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  • Spring security - Reach users ID without passing it through every controller

    - by nilsi
    I have a design issue that I don't know how to solve. I'm using Spring 3.2.4 and Spring security 3.1.4. I have a Account table in my database that looks like this: create table Account (id identity, username varchar unique, password varchar not null, firstName varchar not null, lastName varchar not null, university varchar not null, primary key (id)); Until recently my username was just only a username but I changed it to be the email address instead since many users want to login with that instead. I have a header that I include on all my pages which got a link to the users profile like this: <a href="/project/users/<%= request.getUserPrincipal().getName()%>" class="navbar-link"><strong><%= request.getUserPrincipal().getName()%></strong></a> The problem is that <%= request.getUserPrincipal().getName()%> returns the email now, I don't want to link the user's with thier emails. Instead I want to use the id every user have to link to the profile. How do I reach the users id's from every page? I have been thinking of two solutions but I'm not sure: Change the principal to contain the id as well, don't know how to do this and having problem finding good information on the topic. Add a model attribute to all my controllers that contain the whole user but this would be really ugly, like this. Account account = entityManager.find(Account.class, email); model.addAttribute("account", account); There are more way's as well and I have no clue which one is to prefer. I hope it's clear enough and thank you for any help on this. ====== Edit according to answer ======= I edited Account to implement UserDetails, it now looks like this (will fix the auto generated stuff later): @Entity @Table(name="Account") public class Account implements UserDetails { @Id private int id; private String username; private String password; private String firstName; private String lastName; @ManyToOne private University university; public Account() { } public Account(String username, String password, String firstName, String lastName, University university) { this.username = username; this.password = password; this.firstName = firstName; this.lastName = lastName; this.university = university; } public String getUsername() { return username; } public String getPassword() { return password; } public String getFirstName() { return firstName; } public String getLastName() { return lastName; } public void setUsername(String username) { this.username = username; } public void setPassword(String password) { this.password = password; } public void setFirstName(String firstName) { this.firstName = firstName; } public void setLastName(String lastName) { this.lastName = lastName; } public University getUniversity() { return university; } public void setUniversity(University university) { this.university = university; } public int getId() { return id; } public void setId(int id) { this.id = id; } @Override public Collection<? extends GrantedAuthority> getAuthorities() { // TODO Auto-generated method stub return null; } @Override public boolean isAccountNonExpired() { // TODO Auto-generated method stub return false; } @Override public boolean isAccountNonLocked() { // TODO Auto-generated method stub return false; } @Override public boolean isCredentialsNonExpired() { // TODO Auto-generated method stub return false; } @Override public boolean isEnabled() { // TODO Auto-generated method stub return true; } } I also added <%@ taglib prefix="sec" uri="http://www.springframework.org/security/tags" %> To my jsp files and trying to reach the id by <sec:authentication property="principal.id" /> This gives me the following org.springframework.beans.NotReadablePropertyException: Invalid property 'principal.id' of bean class [org.springframework.security.authentication.UsernamePasswordAuthenticationToken]: Bean property 'principal.id' is not readable or has an invalid getter method: Does the return type of the getter match the parameter type of the setter? ====== Edit 2 according to answer ======= I based my application on spring social samples and I never had to change anything until now. This are the files I think are relevant, please tell me if theres something you need to see besides this. AccountRepository.java public interface AccountRepository { void createAccount(Account account) throws UsernameAlreadyInUseException; Account findAccountByUsername(String username); } JdbcAccountRepository.java @Repository public class JdbcAccountRepository implements AccountRepository { private final JdbcTemplate jdbcTemplate; private final PasswordEncoder passwordEncoder; @Inject public JdbcAccountRepository(JdbcTemplate jdbcTemplate, PasswordEncoder passwordEncoder) { this.jdbcTemplate = jdbcTemplate; this.passwordEncoder = passwordEncoder; } @Transactional public void createAccount(Account user) throws UsernameAlreadyInUseException { try { jdbcTemplate.update( "insert into Account (firstName, lastName, username, university, password) values (?, ?, ?, ?, ?)", user.getFirstName(), user.getLastName(), user.getUsername(), user.getUniversity(), passwordEncoder.encode(user.getPassword())); } catch (DuplicateKeyException e) { throw new UsernameAlreadyInUseException(user.getUsername()); } } public Account findAccountByUsername(String username) { return jdbcTemplate.queryForObject("select username, firstName, lastName, university from Account where username = ?", new RowMapper<Account>() { public Account mapRow(ResultSet rs, int rowNum) throws SQLException { return new Account(rs.getString("username"), null, rs.getString("firstName"), rs.getString("lastName"), new University("test")); } }, username); } } security.xml <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans" xsi:schemaLocation="http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd"> <http pattern="/resources/**" security="none" /> <http pattern="/project/" security="none" /> <http use-expressions="true"> <!-- Authentication policy --> <form-login login-page="/signin" login-processing-url="/signin/authenticate" authentication-failure-url="/signin?error=bad_credentials" /> <logout logout-url="/signout" delete-cookies="JSESSIONID" /> <intercept-url pattern="/addcourse" access="isAuthenticated()" /> <intercept-url pattern="/courses/**/**/edit" access="isAuthenticated()" /> <intercept-url pattern="/users/**/edit" access="isAuthenticated()" /> </http> <authentication-manager alias="authenticationManager"> <authentication-provider> <password-encoder ref="passwordEncoder" /> <jdbc-user-service data-source-ref="dataSource" users-by-username-query="select username, password, true from Account where username = ?" authorities-by-username-query="select username, 'ROLE_USER' from Account where username = ?"/> </authentication-provider> <authentication-provider> <user-service> <user name="admin" password="admin" authorities="ROLE_USER, ROLE_ADMIN" /> </user-service> </authentication-provider> </authentication-manager> </beans:beans> And this is my try of implementing a UserDetailsService public class RepositoryUserDetailsService implements UserDetailsService { private final AccountRepository accountRepository; @Autowired public RepositoryUserDetailsService(AccountRepository repository) { this.accountRepository = repository; } @Override public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException { Account user = accountRepository.findAccountByUsername(username); if (user == null) { throw new UsernameNotFoundException("No user found with username: " + username); } return user; } } Still gives me the same error, do I need to add the UserDetailsService somewhere? This is starting to be something else compared to my initial question, I should maybe start another question. Sorry for my lack of experience in this. I have to read up.

