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  • HTML, CSS, Javascript - Problem with hiding/showing elements

    - by Edward Wong Hau Pepelu Tivrusk
    I'm using the Blueprint CSS grid for my HTML page. I have a table which I want to show/hide - linking it to a button, using jQuery. The problem is that everytime I click on the button to show/hide the table, everything on the page shifts slightly left-right. Is this a common problem? Does anyone know what could be causing this and what I could do to fix the other elements of the page such that they do not move? Edit: grammar.

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  • Parsing back to 'messy' API strcuture

    - by Eric Fail
    I'm fetching data from an online database (REDcap) via API and the data gets delivered in as comma separated string like this, RAW.API <- structure("id,event_arm,name,dob,pushed_text,pushed_calc,complete\n\"01\",\"event_1_arm_1\",\"John\",\"1979-05-01\",\"\",\"\",2\n\"01\",\"event_2_arm_1\",\"John\",\"2012-09-02\",\"abc\",\"123\",1\n\"01\",\"event_3_arm_1\",\"John\",\"2012-09-10\",\"\",\"\",2\n\"02\",\"event_1_arm_1\",\"Mary\",\"1951-09-10\",\"def\",\"456\",2\n\"02\",\"event_2_arm_1\",\"Mary\",\"1978-09-12\",\"\",\"\",2\n", "`Content-Type`" = structure(c("text/html", "utf-8"), .Names = c("", "charset"))) I have this script that nicely parses it into a data frame, (df <- read.table(file = textConnection(RAW.API), header = TRUE, sep = ",", na.strings = "", stringsAsFactors = FALSE)) id event_arm name dob pushed_text pushed_calc complete 1 1 event_1_arm_1 John 1979-05-01 <NA> NA 2 2 1 event_2_arm_1 John 2012-09-02 abc 123 1 3 1 event_3_arm_1 John 2012-09-10 <NA> NA 2 4 2 event_1_arm_1 Mary 1951-09-10 def 456 2 5 2 event_2_arm_1 Mary 1978-09-12 <NA> NA 2 I then do some calculations and write them to pushed_text and pushed_calc whereafter I need to format the data back to the messy comma separated structure it came in. I imagine something like this, API.back <- `some magic command`(df, ...) identical(RAW.API, API.back) [1] TRUE Some command that can format my data from the data frame I made, df, back to the structure that the raw API-object came in, RAW.API. Any help would be very appreciated.

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  • How do you obtain a formatted date and time for the current locale in C?

    - by jwaddell
    What C function should I call to obtain a formatted date and time for the locale where the program is being executed? I'm asking this question because I have run into a problem using the ClamAV daemon API. The VERSION command returns the date and time of the latest virus definitions, but the code uses a call to ctime to format it. As far as I can tell ctime does not format the datetime according to the current locale and uses the English abbreviations for days of the week and the month in the returned string. This causes problems as my Java program which uses the ClamAV API does respect the current locale and thus expects the day of the week and month name to have the local abbreviations. The datetime format would need to be in the same format as that produced by ctime: Www Mmm dd hh:mm:ss yyyy Where Www is the weekday, Mmm the month in letters, dd the day of the month, hh:mm:ss the time, and yyyy the year. I could rewrite the Java program to always assume English dates but I'd be happier to submit a patch to ClamAV as it seems like a bug on their side to me.

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  • Rewinding std::cout to go back to the beginning of a line

    - by fbrereto
    I'm writing a command-line tool for Mac OS X that processes a bunch of files. I would like to show the user the current file being processed, but do not want a bazillion files polluting the terminal window. Instead I would like to use a single line to output the file path, then reuse that line for the next file. Is there a character (or some other code) to output to std::cout to accomplish this? Also, if I wanted to re-target this tool for Windows, would the solution be the same for both platforms?

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  • Delphi DateTimeFormat returning wrong year

    - by Leslie
    I have a form that allows users to enter a date of birth: ie: 4/16/40 Then when the user processes the form there's a function that checks it's length, adds leading zeros, parses the date and then uses FormatDateTime to just return the year of birth: strTemp := strPostedByDOB; If Length(strTemp) = 5 then strTemp = '0' + strTemp; if Length(strTemp) = 6 then begin strTemp := Copy(strTemp, 1 ,2) + '/' + copy(strTemp, 3, 2) + '/' + Copy(strTemp, 5, 2); strTemp := FormatDateTime('YYYY', StrToDate(strTemp)); end else strTemp := EmptyStr; using this code the strTemp is calculated as 2040 instead of 1940. Can anyone help me figure out how to make it show 1940 in strTemp? Do I have to change the form to accept a 4 digit year? Thanks, Leslie

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  • Code-Golf: Friendly Number Abbreviator

