Search Results

Search found 18702 results on 749 pages for 'digital input'.

Page 283/749 | < Previous Page | 279 280 281 282 283 284 285 286 287 288 289 290  | Next Page >

  • On Click alert if $.get returns a value, if not, submit the form

    - by bradenkeith
    If the submit button is clicked, prevent the default action and see if the field 'account_name' is already in use. If the $.get() returns a result, alert the user of the results. If it doesn't, submit form with id="add_account_form". My problem is that my else{} statement is not submitting the form. I get no response when submit is clicked & there is no value returned. Also I would like to change my code where it goes $("#add_account_form").submit(..) instead of .click() however, would that cause a problem when trying to submit the form later in the script? <script type="text/javascript"> $(document).ready( function () { $("#submit").click( function () { var account_name = $("input[name=account_name]").val(); $.get( "'.url::site("ajax/check_account_name").'", {account_name: account_name}, function(data){ if(data.length > 0){ confirm( "The account name you entered looks like the following:\n" +data+ "Press cancel if this account already exists or ok to create it." ); }else{ $("#add_account_form").submit(); } }); return false; }); }); </script> <p> <input type="submit" id="submit" class="submit small" name="submit" value="Submit" /> </p> </form> Thanks for your help. EDIT So anyone who runs into my problems, it's that $.get() is asynchronous, so it will always return false, or true depending on what submitForm is defined as. $.ajax() however, allows async to be set as false, which allows the function to finish before moving on. See what I mean: $(document).ready( function () { $("#add_account_form").submit( function () { var submitForm = true; var account_name = $("input[name=account_name]").val(); $.ajax({ type: "GET", async: false, url: "'.url::site("ajax/check_account_name").'", data: ({account_name: account_name}), success: function(data){ if(data.length > 0){ if(!confirm( "The account name you entered looks like the following:\n" +data+ "Press cancel if this account already exists or ok to create it." )){ submitForm = false; } } } }); if (submitForm == false ) { return false; } }); }); Thanks for your help @Dan

    Read the article

  • how is this jquery app validating the username? (3rd party script)

    - by SarmenHB
    The tutorial that I'm trying to figure out is this: http://www.position-absolute.com/articles/jquery-form-validator-because-form-validation-is-a-mess/ The username field looks like this: <input value="" class="validate[required,custom[noSpecialCaracters],length[0,20],ajax[ajaxUser]]" type="text" name="user" id="user" /> That <input> field has a class item named ajax[ajaxUser] which has its rules contained in this script (jquery.validationEngine-en.js). The snippet for that item looks like this: "ajaxUser":{ "file":"validateUser.php", "extraData":"name=eric", "alertTextOk":"* This user is available", "alertTextLoad":"* Loading, please wait", "alertText":"* This user is already taken"}, What I can't figure out at all is how its PHP page is working which is validateUser.php. Where are all those post fields coming from? I looked around and can't find a field with those names. Thanks

    Read the article

  • Range annotation between nothing and 100?

    - by aticatac
    Hi I have a [Range] annotation that looks like this: [Range(0, 100)] public int AvailabilityGoal { get; set; } It works as it should, I can only enter values between 0 and 100 but I also want the input box to be optional, the user shouldn't get an validation error if the input box is empty. If the user leaves it empty it should make AvailabilityGoal = 0 but I don't want to force the user to enter a zero. I tried this but it (obviously) didn't work: [Range(typeof(int?), null, "100")] Is it possible to solve this with Data Annotations or in some other way? Thanks in advance. Bobby

