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  • Can I use a MySQL PREPARE statement in a function to create a query with a variable table name

    - by aHunter
    I want to create a function that has a select query inside that can be used against multiple database tables but I can not use a variable as the table name. Can I get around this using a PREPARE statement in the function? An Example: FUNCTION `TESTFUNC`(dbTable VARCHAR(25)) RETURNS bigint(20) BEGIN DECLARE datereg DATETIME; DECLARE stmt VARCHAR(255); SET stmt := concat( 'SELECT dateT FROM', dbTable, 'ORDER BY dateT DESC LIMIT 1'); PREPARE stmt FROM @stmt; EXECUTE stmt; RETURN dateT; END $$ Thanks in advance for any input.

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  • Converting a date string which is before 1970 into a timestamp in MySQL.

    - by Jamie
    Not a very good title, so my apologies. For some reason, (i wasn't the person who did it, i digress) we have a table structure where the field type for a date is varchar. (odd). We have some dates, such as: 1932-04-01 00:00:00 and 1929-07-04 00:00:00 I need to do a query which will convert these date strings into a unix time stamp, however, in my sql if you convert a date which is before 1970 it will return 0. Any ideas? Thanks so much! EDIT: Wrong date format. ooops.

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  • How do I create the Controller for a Single Table Inheritance in Rails?

    - by Angela
    I am setting up the Single Table Inheritance, using ContactEvent as the Model that ContactEmail, ContactLetter, and ContactCall will all inherit. But I'm stumped on how to create the routing and the controller. For example, let's say I want to create a new ContactEvent with type Email. I would like a way to do the following: new_contact_event_path(contact, email) This would take the instance from Contact model and from Email model. Inside, I would imagine the contact_event_controller would need to know... @contact_event.type = (params[:email]) # get the type based on what was passed in? @contact_event.event_id = (params[:email]) #get the id for the correct class, in this case Email.id Just not sure how this works....

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  • Multiple Scripts With the Same MySQL Query Running At Once => Will There Be Interference?

    - by walden
    I want to have multiple scripts running from cron at the same time. They will all update, say, 500 rows with a unique status ID for that particular script to use. If each script grabs the same type of rows to update, and the scripts run at once, will there be interference between the queries run at the same time? For example, using this query: UPDATE table SET status = <unique script ID> WHERE status = 0 LIMIT 500 Will I get the same rows updating more than once? I'm trying to get each script to get unique rows. I was thinking of using sleep() to make the queries run at different times, but I'm not sure if that's necessary. Thanks.

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  • How do you encode an apostrophe so that it's searchable in mysql?

    - by Yegor
    I don't think that was the most clear question, but an example should make it a little clearer. I have a table filled with movie names, some of which contain apostrophes. I have a search box which is used to find movies. If I perform searches via mov_title = '$search_keywords' it all works, but this method will not yield any results for partial searches, so I have to use this mov_title LIKE '%$search_keywords%' This method works fine for titles that are A-Za-z0-9, but if a title has an apostrophe, it's not able to find the movie, even if I do an exact match. Before the titles are stored in the DB, I put them through this: $search_keywords = htmlspecialchars(mysql_escape_string($_GET["search_keywords"])); So in the DB, there is a forward slash before every single apostrophe. The only way to match a movie title with an apostrophe is to physically put a forward slash in front of the apostrophe, in the search box. This seems so trivial, and I'm sure the solution is painfully obvious, but I'm just not seeing it.

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  • How can I write this Table Valued Function as a Stored Procedure?

    - by Alex
    I have the following TVF for fulltext search: FUNCTION [dbo].[Fishes_FullTextSearch] (@searchtext nvarchar(4000), @limitcount int) RETURNS TABLE AS RETURN SELECT * FROM Fishes INNER JOIN CONTAINSTABLE(Fishes, *, @searchtext, @limitcount) AS KEY_TBL ON Fishes.Id = KEY_TBL.[KEY] When I'm using this TVF, it doesn't return a collection of objects of type Fish (which I want!) - instead LINQ creates a new result type which includes all "Fish" fields and the fields Key and Rank. In another question, it was suggested that I rewrite this TVF into a stored procedure for it to return Fish objects only. Can someone help me do this please? Also, it needs to be ordered by Rank. Thank you!

