Search Results

Search found 34274 results on 1371 pages for 'mysql table'.

Page 281/1371 | < Previous Page | 277 278 279 280 281 282 283 284 285 286 287 288  | Next Page >

  • Which tools you use for development in your company?…Please be exact [closed]

    - by predrag.music
    If you are a professional php/(my/postgre/?)sql/? developer and working in a professional team ... I would like to know which tools you use for development in your company. I do not care which tool is better or worse, but "which tools you use", if it is not a TOP SECRET :) For example, these are just some of the tools i/we use (first those used most (in general)): Pen, paper lots of cofee, cola ... let me think ... mmmm ... yeah more cofee :) All kinds of books (a lots of books) OS: Win / MacOS X Server: Hosted (CentOS )/ At work Mac OS X Dev server: XAMPP / MAMP / LAMP Editor: Notepad++ IDE: Netbeans / Zend Studio / Eclipse Version Control System: Mercurial / SVN FTP: Filezilla mostly / ... Passwords: KeePass js / ajax: jQuery / pure js / jQuery UI Framework:CI / Zend / pure php Database: MySQL / Other ORM: Framework layer db (Not an ORM I know but...) / Doctrine (2) / no ORM Debugging: Xdebug (PHP) / firebug (ajax/js/html/css/...) / framework profiler (stuff) / ... (x) Dreaming: About... Thinking: Not about chaos in ? direction .... n Anything else that comes to mind n+1 Zilion other stuff i know but i can't remember ... 8 some other stuff i (don't) remember i forgot, give up, delete, lost, said to myself never again, i haven't had time stuff, have on computer stuff but can't find or don't even know i have it on my computer at least 2-3 or more times, stuff I said to myself i'll check later and never checked again for all sort of "perfectly justified" reasons (time, memory, wife :), whatever,...), ... what is the reason i'm asking this?:) 8 and beyond looking forward to see a lot of answers ?

    Read the article

  • Adding a forum to an existing site

    - by Andrew Heath
    I've got a site with ~500 registered members, 300 of which are what you'd call "active". Site data is kept in a MySQL dbase. I'd like to add a myBB forum to the site, but this question applies to any forum really. What I very much want to avoid is requiring my users to register both on the site and on the forum because my userbase is not technically literate and this would confuse a lot of them. However the forum software has its own registration, login, cookie, and password management system which naturally are different from the site's mechanics. I envision the following possibilities: install myBB into the existing database and customize the login code to unify the two systems. This would probably mean changing the site's code to use the myBB system as that would likely be less painful to refactor and wouldn't hurt future myBB upgrade ability. install myBB into separate database and write a bridging script of some sort that auto-registers existing site users with the forum if they elect to participate. Also check new forum registrations against the site's username list to prevent newcomers from taking existing names. run them fully separate and force users to re-register (easiest for ME, but least desirable for them) I would like a suggested course of action from those who have trod this path before... Thank you.

    Read the article

  • Need database selection advise

    - by jacknad
    I know this is considered a bad question since there is no correct answer, but I need to decide on a database for embedded linux (DaVinci 368 based) hardware and I've never had to produce a design with a database before. Each record will probably contain less than 1000 images with associated alpha-numeric data and the mass storage will be some kind of flash drive. Only one user needs access to the data at a time. MySQL claims to be "The world's most popular open source database" but SQLite claims to be "the most widely deployed SQL database engine in the world." Perhaps there is another that is also the best in the world? Which is easiest to use for a database newbie? Should I just flip a coin? Does it really matter which one I pick? Do I even need to use a database software package or should I roll my own? I won't need bells and whistles like sorting, but I'll probably need to delete the oldest records to make room for new ones if the storage fills up.

    Read the article

  • Handling changes to data types and entries in a database migration

    - by jandjorgensen
    I'm fully redesigning a site that indexes a number of articles with basic search functionality. The previous site was written about a decade ago, and I'm salvaging about 30,000 entries with data stored in less-than-ideal formats. While I'm moving from MSSQL to MySQL, I don't need to make any "live" changes, so this is not a production-level migration issue so much as a redesign. For instance, dates are stored the same as tags/subjects about the articles, but in strings as "YYYYMMDDd" (the lowercase d stands for "date" in the string). Essentially, before or after I move from the previous database format to a new one, I'm going to need to do a lot of replacement of individual entries. While I understand how to do operations with regular expressions in non-database issues, my database experience isn't robust enough to know the best way to handle this. What is the best (or standard) way to handle major changes like this? Is there an SQL operation I should be looking into? Please let me know if the problem isn't clear--I'm not entirely sure what kind of answer I'm looking for.

    Read the article

  • How to handle a player's level and its consequent privileges?

