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  • Search for specific call in asterisk log files

    - by chiborg
    In my Asterisk log file, I have a line like this (truncated): Executing [123@mycontext:1] Set("SIP/myhost-b7111840", "__INCOMINGCLI=4711") Now I want to do the following filtering while looking at the log file with tail -f: Match lines with a specific value for "INCOMINGCLI", storing the call ID (the "SIP/myhost-b7111840" part) Output all subsequent lines that contain the call ID. As a bonus, having a grep-like option like -A would be nice. I could do that easily in various programming languages, but how would I do it with standard UNIX commands like sed or awk? Can it be done with these commands?

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  • copy files created in one folder to multiple other folders on linux

    - by Keith
    I'm looking for a way to copy photos that are uploaded to one folder to many other folders and visa versa. Example: a photo is uploaded to folder 1, it is then copied to folders 2-5. And if a photo is uploaded to folder 2 it is copied to folders 1 and 3-5. I'm running CentOS 5. All of these folders are on the same server. I came across another post on here that talked about incron, but that type of programming is over my head.

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  • VNC - Is there any way to turn off logging/log files

    - by Ke
    Hi, I've looked everywhere for a solution to this. Is there any way to turn off this logging in VNC? VNC seems to be logging some large updates I'm doing in mysql and taking up my whole hard drive space. The only way to get rid of the log file is to reboot, which I would prefer not to have to do if possible. Cheers

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  • Is there a piece of software which lets you turn "anything" into a dynamic reorderable list?

    - by Robin Green
    I could write this myself, but I want to know if it already exists. Basically, it must fulfill these criteria: To reorder items, the user must never have to manually renumber them. That would be annoying, and it doesn't scale. Can read from a range of data sources (e.g. a database, a directory on the file system, a text file, another list) When the original data source changes, the list must automatically change with it (possibly with confirmation, e.g. if a list item would be deleted) Ability to persist the list ordering in some fashion Graphical display of list items (so that they can include e.g. images) Optional extras: Ability to modify data and write back to the data source (other than the ordering information)

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  • C# - Cannot implicitly convert type List<Product> to List<IProduct>

    - by Keith Barrows
    I have a project with all my Interface definitions: RivWorks.Interfaces I have a project where I define concrete implmentations: RivWorks.DTO I've done this hundreds of times before but for some reason I am getting this error now: Cannot implicitly convert type 'System.Collections.Generic.List<RivWorks.DTO.Product>' to 'System.Collections.Generic.List<RivWorks.Interfaces.DataContracts.IProduct>' Interface definition (shortened): namespace RivWorks.Interfaces.DataContracts { public interface IProduct { [XmlElement] [DataMember(Name = "ID", Order = 0)] Guid ProductID { get; set; } [XmlElement] [DataMember(Name = "altID", Order = 1)] long alternateProductID { get; set; } [XmlElement] [DataMember(Name = "CompanyId", Order = 2)] Guid CompanyId { get; set; } ... } } Concrete class definition (shortened): namespace RivWorks.DTO { [DataContract(Name = "Product", Namespace = "http://rivworks.com/DataContracts/2009/01/15")] public class Product : IProduct { #region Constructors public Product() { } public Product(Guid ProductID) { Initialize(ProductID); } public Product(string SKU, Guid CompanyID) { using (RivEntities _dbRiv = new RivWorksStore(stores.RivConnString).NegotiationEntities()) { model.Product rivProduct = _dbRiv.Product.Where(a => a.SKU == SKU && a.Company.CompanyId == CompanyID).FirstOrDefault(); if (rivProduct != null) Initialize(rivProduct.ProductId); } } #endregion #region Private Methods private void Initialize(Guid ProductID) { using (RivEntities _dbRiv = new RivWorksStore(stores.RivConnString).NegotiationEntities()) { var localProduct = _dbRiv.Product.Include("Company").Where(a => a.ProductId == ProductID).FirstOrDefault(); if (localProduct != null) { var companyDetails = _dbRiv.vwCompanyDetails.Where(a => a.CompanyId == localProduct.Company.CompanyId).FirstOrDefault(); if (companyDetails != null) { if (localProduct.alternateProductID != null && localProduct.alternateProductID > 0) { using (FeedsEntities _dbFeed = new FeedStoreReadOnly(stores.FeedConnString).ReadOnlyEntities()) { var feedProduct = _dbFeed.AutoWithImage.Where(a => a.ClientID == companyDetails.ClientID && a.AutoID == localProduct.alternateProductID).FirstOrDefault(); if (companyDetails.useZeroGspPath.Value || feedProduct.GuaranteedSalePrice > 0) // kab: 2010.04.07 - new rules... PopulateProduct(feedProduct, localProduct, companyDetails); } } else { if (companyDetails.useZeroGspPath.Value || localProduct.LowestPrice > 0) // kab: 2010.04.07 - new rules... PopulateProduct(localProduct, companyDetails); } } } } } private void PopulateProduct(RivWorks.Model.Entities.Product product, RivWorks.Model.Entities.vwCompanyDetails RivCompany) { this.ProductID = product.ProductId; if (product.alternateProductID != null) this.alternateProductID = product.alternateProductID.Value; this.BackgroundColor = product.BackgroundColor; ... } private void PopulateProduct(RivWorks.Model.Entities.AutoWithImage feedProduct, RivWorks.Model.Entities.Product rivProduct, RivWorks.Model.Entities.vwCompanyDetails RivCompany) { this.alternateProductID = feedProduct.AutoID; this.BackgroundColor = Helpers.Product.GetCorrectValue(RivCompany.defaultBackgroundColor, rivProduct.BackgroundColor); ... } #endregion #region IProduct Members public Guid ProductID { get; set; } public long alternateProductID { get; set; } public Guid CompanyId { get; set; } ... #endregion } } In another class I have: using dto = RivWorks.DTO; using contracts = RivWorks.Interfaces.DataContracts; ... public static List<contracts.IProduct> Get(Guid companyID) { List<contracts.IProduct> myList = new List<dto.Product>(); ... Any ideas why this might be happening? (And I am sure it is something trivially simple!)

