Search Results

Search found 31673 results on 1267 pages for 'php thinker'.

Page 278/1267 | < Previous Page | 274 275 276 277 278 279 280 281 282 283 284 285  | Next Page >

  • penny auctions in PHP

    - by Cudos
    I have a project where I need a penny auction. Rather than doing it from scratch I would like to hear if you know any "ready-to-go" scripts for that? There are alot of them out there but most seems dodgy. I have no problem tweaking/customizing such scripts. I just don't want to start from scratch.

    Read the article

  • How to generate semi transparent shapes in php using gdlib

    - by fabbrillo
    Hi, this is the script i made // Create image $img = imagecreatetruecolor($w, $h); // Transparent image $white = imagecolorallocate($img,255,255,255); imagefilledrectangle($img,0,0,$w,$h,$white); imagecolortransparent($img, $white); //imagealphablending( $img, true ); //imagesavealpha( $img, true ); // Shape color $bgColor = imagecolorallocatealpha($img, 100, 250, 250, 70); imagefilledrectangle($img, 15, 20, 50, 100, $bgColor); imagefilledrectangle($img, 10, 25, 60, 100, $bgColor); imagepng($img, 'file.png'); the problem is the rectangles are transparent among them but not with the background i mean, i need to create a transparent image with a semi transparent shape inside any suggestions? thanks for your help

    Read the article

  • PHP, display image with Header()

    - by user271619
    I'm displaying images from outside my web root, like this: header('Content-type:image/png'); readfile($fullpath); The content-type: image/png is what confuses me. Someone else helped me out with this code, but I noticed that not all images are PNG. Many are jpg or gif. And still they are displayed successfully. does anyone know why?

    Read the article

  • PHP form validation question?

    - by GeNx
    Is it necessary to validate a name or street address? when I have it coded in the following format. And if so why? $address = mysqli_real_escape_string($mysqli, htmlentities($_POST['address'])); $name = mysqli_real_escape_string($mysqli, htmlentities($_POST['name']));

    Read the article

  • I need help with creating a data structure in PHP

    - by alex
    What I need to do is have a data structure that shows jobs organised into 14 day periods, but only when an id is the same. I've implemented all sorts of stuff, but they have failed miserably. Ideally, maybe a SQL expert could handle all of this in the query. Here is some of my code. You can assume all library stuff works as expected. $query = 'SELECT date, rig_id, comments FROM dor ORDER BY date DESC'; $dors = Db::query(Database::SELECT, $query)->execute()->as_array(); This will return all jobs, but I need to have them organised by 14 day period with the same rig_id value. $hitches = array(); foreach($dors as $dor) { $rigId = $dor['rig_id']; $date = strtotime($dor['date']); if (empty($hitches)) { $hitches[] = array( 'rigId' => $rigId, 'startDate' => $date, 'dors' => array($dor) ); } else { $found = false; foreach($hitches as $key => $hitch) { $hitchStartDate = $hitch['startDate']; $dateDifference = abs($hitchStartDate - $date); $isSameHitchTimeFrame = $dateDifference < (Date::DAY * 14); if ($rigId == $hitch['rigId'] AND $isSameHitchTimeFrame) { $found = true; $hitches[$key]['dors'][] = $dor; } } if ($found === false) { $hitches[] = array( 'rigId' => $rigId, 'startDate' => $date, 'dors' => array($dor) ); } } } This seems to work OK splitting up by rig_id, but not by date. I also think I'm doing it wrong because I need to check the earliest date. Is it possible at all to do any of this in the database query? To recap, here is my problem I have a list of jobs with all have a rig_id (many jobs can have the same) and a date. I need the data to be organised into hitches. That is, the rig_id must be the same per hitch, and they must span a 14 day period, in which the next 14 days with the same rig_id will be a new hitch. Can someone please point me on the right track? Cheers

