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  • iPad start in Landscape receive only touch within 768x768

    - by user1307179
    It works perfect fine when starting in portrait and also works when you rotate from portrait to landscape and back. It does not work when starting in landscape. But then it works when you rotate from landscape to portrait and back. In landscape starting mode, the screen does not respond with any touch where screen coordinateX greater than 768. What happens in code is, I use status bar orientation to determine original orientation and rotate each view manually. The views display correctly but does not receive touch properly. Then my root view controller will get called when ipad start rotating with: - (void)willRotateToInterfaceOrientation:(UIInterfaceOrientation)toInterfaceOrientation duration:(NSTimeInterval)duration which will rotate every subviews. Root controller: - (void)loadView { self.view = [[UIView alloc]init ]; //initialize child views [self willRotateToInterfaceOrientation:0 duration:0]; } - (void)willRotateToInterfaceOrientation:(UIInterfaceOrientation)toInterfaceOrientation duration:(NSTimeInterval)duration { if ([model isLandscape]) { self.view.frame = CGRectMake(0, 0, 1024, 768-80); } else { self.view.frame = CGRectMake(0, 0, 768, 1024-80); } //rotate child views } My code [model isLandscape] works so I don't need to provide details as to how it works but here are the code anyway: - (bool)isLandscape { if (orientation == UIInterfaceOrientationLandscapeLeft || orientation == UIInterfaceOrientationLandscapeRight) return true; else return false; } -(id) init { [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(orientationChanged:) name:UIDeviceOrientationDidChangeNotification object:nil]; } - (void)orientationChanged:(NSNotification *)notification { UIInterfaceOrientation curOrientation = [[UIDevice currentDevice] orientation]; if (curOrientation == UIDeviceOrientationPortrait || curOrientation == UIDeviceOrientationPortraitUpsideDown || curOrientation == UIDeviceOrientationLandscapeLeft || curOrientation == UIDeviceOrientationLandscapeRight) { orientation = curOrientation; ((AppDelegate*)([UIApplication sharedApplication].delegate)).savedOrientationForRestart = orientation; NSLog(@"changed"); } } -(void)validateOrientation { //first time when initializing orientation UIInterfaceOrientation curOrientation = [[UIDevice currentDevice] orientation]; if (curOrientation != UIDeviceOrientationPortrait && curOrientation != UIDeviceOrientationPortraitUpsideDown && curOrientation != UIDeviceOrientationLandscapeLeft && curOrientation != UIDeviceOrientationLandscapeRight) { orientation = [[UIApplication sharedApplication] statusBarOrientation]; } }

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  • UITextField inside of UITableViewCell will not activate on iPad but works on iPhone

    - by cfihelp
    I have a UITextField inside a UITableViewCell. It will not activate on the iPad (but it works fine on the iPhone) no matter what I try. Tapping on it and telling it to become the firstResponder both fail. The odd thing is that if I take the exact same code and move it to another view controller in my app it executes just fine. This makes it seem as if there is likely a problem in the parent UITableViewController but I can't find anything obvious. I'm hoping that someone out there has experienced a similar problem and can point me in the right direction. Below is the sample code that works fine when I move it to a new project or put it in a new view controller launched immediately by my app delegate: // Customize the appearance of table view cells. - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; } if (indexPath.row == 0) { UITextField *nameText = [[UITextField alloc] initWithFrame:CGRectMake(5, 5, cell.contentView.frame.size.width, cell.contentView.frame.size.height)]; nameText.delegate = self; nameText.backgroundColor = [UIColor redColor]; [cell.contentView addSubview:nameText]; [nameText becomeFirstResponder]; [nameText release]; } // Configure the cell... return cell; } Help!

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  • Safari openwindow function behavior on iPad versus iPhone