    - by David Murdoch
    Based on this question: Is there a way to round numbers into a friendly format? THE CHALLENGE - UPDATED! (removed hundreds abbreviation from spec) The shortest code by character count that will abbreviate an integer (no decimals). Code should include the full program. Relevant range is from 0 - 9,223,372,036,854,775,807 (the upper limit for signed 64 bit integer). The number of decimal places for abbreviation will be positive. You will not need to calculate the following: 920535 abbreviated -1 place (which would be something like 0.920535M). Numbers in the tens and hundreds place (0-999) should never be abbreviated (the abbreviation for the number 57 to 1+ decimal places is 5.7dk - it is unneccessary and not friendly). Remember to round half away from zero (23.5 gets rounded to 24). Banker's rounding is verboten. Here are the relevant number abbreviations: h = hundred (102) k = thousand (103) M = million (106) G = billion (109) T = trillion (1012) P = quadrillion (1015) E = quintillion (1018) SAMPLE INPUTS/OUTPUTS (inputs can be passed as separate arguments): First argument will be the integer to abbreviate. The second is the number of decimal places. 12 1 => 12 // tens and hundreds places are never rounded 1500 2 => 1.5k 1500 0 => 2k // look, ma! I round UP at .5 0 2 => 0 1234 0 => 1k 34567 2 => 34.57k 918395 1 => 918.4k 2134124 2 => 2.13M 47475782130 2 => 47.48G 9223372036854775807 3 => 9.223E // ect... . . . Original answer from related question (javascript, does not follow spec): function abbrNum(number, decPlaces) { // 2 decimal places => 100, 3 => 1000, etc decPlaces = Math.pow(10,decPlaces); // Enumerate number abbreviations var abbrev = [ "k", "m", "b", "t" ]; // Go through the array backwards, so we do the largest first for (var i=abbrev.length-1; i>=0; i--) { // Convert array index to "1000", "1000000", etc var size = Math.pow(10,(i+1)*3); // If the number is bigger or equal do the abbreviation if(size <= number) { // Here, we multiply by decPlaces, round, and then divide by decPlaces. // This gives us nice rounding to a particular decimal place. number = Math.round(number*decPlaces/size)/decPlaces; // Add the letter for the abbreviation number += abbrev[i]; // We are done... stop break; } } return number; }

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  • How to display a DateTime with chosen date parts, but in the order of the FormatProvider?

    - by Stephane
    I want to display the date in the order that the culture provides, but with the elements I want only. The DateTime.Tostring() method has a list of patterns that are very useful but I would like a very small change in it. The CultureInfo used in the following the following code are chosen as example, I don't want to rely on a specific list of CultureInfo, if possible var now = DateTime.Now; string nowString = now.ToString("m", CultureInfo.GetCultureInfo("en-us")); Console.WriteLine(nowString); nowString = now.ToString("m", CultureInfo.GetCultureInfo("fr-FR")); Console.WriteLine(nowString); displays : April 12 12 avril I would like a pattern that display the abbreviation of the month and the day, but that keeps the correct order from the specified CultureInfo. using the pattern "MMM dd" will always display the month's abbreviation first, followed by the day, breaking the french order for example. Any way to achieve that without too much custom code?

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  • Reading numeric Date value from CSV file to data.frame in "R"

    - by Dick Eshelman
    D <- read.csv("sample1.csv", header = FALSE, sep = ",") D V1 V2 V3 V4 1 20100316 109825 352120 239065 2 20100317 108625 352020 239000 3 20100318 109125 352324 241065 D[,1] [1] 20100316 20100317 20100318 In the above example how do I get the data in D[,1] to be read, and stored as date values: 2010-03-16, 2010-03-17, 2010-03-18 ? I have lots of data files in this format. TIA,

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  • Gnuplot axis scale units

    - by Kami
    I have the following data in a log file: 1270719764.323778250 926 vm-mystery1 1073744528 0 1 1270719764.323815250 926 vm-mystery1 1073746080 0 1 1270719764.323842250 926 vm-mystery1 1075968992 0 1 The first column is a UNIX date that I want to use for my x-axis in a gnuplot graph. My graph looks ugly because the first unit in the x-axis is 1.27072e+09. I would like to have the x-axis looks like the following : x axis [(first row date - first row date) ; (last row date - first row date)] displaying ticks in mili seconds. How to do this ?