    - by Songo
    I'm building a game similar to Mafia Wars where a player can do tasks for his gang and gain experience and thus advancing his level. The game is built using PHP and a Mysql database. In the game I want to limit the resources allowed to player based on his level. For example: ________| (Max gold) | (Max army size) | (Max moves) | ... Level 1 | 1000 | 100 | 10 | ... Level 2 | 1500 | 200 | 20 | ... Level 3 | 3000 | 300 | 25 | ... . . . In addition certain features of the game won't be allowed until a certain level is reached such as players under Level 10 can't trade in the game market, players under Level 20 can't create alliances,...etc. The way I have modeled it is by implementing a very loooong ACL (Access Control List) with about 100 entries (an entry for each level). However, I think there may be a simpler approach to this seeing that this feature have been implemented in many games before.

    Read the article

  • (GUIDE) How to install and configure Mariadb on Ubuntu 12.10+

    - by Myh Yazid
    First of all open terminal and type this sudo apt-get install python-software-properties I recommend you to use MariaDB version 10.0.4 Alpha because when im installed it i've got no errors compare with 5.5 version. 2: Put this commands in terminal sudo apt-get install software-properties-common sudo apt-key adv --recv-keys --keyserver hkp://keyserver.ubuntu.com:80 0xcbcb082a1bb943db sudo add-apt-repository 'deb http://download.nus.edu.sg/mirror/mariadb/repo/10.0/ubuntu quantal main' If you're using other version please change the "quantal" to your ubuntu version codename eg : 13.10 saucy 13.04 raring 12.10 quantal (im using this version) 12.04 precise` 3: Type in this commands sudo apt-get update sudo apt-get install mariadb-server 4: after finished installed mariadb you need to run this sudo mysql_install_db sudo /usr/bin/mysql_secure_installation If have problem consider look at the end of this post for solution 5: You're done!! Problems solving In step 3 if you get problem, like unmet dependencies, Go to /etc/apt/preferences.d then create new file called "mariadb" Then,Consider to put the below code in the mariadb file that you just created Package: * Pin: origin <mirror-domain> Pin-Priority: 1000 In step 4 you may get 2 errors first occur when you run sudo mysql_install_db Solution : open another terminal and do this killall mysqld 2.second eror may occur when you running sudo /usr/bin/mysql_secure_installationcommand Solution : try doing this cd /etc/init.d and try run ./mysqld start if ./mysqld doesnt exists use ./mysql start as in my case That's All Thank you for reading. I wrote this based on my experience installing this.Any errors you get community here can help you if i cant..tq .

    Read the article

  • PHP not working with hosting

    - by Richard
    I have been playing with a php CMS site for someone that I am ready to deploy but am running into a couple problems that I assume to be hosting related. I have been developing and playing with it localy and deploying to a hosting environment friendly towards this specific CMS (joomla). I have recently been trying to deploy to a client's hosting and have been running in to some trouble. Any help would be greatly appreciated. I have been in contact with the clients hosting and have had them set up a mysql DB for me and enable php. Simple php was working but joomla was not able to create the config files it needed to run on this hosting. Therefore I havnt been able to successfully deploy my work. While playing around with some simple php pages I have started getting http 500 errors and now cant seem to get anywhere. This is a smaller hosting company that seems willing to work with me but I dont really know what i need to ask from them to get me working. My questions to you webmaster geniuses would be as follows: Given the situation I have described, is there anything specifically i should do to get my joomla/php site running on this hosting? What specifically should I ask my current hosting providers to do to help me get working? Thanks

    Read the article

  • Defining work days and work time

    - by user2553268
    I'm working on development of SMS parking software, and I'm stuck at one point for a month... I need to implement periods of payment (or work time, of a work day, if you will). Here's the problem: For an example, traffic wardens work from Monday to Saturday. From Monday to Friday, the work times are from 07:00 to 21:00, and on Saturday, the work time is from 07:00 to 14:00. The project request was, that the customer can pay parking by SMS unlimited, which I did, but didn't implement this logic. I started with making a table for this periods of payment, it consists of: dayofweek (INT, for use with mysql function DAYOFWEEK, to tell me which day in week is the current date), work_start and work_stop (DATETIME, for defining starting and ending the work day), but I'm unsure if I should use DATETIME, beacuse of the date, or should I use only TIME. The idea is this: If you send an SMS, at 20:50, Monday, it should be valid until 07:50, Tuesday (it's payed by the hour). Extending the time of payment, regarding the work time in week. Currently, it works with extending time by the hour without this rule. Really would use some help, or some ideas, I'm stuck with this for quite some time...