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  • Get paperclip to crop the image without validating

    - by Micke
    Hello fellow stackoverflow members. I have been following this guide to enable users to have their own avatar. But i have bumped in to a litle problem. When the user is cropping the image the model tries to validate all my validations. My user model looks like this: class User < ActiveRecord::Base has_attached_file :avatar, :styles => { :small => "100x100>", :large => "500x500>" }, :processors => [:cropper] attr_accessor :password, :crop_x, :crop_y, :crop_w, :crop_h attr_accessible :crop_x, :crop_y, :crop_w, :crop_h validates_confirmation_of :password validates_presence_of :password And when the user runs the crop updating script the user model tries to validate the password. But because i have no password field on the cropping page it can't validate it. Here is the updating of the crop: @user = User.find(current_user.id) if @user.update_attributes(params[:user]) flash[:notice] = "Successfully updated user." end How can i bypass this in a easy and clean way?

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  • Seeking enlightenment - global variables in AppEngine (aeoid.get_current_user())

    - by jerd
    Hello This may be a 'Python Web Programming 101' question, but I'm confused about some code in the aeoid project (http://github.com/Arachnid/aeoid). here's the code: _current_user = None def get_current_user(): """Returns the currently logged in user, or None if no user is logged in.""" global _current_user if not _current_user and 'aeoid.user' in os.environ: _current_user = User(None, _from_model_key=os.environ['aeoid.user']) return _current_user But my understanding was that global variables were, ehm, global! And so different requests from different users could (potentially) access and update the same value, hence the need for sessions, in order to store per-user, non-global variables. So, in the code above, what prevents one request from believing the current user is the user set by another request? Sorry if this is basic, it's just not how i thought things worked. Thanks

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  • Trouble with Rails has_many relationships

    - by Tchock
    I'm writing an app where a user can both create their own pages for people to post on, and follow posts on pages that users have created. Here is what my model relationships look like at the moment... class User < ActiveRecord::Base has_many :pages has_many :posts has_many :followings has_many :pages, :through => :followings, :source => :user class Page < ActiveRecord::Base has_many :posts belongs_to :user has_many :followings has_many :users, :through => :followings class Following < ActiveRecord::Base belongs_to :user belongs_to :page class Post < ActiveRecord::Base belongs_to :page belongs_to :user The trouble happens when I try to work my way down through the relationships in order to create a homepage of pages (and corresponding posts) a given user is following (similar to the way Twitter's user homepage works when you login - a page that provides you a consolidated view of all the latest posts from the pages you are following)... I get a "method not found" error when I try to call followings.pages. Ideally, I'd like to be able to call User.pages in a way that gets me the pages a user is following, rather than the pages they have created. I'm a programming and Rails newb, so any help would be much appreciated! I tried to search through as much of this site as possible before posting this question (along with numerous Google searches), but nothing seemed as specific as my problem...

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  • how to assign an object to smarty templates?

