatformID = '#ARGUMENTS.PlatformID#') ORDER BY GenreName ASC, GameReleaseDate DESC Once the query results come back I group them in ColdFusion as follows: <cfoutput query="ListGames" group="gName"> (first loop which lists genres) #ListGames.gName# <cfoutput> (nested loop which lists games) #ListGames.tName# </cfoutput> </cfoutput> The problem is that I only want 10 games from each genre to be listed. If I place a "limit" of 50 in the SQL, I will get ~ 50 games of the same genre (depending on how much games of that genre there are). The second issue is I don't want the overload of querying the database for all games when each person will only look at a few. What is the correct way to do this? Many thanks!

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• How do I Handle Ties When Ranking Results in MySQL?

  - by Laxmidi

  Hi, How does one handle ties when ranking results in a mysql query? I've simplified the table names and columns in this example, but it should illustrate my problem: SET @rank=0; SELECT student_names.students, @rank := @rank +1 AS rank, scores.grades FROM student_names LEFT JOIN scores ON student_names.students = scores.students ORDER BY scores.grades DESC So imagine the the above query produces: Students Rank Grades Al 1 90 Amy 2 90 George 3 78 Bob 4 73 Mary 5 NULL William 6 NULL Even though Al and Amy have the same grade, one is ranked higher than the other. Amy got ripped-off. How can I make it so that Amy and Al have the same ranking, so that they both have a rank of 1. Also, William and Mary didn't take the test. They bagged class and were smoking in the boy's room. They should be tied for last place. The correct ranking should be: Students Rank Grades Al 1 90 Amy 1 90 George 3 78 Bob 4 73 Mary 5 NULL William 5 NULL If anyone has any advice, please let me know. Thank you! -Laxmidi

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• How does this Switch statement know which case to execute? (PHP/MySQL)

  - by ggfan

  Here is a code form a PHP+MySQL book I am reading and I am having trouble understanding this code. This code is about checking a file uploaded into a database. (Please excuse any spelling errors if any, I was typing it in) Q1: How does it know which case to echo? In the whole code, there is no mention of each case. Q2: Why do they skip case 5?! Or does it not matter which numbers you use(so I can have case 1, case 18, case 2?) if($_FILES['userfile']['error']>0) { echo 'Problem: '; switch($_FILES['userfile']['error']) { case 1: echo 'File exceeded upload_max_filesize'; break; case 2: echo 'File exceeded max_file_size'; break; case 3: echo 'File only partially uploaded'; break; case 4: echo 'No file uploaded'; break; case 6: echo 'Cannot upload file: no temp directory specified'; break; case 7: echo 'Upload failed: Cannot write to disk'; break; } exit; }

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• Is there a way to effect user defined data types in MySQL?

  - by Dancrumb

  I have a database which stores (among other things), the following pieces of information: Hardware IDs BIGINTs Storage Capacities BIGINTs Hardware Names VARCHARs World Wide Port Names VARCHARs I'd like to be able to capture a more refined definition of these datatypes. For instance, the hardware IDs have no numerical significance, so I don't care how they are formatted when displayed. The Storage Capacities, however, are cardinal numbers and, at a user's request, I'd like to present them with thousands and decimal separators, e.g. 123,456.789. Thus, I'd like to refine BIGINT into, say ID_NUMBER and CARDINAL. The same with Hardware Names, which are simple text and WWPNs, which are hexstrings, e.g. 24:68:AC:E0. Thus, I'd like to refine VARCHAR into ENGLISH_WORD and HEXSTRING. The specific datatypes I made up are just for illustrative purposes. I'd like to keep all this information in one place and I'm wondering if anybody knows of a good way to hold this all in my MySQL table definitions. I could use the Comment field of the table definition, but that smells fishy to me. One approach would be to define the data structure elsewhere and use that definition to generate my CREATE TABLEs, but that would be a major rework of the code that I currently have, so I'm looking for alternatives. Any suggestions? The application language in use is Perl, if that helps.

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• How do I break down MySQL query results into categories, each with a specific number of rows?

  - by Mel

  Hello, Problem: I want to list n number of games from each genre (order not important) The following MySQL query resides inside a ColdFusion function. It is meant to list all games under a platform (for example, list all PS3 games; list all Xbox 360 games; etc...). The variable for PlatformID is passed through the URL. I have 9 genres, and I would like to list 10 games from each genre. SELECT games.GameID AS GameID, games.GameReleaseDate AS rDate, titles.TitleName AS tName, titles.TitleShortDescription AS sDesc, genres.GenreName AS gName, platforms.PlatformID, platforms.PlatformName AS pName, platforms.PlatformAbbreviation AS pAbbr FROM (((games join titles on((games.TitleID = titles.TitleID))) join genres on((genres.GenreID = games.GenreID))) join platforms on((platforms.PlatformID = games.PlatformID))) WHERE (games.PlatformID = '#ARGUMENTS.PlatformID#') ORDER BY GenreName ASC, GameReleaseDate DESC Once the query results come back I group them in ColdFusion as follows: <cfoutput query="ListGames" group="gName"> (first loop which lists genres) #ListGames.gName# <cfoutput> (nested loop which lists games) #ListGames.tName# </cfoutput> </cfoutput> The problem is that I only want 10 games from each genre to be listed. If I place a "limit" of 50 in the SQL, I will get ~ 50 games of the same genre (depending on how much games of that genre there are). The second issue is I don't want the overload of querying the database for all games when each person will only look at a few. What is the correct way to do this? Many thanks!