    Read the article

  • Dedicated Servers: Is one better then two for LAMP pseudo HA setup? [closed]

    - by bikedorkseattle
    Possible Duplicate: How to find web hosting that meets my requirements? I know there are zillions of commentary about hosting out there, but I haven't read much about this. Our current well known host is having too many problems, the hardware we are on it subpar, and I'm ready to leave. A day of downtime can cost as much as our monthly hosting bill. A month of bad performance is just killing us right now, user and google wise. I'm wondering about running two dedicated boxes for LAMP, one running as the primary Nginx/Apache (proxy pass), and the other as the MySQL box. Running a single box scares the bejesus out of me because who knows how long it will take anyone to fix a raid card or whatever. The idea is to set this up using some sort of failover system using pacemaker and heartbeat. If one server goes down the other can take over for the other running both web and db. There are some good articles over at Linode about this. I have a few DBs that are 1GB+ and would like to load them into memory. Because of this, I'm shying away from a Linode HA setup because for the price I could do it with two dedicated like I described. Am I mad or an idiot? What are people out there doing for pseodu high availability good performance setups under $400/month? I'm a webmaster; I do a lot of things none of it that well :)

    Read the article

  • Data Synchronization in mobile apps - multiple devices, multiple users

    - by ProgrammerNewbie
    I'm looking into building my first mobile app. One of the core features of the application is that multiple devices/users will have access to the same data -- and all of them will have CRUD rights. I believe the architecture should involve a central server where all the data is stored. The devices will use an API to interact with the server to perform its data operations (e.g. adding a record, editing a record, deleting a record). I imagine a scenario where synchronizing the data will become a problem. Assume the application should work when it is not connected to the Internet, and thus cannot communicate with this central server. So: User A is offline and edits record #100 User B is offline and edits record #100 User C is offline and deletes record #100 User C goes online (presumably, record #100 should get deleted on the server) User A and B goes online, but the records they edited no longer exist All sorts of scenarios similar to the above can come up. How is this generally handled? I plan to use MySQL, but am wondering if it's not appropriate for such a problem.

    Read the article

  • What to learn after standard C++?

    - by Luca Cerone
    I switched to C++ a few months ago, learning its syntax, the main features of the STL and what you can usually find in a "learn C++" manual. Now I would like to go further. What would be your recommendations? I would like to know what to learn next (not only about the language, but also debugging, frameworks etc. etc.) I know probably the answer depends on the specific needs of each user, so here is a list of mine: Cross Platform development Developing GUI for my programs Develop extendible software, allowing the use of plugins Use of scientific libraries Interact with databases (mainly MySQL) Having server/client functionalities (I'd like users of my programs to interact through internet.. as you might have guessed I am not a programmer by training so I might have used the wrong terms.. if so I apologize for that). Of course I know it takes time, but I would like to have a good list of references and resources to start (both books and websites are ok). Thanks a lot for your help!

    Read the article

  • Submiting a Form without Refreshing the page with jQuery and Ajax Not updating MySQL database.

    - by HEEEEEEELP
    I'm a newbie to JQuery and have a problem, when I click submit button on the form everything says registration was successful but my MYSQL database was not updated everything worked fine until I tried to add the JQuery to the picture. Can someone help me fix this problem so my database is updated? Thanks Here is the JQuery code. $(function() { $(".save-button").click(function() { var address = $("#address").val(); var address_two = $("#address_two").val(); var city_town = $("#city_town").val(); var state_province = $("#state_province").val(); var zipcode = $("#zipcode").val(); var country = $("#country").val(); var email = $("#email").val(); var dataString = 'address='+ address + '&address_two=' + address_two + '&city_town=' + city_town + '&state_province=' + state_province + '&zipcode=' + zipcode + '&country=' + country + '$email=' + email; if(address=='' || address_two=='' || city_town=='' || state_province=='' || zipcode=='' || country=='' || email=='') { $('.success').fadeOut(200).hide(); $('.error').fadeOut(200).show(); } else { $.ajax({ type: "POST", url: "http://localhost/New%20Project/home/index.php", data: dataString, success: function(){ $('.success').fadeIn(200).show(); $('.error').fadeOut(200).hide(); } }); } return false; }); }); Here is the PHP code. if (isset($_POST['contact_info_submitted'])) { // Handle the form. // Query member data from the database and ready it for display $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, contact_info.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $user_id = mysqli_real_escape_string($mysqli, htmlentities('3')); $address = mysqli_real_escape_string($mysqli, htmlentities($_POST['address'])); $address_two = mysqli_real_escape_string($mysqli, htmlentities($_POST['address_two'])); $city_town = mysqli_real_escape_string($mysqli, htmlentities($_POST['city_town'])); $state_province = mysqli_real_escape_string($mysqli, htmlentities($_POST['state_province'])); $zipcode = mysqli_real_escape_string($mysqli, htmlentities($_POST['zipcode'])); $country = mysqli_real_escape_string($mysqli, htmlentities($_POST['country'])); $email = mysqli_real_escape_string($mysqli, strip_tags($_POST['email'])); //If the table is not found add it to the database if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO contact_info (user_id, address, address_two, city_town, state_province, zipcode, country, email) VALUES ('$user_id', '$address', '$address_two', '$city_town', '$state_province', '$zipcode', '$country', '$email')"); } //If the table is in the database update each field when needed if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE contact_info SET address = '$address', address_two = '$address_two', city_town = '$city_town', state_province = '$state_province', zipcode = '$zipcode', country = '$country', email = '$email' WHERE user_id = '$user_id'"); } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } } Here is the XHTML code. <form method="post" action="index.php"> <fieldset> <ul> <li><label for="address">Address 1: </label><input type="text" name="address" id="address" size="25" class="input-size" value="<?php if (isset($_POST['address'])) { echo $_POST['address']; } else if(!empty($address)) { echo $address; } ?>" /></li> <li><label for="address_two">Address 2: </label><input type="text" name="address_two" id="address_two" size="25" class="input-size" value="<?php if (isset($_POST['address_two'])) { echo $_POST['address_two']; } else if(!empty($address_two)) { echo $address_two; } ?>" /></li> <li><label for="city_town">City/Town: </label><input type="text" name="city_town" id="city_town" size="25" class="input-size" value="<?php if (isset($_POST['city_town'])) { echo $_POST['city_town']; } else if(!empty($city_town)) { echo $city_town; } ?>" /></li> <li><label for="state_province">State/Province: </label> <?php echo '<select name="state_province" id="state_province">' . "\n"; foreach($state_options as $option) { if ($option == $state_province) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="zipcode">Zip/Post Code: </label><input type="text" name="zipcode" id="zipcode" size="5" class="input-size" value="<?php if (isset($_POST['zipcode'])) { echo $_POST['zipcode']; } else if(!empty($zipcode)) { echo $zipcode; } ?>" /></li> <li><label for="country">Country: </label> <?php echo '<select name="country" id="country">' . "\n"; foreach($countries as $option) { if ($option == $country) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else if($option == "-------------") { echo '<option value="' . $option . '" disabled="disabled">' . $option . '</option>'; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="email">Email Address: </label><input type="text" name="email" id="email" size="25" class="input-size" value="<?php if (isset($_POST['email'])) { echo $_POST['email']; } else if(!empty($email)) { echo $email; } ?>" /><br /><span>We don't spam or share your email with third parties. We respect your privacy.</span></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="contact_info_submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

