Search Results

Search found 65497 results on 2620 pages for 'list files'.

Page 36/2620 | < Previous Page | 32 33 34 35 36 37 38 39 40 41 42 43  | Next Page >

  • A queue in C using structs and dynamic memory allocation (linked list)

    - by Martin Pugh
    I am tasked with making a queue data structure in C, as a linked list. Our lecturer gave us a large amount of code to implement a stack, but we have to adapt it to create a queue. The code our lecturer gave us ends up not compiling and segfaulting at the exact same point as the code I wrote for the queue. I'm very new to structs, malloc and C in general, so there could be something painfully obvious I've overlooked. Here is the code I am using: #include <stdio.h> #include <stdlib.h> struct node{ int data; //contains the actual data struct node *prev; //pointer to previous node (Closer to front) struct node *next; //pointer to next node (Closer to back) }; typedef struct node *Nodepointer; struct queue{ Nodepointer front; Nodepointer back; }; typedef struct queue *Queuepointer; main(){ Queuepointer myqueue; //create a queue called myqueue init(myqueue); //initialise the queue Nodepointer new = (Nodepointer)malloc(sizeof(struct node)); myqueue->front = new; } int init(Queuepointer q){ q = (Queuepointer)malloc(sizeof(struct queue)); q->front = NULL; q->back = NULL; } The idea is that the queue struct 'contains' the first and last nodes in a queue, and when a node is created, myqueue is updated. However, I cannot even get to that part (pop and push are written but omitted for brevity). The code is segfaulting at the line myqueue->front = new; with the following gdb output: Program received signal SIGSEGV, Segmentation fault. 0x08048401 in main () at queue.c:27 27 myqueue->front = new; Any idea what I'm doing wrong?

    Read the article

  • Flex List ItemRenderer with image looses BitmapData when scrolling

    - by Dominik
    Hi i have a mx:List with a DataProvider. This data Provider is a ArrayCollection if FotoItems public class FotoItem extends EventDispatcher { [Bindable] public var data:Bitmap; [Bindable] public var id:int; [Bindable] public var duration:Number; public function FotoItem(data:Bitmap, id:int, duration:Number, target:IEventDispatcher=null) { super(target); this.data = data; this.id = id; this.duration = duration; } } my itemRenderer looks like this: <?xml version="1.0" encoding="utf-8"?> <mx:VBox xmlns:fx="http://ns.adobe.com/mxml/2009" xmlns:s="library://ns.adobe.com/flex/spark" xmlns:mx="library://ns.adobe.com/flex/mx" > <fx:Script> <![CDATA[ import mx.collections.ArrayCollection; ]]> </fx:Script> <s:Label text="index"/> <mx:Image source="{data.data}" maxHeight="100" maxWidth="100"/> <s:Label text="Duration: {data.duration}ms"/> <s:Label text="ID: {data.id}"/> </mx:VBox> Now when i am scrolling then all images that leave the screen disappear :( When i take a look at the arrayCollection every item's BitmapData is null. Why is this the case?

    Read the article

  • CSS Hover on parent list Item only

    - by Daniel O'Connor
    Hey Everyone, So I have some nested lists (only one level deep) and I'm running into trouble with the CSS :hover feature. I only want the hover to apply to the parent class, but I can't figure that one out. Here's my CSS <style type="text/css" media="screen"> .listblock li img { visibility: hidden; } .listblock li:hover img { visibility: visible; } </style> And here is a sample of one of the lists. <ul> <li>One <a href="#"><img src="img/basket.png" height="16" width="16" alt="Buy" class="buy" onClick="pageTracker._trackEvent('Outbound Links', 'Amazon');"/></a></li> <li>Two <a href="#"><img src="img/basket.png" height="16" width="16" class="buy" /></a> <ul> <li>Uno<a href="#"><img src="img/basket.png" height="16" width="16" class="buy" /></a></li> <li>Dos <a href="#"><img src="img/basket.png" height="16" width="16" class="buy" /></a></li> </ul> </li> <li>Three <a href="#"><img src="img/basket.png" height="16" width="16" alt="Buy" class="buy" onClick="pageTracker._trackEvent('Outbound Links', 'Amazon');"/></a></li> </ul> The problem is that the image in the Uno and Dos list items also hovers. :( Help please! Thanks a lot

