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  • Adding a third table to a Join

    - by John
    Hello, This query works fine: $sqlStr = "SELECT s.loginid, s.title, s.url, s.displayurl, l.username FROM submission AS s, login AS l WHERE s.loginid = l.loginid ORDER BY s.datesubmitted DESC LIMIT 10"; Would this work if I wanted to join a third MySQL table (called "comment") to it? $sqlStr = "SELECT s.loginid, s.submissionid s.title, s.url, s.displayurl, l.username, count(c.comment) countComments FROM submission AS s, login AS l, comment AS c, WHERE s.loginid = l.loginid AND s.submissionid = c.submissionid ORDER BY s.datesubmitted DESC LIMIT 10"; Thanks in advance, John

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  • What is the best way to move a UIToolbar?

    - by Ferdinand Rios
    Here is an interesting problem. On the iPhone, I have a view set up that has a toolbar on the bottom of the screen. I am currently trying to make this a universal app so that it runs on iPad as well. I would like the toolbar to be at the top of the iPad screen, so in the viewDidLoad method of the specific viewController I have the following code. if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) { //move the toolbar to the top of the page and move the webview down by the height of the toolbar CGRect toolBarFrame = self.aToolBar.frame; CGRect webFrame = self.aWebView.frame; webFrame.origin.y = toolBarFrame.size.height; [self.aWebView setFrame:webFrame]; toolBarFrame.origin.y = 0; [self.aToolBar setFrame:toolBarFrame]; [Utils errorString:[NSString stringWithFormat:@"origen: x=%f y=%f", self.aToolBar.frame.origin.x, self.aToolBar.frame.origin.y]]; [Utils errorString:[NSString stringWithFormat:@"origen: x=%f y=%f", self.aWebView.frame.origin.x, self.aWebView.frame.origin.y]]; } The problem I am having is that the webView moves down fine, but the toolbar only moves up to about what seems to be the height of a iPhone screen. The call to errorString tells me that the webView's origin is at 0,44 (where it should be) and that the toolbar's origin is at 0,0, but it is actually somewhere in the middle of the screen! Anybody have a clue what is going on here?

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  • Frame Showing Problem

    - by Nitz
    Hey Guys I have made one project which is showing the inventory of the stock of one store. In that inventory the software should store data of the products with their images. There is one problem... Bcz of the lots of stock, the screen on which is image is loading taking a lot of time. So, i thought i should give the frame in which there will be on label which will show the "Loading Software". But now when i am setting visible = true for that frame, but bcz of that images screen class loading problem my frame is not showing correctly. I have put screen shot, now my code. JFrame f; try{ f = new JFrame("This is a test"); f.setSize(300, 300); Container content = f.getContentPane(); content.setBackground(Color.white); content.setLayout(new FlowLayout()); JLabel jl = new JLabel(); jl.setText("Loading Please Wait...."); content.add(jl); f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); f.setVisible(true); }catch(Exception e){ e.printStackTrace(); } initComponents(); try { addInverntory = new AddInventoryScreen(); showstock = new showStock(); // this class will take big time. mf = new mainForm(); f.setVisible(false); }catch (Exception ex) { ex.printStackTrace(); } How Can show some message that, other class is loading or "Loading Software" kind of thing in this situation. Just For the know....this class is not screen on which the image will load.

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  • Keep the session maintain of social networking sites

    - by Rana Muhammad Usman
    I want to develop an application where user will login once from his account he will integrate his social network e.g. facebook, twitter etc. And again he will not be required to login again from his social networking site like the following sites https://seesmic.com and http://hootsuite.com How I can maintain this session. I cant save the access token cz it expires after a certain time kindly tell me how it is possible...........