    Read the article

  • ODI 11g – Oracle Multi Table Insert

    - by David Allan
    With the IKM Oracle Multi Table Insert you can generate Oracle specific DML for inserting into multiple target tables from a single query result – without reprocessing the query or staging its result. When designing this to exploit the IKM you must split the problem into the reusable parts – the select part goes in one interface (I named SELECT_PART), then each target goes in a separate interface (INSERT_SPECIAL and INSERT_REGULAR). So for my statement below… /*INSERT_SPECIAL interface */ insert  all when 1=1 And (INCOME_LEVEL > 250000) then into SCOTT.CUSTOMERS_NEW (ID, NAME, GENDER, BIRTH_DATE, MARITAL_STATUS, INCOME_LEVEL, CREDIT_LIMIT, EMAIL, USER_CREATED, DATE_CREATED, USER_MODIFIED, DATE_MODIFIED) values (ID, NAME, GENDER, BIRTH_DATE, MARITAL_STATUS, INCOME_LEVEL, CREDIT_LIMIT, EMAIL, USER_CREATED, DATE_CREATED, USER_MODIFIED, DATE_MODIFIED) /* INSERT_REGULAR interface */ when 1=1  then into SCOTT.CUSTOMERS_SPECIAL (ID, NAME, GENDER, BIRTH_DATE, MARITAL_STATUS, INCOME_LEVEL, CREDIT_LIMIT, EMAIL, USER_CREATED, DATE_CREATED, USER_MODIFIED, DATE_MODIFIED) values (ID, NAME, GENDER, BIRTH_DATE, MARITAL_STATUS, INCOME_LEVEL, CREDIT_LIMIT, EMAIL, USER_CREATED, DATE_CREATED, USER_MODIFIED, DATE_MODIFIED) /*SELECT*PART interface */ select        CUSTOMERS.EMAIL EMAIL,     CUSTOMERS.CREDIT_LIMIT CREDIT_LIMIT,     UPPER(CUSTOMERS.NAME) NAME,     CUSTOMERS.USER_MODIFIED USER_MODIFIED,     CUSTOMERS.DATE_MODIFIED DATE_MODIFIED,     CUSTOMERS.BIRTH_DATE BIRTH_DATE,     CUSTOMERS.MARITAL_STATUS MARITAL_STATUS,     CUSTOMERS.ID ID,     CUSTOMERS.USER_CREATED USER_CREATED,     CUSTOMERS.GENDER GENDER,     CUSTOMERS.DATE_CREATED DATE_CREATED,     CUSTOMERS.INCOME_LEVEL INCOME_LEVEL from    SCOTT.CUSTOMERS   CUSTOMERS where    (1=1) Firstly I create a SELECT_PART temporary interface for the query to be reused and in the IKM assignment I state that it is defining the query, it is not a target and it should not be executed. Then in my INSERT_SPECIAL interface loading a target with a filter, I set define query to false, then set true for the target table and execute to false. This interface uses the SELECT_PART query definition interface as a source. Finally in my final interface loading another target I set define query to false again, set target table to true and execute to true – this is the go run it indicator! To coordinate the statement construction you will need to create a package with the select and insert statements. With 11g you can now execute the package in simulation mode and preview the generated code including the SQL statements. Hopefully this helps shed some light on how you can leverage the Oracle MTI statement. A similar IKM exists for Teradata. The ODI IKM Teradata Multi Statement supports this multi statement request in 11g, here is an extract from the paper at www.teradata.com/white-papers/born-to-be-parallel-eb3053/ Teradata Database offers an SQL extension called a Multi-Statement Request that allows several distinct SQL statements to be bundled together and sent to the optimizer as if they were one. Teradata Database will attempt to execute these SQL statements in parallel. When this feature is used, any sub-expressions that the different SQL statements have in common will be executed once, and the results shared among them. It works in the same way as the ODI MTI IKM, multiple interfaces orchestrated in a package, each interface contributes some SQL, the last interface in the chain executes the multi statement.

