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  • how to use two forms and sumit once

    - by Mac Taylor
    hey guys is it possible to have two forms with two submit buttons but when i click on the button then it saves both forms input fields im concerning to solve this in php /mysql i tried my own way : if ((isset($_POST["form-1"])) && (isset($_POST["form-2"])) { //SQL Insertion } thanks in advance

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  • Curve-fitting in PHP

    - by Francesc
    Hi, I have a MySql table called today_stats. It has got Id, date and clicks. I'm trying to create a script to get the values and try to predict the next 7 days clicks. How I can predict it in PHP?

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  • Oracle vocabulary, what is the mysql/mssql equivalent of a database

    - by jeph perro
    Hi, I need some help with vocabulary, I don't use Oracle that often but I am familiar with MySQL and MSSQL. I have an application I need to upgrade and migrate, and part of the procedure to do that involves exporting to an XML, create new database tables, then populate the new database tables from the XML export. In Oracle, my database connection specifies a username, password, and an SID. This SID contains tables belonging to several applications. My question is: Can I re-use the same user to create the new tables ( with the same names ). In MySQL or MSSQL, I would create a new database and grant my user privileges to create tables in it. OR, do I need to create a new database user for my upgraded tables?

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  • Notify user on database change? JavaScript/AJAX

    - by Andreas Carlbom
    Yo. I'm really quite new to this whole JavaScript business, not to mention AJAX, so I was thinking if you guys could help me out with a conundrum. Basically, what I want is for the user to be notified upon a change in a value of a MySQL table. How should I go about that? Should I use jQuery, or can I slap something together myself? Thankful for any and all replies.

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  • workbench vs phpmyadmin

    - by ajsie
    i've only used phpmyadmin but then i stumbled upon mysql workbench that looks promising. i wonder if someone has tried it out and could give your thoughts about it compared to phpmyadmin. could it replace phpmyadmin completely? thanks in advance

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  • Why is htmlspecialchars adding slashes to my webpage?

    - by Cortopasta
    I have my input placed into mySQL through a PDO prepared statement, and have it placed in my website with PHP using htmlspecialchars() to protect against XSS. Only problem is now I get slashes, before any quotes, that are visible on the webpage to the user it only happens when I upload it to the server. Never happens on my localhost. Why is this happening?

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  • How to avoid this PDO exception: Cannot execute queries while other unbuffered queries are active

    - by Vittorio Vittori
    Hi, I'd like to print a simple table in my page with 3 columns, building name, tags and architecture style. If I try to retrieve the list of building names and arch. styles there is no problem: SELECT buildings.name, arch_styles.style_name FROM buildings INNER JOIN buildings_arch_styles ON buildings.id = buildings_arch_styles.building_id INNER JOIN arch_styles ON arch_styles.id = buildings_arch_styles.arch_style_id LIMIT 0, 10 My problem starts on retreaving the first 5 tags for every building of the query I've just wrote. SELECT DISTINCT name FROM tags INNER JOIN buildings_tags ON buildings_tags.tag_id = tags.id AND buildings_tags.building_id = 123 LIMIT 0, 5 The query itself works perfectly, but not where I thought to use it: <?php // pdo connection allready active, i'm using mysql $pdo_conn->setAttribute(PDO::MYSQL_ATTR_USE_BUFFERED_QUERY, true); $sql = "SELECT buildings.name, buildings.id, arch_styles.style_name FROM buildings INNER JOIN buildings_arch_styles ON buildings.id = buildings_arch_styles.building_id INNER JOIN arch_styles ON arch_styles.id = buildings_arch_styles.arch_style_id LIMIT 0, 10"; $buildings_stmt = $pdo_conn->prepare ($sql); $buildings_stmt->execute (); $buildings = $buildings_stmt->fetchAll (PDO::FETCH_ASSOC); $sql = "SELECT DISTINCT name FROM tags INNER JOIN buildings_tags ON buildings_tags.tag_id = tags.id AND buildings_tags.building_id = :building_id LIMIT 0, 5"; $tags_stmt = $pdo_conn->prepare ($sql); $html = "<table>"; // i'll use it to print my table foreach ($buildings as $building) { $name = $building["name"]; $style = $building["style_name"]; $id = $building["id"]; $tags_stmt->bindParam (":building_id", $id, PDO::PARAM_INT); $tags_stmt->execute (); // the problem is HERE $tags = $tags_stmt->fetchAll (PDO::FETCH_ASSOC); $html .= "... $name ... $style"; foreach ($tags as $current_tag) { $tag = $current_tag["name"]; $html .= "... $tag ..."; // let's suppose this is an area of the table where I print the first 5 tags per building } } $html .= "...</table>"; print $html; I'm not experienced on queries, so i though something like this, but it throws the error: PHP Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[HY000]: General error: 2014 Cannot execute queries while other unbuffered queries are active. Consider using PDOStatement::fetchAll(). Alternatively, if your code is only ever going to run against mysql, you may enable query buffering by setting the PDO::MYSQL_ATTR_USE_BUFFERED_QUERY attribute. What can I do to avoid this? Should I change all and search a different way to get this kind of queries?