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  • There has to be an easier way.. pulling data from mysql

    - by Daniel Hunter
    I need to pull 3 values from a table and assign each one to a variable each value is based on to columns, a type and an id $ht_live_query = mysql_query("SELECT htcode FROM coupon WHERE pid='$pid' AND type='L'"); $ht_live_result = mysql_fetch_array($ht_live_query); $htCODE_Live = $ht_live_result['htcode']; You can see that I am assigning the desired value to the variable $htL $ht_General_query = mysql_query("SELECT htcode FROM coupon WHERE pid='$pid' AND type='G'"); $ht_General_result = mysql_fetch_array($ht_General_query); $htCODE_General = $ht_General_result['htcode']; $ht_Reward_query = mysql_query("SELECT htcode FROM coupon WHERE pid='$pid' AND type='R'"); $ht_Reward_result = mysql_fetch_array($ht_Reward_query); $htCODE_Reward = $ht_Reward_result ['htcode']; I know I am doing this the hard way but can not figure out how to do the foreach or while loop to attain the desired results.

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  • php mysql search in 2 columns in 2 tables.

    - by andrew fishwick
    Hey, I have two tables in one DB, one called Cottages and one called Hotels. In both tables they have the same named fields. I basically have a search bar that i want it to search in both of the fields in both of the tables. (the two fields being called "Name" and "Location" SO far I have $sql = mysql_query("SELECT * FROM Cottages WHERE Name LIKE '%$term%' or Location LIKE '%$term%' LIMIT 0, 30"); But this only searches the Cottages table, how can I make it search both the cottages and hotel tables? Andy

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  • Drawing up a session value within SQL query? PHP and MySQL

    - by Derek
    Hi, on one of my web pages I want my manager user to view all activities assigned to them (personally). In order to do this, I need something like this: $sql = "SELECT * FROM activities WHERE manager = $_SESSION['SESS_FULLNAME']"; Now obviously this syntax is all wrong, but because I am new to this stuff, is there a way I can call up the full name from the user's session within a query? This is so that when I call up the database values to be displayed within the web page, only the activities for the manager who is logged in is displayed. For example, the activities table has a manager column of a full name entry. Any help is much appreciated. Thanks.

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  • MySQL: selecting totals as three fields from same table as one query?

    - by coderama
    I have a table with various orders in it: ID | Date | etc... 1 | 2013-01-01 | etc 2 | 2013-02-01 | etc 3 | 2013-03-01 | etc 4 | 2013-04-01 | etc 5 | 2013-05-01 | etc 6 | 2013-06-01 | etc 7 | 2013-06-01 | etc 8 | 2013-03-01 | etc 9 | 2013-04-01 | etc 10 | 2013-05-01 | etc I want a query that ends wit the result: overallTotal | totalThisMonth | totalLastMonth 10 | 2 | 1 But I want to do this in one query! I am trying to find a way to use subqueries to do this. SO far I have: SELECT * from ( SELECT count(*) as overallTotal from ORDERS ) How can I combine this with other subqueries so I can get the totals in one query?

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  • Way to check for foreign key references before deleting in MySQL?

    - by Chad Johnson
    I'm working with a content management system, and users are prompted with a confirmation screen before deleting records. Some records are foreign key referenced in other tables, and therefore they cannot be deleted. I would like to display a message beside a given record if it has foreign key references. To know whether I should display the message for a record, I could just query the referencing table and see if there are references. But the problem is, there are about a dozen tables with records potentially referencing this record, and a lookup could take a "long" time. Is there an easy way to tell whether the record is delete-ready (ie. has no foreign key references)?

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  • MySQL sorting: NULL to the end & use index? Not possible?

    - by Vojto
    Hello fellow experts, I have a huge table and I want simple sorting. It could be so easy. I could just create an index and do some really fast sorting thanks to that index. But my client wants to put NULLs to the end, which is complicates the whole situation. Instead of simple: SORT BY name ASC I have to do SORT BY name IS NULL ASC, name ASC. That would be ok, but it because of that my index is useless, and the sorting is very slow. I don't know if there's a way to solve this problem, but if there is one, I desperately ask for help. :'(

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  • How to properly design a simple favorites and blocked table?

    - by Nils Riedemann
    Hey, i am currently writing a webapp in rails where users can mark items as favorites and also block them. I came up two ways and wondered which one is more common/better way. 1. Separate join tables Would it be wise to have 2 tables for this? Like: users_favorites - user_id - item_id users_blocked - user_id - item_id 2. single table users_marks (or so) - users_id - item_id - type (["fav", "blk"]) Both ways seem to have advantages. Which one would you use and why?

