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  • org.apache.struts2.dispatcher.Dispatcher: Could not find action or result Error

    - by peterwkc
    i tried to code the following simple struts but encounter this error during run time. [org.apache.struts2.dispatcher.Dispatcher] Could not find action or result: No result defined for action com.peter.action.LoginAction and result success index.jsp <%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%> <%@ taglib prefix="s" uri="/struts-tags" %> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Struts Tutorial</title> </head> <body> <h2>Hello Struts</h2> <s:form action="login" > <s:textfield name="username" label="Username:" /> <s:password name="password" label="Password:"/> <s:submit /> </s:form> </body> </html> LoginAction.java /** * */ package com.peter.action; //import org.apache.struts2.convention.annotation.Namespace; import org.apache.struts2.convention.annotation.ResultPath; import org.apache.struts2.convention.annotation.Result; import org.apache.struts2.convention.annotation.Action; import com.opensymphony.xwork2.ActionSupport; /** * @author nicholas_tse * */ //@Namespace("/") To define URL namespace @ResultPath("/") // To instruct Struts where to search result page(jsp) public class LoginAction extends ActionSupport { private String username, password; /** * */ private static final long serialVersionUID = -8992836566328180883L; /** * */ public LoginAction() { // TODO Auto-generated constructor stub } public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } @Override @Action(value = "login", results = {@Result(name="success", location="welcome.jsp")}) public String execute() { return SUCCESS; } } /* Remove * struts2-gxp-plugin * struts2-portlet-plugin * struts2-jsf-plugin * struts2-osgi-plugin and its related osgi-plugin * struts-rest-plugin * * Add * velocity-tools-view * * */ web.xml <?xml version="1.0" encoding="UTF-8"?> <web-app id="WebApp_ID" version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"> <display-name>Struts</display-name> <!-- org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter org.apache.struts2.dispatcher.FilterDispatcher --> <filter> <filter-name>Struts_Filter</filter-name> <filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class> <init-param> <param-name>actionPackages</param-name> <param-value>com.peter.action</param-value> </init-param> </filter> <filter-mapping> <filter-name>Struts_Filter</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> </web-app> Besides the runtime error, there is deployment error which is ERROR [com.opensymphony.xwork2.util.finder.ClassFinder] (MSC service thread 1-2) Unable to read class [WEB-INF.classes.com.peter.action.LoginAction]: Could not load WEB-INF/classes/com/peter/action/LoginAction.class - [unknown location] at com.opensymphony.xwork2.util.finder.ClassFinder.readClassDef(ClassFinder.java:785) [xwork-core-2.3.1.2.jar:2.3.1.2] AFAIK, the scanning methodology of struts will scan the default packages named struts2 for any annotated class but i have instructed struts2 to scan in com.peter.action using init-param but still unable to find the class. It is pretty weird. Please help. Thanks.

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  • NSData-AES Class Encryption/Decryption in Cocoa

    - by David Schiefer
    hi, I am attempting to encrypt/decrypt a plain text file in my text editor. encrypting seems to work fine, but the decrypting does not work, the text comes up encrypted. I am certain i've decrypted the text using the word i encrypted it with - could someone look through the snippet below and help me out? Thanks :) Encrypting: NSAlert *alert = [NSAlert alertWithMessageText:@"Encryption" defaultButton:@"Set" alternateButton:@"Cancel" otherButton:nil informativeTextWithFormat:@"Please enter a password to encrypt your file with:"]; [alert setIcon:[NSImage imageNamed:@"License.png"]]; NSSecureTextField *input = [[NSSecureTextField alloc] initWithFrame:NSMakeRect(0, 0, 300, 24)]; [alert setAccessoryView:input]; NSInteger button = [alert runModal]; if (button == NSAlertDefaultReturn) { [[NSUserDefaults standardUserDefaults] setObject:[input stringValue] forKey:@"password"]; NSData *data; [self setString:[textView textStorage]]; NSMutableDictionary *dict = [NSDictionary dictionaryWithObject:NSPlainTextDocumentType forKey:NSDocumentTypeDocumentAttribute]; [textView breakUndoCoalescing]; data = [[self string] dataFromRange:NSMakeRange(0, [[self string] length]) documentAttributes:dict error:outError]; NSData*encrypt = [data AESEncryptWithPassphrase:[input stringValue]]; [encrypt writeToFile:[absoluteURL path] atomically:YES]; Decrypting: NSAlert *alert = [NSAlert alertWithMessageText:@"Decryption" defaultButton:@"Open" alternateButton:@"Cancel" otherButton:nil informativeTextWithFormat:@"This file has been protected with a password.To view its contents,enter the password below:"]; [alert setIcon:[NSImage imageNamed:@"License.png"]]; NSSecureTextField *input = [[NSSecureTextField alloc] initWithFrame:NSMakeRect(0, 0, 300, 24)]; [alert setAccessoryView:input]; NSInteger button = [alert runModal]; if (button == NSAlertDefaultReturn) { NSLog(@"Entered Password - attempting to decrypt."); NSMutableDictionary *dict = [NSDictionary dictionaryWithObject:NSPlainTextDocumentType forKey:NSDocumentTypeDocumentOption]; NSData*decrypted = [[NSData dataWithContentsOfFile:[self fileName]] AESDecryptWithPassphrase:[input stringValue]]; mString = [[NSAttributedString alloc] initWithData:decrypted options:dict documentAttributes:NULL error:outError];

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  • django manage.py syncdb not working?