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  • Microsoft Word Document Controls not accepting carriage returns

    - by Scott
    So, I have a Microsoft Word 2007 Document with several Plain Text Format (I have tried Rich Text Format as well) controls which accept input via XML. For carriage returns, I had the string being passed through XML containing "\r\n" when I wanted a carriage return, but the word document ignored that and just kept wrapping things on the same line. I also tried replacing the \r\n with System.Environment.NewLine in my C# mapper, but that just put in \r\n anyway, which still didn't work. Note also that on the control itself I have set it to "Allow Carriage Returns (Multiple Paragrpahs)" in the control properties. This is the XML for the listMapper <Field id="32" name="32" fieldType="SimpleText"> <DataSelector path="/Data/DB/DebtProduct"> <InputField fieldType="" path="/Data/DB/Client/strClientFirm" link="" type=""/> <InputField fieldType="" path="strClientRefDebt" link="" type=""/> </DataSelector> <DataMapper formatString="{0} Account Number: {1}" name="SimpleListMapper" type=""> <MapperData> </MapperData> </DataMapper> </Field> Note that this is the listMapper C# where I actually map the list (notice where I try and append the system.environment.newline) namespace DocEngine.Core.DataMappers { public class CSimpleListMapper:CBaseDataMapper { public override void Fill(DocEngine.Core.Interfaces.Document.IControl control, CDataSelector dataSelector) { if (control != null && dataSelector != null) { ISimpleTextControl textControl = (ISimpleTextControl)control; IContent content = textControl.CreateContent(); CInputFieldCollection fileds = dataSelector.Read(Context); StringBuilder builder = new StringBuilder(); if (fileds != null) { foreach (List<string> lst in fileds) { if (CanMap(lst) == false) continue; if (builder.Length > 0 && lst[0].Length > 0) builder.Append(Environment.NewLine); if (string.IsNullOrEmpty(FormatString)) builder.Append(lst[0]); else builder.Append(string.Format(FormatString, lst.ToArray())); } content.Value = builder.ToString(); textControl.Content = content; applyRules(control, null); } } } } } Does anybody have any clue at all how I can get MS Word 2007 (docx) to quit ignoring my newline characters??

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  • Why am I getting a ParseException when using SimpleDateFormat to format a date and then parse it?

    - by Greg
    I have been debugging some existing code for which unit tests are failing on my system, but not on colleagues' systems. The root cause is that SimpleDateFormat is throwing ParseExceptions when parsing dates that should be parseable. I created a unit test that demonstrates the code that is failing on my system: import java.text.DateFormat; import java.text.ParseException; import java.text.SimpleDateFormat; import java.util.Date; import java.util.TimeZone; import junit.framework.TestCase; public class FormatsTest extends TestCase { public void testParse() throws ParseException { DateFormat formatter = new SimpleDateFormat("yyyyMMddHHmmss.SSS Z"); formatter.setTimeZone(TimeZone.getDefault()); formatter.setLenient(false); formatter.parse(formatter.format(new Date())); } } This test throws a ParseException on my system, but runs successfully on other systems. java.text.ParseException: Unparseable date: "20100603100243.118 -0600" at java.text.DateFormat.parse(DateFormat.java:352) at FormatsTest.testParse(FormatsTest.java:16) I have found that I can setLenient(true) and the test will succeed. The setLenient(false) is what is used in the production code that this test mimics, so I don't want to change it.

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  • Reformatting a Java String

    - by Travis
    I have a string that looks like this: CALDARI_STARSHIP_ENGINEERING and I need to edit it to look like Caldari Starship Engineering Unfortunately it's three in the morning and I cannot for the life of me figure this out. I've always had trouble with replacing stuff in strings so any help would be awesome and would help me understand how to do this in the future.

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  • How do you print a limited number of characters?

    - by Mike Pateras
    Sorry to put a post up about something so simple, but I don't see what I'm doing wrong here. char data[1024]; DWORD numRead; ReadFile(handle, data, 1024, &numRead, NULL); if (numRead > 0) printf(data, "%.5s"); My intention with the above is to read data from a file, and then only print out 5 characters. However, it prints out all 1024 characters, which is contrary to what I'm reading here. The goal, of course, is to do something like: printf(data, "%.*s", numRead); What am I doing wrong here?

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  • AudioConverterConvertBuffer problem with insz error