    - by keisimone
    i created a model object in PHP class User { public $title; public function changeTitle($newTitle){ $this->title = $newTitle; } } How do i expose the property of a User object in smarty just by assigning the object? I know i can do this $smarty->assign('title', $user->title); but my object has something like over 20 plus properties. Please advise. EDIT 1 the following didn't work for me. $smarty->assign('user', $user); OR $smarty->register_object('user', $user); then i try to {$user->title} nothing came out. Thank you.

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  • Model validation with enumerations

    - by Robert Koritnik
    I'm using DataAnnotations attributes to validate my model objects. My model class looks similar to this: public class MyModel { [Required] public string Title { get; set; } [Required] public List<User> Editors { get; set; } } public class User { public int Id { get; set; } [Required] public string FullName { get; set; } [Required] [DataType(DataType.Email)] public string Email { get; set; } } My controller action looks like: public ActionResult NewItem(MyModel data) { //... } User is presented with a view that has a form with: a text box with dummy name where users enter user's names. For each user they enter, there's a client script coupled with ajax that creates an <input type="hidden" name="data.Editors[0].Id" value="userId" /> for each user entered (enumeration index is therefore not always 0 as written here), so default model binder is able to consume and bind the form without any problems. a text box where users enter the title Since I'm using Asp.net MVC 2 RTM which does model validation instead of input validation I don't know how to avoid validation errors. The thing is I have to use BindAttribute on my controller action. I would have to either provide a white or a black list of properties. It's always a better practice to provide a white list. It's also more future proof. The problem My form works fine, but I get validation errors about user's FullName and Email properties since they are not provided. I also shouldn't feed them to the client (via ajax when user enters user data), because email is personal contact data and is not shared between users. If there was just a single user reference on MyModel I would write [Bind(Include = "Title, Editor.Id")] But I have an enumeration of them. How do I provide Bind white list to work with my model?

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  • Why isn't Expression Blend rendering my User Control? It's only showing XAML.

    - by unforgiven3
    I'm opening valid XAML within my VS2008 solution in Expression Blend 3 and it is only showing XAML when I try to open individual XAML files. My solution/projects all build and run correctly. When I go to View - Active Document View the Design View, Split View and XAML View options are all grayed out... which doesn't make much sense. I'm not much of a Blend user, but this has never happened before, and I'm coming up blank for how to fix it. Any ideas?

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  • PHP - Is possible to find if user is browsing from beind a Router and get Router Info

    - by Fábio Antunes
    Hello guys. I think it isn't possible just using PHP, but just to be sure. Is it possible for PHP to know if the user is accessing the web from behind a Router? And if yes, how can i get some information about that router, like: Router Name, Brand, Serial Number, ... Users connected in the same network. Can PHP also find the Local IP Address for the visitor in that Network? A few simple questions. To which i haven't found a solid answer, and i tough that some PHP genius could tell me. And teach me. Thanks for your help.

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  • Fighting Spam - What can I do as an: Email Administrator, Domain Owner, or User?

    - by Chris S
    This is a Canonical Question about Fighting Spam. Also related: How to stop people from using my domain to send spam? There are so many techniques and so much to know about fighting SPAM. What widely used techniques and technologies are available to Administrator, Domain Owners, and End Users to help keep the junk out of our inboxes? We're looking for an answer that covers different tech from various angles. The accepted answer should include a variety of technologies (eg SPF/SenderID, DomainKeys/DKIM, Graylisting, DNS RBLs, Reputation Services, Filtering Software [SpamAssassin, etc]); best practices (eg mail on Port 25 should never be allowed to relay, Port 587 should be used; etc), terminology (eg, Open Relay, Backscatter, MSA/MTA/MUA, Spam/Ham), and possibly other techniques.

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  • Why is the user.dir system property working in Java?

    - by Geo
    Almost every article I read told me that you can't have chdir in Java. The accepted answer to this question says you can't do it in Java. However, here's some of the stuff I tried : geo@codebox:~$ java -version java version "1.6.0_14" Java(TM) SE Runtime Environment (build 1.6.0_14-b08) Java HotSpot(TM) Client VM (build 14.0-b16, mixed mode, sharing) Here's a test class I'm using : import java.io.*; public class Ch { public static void main(String[] args) { System.out.println(new File(".").getAbsolutePath()); System.setProperty("user.dir","/media"); System.out.println(new File(".").getAbsolutePath()); } } geo@codebox:~$ pwd /home/geo geo@codebox:~$ java Ch /home/geo/. /media/. Please explain why this worked. Can I use this from now on and expect it to work the same way on all platforms?