    - by Diego
    Trying to learn Django, I closed the shell and am getting this problem now when I call python manage.py syncdb, any idea what happened?: I've already set up a db. I have manage.py set up in the folder django_bookmarks. What's up here? Traceback (most recent call last): File "manage.py", line 2, in from django.core.management import execute_manager ImportError: No module named django.core.management my-computer:~/Django-1.1.1/django_bookmarks mycomp$ export PATH=/Users/mycomp/bin:$PATH my-computer:~/Django-1.1.1/django_bookmarks mycomp$ python manage.py syncdb Traceback (most recent call last): File "manage.py", line 2, in from django.core.management import execute_manager ImportError: No module named django.core.management my-computer:~/Django-1.1.1/django_bookmarks mycomp$

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  • Subsonic 3, MySql, won't update record.

    - by Warspawn
    [WebMethod] public string GetAuthToken(string username, string password) { var db = new LogicDB(); //var results = from u in db.Users // where u.Username == username && u.Password == password // select u; User u = db.Select .From<User>() .Where(UsersTable.UsernameColumn).IsEqualTo(username) .And(UsersTable.PasswordColumn).IsEqualTo(password) .ExecuteSingle<User>(); if (u == null) { return "{'success': false, 'reason': 'Invalid username and/or password.'}"; } else { // really there should only be one match... Guid code = Guid.NewGuid(); u.Securitycode = code.ToString(); u.Securityexp = System.DateTime.Now.AddHours(24); //u.Save(db.Provider); return "{'id':'" + u.Id.ToString() + "', 'code':'" + code.ToString() + "', 'exp':'" + u.Securityexp.ToString() + "'}" + "\n\n<br/><br/>" + u.GetDirtyColumns().ToArray().ToString(); } } When I run that, I keep getting: System.Collections.Generic.KeyNotFoundException: The given key was not present in the dictionary. This is when u.Save(db.Provider); is uncommented. And happens even with just u.Save(); or using the linq query above results instead.

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  • Brute force characters into a textbox in c#

    - by Fred Dunly
    Hey everyone, I am VERY new to programming and the only language I know is C# So I will have to stick with that... I want to make a program that "test passwords" to see how long they would take to break with a basic brute force attack. So what I did was make 2 text boxes. (textbox1 and textbox2) and wrote the program so if the text boxes had the input, a "correct password" label would appear, but i want to write the program so that textbox2 will run a brute force algorithm in it, and when it comes across the correct password, it will stop. I REALLY need help, and if you could just post my attached code with the correct additives in it that would be great. The program so far is extremely simple, but I am very new to this, so. Thanks in advance. private void textBox2_TextChanged(object sender, EventArgs e) { } private void button1_Click(object sender, EventArgs e) { if (textBox2.Text == textBox1.Text) { label1.Text = "Password Correct"; } else { label1.Text = "Password Wrong"; } } private void label1_Click(object sender, EventArgs e) { } } } `

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  • How to reproduce System.Security.Cryptography.SHA1Managed result in Python

    - by joetyson
    Here's the deal: I'm moving a .NET website to Python. I have a database with passwords hashed using the System.Security.Cryptography.SHA1Managed utility. I'm creating the hash in .NET with the following code: string hashedPassword = Cryptographer.CreateHash("MYHasher", userInfo.Password); The MYHasher block looks like this: <add algorithmType="System.Security.Cryptography.SHA1Managed, mscorlib, Version=2.0.0.0, Culture=neutral, PublicKeyToken=blahblahblah" saltEnabled="true" type="Microsoft.Practices.EnterpriseLibrary.Security.Cryptography.HashAlgorithmProvider, Microsoft.Practices.EnterpriseLibrary.Security.Cryptography, Version=3.0.0.0, Culture=neutral, PublicKeyToken=daahblahdahdah" name="MYHasher" /> So for a given password, I get back and store in the database a 48 byte salted sha1. I assume the last 8 bytes are the salt. I have tried to reproduce the hashing process in python by doing a sha1(salt + password) and sha1(password + salt) but I'm having no luck. My question to you: How are the public keys being used? How is the password rehashed using the salt. How is the salt created? (e.g., When I say saltEnabled="true", what extra magic happens?) I need specific details that don't just reference other .NET libraries, I'm looking for the actual operational logic that happens in the blackbox. Thanks!

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  • ExtJS: Login with 'Remember me' functionality

    - by Chau
    I'm trying to create a simple login window with the very common 'Remember me' functionality. The login validation is done AJAX style, thus the browser won't remember my input. My approach is to use the built-in state functionality, but how to use it confuses me. Ext.state.Manager.setProvider(new Ext.state.CookieProvider({ expires: new Date(new Date().getTime()+(1000*60*60*24*7)), //7 days from now })); ... { xtype: 'textfield', fieldLabel: 'User name', id: 'txt-username', stateful: true, stateId: 'username' }, { xtype: 'textfield', fieldLabel: 'Password', id: 'txt-password', inputType: 'password', stateful: true, stateId: 'password' }, { xtype: 'button', text: 'Validate', stateEvents: 'click' } I know I have to implement the getState method, but on what component (my guess is on the two textfields)? Another thing I fail to realize is, how is my click event on the button connected to the state properties of my textfields?