    Read the article

  • Need Advice on building the database. all in one table or split?

    - by Ibrahim Azhar Armar
    hello, i am developing an application for a real-estate company. the problem i am facing is about implementing the database. however i am just confused on which way to adopt i would appreciate if you could help me out in reasoning the database implementation. here is my situation. a) i have to store the property details in the database. b) the properties have approximately 4-5 categories to which it will belong for ex : resedential, commnercial, industrial etc. c) now the categories have sub-categories. for example. a residential category will have sub category such as. Apartment / Independent House / Villa / Farm House/ Studio Apartment etc. and hence same way commercial and industrial or agricultural will too have sub-categories. d) each sub-categories will have to store the different values. like a resident will have features like Bedrooms/ kitchens / Hall / bathroom etc. the features depends on the sub categories. for an example on how i would want to implement my application you can have a look at this site. http://www.magicbricks.com/bricks/postProperty.html i could possibly think of the solution like this. a) create four to five tables depending upon the categories which will be existing(the problem is categories might increase in the future). b) create different tables for all the features, location, price, description and merge the common property table into one. for example all the property will have the common entity such as location, total area, etc. what would you advice for me given the current situation. thank you

    Read the article

  • SQL: How to select rows from a table while ignoring the duplicate field values?

    - by Maxxon
    How to select rows from a table while ignoring the duplicate field values? Here is an example: id user_id message 1 Adam "Adam is here." 2 Peter "Hi there this is Peter." 3 Peter "I am getting sick." 4 Josh "Oh, snap. I'm on a boat!" 5 Tom "This show is great." 6 Laura "Textmate rocks." What i want to achive is to select the recently active users from my db. Let's say i want to select the 5 recently active users. The problem is, that the following script selects Peter twice. mysql_query("SELECT * FROM messages ORDER BY id DESC LIMIT 5 "); What i want is to skip the row when it gets again to Peter, and select the next result, in our case Adam. So i don't want to show my visitors that the recently active users were Laura, Tom, Josh, Peter, and Peter again. That does not make any sense, instead i want to show them this way: Laura, Tom, Josh, Peter, (skipping Peter) and Adam. Is there an SQL command i can use for this problem?

    Read the article

  • Suggest the best options to me to design the dynamic web interface using PHP MYSQL and AJAX

    - by Krishna
    Hello, I am designing a web interface for a company. I am describing the company's profile: company is currently having 5 branches and planning to extend their branches all over the country. it is an insurance surveying company. they are dealing with 6 Categories in the insurance domain, vide .. Engineering Fire Marine Motor Miscellaneous Risk Inspection and branches named as b1, b2, b3, b4, b5 and Extending. and finally they have contract with 22 companies. For each claim they are assign a unique ID. like contractcompany/category/serialno Ex: take a contracted company names as xxx, sss, zzz. xxx/Engineering/001 sss/Engineering/001 . . . xxx/Enginnering/002 sss/Engineering/002 . . . xxx/Fire/001 sss/Fire/001 . . . xxx/Fire/002 . . . xxx/Fire/002 . . . and so on..... by this way they issue the unique ID for each claim. Finally what i want is developing the interface with PHP mysql and ajax auto generating the unique id for each claim. store full details of the claims with reference to unique id. show all claims in one page, and they can view by branch wise and category wise. send monthly Report (All claims they have given and status of claims) to contract companies. give access to contracted companies, but they can view only their respective claims. Each claim has its own documents. So they can be uploaded by own company users or administrator. these files are associated with unique ID. contracted companies can view files. Give access to branches to enter new claims and update old claims. Administrator can create, update and delete all the claims and their details. Only administrator can grant new users (own company branches / contracted companies) Finally the the panel is completely database driven. Could any body can help. Thanks in advance Kindly do the needful and oblige Thanks and Regards Krishna. P [email protected]

    Read the article

  • MySQL & PHP - select/option lists and showing data to users that still allows me to generate queries