    Read the article

  • Java Box Class: Unsolvable: aligning components to the left or right

    - by user323186
    I have been trying to left align buttons contained in a Box to the left, with no success. They align left alright, but for some reason dont shift all the way left as one would imagine. I attach the code below. Please try compiling it and see for yourself. Seems bizarre to me. Thanks, Eric import java.awt.Dimension; import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import java.io.BufferedReader; import java.io.File; import java.io.FileNotFoundException; import java.io.FileReader; import java.io.IOException; import javax.swing.Box; import javax.swing.BoxLayout; import javax.swing.JButton; import javax.swing.JFileChooser; import javax.swing.JFrame; import javax.swing.JMenu; import javax.swing.JMenuBar; import javax.swing.JMenuItem; import javax.swing.JScrollPane; import javax.swing.JTextArea; public class MainGUI extends Box implements ActionListener{ //Create GUI Components Box centerGUI=new Box(BoxLayout.X_AXIS); Box bottomGUI=new Box(BoxLayout.X_AXIS); //centerGUI subcomponents JTextArea left=new JTextArea(), right=new JTextArea(); JScrollPane leftScrollPane = new JScrollPane(left), rightScrollPane = new JScrollPane(right); //bottomGUI subcomponents JButton encrypt=new JButton("Encrypt"), decrypt=new JButton("Decrypt"), close=new JButton("Close"), info=new JButton("Info"); //Create Menubar components JMenuBar menubar=new JMenuBar(); JMenu fileMenu=new JMenu("File"); JMenuItem open=new JMenuItem("Open"), save=new JMenuItem("Save"), exit=new JMenuItem("Exit"); int returnVal =0; public MainGUI(){ super(BoxLayout.Y_AXIS); initCenterGUI(); initBottomGUI(); initFileMenu(); add(centerGUI); add(bottomGUI); addActionListeners(); } private void addActionListeners() { open.addActionListener(this); save.addActionListener(this); exit.addActionListener(this); encrypt.addActionListener(this); decrypt.addActionListener(this); close.addActionListener(this); info.addActionListener(this); } private void initFileMenu() { fileMenu.add(open); fileMenu.add(save); fileMenu.add(exit); menubar.add(fileMenu); } public void initCenterGUI(){ centerGUI.add(leftScrollPane); centerGUI.add(rightScrollPane); } public void initBottomGUI(){ bottomGUI.setAlignmentX(LEFT_ALIGNMENT); //setBorder(BorderFactory.createLineBorder(Color.BLACK)); bottomGUI.add(encrypt); bottomGUI.add(decrypt); bottomGUI.add(close); bottomGUI.add(info); } @Override public void actionPerformed(ActionEvent arg0) { // find source of the action Object source=arg0.getSource(); //if action is of such a type do the corresponding action if(source==close){ kill(); } else if(source==open){ //CHOOSE FILE File file1 =chooseFile(); String input1=readToString(file1); System.out.println(input1); left.setText(input1); } else if(source==decrypt){ //decrypt everything in Right Panel and output in left panel decrypt(); } else if(source==encrypt){ //encrypt everything in left panel and output in right panel encrypt(); } else if(source==info){ //show contents of info file in right panel doInfo(); } else { System.out.println("Error"); //throw new UnimplementedActionException(); } } private void doInfo() { // TODO Auto-generated method stub } private void encrypt() { // TODO Auto-generated method stub } private void decrypt() { // TODO Auto-generated method stub } private String readToString(File file) { FileReader fr = null; try { fr = new FileReader(file); } catch (FileNotFoundException e1) { e1.printStackTrace(); } BufferedReader br=new BufferedReader(fr); String line = null; try { line = br.readLine(); } catch (IOException e) { e.printStackTrace(); } String input=""; while(line!=null){ input=input+"\n"+line; try { line=br.readLine(); } catch (IOException e) { e.printStackTrace(); } } return input; } private File chooseFile() { //Create a file chooser final JFileChooser fc = new JFileChooser(); returnVal = fc.showOpenDialog(fc); return fc.getSelectedFile(); } private void kill() { System.exit(0); } public static void main(String[] args) { // TODO Auto-generated method stub MainGUI test=new MainGUI(); JFrame f=new JFrame("Tester"); f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); f.setJMenuBar(test.menubar); f.setPreferredSize(new Dimension(600,400)); //f.setUndecorated(true); f.add(test); f.pack(); f.setVisible(true); } }

    Read the article

  • Android - cant read TXT files from SDcard on real mashine?