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  • authlogic in Rails

    - by Adnan
    Hello, I am using the authlogic gem for authentication. I have followed the steps at: http://railscasts.com/episodes/160-authlogic I have the following code: # config/environment.rb config.gem "authlogic" # models/user.rb acts_as_authentic # users_controller.rb def create @user = User.new(params[:user]) if @user.save flash[:notice] = "Registration successful." redirect_to root_url else render :action => 'new' end end def edit @user = current_user end def update @user = current_user if @user.update_attributes(params[:user]) flash[:notice] = "Successfully updated profile." redirect_to root_url else render :action => 'edit' end end # user_sessions_controller.rb def create @user_session = UserSession.new(params[:user_session]) if @user_session.save flash[:notice] = "Successfully logged in." redirect_to root_url else render :action => 'new' end end def destroy @user_session = UserSession.find @user_session.destroy flash[:notice] = "Successfully logged out." redirect_to root_url end # application_controller.rb filter_parameter_logging :password helper_method :current_user private def current_user_session return @current_user_session if defined?(@current_user_session) @current_user_session = UserSession.find end def current_user return @current_user if defined?(@current_user) @current_user = current_user_session && current_user_session.record end # config/routes.rb map.login "login", :controller => "user_sessions", :action => "new" map.logout "logout", :controller => "user_sessions", :action => "destroy" I got it all working, except I would like to have a user_id in session so I can track which user posted which post, where should I set it?

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  • Why does a wired network slow down with user increase?

    - by Ed Briscoe
    If you had a wired network, 20 PCs hooked up to a 100 Mbit/sec switch (same onboard ethernet port speed) and you were just sending some test data round. What is the technical explanation as to why 20 machines sending test data around this network to each other is slower than one to one? I mean I know a busy network means it's slower but I'm really trying to understand some more technical details. Thanks for any help

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  • Passenger: "Missing these required gems redgreen"

    - by Michael Stum
    Hello, total ruby newbie, trying to setup a Rails/MongoDB application on Mac OS X Snow leopard. Installed Ruby 1.9.1 and RubyGems 1.3.7, which ruby and which gem point to the same directory. I'm using the Snow Leopard built-in apache and Passenger 2.2.11. I'm using the rails template from the mongo-site which seems to work okay overall. The exact error that passenger gives me is: /Users/User/Sites/feuerapp/vendor/rails/railties/lib/rails/gem_dependency.rb:119:Warning: Gem::Dependency#version_requirements is deprecated and will be removed on or after August 2010. Use #requirement **Notice: C extension not loaded. This is required for optimum MongoDB Ruby driver performance. You can install the extension as follows: gem install bson_ext If you continue to receive this message after installing, make sure that the bson_ext gem is in your load path and that the bson_ext and mongo gems are of the same version. Missing these required gems: redgreen You're running: ruby 1.9.1.376 at /usr/local/bin/ruby rubygems 1.3.7 at /Users/User/.gem/ruby/1.9.1, /usr/local/lib/ruby/gems/1.9.1 Runrake gems:installto install the missing gems. The weird thing is that redgreen is installed and looks fine to me: Dahlia:feuerapp User$ ls -la vendor/gems/ total 0 drwxr-xr-x 7 User staff 238 May 18 22:56 . drwxr-xr-x 5 User staff 170 May 18 23:00 .. drwxr-xr-x 11 User staff 374 May 18 22:56 factory_girl-1.2.4 drwxr-xr-x 11 User staff 374 May 18 22:56 mocha-0.9.8 drwxr-xr-x 7 User staff 238 May 18 22:56 mongo_mapper-0.7.6 drwxr-xr-x 7 User staff 238 May 18 22:56 redgreen-1.2.2 drwxr-xr-x 11 User staff 374 May 18 22:56 shoulda-2.10.3 Commenting out this line in environment.rb "solves" the issue, but that's not really want I want: config.gem 'redgreen' I don't understand anything of gems yet, but from my limited understanding, redgreen should be there and found?

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  • Receive MMS images and make album using iamge using j2me