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  • Compile classfile issue in Spring 3

    - by Prajith R
    I have used spring framework 3 for my application. Everything is ok while developed in Netbeans But i need a custom build and done for the same The build created without any issue, but i got the following error The error occurred while calling the following method @RequestMapping(value = "/security/login", method = RequestMethod.POST) public ModelAndView login(@RequestParam String userName, @RequestParam String password, HttpServletRequest request) { ...................... But There is no issue while creating the war with netbeans (I am sure it is about the compilation issue) have you any experiance on this issue ... There is any additional javac argument for compile the same (netbeans used there custom task for the compilation) type Exception report message description The server encountered an internal error () that prevented it from fulfilling this request. exception org.springframework.web.util.NestedServletException: Request processing failed; nested exception is org.springframework.web.bind.annotation.support.HandlerMethodInvocationException: Failed to invoke handler method [public org.springframework.web.servlet.ModelAndView com.mypackage.security.controller.LoginController.login(java.lang.String,java.lang.String,javax.servlet.http.HttpServletRequest)]; nested exception is java.lang.IllegalStateException: No parameter name specified for argument of type [java.lang.String], and no parameter name information found in class file either. org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:659) org.springframework.web.servlet.FrameworkServlet.doPost(FrameworkServlet.java:563) javax.servlet.http.HttpServlet.service(HttpServlet.java:637) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) com.mypackage.security.controller.AuthFilter.doFilter(Unknown Source) org.springframework.web.filter.DelegatingFilterProxy.invokeDelegate(DelegatingFilterProxy.java:237) org.springframework.web.filter.DelegatingFilterProxy.doFilter(DelegatingFilterProxy.java:167) root cause org.springframework.web.bind.annotation.support.HandlerMethodInvocationException: Failed to invoke handler method [public org.springframework.web.servlet.ModelAndView com.mypackage.security.controller.LoginController.login(java.lang.String,java.lang.String,javax.servlet.http.HttpServletRequest)]; nested exception is java.lang.IllegalStateException: No parameter name specified for argument of type [java.lang.String], and no parameter name information found in class file either. org.springframework.web.bind.annotation.support.HandlerMethodInvoker.invokeHandlerMethod(HandlerMethodInvoker.java:171) org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter.invokeHandlerMethod(AnnotationMethodHandlerAdapter.java:414) org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter.handle(AnnotationMethodHandlerAdapter.java:402) org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:771) org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:716) org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:647) org.springframework.web.servlet.FrameworkServlet.doPost(FrameworkServlet.java:563) javax.servlet.http.HttpServlet.service(HttpServlet.java:637) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) com.mypackage.security.controller.AuthFilter.doFilter(Unknown Source) org.springframework.web.filter.DelegatingFilterProxy.invokeDelegate(DelegatingFilterProxy.java:237) org.springframework.web.filter.DelegatingFilterProxy.doFilter(DelegatingFilterProxy.java:167) root cause java.lang.IllegalStateException: No parameter name specified for argument of type [java.lang.String], and no parameter name information found in class file either. org.springframework.web.bind.annotation.support.HandlerMethodInvoker.getRequiredParameterName(HandlerMethodInvoker.java:618) org.springframework.web.bind.annotation.support.HandlerMethodInvoker.resolveRequestParam(HandlerMethodInvoker.java:417) org.springframework.web.bind.annotation.support.HandlerMethodInvoker.resolveHandlerArguments(HandlerMethodInvoker.java:277) org.springframework.web.bind.annotation.support.HandlerMethodInvoker.invokeHandlerMethod(HandlerMethodInvoker.java:163) org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter.invokeHandlerMethod(AnnotationMethodHandlerAdapter.java:414) org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter.handle(AnnotationMethodHandlerAdapter.java:402) org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:771) org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:716) org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:647) org.springframework.web.servlet.FrameworkServlet.doPost(FrameworkServlet.java:563) javax.servlet.http.HttpServlet.service(HttpServlet.java:637) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) com.mypackage.security.controller.AuthFilter.doFilter(Unknown Source) org.springframework.web.filter.DelegatingFilterProxy.invokeDelegate(DelegatingFilterProxy.java:237) org.springframework.web.filter.DelegatingFilterProxy.doFilter(DelegatingFilterProxy.java:167) note The full stack trace of the root cause is available in the Apache Tomcat/6.0.18 logs.