    - by Andrew Heath
    Sorry for the unclear title, an example will clear things up: TABLE: Scenario_victories ID scenid timestamp userid side playdate 1 RtBr001 2010-03-15 17:13:36 7 1 2010-03-10 2 RtBr001 2010-03-15 17:13:36 7 1 2010-03-10 3 RtBr001 2010-03-15 17:13:51 7 2 2010-03-10 ID and timestamp are auto-insertions by the database when the other 4 fields are added. The first thing to note is that a user can record multiple playings of the same scenario (scenid) on the same date (playdate) possibly with the same outcome (side = winner). Hence the need for the unique ID and timestamps for good measure. Now, on their user page, I'm displaying their recorded play history in a <select><option>... list form with 2 buttons at the end - Delete Record and Go to Scenario My script takes the scenid and after hitting a few other tables returns with something more user-friendly like: (playdate) (from scenid) (from side) ######################################################### # 2010-03-10 Road to Berlin #1 -- Germany, Hungary won # # 2010-03-10 Road to Berlin #1 -- Germany, Hungary won # # 2010-03-10 Road to Berlin #1 -- Soviet Union won # ######################################################### [Delete Record] [Go To Scenario] in HTML: <select name="history" size=3> <option>2010-03-10 Road to Berlin #1 -- Germany, Hungary won</option> <option>2010-03-10 Road to Berlin #1 -- Germany, Hungary won</option> <option>2010-03-10 Road to Berlin #1 -- Soviet Union won</option> </select> Now, if you were to highlight the first record and click Go to Scenario there is enough information there for me to parse it and produce the exact scenario you want to see. However, if you were to select Delete Record there is not - I have the playdate and I can parse the scenid and side from what's listed, but in this example all three records would have the same result. I appear to have painted myself into a corner. Does anyone have a suggestion as to how I can get some unique identifying data (ID and/or timestamp) to ride along on this form without showing it to the user? PHP-only please, I must be NoScript compliant!

    Read the article

  • Converting table columns to key value pairs

    - by TomD1
    I am writing a PL/SQL procedure that loads some data from Schema A into Schema B. They are both very different schemas and I can't change the structure of Schema B. Columns in various tables in Schema A (joined together in a view) need to be inserted into Schema B as key=value pairs in 2 columns in a table, each on a separate row. For example, an employee's first name might be present as employee.firstname in Schema A, but would need to be entered in Schema B as: id=>1, key=>'A123', value=>'Smith' There are almost 100 keys, with the potential for more to be added in future. This means I don't really want to hardcode any of these keys. Sample code: create table schema_a_employees ( emp_id number(8,0), firstname varchar2(50), surname varchar2(50) ); insert into schema_a_employees values ( 1, 'James', 'Smith' ); insert into schema_a_employees values ( 2, 'Fred', 'Jones' ); create table schema_b_values ( emp_id number(8,0), the_key varchar2(5), the_value varchar2(200) ); I thought an elegant solution would most likely involve a lookup table to determine what value to insert for each key, and doesn't involve effectively hardcoding dozens of similar statements like.... insert into schema_b_values ( 1, 'A123', v_firstname ); insert into schema_b_values ( 1, 'B123', v_surname ); What I'd like to be able to do is have a local lookup table in Schema A that lists all the keys from Schema B, along with a column that gives the name of the column in the table in Schema A that should be used to populate, e.g. key "A123" in Schema B should be populated with the value of the column "firstname" in Schema A, e.g. create table schema_a_lookup ( the_key varchar2(5), the_local_field_name varchar2(50) ); insert into schema_a_lookup values ( 'A123', 'firstname' ); insert into schema_a_lookup values ( 'B123', 'surname' ); But I'm not sure how I could dynamically use values from the lookup table to tell Oracle which columns to use. So my question is, is there an elegant solution to populate schema_b_values table with the data from schema_a_employees without hardcoding for every possible key (i.e. A123, B123, etc)? Cheers.

    Read the article

  • How do you update table row background color in IE using Javascript/CSS ?

    - by giulio
    I have a table that i want to "highlight" during onmouseover/onmouseout. I already know this is required in IE but not in other browsers. I have managed to detect the events triggering and this TR tag effectively works. (Note that the originating class "contentTableRow" doesn't seem to be causing any issues.) class="contentTableRow" onclick="openForm('SomeID');" onmouseover="highlight('someRowID', true);" onmouseout="highlight('someRowID', false);" id="someRowID" All is fine and dandy, the "highlight" function fires and actually sets the appropriate class. It's just that IE won't process the CSS class name change. Here is a snippet of the CSS I am using to make the change. .HighlightOn { cursor:pointer; background-color: #D1DFFF; } .HighlightOff { background-color: #E1EEFE; } I can see that the Class names are getting updated when I debug it, and also check it in Firebug. But it seems that IE doesn't like this usage of classes with a TR tag.. Is it the way I am structuring the class for Tables ? Any advice ?

    Read the article

  • Why do Firefox and Opera ignore max-width inside of display: table-cell?