    - by Abdul Basit
    I am trying to made application which receive MMS images and make a album from them user can view the pictures while running this application. I am facing problem while running application on mobile. while this application is fully working in wireless tookit emulator. Please guide me to fix this problem.`//package hello; import javax.microedition.midlet.; import javax.microedition.lcdui.; import javax.wireless.messaging.*; import java.io.IOException; import java.util.Vector; import javax.microedition.io.Connector; import javax.microedition.lcdui.Display; //, ItemStateListener public class MMSS extends MIDlet implements CommandListener, Runnable, MessageListener { //-----------------------------------Receive MMS --------------------------- private Thread mReceiver = null; private boolean mEndNow = false; private Message msg = null; String msgReceived = null; private Image[] receivedImage = new Image[5]; private Command mExitCommand = new Command("Exit", Command.EXIT, 2); private Command mRedCommand = new Command("Back", Command.SCREEN, 1); private Command mBlueCommand = new Command("Next", Command.SCREEN, 1); private Command mPlay = new Command("Play", Command.SCREEN, 1); protected static final String DEFAULT_IMAGE = "/MMSS_logo.jpg"; //protected static final String DEFAULT_IMAGE = "/wait.png"; private Display mDisplay = null; //protected ImageItem mColorSquare = null; protected Image mInitialImage = null; private String mAppID = "MMSMIDlet"; private TextField imageName = null; //private Form mForm = null; private int count = 0; private int next = 0; private Integer mMonitor = new Integer(0); //----------------------------------- End Receive MMS --------------------------- private boolean midletPaused = false; private Command exitCommand; private Command exitCommand1; private Command backCommand; private Form form; private StringItem stringItem; private ImageItem imageItem; private Image image1; private Alert alert; private List locationList; private Alert cannotAddLocationAlert; public MMSS() { } /** * Initilizes the application. * It is called only once when the MIDlet is started. The method is called before the startMIDlet method. */ private void initialize() { } /** * Performs an action assigned to the Mobile Device - MIDlet Started point. */ public void startMIDlet() { // write pre-action user code here switchDisplayable(null, getForm()); // write post-action user code here } /** * Performs an action assigned to the Mobile Device - MIDlet Resumed point. */ public void resumeMIDlet() { } /** * Switches a current displayable in a display. The display instance is taken from getDisplay method. This method is used by all actions in the design for switching displayable. * @param alert the Alert which is temporarily set to the display; if null, then nextDisplayable is set immediately * @param nextDisplayable the Displayable to be set / public void switchDisplayable(Alert alert, Displayable nextDisplayable) {//GEN-END:|5-switchDisplayable|0|5-preSwitch // write pre-switch user code here Display display = getDisplay();//GEN-BEGIN:|5-switchDisplayable|1|5-postSwitch if (alert == null) { display.setCurrent(nextDisplayable); } else { display.setCurrent(alert, nextDisplayable); } } /* * Called by a system to indicated that a command has been invoked on a particular displayable. * @param command the Command that was invoked * @param displayable the Displayable where the command was invoked */ public void commandAction(Command command, Displayable displayable) { // write pre-action user code here if (displayable == form) { if (command == exitCommand) { // write pre-action user code here exitMIDlet(); // write post-action user code here } } // write post-action user code here } /** * Returns an initiliazed instance of exitCommand component. * @return the initialized component instance */ public Command getExitCommand() { if (exitCommand == null) { // write pre-init user code here exitCommand = new Command("Exit", Command.EXIT, 0); // write post-init user code here } return exitCommand; } /** * Returns an initiliazed instance of form component. * @return the initialized component instance */ public Form getForm() { if (form == null) { // write pre-init user code here form = new Form("Welcome to MMSS", new Item[] { getStringItem(), getImageItem() }); form.addCommand(getExitCommand()); form.setCommandListener(this); // write post-init user code here } return form; } /** * Returns an initiliazed instance of stringItem component. * @return the initialized component instance */ public StringItem getStringItem() { if (stringItem == null) { // write pre-init user code here stringItem = new StringItem("Hello", "Hello, World!"); // write post-init user code here } return stringItem; } /** * Returns an initiliazed instance of exitCommand1 component. * @return the initialized component instance / public Command getExitCommand1() { if (exitCommand1 == null) { // write pre-init user code here exitCommand1 = new Command("Exit", Command.EXIT, 0); // write post-init user code here } return exitCommand1; } /* * Returns an initiliazed instance of imageItem component. * @return the initialized component instance */ public ImageItem getImageItem() { if (imageItem == null) { // write pre-init user code here imageItem = new ImageItem("imageItem", getImage1(), ImageItem.LAYOUT_CENTER | Item.LAYOUT_TOP | Item.LAYOUT_BOTTOM | Item.LAYOUT_VCENTER | Item.LAYOUT_EXPAND | Item.LAYOUT_VEXPAND, "");//GEN-LINE:|26-getter|1|26-postInit // write post-init user code here } return imageItem; } /** * Returns an initiliazed instance of image1 component. * @return the initialized component instance */ public Image getImage1() { if (image1 == null) { // write pre-init user code here try { image1 = Image.createImage("/B.jpg"); } catch (java.io.IOException e) { e.printStackTrace(); } // write post-init user code here } return image1; } /** * Returns a display instance. * @return the display instance. */ public Display getDisplay () { return Display.getDisplay(this); } /** * Exits MIDlet. */ public void exitMIDlet() { switchDisplayable (null, null); destroyApp(true); notifyDestroyed(); } /** * Called when MIDlet is started. * Checks whether the MIDlet have been already started and initialize/starts or resumes the MIDlet. */ public void startApp() { if (midletPaused) { resumeMIDlet (); } else { initialize (); startMIDlet (); } midletPaused = false; /////////////////////////////////////////////////////////////////////// /////////////////////////////////////////////////////////////////////// try { conn = (MessageConnection) Connector.open("mms://:" + mAppID); conn.setMessageListener(this); } catch (Exception e) { System.out.println("startApp caught: "); e.printStackTrace(); } if (conn != null) { startReceive(); } /////////////////////////////////////////////////////////////////////// /////////////////////////////////////////////////////////////////////// } /** * Called when MIDlet is paused. */ public void pauseApp() { midletPaused = true; mEndNow = true; try { conn.setMessageListener(null); conn.close(); } catch (IOException ex) { System.out.println("pausetApp caught: "); ex.printStackTrace(); } } /** * Called to signal the MIDlet to terminate. * @param unconditional if true, then the MIDlet has to be unconditionally terminated and all resources has to be released. */ public void destroyApp(boolean unconditional) { mEndNow = true; try { conn.close(); } catch (IOException ex) { System.out.println("destroyApp caught: "); ex.printStackTrace(); } } private void startReceive() { mEndNow = false; //---- Start receive thread mReceiver = new Thread(this); mReceiver.start(); } protected MessageConnection conn = null; protected int mMsgAvail = 0; // -------------------- Get Next Images ------------------------------------ private void getMessage() { synchronized(mMonitor) { mMsgAvail++; mMonitor.notify(); } } // -------------------- Display Images Thread ------------------------------ public void notifyIncomingMessage(MessageConnection msgConn) { if (msgConn == conn) getMessage(); } public void itemStateChanged(Item item) { throw new UnsupportedOperationException("Not supported yet."); } class SetImage implements Runnable { private Image img = null; public SetImage(Image inImg) { img = inImg; } public void run() { imageItem.setImage(img); imageName.setString(Integer.toString(count)); } } public void run() { mMsgAvail = 0; while (!mEndNow) { synchronized(mMonitor) { // Enter monitor if (mMsgAvail <= 0) try { mMonitor.wait(); } catch (InterruptedException ex) { } mMsgAvail--; } try { msg = conn.receive(); if (msg instanceof MultipartMessage) { MultipartMessage mpm = (MultipartMessage)msg; MessagePart[] parts = mpm.getMessageParts(); if (parts != null) { for (int i = 0; i < parts.length; i++) { MessagePart mp = parts[i]; byte[] ba = mp.getContent(); receivedImage[count] = Image.createImage(ba, 0, ba.length); } Display.getDisplay(this).callSerially(new SetImage(receivedImage[count])); } } } catch (IOException e) { System.out.println("Receive thread caught: "); e.printStackTrace(); } count++; } // of while } } `