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  • Get paperclip to crop the image without validating

    - by Micke
    Hello fellow stackoverflow members. I have been following this guide to enable users to have their own avatar. But i have bumped in to a litle problem. When the user is cropping the image the model tries to validate all my validations. My user model looks like this: class User < ActiveRecord::Base has_attached_file :avatar, :styles => { :small => "100x100>", :large => "500x500>" }, :processors => [:cropper] attr_accessor :password, :crop_x, :crop_y, :crop_w, :crop_h attr_accessible :crop_x, :crop_y, :crop_w, :crop_h validates_confirmation_of :password validates_presence_of :password And when the user runs the crop updating script the user model tries to validate the password. But because i have no password field on the cropping page it can't validate it. Here is the updating of the crop: @user = User.find(current_user.id) if @user.update_attributes(params[:user]) flash[:notice] = "Successfully updated user." end How can i bypass this in a easy and clean way?

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  • SMO restore of SQL database doesn't overwrite

    - by Tom H.
    I'm trying to restore a database from a backup file using SMO. If the database does not already exist then it works fine. However, if the database already exists then I get no errors, but the database is not overwritten. The "restore" process still takes just as long, so it looks like it's working and doing a restore, but in the end the database has not changed. I'm doing this in Powershell using SMO. The code is a bit long, but I've included it below. You'll notice that I do set $restore.ReplaceDatabase = $true. Also, I use a try-catch block and report on any errors (I hope), but none are returned. Any obvious mistakes? Is it possible that I'm not reporting some error and it's being hidden from me? Thanks for any help or advice that you can give! function Invoke-SqlRestore { param( [string]$backup_file_name, [string]$server_name, [string]$database_name, [switch]$norecovery=$false ) # Get a new connection to the server [Microsoft.SqlServer.Management.Smo.Server]$server = New-SMOconnection -server_name $server_name Write-Host "Starting restore to $database_name on $server_name." Try { $backup_device = New-Object("Microsoft.SqlServer.Management.Smo.BackupDeviceItem") ($backup_file_name, "File") # Get local paths to the Database and Log file locations If ($server.Settings.DefaultFile.Length -eq 0) {$database_path = $server.Information.MasterDBPath } Else { $database_path = $server.Settings.DefaultFile} If ($server.Settings.DefaultLog.Length -eq 0 ) {$database_log_path = $server.Information.MasterDBLogPath } Else { $database_log_path = $server.Settings.DefaultLog} # Load up the Restore object settings $restore = New-Object Microsoft.SqlServer.Management.Smo.Restore $restore.Action = 'Database' $restore.Database = $database_name $restore.ReplaceDatabase = $true if ($norecovery.IsPresent) { $restore.NoRecovery = $true } Else { $restore.Norecovery = $false } $restore.Devices.Add($backup_device) # Get information from the backup file $restore_details = $restore.ReadBackupHeader($server) $data_files = $restore.ReadFileList($server) # Restore all backup files ForEach ($data_row in $data_files) { $logical_name = $data_row.LogicalName $physical_name = Get-FileName -path $data_row.PhysicalName $restore_data = New-Object("Microsoft.SqlServer.Management.Smo.RelocateFile") $restore_data.LogicalFileName = $logical_name if ($data_row.Type -eq "D") { # Restore Data file $restore_data.PhysicalFileName = $database_path + "\" + $physical_name } Else { # Restore Log file $restore_data.PhysicalFileName = $database_log_path + "\" + $physical_name } [Void]$restore.RelocateFiles.Add($restore_data) } $restore.SqlRestore($server) # If there are two files, assume the next is a Log if ($restore_details.Rows.Count -gt 1) { $restore.Action = [Microsoft.SqlServer.Management.Smo.RestoreActionType]::Log $restore.FileNumber = 2 $restore.SqlRestore($server) } } Catch { $ex = $_.Exception Write-Output $ex.message $ex = $ex.InnerException while ($ex.InnerException) { Write-Output $ex.InnerException.message $ex = $ex.InnerException } Throw $ex } Finally { $server.ConnectionContext.Disconnect() } Write-Host "Restore ended without any errors." }

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  • How to Send user to two different web pages when login

    - by Pradeep
    protected static Boolean Authentication(string username, string password) { string sqlstring; sqlstring = "Select Username, Password, UserType from Userprofile WHERE Username='" + username + "' and Password ='" + password + "'"; // create a connection with sqldatabase System.Data.SqlClient.SqlConnection con = new System.Data.SqlClient.SqlConnection( "Data Source=PRADEEP-LAPTOP\\SQLEXPRESS;Initial Catalog=BookStore;Integrated Security=True"); // create a sql command which will user connection string and your select statement string System.Data.SqlClient.SqlCommand comm = new System.Data.SqlClient.SqlCommand(sqlstring, con); // create a sqldatabase reader which will execute the above command to get the values from sqldatabase System.Data.SqlClient.SqlDataReader reader; // open a connection with sqldatabase con.Open(); // execute sql command and store a return values in reade reader = comm.ExecuteReader(); // check if reader hase any value then return true otherwise return false if (reader.Read()) return true; else return false; } Boolean blnresult; blnresult = Authentication(Login2.UserName, Login2.Password); if (blnresult == true) { Session["User_ID"] = getIDFromName(Login2.UserName); Session["Check"] = true; Session["Username"] = Login2.UserName; Response.Redirect("Index.aspx"); } so a user like Staff or even Administrators loging to same Index.aspx. i want to change it to different web pages. how to change sites for each user types. i have seperate user types. and i have taken UserType in the Authentication function.