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  • best method in jquery for replacing rows in a table after server side processing such as mysql sorti

    - by Kevin J
    What is the 'best practice' when returning dynamic data for a table (server side sorting, filtering etc from a db) ? Do you return just the data in json, and repeatedly clone a row element, replacing the values in each row (thus decreasing the size of the ajax call, but increasing the client side processing), or return the full html, and replace with .html or .append? Or is there another method I'm missing? This is a frequent situation in my app, and in some cases a bottleneck, and I am unsure if what I am doing is the best solution. Currently, I return the row html and use a single .append call, after emptying all the rows except the header.

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  • How do I update mysql database when posting form without using hidden inputs?

    - by user1322707
    I have a "members" table in mysql which has approximately 200 field names. Each user is given up to 7 website templates with 26 different values they can insert unique data into for each template. Each time they create a template, they post the form with the 26 associated values. These 26 field names are the same for each template, but are differentiated by an integer at the end, ie _1, _2, ... _7. In the form submitting the template, I have a variable called $pid_sum which is inserted at the end of each field name to identify which template they are creating. For instance: <form method='post' action='create.template.php'> <input type='hidden' name='address_1' value='address_1'> <input type='hidden' name='city_1' value='city_1'> <input type='hidden' name='state_1' value='state_1'> etc... <input type='hidden' name='address_1' value='address_2'> <input type='hidden' name='city_1' value='city_2'> <input type='hidden' name='state_1' value='state_2'> etc... <input type='hidden' name='address_2' value='address_3'> <input type='hidden' name='city_2' value='city_3'> <input type='hidden' name='state_2' value='state_3'> etc... <input type='hidden' name='address_2' value='address_4'> <input type='hidden' name='city_2' value='city_4'> <input type='hidden' name='state_2' value='state_4'> etc... <input type='hidden' name='address_2' value='address_5'> <input type='hidden' name='city_2' value='city_5'> <input type='hidden' name='state_2' value='state_5'> etc... <input type='hidden' name='address_2' value='address_6'> <input type='hidden' name='city_2' value='city_6'> <input type='hidden' name='state_2' value='state_6'> etc... <input type='hidden' name='address_2' value='address_7'> <input type='hidden' name='city_2' value='city_7'> <input type='hidden' name='state_2' value='state_7'> etc... // Visible form user fills out in creating their template ($pid_sum converts // into an integer 1-7, depending on what template they are filling out) <input type='' name='address_$pid_sum'> <input type='' name='city_$pid_sum'> <input type='' name='state_$pid_sum'> etc... <input type='submit' name='save_button' id='save_button' value='Save Settings'> <form> Each of these need updated in a hidden input tag with each form post, or the values in the database table (which aren't submitted with the form) get deleted. So I am forced to insert approximately 175 hidden input tags with every creation of 26 new values for one of the 7 templates. Is there a PHP function or command that would enable me to update all these values without inserting 175 hidden input tags within each form post? Here is the create.template.php file which the form action calls: <?php $q=new Cdb; $t->set_file("content", "create_template.html"); $q2=new CDB; $query="SELECT menu_category FROM menus WHERE link='create.template.ag.php'"; $q2->query($query); $toall=0; if ($q2->nf()<1) { $toall=1; } while ($q2->next_record()) { if ($q2->f('menu_category')=="main") { $toall=1; } } if ($toall==0) { get_logged_info(); $q2=new CDB; $query="SELECT id FROM menus WHERE link='create_template.php'"; $q2->query($query); $q2->next_record(); $query="SELECT membership_id FROM menu_permissions WHERE menu_item='".$q2->f("id")."'"; $q2->query($query); while ($q2->next_record()) { $permissions[]=$q2->f("membership_id"); } if (count($permissions)>0) { $error='<center><font color="red"><b>You do not have access to this area!<br><br>Upgrade your membership level!</b></font></center>'; foreach ($permissions as $value) { if ($value==$q->f("membership_id")) { $error=''; break; } } if ($error!="") { die("$error"); } } } $member_id=$q->f("id"); $pid=$q->f("pid"); $pid_sum = $pid +1; $first_name=$q->f("first_name"); $last_name=$q->f("last_name"); $email=$q->f("email"); echo " // THIS IS WHERE THE HTML FORM GOES "; replace_tags_t($q->f("id"), $t); ?>

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  • Parsing timestamps - do it in MySQL or in PHP?