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  • How to do custom display and auto-select in django admin multi-select field?

    - by rsp
    I'm new to django, so please feel free to tell me if I'm doing this incorrectly. I am trying to create a django ordering system. My order model: class Order(models.Model): ordered_by = models.ForeignKey(User, limit_choices_to = {'groups__name': "Managers", 'is_active': 1}) in my admin ANY user can enter an order, but ordered_by must be someone in the group "managers" (this is the behavior I want). Now, if the logged in user happens to be a manager I want it to automatically fill in the field with that logged in user. I have accomplished this by: class OrderAdmin(admin.ModelAdmin): def formfield_for_foreignkey(self, db_field, request, **kwargs): if db_field.name == "ordered_by": if request.user in User.objects.filter(groups__name='Managers', is_active=1): kwargs["initial"] = request.user.id kwargs["empty_label"] = "-------------" return db_field.formfield(**kwargs) return super(OrderAdmin, self).formfield_for_foreignkey(db_field, request, **kwargs) This also works, but the admin puts the username as the display for the select box by default. It would be nice to have the user's real name listed. I was able to do it with this: class UserModelMultipleChoiceField(forms.ModelMultipleChoiceField): def label_from_instance(self, obj): return obj.first_name + " " + obj.last_name class OrderForm(forms.ModelForm): ordered_by = UserModelChoiceField(queryset=User.objects.all().filter(groups__name='Managers', is_active=1)) class OrderAdmin(admin.ModelAdmin): form = OrderForm My problem: I can't to both of these. If I put in the formfield_for_foreignkey function and add form = OrderForm to use my custom "UserModelChoiceField", it puts the nice name display but it won't select the currently logged in user. I'm new to this, but my guess is that when I use UserModelChoiceField it "erases" the info passed in via formfield_for_foreignkey. Do I need to use the super() function somehow to pass on this info? or something completely different?

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  • Activity tracking usecase for login tracking.