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  • Salt, passwords and security

    - by Jonathan
    I've read through many of the questions on SO about this, but many answers contradict each other or I don't understand. You should always store a password as a hash, never as plain text. But should you store the salt (unique for each user) next to the hashed password+salt in the database. This doesn't seem very clever to me as couldn't someone gain access to the database, look for says the account called Admin or whatever and then work out the password from that?

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  • Datamining on a mysql database

    - by sliptix
    Hello, I Begin with textmining. I have two database tables with thousands of data.. a table for "skills" and a table for "skills categories" every "skill" belongs to a skills categorie. a "skill" is , physicaly, a varchar(200) field in the database, where there is some text describing the skill. Here are some skills extracted from the skills table: "PHP (good level), Java (intermediaite), C++" "PHP5" "project management and quality management" "begining Javascript" "water engineering" "dfsdf zerze rzer" "cibling customers" what i want to do is to extract knowledge from those fields, i mean extract only the real skill and ignore the rest of useless text. for the above example i want to get only an array with: "PHP" "Java" "C++" "PHP5" "project management" "quality management" "Javascript" "water engineering" "cibling customers" what should i do to extract the skills from tons of data please ? do you know specific algorithms to do this ? ex : k-means ... ? Thanks in advance.

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  • Problem with a test method in Yii web services

    - by Conrad
    Hi There, Is there anyone here who might be familiar with web services in the yii framework? I declared the following test method: /** * Send a single SMS message * * @param string $username Username * @param string $password Password * @param string $identifier Valid Identifier to use * @param string $mobileNumber Mobile Number to send message to * @param string $message Message to send * @return string 'OK' on success, error message on failure * @soap */ public function singleSms($username, $password, $identifier,$mobileNumber, $message){ return "username=$username, pwd=$password, source=$identifier, mobno=$mobileNumber, msg=$message"; } But when I try to call this method I get the following response: - - WSDL - SOAP-ERROR: Parsing WSDL: Couldn't load from 'http://sms.chillnethosting.co.za/index.php?r=sms/webservice' : Start tag expected, '<' not found The WSDL generates when I call my URL: Web Service URL Any Ideas?

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  • Preferred place to store username

    - by Rudiger
    I am dealing with a single username and password in an App, I'm storing the password in the keychain for security but where best to store the username? In NSUserDefaults, CFPreferences or is there a way to retrieve it out of the keychain along with the password. Later on there might be two entries in the keychain so I think this might be out of the question. Or does it not matter at all?

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  • How to pass a random User/Pass (for Basic Authentication) with JMeter?

    - by Pure.Krome
    Hi folks, I'm using JMeter to stress test an API. I've got Basic Authentication set up - seems to be working great. Now, i'm trying to randomize the credentials that JMeter passes across the wire. So, there's two ways I know I can do this. Add a custom HTTP Header (via an HTTP Header Manager Element) and set then value to the random fields (ie. something I've read in from a csv file) Use the HTTP Authorization Manager Element and pass in the username and password there. Now, if I try and use method (1) above, I need to create the following header/data :- Authorization: Basic <some Base64 encoded string in the format username:password> eg. Authorization: Basic OnVzZXIxOnBhc3Mx Kewl. simple. BUT that header value is not getting passed across the wire :( I can add any other header type and it's passed across the wire.. hmm .. ok then .. lets try method (2). Now that works .. but I can only hardcode in the username & password. I can't see how I can pass in a username VARIABLE (ie. ${usernmae} ) or a password VARIABLE (ie. ${password} ).... If it's hardcoded, then the server correctly replies with the correct page/data. so .. can someone please help?

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  • Cannot login to Activeadmin after gem update

