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  • squid3 auth thru samba using ntlm to AD doesn't work

    - by derty
    some users here are spending to much time exploring the WWW. So big boss whats to get this under control. We use a squid3 just for some security reason and chace benefits. and now i'm trying to set up a new proxy on a different server (Debian 6) Permissions are defined in AC and the squid3 should get the auth thru samba/winbind by using the ntlm protocol. but i'll get all the time Access, denited. it only works by using LDAP but thats not the way i need it. here some log and confs squid access.log 1326878095.784 1 192.168.15.27 TCP_DENIED/407 4049 GET http://at.msn.com/? -NONE/- text/html 1326878095.791 1 192.168.15.27 TCP_DENIED/407 4294 GET http://at.msn.com/? - NONE/- text/html 1326878095.803 9 192.168.15.27 TCP_DENIED/403 4028 GET http://at.msn.com/? kavan NONE/- text/html 1326878095.848 0 192.168.15.27 TCP_DENIED/403 3881 GET http://www.squid-cache.org/Artwork/SN.png kavan NONE/- text/html 1326878100.279 0 192.168.15.27 TCP_DENIED/403 3735 GET http://www.google.at/ kavan NONE/- text/html 1326878100.296 0 192.168.15.27 TCP_DENIED/403 3870 GET http://www.squid-cache.org/Artwork/SN.png kavan NONE/- text/html 1326878155.700 0 192.168.15.27 TCP_DENIED/407 4072 GET http://ie9cvlist.ie.microsoft.com/IE9CompatViewList.xml - NONE/- text/html 1326878155.705 2 192.168.15.27 TCP_DENIED/407 4317 GET http://ie9cvlist.ie.microsoft.com/IE9CompatViewList.xml - NONE/- text/html 1326878155.709 3 192.168.15.27 TCP_DENIED/403 4026 GET http://ie9cvlist.ie.microsoft.com/IE9CompatViewList.xml kavan NONE/- text/html squid chace 2012/01/18 10:12:49| Creating Swap Directories 2012/01/18 10:12:49| Starting Squid Cache version 3.1.6 for x86_64-pc-linux-gnu... 2012/01/18 10:12:49| Process ID 17236 2012/01/18 10:12:49| With 65535 file descriptors available 2012/01/18 10:12:49| Initializing IP Cache... 2012/01/18 10:12:49| DNS Socket created at [::], FD 7 2012/01/18 10:12:49| DNS Socket created at 0.0.0.0, FD 8 2012/01/18 10:12:49| Adding nameserver 192.168.15.2 from /etc/resolv.conf 2012/01/18 10:12:49| Adding nameserver 192.168.15.19 from /etc/resolv.conf 2012/01/18 10:12:49| Adding nameserver 192.168.15.1 from /etc/resolv.conf 2012/01/18 10:12:49| Adding domain schoenbrunn.local from /etc/resolv.conf 2012/01/18 10:12:49| helperOpenServers: Starting 5/5 'squid_ldap_auth' processes 2012/01/18 10:12:49| helperOpenServers: Starting 10/10 'ntlm_auth' processes 2012/01/18 10:12:49| helperOpenServers: Starting 10/10 'squid_kerb_auth' processes 2012/01/18 10:12:49| squid_kerb_auth: INFO: Starting version 1.0.5 2012/01/18 10:12:49| squid_kerb_auth: INFO: Starting version 1.0.5 2012/01/18 10:12:49| squid_kerb_auth: INFO: Starting version 1.0.5 2012/01/18 10:12:49| squid_kerb_auth: INFO: Starting version 1.0.5 2012/01/18 10:12:49| squid_kerb_auth: INFO: Starting version 1.0.5 2012/01/18 10:12:49| squid_kerb_auth: INFO: Starting version 1.0.5 2012/01/18 10:12:49| squid_kerb_auth: INFO: Starting version 1.0.5 2012/01/18 10:12:49| squid_kerb_auth: INFO: Starting version 1.0.5 2012/01/18 10:12:49| helperOpenServers: Starting 5/5 'squid_ldap_group' processes 2012/01/18 10:12:49| squid_kerb_auth: INFO: Starting version 1.0.5 2012/01/18 10:12:49| squid_kerb_auth: INFO: Starting version 1.0.5 2012/01/18 10:12:49| Unlinkd pipe opened on FD 73 2012/01/18 10:12:49| Local cache digest enabled; rebuild/rewrite every 3600/3600 sec 2012/01/18 10:12:49| Store logging disabled 2012/01/18 10:12:49| Swap maxSize 0 + 262144 KB, estimated 20164 objects 2012/01/18 10:12:49| Target number of buckets: 1008 2012/01/18 10:12:49| Using 8192 Store buckets 2012/01/18 10:12:49| Max Mem size: 262144 KB 2012/01/18 10:12:49| Max Swap size: 0 KB 2012/01/18 10:12:49| Using Least Load store dir selection 2012/01/18 10:12:49| Set Current Directory to /var/spool/squid3 2012/01/18 10:12:49| Loaded Icons. 2012/01/18 10:12:49| Accepting HTTP connections at [::]:3128, FD 74. 2012/01/18 10:12:49| HTCP Disabled. 2012/01/18 10:12:49| Squid modules loaded: 0 2012/01/18 10:12:49| Adaptation support is off. 2012/01/18 10:12:49| Ready to serve requests. 2012/01/18 10:12:50| storeLateRelease: released 0 objects smb.conf # Domain Authntication Settings workgroup = <WORKGROUP> security = ads password server = <DOMAINNAME>.LOCAL realm = <DOMAINNAME>.LOCAL ldap ssl = no # logging log level = 5 max log size = 50 # logs split per machine log file = /var/log/samba/%m.log # max 50KB per log file, then rotate ; max log size = 50 # User settings username map = /etc/samba/smbusers idmap uid = 10000-20000000 idmap gid = 10000-20000000 idmap backend = ad ; template primary group = <ad group> template shell = /sbin/nologin # Winbind Settings winbind separator = + winbind enum users = Yes winbind enum groups = Yes winbind netsted groups = Yes winbind nested groups = Yes winbind cache time = 10 winbind use default domain = Yes #Other Globals unix charset = LOCALE server string = <SERVERNAME> load printers = no printing = cups cups options = raw ; printcap name = /etc/printcap #obtain list of printers automatically on SystemV ; printcap name = lpstat ; printing = cups squid.conf auth_param ntlm program /usr/bin/ntlm_auth --require-membership-of=<DOMAINNAME>\\INTERNETZ --helper-protocol=squid-2.5-ntlmssp auth_param ntlm children 10 auth_param basic program /usr/lib/squid3/squid_ldap_auth -R -b "dc=<dcname>,dc=local" -D "cn=administrator,cn=Users,dc=<domainname>,dc=local" -w "******" -f sAMAccountName=%s -h 192.168.15.19:3268 auth_param basic realm "Proxy Authentifizierung. Bitte geben Sie Ihren Benutzername und Ihr Passwort ein!" #means insert you PW in an other language - # external_acl_type InetGroup %LOGIN /usr/lib/squid3/squid_ldap_group -R -b "dc=<domainname>,dc=local" -D "cn=administrator,cn=Users,dc=<domainname>,dc=local" -w "******" -f "(&(objectclass=person)(sAMAccountName=%v) (memberof=cn=%a,cn=internetz,dc=<domainname>,dc=local))" -h 192.168.15.19:3268 auth_param negotiate program /usr/lib/squid3/squid_kerb_auth -d auth_param negotiate children 10 auth_param negotiate keep_alive on acl localnet proxy_auth REQUIRED acl InetAccess external InetGroup Internetz http_access allow InetAccess http_access deny all acl auth proxy_auth REQUIRED http_access allow auth and a very suspicious is that by adding the proxy server to the Domain i see 2 new entries in the PC one with the original computer-name leopoldine and one with leopoldine CNF:f8efa4c4-ff0e-4217-939d-f1523b43464d ?!? I tried a lot, really... but i stuck on this problem... i actually i even reinstalled all dependent programs and reconfigured them from default. Group exists and has me in it. Firefox running on the old proxy and i use IE for testing the new one. But i'll get all the time Access-Denited and to be honest i'm quite a beginner, so please don't be to prude. I'll interested in improving, i'll get the information we need to fix this but i started working 2 month ago and got only 1 1/2 year's training and not a single sec. in linux ;)