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  • Complete Guide to Networking Windows 7 with XP and Vista

    - by Mysticgeek
    Since there are three versions of Windows out in the field these days, chances are you need to share data between them. Today we show how to get each version to be share files and printers with one another. In a perfect world, getting your computers with different Microsoft operating systems to network would be as easy as clicking a button. With the Windows 7 Homegroup feature, it’s almost that easy. However, getting all three of them to communicate with each other can be a bit of a challenge. Today we’ve put together a guide that will help you share files and printers in whatever scenario of the three versions you might encounter on your home network. Sharing Between Windows 7 and XP The most common scenario you’re probably going to run into is sharing between Windows 7 and XP.  Essentially you’ll want to make sure both machines are part of the same workgroup, set up the correct sharing settings, and making sure network discovery is enabled on Windows 7. The biggest problem you may run into is finding the correct printer drivers for both versions of Windows. Share Files and Printers Between Windows 7 & XP  Map a Network Drive Another method of sharing data between XP and Windows 7 is mapping a network drive. If you don’t need to share a printer and only want to share a drive, then you can just map an XP drive to Windows 7. Although it might sound complicated, the process is not bad. The trickiest part is making sure you add the appropriate local user. This will allow you to share the contents of an XP drive to your Windows 7 computer. Map a Network Drive from XP to Windows 7 Sharing between Vista and Windows 7 Another scenario you might run into is having to share files and printers between a Vista and Windows 7 machine. The process is a bit easier than sharing between XP and Windows 7, but takes a bit of work. The Homegroup feature isn’t compatible with Vista, so we need to go through a few different steps. Depending on what your printer is, sharing it should be easier as Vista and Windows 7 do a much better job of automatically locating the drivers. How to Share Files and Printers Between Windows 7 and Vista Sharing between Vista and XP When Windows Vista came out, hardware requirements were intensive, drivers weren’t ready, and sharing between them was complicated due to the new Vista structure. The sharing process is pretty straight-forward if you’re not using password protection…as you just need to drop what you want to share into the Vista Public folder. On the other hand, sharing with password protection becomes a bit more difficult. Basically you need to add a user and set up sharing on the XP machine. But once again, we have a complete tutorial for that situation. Share Files and Folders Between Vista and XP Machines Sharing Between Windows 7 with Homegroup If you have one or more Windows 7 machine, sharing files and devices becomes extremely easy with the Homegroup feature. It’s as simple as creating a Homegroup on on machine then joining the other to it. It allows you to stream media, control what data is shared, and can also be password protected. If you don’t want to make your Windows 7 machines part of the same Homegroup, you can still share files through the Public Folder, and setup a printer to be shared as well.   Use the Homegroup Feature in Windows 7 to Share Printers and Files Create a Homegroup & Join a New Computer To It Change which Files are Shared in a Homegroup Windows Home Server If you want an ultimate setup that creates a centralized location to share files between all systems on your home network, regardless of the operating system, then set up a Windows Home Server. It allows you to centralize your important documents and digital media files on one box and provides easy access to data and the ability to stream media to other machines on your network. Not only that, but it provides easy backup of all your machines to the server, in case disaster strikes. How to Install and Setup Windows Home Server How to Manage Shared Folders on Windows Home Server Conclusion The biggest annoyance is dealing with printers that have a different set of drivers for each OS. There is no real easy way to solve this problem. Our best advice is to try to connect it to one machine, and if the drivers won’t work, hook it up to the other computer and see if that works. Each printer manufacturer is different, and Windows doesn’t always automatically install the correct drivers for the device. We hope this guide helps you share your data between whichever Microsoft OS scenario you might run into! Here are some other articles that will help you accomplish your home networking needs: Share a Printer on a Home Network from Vista or XP to Windows 7 How to Share a Folder the XP Way in Windows Vista Similar Articles Productive Geek Tips Delete Wrong AutoComplete Entries in Windows Vista MailSvchost Viewer Shows Exactly What Each svchost.exe Instance is DoingFixing "BOOTMGR is missing" Error While Trying to Boot Windows VistaShow Hidden Files and Folders in Windows 7 or VistaAdd Color Coding to Windows 7 Media Center Program Guide TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 Icelandic Volcano Webcams Open Multiple Links At One Go NachoFoto Searches Images in Real-time Office 2010 Product Guides Google Maps Place marks – Pizza, Guns or Strip Clubs Monitor Applications With Kiwi