    Read the article

  • Excel CSV into Nested Dictionary; List Comprehensions

    - by victorhooi
    heya, I have a Excel CSV files with employee records in them. Something like this: mail,first_name,surname,employee_id,manager_id,telephone_number [email protected],john,smith,503422,503423,+65(2)3423-2433 [email protected],george,brown,503097,503098,+65(2)3423-9782 .... I'm using DictReader to put this into a nested dictionary: import csv gd_extract = csv.DictReader(open('filename 20100331 original.csv'), dialect='excel') employees = dict([(row['employee_id'], row) for row in gp_extract]) Is the above the proper way to do it - it does work, but is it the Right Way? Something more efficient? Also, the funny thing is, in IDLE, if I try to print out "employees" at the shell, it seems to cause IDLE to crash (there's approximately 1051 rows). 2. Remove employee_id from inner dict The second issue issue, I'm putting it into a dictionary indexed by employee_id, with the value as a nested dictionary of all the values - however, employee_id is also a key:value inside the nested dictionary, which is a bit redundant? Is there any way to exclude it from the inner dictionary? 3. Manipulate data in comprehension Thirdly, we need do some manipulations to the imported data - for example, all the phone numbers are in the wrong format, so we need to do some regex there. Also, we need to convert manager_id to an actual manager's name, and their email address. Most managers are in the same file, while others are in an external_contractors CSV, which is similar but not quite the same format - I can import that to a separate dict though. Are these two items things that can be done within the single list comprehension, or should I use a for loop? Or does multiple comprehensions work? (sample code would be really awesome here). Or is there a smarter way in Python do it? Cheers, Victor

    Read the article

  • Lazy non-modifiable list

    - by mindas
    I was looking for a decent implementation of a generic lazy non-modifiable list implementation to wrap my search result entries. The unmodifiable part of the task is easy as it can be achieved by Collections.unmodifiableList() so I only need to sort out the the lazy part. Surprisingly, google-collections doesn't have anything to offer; while LazyList from Apache Commons Collections does not support generics. I have found an attempt to build something on top of google-collections but it seems to be incomplete (e.g. does not support size()), outdated (does not compile with 1.0 final) and requiring some external classes, but could be used as a good starting point to build my own class. Is anybody aware of any good implementation of a LazyList? If not, which option do you think is better: write my own implementation, based on google-collections ForwardingList, similar to what Peter Maas did; write my own wrapper around Commons Collections LazyList (the wrapper would only add generics so I don't have to cast everywhere but only in the wrapper itself); just write something on top of java.util.AbstractList; Any other suggestions are welcome.

    Read the article

  • Linked List pop() function

    - by JKid314159
    Consider the following list: [LinkNode * head -- LinkNode * node1 -- LinkNode * node2] I'm creating a stack of FIFO. I Call pop() which I want to pop node1. LinkNode::LinkNode(int numIn) { this->numIn = numIn; next = null; } . . . int LinkNode::pop() { Link * temp = head->next; head = temp->next; int popped = head->nodeNum; delete temp; Return numOut; Question: 1) head should be a pointer or a LinkNode *? 2) Link * temp is created on the call stack and when pop finishes doesn't temp delete automatically? 3) My major confusion is on what is the value of temp-next? Does this point to node1.next which equals node2? Appreciate your help? My reference is C++ for Java Programmers by Weiss.

    Read the article

  • sorting names in a linked list

    - by sil3nt
    Hi there, I'm trying to sort names into alphabetical order inside a linked list but am getting a run time error. what have I done wrong here? #include <iostream> #include <string> using namespace std; struct node{ string name; node *next; }; node *A; void addnode(node *&listpointer,string newname){ node *temp; temp = new node; if (listpointer == NULL){ temp->name = newname; temp->next = listpointer; listpointer = temp; }else{ node *add; add = new node; while (true){ if(listpointer->name > newname){ add->name = newname; add->next = listpointer->next; break; } listpointer = listpointer->next; } } } int main(){ A = NULL; string name1 = "bob"; string name2 = "tod"; string name3 = "thomas"; string name4 = "kate"; string name5 = "alex"; string name6 = "jimmy"; addnode(A,name1); addnode(A,name2); addnode(A,name3); addnode(A,name4); addnode(A,name5); addnode(A,name6); while(true){ if(A == NULL){break;} cout<< "name is: " << A->name << endl; A = A->next; } return 0; }