    Read the article

  • Mysql php error insert statement not working

    - by DAFFODIL
    I created database using mysql but now,i am unable to insert data,I am getting this error. Notice: Undefined index: Name in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Address in C:\wamp\www\customer.php on line 12 Notice: Undefined index: City in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Pincode in C:\wamp\www\customer.php on line 12 Notice: Undefined index: State in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Country in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Phone in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Mobile in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Fax in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Email in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Website in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Notes in C:\wamp\www\customer.php on line 12 Error: Table 'form.customer' doesn't exist

    Read the article

  • PHP MVC Principles

    - by George
    I'm not using an off-the-shelf framework and don't particularly want to (nor d I want to go into the reasons why...). Anyway, onto my question(s), I hope it make sense.... I'm trying to get my head around what should go in the model and what should go in the controller. Originally I had the impression that a model class should represent an actual object (eg - a car from the cars table of a database) and model properties should mirror the database fields. However I'm now getting the feeling that I've got the wrong idea - should an instance of a model class represent an actual item, or should it contain a number of methods for doing stuff - sometimes to one car or sometimes to multiple cars based on my example earlier. For example I want to get all the cars from a the database and show them in the view. Am I right in think it should be along the lines of this? Controller File function list() { $cars = $this->model->get_all(); $this->view->add($cars); $this->view->render('cars-list'); } Model File function get_all() { // Use a database interaction class that I've written $cars = Database::select(); return $cars; } Now, if the car had a "status" field that was stored as an integer in the database and I wanted to change that to a string, where should that be done? By looping the SQL results array in the get_all() method in the model? Also, where should form validation live? I have written a validation class that works a little like this: $validator = new Validator(); $validator->check('field_name', 'required'); If the check fails, it adds an error message to the array in the Validator. This array of error messages would then get passed to the view. Should the use of my validator class go in model or the controller? Thanks in advance for for any help anyone can offer. If you know of any links to a simple MVC example / open source application that deals with basic CRUD, they would be much appreciated.

    Read the article

  • Debugging 500 Internal Server Error on PHP running on IIS7 cluster

    - by Matthijs P
    Recently my ISP switched our website to an IIS7.0 high availibility cluster. The website is running on PHP5.2.1 and I can only upload files (so no registry tweaks). I had tested the website before and everything seemed to be working, but now the checkout page fails with: 500 - Internal server error. There is a problem with the resource you are looking for, and it cannot be displayed. As error messages go, this isn't very informative. I've tried: ini_set('display_errors', 1); ini_set('error_log', $file_php_can_write_to ); but both don't seem to do anything. Anyone know how to get better debugging output?

    Read the article

  • PHP IP Validation Help

    - by Zubair1
    Hello, I am using this IP Validation Function that i came across while browsing, it has been working well until today i ran into a problem. For some reason the function won't validate this IP as valid: 203.81.192.26 I'm not too great with regular expressions, so would appreciate any help on what could be wrong. If you have another function, i would appreciate if you could post that for me. |--------------------------------------------| The code for the function is below: |--------------------------------------------| public static function validateIpAddress($ip_addr) { global $errors; $preg = '#^(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}' . '(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)$#'; if(preg_match($preg, $ip_addr)) { //now all the intger values are separated $parts = explode(".", $ip_addr); //now we need to check each part can range from 0-255 foreach($parts as $ip_parts) { if(intval($ip_parts) > 255 || intval($ip_parts) < 0) { $errors[] = "ip address is not valid."; return false; } return true; } return true; } else { $errors[] = "please double check the ip address."; return false; } }

    Read the article

  • [PHP] Invalid argument supplied for foreach()

    - by Roberto Aloi
    It often happens to me to handle data that can be either an array or a null variable and to feed some foreach with these data. $values = get_values(); foreach ($values as $value){ ... } When you feed a foreach with data that are not an array, you get a warning: Warning: Invalid argument supplied for foreach() in [...] Assuming it's not possible to refactor the get_values() function to always return an array (backward compatibility, not available source code, whatever other reason), I'm wondering which is the cleanest and most efficient way to avoid these warnings: Casting $values to array Initializing $values to array Wrapping the foreach with an if Other (please suggest)