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  • Silverlight Tree View with Multiple Levels

    - by psheriff
    There are many examples of the Silverlight Tree View that you will find on the web, however, most of them only show you how to go to two levels. What if you have more than two levels? This is where understanding exactly how the Hierarchical Data Templates works is vital. In this blog post, I am going to break down how these templates work so you can really understand what is going on underneath the hood. To start, let’s look at the typical two-level Silverlight Tree View that has been hard coded with the values shown below: <sdk:TreeView>  <sdk:TreeViewItem Header="Managers">    <TextBlock Text="Michael" />    <TextBlock Text="Paul" />  </sdk:TreeViewItem>  <sdk:TreeViewItem Header="Supervisors">    <TextBlock Text="John" />    <TextBlock Text="Tim" />    <TextBlock Text="David" />  </sdk:TreeViewItem></sdk:TreeView> Figure 1 shows you how this tree view looks when you run the Silverlight application. Figure 1: A hard-coded, two level Tree View. Next, let’s create three classes to mimic the hard-coded Tree View shown above. First, you need an Employee class and an EmployeeType class. The Employee class simply has one property called Name. The constructor is created to accept a “name” argument that you can use to set the Name property when you create an Employee object. public class Employee{  public Employee(string name)  {    Name = name;  }   public string Name { get; set; }} Finally you create an EmployeeType class. This class has one property called EmpType and contains a generic List<> collection of Employee objects. The property that holds the collection is called Employees. public class EmployeeType{  public EmployeeType(string empType)  {    EmpType = empType;    Employees = new List<Employee>();  }   public string EmpType { get; set; }  public List<Employee> Employees { get; set; }} Finally we have a collection class called EmployeeTypes created using the generic List<> class. It is in the constructor for this class where you will build the collection of EmployeeTypes and fill it with Employee objects: public class EmployeeTypes : List<EmployeeType>{  public EmployeeTypes()  {    EmployeeType type;            type = new EmployeeType("Manager");    type.Employees.Add(new Employee("Michael"));    type.Employees.Add(new Employee("Paul"));    this.Add(type);     type = new EmployeeType("Project Managers");    type.Employees.Add(new Employee("Tim"));    type.Employees.Add(new Employee("John"));    type.Employees.Add(new Employee("David"));    this.Add(type);  }} You now have a data hierarchy in memory (Figure 2) which is what the Tree View control expects to receive as its data source. Figure 2: A hierachial data structure of Employee Types containing a collection of Employee objects. To connect up this hierarchy of data to your Tree View you create an instance of the EmployeeTypes class in XAML as shown in line 13 of Figure 3. The key assigned to this object is “empTypes”. This key is used as the source of data to the entire Tree View by setting the ItemsSource property as shown in Figure 3, Callout #1. Figure 3: You need to start from the bottom up when laying out your templates for a Tree View. The ItemsSource property of the Tree View control is used as the data source in the Hierarchical Data Template with the key of employeeTypeTemplate. In this case there is only one Hierarchical Data Template, so any data you wish to display within that template comes from the collection of Employee Types. The TextBlock control in line 20 uses the EmpType property of the EmployeeType class. You specify the name of the Hierarchical Data Template to use in the ItemTemplate property of the Tree View (Callout #2). For the second (and last) level of the Tree View control you use a normal <DataTemplate> with the name of employeeTemplate (line 14). The Hierarchical Data Template in lines 17-21 sets its ItemTemplate property to the key name of employeeTemplate (Line 19 connects to Line 14). The source of the data for the <DataTemplate> needs to be a property of the EmployeeTypes collection used in the Hierarchical Data Template. In this case that is the Employees property. In the Employees property there is a “Name” property of the Employee class that is used to display the employee name in the second level of the Tree View (Line 15). What is important here is that your lowest level in your Tree View is expressed in a <DataTemplate> and should be listed first in your Resources section. The next level up in your Tree View should be a <HierarchicalDataTemplate> which has its ItemTemplate property set to the key name of the <DataTemplate> and the ItemsSource property set to the data you wish to display in the <DataTemplate>. The Tree View control should have its ItemsSource property set to the data you wish to display in the <HierarchicalDataTemplate> and its ItemTemplate property set to the key name of the <HierarchicalDataTemplate> object. It is in this way that you get the Tree View to display all levels of your hierarchical data structure. Three Levels in a Tree View Now let’s expand upon this concept and use three levels in our Tree View (Figure 4). This Tree View shows that you now have EmployeeTypes at the top of the tree, followed by a small set of employees that themselves manage employees. This means that the EmployeeType class has a collection of Employee objects. Each Employee class has a collection of Employee objects as well. Figure 4: When using 3 levels in your TreeView you will have 2 Hierarchical Data Templates and 1 Data Template. The EmployeeType class has not changed at all from our previous example. However, the Employee class now has one additional property as shown below: public class Employee{  public Employee(string name)  {    Name = name;    ManagedEmployees = new List<Employee>();  }   public string Name { get; set; }  public List<Employee> ManagedEmployees { get; set; }} The next thing that changes in our code is the EmployeeTypes class. The constructor now needs additional code to create a list of managed employees. Below is the new code. public class EmployeeTypes : List<EmployeeType>{  public EmployeeTypes()  {    EmployeeType type;    Employee emp;    Employee managed;     type = new EmployeeType("Manager");    emp = new Employee("Michael");    managed = new Employee("John");    emp.ManagedEmployees.Add(managed);    managed = new Employee("Tim");    emp.ManagedEmployees.Add(managed);    type.Employees.Add(emp);     emp = new Employee("Paul");    managed = new Employee("Michael");    emp.ManagedEmployees.Add(managed);    managed = new Employee("Sara");    emp.ManagedEmployees.Add(managed);    type.Employees.Add(emp);    this.Add(type);     type = new EmployeeType("Project Managers");    type.Employees.Add(new Employee("Tim"));    type.Employees.Add(new Employee("John"));    type.Employees.Add(new Employee("David"));    this.Add(type);  }} Now that you have all of the data built in your classes, you are now ready to hook up this three-level structure to your Tree View. Figure 5 shows the complete XAML needed to hook up your three-level Tree View. You can see in the XAML that there are now two Hierarchical Data Templates and one Data Template. Again you list the Data Template first since that is the lowest level in your Tree View. The next Hierarchical Data Template listed is the next level up from the lowest level, and finally you have a Hierarchical Data Template for the first level in your tree. You need to work your way from the bottom up when creating your Tree View hierarchy. XAML is processed from the top down, so if you attempt to reference a XAML key name that is below where you are referencing it from, you will get a runtime error. Figure 5: For three levels in a Tree View you will need two Hierarchical Data Templates and one Data Template. Each Hierarchical Data Template uses the previous template as its ItemTemplate. The ItemsSource of each Hierarchical Data Template is used to feed the data to the previous template. This is probably the most confusing part about working with the Tree View control. You are expecting the content of the current Hierarchical Data Template to use the properties set in the ItemsSource property of that template. But you need to look to the template lower down in the XAML to see the source of the data as shown in Figure 6. Figure 6: The properties you use within the Content of a template come from the ItemsSource of the next template in the resources section. Summary Understanding how to put together your hierarchy in a Tree View is simple once you understand that you need to work from the bottom up. Start with the bottom node in your Tree View and determine what that will look like and where the data will come from. You then build the next Hierarchical Data Template to feed the data to the previous template you created. You keep doing this for each level in your Tree View until you get to the last level. The data for that last Hierarchical Data Template comes from the ItemsSource in the Tree View itself. NOTE: You can download the sample code for this article by visiting my website at http://www.pdsa.com/downloads. Select “Tips & Tricks”, then select “Silverlight TreeView with Multiple Levels” from the drop down list.