    - by CodeLizard
    An identical javascript:openwindow call with a link to Google maps opens in Safari on the iPad but in the Google Maps App on the iPhone. Why the difference? <html> <head> </head> <body> <a title="View an area map for this property" href="javascript:openwindow ('http://maps.google.com/maps?f=q&source=s_q&hl=en&geocode=&q=1+Infinite+Loop, +Cupertino,+CA%E2%80%8E&sll=37.329389, -122.029696&sspn=0.015714,0.033023&ie=UTF8&hq=&hnear=1+Infinite+Loop, +Cupertino,+Santa+Clara, +California+95014&ll=37.331539, -122.030704&spn=0.007857,0.016512&z=17&ssa=1', 760, 500,'yes', 'yes')"> <font face="arial,helvetica" color="#000000" size="-1">Map It</font> </a> </body> <script> function openwindow(url,width,height,resizable,scrollbars,posx,posy) { if(posx==null)posx=20; if(posy==null)posy=20; now=new Date(); var x_offset=0; var y_offset=0; try { if(window.screen.left != undefined && window.screen.top != undefined) { x_offset=window.screen.left; y_offset=window.screen.top; } }catch(e){} var window_x=posx+x_offset; var window_y=posy+y_offset; new_window=window.open(url,now.getTime(),'width='+width+',height='+height+', resizable='+resizable+',scrollbars='+scrollbars+',top='+window_y+', left='+window_x+',screenX='+window_x+',screenY='+window_y); if(!new_window.opener) new_window.opener=self; try { new_window.focus(); }catch(e){} } </script> </html>

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  • How can I programmatically add more than just one view object to my view controller?

    - by BeachRunnerJoe
    I'm diving into iPhone OS development and I'm trying to understand how I can add multiple view objects to the "Left/Root" view of my SplitView iPad app. I've figured out how to programmatically add a TableView to that view based on the example code I found in Apple's online documentation... RootViewController.h @interface RootViewController : UITableViewController <NSFetchedResultsControllerDelegate, UITableViewDelegate, UITableViewDataSource> { DetailViewController *detailViewController; UITableView *tableView; NSFetchedResultsController *fetchedResultsController; NSManagedObjectContext *managedObjectContext; } RootViewController.m - (void)loadView { UITableView *newTableView = [[UITableView alloc] initWithFrame:[[UIScreen mainScreen] applicationFrame] style:UITableViewStylePlain]; newTableView.autoresizingMask = UIViewAutoresizingFlexibleHeight|UIViewAutoresizingFlexibleWidth; newTableView.delegate = self; newTableView.dataSource = self; [newTableView reloadData]; self.view = newTableView; [newTableView release]; } but there are a few things I don't understand about it and I was hoping you veterans could help clear up some confusion. In the statement self.view = newTableView, I assume I'm setting the entire view to a single UITableView. If that's the case, then how can I add additional view objects to that view alongside the table view? For example, if I wanted to have a DatePicker view object and the TableView object instead of just the TableView object, then how would I programmatically add that? Referencing the code above, how can I resize the table view to make room for the DatePicker view object that I'd like to add? Thanks so much in advance for your help! I'm going to continue researching these questions right now.

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  • iPhone/iPad : Check for invalid characters in a textbox made for Integers only

    - by JustinXXVII
    I noticed that the iPhone OS is pretty good about picking out Integer values when asked to. Specifically, if you use NSString *stringName = @"6("; int number = [stringName intValue]; the iPhone OS will pick out the 6 and turn the variable number into 6. However, in more complex mistypes, this also makes the int variable 6: NSString *stringName = @"6(5"; int number = [stringName intValue]; The iPhone OS misses the other digit, when what could have possibly been the user trying to enter the number 65, the OS only gets the number 6 out of it. I need a solution to check a string for invalid characters and return NO if there is anything other than an unsigned integer in a textbox. This is for iPad, and currently there is no numeric keyboard like the iPhone has, and I'm instead limited to the standard 123 keyboard. I was thinking that I need to use NSRange and somehow loop through the entire string in the textbox, and checking to see if the current character in the iteration is a number. I'm lost as far as that goes. I can think of testing it against zero, but zero is a valid integer. Can anyone help?

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  • How can I replace a UITableViewController with a UIViewController that contains a UITableView?