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  • Storing LDAP Credentials

    - by Floetic
    What's the ideal way to store login and password for LDAP membership providers in the web.config? Having the login and password stored in the provider under connectionUsername/connectionPassword attributes does not go well with me because, I would want to encrypt the connection string later on. Don't have much experience with this, and was wondering if anyone had any best practices for this.

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  • squirrelmail http error

    - by Permana
    I have install squirrel mail and get this message error when trying to login. 0 : Unable to find the socket transport "http" - did you forget to enable it when you configured PHP? I have create a test user, and when login I type test@localhost I use XAMPP (Basis Package) version 1.7.2

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  • Django facebook integration error

    - by Gaurav
    I'm trying to integrate facebook into my application so that users can use their FB login to login to my site. I've got everything up and running and there are no issues when I run my site using the command line python manage.py runserver But this same code refuses to run when I try and run it through Apache. I get the following error: Environment: Request Method: GET Request URL: http://helvetica/foodfolio/login Django Version: 1.1.1 Python Version: 2.6.4 Installed Applications: ['django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'foodfolio.app', 'foodfolio.facebookconnect'] Installed Middleware: ('django.contrib.sessions.middleware.SessionMiddleware', 'facebook.djangofb.FacebookMiddleware', 'django.middleware.common.CommonMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'facebookconnect.middleware.FacebookConnectMiddleware') Template error: In template /home/swat/website-apps/foodfolio/facebookconnect/templates/facebook/js.html, error at line 2 Caught an exception while rendering: No module named app.models 1 : <script type="text/javascript"> 2 : FB_RequireFeatures(["XFBML"], function() {FB.Facebook.init("{{ facebook_api_key }}", " {% url facebook_xd_receiver %} ")}); 3 : 4 : function facebookConnect(loginForm) { 5 : FB.Connect.requireSession(); 6 : FB.Facebook.get_sessionState().waitUntilReady(function(){loginForm.submit();}); 7 : } 8 : function pushToFacebookFeed(data){ 9 : if(data['success']){ 10 : var template_data = data['template_data']; 11 : var template_bundle_id = data['template_bundle_id']; 12 : feedTheFacebook(template_data,template_bundle_id,function(){}); Traceback: File "/usr/lib/pymodules/python2.6/django/core/handlers/base.py" in get_response 92. response = callback(request, *callback_args, **callback_kwargs) File "/home/swat/website-apps/foodfolio/app/controller.py" in __showLogin__ 238. context_instance = RequestContext(request)) File "/usr/lib/pymodules/python2.6/django/shortcuts/__init__.py" in render_to_response 20. return HttpResponse(loader.render_to_string(*args, **kwargs), **httpresponse_kwargs) File "/usr/lib/pymodules/python2.6/django/template/loader.py" in render_to_string 108. return t.render(context_instance) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 178. return self.nodelist.render(context) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 779. bits.append(self.render_node(node, context)) File "/usr/lib/pymodules/python2.6/django/template/debug.py" in render_node 71. result = node.render(context) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 946. autoescape=context.autoescape)) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 779. bits.append(self.render_node(node, context)) File "/usr/lib/pymodules/python2.6/django/template/debug.py" in render_node 81. raise wrapped Exception Type: TemplateSyntaxError at /foodfolio/login Exception Value: Caught an exception while rendering: No module named app.models

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  • Getting TypeError: Error #1009: Cannot access a property or method of a null object reference.