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  • Ingredient Substitutes while Baking

    - by Rekha
    In our normal cooking, we substitute the vegetables for the gravies we prepare. When we start baking, we look for a good recipe. At least one or two ingredient will be missing. We do not know where to substitute what to bring same output. So we finally drop the plan of baking. Again after a month, we get the interest in baking. Again one or two lack of ingredient and that’s it. We keep on doing this for months. When I was going through the cooking blogs, I came across a site with the Ingredient Substitutes for Baking: (*) is to indicate that this substitution is ideal from personal experience. Flour Substitutes ( For 1 cup of Flour) All Purpose Flour 1/2 cup white cake flour plus 1/2 cup whole wheat flour 1 cup self-rising flour (omit using salt and baking powder if the recipe calls for it since self raising flour has it already) 1 cup plus 2 tablespoons cake flour 1/2 cup (75 grams) whole wheat flour 7/8 cup (130 grams) rice flour (starch) (do not replace all of the flour with the rice flour) 7/8 cup whole wheat Bread Flour 1 cup all purpose flour 1 cup all purpose flour plus 1 teaspoon wheat gluten (*) Cake Flour Place 2 tbsp cornstarch in 1 cup and fill the rest up with All Purpose flour (*) 1 cup all purpose flour minus 2 tablespoons Pastry flour Place 2 tbsp cornstarch in 1 cup and fill the rest up with All Purpose flour Equal parts of All purpose flour plus cake flour (*) Self-rising Flour 1½ teaspoons of baking powder plus ½ teaspoon of salt plus 1 cup of all-purpose flour. Cornstarch (1 tbsp) 2 tablespoons all-purpose flour 1 tablespoon arrowroot 4 teaspoons quick-cooking tapioca 1 tablespoon potato starch or rice starch or flour Tapioca (1 tbsp) 1 – 1/2 tablespoons all-purpose flour Cornmeal (stone ground) polenta OR corn flour (gives baked goods a lighter texture) if using cornmeal for breading,crush corn chips in a blender until they have the consistency of cornmeal. maize meal Corn grits Sweeteners ( for Every 1 cup ) * * (HV) denotes Healthy Version for low fat or fat free substitution in Baking Light Brown Sugar 2 tablespoons molasses plus 1 cup of white sugar Dark Brown Sugar 3 tablespoons molasses plus 1 cup of white sugar Confectioner’s/Powdered Sugar Process 1 cup sugar plus 1 tablespoon cornstarch Corn Syrup 1 cup sugar plus 1/4 cup water 1 cup Golden Syrup 1 cup honey (may be little sweeter) 1 cup molasses Golden Syrup Combine two parts light corn syrup plus one part molasses 1/2 cup honey plus 1/2 cup corn syrup 1 cup maple syrup 1 cup corn syrup Honey 1- 1/4 cups sugar plus 1/4 cup water 3/4 cup maple syrup plus 1/2 cup granulated sugar 3/4 cup corn syrup plus 1/2 cup granulated sugar 3/4 cup light molasses plus 1/2 cup granulated white sugar 1 1/4 cups granulated white or brown sugar plus 1/4 cup additional liquid in recipe plus 1/2 teaspoon cream of tartar Maple Syrup 1 cup honey,thinned with water or fruit juice like apple 3/4 cup corn syrup plus 1/4 cup butter 1 cup Brown Rice Syrup 1 cup Brown sugar (in case of cereals) 1 cup light molasses (on pancakes, cereals etc) 1 cup granulated sugar for every 3/4 cup of maple syrup and increase liquid in the recipe by 3 tbsp for every cup of sugar.If baking soda is used, decrease the amount by 1/4 teaspoon per cup of sugar substituted, since sugar is less acidic than maple syrup Molasses 1 cup honey 1 cup dark corn syrup 1 cup maple syrup 3/4 cup brown sugar warmed and dissolved in 1/4 cup of liquid ( use this if taste of molasses is important in the baked good) Cocoa Powder (Natural, Unsweetened) 3 tablespoons (20 grams) Dutch-processed cocoa plus 1/8 teaspoon cream of tartar, lemon juice or white vinegar 1 ounce (30 grams) unsweetened chocolate (reduce fat in recipe by 1 tablespoon) 3 tablespoons (20 grams) carob powder Semisweet baking chocolate (1 oz) 1 oz unsweetened baking chocolate plus 1 Tbsp sugar Unsweetened baking chocolate (1 oz ) 3 Tbsp baking cocoa plus 1 Tbsp vegetable oil or melted shortening or margarine Semisweet chocolate chips (1 cup) 6 oz semisweet baking chocolate, chopped (Alternatively) For 1 cup of Semi sweet chocolate chips you can use : 6 tablespoons unsweetened cocoa powder, 7 tablespoons sugar ,1/4 cup fat (butter or oil) Leaveners and Diary * * (HV) denotes Healthy Version for low fat or fat free substitution in Baking Compressed Yeast (1 cake) 1 envelope or 2 teaspoons active dry yeast 1 packet (1/4 ounce) Active Dry yeast 1 cake fresh compressed yeast 1 tablespoon fast-rising active yeast Baking Powder (1 tsp) 1/3 teaspoon baking soda plus 1/2 teaspoon cream of tartar 1/2 teaspoon baking soda plus 1/2 cup buttermilk or plain yogurt 1/4 teaspoon baking soda plus 1/3 cup molasses. When using the substitutions that include liquid, reduce other liquid in recipe accordingly Baking Soda(1 tsp) 3 tsp Baking Powder ( and reduce the acidic ingredients in the recipe. Ex Instead of buttermilk add milk) 1 tsp potassium bicarbonate Ideal substitution – 2 tsp Baking powder and omit salt in recipe Cream of tartar (1 tsp) 1 teaspoon white vinegar 1 tsp lemon juice Notes from What’s Cooking America – If cream of tartar is used along with baking soda in a cake or cookie recipe, omit both and use baking powder instead. If it calls for baking soda and cream of tarter, just use baking powder.Normally, when cream of tartar is used in a cookie, it is used together with baking soda. The two of them combined work like double-acting baking powder. When substituting for cream of tartar, you must also substitute for the baking soda. If your recipe calls for baking soda and cream of tarter, just use baking powder. One teaspoon baking powder is equivalent to 1/4 teaspoon baking soda plus 5/8 teaspoon cream of tartar. If there is additional baking soda that does not fit into the equation, simply add it to the batter. Buttermilk (1 cup) 1 tablespoon lemon juice or vinegar (white or cider) plus enough milk to make 1 cup (let stand 5-10 minutes) 1 cup plain or low fat yogurt 1 cup sour cream 1 cup water plus 1/4 cup buttermilk powder 1 cup milk plus 1 1/2 – 1 3/4 teaspoons cream of tartar Plain Yogurt (1 cup) 1 cup sour cream 1 cup buttermilk 1 cup crème fraiche 1 cup heavy whipping cream (35% butterfat) plus 1 tablespoon freshly squeezed lemon juice Whole Milk (1 cup) 1 cup fat free milk plus 1 tbsp unsaturated Oil like canola (HV) 1 cup low fat milk (HV) Heavy Cream (1 cup) 3/4 cup milk plus 1/3 cup melted butter.(whipping wont work) Sour Cream (1 cup) (pls refer also Substitutes for Fats in Baking below) 7/8 cup buttermilk or sour milk plus 3 tablespoons butter. 1 cup thickened yogurt plus 1 teaspoon baking soda. 3/4 cup sour milk plus 1/3 cup butter. 3/4 cup buttermilk plus 1/3 cup butter. Cooked sauces: 1 cup yogurt plus 1 tablespoon flour plus 2 teaspoons water. Cooked sauces: 1 cup evaporated milk plus 1 tablespoon vinegar or lemon juice. Let stand 5 minutes to thicken. Dips: 1 cup yogurt (drain through a cheesecloth-lined sieve for 30 minutes in the refrigerator for a thicker texture). Dips: 1 cup cottage cheese plus 1/4 cup yogurt or buttermilk, briefly whirled in a blender. Dips: 6 ounces cream cheese plus 3 tablespoons milk,briefly whirled in a blender. Lower fat: 1 cup low-fat cottage cheese plus 1 tablespoon lemon juice plus 2 tablespoons skim milk, whipped until smooth in a blender. Lower fat: 1 can chilled evaporated milk whipped with 1 teaspoon lemon juice. 1 cup plain yogurt plus 1 tablespoon cornstarch 1 cup plain nonfat yogurt Substitutes for Fats in Baking * * (HV) denoted Healthy Version for low fat or fat free substitution in Baking Butter (1 cup) 1 cup trans-free vegetable shortening 3/4 cups of vegetable oil (example. Canola oil) Fruit purees (example- applesauce, pureed prunes, baby-food fruits). Add it along with some vegetable oil and reduce any other sweeteners needed in the recipe since fruit purees are already sweet. 1 cup polyunsaturated margarine (HV) 3/4 cup polyunsaturated oil like safflower oil (HV) 1 cup mild olive oil (not extra virgin)(HV) Note: Butter creates the flakiness and the richness which an oil/purees cant provide. If you don’t want to compromise that much to taste, replace half the butter with the substitutions. Shortening(1 cup) 1 cup polyunsaturated margarine like Earth Balance or Smart Balance(HV) 1 cup + 2tbsp Butter ( better tasting than shortening but more expensive and has cholesterol and a higher level of saturated fat; makes cookies less crunchy, bread crusts more crispy) 1 cup + 2 tbsp Margarine (better tasting than shortening but more expensive; makes cookies less crunchy, bread crusts tougher) 1 Cup – 2tbsp Lard (Has cholesterol and a higher level of saturated fat) Oil equal amount of apple sauce stiffly beaten egg whites into batter equal parts mashed banana equal parts yogurt prune puree grated raw zucchini or seeds removed if cooked. Works well in quick breads/muffins/coffee cakes and does not alter taste pumpkin puree (if the recipe can handle the taste change) Low fat cottage cheese (use only half of the required fat in the recipe). Can give rubbery texture to the end result Silken Tofu – (use only half of the required fat in the recipe). Can give rubbery texture to the end result Equal parts of fruit juice Note: Fruit purees can alter the taste of the final product is used in large quantities. Cream Cheese (1 cup) 4 tbsps. margarine plus 1 cup low-fat cottage cheese – blended. Add few teaspoons of fat-free milk if needed (HV) Heavy Cream (1 cup) 1 cup evaporated skim milk (or full fat milk) 1/2 cup low fat Yogurt plus 1/2 low fat Cottage Cheese (HV) 1/2 cup Yogurt plus 1/2 Cottage Cheese Sour Cream (1 cup) 1 cup plain yogurt (HV) 3/4 cup buttermilk or plain yogurt plus 1/3 cup melted butter 1 cup crème fraiche 1 tablespoon lemon juice or vinegar plus enough whole milk to fill 1 cup (let stand 5-10 minutes) 1/2 cup low-fat cottage cheese plus 1/2 cup low-fat or nonfat yogurt (HV) 1 cup fat-free sour cream (HV) Note: How to Make Maple Syrup Substitute at home For 1 Cup Maple Syrup 1/2 cup granulated sugar 1 cup brown sugar, firmly packed 1 cup boiling water 1 teaspoon butter 1 teaspoon maple extract or vanilla extract Method In a heavy saucepan, place the granulated sugar and keep stirring until it melts and turns slightly brown. Alternatively in another pan, place brown sugar and water and bring to a boil without stirring. Now mix both the sugars and simmer in low heat until they come together as one thick syrup. Remove from heat, add butter and the extract. Use this in place of maple syrup. Store it in a fridge in an air tight container. Even though this was posted in their site long back, I found it helpful. So posting it for you. via chefinyou . cc image credit: flickr/zetrules