    - by Mdillion
    Creating an activity tracking system for a social site. All user activiti from pooint of login til logoff are to be tracked. This means the first use case is the user's login. Every activity will have the same format so once I figure out how to track one activity then I can create chema for all activities. Currently for login I have steps like: Two solutions I have: Activity 1: User attempts to login Activity 2 A: User has successfully logged in Activity 2 B: User failed to login. Activity 2 B A: User failed to login due to invalid password Activity 2 B B: User failed to login due to locked account. OR Activty 1: User login - with result = Pass or Fail and if Fail reason = flag_id of reason. Accordingly I have to create the schema. For now I have it like this: activity_id object_id (fk) session_id (fk) user_id (fk) flag_id (fk) created_dt friend_id (fk) result (pass/fail) But ofcourse this a work in progress.

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  • Best way to handle multiple tables to replace one big table in Rails? (e.g. 'Books1', 'Books2', etc.

    - by mikep
    Hello, I've decided to use multiple tables for an entity (e.g. Books1, Books2, Books3, etc.), instead of just one main table which could end up having a lot of rows (e.g. just Books). I'm doing this to try and to avoid a potential future performance drop that could come with having too many rows in one table. With that, I'm looking for a good way to handle this in Rails, mainly by trying to avoid loading a bunch of unused associations. (I know that I could use a partition for this, but, for now, I've decided to go the 'multiple tables' route.) Each user has their books placed into a specific table. The actual book table is chosen when the user is created, and all of their books go into the same table. I'm going to split the adds across the tables. The goal is to try and keep each table pretty much even -- but that's a different issue. One thing I don't particularly want to have is a bunch of unused associations in the User class. Right now, it looks like I'd have to do the following: class User < ActiveRecord::Base has_many :books1, :books2, :books3, :books4, :books5 end class Books1 < ActiveRecord::Base belongs_to :user end class Books2 < ActiveRecord::Base belongs_to :user end class Books3 < ActiveRecord::Base belongs_to :user end I'm assuming that the main performance hit would come in terms of memory and possibly some method call overhead for each User object, since it has to load all of those associations, which in turn creates all of those nice, dynamic model accessor methods like User.find_by_. But for each specific user, only one of the book tables would be usable/applicable, since all of a user's books are stored in the same table. So, only one of the associations would be in use at any time and any other has_many :bookX association that was loaded would be a waste. For example, with a user.id of 2, I'd only need books3.find_by_author('Author'), but the way I'm thinking of setting this up, I'd still have access to Books1..n. I don't really know Ruby/Rails does internally with all of those has_many associations though, so maybe it's not so bad. But right now I'm thinking that it's really wasteful, and that there may just be a better, more efficient way of doing this. So, a few questions: 1) Is there's some sort of special Ruby/Rails methodology that could be applied to this 'multiple tables to represent one entity' scheme? Are there any 'best practices' for this? 2) Is it really bad to have so many unused has_many associations for each object? Is there a better way to do this? 3) Does anyone have any advice on how to abstract the fact that there's multiple book tables behind a single books model/class? For example, so I can call books.find_by_author('Author') instead of books3.find_by_author('Author'). Thank you!

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  • Custom Membership in ASP.NET MVC 2

    - by Interfector
    Hello, I'm trying to make my Custom Membership starting from ASP.NET's. I have a users table created by me which has as Primary Key a Guid UserId, exactly the sames as ASP.NET's default user and membership table. I have all the Foreign Key relationships built. However, I cannot insert the user into my custom users table. The data gets inserted correctly into the default ASP.NET's tables. I have tried the following scenarios: First version Receive the user model from POST call the CreateUser method of the Membership.class (stuff gets inserted) without modifying the user object, I try to insert it using EF's AddObject I receive the following error: "Cannot insert the value NULL into column 'LoweredUserName', table 'asp.dbo.aspnet_Users'; column does not allow nulls. INSERT fails.\r\nThe statement has been terminated."} System.Exception {System.Data.SqlClient.SqlException The error actually makes sense as EF's AddObject doesn't know how to create the LoweredUserName value, and I don't want to do it, this is ASP.NET's job. Second version Receive the user model from POST call the CreateUser method of the Membership.class (stuff gets inserted) Get the Guid of the freshly inserted system user get the ASP.NET's User object and overwrite that of user.User get the ASP.NET's Membership object and overwrite that of user.Membership (remember the FKs) try again EF's AddObject new error {"The relationship between the two objects cannot be defined because they are attached to different ObjectContext objects."} System.Exception {System.InvalidOperationException} Don't know what this is, but it certenly doesn't make any sense for me. After some googleing I think that it has something to do with the context, but as I'm a beginner I don't know how to fix it. Any ideeas on how to accomplish this task are more than welcomed, especially if they follow some good practices. Thx

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  • Javascript, Can I "redirect" user in onbeforeunload? If cant, how to...