    Read the article

  • SharePoint: Filtering a List that has Folders

    - by Gary McGill
    I have a SharePoint document library that has a folder structure used for organizing the documents (but also for controlling access, via permissions on the folders). The documents in the library are updated every month, and we store every month's version of the document in the same folder; there's a "month" column used for filtering that will contain values like Jan 09, Feb 09, etc. It looks like this: Title Month ----- ----- SubFolder 1 SubFolder 2 [] Interesting Facts Jan 09 [] Interesting Facts Feb 09 [] Interesting Facts Mar 09 [] Fascinating Numbers Jan 09 [] Fascinating Numbers Feb 09 ... Now, because users will generally be most interested in the 'current' month, I'd like them to be able to apply a filter, and select (say) Mar 09. However, if they do this using the built-in filtering, it also filters out the folders, and they can no longer navigate the folder hierarchy. This is no good - I want them to be able to move between folders with the filter intact, so that they don't need to keep switching it off and on again. I figured I might be able to use a custom view (selecting where type=folder or month=[month]), and to an extent that does work. However, I can only get it to work for a fixed month, whereas I need the user to be able to select the month - perhaps via a drop-down control on the page (and I don't want to create 60 views for 5 years' worth of months, nor do I want to have to create a new view every month). I thought it might be possible to create a view in code (rather than via the UI), but I've not been able to figure out how to get a dynamic value (a user-specific setting) into the CAML query. Any pointers gratefully appreciated! And by the way, I am aware of the dogma that folders are bad, and that everything should just be a list. However, having considered the alternatives, I still favour using folders - if I can solve this problem. Thanks in advance.

    Read the article

  • How to take a Serialized String from the DB and output a UL list with Coldfusion

    - by nobosh
    Given a string from the database as follows: ul[0][id]=main1&ul[0][children][0][id]=child2&ul[0][children][0][class]=&ul[1][id]=main3&ul[2][id]=main4&ul[3][id]=main5 Where what's after the equal sign is an ID, how can I take this string on the backend and build out a list as following from front-end output? <UL id="container"> <LI id="main1"> Lorem ipsum dolor sit amet, consectetur <UL> <LI id="child2"> In hac habitasse platea dictumst. <UL></UL> </LI> </UL> </LI> <LI id="main3"> In hac habitasse platea dictumst. <UL></UL> </LI> <LI id="main4"> In hac habitasse platea dictumst. <UL></UL> </LI> <LI id="main5"> In hac habitasse platea dictumst. <UL></UL> </LI> </UL> Thanks

    Read the article

  • Finding the index of a list item in jQuery

    - by Tim Piele
    I have an unordered list of eight items. On page load the first five <li> have default thumbnail images in them and the 6th one has a 1px by 1px placeholder image with the ID of $('#last'). When a user inserts a new image it replaces the 'src' of $('#last') with their new image. It's not the most efficient way but it works. <ul> <li><img src="img1.png" /></li> <li><img src="img2.png" /></li> <li><img src="img3.png" /></li> <li><img src="img4.png" /></li> <li><img src="img5.png" /></li> <li><img src="1px.png" id="last"/></li> <li></li> <li></li> </ul> When the user adds a new image the ID of $('#last') is removed and I use each() to find the next empty <li> and insert the 1px by 1px image in it, with an ID of $('#last') so it is ready for the next image upload. At this point I need to get the index() of the <li> that now has the 1px by 1px image in it, whose ID is $('#last'), so that I can store the index in the session, so when a user comes back to the page the $('#last') ID is still set and ready to accept another image. How do I get the index of the <li> with that image in it, since it was set after page load? Is there a way to use delegate() or on() to get it? i.e. how do I get the index of an element that was set after page load?