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• Top 10 collection completion - a monster in-query formula in MySQL?

  - by Andrew Heath

  I've got the following tables: User Basic Data (unique) [userid] [name] [etc] User Collection (one to one) [userid] [game] User Recorded Plays (many to many) [userid] [game] [scenario] [etc] Game Basic Data (unique) [game] [total_scenarios] I would like to output a table that shows the collection play completion percentage for the Top 10 users in descending order of %: Output Table [userid] [collection_completion] 3 95% 1 81% 24 68% etc etc In my mind, the calculation sequence for ONE USER is: grab user's total owned scenarios from User Collection joined with Game Basic Data and COUNT(gbd.total_scenarios) grab all recorded plays by COUNT(DISTINCT scenario) for that user Divide all recorded plays by total owned scenarios So that's 2 queries and a little PHP massage at the end. For a list of users sorted by completion percentage things get a little more complicated. I figure I could grab all users' collection totals in one query, and all users recorded plays in another, and then do the calcs and sort the final array in PHP, but it seems like overkill to potentially be doing all that for 1000+ users when I only ever want the Top 10. Is there a wicked monster query in MySQL that could do all that and LIMIT 10? Or is sticking with PHP handling the bulk of the work the way to go in this case?

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• mysql prevent displaying a row ONE which has reference in another row TWO but no reference in row THREE

  - by Jayapal Chandran

  I have a table like the following id | name | pid 1 | sam | NULL 2 | sams ref | 1 3 | pam | NULL For the first time the first row gets inserted which will have pid as null I insert a row which is related to the first row and then i insert a row which is new and which may be referred by another row in future. now i want only the third row to be displayed and not the first and second row as the second row contains the reference of first row. so if any row has a reference to another row then both the rows should not be displayed. Only rows which is not having any reference should be displayed. BESIDES, IS IT A GOOD PRACTICE? PLEASE ADVICE ON THIS. Edited When i updated in server the query is always giving empty result. here is what i have and this one When pid is NULL then that row should appear but when another entry in the same table with pid as its parent id or any other rows id appears then both the rows should not appear. so if any pid has been referred then both the rows should not appear. here only one row will refer another row and not more than that. in my localhost i have mysql version 5.0.1 or something like that but when i installed xampp in another system it had 5.5 and in the live server it was 5.3 so in version around 5.0 the query is returning rows but in higher versions it is returning empty rows. so now i this case how to make a query?

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• Starting with versioning mysql schemata without overkill. Good solutions?

  - by tharkun

  I've arrived at the point where I realise that I must start versioning my database schemata and changes. I consequently read the existing posts on SO about that topic but I'm not sure how to proceed. I'm basically a one man company and not long ago I didn't even use version control for my code. I'm on a windows environment, using Aptana (IDE) and SVN (with Tortoise). I work on PHP/mysql projects. What's a efficient and sufficient (no overkill) way to version my database schemata? I do have a freelancer or two in some projects but I don't expect a lot of branching and merging going on. So basically I would like to keep track of concurrent schemata to my code revisions. [edit] Momentary solution: for the moment I decided I will just make a schema dump plus one with the necessary initial data whenever I'm going to commit a tag (stable version). That seems to be just enough for me at the current stage.[/edit] [edit2]plus I'm now also using a third file called increments.sql where I put all the changes with dates, etc. to make it easy to trace the change history in one file. from time to time I integrate the changes into the two other files and empty the increments.sql[/edit]

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• Record Disappeared from Mysql Table, How Can I Find Out What Happened?

  - by Jascha

  I got the fire alarm phone call, AIM messages and email today from a client stating "The site is down!, WTF happened?!" Well, after a little digging, it turns out one of the records in a table had been wiped clean, but without removing the row itself. So, I had the representation of data, but a bunch of empty fields. (needless to day I need to write into my code a catch for this.) What my real question is, where can I figure out what happened? I've got access to phpmyadmin and that's about it. I found some access logs on in the root directory of my server, but that just tells me the client was in the admin area I built editing that record, I'd like to know specifically what they did that made all of the data go away. (what query was run etc...) is it possible without real server admin access? is there a neat little php to mysql class that returns data like this? Thanks in advance. -Jascha

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