    - by brad
    The following code displays correctly in Chrome or IE (the image is 200px wide). In Firefox and Opera the max-width style is ignored completely. Why does this happen and is there a good work around? Also, which way is most standards compliant? Note One possible work around for this particular situation is to set max-width to 200px. However, this is a rather contrived example. I'm looking for a strategy for a variable width container. <!doctype html> <html> <head> <style> div { display: table-cell; padding: 15px; width: 200px; } div img { max-width: 100%; } </style> </head> <body> <div> <img src="http://farm4.static.flickr.com/3352/4644534211_b9c887b979.jpg" /> <p> Lorem ipsum dolor sit amet, consectetur adipiscing elit. Donec facilisis ante, facilisis posuere ligula feugiat ut. Fusce hendrerit vehicula congue. at ligula dolor. Lorem ipsum dolor sit amet, consectetur adipiscing elit. leo metus, aliquam eget convallis eget, molestie at massa. </p> </div> </body> </html> [Update] As stated by mVChr below, the w3.org spec states that max-width does not apply to inline elements. I've tried using div img { max-width: 100%; display: block; }, but it does not seem to correct the issue.

    Read the article

  • Using JQuery to insert new cells in a table row?

    - by Michael Smith
    I know that JQuery is a very powerful library and was just wondering if it had the following capability that I really need. Lets say I need to insert new cells into a table row, I know how to do this basic task, but I need to insert my cells in a highly unusual way due to some of the requirements that are needed for the new cells. I need to be able to insert cells a certain distance into the row, For example, if a row was 1000pixels wide, is there a feature in JQuery that would allow me to insert the cell 250pixels into the row and have a cell width of 50pixels and insert another cell 500pixels into the row with a cell width of 100pixels. I know how to set a cells width using JQuery, just not distance into a row. The values wont ever be the exact same as above though because they are actually read from a database, so for example, one cell would have the following values: CELL_01 $start=100; $finish=150; the above would mean a new cell is needed that needs to be inserted 100pixels into the row and has a width of 50pixels, I just cant seem to find a way to implement this feature into my application. How could I accomplish this task? Sorry for such a strange question, but i just cant seem to get this working. Thanks!

    Read the article

  • Not getting the right expected output for my Mysql Query?

    - by user1878107
    i've 4 tables as shown below doctors id name ------------ 1 Mathew 2 Praveen 3 Rosie 4 Arjun 5 Denis doctors_appointments id doctors_id patient_name contact date status -------------------------------------------------------------------------------------- 1 5 Nidhin 9876543210 2012-12-10 15:39:41 Registered 2 5 Sunny 9876543210 2012-12-18 15:39:48 Registered 3 5 Mani 9876543210 2012-12-12 15:39:57 Registered 4 2 John 9876543210 2012-12-24 15:40:09 Registered 5 4 Raj 9876543210 2012-12-05 15:41:57 Registered 6 3 Samuel 9876543210 2012-12-14 15:41:33 Registered 7 2 Louis 9876543210 2012-12-24 15:40:23 Registered 8 1 Federick 9876543210 2012-12-28 15:41:05 Registered 9 2 Sam 9876543210 2012-12-12 15:40:38 Registered 10 4 Sita 9876543210 2012-12-12 15:41:00 Registered doctors_dutyplan id doctor_id weeks time no_of_patients ------------------------------------------------------------------ 1 1 3,6,7 9:00am-1:00pm 10 2 2 3,4,5 1:00pm-4:00pm 7 3 3 3,6,7 10:00am-2:00pm 10 4 4 3,4,5,6 8:30am-12:30pm 12 5 5 3,4,5,6,7 9:00am-4:00pm 30 emp_leave id empid leavedate -------------------------------- 1 2 2012-12-05 14:42:36 2 2 2012-12-03 14:42:59 3 3 2012-12-03 14:43:06 4 3 2012-12-06 14:43:14 5 5 2012-12-04 14:43:24 My task is to find all the days in a month in which the doctor is available excluding the leave dates. My query what is wrote is given below: SELECT DATE_ADD( '2012-12-01', INTERVAL ROW DAY ) AS Date, ROW +1 AS DayOfMonth FROM ( SELECT @row := @row +1 AS ROW FROM ( SELECT 0 UNION ALL SELECT 1 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 )t1, ( SELECT 0 UNION ALL SELECT 1 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 )t2, ( SELECT @row := -1 )t3 LIMIT 31 )b WHERE DATE_ADD( '2012-12-01', INTERVAL ROW DAY ) BETWEEN '2012-12-01' AND '2012-12-31' AND DAYOFWEEK( DATE_ADD( '2012-12-01', INTERVAL ROW DAY ) ) =2 AND DATE_ADD( '2012-12-01', INTERVAL ROW DAY ) NOT IN ( SELECT DATE_FORMAT( l.leavedate, '%Y-%m-%d' ) AS date FROM doctors_dutyplan d LEFT JOIN emp_leave AS l ON d.doctor_id = l.empid WHERE doctor_id =2 ) This works fine for all doctors who took any leave in a particular day in a month (here in the example it is Decemeber 2012). and the result is shown below: Date DayOfMonth ----------------------- 2012-12-10 10 2012-12-17 17 2012-12-24 24 2012-12-31 31 But on the other hand for the doctors who did'nt took any leave , for that my query is showing empty table, example for the doctor Mathew whose id is 1, my query returns an empty result can anyone please tell a solution for this problem. Thanks in advance.