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  • Warning message during boot after installation of kernel 3.3: Kernel needs AppArmor 2.4 compatibility patch

    - by Matus Frisik
    I have Ubuntu Server 11.10 and after installation of kernel 3.3 (I just followed instructions from site www.upbuntu.com - How To Install Linux 3.3 Kernel In Ubuntu 11.10/12.04) It shows me following message during boot: fsck from util-linux 2.19.1 fsck from util-linux 2.19.1 /dev/sda5: clean, 204099/1152816 files, 988854/4608639 blocks /dev/sda6: clean, 2345/1281120 files, 142711/5120710 blocks modem-manager[830]: ModemManager (version 0.5) starting... * Starting mDNS/DNS-SD daemon [154G[ OK ] * Starting CUPS printing spooler/server [154G[ OK ] * Starting Mount network filesystems [154G[ OK ] * Stopping Mount network filesystems [154G[ OK ] * Starting System V initialisation compatibility [154G[ OK ] * Stopping Failsafe Boot Delay [154G[ OK ] Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/bin.ping (/etc/apparmor.d/bin.ping line 28): profile /bin/ping network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/lightdm-guest-session (/etc/apparmor.d/lightdm-guest-session line 71): profile /usr/lib/lightdm/lightdm-guest-session-wrapper network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/sbin.dhclient (/etc/apparmor.d/sbin.dhclient line 73): profile /sbin/dhclient network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/sbin.klogd (/etc/apparmor.d/sbin.klogd line 35): profile /sbin/klogd network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/sbin.syslog-ng (/etc/apparmor.d/sbin.syslog-ng line 52): profile /sbin/syslog-ng network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/sbin.syslogd (/etc/apparmor.d/sbin.syslogd line 40): profile /sbin/syslogd network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.bin.chromium-browser (/etc/apparmor.d/usr.bin.chromium-browser line 165): profile /usr/lib/chromium-browser/chromium-browser network rules not enforced Warning from /etc/apparmor.d/usr.bin.chromium-browser (/etc/apparmor.d/usr.bin.chromium-browser line 165): profile browser_java network rules not enforced Warning from /etc/apparmor.d/usr.bin.chromium-browser (/etc/apparmor.d/usr.bin.chromium-browser line 165): profile browser_openjdk network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.bin.evince (/etc/apparmor.d/usr.bin.evince line 142): profile /usr/bin/evince network rules not enforced Warning from /etc/apparmor.d/usr.bin.evince (/etc/apparmor.d/usr.bin.evince line 142): profile /usr/bin/evince-previewer network rules not enforced Warning from /etc/apparmor.d/usr.bin.evince (/etc/apparmor.d/usr.bin.evince line 142): profile /usr/bin/evince-thumbnailer network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Skipping profile in /etc/apparmor.d/disable: usr.bin.firefox Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.lib.dovecot.deliver (/etc/apparmor.d/usr.lib.dovecot.deliver line 24): profile /usr/lib/dovecot/deliver network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.lib.dovecot.dovecot-auth (/etc/apparmor.d/usr.lib.dovecot.dovecot-auth line 24): profile /usr/lib/dovecot/dovecot-auth network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.lib.dovecot.imap (/etc/apparmor.d/usr.lib.dovecot.imap line 23): profile /usr/lib/dovecot/imap network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.lib.dovecot.imap-login (/etc/apparmor.d/usr.lib.dovecot.imap-login line 22): profile /usr/lib/dovecot/imap-login network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.lib.dovecot.managesieve-login (/etc/apparmor.d/usr.lib.dovecot.managesieve-login line 22): profile /usr/lib/dovecot/managesieve-login network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.lib.dovecot.pop3 (/etc/apparmor.d/usr.lib.dovecot.pop3 line 22): profile /usr/lib/dovecot/pop3 network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.lib.dovecot.pop3-login (/etc/apparmor.d/usr.lib.dovecot.pop3-login line 21): profile /usr/lib/dovecot/pop3-login network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.lib.telepathy (/etc/apparmor.d/usr.lib.telepathy line 86): profile /usr/lib/telepathy/mission-control-5 network rules not enforced Warning from /etc/apparmor.d/usr.lib.telepathy (/etc/apparmor.d/usr.lib.telepathy line 86): profile /usr/lib/telepathy/telepathy-* network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.sbin.avahi-daemon (/etc/apparmor.d/usr.sbin.avahi-daemon line 30): profile /usr/sbin/avahi-daemon network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.sbin.cupsd (/etc/apparmor.d/usr.sbin.cupsd line 170): profile /usr/lib/cups/backend/cups-pdf network rules not enforced Warning from /etc/apparmor.d/usr.sbin.cupsd (/etc/apparmor.d/usr.sbin.cupsd line 170): profile /usr/sbin/cupsd network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.sbin.dnsmasq (/etc/apparmor.d/usr.sbin.dnsmasq line 51): profile /usr/sbin/dnsmasq network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.sbin.dovecot (/etc/apparmor.d/usr.sbin.dovecot line 37): profile /usr/sbin/dovecot network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.sbin.identd (/etc/apparmor.d/usr.sbin.identd line 31): profile /usr/sbin/identd network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.sbin.mdnsd (/etc/apparmor.d/usr.sbin.mdnsd line 35): profile /usr/sbin/mdnsd network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.sbin.mysqld (/etc/apparmor.d/usr.sbin.mysqld line 44): profile /usr/sbin/mysqld network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.sbin.nmbd (/etc/apparmor.d/usr.sbin.nmbd line 21): profile /usr/sbin/nmbd network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.sbin.nscd (/etc/apparmor.d/usr.sbin.nscd line 46): profile /usr/sbin/nscd network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.sbin.smbd (/etc/apparmor.d/usr.sbin.smbd line 40): profile /usr/sbin/smbd network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.sbin.tcpdump (/etc/apparmor.d/usr.sbin.tcpdump line 64): profile /usr/sbin/tcpdump network rules not enforced Cache read/write disabled: /sys/kernel/security/apparmor/features interface file missing. (Kernel needs AppArmor 2.4 compatibility patch.) Warning from /etc/apparmor.d/usr.sbin.traceroute (/etc/apparmor.d/usr.sbin.traceroute line 26): profile /usr/sbin/traceroute network rules not enforced * Starting AppArmor profiles [160G [154G[ OK ] speech-dispatcher disabled; edit /etc/default/speech-dispatcher Checking for running unattended-upgrades: What does this warnings mean and how can I fix it? Informations about my system: response@response:~$ uname -a Linux response 3.3.0-030300-generic #201203182135 SMP Mon Mar 19 01:43:18 UTC 2012 i686 i686 i386 GNU/Linux