    - by nemade-vipin
    hello friends, I have created small application for login in flex desktop application. In which I am refering webservice method for login for this have created the Authentication class. Now I want to refer different Textinput value for mobile no and Textinput value for password. In my Authentication class. for this I have created the object of mxml class.And using this I am getting the mobile no value and password value in My Action script class. This my code :- SBTS.mxml file xmlns:mx="http://www.adobe.com/2006/mxml" layout="absolute" public function login():void { var User:Authentication; User = new Authentication(); User.authentication(); } ]] text=" Select Child."/ Action script class :- package src { import adobe.utils.XMLUI; import generated.webservices.*; import mx.collections.ArrayCollection; import mx.controls.Alert; import mx.rpc.events.FaultEvent; public class Authentication { [ Bindable] private var childName:ArrayCollection; [ Bindable] private var childId:ArrayCollection; private var photoFeed:ArrayCollection; private var arrayOfchild:Array; private var newEntry:GetSBTSMobileAuthentication; public var user:SBTSWebService; public var mxmlobj:SBTS; public function authentication():void { user = new SBTSWebService(); if(user!=null) { user.addSBTSWebServiceFaultEventListener(handleFaults); user.addgetSBTSMobileAuthenticationEventListener(authenticationResult); newEntry = new GetSBTSMobileAuthentication(); if(newEntry!=null) { mxmlobj = new SBTS(); if(mxmlobj != null) { newEntry.mobile = mxmlobj.mobileno.text; // Getting error here error mention below newEntry.password= mxmlobj.password.text; } user.getSBTSMobileAuthentication(newEntry); } } } public function handleFaults(event:FaultEvent):void { Alert.show( "A fault occured contacting the server. Fault message is: " + event.fault.faultString); } public function authenticationResult(event:GetSBTSMobileAuthenticationResultEvent):void { if(event.result != null && event.result._return0) { if(event.result._return 0) { var UserId:int = event.result._return; if(mxmlobj != null) { mxmlobj.loginform.enabled = false; mxmlobj.viewstack2.selectedIndex=1; } } else { Alert.show( "Authentication fail"); } } } } } I am getting this error :- TypeError: Error #1009: Cannot access a property or method of a null object reference. at SBTSBusineesObject::Authentication/authentication()[E:\Users\User1\Documents\Fl ex Builder 3\SBTS\src\SBTSBusineesObject\Authentication.as:35] at SBTS/login()[E:\Users\User1\Documents\Flex Builder 3\SBTS\src\SBTS.mxml:12] at SBTS/___SBTS_Button1_click()[E:\Users\User1\Documents\Flex Builder 3\SBTS\src\SBTS.mxml:27] please help me to remove this error.

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  • Django authentication

    - by webvulture
    In my base.html file, I am using {% if user.is_authenticated %} <a href="#">{{user.username}}</a> {% else %} <a href="/acc/login/">log in</a> Here, even if the user is logged in, the log in button shows up. Now when I click on the log in link, it shows the username and also the normal login view, saying user is logged in. So, what's wrong?

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  • Mod Rewrite Hide Folder

    - by MILESMIBALERR
    I think this is a pretty simple question. How do you an apache rewrite to hide a folder. EX: www.website.com/pages/login.php to www.website.com/login.php or www.website.com/pages/home.php to www.website.com/home.php The folder needs to alway be hidden. thanks

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  • SOAP, Python, suds

    - by iscarface
    Hello everybody! Please advise library for working with soap in python. Now, i'm trying to use "suds". And i can't undestand how get http headers from server reply Code example: from suds.client import Client url = "http://10.1.0.36/money_trans/api3.wsdl" client = Client(url) login_res = client.service.Login("login", "password") variable "login_res" contain xml answer and doesnt contain http headers. But i need to get session id from them. Thank you.

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  • Tomcat 403 error after LDAP authentication.