    - by user1883793
    After bundle update I cannot login to my Activeadmin, here is the log. Is it because the unpermitted params? do I need to config strong parameter to make admin login work? I already have this code for devise: def configure_permitted_parameters devise_parameter_sanitizer.for(:sign_in) { |u| u.permit(:email, :password, :remember_me) } devise_parameter_sanitizer.for(:sign_up) { |u| u.permit(:username, :email, :password) } end Started POST "/admin/login" for 127.0.0.1 at 2013-10-30 22:33:25 +1300 Processing by ActiveAdmin::Devise::SessionsController#create as HTML Parameters: {"utf8"=>"?", "authenticity_token"=>"MhoM/R/oVfad/iiov2zpqfoJ5XOSLda6rTl/V2cMIZE=", "admin_user"=>{"email"=>"[email protected]", "password"=>"[FILTERED]", "remember_me"=>"0"}, "commit"=>"Login"} Completed 401 Unauthorized in 0.6ms Processing by ActiveAdmin::Devise::SessionsController#new as HTML Parameters: {"utf8"=>"?", "authenticity_token"=>"MhoM/R/oVfad/iiov2zpqfoJ5XOSLda6rTl/V2cMIZE=", "admin_user"=>{"email"=>"[email protected]", "password"=>"[FILTERED]", "remember_me"=>"0"}, "commit"=>"Login"} Unpermitted parameters: email, password, remember_me Rendered /home/jcui/.rvm/gems/ruby-1.9.3-p194/gems/activeadmin-0.6.2/app/views/active_admin/devise/shared/_links.erb (0.6ms) Rendered /home/jcui/.rvm/gems/ruby-1.9.3-p194/gems/activeadmin-0.6.2/app/views/active_admin/devise/sessions/new.html.erb within layouts/active_admin_logged_out (118.2ms) Completed 200 OK in 130.7ms (Views: 129.9ms | ActiveRecord: 0.0ms | Solr: 0.0ms)

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  • Migration for creating and deleting model in South

    - by Almad
    I've created a model and created initial migration for it: db.create_table('tvguide_tvguide', ( ('id', models.AutoField(primary_key=True)), ('date', models.DateField(_('Date'), auto_now=True, db_index=True)), )) db.send_create_signal('tvguide', ['TVGuide']) models = { 'tvguide.tvguide': { 'channels': ('models.ManyToManyField', ["orm['tvguide.Channel']"], {'through': "'ChannelInTVGuide'"}), 'date': ('models.DateField', ["_('Date')"], {'auto_now': 'True', 'db_index': 'True'}), 'id': ('models.AutoField', [], {'primary_key': 'True'}) } } complete_apps = ['tvguide'] Now, I'd like to drop it: db.drop_table('tvguide_tvguide') However, I have also deleted corresponding model. South (at least 0.6.2) is however trying to access it: (venv)[almad@eva-03 project]$ ./manage.py migrate tvguide Running migrations for tvguide: - Migrating forwards to 0002_removemodels. > tvguide: 0001_initial Traceback (most recent call last): File "./manage.py", line 27, in <module> execute_from_command_line() File "/usr/lib/python2.6/site-packages/django/core/management/__init__.py", line 353, in execute_from_command_line utility.execute() File "/usr/lib/python2.6/site-packages/django/core/management/__init__.py", line 303, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/usr/lib/python2.6/site-packages/django/core/management/base.py", line 195, in run_from_argv self.execute(*args, **options.__dict__) File "/usr/lib/python2.6/site-packages/django/core/management/base.py", line 222, in execute output = self.handle(*args, **options) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/management/commands/migrate.py", line 91, in handle skip = skip, File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/migration.py", line 581, in migrate_app result = run_forwards(mapp, [mname], fake=fake, db_dry_run=db_dry_run, verbosity=verbosity) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/migration.py", line 388, in run_forwards verbosity = verbosity, File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/migration.py", line 287, in run_migrations orm = klass.orm File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 62, in __get__ self.orm = FakeORM(*self._args) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 45, in FakeORM _orm_cache[args] = _FakeORM(*args) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 106, in __init__ self.models[name] = self.make_model(app_name, model_name, data) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 307, in make_model tuple(map(ask_for_it_by_name, bases)), File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/utils.py", line 23, in ask_for_it_by_name ask_for_it_by_name.cache[name] = _ask_for_it_by_name(name) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/utils.py", line 17, in _ask_for_it_by_name return getattr(module, bits[-1]) AttributeError: 'module' object has no attribute 'TVGuide' Is there a way around?

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  • Credentials can not be delegated - Alfresco Share