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  • I need help on my C++ assignment using MS Visual C++

    - by krayzwytie
    Ok, so I don't want you to do my homework for me, but I'm a little lost with this final assignment and need all the help I can get. Learning about programming is tough enough, but doing it online is next to impossible for me... Now, to get to the program, I am going to paste what I have so far. This includes mostly //comments and what I have written so far. If you can help me figure out where all the errors are and how to complete the assignment, I will really appreciate it. Like I said, I don't want you to do my homework for me (it's my final), but any constructive criticism is welcome. This is my final assignment for this class and it is due tomorrow (Sunday before midnight, Arizona time). This is the assignment: Examine the following situation: o Your company, Datamax, Inc., is in the process of automating its payroll systems. Your manager has asked you to create a program that calculates overtime pay for all employees. Your program must take into account the employee’s salary, total hours worked, and hours worked more than 40 in a week, and then provide an output that is useful and easily understood by company management. • Compile your program utilizing the following background information and the code outline in Appendix D (included in the code section). • Submit your project as an attachment including the code and the output. Company Background: o Three employees: Mark, John, and Mary o The end user needs to be prompted for three specific pieces of input—name, hours worked, and hourly wage. o Calculate overtime if input is greater than 40 hours per week. o Provide six test plans to verify the logic within the program. o Plan 1 must display the proper information for employee #1 with overtime pay. o Plan 2 must display the proper information for employee #1 with no overtime pay. o Plans 3-6 are duplicates of plan 1 and 2 but for the other employees. Program Requirements: o Define a base class to use for the entire program. o The class holds the function calls and the variables related to the overtime pay calculations. o Define one object per employee. Note there will be three employees. o Your program must take the objects created and implement calculations based on total salaries, total hours, and the total number of overtime hours. See the Employee Summary Data section of the sample output. Logic Steps to Complete Your Program: o Define your base class. o Define your objects from your base class. o Prompt for user input, updating your object classes for all three users. o Implement your overtime pay calculations. o Display overtime or regular time pay calculations. See the sample output below. o Implement object calculations by summarizing your employee objects and display the summary information in the example below. And this is the code: // Final_Project.cpp : Defines the entry point for the console application. // #include "stdafx.h" #include <iostream> #include <string> #include <iomanip> using namespace std; // //CLASS DECLARATION SECTION // class CEmployee { public: void ImplementCalculations(string EmployeeName, double hours, double wage); void DisplayEmployInformation(void); void Addsomethingup (CEmployee, CEmployee, CEmployee); string EmployeeName ; int hours ; int overtime_hours ; int iTotal_hours ; int iTotal_OvertimeHours ; float wage ; float basepay ; float overtime_pay ; float overtime_extra ; float iTotal_salaries ; float iIndividualSalary ; }; int main() { system("cls"); cout << "Welcome to the Employee Pay Center"; /* Use this section to define your objects. You will have one object per employee. You have only three employees. The format is your class name and your object name. */ std::cout << "Please enter Employee's Name: "; std::cin >> EmployeeName; std::cout << "Please enter Total Hours for (EmployeeName): "; std::cin >> hours; std::cout << "Please enter Base Pay for(EmployeeName): "; std::cin >> basepay; /* Here you will prompt for the first employee’s information. Prompt the employee name, hours worked, and the hourly wage. For each piece of information, you will update the appropriate class member defined above. Example of Prompts Enter the employee name = Enter the hours worked = Enter his or her hourly wage = */ /* Here you will prompt for the second employee’s information. Prompt the employee name, hours worked, and the hourly wage. For each piece of information, you will update the appropriate class member defined above. Enter the employee name = Enter the hours worked = Enter his or her hourly wage = */ /* Here you will prompt for the third employee’s information. Prompt the employee name, hours worked, and the hourly wage. For each piece of information, you will update the appropriate class member defined above. Enter the employee name = Enter the hours worked = Enter his or her hourly wage = */ /* Here you will implement a function call to implement the employ calcuations for each object defined above. You will do this for each of the three employees or objects. The format for this step is the following: [(object name.function name(objectname.name, objectname.hours, objectname.wage)] ; */ /* This section you will send all three objects to a function that will add up the the following information: - Total Employee Salaries - Total Employee Hours - Total Overtime Hours The format for this function is the following: - Define a new object. - Implement function call [objectname.functionname(object name 1, object name 2, object name 3)] /* } //End of Main Function void CEmployee::ImplementCalculations (string EmployeeName, double hours, double wage){ //Initialize overtime variables overtime_hours=0; overtime_pay=0; overtime_extra=0; if (hours > 40) { /* This section is for the basic calculations for calculating overtime pay. - base pay = 40 hours times the hourly wage - overtime hours = hours worked – 40 - overtime pay = hourly wage * 1.5 - overtime extra pay over 40 = overtime hours * overtime pay - salary = overtime money over 40 hours + your base pay */ /* Implement function call to output the employee information. Function is defined below. */ } // if (hours > 40) else { /* Here you are going to calculate the hours less than 40 hours. - Your base pay is = your hours worked times your wage - Salary = your base pay */ /* Implement function call to output the employee information. Function is defined below. */ } // End of the else } //End of Primary Function void CEmployee::DisplayEmployInformation(); { // This function displays all the employee output information. /* This is your cout statements to display the employee information: Employee Name ............. = Base Pay .................. = Hours in Overtime ......... = Overtime Pay Amount........ = Total Pay ................. = */ } // END OF Display Employee Information void CEmployee::Addsomethingup (CEmployee Employ1, CEmployee Employ2) { // Adds two objects of class Employee passed as // function arguments and saves them as the calling object's data member values. /* Add the total hours for objects 1, 2, and 3. Add the salaries for each object. Add the total overtime hours. */ /* Then display the information below. %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%%% EMPLOYEE SUMMARY DATA%%%%%%%%%%%%%%%%%%%%%%% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%%% Total Employee Salaries ..... = 576.43 %%%% Total Employee Hours ........ = 108 %%%% Total Overtime Hours......... = 5 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% */ } // End of function

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  • Simplemodal: four times on a page leads to extra "next" or "previous" button