    Read the article

  • how to find the directory already is there or not in php

    - by zahir hussain
    hi i want know find the directory is already there or not... if not i would like to create the directory... my coding is below... $da = getdate(); $dat = $da["year"]."-".$da["mon"]."-".$da["mday"]; $m = md5($url)."xml"; if(is_dir($dat)) { chdir($dat); $fh = fopen($m, 'w'); fwrite($fh, $xml); fclose($fh); echo "yes"; } else { mkdir($dat,0777,true); chdir($dat); $fh = fopen($m, 'w'); fwrite($fh, $xml); fclose($fh); echo "not"; } thanks and advance

    Read the article

  • How to simplify my country select menu PHP/mysql

    - by user342391
    I have a select menu that displays countries. It looks at the DB and judging by the value in the db shows the option as selected. Is there a simpler way off doing this than: if ($country == 'AG') {echo '<option value="AG" selected="selected">Antigua</option>';} else {echo '<option value="AG">Antigua</option>';}; if ($country == 'AR') {echo '<option value="AR" selected="selected">Argentina</option>';} else {echo '<option value="AR">Argentina</option>';}; if ($country == 'AM') {echo '<option value="AM" selected="selected">Armenia</option>';} else {echo '<option value="AM">Armenia</option>';}; if ($country == 'AW') {echo '<option value="AW" selected="selected">Aruba</option>';} else {echo '<option value="AW">Aruba</option>';}; if ($country == 'AU') {echo '<option value="AU" selected="selected">Australia</option>';} else {echo '<option value="AU">Australia</option >';}; if ($country == 'AT') {echo '<option value="AT" selected="selected">Austria</option>';} else {echo '<option value="AT">Austria</option>';}; if ($country == 'AZ') {echo '<option value="AZ" selected="selected">Azerbaijan</option>';} else {echo '<option value="AZ">Azerbaijan</option>';}; if ($country == 'BS') {echo '<option value="BS" selected="selected">Bahamas</option>';} else {echo '<option value="BS">Bahamas</option>';}; if ($country == 'BH') {echo '<option value="BH" selected="selected">Bahrain</option>';} else {echo '<option value="BH">Bahrain</option>';}; There are a lot of countries and doing this would be madness wouldn't it????

    Read the article

  • PHP: Strange Date Problem

    - by Me-and-Coding
    Hi, I have two users in my database whose birth date is set to: 1985-01-26 And then i have function which when provided the users' date, tells how many days are left in the birthday. Here is the function: function retage($iy,$im,$id) { if(!empty($iy)>0 && intval($im)>0 && intval($id)>0) { $tdo=$iy.'-'.$im.'-'.$id; $tdc=date('Y').'-'.$im.'-'.$id; /*echo "<br/>";*/ $cd=date('Y-n-j'); /*echo "<br/>";*/ if(strtotime($tdc)>strtotime($cd))//coming { $ty=floor((strtotime($tdc)-strtotime($tdo))/(3600*24*365)); $td=floor((strtotime($tdc)-strtotime($cd))/(24*3600)); if($td==1) { $td=round((strtotime($tdc)-strtotime($cd))/(24*3600)).' day to go'; } else { $td=round((strtotime($tdc)-strtotime($cd))/(24*3600)).' days to go'; } $ty='<font color="#C7C5C5">is turning '.$ty.' on <br>'.date('M jS Y',strtotime($tdc)).'</font>'; //return 'is turning '.$ty.' on '.$tdc; } elseif(strtotime($tdc)<strtotime($cd))//past { $ty=floor((strtotime($tdc)-strtotime($tdo))/(3600*24*365)); if($ty>0) { //$td='gone '.floor((strtotime($cd)-strtotime($tdc))/(24*3600)).' days ago'; $ndays=floor((strtotime($cd)-strtotime($tdc))/(24*3600)); if($ndays==1) $td=' gone '.round((strtotime($cd)-strtotime($tdc))/(24*3600)).' day ago'; else $td=' gone '.round((strtotime($cd)-strtotime($tdc))/(24*3600)).' days ago'; $ty='<font color="#C7C5C5">had turned '.$ty.' on <br>'.date('M jS Y',strtotime($tdc)).'</font>'; //return 'had turned '.$ty.' on '.$tdc; } else { $tdc=(date('Y')+1).'-'.$im.'-'.$id; $ty=floor((strtotime($tdc)-strtotime($tdo))/(3600*24*365)); //$td=floor((strtotime($tdc)-strtotime($cd))/(24*3600)).' days to go'; $td=floor((strtotime($tdc)-strtotime($cd))/(24*3600)); if($td==1) { $td=round((strtotime($tdc)-strtotime($cd))/(24*3600)).' day to go'; } else { $td=round((strtotime($tdc)-strtotime($cd))/(24*3600)).' days to go'; } $ty='<font color="#C7C5C5">is turning '.$ty.' on <br>'.date('M jS Y',strtotime($tdc)).'</font>'; //return 'is turning '.$ty.' on '.$tdc; } } else//today { $ty=floor((strtotime($tdc)-strtotime($tdo))/(3600*24*365)); if($ty>0) { $td='today'; $ty='<font color="#C7C5C5">has turned <br>'.$ty.' on today </font>'; //return 'has turned '.$ty.' on today'; } else { $ty='<font color="#C7C5C5">today</font>';$td=''; //return ''; } } } else { $ty='';$td=''; //return ''; } $ta[0]=$ty; $ta[1]=$td ; return $ta; } I use below code to show the days remaining: while($rs=mysql_fetch_array($result)) { if (isset($rs['byear'],$rs['bmonth'],$rs['bdate'])) { $tmptxt = retage($rs['byear'],$rs['bmonth'],$rs['bdate']); echo $tmptxt[1]; } } The strange thing is that for one user, the days remaining is shown correctly eg: gone 120 days ago And for other user having same birth date, this is shown: Jan 1st 1970 -14755 days to go Strange: When I use the same function outside of the loop and test with date 1985-01-26, the correct result is shown. Note: You can check out the function for yourself. Could you please tell what could be wrong there, your help will be highly appreciated. Thanks.