    Read the article

  • Grouping Rows with Client Side HTML Table Sorting

    - by Alan Storm
    Are there any existing table sorting libraries, or is there a way to configure tablesorter, to sort every two rows? Alternatly, is there a better way to semantially express my table such that standard row sorting will work. I have an html table that looks something like this <table> <thead> <tr> <th>Header 1</th> <th>Header 2</th> </tr> </thead> <tbody> <tr> <td>Some Data: 1</td> <td>Some More Data:1 </td> </tr> <tr> <td colspan="2">Some text about the above data that puts it in context and visually spans under both of the cells above so as not to create a weird looking table</td> </tr> <tr> <td>Some Data: 2</td> <td>Some More Data: 2</td> </tr> <tr> <td colspan="2">Some text about the above data 2 set that puts it in context and visually spans under both of the cells above so as not to create a weird looking table</td> </tr> </tbody> </table> I'm looking for a way to sort the table such that the table is sorted by the data rows, but the row with the colspan travels with its data and is not sorted separately.

    Read the article

  • PHP / Zend Framework: Force prepend table name to column name in result array?

    - by Brian Lacy
    I am using Zend_Db_Select currently to retrieve hierarchical data from several joined tables. I need to be able to convert this easily into an array. Short of using a switch statement and listing out all the columns individually in order to sort the data, my thought was that if I could get the table names auto-prepended to the keys in the result array, that would solve my problem. So considering the following (assembled) SQL: SELECT user.*, contact.* FROM user INNER JOIN contact ON contact.user_id = user.user_id I would normally get a result array like this: [username] => 'bob', [contact_id] => 5, [user_id] => 2, [firstname] => 'bob', [lastname] => 'larsen' But instead I want this: [user.user_id] => 2, [user.username] => 'bob', [contact.contact_id] => 5, [contact.firstname] => 'bob', [contact.lastname] => 'larsen' Does anyone have an idea how to achieve this? Thanks!

    Read the article

  • How to store date into Mysql database with play framework in scala?

    - by Rahul Kulhari
    I am working with play framework with scala and what am i doing : login page to login into web app sign up page to register into web app after login i want to store all databases values to user what i want to do: when user register for web app then i want to store user values into database with current time and date but my form is giving error. error: List(FormError(dates,error.required,List())),None) controllers/Application.scala object Application extends Controller { val ta:Form[Keyword] = Form( mapping( "id" -> ignored(NotAssigned:Pk[Long]), "word" -> nonEmptyText, "blog" -> nonEmptyText, "cat" -> nonEmptyText, "score"-> of[Long], "summaryId"-> nonEmptyText, "dates" -> date("yyyy-MM-dd HH:mm:ss") )(Keyword.apply)(Keyword.unapply) ) def index = Action { Ok(html.index(ta)); } def newTask= Action { implicit request => ta.bindFromRequest.fold( errors => {println(errors) BadRequest(html.index(errors))}, keywo => { Keyword.create(keywo) Ok(views.html.data(Keyword.all())) } ) } models/keyword.scala case class Keyword(id: Pk[Long],word: String,blog: String,cat: String,score: Long, summaryId: String,dates: Date ) object Keyword { val keyw = { get[Pk[Long]]("keyword.id") ~ get[String]("keyword.word")~ get[String]("keyword.blog")~ get[String]("keyword.cat")~ get[Long]("keyword.score") ~ get[String]("keyword.summaryId")~ get[Date]("keyword.dates") map { case id~blog~cat~word~score~summaryId~dates => Keyword(id,word,blog,cat,score, summaryId,dates) } } def all(): List[Keyword] = DB.withConnection { implicit c => SQL("select * from keyword").as(Keyword.keyw *) } def create(key: Keyword){DB.withConnection{implicit c=> SQL("insert into keyword values({word},{blog}, {cat}, {score},{summaryId},{dates})").on('word-> key.word,'blog->key.blog, 'cat -> key.cat, 'score-> key.score, 'summaryId -> key.summaryId, 'dates->new Date()).executeUpdate } } views/index.scala.html @(taskForm: Form[Keyword]) @import helper._ @main("Todo list") { @form(routes.Application.newTask) { @inputText(taskForm("word")) @inputText(taskForm("blog")) @inputText(taskForm("cat")) @inputText(taskForm("score")) @inputText(taskForm("summaryId")) <input type="submit"> <a href="">Go Back</a> } } please give me some idea to store date into mysql databse and date is not a field of form

    Read the article

< Previous Page | 277 278 279 280 281 282 283 284 285 286 287 288  | Next Page >