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  • Oracle Sql Developer vendor code 1317

    - by Zemian
    Hi, I am using Oracle Sql Developer to browse a MySQL database. When I browse table with Columns tab(shows table definitions), some of tables will display an Error Encountered dialog that says: Vendor code 1317. Does anyone know how I can resolve this? Thanks, /Z

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  • stored procedures, error #1312, CLIENT_MULTI_RESULTS flag

    - by aadersh patel
    i am writing stored procedures in MySQL that return values; CREATE PROCEDURE getCustomerById (id int) BEGIN SELECT * FROM customer WHERE customer.id = id; END; and i get the error that the results cannot be shown in the given context. after some googling, i think that i need to set the flag "CLIENT_MULTI_RESULTS" - i am connecting the database from JDBC using a java app, but cant find where to set it! any suggestions?

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  • nested sql statment using and

    - by klay
    hi guys, how to make this work in mysql? select ID,COMPANY_NAME,contact1, SUBURB, CATEGORY, PHONE from Victoria where (city in ( select suburb from allsuburbs)) and CATEGORY='Banks' this below statement is working: select ID,COMPANY_NAME,contact1, SUBURB, CATEGORY, PHONE from Victoria where city in ( select suburb from allsuburbs) if I add "and" , it gives me an empty resultset, thanks

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  • Calling ADODB inside a function?

    - by David
    Hi, I'm wondering why when i put an sql ADODB query in side a function it produces the following error: Fatal error: Call to a member function Execute() on a non-object in -path to script- My function is something like: $dsn = 'mysql://user:pass@localhost/db'; $db = ADONewConnection($dsn); function getem($q){ $r=$db->Execute($q); return $r->RecordCount(); } echo getem("select * from table"); Any ideas how to fix that?

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  • Datatype query on datetime and tinyint

    - by sarah
    Hi , I have Mysql column type has datetime what should be the corresponding datatype in entity bean class for the same column ,as well for tinyint what would be the corresponding datatype in entity bean class for the same column ?

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  • Books or resources for high-loaded sites.

    - by Alex
    Currently I'm developing high-loaded financial portal(we use LAMP to run our project). There are great number of incoming data to be processed and stored. So optimization tasks become very important for us. Could you suggest books, articles or resources, that discover optimization questions (especially bboks). NOTE: At the moment I'm reading great book High Performance MySQL, but besides I want to know other facilities of optimization.

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  • Application time out issue

    - by harigm
    I have build the web application using Java1.5, Struts framework with Mysql database Deployed on the JBOSS4.0.5 Server Every thing seems to be fine when the activity is there on the server. Every morning, If I tried to connect to application, it shows the application is down. Once I restart the server, It works fine. From past 1 month, I am just restarting the server every day. Can any one help me where I am doing wrong in the configuration settings Please suggest me How i can eliminate this extra work every day

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  • problem with unicode in javaEE and save question mark in database

    - by Jeus
    when i insert persian information with use JEE6(JSF and JPA) my information save question mark for example "???" === "???" my database is Mysql and my table is UTF-8 . when insert persian data directly in database is correct and save correct. i know that with change one property in JEE my problem go to solved but i don`t know where is it ?