    - by JustMe
    Hello! When I run the code bellow in the virtual android (1.5) it works well, TextSwitcher shows first 80 chars from each txt file from /sdcard/documents/ , but when I run it on my Samsung Galaxy i7500 (1.6) there are no contents in TextSwitcher, however in LogCat there are FileNames of txt files. My Code: public void getTxtFiles(){ //Scan /sdcard/documents and put .txt files in array File TxtFiles[] String path = Environment.getExternalStorageDirectory().toString()+"/documents/"; String files; File folder = new File(path); if(folder.exists()==false){if (!folder.mkdirs()) { Log.e("TAG", "Create dir in sdcard failed"); return; }} else{ File listOfFiles[] = folder.listFiles(); for (int i = 0; i < listOfFiles.length; i++) { if (listOfFiles[i].isFile()) { files = listOfFiles[i].getName(); if (files.endsWith(".txt") || files.endsWith(".TXT")) { if((files.length()-1)>i){resizeArray(TxtFiles, files.length()+10);} TxtFiles[i]=listOfFiles[i]; System.out.println(TxtFiles[i]); } } }} } private void updateCounter(int Pozicija) { if(Pozicija<0){Toast.makeText(getApplicationContext(), R.string.LastTxt, 5).show(); mCounter++;} else if(TxtFiles[mCounter]!=null){ TextToShow = getContents(TxtFiles[mCounter]); if(TextToShow.length()>80)TextToShow=TextToShow.substring(0, 80); mSwitcher.setText(TextToShow); System.out.println(Pozicija); } else mCounter--; } static public String getContents(File aFile) { //...checks on aFile are elided StringBuilder contents = new StringBuilder(); try { //use buffering, reading one line at a time //FileReader always assumes default encoding is OK! BufferedReader input = new BufferedReader(new FileReader(aFile)); try { String line = null; //not declared within while loop /* * readLine is a bit quirky : * it returns the content of a line MINUS the newline. * it returns null only for the END of the stream. * it returns an empty String if two newlines appear in a row. */ while (( line = input.readLine()) != null){ contents.append(line); contents.append(System.getProperty("line.separator")); } } finally { input.close(); } } catch (IOException ex){ ex.printStackTrace(); } return contents.toString(); } And I am able to write contents of those files though LogCat! Any ideas?

    Read the article

  • need some tips on Drupal $form value

    - by bert
    I got dpm($form) working. Nice! This is much better way to view data. I am still trying to figure out where stuff is coming from eg: location longitude & latitude. The word 'longitude' is referenced in 20 different places. I thought this was a likely place to isolate text box for this input field. dpm($form['#field_info']['field_store_latitude']['location_settings']['form']['fields']); Any tips on how to track down individual input elements?

    Read the article

  • Sending JSON collection to ASMX webservice

    - by Mironline
    I have got this json collection in page : var json= { "Elements": [ {"Alignment":null,"Bold":false}, {"Alignment":null,"Bold":false} ], "Front":true, "ThemeID":"9" }; I've generated this JSON in run-time & posted to page. my question is , What is the best solution to send this json to web-service using jQuery. should I use the JSON.stringify method and sent it as as string ? if yes what is the input type in web-service ? can I send it as an object to web-service and set the List<CusomeObject> as input ? in this case how can I implement that ?

    Read the article

  • How to pass values from client side to server side ?

    - by manojp1988
    Hi All, I got a situation to transfer values from jsp to servlet's action class. Previously we did it using <input type="hidden" id="name" value="manoj" /> we take this value in action class by request.getParameter("name"). But now we couldn't pass value like "Hi\n i am\n Manoj". Since it has new line included in the string we couldn't take it like this to action. So how I can take value like this to action or is there any way other than hidden input? Thanks .

    Read the article

  • Zend Framework decorator subform add a class tag to DD wrapper tag

    - by Samuele
    I have this form: class Request_Form_Prova extends Zend_Form { public function init() { $this->setMethod('post'); $SubForm_Step = new Zend_Form_SubForm(); $SubForm_Step->setAttrib('class','Step'); $this->addSubform($SubForm_Step, 'Chicco'); $PrivacyCheck = $SubForm_Step->createElement('CheckBox', 'PrivacyCheck'); $PrivacyCheck->setLabel('I have read and I agre bla bla...') ->setRequired(true) ->setUncheckedValue(''); $PrivacyCheck->getDecorator('Label')->setOption('class', 'inline'); $SubForm_Step->addElement($PrivacyCheck); $SubForm_Step->addElement('submit', 'submit', array( 'ignore' => true, 'label' => 'OK', )); } } That generate this HTML: <form enctype="application/x-www-form-urlencoded" method="post" action=""> <dl class="zend_form"> <dt id="Chicco-label">&nbsp;</dt> <dd id="Chicco-element"> <fieldset id="fieldset-Chicco" class="Step"> <dl> <dt id="Chicco-PrivacyCheck-label"><label for="Chicco-PrivacyCheck" class="inline required">I have read and I agre bla bla...</label></dt> <dd id="Chicco-PrivacyCheck-element"> <input type="hidden" name="Chicco[PrivacyCheck]" value=""><input type="checkbox" name="Chicco[PrivacyCheck]" id="Chicco-PrivacyCheck" value="1"> </dd> <dt id="submit-label">&nbsp;</dt> <dd id="submit-element"> <input type="submit" name="Chicco[submit]" id="Chicco-submit" value="OK"> </dd> </dl> </fieldset> </dd> </dl> </form> How can I add a class="Test" to the <dd id="Chicco-element"> elemnt? In order to have it like that: <dd id="Chicco-element" class="Test"> I thought something like that but it don't work: $SubForm_Step->getDecorator('DdWrapper')->setOption('class', 'Test'); OR $SubForm_Step->getDecorator('DtDdWrapper')->setOption('class', 'Test'); How can I do it? And last question: How can I wrap that DD and DT element of a SubForm in another DL element? Like that: ( second line ) <dl class="zend_form"> <dl> <dt id="Chicco-label">&nbsp;</dt> <dd id="Chicco-element"> <fieldset id="fieldset-Chicco" class="Step"> <dl> .......