    Read the article

  • How can I execute CGI files from PHP?

    - by Henri W
    I'm trying to make a web app that will manage my Mercurial repositories for me. I want it so that when I tell it to load repository X: Connect to a MySQL server and make sure X exists. Check if the user is allowed to access the repository. If above is true, get the location of X from a mysql server. Run a hgweb cgi script (python) containing the path of the repository. Here is the problem, I want to: take the hgweb script, modify it, and run it. But I do not want to: take the hgweb script, modify it, write it to a file and redirect there. I am using Apache to run the httpd process.

    Read the article

  • web design question (php/ajax)

    - by tom smith
    Hi guys... Hope this isn't a waste of your time. I'm working on a project, and it occured to me that there's a chunk of code out there, that should allow me to see how others have implemented this. I've got a project where I'm going to have a page, with a sel box. the user will select an item from the selList, and based on the item selected, a separate section of the page (areaB) will change in terms of the content/tbls being displayed. i then want to allow the user to go through a series of subpages in areaB, where the user goes through a submit/cancel/confirm process, where the stuff in areaB changes, with the rest of the page remaining the same... i'm trying to figure out the best approach to implement the on both client/server side. i could just have an ugly "if block" where i have abunch of logic, and i completely regen the page each time the user selects an action.. i could have an approach that might involve divs/frames, where i then just regen the targeted frame/div area.. is this even possible?? i could have some form of ajaxy process, which would only alter the targeted section(s) of the page... so.. i'm trying to talk to anyone who has ideas on how to do this, or more ideally, if you know of a good code (client/server) side example of this... that i can examine. i'd really appreciate it!! i've got a more detailed overview but didn't know if it would be cool to post it here... thanks.. tom

    Read the article

  • find and replace values in a flat-file using PHP

    - by peirix
    I'd think there was a question on this already, but I can't find one. Maybe the solution is too easy... Anyway, I have a flat-file and want to let the user change the values based on a name. I've already sorted out creating new name+value-pairs using the fopen('a') mode, using jQuery to send the AJAX call with newValue and newName. But say the content looks like this: host|http:www.stackoverflow.com folder|/questions/ folder2|/users/ And now I want to change the folder value. So I'll send in folder as oldName and /tags/ as newValue. What's the best way to overwrite the value? The order in the list doesn't matter, and the name will always be on the left, followed by a |(pipe), the value and then a new-line. My first thought was to read the list, store it in an array, search all the [0]'s for oldName, then change the [1] that belongs to it, and then write it back to a file. But I feel there is a better way around this? Any ideas? Maybe regex?

