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  • failed to load source for

    - by ohana
    hi, I have a php project which used to work well, yesterday it suddenly failed, from the login page i cannot actually get into the system with the right username/password. i checked it in Firebug, it said: failed to load source for the php file that's supposed to load after login.what could be wrong? anyone have any idea? Thanks.

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  • Combined sign in and registration page?

    - by Ryan
    This is somewhat against rails convention but I am trying to have one controller that manages both user session authentication and user registration. I am having troubles figuring out how to go about this. So far I am merging the User Controller and the Sessions Controller and having the 'new' method deliver both a new usersession and a new user instance. With the new routes in rails 3 though, I am having trouble figuring out how to generate forms for these items. Below is the code: user_controller.rb class UserController < ApplicationController def new @user_session = UserSession.new @user = User.new end def create_user @user = User.new(params[:user]) if @user.save flash[:notice] = "Account Successfully Registered" redirect_back_or_default signup_path else render :action => new end end def create_session @user_session = UserSession.new(params[:user_session]) if @user_session.save flash[:notice] = "Login successful!" redirect_back_or_default login_path else render :action => new end end end views/user/new.html.erb <div id="login_section"> <% form_for @user_session do |f| -%> <%= f.label :email_address, "Email Address" %> <%= f.text_field :email %> <%= f.label :password, "Password" %> <%= f.text_field :password %> <%= f.submit "Login", :disable_with => 'Logining...' %> <% end -%> </div> <div id="registration_section"> <% form_for @user do |f| -%> <%= f.label :email_address, "Email Address" %> <%= f.text_field :email %> <%= f.label :password, "Password" %> <%= f.text_field :password %> <%= f.label :password_confirmation, "Password Confirmation" %> <%= f.text_field :password_confirmation %> <%= f.submit "Register", :disable_with => 'Logining...' %> <% end -%> </div> I imagine I will need to use :url = something for those forms, but I am unsure how to specify. Within routes.rb I have yet to specify either Usersor UserSessions as resources (not convinced that this is the best way to do it... but I could be). I would like, however, the registration and login on the same page and have implemented this by doing the following: routes.rb match 'signup' => 'user#new' match 'login' => 'user#new' What's the best way to go about solving this?

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  • MySQL subqueries

    - by swamprunner7
    Can we do this query without subqueries? SELECT login, post_n, (SELECT SUM(vote) FROM votes WHERE votes.post_n=posts.post_n)AS votes, (SELECT COUNT(comments.post_n) FROM comments WHERE comments.post_n=posts.post_n)AS comments_count FROM users, posts WHERE posts.id=users.id AND (visibility=2 OR visibility=3) ORDER BY date DESC LIMIT 0, 15 tables: Users: id, login Posts: post_n, id, visibility Votes: post_n, vote id — it`s user id, Users the main table.

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  • How to programmatically logout in acegi plugin in Grails?

    - by firnnauriel
    Is there a similar logic for logout using this login code: // login account def autht = new AuthToken(username, password) def authtoken = daoAuthenticationProvider.authenticate(autht) SecurityContextHolder.context.authentication = authtoken I checked LogoutController and this is the only logic for logout: redirect(uri: '/j_spring_security_logout') Any idea? Thanks

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  • how to clear the the activity stack in android.

    - by Sam
    Hi, im having following application flow in my android app, Login-Home-screen1-screen2-screen3-screen4- logout In the screen4 i've a log out button,which allow user to logout from the application and re login.when i re-logn to the app previous data still be shown,is there way to start the application in fresh when user log out from the app NOTE: all the above activities launch mode set to "single task", regards, Sam.