    - by user352636
    I'm currently trying to use an LDAP server to authenticate users who are trying to access our Tomcat setup. I believe I have managed to get the LDAP authentication working in the form of a JNDI realm call from Tomcat, but immediately after the user enters their password Tomcat starts throwing 403 (permission denied) errors for everything except from the root page (ttp://localhost:1337/). I have no idea why this is happening. I am following the example at http://blog.mc-thias.org/?title=tomcat_ldap_authentication&more=1&c=1&tb=1&pb=1 . server.xml (the interesting/changed bits) <Realm className="org.apache.catalina.realm.JNDIRealm" debug="99" connectionURL="ldap://localhost:389" userPattern="uid={0},ou=People,o=test,dc=company,dc=uk" userSubTree="true" roleBase="ou=Roles,o=test,dc=company,dc=uk" roleName="cn" roleSearch="memberUid={1}" /> <Valve className="org.apache.catalina.authenticator.SingleSignOn" /> web.xml (the interesting/changed bits) <security-constraint> <display-name>Security Constraint</display-name> <web-resource-collection> <web-resource-name>Protected Area</web-resource-name> <!-- Define the context-relative URL(s) to be protected --> <url-pattern>/*</url-pattern> <!-- If you list http methods, only those methods are protected --> </web-resource-collection> <auth-constraint> <!-- Anyone with one of the listed roles may access this area --> <role-name>admin</role-name> <role-name>regular</role-name> </auth-constraint> </security-constraint> <!-- Default login configuration uses form-based authentication --> <login-config> <auth-method>BASIC</auth-method> </login-config> <!-- Security roles referenced by this web application --> <security-role> <role-name>admin</role-name> <role-name>regular</role-name> </security-role> I cannot access my LDAP setup at the moment, but I believe it is alright as the login is accepted by the BASIC auth method, it's just tomcat that is rejecting it. The roles should be as defined in web.xml - admin and regular. If there is any other information you require me to provide, please just ask! My thanks in advance to anyone who can help, and my apologies for any major mistakes I have made - yesterday was pretty much the first time I'd ever heard of LDAP =D. EDIT: Fixed the second xml segment. Apologies for the formating-fail.

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  • Javascript running in facebox window

    - by Rudiger
    I'm modifying a website to have a pop up box appear when a user rates something prompting the user to login. Unfortunately the login process is something that I don't control and it uses a whole heap of javascript and redirects to do it and it seems that the javascript is failing. Can javascript run in the modal box or is there a way around this?

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  • How automatically fill a form with jQuery ?

    - by Shady
    Hi, I have a website that changes his inputs ids, and I'm trying to make a semi auto-login, filling automatically the email and the password part... I'm doing this with greasemonkey and jQuery... I'm trying something like this $("input[@type=text]").setValue("[email protected]"); but had no success... The Page has only the login part, two text type inputs... What am I missing here?

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  • Help with storing/accessing user access roles C# Winforms

    - by user222453
    Hello, firstly I would like to thank you in advance for any assistance provided. I am new to software development and have designed several Client/Server applications over the last 12 months or so, I am currently working on a project that involves a user logging in to gain access to the application and I am looking at the most efficient and "simple" method of storing the users permissions once logged in to the application which can be used throughout restricting access to certain tabs on the main form. I have created a static class called "User" detailed below: static class User { public static int _userID; public static string _moduleName; public static string _userName; public static object[] UserData(object[] _dataRow) { _userID = (int)_dataRow[0]; _userName = (string)_dataRow[1]; _moduleName = (string)_dataRow[2]; return _moduleName; } } When the user logs in and they have been authenticated, I wish to store the _moduleName objects in memory so I can control which tabs on the main form tab control they can access, for example; if the user has been assigned the following roles in the database: "Sales Ledger", "Purchase Ledger" they can only see the relevant tabs on the form, by way of using a Switch - Case block once the login form is hidden and the main form is instantiated. I can store the userID and userName variables in the main form once it loads by means of say for example: Here we process the login data from the user: DataAccess _dal = new DataAccess(); switch (_dal.ValidateLogin(txtUserName.Text, txtPassword.Text)) { case DataAccess.ValidationCode.ConnectionFailed: MessageBox.Show("Database Server Connection Failed!"); break; case DataAccess.ValidationCode .LoginFailed: MessageBox.Show("Login Failed!"); _dal.RecordLogin(out errMsg, txtUserName.Text, workstationID, false); break; case DataAccess.ValidationCode .LoginSucceeded: frmMain frmMain = new frmMain(); _dal.GetUserPrivList(out errMsg,2); //< here I access my DB and get the user permissions based on the current login. frmMain.Show(); this.Hide(); break; default: break; } private void frmMain_Load(object sender, EventArgs e) { int UserID = User._userID; } That works fine, however the _modules object contains mutiple permissions/roles depending on what has been set in the database, how can I store the multiple values and access them via a Switch-Case block? Thank you again in advance.