    - by Dr Dork
    I created a new SplitView iPad project in Xcode and setup the code to populate the TableView (in the RootView on the left) with data. Now I'd like to customize the RootView to contain a DatePicker view along with the TableView, but I'm unsure how to accomplish this. Since the default RootViewController is a subclass of a UITableViewController, I couldn't add a DatePicker view to it in IB (since you can't add a DatePicker to a UITableView). The only way I understand to accomplish my goal of adding a DatePicker to the "Left" RootView is to change the RootViewController from a subclass of a UITableViewController to a subclass of a UIViewController, then I'll be able to add a view to it that contains a DatePicker view and a TableView using IB. Questions... Is this the correct approach to add a DatePicker to the "Left" RootView? If so and I change the RootViewController to a subclass of a UIViewController (instead of a UITableViewController) and add to it a TableView (along with the DatePicker), how will that affect the code I currently have in place for populating my current TableView? Thanks so much for all your help! Below is my current interface code for my RootViewController, if it'll help any. @interface RootViewController : UITableViewController <NSFetchedResultsControllerDelegate> { DetailViewController *detailViewController; NSFetchedResultsController *fetchedResultsController; NSManagedObjectContext *managedObjectContext; } @property (nonatomic, retain) IBOutlet DetailViewController *detailViewController; @property (nonatomic, retain) NSFetchedResultsController *fetchedResultsController; @property (nonatomic, retain) NSManagedObjectContext *managedObjectContext; - (void)insertNewObject:(id)sender; @end

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  • glDrawArrays() slow on iPad?

    - by Nick
    Hey guys, I was wondering how to speed up my iPad application using OpenGLES 2.0. At the moment we have every drawable object draw itself with a call to glDrawArrays(). Blend mode is on, we really need it. Without disabling blendmode, how would we improve performance for this app? For instances, if we now draw 1 texture across the whole screen, the app only gets 15FPS, which is really slow I think? Are we doing something terribly wrong? Our drawing code (for each drawable), is as follows: - (void) draw { GLuint textureAvailable = 0; if(texture != nil){ textureAvailable = 1; } glActiveTexture(GL_TEXTURE0); glBindTexture(GL_TEXTURE_2D, texture.name); glVertexAttribPointer(ATTRIB_VERTEX, 2, GL_FLOAT, 0, 0, vertices); glEnableVertexAttribArray(ATTRIB_VERTEX); glVertexAttribPointer(ATTRIB_COLOR, 4, GL_FLOAT, 1, 0, colorsWithMultipliedAlpha); glEnableVertexAttribArray(ATTRIB_COLOR); glVertexAttribPointer(ATTRIB_TEXTUREMAP, 2, GL_FLOAT, 1, 0, textureMapping); glEnableVertexAttribArray(ATTRIB_TEXTUREMAP); //Note that we are NOT using position.z here because that is only used to determine drawing order int *jnUniforms = JNOpenGLConstants::getInstance().uniforms; glUniform4f(jnUniforms[UNIFORM_TRANSLATE], position.x, position.y, 0.0, 0.0); glUniform4f(jnUniforms[UNIFORM_SCALE], scale.x, scale.y, 1.0, 1.0); glUniform1f(jnUniforms[UNIFORM_ROTATION], rotation); glUniform1i(jnUniforms[UNIFORM_TEXTURE_SAMPLE], 0); glUniform2f(jnUniforms[UNIFORM_TEXTURE_REPEAT], textureRepeat.x, textureRepeat.y); glUniform1i(jnUniforms[UNIFORM_TEXTURE_AVAILABLE], textureAvailable); glDrawArrays(GL_TRIANGLE_STRIP, 0, 4); }

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  • Differences in accessing resources between Simulator and Device?

    - by Tony
    Is there some difference between the way that bundle resources can be accessed on the iPhone simulator versus a device (in my case, an iPad)? I am able to access a file on the former, but not the latter. NSString *filePath = [NSString stringWithFormat:@"%@%@",[[NSBundle mainBundle] bundlePath], @"/AppResources/html/pages/quickHelp.html"]; BOOL fileExists = [[NSFileManager defaultManager] fileExistsAtPath:filePath]; // fileExists == YES in the debugger on both the simulator and the device NSString *path = [NSString stringWithFormat:@"AppResources/html/pages/%@", contentsFileName]; NSString *pathForURL = [[NSBundle mainBundle] pathForResource:path ofType:@"html"]; NSURL *url = [NSURL fileURLWithPath:pathForURL isDirectory:NO]; The code above works fine in the simulator, but on the device pathForResource:path returns nil, so the last line throws a 'nil string parameter' exception. Am I missing something obvious? edit: Of course, in the above @"quickHelp" is being passed in the contentsFileName var. edit2: if it makes any difference, in my build settings "Base SDK" is set to "iPhone Device 4.0", and "iPhone OS Deployment Target" is set to "iPhone OS 3.1.3". Any other settings that might have an influence?