    Read the article

  • Weird margin in a list

    - by kevin
    I'm trying to style a menu, but I keep running into this weird margin that's appearing in both FF4 and IE. This is the only affecting css: #header ul { display: inline; } #header ul li { list-style-type: none; background: #000; display: inline; margin: 0; padding: 0; } #header ul li a { color: #fff; text-decoration: none; display: inline-block; width: 100px; text-align: center; } And this is the HTML: <div id="header"> <ul id="toplinks"> <li><a href="#">Hello</a></li> <li><a href="#">Herp</a></li> <li><a href="#">Derp</a></li> </ul> </div> As you can see, there's a margin appearing on both sides, and I'd like it so it would have no margin (or maybe 1px would be okay)...

    Read the article

  • pointer to a pointer in a linked list

    - by user1596497
    I'm trying to set a linked list head through pointer to a pointer. I can see inside the function that the address of the head pointer is changing but as i return to the main progran it becomes NULL again. can someone tell me what I'm doing wrong ?? #include <stdio.h> #include <stdlib.h> typedef void(*fun_t)(int); typedef struct timer_t { int time; fun_t func; struct timer_t *next; }TIMER_T; void add_timer(int sec, fun_t func, TIMER_T *head); void run_timers(TIMER_T **head); void timer_func(int); int main(void) { TIMER_T *head = NULL; int time = 1; fun_t func = timer_func; while (time < 1000) { printf("\nCalling add_timer(time=%d, func=0x%x, head=0x%x)\n", time, func, &head); add_timer(time, func, head); time *= 2; } run_timers(&head); return 0; } void add_timer(int sec, fun_t func, TIMER_T *head) { TIMER_T ** ppScan=&head; TIMER_T *new_timer = NULL; new_timer = (TIMER_T*)malloc(sizeof(TIMER_T)); new_timer->time = sec; new_timer->func = func; new_timer->next = NULL; while((*ppScan != NULL) && (((**ppScan).time)<sec)) ppScan = &(*ppScan)->next; new_timer->next = *ppScan; *ppScan = new_timer; }

    Read the article

  • Should xml represent a set or a list?

    - by sixtyfootersdude
    I always think of xml like a set data structure. Ie: <class> <person>john</person> <person>sarah</person> </class> Is equivalent to: <class> <person>sarah</person> <person>john</person> </class> Question One: Are these two things logicly equivalant? Are you allowed to make things like this in xml? <methodCall> <param>happy</param> <param>sad</param> </methodCall> Or do you need to do it like this: <methodCall> <param arg="1">happy</param> <param arg="2">sad</param> </methodCall> Question Two: Are these two things logically equivalent? Question Three: Is xml usually treated like a set or a list?

    Read the article

  • adding elements in to the doubly linked list

    - by user329820
    Hi this is my code for main class and doubly linked class and node class but when I run the program ,in the concole will show this"datastructureproject.DoublyLinkedList@19ee1ac" instead of the random numbers .please help me thanks! main class: public class Main { public static int getRandomNumber(double min, double max) { Random random = new Random(); return (int) (random.nextDouble() * (max - min) + min); } public static void main(String[] args) { int j; int i = 0; i = getRandomNumber(10, 10000); DoublyLinkedList listOne = new DoublyLinkedList(); for (j = 0; j <= i / 2; j++) { listOne.add(getRandomNumber(10, 10000)); } System.out.println(listOne); } } doubly linked list class: public class DoublyLinkedList { private Node head ; private Node tail; private long size = 0; public DoublyLinkedList() { head= new Node(0, null, null); tail = new Node(0, head, null); } public void add(int i){ head.setValue(i); Node newNode = new Node(); head.setNext(newNode); newNode.setPrev(head); newNode = head; } } and the node class is like the class that you have seen before (Node prev,Node next,int value)

    Read the article

  • Linked List Inserting strings in alphabetical order

    - by user69514
    I have a linked list where each node contains a string and a count. my insert method needs to inset a new node in alphabetical order based on the string. if there is a node with the same string, then i increment the count. the problem is that my method is not inserting in alphabetical order public Node findIsertionPoint(Node head, Node node){ if( head == null) return null; Node curr = head; while( curr != null){ if( curr.getValue().compareTo(node.getValue()) == 0) return curr; else if( curr.getNext() == null || curr.getNext().getValue().compareTo(node.getValue()) > 0) return curr; else curr = curr.getNext(); } return null; } public void insert(Node node){ Node newNode = node; Node insertPoint = this.findIsertionPoint(this.head, node); if( insertPoint == null) this.head = newNode; else{ if( insertPoint.getValue().compareTo(node.getValue()) == 0) insertPoint.getItem().incrementCount(); else{ newNode.setNext(insertPoint.getNext()); insertPoint.setNext(newNode); } } count++; }