    Read the article

  • Applying JQuery UI css to a textarea element

    - by Felix Guerrero
    Hi. I'm using JQuery UI for a web based development at the University. I got some forms that I put into a dialog, so I got elements like <label for="name">ID user</label><input type="text" name="iduser" size="15" id="iduser" class="text ui-widget-content ui-corner-all" maxlength=12 /> But I got some textarea elements like <label for="name">Description</label><textarea name="description" id="description" class="text ui-widget-content ui-corner-all" value=""></textarea> The issue: textarea is not taking the css as inputs does, I mean, I got corner rounder textarea as input texts but the font size and font family don't.

    Read the article

  • Better explanation of $this-> in this example please

    - by Doug
    Referring to this question: http://stackoverflow.com/questions/2035449/why-is-oop-hard-for-me class Form { protected $inputs = array(); public function makeInput($type, $name) { echo '<input type="'.$type.'" name="'.$name.'">'; } public function addInput($type, $name) { $this->inputs[] = array("type" => $type, "name" => $name); } public function run() { foreach($this->inputs as $array) { $this->makeInput($array['type'], $array['name']; } } } $form = new form(); $this->addInput("text", "username"); $this->addInput("text", "password");** Can I get a better explanation of what the $this->input[] is doing in this part: public function addInput($type, $name) { $this->inputs[] = array("type" => $type, "name" => $name); }

    Read the article

  • Ignoring unclosed tags from another <div>?

    - by Mike
    I have a website where members can input text using a limited subset of HTML. When a page is displayed that contains a user's text, if they have any unclosed tags, the formatting "bleeds" across into the next area. For example, if the user entered: Hi, my name is <b>John Then, the rest of the page will be bold. Ideally, there'd be someting I could do that would be this simple: <div contained>Hi, my name is <b>John</div> And no tags could bleed out of that div. Assuming there isn't anything this simple, how would I accomplish a similar effect? Or, is there something this easy? Importantly, I do not want to validate the user's input and return an error if they have unclosed tags, since I want to provide the "easiest" user interface possible for my users. Thanks!

    Read the article

  • Dynamically/recursively building hashes in Perl?

    - by Gaurav Dadhania
    I'm quite new to Perl and I'm trying to build a hash recursively and getting nowhere. I tried searching for tutorials to dynamically build hashes, but all I could find were introductory articles about hashes. I would be grateful if you point me towards the right direction or suggest a nice article/tutorial. I'm trying to read from a file which has paths in the form of one/two/three four five/six/seven/eight and I want to build a hash like VAR = { one : { two : { three : "" } } four : "" five : { six : { seven : { eight : "" } } } } The script I'm using currently is : my $finalhash = {}; my @input = <>; sub constructHash { my ($hashrf, $line) = @_; @elements = split(/\//, $line); if(@elements > 1) { $hashrf->{shift @elements} = constructHash($hashrf->{$elements[0]}, @elements ); } else { $hashrf->{shift @elements} = ""; } return $hashrf; } foreach $lines (@input) { $finalhash = constructHash($finalhash, $lines); }

    Read the article

  • Odd C interview question

    - by Brennan Vincent
    Hi guys. I found this problem on a site full of interview questions, and was stumped by it. Is there some preprocessor directive that allows one to read from standard input during compilation? Write a small C program, which while compiling takes another program from input terminal, and on running gives the result for the second program. (NOTE: The key is, think UNIX). Suppose, the program is 1.c Then, while compiling $ cc -o 1 1.c int main() { printf("Hello World\n"); } ^D $ ./1 Hello World

    Read the article

  • Multiple children in single form in rails

    - by CaptnCraig
    I have a model that has an arbitrary number of children entities. For simplicity lets call the entities Orders and Items. I would like to have a create Orders form where I input the order information, as well as add as many items as I want. If I click the "Add another item" button, a new set of form elements will be added to input the new data, amounts, etc.. I could hack this out in pure javascript, but I'm pretty sure there has to be a more magical, railsish way to do it, maybe with a partial view or something. I'm just a little too new to rails to know what it is. What is the best way to dynamically add the new form elements, and then to access them in the create controller?