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  • Positioning objects in views during re-orientation in iPad

    - by Arni
    iPad Gurus: Apple wants us to support all orientations. I take that to mean that a particular layout should either rotate so that all objects are positioned relatively the same OR, if that doesn't look good, then they ought to be repositioned, OR two views ought to be designed and built. If I rely on the built-in rotation mechanism, the objects either get resized or they straddle the edge of the page in one orientation or the other, or they disappear from view altogether. I can't seem to find the right settings to get the objects to align clearly so they are seen in each orientation. Repositioning leads to a lot of if statements in the View Controller. So I don't think Apple had that in mind. I tried replacing views and even view controllers in "willRotateToInterfaceOrientation" method, but that either causes crashes or the portrait views end up in landscape unexpectedly and vv. Moreover, two view controllers means double the coding for the same view. There must be proper way to handle orientation changes, but I have searched the internet and documentation and sample code in vain for something that works. How is this done properly? Thanks!

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  • iPhone and iPad : Doing a "select * from something" query in a SQLite database

    - by Abramodj
    Hi folks, i'm trying to use the SQLite data base in my iPad app, and here's my function to make a query: - (void)executeQuery:(char*)query { NSString *file = [self getWritableDBPath]; NSFileManager *fileManager = [NSFileManager defaultManager]; BOOL success = [fileManager fileExistsAtPath:file]; // If its not a local copy set it to the bundle copy if(!success) { //file = [[NSBundle mainBundle] pathForResource:DATABASE_TITLE ofType:@"db"]; [self createEditableCopyOfDatabaseIfNeeded]; } dataArray = NULL; dataArray = [NSMutableArray array]; sqlite3 *database = NULL; if (sqlite3_open([file UTF8String], &database) == SQLITE_OK) { sqlite3_exec(database, query, loadTimesCallback, dataArray, NULL); } sqlite3_close(database); [self logResults]; } if I call [self executeQuery:"select name from table1"]; everything is working fine. But if i call [self executeQuery:"select * from cars"]; the app crashes telling me that the NSMutableArray dataArray is not the right kind of variable where to set the query results. So, how can i do a "select * form table1" query, and store the results? Thanks! EDIT: Here's my loadTimesCallback method: static int loadTimesCallback(void *context, int count, char **values, char **columns) { NSMutableArray *times = (NSMutableArray *)context; for (int i=0; i < count; i++) { const char *nameCString = values[i]; [times addObject:[NSString stringWithUTF8String:nameCString]]; } return SQLITE_OK; }

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  • Structuring iPhone/iPad application views

    - by Mark
    I have an idea about an application that I want to build and Im new to iPhone/iPad development (but not new to development in other languages/frameworks such as .NET and Java). I want to layout some views on the screen so that they animate (slide in) from different directions into their places. The question is about the strucuture of the application, if I have say 4 rectanglular areas on the screen that contain business data, such as contacts (name, photo, etc...) and they all take up different widths of the screen (say the first contact takes up one row of the screen, but the next 2 take up half the width of the next row each, and so on). Should I create a custom view for the different sized contact views, (i.e. LargeCustomView and SmallCustomView, and any other special type that I make) or should it all be one type, say, CustomerDetailsView which could be stretched to fit at design time? Also, if there were, say, 3 different instances of the same custom view on the one screen, are there 3 instances of the view controller also? Im a little confused about powering the data behind a view, can someone shed some light on this for me? Do I just set the properties (say an instance variable ContactForView) on the view controller for each instance? Thanks for any help you can give Cheers, Mark

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  • Getting Exception thrown and not caught error on jquery ui tabs in ie8

    - by Jason
    I am getting the following error (pointing to jquery-1.4.2.js): Message: Exception thrown and not caught Line: 2904 Char: 2 Code: 0 With the following: IE8 jquery 1.4.2 jquery ui 1.8.1 When I do the following: $("#theTabs").tabs(); On the same page I also have two instances of the jquery ui dialog and one instance of the jquery ui accordion. Am I missing something? This does not happen in FF on Windows (nor in Safari or FF on OS X) I use the same code elsewhere for tabs and they work just fine.