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  • Working with foreigh keys - cannot insert

    - by Industrial
    Hi everyone! Doing my first tryouts with foreign keys in a mySQL database and are trying to do a insert, that fails for this reason: Integrity constraint violation: 1452 Cannot add or update a child row: a foreign key constraint fails Does this mean that foreign keys restrict INSERTS as well as DELETES and/or UPDATES on each table that is enforced with foreign keys relations? Thanks!

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  • Anything similar to Hibernate in PHP?

    - by harigm
    I am a Java programmer and was working on a project using Hibernate and Struts for some time. Now For my new project, I am working on PHP and Mysql (learning PHP). Is there any technology which is similar to Hibernate for PHP? If yes, can anyone give me the link where I can understand and use it? Is there a POJO concept in PHP?

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  • How to create a "facade" table?

    - by tputkonen
    A legacy database contains a join table which links tables table1 and table2, and contains just two foreign keys: TABLE_ORIG: table1_id table2_id In order to utilize this table using JPA I would need to create a surrogate primary key to the link table. However, the existing table must not be modified at all. I would like to create another table which would contain also a primary key in addition to the foreign keys: TABLE_NEW: id table1_id table2_id All changes to TABLE_ORIG should be reflected in TABLE_NEW, and vice versa. Is this doable in mysql?

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  • Ajax problem not displaying data using multiple javascript calls...

    - by Ronedog
    I'm writing an app that uses ajax to retrieve data from a mysql db using php. Because of the nature of the app, the user clicks an href link that has an "onclick" event used to call the javascript/ajax. I'm retrieving the data from mysql, then calling a separate php function which creates a small html table with the necessary data in it. The new table gets passed back to the responseText and is displayed inside a div tag. The tables only have around 10-20 rows of data in them. This functionality is working fine and displays the data in html form exactly as it needs to be on the page. The problem is this. the HREF "onclick" event needs to run multiple scripts one right after the other. The first script updates the "existing" data and inside the "update_existing" function is a call to refresh a section of the page with the updated HTML from the responseText. Then when that is done a "display_html" function is called which also updates a different section of the page with it's newly created HTML table. The event looks like this: Update This string gets built dynamically using php with parameters supplied, but for this example I simply took the parameters out so it didn't get confusing. The "update_existion() function actually calls the display_html() function which updates a section of the page as needed. I need to update a different section of the page on the same click of the mouse right after the update, which is why I'm calling the display_html() again, right after it. The problem is only the last call is being updated on my screen. In other words, the 2nd function call "display_html()" executes and displays the refreshed data just fine, but the previous call to update_existing() runs and updates the database properly, but doesn't display on the screen unless I press the browsers "refresh" button, which of course displays the new data exactly how I want it to, but I don't want the users to have to press the "refresh" button. I tried adding multiple "display_html() calls one right after the other, separating all of them with the semicolon and learned that only the very last function call actually refreshed the div element on the html page with the table information, although all the previous display_html() calls worked, they couldn't be seen on the page without a refresh of the browser. Is this a problem with javascript, or the ajax call, or is this a limitation in the DOM that only allows one element to be updated at a time. The ajax call is asynchroneous, but I've tried both, only async works period. This is the same in both Firefox and Internet Explorer Any ideas what's going on and how to get around it so I can run these multiple scripts?

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  • uploading file size

    - by Anup Prakash
    As we all know, By default in PHP+MySQL, we can upload a file of size 1.4MB (max). 1) My Question is how can i increase the limitation of this uploading file size? 2) What is the maximum limitation for file to be uploaded in database? Thanx for viewing my query and special thanx for answering my questin.

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  • how to compare dates in php and sql?

    - by sebastian
    Hi, I want to make a notification system. Shortly.. to compare two dates, the only problem is that i want to compare the months. to see if a month or two have passed from last notification. i want to use one or two months from an entry in a mysql database. the client must select when the notification must come, one or two months. thank you, Sebastian

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