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  • Converting hierarchial data into an unordered list Programmatically using asp.net/C#

    - by kranthi
    hi everyone, I've data which looks something like this. | id | name | depth | itemId | +-----+----------------------+-------+-------+ | 0 | ELECTRONICS | 0 | NULL | | 1 | TELEVISIONS | 1 | NULL | | 400 | Tube | 2 | NULL | | 432 | LCD | 3 | 1653 | | 422 | Plasma | 3 | 1633 | | 416 | Portable electronics | 3 | 1595 | | 401 | MP3 Player | 3 | 1249 | | 191 | Flash | 2 | NULL | | 555 | CD Players | 3 | 2198 | | 407 | 2 Way Radio | 3 | 1284 | | 388 | I've a problem with | 3 | 1181 | | 302 | What is your bill pa | 3 | 543 | | 203 | Where can I find my | 3 | 299 | | 201 | I would like to make | 3 | 288 | | 200 | Do you have any job | 3 | 284 | | 192 | About Us | 3 | NULL | | 199 | What can you tell me | 4 | 280 | | 198 | Do you help pr | 4 | 276 | | 197 | would someone help co| 4 | 272 | | 196 | can you help ch | 4 | 268 | | 195 | What awards has Veri | 4 | 264 | | 194 | What's the latest ne | 4 | 260 | | 193 | Can you tell me more | 4 | 256 | | 180 | Site Help | 2 | NULL | | 421 | Where are the | 3 | 1629 | | 311 | How can I access My | 3 | 557 | | 280 | Why isn't the page a | 3 | 512 | To convert the above data into unordered list based on depth, I'm using the following code int lastDepth = -1; int numUL = 0; StringBuilder output = new StringBuilder(); foreach (DataRow row in ds.Tables[0].Rows) { int currentDepth = Convert.ToInt32(row["Depth"]); if (lastDepth < currentDepth) { if (currentDepth == 0) { output.Append("<ul class=\"simpleTree\">"); output.AppendFormat("<li class=\"root\"><span><a href=\"#\" title=\"root\">root</a></span><ul><li class=\"open\" ><span><a href=\"#\" title={1}>{0}</a></span>", row["name"],row["id"]); } else { output.Append("<ul>"); if(currentDepth==1) output.AppendFormat("<li><span>{0}</span>", row["name"]); else output.AppendFormat("<li><span class=\"text\"><a href=\"#\" title={1}>{0}</a></span>", row["name"], row["id"]); } numUL++; } else if (lastDepth > currentDepth) { output.Append("</li></ul></li>"); if(currentDepth==1) output.AppendFormat("<li><span>{0}</span>", row["name"]); else output.AppendFormat("<li><span class=\"text\"><a href=\"#\" title={1}>{0}</a></span>", row["name"], row["id"]); numUL--; } else if (lastDepth > -1) { output.Append("</li>"); output.AppendFormat("<li><span class=\"text\"><a href=\"#\" title={1}>{0}</a></span>", row["name"],row["id"]); } lastDepth = currentDepth; } for (int i = 1; i <= numUL+1; i++) { output.Append("</li></ul>"); } myliteral.text=output.ToString(); But the resulting unordered list doesnt seem to be forming properly(using which i am constructing a tree).For example "Site Help" with id '180' is supposed to appear as a direct child of "Televisions" with id '1',is appearing as a direct child of 'Flash' with id '191' using my code.so in addition to considering depth,I've decided to consider itemid as well in order to get the treeview properly.Those rows of the table with itemId not equal to null are not supposed to have a child node(i.e.,they are the leaf nodes in the tree) and all the other nodes can have child nodes. Please could someone help me in constructing a proper unordered list based on my depth,itemid coulumns? Thanks.