    - by Andrew Heath
    Let's say you've got a table with a timestamp column, and you want to parse that column into two arrays - $date and $time. Do you, personally: a) query like this DATE(timestamp), TIME(timestamp) , or perhaps even going as far as HOUR(timestamp), MINUTE(timestamp b) grab the timestamp column and parse it out as needed with a loop in PHP I feel like (a) is easier... but I know that I don't know anything. And it feels a little naughty to make my query hit the same column 2 or 3 times for output... Is there a best-practice for this?

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  • How to create wordpress-like option table and get values for each row? (PHP-MySQL)

    - by Nacho
    Hi guys. I'm looking to create an options table in my db that makes every record a system option, so i can work with a little number of fields. my db has the following structure: 3 columns named id, name, and value following data is inserted as an example -- id - name - value 1 - uri - www.example.com 2 - sitename - Working it out 3 - base_folder - /folder1/folder2/ 4 - slogan - Just a slogan for the site -- that way i can include a large number of customizable system options very easily the problem is that i don't know how to retrieve them how do i get the value of uri and store it as a var? and better yet, how do i get, for exmaple, values of id 1 and 4 only without making a query each time? (i assume multiple queries are useless and a pretty ugly method) i know the question is pretty basic but i'm lost here. i'd really appreciate your answer! Thanks in advance

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  • How do I select the most recent entry in mysql?

    - by ggfan
    i want to select the most recent entry from a table and see if that entry is exactly the same as the one the user is trying to enter. How do I do a query to "select * from the most recent entry of 'posting'"? $query="Select * FROM //confused here (SELECT * FROM posting ORDER BY date_added DESC) WHERE user_id='{$_SESSION['user_id']}' AND title='$title' AND price='$price' AND city='$city' AND state='$state' AND detail='$detail' "; $data = mysqli_query($dbc, $query); $row = mysqli_fetch_array($data); if(mysqli_num_rows($data)>0) { echo "You already posted this ad. Most likely caused by refreshing too many times."; echo "<br>"; $linkposting_id=$row['posting_id']; echo "See the <a href='ad.php?posting_id=$linkposting_id'>Ad</a>"; } else { ...insert into the dbc }

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  • MySQL query to find the most popular value in a column joined by another value in a second table

    - by Budove
    I have two tables: users: user_id, user_zip settings: user_id, pref_ex_loc I need to find the single most popular 'pref_ex_loc' from the settings table based on a particular user_zip, which will be specified as the variable $userzip. Here is the query that I have now and obviously it doesn't work. $popularexloc = "SELECT pref_ex_loc, user_id COUNT(pref_ex_loc) AS countloc FROM settings FULL OUTER JOIN users ON settings.user_id = users.user_id WHERE users.user_zip='$userzip' GROUP BY settings.pref_ex_loc ORDER BY countloc LIMIT 1"; $popexloc = mysql_query($popularexloc) or die('SQL Error :: '.mysql_error()); $exlocrow = mysql_fetch_array($popexloc); $mostpopexloc=$exlocrow[0]; echo '<option value="'.$mostpopexloc.'">'.$mostpopexloc.'</option>'; What am I doing wrong here? I'm not getting any kind of error from this either.

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  • SQL SERVER – Check the Isolation Level with DBCC useroptions

    - by pinaldave
    In recent consultancy project coordinator asked me – “can you tell me what is the isolation level for this database?” I have worked with different isolation levels but have not ever queried database for the same. I quickly looked up bookonline and found out the DBCC command which can give me the same details. You can run the DBCC UserOptions command on any database to get few details about dateformat, datefirst as well isolation level. DBCC useroptions Set Option                  Value --------------------------- -------------- textsize                    2147483647 language                    us_english dateformat                  mdy datefirst                   7 lock_timeout                -1 quoted_identifier           SET arithabort                  SET ansi_null_dflt_on           SET ansi_warnings               SET ansi_padding                SET ansi_nulls                  SET concat_null_yields_null     SET isolation level             read committed I thought this was very handy script, which I have not used earlier. Thanks Gary for asking right question. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Query, SQL Scripts, SQL Server, SQL System Table, SQL Tips and Tricks, T SQL, Technology Tagged: Transaction Isolation