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  • Loading Modules in Angular

    - by SL Dev
    I'm new to AngularJS. In my efforts to learn, I've relied on the AngularJS tutorials. Now, I'm trying to build an app using the AngularSeed project template. I'm trying to make my project as modular as possible. For that reason, my controllers are broken out into several files. Currently, I have the following: /app index.html login.html home.html javascript app.js loginCtrl.js homeCtrl.js my app.js file has the following: 'use strict'; var app = angular.module('site', ['ngRoute']); app.config(function($routeProvider, $locationProvider) { $locationProvider.html5Mode(true); $routeProvider.when('/login', {templateUrl: 'app/login.html', controller:'loginCtrl'}); $routeProvider.when('/home', {templateUrl: 'app/home.html', controller:'homeCtrl'}); $routeProvider.otherwise({redirectTo: '/login'}); }); my loginCtrl.js file is very basic at the moment. It only has: 'use strict'; app.controller('loginCtrl', function loginCtrl($scope) { } ); My homeCtrl.js is almost the same, except for the name. It looks like the following: 'use strict'; app.controller('homeCtrl', function homeCtrl($scope) { } ); My index.html file is the angularSeed index-async.html file. However, when I load the dependencies, I have the following: // load all of the dependencies asynchronously. $script([ 'http://ajax.googleapis.com/ajax/libs/angularjs/1.2.0-rc.3/angular.min.js', 'http://ajax.googleapis.com/ajax/libs/angularjs/1.2.0-rc.3/angular-route.min.js', 'javascript/app.js', 'javascript/loginCtrl.js', 'javascript/homeCtrl.js' ], function() { // when all is done, execute bootstrap angular application angular.bootstrap(document, ['site']); }); My problem is, sometimes my app works and sometimes it doesn't. It's almost like something gets loaded before something else. Occasionally, I receive this error. Other times, I get an error in the console window that says: 'Uncaught ReferenceError: app is not defined' in loginCtrl.js. Sometimes it happens with homeCtrl.js. What am I doing wrong? It feels like I need to have my controllers in a module and pass that module in my app.config in the app.js file. However, a) I'm not sure if that allowed and b) I'm not sure how to do it.

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  • Cross-site request forgery protections: Where do I put all these lines?

    - by brilliant
    Hello, I was looking for a python code that would be able to log in from "Google App Engine" to some of my accounts on some websites (like yahoo or eBay) and was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() Unfortunately, this code didn't work, so I asked another question here and one supporter among other things said this: "You send MD5 hash and not plain password. Also you'd have to play along with all kinds of CSRF protections etc. that they're implementing. Look: <input type="hidden" name=".tries" value="1"> <input type="hidden" name=".src" value="ym"> <input type="hidden" name=".md5" value=""> <input type="hidden" name=".hash" value=""> <input type="hidden" name=".js" value=""> <input type="hidden" name=".last" value=""> <input type="hidden" name="promo" value=""> <input type="hidden" name=".intl" value="us"> <input type="hidden" name=".bypass" value=""> <input type="hidden" name=".partner" value=""> <input type="hidden" name=".u" value="bd5tdpd5rf2pg"> <input type="hidden" name=".v" value="0"> <input type="hidden" name=".challenge" value="5qUiIPGVFzRZ2BHhvtdGXoehfiOj"> <input type="hidden" name=".yplus" value=""> <input type="hidden" name=".emailCode" value=""> <input type="hidden" name="pkg" value=""> <input type="hidden" name="stepid" value=""> <input type="hidden" name=".ev" value=""> <input type="hidden" name="hasMsgr" value="0"> <input type="hidden" name=".chkP" value="Y"> <input type="hidden" name=".done" value="http://mail.yahoo.com"> <input type="hidden" name=".pd" value="ym_ver=0&c=&ivt=&sg="> I am not quite sure where he got all these lines from and where in my code I am supposed to add them. Do You have any idea? I know I was supposed to ask him this question first, and I did, but he never returned, so I decided to ask a separate question here.

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  • iis7 integrated mode asp.net 4.0 forms authentication problem using IE8

    - by FiveTools
    Anyone experience any issues with IIS7, integrated mode forms authentication while using IE8? I have a website with a login form, once logged in, any postback causes the user to be logged out. This doesn't even happen consistently, sometimes I can login and not experience this issue, other times it happens instantly. I can not replicate the problem in any other browser and I cannot replicate on my development machine running / debugging vs2010.

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  • Linq, how to specify timestamp condition?