    Read the article

  • Password checking in dojo

    - by Richard
    I want to check that two passwords are the same using Dojo. Here is the HTML I have: <form id="form" action="." dojoType="dijit.form.Form" / <pPassword: <input type="password" name="password1" id="password1" dojoType="dijit.form.ValidationTextBox" required="true" invalidMessage="Please type a password" /</p <pConfirm: <input type="password" name="password2" id="password2" dojoType="dijit.form.ValidationTextBox" required="true" invalidMessage="This password doesn't match your first password" /</p <div dojoType="dijit.form.Button" onClick="onSave"Save</div </form Here is the JavaScript I have so far: var onSave = function() { if(dijit.byId('form').validate()) { alert('Good form'); } else { alert('Bad form'); } } Thanks for your help. I could do this in pure JavaScript, but I'm trying to find the Dojo way of doing it.

    Read the article

  • SQL CLR and nullable datetime parameter

    - by toluca70
    I'm trying to write a SQLCLR function that takes a DateTime2 as input and returns another DateTime2. Based on this post I altered the parameter to be the C# type DateTime giving me the level of precision I require. However because the input can be null I would like it to be DateTime?; the return type as well. using System; using Microsoft.SqlServer.Server; namespace SqlServer.Functions { public class UserDefinedFunctions { [SqlFunction(DataAccess = DataAccessKind.None)] public static DateTime? GetLocalTimeFromGMT(DateTime? dateTime) { if (dateTime.HasValue) return DateTime.SpecifyKind(dateTime.Value, DateTimeKind.Utc).ToLocalTime(); else return (DateTime?)null; } } } The problem is I get the following error when I try to deploy: Error 1 Cannot find the type 'Nullable`1', because it does not exist or you do not have permission. SqlServer.Functions I'm using Sql Server 2008 and Visual Studio 2008.

    Read the article

  • Proper HTML technique to create an web form out of an image

    - by Lars
    I plan to create an interactive golf score card for my website (XHTML). (Btw. thats how such a scorecard looks like: ScoreCard). So at the end one should be able to insert a score for each hole in the appropriated input field in the virtual scorecard on the website. For me it is very important that the interactive scorecard really looks the same as the original (paper-) scorecard does and so my first approach was to scan and slice the scorecard image to reach that appearance. Here you can see the way I sliced the image: The idea was to insert HTML text input for each score field ending up with something like this: After I sliced the image I reconstructed it using the HTML . To do that I put the image slices as the cell background. <table> <tr> <td style="background: url("slice1.jpg") width="58px" height="25px"> <input type="text"></inputText> </td> </tr> ... </table> At the first moment this worked fine (as Gimp offers quite a nice feature for this). Then the problem was that I had to create a HTML table to create the exact layout. As you can see the lower part of the layout is split up into 3 columns. The middle column is split up into several (for each hole) rows. So the left and right column have to be spanned over those rows. Ok finally that worked, but it lead to some kind of scaling problem. If I zoom in or out on the table the middle column (and only that one) is not scaled the right way. Iam not able to fix this, and so I start doubting if this is the right technique for html image virtualization. Iam really no specialist in the area of creating websites, so I would really appriciate any help on this. Maybe there is a complete other and better technique to do that, as I think it is a common job in webcreation. I couldnt find any nice examples or tuts on that.