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  • SQL SERVER – Disabled Index and Update Statistics

    - by pinaldave
    When we try to update the statistics, it throws an error as if the clustered index is disabled. Now let us enable the clustered index only and attempt to update the statistics of the table right after that. Have you ever come across the situation where a conversation never gets over and it continues even though original point of discussion has passed. I am facing the same situation in the case of Disabled Index. Here is the link to original conversations. SQL SERVER – Disable Clustered Index and Data Insert – Reader had a issue here with Disabled Index SQL SERVER – Understanding ALTER INDEX ALL REBUILD with Disabled Clustered Index – Reader asked the effect of Rebuilding Indexes The same reader asked me today – “I understood what the disabled indexes do; what is their effect on statistics. Is it true that even though indexes are disabled, they continue updating the statistics?“ The answer is very interesting: If you have disabled clustered index, you will be not able to update the statistics at all for any index. If you have enabled clustered index and disabled non clustered index when you update the statistics of the table, it automatically updates the statistics of the ALL (disabled and enabled – both) the indexes on the table. If you are not satisfied with the answer, let us go over a simple example. I have written necessary comments in the code itself to have a clear idea. USE tempdb GO -- Drop Table if Exists IF EXISTS (SELECT * FROM sys.objects WHERE OBJECT_ID = OBJECT_ID(N'[dbo].[TableName]') AND type IN (N'U')) DROP TABLE [dbo].[TableName] GO -- Create Table CREATE TABLE [dbo].[TableName]( [ID] [int] NOT NULL, [FirstCol] [varchar](50) NULL ) GO -- Insert Some data INSERT INTO TableName SELECT 1, 'First' UNION ALL SELECT 2, 'Second' UNION ALL SELECT 3, 'Third' UNION ALL SELECT 4, 'Fourth' UNION ALL SELECT 5, 'Five' GO -- Create Clustered Index ALTER TABLE [TableName] ADD CONSTRAINT [PK_TableName] PRIMARY KEY CLUSTERED ([ID] ASC) GO -- Create Nonclustered Index CREATE UNIQUE NONCLUSTERED INDEX [IX_NonClustered_TableName] ON [dbo].[TableName] ([FirstCol] ASC) GO -- Check that all the indexes are enabled SELECT OBJECT_NAME(OBJECT_ID), Name, type_desc, is_disabled FROM sys.indexes WHERE OBJECT_NAME(OBJECT_ID) = 'TableName' GO Now let us update the statistics of the table and check the statistics update date. -- Update the stats of table UPDATE STATISTICS TableName WITH FULLSCAN GO -- Check Statistics Last Updated Datetime SELECT name AS index_name, STATS_DATE(OBJECT_ID, index_id) AS StatsUpdated FROM sys.indexes WHERE OBJECT_ID = OBJECT_ID('TableName') GO Now let us disable the indexes and check if they are disabled using sys.indexes. -- Disable Indexes -- Disable Nonclustered Index ALTER INDEX [IX_NonClustered_TableName] ON [dbo].[TableName] DISABLE GO -- Disable Clustered Index ALTER INDEX [PK_TableName] ON [dbo].[TableName] DISABLE GO -- Check that all the indexes are disabled SELECT OBJECT_NAME(OBJECT_ID), Name, type_desc, is_disabled FROM sys.indexes WHERE OBJECT_NAME(OBJECT_ID) = 'TableName' GO Let us try to update the statistics of the table. -- Update the stats of table UPDATE STATISTICS TableName WITH FULLSCAN GO /* -- Above operation should thrown following error Msg 1974, Level 16, State 1, Line 1 Cannot perform the specified operation on table 'TableName' because its clustered index 'PK_TableName' is disabled. */ When we try to update the statistics it throws an error as it clustered index is disabled. Now let us enable the clustered index only and attempt to update the statistics of the table right after that. -- Now let us rebuild clustered index only ALTER INDEX [PK_TableName] ON [dbo].