    - by 5YrsLaterDBA
    I have a logins table which records all login and logout activities. I want to look at all login activities of a particular user within 24 hrs. how to do it? something like this: var records = from record in db.Logins where record.Users.UserId == userId && record.Timestamp <= (DateTime.Now + 24) select record; record.Timestamp <= (DateTime.Now + 24) is wrong here. I am using C# 3 + L2E.

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  • targeting sprites from a method in the document class - null object reference

    - by Freddyk
    Hi I am trying to code a flash app entirely in the document class. I am using GestureWorks with a touch screen. When a user essentially presses a button it calls a method that should hide a specific graphic but not the graphic they touched. Essentially I need a way to refer to a graphic on the screen using a method besides 'e.target'. //This code works because it can access 'e.target'. private function photo1SpriteFlickHandler(e:GestureEvent):void { var openTween:Tween = new Tween(e.target, "x", Strong.easeOut, 232, 970, 5, true); } //this code gives me a null object reference because I am using 'photo1Sprite' rather than 'e.target' private function photo1SpriteFlickHandler(e:GestureEvent):void { var openTween:Tween = new Tween(photo1Sprite, "x", Strong.easeOut, 232, 970, 5, true); } //photo1Sprite has already been programatically added to the screen as so: var photo1Sprite = new TouchSprite(); var photo1Loader=new Loader(); photo1Loader.load(new URLRequest("media/photos1/photo1.jpg")); photo1Loader.contentLoaderInfo.addEventListener(Event.COMPLETE,loaderComplete); photo1Sprite.x = 232; photo1Sprite.y = 538; photo1Sprite.scaleX = .3; photo1Sprite.scaleY = .3; photo1Sprite.blobContainerEnabled = true; photo1Sprite.addEventListener(TouchEvent.TOUCH_DOWN, startDrag_Press); photo1Sprite.addEventListener(TouchEvent.TOUCH_UP, stopDrag_Release); photo1Sprite.addChild(photo1Loader); addChild(photo1Sprite); So I can make photo1Sprite react if my method is attached to it directly using 'e.target' but not if I am trying to call it from a method that was called from another element on the screen.

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  • Using @Secured Annotation causes IS_FULLY_AUTHENTICATED problem in grails

    - by TripWired
    I'm using Acegi/Spring Security in grails and when i use the annotations like @Secured(['ROLE_ADMIN']) it denies my login even though the user is part of ROLE_ADMIN. In looking through the login is it seems that it's getting an IS_AUTHENTICATED_FULLY role also but I have never added that to a page so i'm not sure how to bypass that. I read somewhere to preauthorize the user, but i'm not sure how to do that with grails.

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  • Error creating new user by Admin

    - by rahul
    I am creating a web application using Form Authentication of Asp.Net with C# and back end Sql Server. Here in my application administrator login and creates new users. I am using the create user wizard under login controls. My problem is when the new user is created by Admin he is automatically logged out and logged in with new user credentials which he has just created. Any help would be highly appreciated.

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  • How do I make a page aware that the viewer is logged in or not?

    - by Joann
    I am building a membership site... I just got thru the login page and I can now login and logout. However that alone doesn't protect all my pages in the root.. How do I go about this? I'd like to set it up like so when the viewer isn't log-in, the page that's being opened would say "Log in first blah3x"... Any help pls??? :-(

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  • How to use type: "POST" in jsonp ajax call

    - by MKS
    Hi Guy, I am using JQuery ajax jsonp. I have got below JQuery Code: $.ajax({ type:"GET", url: "Login.aspx", // Send the login info to this page data: str, dataType: "jsonp", timeout: 200000, jsonp:"skywardDetails", success: function(result) { // Show 'Submit' Button $('#loginButton').show(); // Hide Gif Spinning Rotator $('#ajaxloading').hide(); } }); The above code is working fine, I just want to send the request as "POST" instead of "GET", Please suggest how can I achieve this. Thanks

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  • Changing GORM table name

    - by Matthias Hryniszak
    Hi I'm fighting to get the following mapping working in Grails 1.3.1 and MySQL: class Login { int id String email static mappings = { table 'my_table' id column: "Mgr_id" version: false } } No matter what I do the queries that are being issued refer to "schema.login" table instead of "schema.my_table". This is very frustrating... Can anyone answer why this might not be working?