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  • jqGrid jQuery UI button wrapping in toolbar

    - by gurun8
    I have a jQuery UI Button that I'm placing in a jqGrid toolbar but the contents of the button are wrapping. I've tried to prevent the wrapping by using CSS white-space Property to no avail. Here's a snapshot of what's happening: Here are two code snippets of my attempt to fix the problem: $("#t_imageList").css("white-space", "nowrap").html('<button>Add</button>'); $("#t_imageList button").button({ icons: {primary: 'ui-icon-plus'}, text: true }); and/or $("#t_imageList button").css("white-space", "nowrap").button({ icons: {primary: 'ui-icon-plus'}, text: true }); Has someone experienced the same issue? If so, what was your solution?

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  • JQUERY UI Accordion Resize on Window Resize?

    - by nobosh
    I'm using the JQUERY UI Accordion module: <script type="text/javascript"> $(function() { $("#sidebar_column_accordion").accordion({ fillSpace: true, icons: { 'header': 'ui-icon-plus', 'headerSelected': 'ui-icon-minus' } }); }); </script> By using the fillSpace option, the accordion takes up the entire height of the window which I want. Problem is it calculate the height on page load, and if the user resizes their browser, it does not adjust... Is there a way to have the accordion recalculate the height/size when the browser window is resized? Thanks

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  • jquery ui tabs major style change

    - by Jonah
    I am using jquery UI tabs and I need to majorly change the styling on it. I need to rempve the background image, the borders, almost everything. I need it to look minimal, and not like it's self contained. What's the best way to do this? I need to use the default UI styling for the calendar widget however, which is on the same page. I've done a lot of research and everyone seems to point to the theme-roller. However, i do not just want to change the colors and border radii. I need to delete crap. theme-roller seems to be just change things like colors (not really useful for the real world) Is it even worth using jquery UI for my tabs?

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  • JQuery UI sortable is slow in IE8, but works good in IE7 and IE8 compatible mode

    - by artvolk
    JQuery UI sortable (including demos) are slow in all IE8 I can test, but runs smoothly in IE7 and IE8 compatible mode. The more complex is a markup on the page, the more IE8 is slowing down (that's I can understand, the DOM tree became more complex). I'm using JQuery 1.3.2 and JQuery UI 1.7.2 (tested with 1.7.3 -- the same story). I've found a lot of similar reports (for the new JQuery UI 1.8.x with JQuery 1.4 too), but no answers. May be there is a some solution (EXCEPT turning IE8 into IE7 compatibility mode by metatag or header). Thanks in advance!

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  • Undefined Results in jQuery Autocomplete

    - by CreativeNotice
    So I've got the latest versions of jQuery and UI running. I'm using the basic autocomplete invocation and returning valid JSON (validated via JSONLint). $("input#cust_id").autocomplete({ source: yoda.app.base + "/assets/cfc/util/autocomplete.cfc?method=cust", minLength: 2, select: function(event, ui) { log(ui.item ? ("Selected: " + ui.item.value + " aka " + ui.item.id) : "Nothing selected, input was " + this.value); } }); Both the value and label elements of the returned array show up in the list as undefined. I can watch the results returned via Firebug and the JSON is correct there as well. Also, while the list only says "undefined" it does say that the same number of times as records returned in JSON. [{"VALUE":"custid1","LABEL":"My Customer Name 1"},{"VALUE":"custname2","LABEL":"My customer name 2"}]

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  • jquery UI portlet inside tab - out of boundary problem

    - by mango
    I am using jquery UI tab, and one of the tab panels contains the UI portlets. The problem is that the portlets are not inside the tab boundary, here is a screen shot: http://pic20.picturetrail.com/VOL22/543225/792958/384422925.jpg here is the main page http://codepad.org/fQRxsosu here is the include file for the portlets, newPortlets.html which is essentially the example from jquery ui docs. http://codepad.org/kAlT9CAy the tab containing the portlet will be ultimately created dynamically. i have been looking at the markup, etc using firebug and there is no error. tia for any help!

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  • Jquery UI Sortable - Get the item being sorted.