[TableName] REBUILD GO -- Check that all the indexes status SELECT OBJECT_NAME(OBJECT_ID), Name, type_desc, is_disabled FROM sys.indexes WHERE OBJECT_NAME(OBJECT_ID) = 'TableName' GO -- Check Statistics Last Updated Datetime SELECT name AS index_name, STATS_DATE(OBJECT_ID, index_id) AS StatsUpdated FROM sys.indexes WHERE OBJECT_ID = OBJECT_ID('TableName') GO -- Update the stats of table UPDATE STATISTICS TableName WITH FULLSCAN GO -- Check Statistics Last Updated Datetime SELECT name AS index_name, STATS_DATE(OBJECT_ID, index_id) AS StatsUpdated FROM sys.indexes WHERE OBJECT_ID = OBJECT_ID('TableName') GO We can clearly see that even though the nonclustered index is disabled it is also updated. If you do not need a nonclustered index, I suggest you to drop it as keeping them disabled is an overhead on your system. This is because every time the statistics are updated for system all the statistics for disabled indexesare also updated. -- Clean up DROP TABLE [TableName] GO The complete script is given below for easy reference. USE tempdb GO -- Drop Table if Exists IF EXISTS (SELECT * FROM sys.objects WHERE OBJECT_ID = OBJECT_ID(N'[dbo].[TableName]') AND type IN (N'U')) DROP TABLE [dbo].[TableName] GO -- Create Table CREATE TABLE [dbo].[TableName]( [ID] [int] NOT NULL, [FirstCol] [varchar](50) NULL ) GO -- Insert Some data INSERT INTO TableName SELECT 1, 'First' UNION ALL SELECT 2, 'Second' UNION ALL SELECT 3, 'Third' UNION ALL SELECT 4, 'Fourth' UNION ALL SELECT 5, 'Five' GO -- Create Clustered Index ALTER TABLE [TableName] ADD CONSTRAINT [PK_TableName] PRIMARY KEY CLUSTERED ([ID] ASC) GO -- Create Nonclustered Index CREATE UNIQUE NONCLUSTERED INDEX [IX_NonClustered_TableName] ON [dbo].[TableName] ([FirstCol] ASC) GO -- Check that all the indexes are enabled SELECT OBJECT_NAME(OBJECT_ID), Name, type_desc, is_disabled FROM sys.indexes WHERE OBJECT_NAME(OBJECT_ID) = 'TableName' GO -- Update the stats of table UPDATE STATISTICS TableName WITH FULLSCAN GO -- Check Statistics Last Updated Datetime SELECT name AS index_name, STATS_DATE(OBJECT_ID, index_id) AS StatsUpdated FROM sys.indexes WHERE OBJECT_ID = OBJECT_ID('TableName') GO -- Disable Indexes -- Disable Nonclustered Index ALTER INDEX [IX_NonClustered_TableName] ON [dbo].[TableName] DISABLE GO -- Disable Clustered Index ALTER INDEX [PK_TableName] ON [dbo].[TableName] DISABLE GO -- Check that all the indexes are disabled SELECT OBJECT_NAME(OBJECT_ID), Name, type_desc, is_disabled FROM sys.indexes WHERE OBJECT_NAME(OBJECT_ID) = 'TableName' GO -- Update the stats of table UPDATE STATISTICS TableName WITH FULLSCAN GO /* -- Above operation should thrown following error Msg 1974, Level 16, State 1, Line 1 Cannot perform the specified operation on table 'TableName' because its clustered index 'PK_TableName' is disabled. */ -- Now let us rebuild clustered index only ALTER INDEX [PK_TableName] ON [dbo].[TableName] REBUILD GO -- Check that all the indexes status SELECT OBJECT_NAME(OBJECT_ID), Name, type_desc, is_disabled FROM sys.indexes WHERE OBJECT_NAME(OBJECT_ID) = 'TableName' GO -- Check Statistics Last Updated Datetime SELECT name AS index_name, STATS_DATE(OBJECT_ID, index_id) AS StatsUpdated FROM sys.indexes WHERE OBJECT_ID = OBJECT_ID('TableName') GO -- Update the stats of table UPDATE STATISTICS TableName WITH FULLSCAN GO -- Check Statistics Last Updated Datetime SELECT name AS index_name, STATS_DATE(OBJECT_ID, index_id) AS StatsUpdated FROM sys.indexes WHERE OBJECT_ID = OBJECT_ID('TableName') GO -- Clean up DROP TABLE [TableName] GO Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Index, SQL Optimization, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology Tagged: SQL Statistics

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  • Juju stuck in "pending" state when using LXC