    - by DDF
    We are experiencing a problem with each instance of the call to the simplemodal div class .basic-modal-content adding an extra next or previous button in the modal windows. We are using simplemodal in four places on a page using a common JS in the container (provided below) and a common CSS format for the modal windows. In one area we are using six "statements" in a window with a next and previous button. I would include a picture of the modal window but it's being disallowed by the system as I'm a first time poster to this forum. In the other three areas we are using three "biographies" in a similar window with the ability to see each of the three bios from each of modal windows. We are using a common Simplemodal JS script in the page which has the following code: <script> $(function() { $('a').each(function() { $(this).click(function() { $('#modal_' + this.id).modal({ overlayClose:true }); }); }); var num_divs = $('div.basic-modal-content').length; $('div.basic-modal-content').each(function(i) { /* if there is a previous div add a link to it */ if (i > 0) { /* get the ID for previous div */ var prev_id = $(this).prev('.basic-modal-content').attr('id'); /* add the link with click event */ $('<a href="#" class="simplemodal-container-prev"></a>') .click(function() { $.modal.close(); $('#' + prev_id).modal({overlayClose:true}); }) .appendTo($(this)); } /* if there is a next div add a link to it */ if (i < num_divs - 1) { /* get the ID for next div */ var next_id = $(this).next('.basic-modal-content').attr('id'); /* add the link with click event */ $('<a href="#" class="simplemodal-container-next"></a>') .click(function() { $.modal.close(); $('#' + next_id).modal({overlayClose:true}); }) .appendTo($(this)); } }); }); </script> and some CSS to create an image for each window that shows the progress bar through the ul/li list. The code to produce the above looks like this: <h1>Our HEADLINE</h1> <div id='basic-modal'> <ul> <li><a href='#' id='one'>TEXT 1</a></li> <li><a href='#' id='two'>TEXT 2</a></li> <li><a href='#' id='three'>TEXT 3</a></li> <li><a href='#' id='four'>TEXT 4</a></li> <li><a href='#' id='five'>TEXT 5</a></li> <li><a href='#' id='six'>TEXT 6</a></li> </ul> </div> <div class="basic-modal-content" id="modal_one"> <img src="link to modal_one.png" alt="progress bar"/> <h3>headline text</h3> <p>body text</p> </div> <div class="basic-modal-content" id="modal_two"> <img src="link to modal_two.png" alt="progress bar"/> <h3>headline text</h3> <p>body text</p> </div> <div> ... other divs 3 4 and 5 </div> <div class="basic-modal-content" id="modal_six"> <img src="link to modal_six.png" alt="progress bar"/> <h3>headline text</h3> <p>body text</p> </div> </div> The ul/li structure works on the main page for the links. The modal windows allow one to browse through all of the six TEXTs. There is a common CSS style to the windows and a custom image in each of the modal windows derived from the "#modal_[number] img" CSS in the form of a progress bar. It should be noted that the first modal window in the first set of ul/li (the six) do not exhibit the extra previous button. Here is the relevant code from one of the three biographic links. You will note that the biographic links each have to have all three in this current configuration. <h4>Our HEADLINE</h4> <div class="bottom-widget-text"> <img src="picture" alt="not relevant to the simplemodal problem"/> <p>Read about person NUMBER 1 by clicking on the following link: <a href='#' id='seven' >Expand</a> </p> </div> <div class="basic-modal-content" id="modal_seven"> <img src="link to modal_seven.png" alt="portrait 1"/> <h3>headline text</h3> <p>BIOGRAPHY</p> </div> <div class="basic-modal-content" id="modal_eight"> <img src="link to modal_eight.png" alt="portrait 2"/> <h3>headline text</h3> <p>BIOGRAPHY</p> </div> <div class="basic-modal-content" id="modal_nine"> <img src="link to modal_nine.png" alt="portrait 3"/> <h3>headline text</h3> <p>BIOGRAPHY</p> </div> </div> Similarly the "biographies" open up from a different area of the page. The modal windows allow one to browse through all three of the BIOs. The bios use the SAME CSS style windows and a custom image in each of the modal windows derived from the "#modal_[number] img" CSS in the form of a portrait. Everything is working well except one thing: the first six windows have an extra next button that leads to an image of the close widow button only. Similarly, the BIOs pages have extra previous button that leads to the same "close button only" shown above. We want to maintain the same base CSS for the modal windows for this page. We want to keep the JS simple. The only behavior that is bad is the extra previous and next bottons that appear to be spurious. So is this a fix to the JS? Or do I have the instances of the modal windows too entangled? Perhaps there is a better method for having multiple instances of a simplemodal window on the same page? Or is the problem the "#" variable being common to each of the uses of the JS? Thanks in advance. DDF

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  • I need help on my C++ assignment using Microsoft Visual C++

    - by krayzwytie
    Ok, so I don't want you to do my homework for me, but I'm a little lost with this final assignment and need all the help I can get. Learning about programming is tough enough, but doing it online is next to impossible for me... Now, to get to the program, I am going to paste what I have so far. This includes mostly //comments and what I have written so far. If you can help me figure out where all the errors are and how to complete the assignment, I will really appreciate it. Like I said, I don't want you to do my homework for me (it's my final), but any constructive criticism is welcome. This is my final assignment for this class and it is due tomorrow (Sunday before midnight, Arizona time). This is the assignment: Examine the following situation: Your company, Datamax, Inc., is in the process of automating its payroll systems. Your manager has asked you to create a program that calculates overtime pay for all employees. Your program must take into account the employee’s salary, total hours worked, and hours worked more than 40 in a week, and then provide an output that is useful and easily understood by company management. Compile your program utilizing the following background information and the code outline in Appendix D (included in the code section). Submit your project as an attachment including the code and the output. Company Background: Three employees: Mark, John, and Mary The end user needs to be prompted for three specific pieces of input—name, hours worked, and hourly wage. Calculate overtime if input is greater than 40 hours per week. Provide six test plans to verify the logic within the program. Plan 1 must display the proper information for employee #1 with overtime pay. Plan 2 must display the proper information for employee #1 with no overtime pay. Plans 3-6 are duplicates of plan 1 and 2 but for the other employees. Program Requirements: Define a base class to use for the entire program. The class holds the function calls and the variables related to the overtime pay calculations. Define one object per employee. Note there will be three employees. Your program must take the objects created and implement calculations based on total salaries, total hours, and the total number of overtime hours. See the Employee Summary Data section of the sample output. Logic Steps to Complete Your Program: Define your base class. Define your objects from your base class. Prompt for user input, updating your object classes for all three users. Implement your overtime pay calculations. Display overtime or regular time pay calculations. See the sample output below. Implement object calculations by summarizing your employee objects and display the summary information in the example below. And this is the code: // Final_Project.cpp : Defines the entry point for the console application. // #include "stdafx.h" #include <iostream> #include <string> #include <iomanip> using namespace std; // //CLASS DECLARATION SECTION // class CEmployee { public: void ImplementCalculations(string EmployeeName, double hours, double wage); void DisplayEmployInformation(void); void Addsomethingup (CEmployee, CEmployee, CEmployee); string EmployeeName ; int hours ; int overtime_hours ; int iTotal_hours ; int iTotal_OvertimeHours ; float wage ; float basepay ; float overtime_pay ; float overtime_extra ; float iTotal_salaries ; float iIndividualSalary ; }; int main() { system("cls"); cout << "Welcome to the Employee Pay Center"; /* Use this section to define your objects. You will have one object per employee. You have only three employees. The format is your class name and your object name. */ std::cout << "Please enter Employee's Name: "; std::cin >> EmployeeName; std::cout << "Please enter Total Hours for (EmployeeName): "; std::cin >> hours; std::cout << "Please enter Base Pay for(EmployeeName): "; std::cin >> basepay; /* Here you will prompt for the first employee’s information. Prompt the employee name, hours worked, and the hourly wage. For each piece of information, you will update the appropriate class member defined above. Example of Prompts Enter the employee name = Enter the hours worked = Enter his or her hourly wage = */ /* Here you will prompt for the second employee’s information. Prompt the employee name, hours worked, and the hourly wage. For each piece of information, you will update the appropriate class member defined above. Enter the employee name = Enter the hours worked = Enter his or her hourly wage = */ /* Here you will prompt for the third employee’s information. Prompt the employee name, hours worked, and the hourly wage. For each piece of information, you will update the appropriate class member defined above. Enter the employee name = Enter the hours worked = Enter his or her hourly wage = */ /* Here you will implement a function call to implement the employ calcuations for each object defined above. You will do this for each of the three employees or objects. The format for this step is the following: [(object name.function name(objectname.name, objectname.hours, objectname.wage)] ; */ /* This section you will send all three objects to a function that will add up the the following information: - Total Employee Salaries - Total Employee Hours - Total Overtime Hours The format for this function is the following: - Define a new object. - Implement function call [objectname.functionname(object name 1, object name 2, object name 3)] /* } //End of Main Function void CEmployee::ImplementCalculations (string EmployeeName, double hours, double wage){ //Initialize overtime variables overtime_hours=0; overtime_pay=0; overtime_extra=0; if (hours > 40) { /* This section is for the basic calculations for calculating overtime pay. - base pay = 40 hours times the hourly wage - overtime hours = hours worked – 40 - overtime pay = hourly wage * 1.5 - overtime extra pay over 40 = overtime hours * overtime pay - salary = overtime money over 40 hours + your base pay */ /* Implement function call to output the employee information. Function is defined below. */ } // if (hours > 40) else { /* Here you are going to calculate the hours less than 40 hours. - Your base pay is = your hours worked times your wage - Salary = your base pay */ /* Implement function call to output the employee information. Function is defined below. */ } // End of the else } //End of Primary Function void CEmployee::DisplayEmployInformation(); { // This function displays all the employee output information. /* This is your cout statements to display the employee information: Employee Name ............. = Base Pay .................. = Hours in Overtime ......... = Overtime Pay Amount........ = Total Pay ................. = */ } // END OF Display Employee Information void CEmployee::Addsomethingup (CEmployee Employ1, CEmployee Employ2) { // Adds two objects of class Employee passed as // function arguments and saves them as the calling object's data member values. /* Add the total hours for objects 1, 2, and 3. Add the salaries for each object. Add the total overtime hours. */ /* Then display the information below. %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%%% EMPLOYEE SUMMARY DATA%%%%%%%%%%%%%%%%%%%%%%% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%%% Total Employee Salaries ..... = 576.43 %%%% Total Employee Hours ........ = 108 %%%% Total Overtime Hours......... = 5 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% */ } // End of function