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  • Linked List exercise, what am I doing wrong?

    - by Sean Ochoa
    Hey all. I'm doing a linked list exercise that involves dynamic memory allocation, pointers, classes, and exceptions. Would someone be willing to critique it and tell me what I did wrong and what I should have done better both with regards to style and to those subjects I listed above? /* Linked List exercise */ #include <iostream> #include <exception> #include <string> using namespace std; class node{ public: node * next; int * data; node(const int i){ data = new int; *data = i; } node& operator=(node n){ *data = *(n.data); } ~node(){ delete data; } }; class linkedList{ public: node * head; node * tail; int nodeCount; linkedList(){ head = NULL; tail = NULL; } ~linkedList(){ while (head){ node* t = head->next; delete head; if (t) head = t; } } void add(node * n){ if (!head) { head = n; head->next = NULL; tail = head; nodeCount = 0; }else { node * t = head; while (t->next) t = t->next; t->next = n; n->next = NULL; nodeCount++; } } node * operator[](const int &i){ if ((i >= 0) && (i < nodeCount)) throw new exception("ERROR: Invalid index on linked list.", -1); node *t = head; for (int x = i; x < nodeCount; x++) t = t->next; return t; } void print(){ if (!head) return; node * t = head; string collection; cout << "["; int c = 0; if (!t->next) cout << *(t->data); else while (t->next){ cout << *(t->data); c++; if (t->next) t = t->next; if (c < nodeCount) cout << ", "; } cout << "]" << endl; } }; int main (const int & argc, const char * argv[]){ try{ linkedList * myList = new linkedList; for (int x = 0; x < 10; x++) myList->add(new node(x)); myList->print(); }catch(exception &ex){ cout << ex.what() << endl; return -1; } return 0; }

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  • Common idiom in Java to Scala, traverse/Iterate Java list into Scala list

    - by Berlin Brown
    I am processing a XML document and iterating through nodes. I want to iterate through the nodes and build a new List of some type. How would I do this with Scala: Here is my XML traverse code: def findClassRef(xmlNode: Elem) = { xmlNode\"classDef" foreach { (entry) => val name = entry \ "@name" val classid = entry \ "@classId" println(name + "//" + classid) } } Where the line of println is, I want to append elements to a list.

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  • Why declare "private List contactInfos" without a generic ("private List <ContactInfo> contactInfos"

    - by g_imp
    In this example from the App Engine docs, why does the example declare contactInfos like this (no Generics): import javax.jdo.annotations.Element; // ... @Persistent @Element(dependent = "true") private List contactInfos; instead of like this, using a Generic: import javax.jdo.annotations.Element; // ... @Persistent @Element(dependent = "true") private List <ContactInfo> contactInfos;

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  • not able to add list item between a list using jquery

    - by Pradyut Bhattacharya
    Hi I m having a ordered list having the structure Test another test Add I want to add a list item between sublist 2 and 3 using jquery I used the code: - $("ol#update li ol li:eq(1)").append("<li> test </li>"); But this appends inside the li "another test" and not after the 2 li Here is the example page On-click "sub-comment" adds a li inside li 2 Clicking on "comment" shows the structure of the sub lis Please help Thanks Pradyut

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  • Haskell Add Function Return to List Until Certain Length