    - by Andre
    So I'm trying to get started with Juju, and tried to do this locally using LXC. I followed the instructions here: How do I configure juju for local usage? Unfortunately this doesn't seem to work for me. status shows the following: $ juju status machines: 0: agent-state: running dns-name: localhost instance-id: local instance-state: running services: mysql: charm: cs:precise/mysql-1 relations: db: - wordpress units: mysql/0: agent-state: pending machine: 0 public-address: null wordpress: charm: cs:precise/wordpress-0 exposed: true relations: db: - mysql units: wordpress/0: agent-state: pending machine: 0 open-ports: [] public-address: null 2012-05-10 14:09:38,155 INFO 'status' command finished successfully As you can see the agent-state is 'pending' and there is no public address where I'm able to access the newly created site. Am I missing something here? UPDATE: Tried destroying the environment an doing everything again (multiple times). This is the output for debug-log: ~$ juju debug-log 2012-05-11 08:50:23,790 INFO Enabling distributed debug log. 2012-05-11 08:50:23,806 INFO Tailing logs - Ctrl-C to stop. 2012-05-11 08:50:42,338 Machine:0: juju.agents.machine DEBUG: Units changed old:set([]) new:set(['mysql/0']) 2012-05-11 08:50:42,339 Machine:0: juju.agents.machine DEBUG: Starting service unit: mysql/0 ... 2012-05-11 08:50:42,459 Machine:0: unit.deploy DEBUG: Downloading charm cs:precise/mysql-1 to /home/andre/.juju/data/andre-local/charms 2012-05-11 08:50:42,620 Machine:0: unit.deploy DEBUG: Using <juju.machine.unit.UnitContainerDeployment object at 0x9c54b6c> for mysql/0 in /home/andre/.juju/data/andre-local 2012-05-11 08:50:42,648 Machine:0: unit.deploy DEBUG: Starting service unit mysql/0... 2012-05-11 08:50:42,649 Machine:0: unit.deploy DEBUG: Creating master container... 2012-05-11 08:54:33,992 Machine:0: unit.deploy DEBUG: Created master container andre-local-0-template 2012-05-11 08:54:33,993 Machine:0: unit.deploy INFO: Creating container mysql-0... 2012-05-11 08:56:18,760 Machine:0: unit.deploy INFO: Container created for mysql/0 2012-05-11 08:56:19,466 Machine:0: unit.deploy DEBUG: Charm extracted into container 2012-05-11 08:56:19,569 Machine:0: unit.deploy DEBUG: Starting container... 2012-05-11 08:56:22,707 Machine:0: unit.deploy INFO: Started container for mysql/0 2012-05-11 08:56:22,707 Machine:0: unit.deploy INFO: Started service unit mysql/0 2012-05-11 08:56:23,012 Machine:0: juju.agents.machine DEBUG: Units changed old:set(['mysql/0']) new:set(['wordpress/0', 'mysql/0']) 2012-05-11 08:56:23,039 Machine:0: juju.agents.machine DEBUG: Starting service unit: wordpress/0 ... 2012-05-11 08:56:23,154 Machine:0: unit.deploy DEBUG: Downloading charm cs:precise/wordpress-0 to /home/andre/.juju/data/andre-local/charms 2012-05-11 08:56:23,396 Machine:0: unit.deploy DEBUG: Using <juju.machine.unit.UnitContainerDeployment object at 0x9c519cc> for wordpress/0 in /home/andre/.juju/data/andre-local 2012-05-11 08:56:23,620 Machine:0: unit.deploy DEBUG: Starting service unit wordpress/0... 2012-05-11 08:56:23,621 Machine:0: unit.deploy INFO: Creating container wordpress-0... 2012-05-11 08:58:24,739 Machine:0: unit.deploy INFO: Container created for wordpress/0 2012-05-11 08:58:25,163 Machine:0: unit.deploy DEBUG: Charm extracted into container 2012-05-11 08:58:25,397 Machine:0: unit.deploy DEBUG: Starting container... 2012-05-11 08:58:27,982 Machine:0: unit.deploy INFO: Started container for wordpress/0 2012-05-11 08:58:27,983 Machine:0: unit.deploy INFO: Started service unit wordpress/0 This is the result for the status command (with verbose flag): ~$ juju -v status 2012-05-11 08:51:53,464 DEBUG Initializing juju status runtime 2012-05-11 08:51:53,625:4030(0xb7345b00):ZOO_INFO@log_env@658: Client environment:zookeeper.version=zookeeper C client 3.3.5 2012-05-11 08:51:53,625:4030(0xb7345b00):ZOO_INFO@log_env@662: Client environment:host.name=andre-ufo 2012-05-11 08:51:53,625:4030(0xb7345b00):ZOO_INFO@log_env@669: Client environment:os.name=Linux 2012-05-11 08:51:53,625:4030(0xb7345b00):ZOO_INFO@log_env@670: Client environment:os.arch=3.2.0-24-generic-pae 2012-05-11 08:51:53,625:4030(0xb7345b00):ZOO_INFO@log_env@671: Client environment:os.version=#37-Ubuntu SMP Wed Apr 25 10:47:59 UTC 2012 2012-05-11 08:51:53,626:4030(0xb7345b00):ZOO_INFO@log_env@679: Client environment:user.name=andre 2012-05-11 08:51:53,626:4030(0xb7345b00):ZOO_INFO@log_env@687: Client environment:user.home=/home/andre 2012-05-11 08:51:53,626:4030(0xb7345b00):ZOO_INFO@log_env@699: Client environment:user.dir=/home/andre 2012-05-11 08:51:53,626:4030(0xb7345b00):ZOO_INFO@zookeeper_init@727: Initiating client connection, host=192.168.122.1:41779 sessionTimeout=10000 watcher=0xb7780620 sessionId=0 sessionPasswd=<null> context=0x9242ee8 flags=0 2012-05-11 08:51:53,627:4030(0xb6b90b40):ZOO_INFO@check_events@1585: initiated connection to server [192.168.122.1:41779] 2012-05-11 08:51:53,649:4030(0xb6b90b40):ZOO_INFO@check_events@1632: session establishment complete on server [192.168.122.1:41779], sessionId=0x1373ae057d90007, negotiated timeout=10000 2012-05-11 08:51:53,651 DEBUG Environment is initialized. machines: 0: agent-state: running dns-name: localhost instance-id: local instance-state: running services: mysql: charm: cs:precise/mysql-1 relations: db: - wordpress units: mysql/0: agent-state: pending machine: 0 public-address: null wordpress: charm: cs:precise/wordpress-0 relations: db: - mysql units: wordpress/0: agent-state: pending machine: 0 public-address: null