    - by leftcase
    I've hit a brick wall configuring Alfresco 4.0.d on Redhat 6. I'm using Kerberos authentication, it seems to be working normally, and single sign on is working on the main alfresco app itself. I've been through the configuration steps to get the share app working, but try as I may, I keep getting this error in catalina.out each time a browser accesses http://server:8080/share along with a 'Windows Security' password box. WARN [site.servlet.KerberosSessionSetupPrivilegedAction] credentials can not be delegated! Here's what I've done so far: Using AD users and computers, selected the alfrescohttp account, and selected 'trust this user for delegation to any service (Kerberos only). Copied /opt/alfresco-4.0.d/tomcat/shared/classes/alfresco/web-extension/share-config-custom.xml.sample to share-config-custom.xml and edited like this: <config evaluator="string-compare" condition="Kerberos" replace="true"> <kerberos> <password>*****</password> <realm>MYDOMAIN.CO.UK</realm> <endpoint-spn>HTTP/[email protected]</endpoint-spn> <config-entry>ShareHTTP</config-entry> </kerberos> </config> <config evaluator="string-compare" condition="Remote"> <remote> <keystore> <path>alfresco/web-extension/alfresco-system.p12</path> <type>pkcs12</type> <password>alfresco-system</password> </keystore> <connector> <id>alfrescoCookie</id> <name>Alfresco Connector</name> <description>Connects to an Alfresco instance using cookie-based authentication</description> <class>org.springframework.extensions.webscripts.connector.AlfrescoConnector</class> </connector> <endpoint> <id>alfresco</id> <name>Alfresco - user access</name> <description>Access to Alfresco Repository WebScripts that require user authentication</description> <connector-id>alfrescoCookie</connector-id> <endpoint-url>http://localhost:8080/alfresco/wcs</endpoint-url> <identity>user</identity> <external-auth>true</external-auth> </endpoint> </remote> </config> Setup the /etc/krb5.conf file like this: [logging] default = FILE:/var/log/krb5libs.log kdc = FILE:/var/log/krb5kdc.log admin_server = FILE:/var/log/kadmind.log [libdefaults] default_realm = MYDOMAIN.CO.UK default_tkt_enctypes = rc4-hmac default_tgs_enctypes = rc4-hmac forwardable = true proxiable = true [realms] MYDOMAIN.CO.UK = { kdc = mydc.mydomain.co.uk admin_server = mydc.mydomain.co.uk } [domain_realm] .mydc.mydomain.co.uk = MYDOMAIN.CO.UK mydc.mydomain.co.uk = MYDOMAIN.CO.UK /opt/alfresco-4.0.d/java/jre/lib/security/java.login.config is configured like this: Alfresco { com.sun.security.auth.module.Krb5LoginModule sufficient; }; AlfrescoCIFS { com.sun.security.auth.module.Krb5LoginModule required storeKey=true useKeyTab=true keyTab="/etc/alfrescocifs.keytab" principal="cifs/server.mydomain.co.uk"; }; AlfrescoHTTP { com.sun.security.auth.module.Krb5LoginModule required storeKey=true useKeyTab=true keyTab="/etc/alfrescohttp.keytab" principal="HTTP/server.mydomain.co.uk"; }; com.sun.net.ssl.client { com.sun.security.auth.module.Krb5LoginModule sufficient; }; other { com.sun.security.auth.module.Krb5LoginModule sufficient; }; ShareHTTP { com.sun.security.auth.module.Krb5LoginModule required storeKey=true useKeyTab=true keyTab="/etc/alfrescohttp.keytab" principal="HTTP/server.mydomain.co.uk"; }; And finally, the following settings in alfresco-global.conf authentication.chain=kerberos1:kerberos,alfrescoNtlm1:alfrescoNtlm kerberos.authentication.real=MYDOMAIN.CO.UK kerberos.authentication.user.configEntryName=Alfresco kerberos.authentication.cifs.configEntryName=AlfrescoCIFS kerberos.authentication.http.configEntryName=AlfrescoHTTP kerberos.authentication.cifs.password=****** kerberos.authentication.http.password=***** kerberos.authentication.defaultAdministratorUserNames=administrator ntlm.authentication.sso.enabled=true As I say, I've hit a brick wall with this and I'd really appreciate any help you can give me! This question is also posted on the Alfresco forum, but I wondered if any folk here on serverfault have come across similar implementation challenges?

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  • SecurityException when accessing (ejb2-) session bean via local interface in JBoss 5