    Read the article

  • read java.security.key stored as object inside a file which is in jar

    - by Tal
    I saved a PublicKey instance in a file using ObjectOutputStream. This file is then stored inside a jar file which is then loaded by JBoss. I'm trying to read this file but it throws me an exception telling that it's not serializable. Here is the code : InputStream input = KeyLoader.class.getClassLoader().getResourceAsStream(resource); ObjectInputStream objectInputStream = new ObjectInputStream(input); Object obj = objectInputStream.readObject(); Key output = (Key) obj; objectInputStream.close(); return output; which throws me this exception An exception occurred: java.io.NotSerializableException

    Read the article

  • Why i get everytime the error-message that i've already sent the headers

    - by mikep
    Hey, i've another question about web-programming. I programmed a login script, but everytime when i try to login it says that i've send the header informations already. Here are the 2 files: <?php if($_GET['logout'] == 1) { setcookie('authorized', 1, time()-3600); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Login - photoAdminSite</title> </head> <style type="text/css"> body { text-align: center; font-family: helvetica; } #loginForm { padding: 1em; background: #e3e3e3; width: 260px; margin: 3em auto 0; text-align: left; } </style> <body> <div id="loginForm"> <form method="post" action="confirm_login_credentials.php"> <h2>LOGIN</h2> <p>Username: <input type="text" name="username" /></p> <p>Password: <input type="password" name="password" /></p> <p><input type="submit" value="Login" name="submit" /></p> </form> </div> </body> </html> <?php $username = $_POST['username']; $password = $_POST['password']; require 'database.php'; $q = "SELECT id FROM users_photoadminsite WHERE user_name = '$username' AND password = '$password'"; $result = $mysqli->query($q) or die(mysqli_error()); if (mysqli_num_rows($result) == 1) { setcookie('authorized', 1, 0); header("Location: index.php"); } else { header("Location: login.php"); } ?> i would be really happy about some helpful answers.

    Read the article

  • Spring 3 MVC : problem with form:errors and bindingresult

    - by Maxime ARNSTAMM
    Hi, I want to validate my inputs but i can't make it work : nothing appear on the page. My project is in java 5, so no JSR303 (@Valid). My only solution, if i'm not mistaken, is to use BindingResult. My controller : @Controller public class MyController { @RequestMapping(method = RequestMethod.POST, value = "myPage.html") public void myHandler(MyForm myForm, BindingResult result, Model model) { result.reject("field1", "error message 1"); } } My jsp : <form:form commandName="myForm" method="post"> <label>Field 1 : </label> <form:input path="field1" /> <form:errors path="field1" /> <input type="submit" value="Post" /> </form:form> What am i missing ? Thanks !

    Read the article

  • Help with Pixel Shader effect for brightness and contrast

    - by Hans
    What is a simple pixel shader script effect to apply brightness and contrast? I found this one, but it doesn't seem to be correct: sampler2D input : register(s0); float brightness : register(c0); float contrast : register(c1); float4 main(float2 uv : TEXCOORD) : COLOR { float4 color = tex2D(input, uv); float4 result = color; result = color + brightness; result = result * (1.0+contrast)/1.0; return result; } thanks!

    Read the article

  • jQuery mobile ajax login form authentication

    - by Jakub Zak
    I know i already asked simillar question, but now when I work with jQuery Mobile I can't figure it out. So I have this form: <div data-role="page" data-theme="a" id="login_page"> <div data-role="header" data-position="fixed"> <h1>****</h1> </div> <div data-role="content"> <form id="login_form" method="POST" data-ajax="false"> <label for="basic">Username:</label> <input type="text" name="name" id="username" value=""/> <label for="basic">Password:</label> <input type="password" name="password" id="password" value=""/> <input type="submit" value="Login" id="login" name="login"/> </form> </div> <div data-role="footer" data-position="fixed"> <div data-role="navbar"></div> </div> </div> And I need to submit Username and Password to php script, where php replies and send "success" or "failed". Here is php: <?php session_start(); $username = $_POST["name"]; $password = $_POST["password"]; include('mysql_connection.php'); mysql_select_db("jzperson_imesUsers", $con); $res1 = mysql_query("SELECT * FROM temp_login WHERE username='$username' AND password='$password'"); $count=mysql_num_rows($res1); if($count==1){ echo "success"; }else{ echo "failed"; } ?> And to do all this I want to use this script: $(document).ready(function() { $("form").submit(function(){ $.mobile.showPageLoadingMsg(); $.ajax({ url: "http://imes.jzpersonal.com/login_control.php", type: "POST", dataType: "jsonp", jsonp: "jsoncallback", data: $("form#login_form").serialize(), success: function( response ){ $.mobile.changePage( "http://imes.jzpersonal.com/user_panel.html"); } }); return false; }); }); But I can't make it work, I know I must have mistakes in there, I just can't find them, or better way to do it. Thank you in advance for any help.

    Read the article

< Previous Page | 279 280 281 282 283 284 285 286 287 288 289 290  | Next Page >