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  • Win7 playback of dvr-ms files stutters

    - by Jim Lynn
    I've just had to install Windows 7 on my Media Center machine because my Vista installation had a faulty drive. I've got the latest drivers that I can find - Intel 945GM integrated Graphics, Realtek audio drivers. Things are working OK with one exception. Playback of old recordings, from dvr-ms format files, is choppy. The picture freezes for a fraction of a second, then quickly catches up. The sound is uninterrupted and doesn't pause. These freezes happen once every 5 seconds or so. It's very regular. Playback of Live TV from the digital tuner is perfectly smooth. DVD playback is perfectly smooth. As an experiment, I used the MPEG editing package VideoReDo to create a small test file in three different formats. This program takes the raw MPEG streams and repackages them into the desired container. I took the same clip and created three files in three formats: dvr-ms (Microsoft's old recorded TV format); mpg (standard MPEG); and ts (raw MPEG transport stream of the kind often produced by PVRs). When these three files are played back under Windows 7, the mpg and ts files play smoothly, but the dvr-ms file stutters. The last piece of data I have is that two other Windows 7 machines can play back dvr-ms files smoothly with no stuttering. One is a netbook, with less grunt than the media centre. So there must be something specific about my Media Center machine that's causing the problem. Does anyone have any idea where I can look now? I don't know much about AV software, codecs, filter graphs etc. but I suspect that's where the problem lies. Rendering the video isn't the problem, but extracting the streams is. How would I go about diagnosing the problem? Edited to add: I just used the GraphStudio tool to look at the filter graph on the offending PC. The filter graph it uses by default for dvr-ms looks identical to the other machines, and, interestingly, when I play the files using GraphStudio they run smoothly. Under Windows Media Player and Windows Media Center they stutter. I'd like to see the filter graph for WMP but GraphStudio won't show it. It looks like WMP and WMC are using a different decoding path to GraphStudio. Edited again to add: Today I purchased a new HDTV. The same Media Center driving the TV at 1080p is now playing back the old Recorded TV files smoothly, without stuttering. So whatever the cause of the original problem, using a different resolution seems to have removed the problem. It might also explain why nobody else has had this problem. I doubt many people use Media Centre with a 14in portable TV.

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  • Why does rsync spawn multiple processes for me?

    - by Yoga
    I am using the following cron statement to backup from one folder to another folder in the same machine: 19 21 * * * root rsync -ac --delete /source/folder /dest/folder When I use pstree, I see the cron forked three processes +-cron---cron---rsync---rsync---rsync And ps 9972 ? Ds 1:00 rsync -ac --delete /source/folder /dest/folder 9973 ? S 0:29 rsync -ac --delete /source/folder /dest/folder 9974 ? S 0:09 rsync -ac --delete /source/folder /dest/folder Why are three processes? Can I limit to only one?

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  • ATI Eyefinity under linux

    - by Bryan Ward
    I know that the new 5xxx series cards from ATI are capable of powering up to 6 monitors, but I was curious if anyone had any such luck setting this up under linux. I actually only have three monitors that I am interested in using, but three is the point where the previous generation video cards started to get a little buggy as a result of needing multiple video cards. Is the linux support for this capability any good at this point, or is the Eyefinity support really only for windows at this time.

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  • Eyefinity resolution on third monitor

    - by Sam2299
    I'm now using three monitors with resolution capability of 1920x1080. The one monitor connected to Active Display Port is (from some reason) limited to 1440x900. Is there a way to increase the resolution of the third monitor to have all three at 1920X1080? My machine: Graphics card - AMD 5770 Processor - Intel Core i7-2600 Ram - 8GB OS - Windows 7 64bit. VGC(Video Graphics Controller) driver is up to date. Got this message:

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  • Windows 7 playback of dvr-Microsoft files stutters

    - by Jim Lynn
    I've just had to install Windows 7 on my Media Center machine because my Vista installation had a faulty drive. I've got the latest drivers that I can find - Intel 945GM integrated Graphics, Realtek audio drivers. Things are working OK with one exception. Playback of old recordings, from dvr-Microsoft format files, is choppy. The picture freezes for a fraction of a second, then quickly catches up. The sound is uninterrupted and doesn't pause. These freezes happen once every 5 seconds or so. It's very regular. Playback of Live TV from the digital tuner is perfectly smooth. DVD playback is perfectly smooth. As an experiment, I used the MPEG editing package VideoReDo to create a small test file in three different formats. This program takes the raw MPEG streams and repackages them into the desired container. I took the same clip and created three files in three formats: dvr-Microsoft (Microsoft's old recorded TV format); mpg (standard MPEG); and ts (raw MPEG transport stream of the kind often produced by PVRs). When these three files are played back under Windows 7, the mpg and ts files play smoothly, but the dvr-Microsoft file stutters. The last piece of data I have is that two other Windows 7 machines can play back dvr-Microsoft files smoothly with no stuttering. One is a netbook, with less grunt than the media centre. So there must be something specific about my Media Center machine that's causing the problem. Does anyone have any idea where I can look now? I don't know much about AV software, codecs, filter graphs etc. but I suspect that's where the problem lies. Rendering the video isn't the problem, but extracting the streams is. How would I go about diagnosing the problem? Edited to add: I just used the GraphStudio tool to look at the filter graph on the offending PC. The filter graph it uses by default for dvr-Microsoft looks identical to the other machines, and, interestingly, when I play the files using GraphStudio they run smoothly. Under Windows Media Player and Windows Media Center they stutter. I'd like to see the filter graph for Windows Media Player but GraphStudio won't show it. It looks like Windows Media Player and WMC are using a different decoding path to GraphStudio. Edited again to add: Today I purchased a new HDTV. The same Media Center driving the TV at 1080p is now playing back the old Recorded TV files smoothly, without stuttering. So whatever the cause of the original problem, using a different resolution seems to have removed the problem. It might also explain why nobody else has had this problem. I doubt many people use Media Centre with a 14in portable TV.