    - by Smickie
    Hi, When using Jquery UI Sortable (which is great by the way) how do you get the item that is currently being sorted. When you use $(this); it return the actual sortable list, not the current sorted item. I want to do fancy-pants things with the widget when the user is dragging it around. E.g. Animate it when dragging between two lists. So how do I get the current item being sorted? There a little code below just to explain a little more... $(function() { $("#sortable_1").sortable({ start : function(event, ui){ //get current element being sorted }, stop : function(event, ui){ //get current element being sorted } }).disableSelection(); });

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  • jQuery UI Draggable-Droppable overflow:visible

    - by Jeff
    Sadly, I am unable to provide any JSFiddle for this issue, as I cant seem to reproduce it outside my project. I have a container where there are some boxes, that can be arranged using drag and drop, by utilizing jQuery UI. The problem is, that the container is overflow:auto; but it needs to be overflow:visible;, but if I do that, jQuery UI malfunctions. When a box drag is initiated, it will immediatly jump up aproximately 400-500px. This is how the draggable is created: $(".draggable").draggable({ revert: 'invalid', // when not dropped, the item will revert back to its initial position containment: '#editContainer', // stick to demo-frame if present helper: 'original', cursor: 'move' }); Is this a bug with jQuery UI, or can this be fixed on my end? I apologize for the lack of source code.

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  • JQuery UI: Accordion callbacks

    - by user177215
    I need my javascript to only do the callback when I OPEN a section on the accordion, as of right now it does a callback when I open OR close a section because I'm only using a click function. Is there a way I can modify my existing click function to only run when the given section is activated? My current click function: $("a#mimetypes").click(function() { $("span#mimetypesthrobber").loading(true, { max: 1500 }) $.getJSON("../mimetypes", function(data) { //callback }); }); Thanks! EDIT: I already tried this with another part of the accordion and it wasn't working properly: $('.ui-accordion').bind('accordionchange', function(event, ui) { if (ui.newHeader == "Encoders") { EncodersGet(); } });

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  • jquery-ui from a bookmarklet

    - by Mala
    Hi I'm trying to create a bookmarklet which will use the jquery-ui - what steps must I take to do this? My bookmarklet loads a remote script and appends it to the page. This script includes jquery and jquery-ui, but getting the stylesheets and images is turning into a nightmare. Do I have to edit all the CSS to point images to their locations on the remote server? Effectively what I'm trying to do is have a bookmarklet which will pop up some information in a nice pretty draggable jquery-ui dialog. Is there an easier way? Thanks, Mala

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  • Drag and drop: jQuery UI or Scriptaculous?

    - by jpartogi
    Dear all, I am in the middle of the road whether to use jQuery UI or Scriptaculous for drag and drop. I am using Ruby on Rails, and Scriptaculous support in Ruby on Rails is superb with the existence of scriptaculous_helper.rb. But I have already use jQuery for the ajax and DOM manipulation. I do not mind to use scriptaculous since we can use jQuery.noConflict() in the code. I also kind of get the impression that scriptaculous drag and drop is better than jQuery UI drag and drop based on the online demos. So back to the original question, which one would you recommend as a drag and drop library and which one do you think is better than the other? Scriptaculous or jQuery UI?

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  • Want to bind an input field to a jquery-ui slider handle

    - by BFTrick
    hello, I want to bind an input field to the jquery-ui slider handle. So whenever one value changes I want the other value to also change. Ex: if someone types 1000 into the minimum value input field I want the lower slider handle to move to the 1000 mark. Also if the user drags the lower slider handle to 1000 the input field should reflect that. Making the slider reflect the changes in the input field is easy: $(minYearInput).blur(function () { $("#yearSlider").slider("values", 0, parseInt($(this).val())); }); $(maxYearInput).blur(function () { $("#yearSlider").slider("values", 1, parseInt($(this).val())); }); I just need help making the text fields mimic the slider. $("#yearSlider").slider({ range: true, min: 1994, max: 2011, step: 1, values: [ 1994 , 2011 ], slide: function(event, ui) { //what goes here? } }); Any ideas? A similar question from this site: http://stackoverflow.com/questions/1330008/jquery-ui-slider-input-a-value-and-slider-move-to-location

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  • Android Activities UI Persistence

    - by aandroid
    I need to have two activities in an Android app that can be switched between each other with UI persistence as follows: Activity A launches Activity B. User triggers some UI changes in Activity B. Activity B returns to Activity A (by a call to onBackPressed() or something similar) Activity A re-launches Activity B. I would like the changes made in step 2 to be visible in step 4. I have tried using the singleInstance activity tag on Activity B to no avail. I would also prefer a more elegant solution than simply writing all object properties to a file or SQLite table. It seems that this behaviour must be easily achievable given that Android does it automatically for calls to onBackPressed() where the parent Activity's UI is saved. Any help is much appreciated.

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