    - by kanayaki
    Is it possible to redirect to another page when userclose browser? Attempts: I tried onunload, does not work window.onunload = function redirect(){...} I also tried another method, it does not work as well: window.onbeforeunload = redirect(){...} <body onbeforeunload="return false; redirecty()"> The 3rd method, i want to cancel the onbeforeunload (means delay closing the browser), the I call the redirect function, window.confirm, if yes redirect, if no then close the browser. But it does not work as well. Is there any other way?? Run out of ideas... -- Prompt to let user select whether to redirect to new page when he/she close the browser -- This is the first time, I could not get best answer in stackoverflow :(

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  • Postfix relay to multiple servers and multiple users

    - by Frankie
    I currently have postfix configured so that all users get relayed by the local machine with the exception of one user that gets relayed via gmail. To that extent I've added the following configuration: /etc/postfix/main.cf # default options to allow relay via gmail smtp_use_tls=yes smtp_sasl_auth_enable = yes smtp_tls_CAfile = /etc/ssl/certs/ca-bundle.crt smtp_sasl_security_options = noanonymous # map the relayhosts according to user sender_dependent_relayhost_maps = hash:/etc/postfix/relayhost_maps # keep a list of user and passwords smtp_sasl_password_maps = hash:/etc/postfix/sasl_passwd /etc/postfix/relayhost_maps user-one@localhost [smtp.gmail.com]:587 /etc/postfix/sasl_passwd [smtp.gmail.com]:587 [email protected]:user-one-pass-at-google I know I can map multiple users to multiple passwords using smtp_sasl_password_maps but that would mean that all relay would be done by gmail where I specifically want all relay to be done by the localhost with the exception of some users. Now I would like to have a user-two@localhost (etc) relay via google with their own respective passwords. Is that possible?

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  • How to execute with /bin/false shell

    - by Amar
    I am trying to setup per-user fastcgi scripts that will run each on a different port and with a different user. Here is example of my script: #!/bin/bash BIND=127.0.0.1:9001 USER=user PHP_FCGI_CHILDREN=2 PHP_FCGI_MAX_REQUESTS=10000 etc... However, if I add user with /bin/false (which I want, since this is about to be something like shared hosting and I don't want users to have shell access), the script is run under 1001, 1002 'user' which, as my Google searches showed, might be a security hole. My question is: Is it possible to allow user(s) to execute shell scripts but disable them so they cannot log in via SSH?

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  • How can I make two "user" editable areas in Wordpress?

    - by thatryan
    Hi all, is there a way to have two posting areas in Wordpress, for clients who can not go into any HTML? Basically the template has 3 columns. One is vertical nav, thats no prob. Second is like a "sidebar" but where the main post will go, a skinny column. Third is large, "main area" size, but will also be user editable content. Does that make sense? Has anyone done something like this before? Thank you.

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  • My server is slower than the average user's computer, should I still offload Access queries to SQL Server? [closed]

    - by andrewb
    Possible Duplicate: How do you do Load Testing and Capacity Planning for Databases I have a database set up with MS Access 2007 front ends and an SQL Server 2005 back end. At the moment, all the queries are saved in the front end as I've only recently moved to an SQL Server backend. I'm wondering how much of those queries I should save as stored procedures/views on SQL Server. About the system The number of concurrent users is only a handful, though it could be as high as 25 at one time (very unlikely). The average computer has an Intel i3-2120 CPU running at 3.3 GHz, which gets a PassMark score of 3,987, whilst the server has an Intel Xeon E5335 running at 2.0 GHz, which gets a PassMark score of 2,637. Always an awkward situation when an i3 outperforms a Xeon... though the i3 is from Q1 2011 and the Xeon is Q2 2009. There is potential for a server upgrade in the future, though it wouldn't come easy. I'm inclined to move the queries to the back end, as they are beginning to take noticeable time and I figure that is a better way of doing things. I like the idea of throwing everything at the server, then pushing for a server upgrade. It makes more sense in my mind to be upgrading one server rather than 30 PCs. Or am I being overzealous? Why my question isn't a duplicate It seems that my question has been misinterpreted and labelled a duplicate of quite a different question, one about testing and capacity planning. I'll try explain how my question is very different from the linked question. The crux of my question is something like "Even though my server is technically slower, is it better to have it doing more of the queries?" There's two ways that people could have answered this: I agree the server is going to be slower, but the extra benefits of such and such (like the less Access the better) means you should move most to the server anyway. (OR no it doesn't outweigh the benefit, keep them in Access) Actually the server will be faster because of such and such. I'm hoping that people out there could provide some answers like this, and the question in the dupe link doesn't really provide either of these answers. Ok sure, I suppose I could do extensive performance testing to compare Access queries running on a local machine to SQL Server queries running on the server, but that sounds like a very hard task (particularly performance testing of access) compared to someone giving some quick general guidance, and again, my question is looking for a lot more than immediate performance benefit.

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