    - by sme
    I have the following problem with an EJB 2 SessionBean when deploying in JBoss 5: The SessionBean (called LVSKeepAliveDispatcher) requires a specific user role (called "LVSUser"), specified by <method-permission > <description></description> <role-name>LVSUser</role-name> <method > <description></description> <ejb-name>LVSKeepAliveDispatcher</ejb-name> <method-name>*</method-name> </method> </method-permission> in ejb-jar.xml. I now want to access this SessionBean from a Service (i.e. a class implementing the org.jboss.varia.scheduler.Schedulable interface that is then registered as a service) running inside the same JBoss instance. This is my jboss-service.xml: <server> <mbean code="org.jboss.varia.scheduler.Scheduler" name="lvs:service=TranslationService"> <attribute name="StartAtStartup">true</attribute> <attribute name="SchedulableClass">de.repower.lvs.server.service.translation.TranslationService</attribute> <attribute name="SchedulableArguments"></attribute> <attribute name="SchedulableArgumentTypes"></attribute> <attribute name="InitialStartDate">NOW</attribute> <attribute name="SchedulePeriod">60000</attribute> <attribute name="InitialRepetitions">1</attribute> <attribute name="TimerName">jboss:service=Timer,name=TranslationServiceTimer</attribute> <depends><mbean code="javax.management.timer.Timer" name="jboss:service=Timer,name=TranslationServiceTimer"/></depends> <depends>jboss.j2ee:service=EJB,jndiName=de/repower/lvs/i18n/sessionbeans/LVSTranslation</depends> </mbean> As the service is deployed in the same vm as the session bean I want to call the session bean via the local interface, but I get a SecurityException when I try to create an instance. When instead I do a lookup of the RemoteInterface it works. This is the code inside the perform method of my service class: public void perform(Date now, long remainingRepetitions) { try { final UsernamePasswordHandler handler = new UsernamePasswordHandler(USERNAME, PASSWORD); final LoginContext lc = new LoginContext("client-login", handler); lc.login(); // Trying to instantiate an LVSKeepAliveDispatcher via remote interface // This part works LVSKeepAliveDispatcher localvHome = LVSKeepAliveDispatcherUtil.getHome().create(); LOGGER.info("Successfully instantiated an LVSKeepAliveDispatcher " + localvHome.toString()); // Trying to instantiate an LVSKeepAliveDispatcherLocal via local interface LVSKeepAliveDispatcherLocal localvLocalHome = LVSKeepAliveDispatcherUtil.getLocalHome().create(); // this code is unforunately never reached LOGGER.info("Successfully instantiated an LVSKeepAliveDispatcherLocal " + localvLocalHome.toString()); lc.logout(); } catch (final Exception ex) { LOGGER.error("Error: ", ex); } } Exception: 2009-02-17 10:38:02,266 INFO [lvsi18n] (Timer-2) Successfully instantiated an LVSKeepAliveDispatcher de/repower/lvs/server/service/alive/sessionbeans/LVSKeepAliveDispatcher:Stateless 2009-02-17 10:38:02,297 ERROR [org.jboss.ejb.plugins.SecurityInterceptor] (Timer-2) Error in Security Interceptor java.lang.SecurityException: Authentication exception, principal=internalSystemUser at org.jboss.ejb.plugins.SecurityInterceptor.checkSecurityContext(SecurityInterceptor.java:321) at org.jboss.ejb.plugins.SecurityInterceptor.process(SecurityInterceptor.java:243) at org.jboss.ejb.plugins.SecurityInterceptor.invokeHome(SecurityInterceptor.java:205) at org.jboss.ejb.plugins.security.PreSecurityInterceptor.process(PreSecurityInterceptor.java:136) at org.jboss.ejb.plugins.security.PreSecurityInterceptor.invokeHome(PreSecurityInterceptor.java:88) at org.jboss.ejb.plugins.LogInterceptor.invokeHome(LogInterceptor.java:132) at org.jboss.ejb.plugins.ProxyFactoryFinderInterceptor.invokeHome(ProxyFactoryFinderInterceptor.java:107) at org.jboss.ejb.SessionContainer.internalInvokeHome(SessionContainer.java:639) at org.jboss.ejb.Container.invoke(Container.java:1046) at org.jboss.ejb.plugins.local.BaseLocalProxyFactory.invokeHome(BaseLocalProxyFactory.java:362) at org.jboss.ejb.plugins.local.LocalHomeProxy.invoke(LocalHomeProxy.java:133) at $Proxy193.create(Unknown Source) at de.repower.lvs.server.service.translation.TranslationService.perform(TranslationService.java:68) at org.jboss.varia.scheduler.Scheduler$PojoScheduler.invoke(Scheduler.java:1267) at org.jboss.varia.scheduler.Scheduler$BaseListener.handleNotification(Scheduler.java:1235) at sun.reflect.GeneratedMethodAccessor281.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.jboss.mx.notification.NotificationListenerProxy.invoke(NotificationListenerProxy.java:153) at $Proxy87.handleNotification(Unknown Source) at javax.management.NotificationBroadcasterSupport.handleNotification(NotificationBroadcasterSupport.java:257) at javax.management.NotificationBroadcasterSupport$SendNotifJob.run(NotificationBroadcasterSupport.java:322) at javax.management.NotificationBroadcasterSupport$1.execute(NotificationBroadcasterSupport.java:307) at javax.management.NotificationBroadcasterSupport.sendNotification(NotificationBroadcasterSupport.java:229) at javax.management.timer.Timer.sendNotification(Timer.java:1234) at javax.management.timer.Timer.notifyAlarmClock(Timer.java:1203) at javax.management.timer.TimerAlarmClock.run(Timer.java:1286) at java.util.TimerThread.mainLoop(Timer.java:512) at java.util.TimerThread.run(Timer.java:462) To further diagnose the error I debugged through the SecurityInterceptor and found that in the first case (successful creating an instance via the remote interface) the security context "lvs-security" (which I defined in login-config.xml) is being used whereas in the second case (failure when creating an instance via the local interface) the generic security context "CLIENT-LOGIN" is being used. This is the definition of the securit context "lvs-security" in login-config.xml: <application-policy name = "lvs-security"> <authentication> <login-module code = "org.jboss.security.ClientLoginModule" flag = "required"> </login-module> <login-module code = "de.repower.lvs.security.UsersRolesLoginModule" flag = "sufficient"> </login-module> <login-module code = "de.repower.lvs.security.login.LVSLoginModule" flag = "required"> <module-option name = "lvs-jboss-host">localhost</module-option> <module-option name = "lvs-jboss-jndi-port">1099</module-option> </login-module> </authentication> </application-policy> I'm now kind of stuck and hope someone can give me a hint about where to further look for the cause of the problem. This worked fine in JBoss 3.2.7. Edit: My current workaround for this problem: create a new container configuration in jboss.xml and remove the security interceptor stuff from this configuration use this newly created container configuration for all my session beans that I only use locally (i.e. via local interface).