    Read the article

  • PHP Associative Array Duplicate Key?

    - by Steven
    Hello, I have an associative array, however when I add values to it using the below function it seems to overwrite the same keys. Is there a way to have multiple of the same keys with different values? Or is there another form of array that has the same format? I want to have 42=56 42=86 42=97 51=64 51=52 etc etc function array_push_associative(&$arr) { $args = func_get_args(); foreach ($args as $arg) { if (is_array($arg)) { foreach ($arg as $key => $value) { $arr[$key] = $value; $ret++; } }else{ $arr[$arg] = ""; } } return $ret; }

    Read the article

  • Multiple table relationships in Zend Help

    - by Zogi
    Hi Guys I have been doing some DB mapping to link two tables to no avail. Everytime I run the code I get the following error: Message: File "Role.php" does not exist or class "Role" was not found in the file Stack trace: #0 C:\wamp\www\zend\library\Zend\Db\Table\Row\Abstract.php(867): Zend_Db_Table_Row_Abstract->_getTableFromString('Role') #1 C:\wamp\www\uw\application\models\admin\User.php(56): Zend_Db_Table_Row_Abstract->findDependentRowset('Role') #2 C:\wamp\www\uw\application\controllers\AdminController.php(110): Application_Model_Admin_User->getUsers() #3 C:\wamp\www\zend\library\Zend\Controller\Action.php(513): AdminController->usersAction() #4 C:\wamp\www\zend\library\Zend\Controller\Dispatcher\Standard.php(289): Zend_Controller_Action->dispatch('usersAction') #5 C:\wamp\www\zend\library\Zend\Controller\Front.php(954): Zend_Controller_Dispatcher_Standard->dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http)) #6 C:\wamp\www\zend\library\Zend\Application\Bootstrap\Bootstrap.php(97): Zend_Controller_Front->dispatch() #7 C:\wamp\www\zend\library\Zend\Application.php(366): Zend_Application_Bootstrap_Bootstrap->run() #8 C:\wamp\www\uwi\public\index.php(26): Zend_Application->run() #9 {main} Code & DB below: application/models/admin/User.php class Application_Model_Admin_User extends Zend_Db_Table_Abstract { protected $_name = 'user'; protected $_dependentTables = array('Role'); public function getUsers() { $rows = $this->fetchAll($this->select()->where('active = ?', 1)); $rows1 = $rows->current(); $rows2 = $rows1->findDependentRowset('Role'); return $rows2; } } application/models/admin/Role.php class Application_Model_Admin_Role extends Zend_Db_Table_Abstract { protected $_name = 'role'; protected $_referenceMap = array ( 'Role' => array( 'columns' => array('id'), 'refTableClass' => 'User', 'refColumns' => array('role_id') ); } DB tables CREATE TABLE role ( id integer auto_increment NOT NULL, name varchar(120), PRIMARY KEY(id) ); CREATE TABLE user ( id integer auto_increment NOT NULL, username varchar(120), PRIMARY KEY(id), FOREIGN KEY(role_id) REFERENCES role(id) );

    Read the article

  • PHP Application check name is unique if not append

    - by user270797
    My application requires the user to enter their business name, which the application will automatically create into a unique identifier to be used in URLs, ie "Bob's Cafe" will become "bobs-cafe" But if there are duplicate names I would like the application to add a number so if there is already a "bobs-cafe" we will use "bobs-cafe-1" and likewise if there is already a "bobs-cafe-1" we will use "bobs-cafe-2" Ive used explode and also looked at a regular expressions but I dont know the best way to approach this. Im stuck in being able to grab the number and incrementing it and returning the string

    Read the article

< Previous Page | 274 275 276 277 278 279 280 281 282 283 284 285  | Next Page >