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  • Remote Desktop 7 XP -> Windows 7

    - by Michael
    I am running Windows 7 at my office and Windows XP at home. I have seen the new Remote Desktop and want to use (I have three monitors at office and three at home) In the specs I saw where in order to use the multimon features you must connect to a Windows 7 client (I am running Windows 7 Professional 64-bit in my office) When I connect to it (from XP running RDP 7) I can't get all my monitors to come up, just one Is there something I am doing wrong? Both are running the same version of RDP Thanks for any help

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  • What do the numbers on Western Digital drives mean?

    - by Evan Carroll
    There are numerous numbers on a Western Digital drive, MDL (presumably model, ex WD5000BEKT-00KA9T0) -- not sure what the 99KA9T0 is. WWN (ex 50014EE25AC8C945) DCM (ex HBNTJBBB) LBA (ex 976773168) R/N (ex 77174) Then there are three numbers on the back of the PCB on a sticker White Sticker Left: 2061-771714-002 AC White Sticker Right: XT BD34 T7KQ 8 0002270 White Sticker far-Right: 272 Then there is one number printed on the PCB, REV P1 2060-771714-002 Then there is one number (or three) on the spindle, 71206-T8Y-03 9X0X22MF 32H Does anyone know what these numbers mean?

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  • Exchange 2007 and migrating only some users under a shared domain name

    - by DomoDomo
    I'm in the process of moving two law firms to hosted Exchange 2007, a service that the consulting company I work for offers. Let's call these two firms Crane Law and Poole Law. These two firms were ONE firm just six months ago, but split. So they have three email domains: Old Firm: craneandpoole.com New Firm 1: cranelaw.com New Firm 2: poolelaw.com Both Firm 1 & Firm 2 use craneandpoole.com email addresses, as for the other two domains, only people who work at the respective firm use that firm's domain name, natch. Currently these two firms are still using the same pre-split internal Exchange 2007 server, where MX records for all three domains point. Here's the problem. I'm not moving both companies at the same time. I'm moving Crane Law two weeks before Poole Law. During this two weeks, both companies need to be able to: Continue to receive emails addressed to craneandpoole.com Send emails between firms, using cranelaw.com and poolelaw.com accounts I also have a third problem: I'd like to setup all three domains in my hosting infrastructure way ahead of time, to make my own life easier What would solve all my problems would be, if there is some way I can tell Exchange 2007, even though this domain exists locally forward on the message to the outside world using public MX record as a basis for where to send it (or if I could somehow create a route for it statically that would work too). If this doesn't work, to address points #1 when I migrate Crane Law, I will delete all references locally to cranelaw.com on their current Exchange server, and setup individual forwards for each of their craneandpool.com mailboxes to forward to our hosted exchange server. This will also take care of point #2, since the cranelaw.com won't be there locally, when poolelaw.com tries to send to cranelaw.com, public MX records will be used for mail routing decisions and go to my hosted exchange. The bummer of that though is, I won't be able to setup poolelaw.com ahead of time in hosted Exchange, will have to wait to do it day of :( Sorry for the long and confusing post. Just wondering if there is a better or simpler way to do what I want? Three tier forests and that kind of thing are out, this is just a two week window where they won't be in the same place.

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  • Reserve internet connection.

    - by amouniverso
    I have the router D-link 804HV that have 20mbit\s internet via PPoE tunnel . It connect three PC with Windows Xp to my home net. One of three my PC have reserve stability wi-fi internet connection. How can I use the wi-fi connection as reserve if the router connection is not available? I try to set the Wi-fi PC as gate for the other two, but it's not working.

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  • Firewalls: What is the difference between Policy, NAT and Routes?

    - by Jakobud
    I'm learning fwbuilder and firewalls in general. I don't understand the differences between Policy, NAT and Routes. They all seem like they are just ways to tell the data where to go depending on what it is and where its coming from. What is the real difference? Is a properly configured firewall taking advantage of all three (Policy, NAT and Routes) or are they just three different ways to accomplish the same thing and you only need one of them?

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  • Compare 2 sets of data in Excel and returning a value when multiple columns match

    - by Susan C
    I have a data set for employees that contains name and 3 attributes (job function, job grade and location). I then have a data set for open positions that contains the requisition number and 3 attributes (job function, job grade and job location). For every employee, i would like the three attributes associated with them compared to the same three attributes of the open positions and have the cooresponding requisition numbers displayed for each employee where there is a match.

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  • Uneven Cassandra load

    - by David Keen
    Should a three node Cassandra cluster with a replication factor of 3 have the same load value for all three nodes? We are using a random partitioner and NetworkTopologyStrategy. Nodetool ring shows equal values for "Owns" but unequal values for "Load". Load Owns Token 113427455640312821154458202477256070484 16.53 GB 33.33% 0 14.8 GB 33.33% 56713727820156410577229101238628035242 15.65 GB 33.33% 113427455640312821154458202477256070484 Running nodetool repair and cleanup on each node brought the load a little closer but it still seems quite unbalanced. Is this considered normal?

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  • usb audio recording: clicking noice

    - by snot
    I'm having problems recording audio on windows using usb audio devices. The recorded material will have some kind of jitter/clicking noice. I tested three different usb microphones and three different recording applications. Every combination will have the same problem. Does some one know a solution for this problem?

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  • Primary/secondary ethernet interfaces via NetworkManager in Ubuntu 9.10

    - by Josh
    I have an Ubuntu 9.10 machine with three ethernet interfaces, eth0, eth1 and eth2. eth2 is connected to a private network. eth0 and eth2 are connected to two different LANs. Either one will provide access to the internet. All three networks have DHCP servers. Using Ubuntu's the default settings (And Gnome), when I boot up all the interfaces are active and my system gets three IP addresses. However any attempt to access the internet results in connection timeouts and other weirdness. I suspect that traffic is going out on one NIC (like eth0) and coming back in on another (like eth1). I'm not sure what's going on. The only way I can access the internet at the moment is to bring two of the devices down with ifdown. How can I configure eth0 as my primary interface so all trafic goes out by default on that interface, while keeping the other two active? Also, I want to make sure Avahi broadcasts properly on all three IPs so that the computers on the LAN of eth1 can still connect to myHostname.local... EDIT: Here's my routing table: Kernel IP routing table Destination Gateway Genmask Flags MSS Window irtt Iface 172.16.151.0 0.0.0.0 255.255.255.0 U 0 0 0 eth2 172.16.30.0 0.0.0.0 255.255.255.0 U 0 0 0 eth0 10.1.0.0 0.0.0.0 255.255.0.0 U 0 0 0 eth1 169.254.0.0 0.0.0.0 255.255.0.0 U 0 0 0 eth1 0.0.0.0 172.16.30.2 0.0.0.0 UG 0 0 0 eth0 0.0.0.0 10.1.0.1 0.0.0.0 UG 0 0 0 eth1 I want the 172.16.30.2 network to be the primary one and the 10.1.0.0 network to be the secondary one. EDIT2: My nameservers are also incorrect. It seems like Ubuntu is bringing the networks up in order, eth0, then 1, then 2, and the DHCP information from eth1 is overriding eth0, and eth2 is overriding eth1. How can I reverse this so the DHCP information from eth0 is the "master"? EDIT3: This seems to be an issue with Gnome's NetworkManager.

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  • MS SQL server: Single or multiple instances?

    - by Hugo Riley
    How costly (CPU or memory wise) is it to have multiple instances of SQL server 2005 instead of only one instance with prefixed databases? A company have three application providers. They each will install one application and they each require two or three databases. Should they all use the same instance or should every provider use it's own named instance? Is there any strong reason for one or other setup?

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  • SQL Server 2000 Enterprise Edition - Login Fail for User (computer Name)/Guest

    - by Nazmuzzaman Manna
    Hi: Subject: SQL Server 2000 Enterprise Edition, windows XP Log-in fail for odbc sql server user computer name/guest I am connecting for several computer with the VB6 application with following connection string "PROVIDER=MSDASQL;driver={SQL Server};server=Computer Name.;uid=;pwd=;database=Test Name;" BUT, just Three Computer not Log-in. This three (connected with each other) are completely separate in other Room. I checked all possible options. Besides, which option is missing??? Please Help me...

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