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  • Usernames are evil. How can I make Restful Authentication only require an email address and password

    - by Koning WWWWWWWWWWWWWWWWWWWWWWW
    As the title says: how can I use the Restful Authentication Plugin with Ruby on Rails. When I want to create a new user, it requires me to set the (wrong-named, confusing field) login (= username), email address and password. However, I want, like Facebook does, to require the user to enter only an email address and password, not a username. People will also login with this email address. Can anyone help me?

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  • WPF : Multiple views, one DataContext

    - by zapho
    Hi, I'm working on a WPF application which must handle multiple screens (two at this this time). One view can be opened on several screens and user actions must be reflected consistently on all screens. To achieve this, for a given type of view, a single DataContext is instantiated. Then, when a view is displayed on a screen, the unique DataContext is attached to it. So, one DataContext, several views (same type of view/xaml). So far so good. It works quite well in most cases. I do have a problem with a specific view which relies on ItemsControl. These ItemsControl are used to display UIElements dynamically build in the ViewModel/DataContext (C# code). These UIElements are mostly Path objects. Example : <ItemsControl ItemsSource="{Binding WindVectors}"> <ItemsControl.Template> <ControlTemplate TargetType="{x:Type ItemsControl}"> <Canvas IsItemsHost="True" /> </ControlTemplate> </ItemsControl.Template> </ItemsControl> Here, WindVectors is a ObservableCollection<UIElement>. When the view is opened the first time, everything is fine. The problem is that when the view is opened one another screen, all ItemsControl are removed from the first screen and displayed one the second screen. Other WPF components (TextBlock for instance) on this view react normally and are displayed on both screens. Any help would be greatly appreciated. Thanks. Fabrice

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  • Storing Requested URL in Global.asax without Session State in ASP.NET

    - by Mark Richman
    I have a complex URL rewriting scheme which breaks the built in Forms Authentication ReturnUrl mechanism. I would like to grab the requested URL for later redirection away from my login.aspx. I can get this URL in Application_BeginRequest via HttpContext.Current.Request.AppRelativeCurrentExecutionFilePath. However, Session state is not available in Application_BeginRequest. How can I store this URL prior to ASP.NET redirecting me to login.aspx?

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  • Safari openwindow function behavior on iPad versus iPhone

    - by CodeLizard
    An identical javascript:openwindow call with a link to Google maps opens in Safari on the iPad but in the Google Maps App on the iPhone. Why the difference? <html> <head> </head> <body> <a title="View an area map for this property" href="javascript:openwindow ('http://maps.google.com/maps?f=q&source=s_q&hl=en&geocode=&q=1+Infinite+Loop, +Cupertino,+CA%E2%80%8E&sll=37.329389, -122.029696&sspn=0.015714,0.033023&ie=UTF8&hq=&hnear=1+Infinite+Loop, +Cupertino,+Santa+Clara, +California+95014&ll=37.331539, -122.030704&spn=0.007857,0.016512&z=17&ssa=1', 760, 500,'yes', 'yes')"> <font face="arial,helvetica" color="#000000" size="-1">Map It</font> </a> </body> <script> function openwindow(url,width,height,resizable,scrollbars,posx,posy) { if(posx==null)posx=20; if(posy==null)posy=20; now=new Date(); var x_offset=0; var y_offset=0; try { if(window.screen.left != undefined && window.screen.top != undefined) { x_offset=window.screen.left; y_offset=window.screen.top; } }catch(e){} var window_x=posx+x_offset; var window_y=posy+y_offset; new_window=window.open(url,now.getTime(),'width='+width+',height='+height+', resizable='+resizable+',scrollbars='+scrollbars+',top='+window_y+', left='+window_x+',screenX='+window_x+',screenY='+window_y); if(!new_window.opener) new_window.opener=self; try { new_window.focus(); }catch(e){} } </script> </html>

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  • secure from unauthorised access

    - by soclose
    Hi, Based on the user requirements, he wants to use our android application via pin code access like login whenever he starts to use this application. In Android or any mobile, most of the applications start again the last using layout. so which event should i call this login alertdialog to access each time users start to use it? Or let me know the better. Thank you.

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