    Read the article

  • Deleting first and last element of a linked list in C

    - by LuckySlevin
    struct person { int age; char name[100]; struct person *next; }; void delfirst(struct person **p)// For deleting the beginning { struct person *tmp,*m; m = (*p); tmp = (*p)->next; free(m); return; } void delend(struct person **p)// For deleting the end { struct person *tmp,*m; tmp=*p; while(tmp->next!=NULL) { tmp=tmp->next; } m->next=tmp; free(tmp); m->next = NULL; return; } I'm looking for two seperate functions to delete the first and last elements of a linked list. Here is what i tried. What do you suggest? Especially deleting first is so problematic for me.

    Read the article

  • Cleaner method for list comprehension clean-up

    - by Dan McGrath
    This relates to my previous question: Converting from nested lists to a delimited string I have an external service that sends data to us in a delimited string format. It is lists of items, up to 3 levels deep. Level 1 is delimited by '|'. Level 2 is delimited by ';' and level 3 is delimited by ','. Each level or element can have 0 or more items. An simplified example is: a,b;c,d|e||f,g|h;; We have a function that converts this to nested lists which is how it is manipulated in Python. def dyn_to_lists(dyn): return [[[c for c in b.split(',')] for b in a.split(';')] for a in dyn.split('|')] For the example above, this function results in the following: >>> dyn = "a,b;c,d|e||f,g|h;;" >>> print (dyn_to_lists(dyn)) [[['a', 'b'], ['c', 'd']], [['e']], [['']], [['f', 'g']], [['h'], [''], ['']]] For lists, at any level, with only one item, we want it as a scalar rather than a 1 item list. For lists that are empty, we want them as just an empty string. I've came up with this function, which does work: def dyn_to_min_lists(dyn): def compress(x): return "" if len(x) == 0 else x if len(x) != 1 else x[0] return compress([compress([compress([item for item in mv.split(',')]) for mv in attr.split(';')]) for attr in dyn.split('|')]) Using this function and using the example above, it returns: [[['a', 'b'], ['c', 'd']], 'e', '', ['f', 'g'], ['h', '', '']] Being new to Python, I'm not confident this is the best way to do it. Are there any cleaner ways to handle this? This will potentially have large amounts of data passing through it, are there any more efficient/scalable ways to achieve this?

    Read the article

  • Python - creating a list with 2 characteristics bug

    - by user2733911
    The goal is to create a list of 99 elements. All elements must be 1s or 0s. The first element must be a 1. There must be 7 1s in total. import random import math import time # constants determined through testing generation_constant = 0.96 def generate_candidate(): coin_vector = [] coin_vector.append(1) for i in range(0, 99): random_value = random.random() if (random_value > generation_constant): coin_vector.append(1) else: coin_vector.append(0) return coin_vector def validate_candidate(vector): vector_sum = sum(vector) sum_test = False if (vector_sum == 7): sum_test = True first_slot = vector[0] first_test = False if (first_slot == 1): first_test = True return (sum_test and first_test) vector1 = generate_candidate() while (validate_candidate(vector1) == False): vector1 = generate_candidate() print vector1, sum(vector1), validate_candidate(vector1) Most of the time, the output is correct, saying something like [1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0] 7 True but sometimes, the output is: [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] 2 False What exactly am I doing wrong?

    Read the article

  • Monitor flashes black when starting video files, opening folders with video files

    - by Bob
    My entire monitor flashes black for a second or so when starting any video file. It does the same thing when closing the file. It also does this when opening a folder that has video files and a thumbnail view, or when I do anything that presumably accesses the video stream inside a video file. It happens in VLC and Windows Media Player, though it occurs to me certain video editors I have like avidemux and virtualdub don't have that issue when opening video files... It also does not happen when watching flash-based videos on web sites. It doesn't seem to happen when Quicktime. I went through and uninstalled any extraneous programs a week or so ago and didn't see any change. I also updated the graphics card driver. What can I do to troubleshoot/fix this?