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  • PHP: Check if URL redirects?

    - by Industrial
    Hi everybody, I have built a secured login backend that controls if a user is logged in or not. If not, the user is redirected to a login page. I would like to make a PHP function that iterates through a number of set url:s (array with url:s) to see if they are redirected or not. How could this be done? Thanks

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  • extended permission using php sdk

    - by Awais Qarni
    Hello, I am developing a facebook application using php-sdk. i want to take some extended permissions from user of my application. As this is application where user comes after login into facebook, so how can i take extended permission when user visit my page? We cannot place login button in which we can take permissions. now any one can guide me how to take and where to place that code? Thanks in advance. Regards, Awais Qarni

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  • how to connect j2me application with gtalk

    - by Rishabh
    Hi, I have created a login page on mobile. after login with google username and password, i want connect it with g-talk. I need to see my all gtalk contacts on mobile application. How I authenticate and get contacts here, Is there any web service url for user authentication ? Please help me!

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  • Django message framework and login_required

    - by Brandon
    I'm using the Django Message Framework to show messages to users as well as the @login_required decorator on one of my views. So if a user tries to access a certain view without being logged in, they get kicked to the login page. How would I go about adding an error message to the login page saying "In order to do ... you must be logged in". I can't add it in the view like you normally would because the non-logged in user would never get to there.

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  • How to intercept touch events globally?

    - by mystify
    I have an view which is sometimes covered by some other views. However, if the user slides the finger across the screen, I want to slide that underlying view across the screen, too. I could start making custom views for all those covering subviews and forward all kinds of touch events, but that's somewhat cumbersome. Maybe there's some kind of notification or another way that a UIView or UIControl subclass can be aware of touch events happening right now, no matter where they are. In short: I need an UIView subclass or UIControl subclass which knows about any touch events happening on the entire screen. Or at least if tht's not possible, knowing about any touch events happening above itself in the same underlying superview. Another description: There are 20 views, all reside inside the same superview. The first view is covered by 19 others. But if the user slides across the screen, that first view must slide too, so it must be aware of touch events. Is there any better solution that making all 19 views forward touch events? (yes, all 19 views respond to touch events in this example)

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  • How to you password protect a page with Wicket?

    - by Kane
    I want to password protect a webpage in Wicket so the user may only access it if he/she has logged in. I'd also like the page to show the login page, and then after logging in the original page the user was trying to get to. How is this done with wicket? I've already created a login page and extended the session class.

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  • Method in RootViewController not Storing Array

    - by Antonio
    I have an array initialized in my RootViewController and a method that addsObjects to an array. I created a RootViewController object in my SecondViewController. The method runs (outputs a message) but it doesn't add anything to the array, and the array seems empty. Code is below, any suggestions? RootViewController.h #import "RootViewController.h" #import "SecondViewController.h" @implementation RootViewController - (void)viewDidLoad { [super viewDidLoad]; myArray2 = [[NSMutableArray alloc] init]; NSLog(@"View was loaded"); } -(void)addToArray2{ NSLog(@"Array triggered from SecondViewController"); [myArray2 addObject:@"Test"]; [self showArray2]; } -(void)showArray2{ NSLog(@"Array Count: %d", [myArray2 count]); } -(IBAction)switchViews{ SecondViewController *screen = [[SecondViewController alloc] initWithNibName:nil bundle:nil]; screen.modalTransitionStyle = UIModalTransitionStyleCoverVertical; [self presentModalViewController:screen animated:YES]; [screen release]; } SecondViewController.m #import "SecondViewController.h" #import "RootViewController.h" @implementation SecondViewController -(IBAction)addToArray{ RootViewController *object = [[RootViewController alloc] init]; [object addToArray2]; } -(IBAction)switchBack{ [self dismissModalViewControllerAnimated:YES]; } EDIT***** With Matt's code I got the following error: " expected specifier-qualifier-list before 'RootViewController' "

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