    - by Samuel
    Hi Codegurus, I have a problem with the this function AudioConverterConvertBuffer. Basically I want to convert from this format _ streamFormat.mFormatFlags = kLinearPCMFormatFlagIsSignedInteger | kLinearPCMFormatFlagIsPacked |0 ; _streamFormat.mBitsPerChannel = 16; _streamFormat.mChannelsPerFrame = 2; _streamFormat.mBytesPerPacket = 4; _streamFormat.mBytesPerFrame = 4; _streamFormat.mFramesPerPacket = 1; _streamFormat.mSampleRate = 44100; _streamFormat.mReserved = 0; to this format _streamFormatOutput.mFormatFlags = kLinearPCMFormatFlagIsSignedInteger | kLinearPCMFormatFlagIsPacked|0 ;//| kAudioFormatFlagIsNonInterleaved |0; _streamFormatOutput.mBitsPerChannel = 16; _streamFormatOutput.mChannelsPerFrame = 1; _streamFormatOutput.mBytesPerPacket = 2; _streamFormatOutput.mBytesPerFrame = 2; _streamFormatOutput.mFramesPerPacket = 1; _streamFormatOutput.mSampleRate = 44100; _streamFormatOutput.mReserved = 0; and what i want to do is to extract an audio channel(Left channel or right channel) from an LPCM buffer based on the input format to make it mono in the output format. Some logic code to convert is as follows This is to set the channel map for PCM output file SInt32 channelMap[1] = {0}; status = AudioConverterSetProperty(converter, kAudioConverterChannelMap, sizeof(channelMap), channelMap); and this is to convert the buffer in a while loop AudioBufferList audioBufferList; CMBlockBufferRef blockBuffer; CMSampleBufferGetAudioBufferListWithRetainedBlockBuffer(sampBuffer, NULL, &audioBufferList, sizeof(audioBufferList), NULL, NULL, 0, &blockBuffer); for (int y=0; y<audioBufferList.mNumberBuffers; y++) { AudioBuffer audioBuffer = audioBufferList.mBuffers[y]; //frames = audioBuffer.mData; NSLog(@"the number of channel for buffer number %d is %d",y,audioBuffer.mNumberChannels); NSLog(@"The buffer size is %d",audioBuffer.mDataByteSize); numBytesIO = audioBuffer.mDataByteSize; convertedBuf = malloc(sizeof(char)*numBytesIO); status = AudioConverterConvertBuffer(converter, audioBuffer.mDataByteSize, audioBuffer.mData, &numBytesIO, convertedBuf); char errchar[10]; NSLog(@"status audio converter convert %d",status); if (status != 0) { NSLog(@"Fail conversion"); assert(0); } NSLog(@"Bytes converted %d",numBytesIO); status = AudioFileWriteBytes(mRecordFile, YES, countByteBuf, &numBytesIO, convertedBuf); NSLog(@"status for writebyte %d, bytes written %d",status,numBytesIO); free(convertedBuf); if (numBytesIO != audioBuffer.mDataByteSize) { NSLog(@"Something wrong in writing"); assert(0); } countByteBuf = countByteBuf + numBytesIO; But the insz problem is there... so it cant convert. I would appreciate any input Thanks in advance

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  • Replicating Java's DecimalFormat in C#

    - by Frank Krueger
    I am trying to replicate a subset of Java's DecimalFormat class. Below is what I've come up with. Does this look right to everyone? public class DecimalFormat : NumberFormat { int _maximumFractionDigits; int _minimumFractionDigits; string _format; void RebuildFormat () { _format = "{0:0."; _format += new string ('0', _minimumFractionDigits); if (_maximumFractionDigits > _minimumFractionDigits) { _format += new string ('#', _maximumFractionDigits - _minimumFractionDigits); } _format += "}"; } public override string format (object value) { return string.Format (_format, value); } public override void setMaximumFractionDigits (int n) { _maximumFractionDigits = n; RebuildFormat (); } public override void setMinimumFractionDigits (int n) { _minimumFractionDigits = n; RebuildFormat (); } public override void setGroupingUsed (bool g) { } public static NumberFormat getInstance () { return new DecimalFormat (); } }

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  • Finding character in String in Vector.

    - by SoulBeaver
    Judging from the title, I kinda did my program in a fairly complicated way. BUT! I might as well ask anyway xD This is a simple program I did in response to question 3-3 of Accelerated C++, which is an awesome book in my opinion. I created a vector: vector<string> countEm; That accepts all valid strings. Therefore, I have a vector that contains elements of strings. Next, I created a function int toLowerWords( vector<string> &vec ) { for( int loop = 0; loop < vec.size(); loop++ ) transform( vec[loop].begin(), vec[loop].end(), vec[loop].begin(), ::tolower ); that splits the input into all lowercase characters for easier counting. So far, so good. I created a third and final function to actually count the words, and that's where I'm stuck. int counter( vector<string> &vec ) { for( int loop = 0; loop < vec.size(); loop++ ) for( int secLoop = 0; secLoop < vec[loop].size(); secLoop++ ) { if( vec[loop][secLoop] == ' ' ) That just looks ridiculous. Using a two-dimensional array to call on the characters of the vector until I find a space. Ridiculous. I don't believe that this is an elegant or even viable solution. If it was a viable solution, I would then backtrack from the space and copy all characters I've found in a separate vector and count those. My question then is. How can I dissect a vector of strings into separate words so that I can actually count them? I thought about using strchr, but it didn't give me any epiphanies.

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  • Format date in String Template email

    - by Gearóid
    I'm creating an email using String Template but when I print out a date, it prints out the full date (eg. Wed Apr 28 10:51:37 BST 2010). I'd like to print it out in the format dd/mm/yyyy but don't know how to format this in the .st file. I can't modify the date individually (using java's simpleDateFormatter) because I iterate over a collection of objects with dates. Is there a way to format the date in the .st email template?

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