    - by kienjakenobi
    I want to write a function which takes a list and constructs a subset of that list of a certain length based on the output of a function. If I were simply interested in the first 50 elements of the sorted list xs, then I would use fst (splitAt 50 (sort xs)). However, the problem is that elements in my list rely on other elements in the same list. If I choose element p, then I MUST also choose elements q and r, even if they are not in the first 50 elements of my list. I am using a function finderFunc which takes an element a from the list xs and returns a list with the element a and all of its required elements. finderFunc works fine. Now, the challenge is to write a function which builds a list whose total length is 50 based on multiple outputs of finderFunc. Here is my attempt at this: finish :: [a] -> [a] -> [a] --This is the base case, which adds nothing to the final list finish [] fs = [] --The function is recursive, so the fs variable is necessary so that finish -- can forward the incomplete list to itself. finish ps fs -- If the final list fs is too small, add elements to it | length fs < 50 && length (fs ++ newrs) <= 50 = fs ++ finish newps newrs -- If the length is met, then add nothing to the list and quit | length fs >= 50 = finish [] fs -- These guard statements are currently lacking, not the main problem | otherwise = finish [] fs where --Sort the candidate list sortedps = sort ps --(finderFunc a) returns a list of type [a] containing a and all the -- elements which are required to go with it. This is the interesting -- bit. rs is also a subset of the candidate list ps. rs = finderFunc (head sortedps) --Remove those elements which are already in the final list, because -- there can be overlap newrs = filter (`notElem` fs) rs --Remove the elements we will add to the list from the new list -- of candidates newps = filter (`notElem` rs) ps I realize that the above if statements will, in some cases, not give me a list of exactly 50 elements. This is not the main problem, right now. The problem is that my function finish does not work at all as I would expect it to. Not only does it produce duplicate elements in the output list, but it sometimes goes far above the total number of elements I want to have in the list. The way this is written, I usually call it with an empty list, such as: finish xs [], so that the list it builds on starts as an empty list.

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  • Splitting list into a list of possible tuples

    - by user1742646
    I need to split a list into a list of all possible tuples, but I'm unsure of how to do so. For example pairs ["cat","dog","mouse"] should result in [("cat","dog"), ("cat","mouse"), ("dog","cat"), ("dog","mouse"), ("mouse","cat"), ("mouse","dog")] I was able to form the first two, but am unsure of how to get the rest. Here's what I have so far: pairs :: [a] -> [(a,a)] pairs (x:xs) = [(m,n) | m <- [x], n <- xs]

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  • find if list 1 is a sequence of list 2 in haskell

    - by Isaak Wahb
    im trying to check if a given list is a subsequence of another list: here are example of lists which gives true: subseq "" "w" subseq "w" "w" subseq "ab" "cab" subseq "cb" "cab" subseq "aa" "xaxa" not (subseq "aa" "xax") not (subseq "ab" "ba") i just come to this but in some cases it gives a wrong result subseq :: Eq a => [a] -> [a] -> Bool subseq [] [] = True subseq [] ys = True subseq xs [] = False subseq (x:xs) (y:ys) = x == y || subseq xs ( 1 `drop` ys )

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  • troubles creating a List of doubles from a list of objects

    - by Michel
    Hi, i have a list with objects. The object has a property 'Sales' which is a string. Now i want to create a list of doubles with the values of all objects' 'Sales' properties. I tried this: var tmp = from n in e.Result select new{ Convert.ToDouble ( n.Sales) }; but this gives me this error: Error 106 Invalid anonymous type member declarator. Anonymous type members must be declared with a member assignment, simple name or member access.

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  • django convert list of objects to list of primary keys

    - by John
    Hi, As the title says I have a list of Django objects and I want to get a list of primary keys. What is the best way of doing this? I know I could do my_list = [] for item in object_list: my_list.append(item.pk) but was wondering if there is Django or Python specific way of doing this better. Thanks

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  • Could not determine metatable error binding list to asp.net datagridview

    - by Scott Vercuski
    I am working with the following block of code ... List<ThemeObject> themeList = (from theme in database.Themes join image in database.DBImages on theme.imageID equals image.imageID into resultSet from item in resultSet select new ThemeObject { Name = theme.Name, ImageID = item.imageID}).ToList(); dgvGridView.DataSource = themeList; dgvGridView.DataBind(); The list object populates fine. The datagrid is setup with 2 columns. A textbox column for the "Name" which is bound to "Name" An image column which is bound to the "ImageID" field When I execute the code I receive the following error on the DataBind() Could not determine a MetaTable. A MetaTable could not be determined for the data source '' and one could not be inferred from the request URL. Make sure that the table is mapped to the dats source, or that the data source is configured with a valid context type and table name, or that the request is part of a registered DynamicDataRoute. I'm not using any dynamicdataroutes as far as I can tell. Has anyone experienced this error before?