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  • storing user info/pass in web.config authentication

    - by Tomaszewski
    Hello, I am trying to write a simple internal app with some simple authentication. I'm also trying to make this quick and learn about the forms authentication via web.config. So i have my authentication working if I hard code my 'user name' and 'password' into C# code and do a simple conditional. However, I'm having a tough time storing the a user/pass to be checked against in the web.config file. The MSDN manual says to put this into the web.config: <authentication mode="Forms"> <forms loginUrl="login.aspx"> <credentials passwordFormat="SHA1"> <user name="user1" password="27CE4CA7FBF00685AF2F617E3F5BBCAFF7B7403C" /> <user name="user2" password="D108F80936F78DFDD333141EBC985B0233A30C7A" /> <user name="user3" password="7BDB09781A3F23885CD43177C0508B375CB1B7E9"/> </credentials> </forms> </authentication> However, the minute I add 'credentials' into the 'authentication' section, I get this error: Server Error in '/' Application. Configuration Error Description: An error occurred during the processing of a configuration file required to service this request. Please review the specific error details below and modify your configuration file appropriately. Parser Error Message: Unrecognized element 'credentials'. Source Error: Line 44: <authentication mode="Forms"> Line 45: <forms loginUrl="login.aspx" /> Line 46: <credentials> Line 47: Line 48: </credentials> Source File: C:\inetpub\wwwroot\asp\projects\passwordCatalog\passwordCatalog\web.config Line: 46 So my question is, how and where would I add the following in the web.config file? <credentials passwordFormat="SHA1"> <user name="johndoe" password="mypass123" /> </credentials>

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  • Haystack / Whoosh Index Generation Error

    - by Keith Fitzgerald
    I'm trying to setup haystack with whoosh backend. When i try to gen the index [or any index command for that matter] i receive: TypeError: Item in ``from list'' not a string if i completely remove my search_indexes.py i get the same error [so i'm guessing it can't find that file at all] what might cause this error? it's set to autodiscover and i'm sure my app is installed because i'm currently using it. Full traceback: Traceback (most recent call last): File "./manage.py", line 17, in <module> execute_manager(settings) File "/Users/ghostrocket/Development/Redux/.dependencies/django/core/management/__init__.py", line 362, in execute_manager utility.execute() File "/Users/ghostrocket/Development/Redux/.dependencies/django/core/management/__init__.py", line 303, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/Users/ghostrocket/Development/Redux/.dependencies/django/core/management/__init__.py", line 257, in fetch_command klass = load_command_class(app_name, subcommand) File "/Users/ghostrocket/Development/Redux/.dependencies/django/core/management/__init__.py", line 67, in load_command_class module = import_module('%s.management.commands.%s' % (app_name, name)) File "/Users/ghostrocket/Development/Redux/.dependencies/django/utils/importlib.py", line 35, in import_module __import__(name) File "/Users/ghostrocket/Development/Redux/.dependencies/haystack/__init__.py", line 124, in <module> handle_registrations() File "/Users/ghostrocket/Development/Redux/.dependencies/haystack/__init__.py", line 121, in handle_registrations search_sites_conf = __import__(settings.HAYSTACK_SITECONF) File "/Users/ghostrocket/Development/Redux/website/../website/search_sites.py", line 2, in <module> haystack.autodiscover() File "/Users/ghostrocket/Development/Redux/.dependencies/haystack/__init__.py", line 83, in autodiscover app_path = __import__(app, {}, {}, [app.split('.')[-1]]).__path__ TypeError: Item in ``from list'' not a string and here is my search_indexes.py from haystack import indexes from haystack import site from myproject.models import * site.register(myobject)

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  • PHP and Regular Expressions question?

    - by php
    I was wondering if the codes below are the correct way to check for a street address, email address, password, city and url using preg_match using regular expressions? And if not how should I fix the preg_match code? preg_match ('/^[A-Z0-9 \'.-]{1,255}$/i', $trimmed['address']) //street address preg_match ('/^[\w.-]+@[\w.-]+\.[A-Za-z]{2,6}$/', $trimmed['email'] //email address preg_match ('/^\w{4,20}$/', $trimmed['password']) //password preg_match ('/^[A-Z \'.-]{1,255}$/i', $trimmed['city']) //city preg_match("/^[a-zA-Z]+[:\/\/]+[A-Za-z0-9\-_]+\\.+[A-Za-z0-9\.\/%&=\?\-_]+$/i", $trimmed['url']) //url

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  • [java] Keystore change passwords

    - by user313724
    Hi, I currently have a keystore, with a particular password that only I should know. I now need to give access to that keystore to someone else, so I would like to either: 1) Change the password, so I can share it with others and let them sign 2) Create a different password and allow them to sign with it. Is this possible? and - if yes - how?

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  • Windows Authentication for winforms with Windows 2000

    - by The King
    I use the following code to validate users through windows authentication for my winform application. This works fine with windows XP but when the user is using windows 2000, it says that the userid or password is in valid. How do I do this in Windows 2000. Further, How do I detect whether the user is using Windows Xp or windows 2000. [System.Runtime.InteropServices.DllImport("advapi32.dll")] public static extern bool LogonUser(string userName, string domainName, string password, int LogonType, int LogonProvider, ref IntPtr phToken); public bool IsValidateCredentials(string userName, string password, string domain) { IntPtr tokenHandler = IntPtr.Zero; bool isValid = LogonUser(userName, domain, password, 2, 0, ref tokenHandler); return isValid; } Thanks

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