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  • embedding LEFT OUTER JOIN within INNER JOIN

    - by user3424954
    I am having some problems with one of the question's answered in the book "SQL FOR MERE MORTALS". Here is the problem statement Here is the Database Structure Here is the answer which I am unable to comprehend Here is an answer which looks perfect to me Now the problem with the first answer I am having is: We first use LEFT OUTER JOIN for recipe class and recipes. So it selects all recipe class rows but only matching recipes. Perfecty fine as the question is demanding. Lets call this result set R. Now in the next step when we use INNER JOIN to join RecipieIngridients, it should filter out the rows from R in which Recipie ID doesn't match with the Recipe Id in Recipie Ingredients and hence filtering out the related Recipe class and recipe description also(Since it filters out the entire row of R). So this contradicts with the problem which demands all recipieID and RecipieDescription to be displayed from Recipe_Classes Table in this very step only. How can it be correct. Or Am i Missing some concept.

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  • Doubt regarding search engine/plugin(One present on the website itself)

    - by Ravi Gupta
    I am new to web development and trying to study various types of websites as case study. Right now my focus is on how search engines works for an eCommerce website. I know basic functioning for a search engine, i.e. crawl web pages, index them and the display the results using those indexes. But I got little confuse in case of an eCommerce website. Don't you think that it would be better if a search engine instead of crawling the web pages containing products, it should directly crawl the database and index the products stored in the database? And when a user search for any product, it will simply give us the rows of the table which matches the user query? If this is not the case, can someone please explain how the usual method works on eCommerce website?

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  • 1 to 1 Comparison and Ranking System

    - by David
    I'm looking to create a comparison and ranking system which allows users to view 2 items, click on the one that they feel is the better one and then get presented with 2 more random items and continue to do this until they decide to stop. In the background, I want the system to use these wins and loses to rank each item in an overall ranking table so I can then see what is #1 and what isn't. I haven't got a clue where to begin with the formula, but I image I need to log wins and loses. Any help/direction appreciated!

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