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  • [WPF Datagrid] Binding to a List<>

    - by Tr?n Qu?c Bình
    I have a datagrid like this: <dg:DataGrid Name="dg" AutoGenerateColumns="False" CanUserDeleteRows="True"> <dg:DataGrid.Columns> <dg:DataGridTextColumn Header="Product Code" x:Name="columnProductCode" Binding="{Binding Path=Product.ProductCode}" IsReadOnly="True" ></dg:DataGridTextColumn> <dg:DataGridTextColumn Header="Product Name" x:Name="columnProductName" Binding="{Binding Path=Product.Name}" IsReadOnly="True" ></dg:DataGridTextColumn> <dg:DataGridTextColumn Header="ProductMeasure" x:Name="columnDonViTinh" Binding="{Binding Path=Product.Measure IsReadOnly="True"></dg:DataGridTextColumn> <dg:DataGridTextColumn Header="Quantity" x:Name="ColumnQuantity" Binding="{Binding Path=Quantity IsReadOnly="False"></dg:DataGridTextColumn> </dg:DataGrid.Columns> </dg:DataGrid> In the behind code, I have a struct like this: private struct ProductDetail { public TProduct Product { get; set ; } // TProduct is a class provied by a web service public int Quantity { get; set; } } and a List like this: private IList<ProductDetail> bs = new List<ProductDetail>(); I had tried to fill data to "bs". And binding like this: this.dg.ItemsSource = this.bs; Everything is ok. I can insert a new row, delete row, but when I try to modified the column Quantity then click on the header of the datagrid (to resort) -- the Quantity column change to it is before. How can I fix this problem. Thanks advanced.

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  • select & print multiple value from dropdown list

    - by sandy
    hi , in this code how can selected multiple value from dropdown list <?php include ("connect.php"); $member_id = intval($_POST['sector_list']); if($member_id == 0) { // Default choice was selected } else { $res = mysql_query("SELECT * FROM members WHERE MemberID = $member_id LIMIT 1"); if(mysql_num_rows($res) == 0) { // Not a valid member } else { // The member is in the database } } ?> <form method="post" action=""> <input type="hidden" name="sector" value="sector_list"> <select name="sector_list" class="inputstandard" multiple="multiple"> <option value="0">send to</option> <?php $result = mysql_query('SELECT * from members') or die(mysql_error()); while ($row = mysql_fetch_assoc($result)) { echo '<option value="' . $row['MemberID'] . '">' . $row['MemberName']. '</option>'; } ?> </select> </form> assume the drop down list contain on (a,s,d,f,g,h,j,) users selects multiple value ( a,s,j) output = a,s,j not only j ???

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  • Presentation Issue in an Unordered List

    - by phreeskier
    I'm having an issue with correctly presenting items in an unordered list. The labels are floating left and the related spans that are long in length are wrapping and showing below the label. I need a solution that keeps the related spans in their respective columns. In other words, I don't want long spans to show under the labels. What property can I take advantage of so that I get the desired layout in all of the popular browsers, including IE6? Thanks in advance for the help. My code is as follows: <ul> <li> <label>Name</label> <span><%= Html.Encode(Model.Name) %></span> </li> <li> <label>Entity</label> <span><%= Html.Encode(Model.Entity) %></span> </li> <li> <label>Phone</label> <span><%= Html.Encode(Model.Phone) %></span> </li> </ul> My CSS styling is as follows: ul { display:block; list-style-type:none; margin:0; padding:0; } ul li label { float:left; width:100px; }

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  • How to create a list/structure? in JAVA

    - by lox
    i have to create a list of ,let's say 50 people, (in JAVA) and display the list, and i don't really know how to do that. so this is what i have tried to do so far . please correct and complete some of my code . public class Person { String name; String stuff; } public class CreatePerson { public static void ang() { ArrayList<Person> thing=new ArrayList<Person>(); Scanner diskScanner = new Scanner(in); for(int i=0; i<50; i++){ Person pers = new Person(); out.print("name: "); pers.name=diskScanner.nextLine(); out.print("stuff: "); pers.stuff=diskScanner.nextLine(); thing.add(pers); break; } // Display people for (int i=0; i<50; i++) { out.println(??);{ } } }}

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