    Read the article

  • Recovering files that do not appear in the Recycle Bin, but are in the $Recycle.bin folder on external drive

    - by Zach Morgan
    Problem: I have an NTFS external drive with a $Recycle.bin folder on the root (E:/$Recycle.bin/) that has about 70gb worth of data. For whatever reason, the folder is no longer a hidden system file and no Windows machine I have used the drive on will show the files in the actual Recycle Bin. What I Want To Do: I want to atleast view the recycle bin files from this external, and all of the help articles I have read just talk about deleting the folder all together. I plan on reformating the drive, but first I need to see if there are any important deleted files. What Didn't Work: Recuva - didn't see any of my files Resetting the external's Recycle Bin via command prompt and moving the old $Recycle.bin files into the new external $Recycle.bin folder (I didn't read this anywhere, just made it up on my own)

    Read the article

  • Replacing files in a folder structure with files from an unsorted folder

    - by Andrew
    I have over 50,000 PDFs organized into folders in a file called PDFACT. I needed to compress these files so I ran them through Adobe to batch compress them and this worked—except Adobe could only output the files without their folder structure. So basically I have 50,000 PDFs set up in a folder with hundreds of subfolders, and everything was organized. I ended up with one folder with 50,000 compressed PDFs in it, just in alphabetical order. Somehow I need to replace all the orginal PDFs with their compressed copies. Let me give an example: In the folder PDFACT we have the following file: C:\PDFACT\BIG DINNER\BILL\NEWESTBILL.PDF … and in the output folder that Adobe created we have just: C:\COMPRESSED_PDF_FOLDER\NEWESTBILL.PDF This copy is smaller then the one in PDFACT and has the same name but it is just lumped in with every other PDF. The folder structure and subfolders are gone. Is there any way to replace all the larger uncompressed PDFS inside the orginal folder structure with their now compressed counterparts?

    Read the article

  • print a linear linked list into a table

    - by user1796970
    I am attempting to print some values i have stored into a LLL into a readable table. The data i have stored is the following : DEBBIE STARR F 3 W 1000.00 JOAN JACOBUS F 9 W 925.00 DAVID RENN M 3 H 4.75 ALBERT CAHANA M 3 H 18.75 DOUGLAS SHEER M 5 W 250.00 SHARI BUCHMAN F 9 W 325.00 SARA JONES F 1 H 7.50 RICKY MOFSEN M 6 H 12.50 JEAN BRENNAN F 6 H 5.40 JAMIE MICHAELS F 8 W 150.00 i have stored each firstname, lastname, gender, tenure, payrate, and salary into their own List. And would like to be able to print them out in the same format that they are viewed on the text file i read them in from. i have messed around with a few methods that allow me to traverse and print the Lists, but i end up with ugly output. . . here is my code for the storage of the text file and the format i would like to print out: public class Payroll { private LineWriter lw; private ObjectList output; ListNode input; private ObjectList firstname, lastname, gender, tenure, rate, salary; public Payroll(LineWriter lw) { this.lw = lw; this.firstname = new ObjectList(); this.lastname = new ObjectList(); this.gender = new ObjectList(); this.tenure = new ObjectList(); this.rate = new ObjectList(); this.salary = new ObjectList(); this.output = new ObjectList(); this.input = new ListNode(); } public void readfile() { File file = new File("payfile.txt"); try{ Scanner scanner = new Scanner(file); while(scanner.hasNextLine()) { String line = scanner.nextLine(); Scanner lineScanner = new Scanner(line); lineScanner.useDelimiter("\\s+"); while(lineScanner.hasNext()) { firstname.insert1(lineScanner.next()); lastname.insert1(lineScanner.next()); gender.insert1(lineScanner.next()); tenure.insert1(lineScanner.next()); rate.insert1(lineScanner.next()); salary.insert1(lineScanner.next()); } } }catch(FileNotFoundException e) {e.printStackTrace();} } public void printer(LineWriter lw) { String msg = " FirstName " + " LastName " + " Gender " + " Tenure " + " Pay Rate " + " Salary "; output.insert1(msg); System.out.println(output.getFirst()); System.out.println(" " + firstname.getFirst() + " " + lastname.getFirst() + "\t" + gender.getFirst() + "\t" + tenure.getFirst() + "\t" + rate.getFirst() + "\t" + salary.getFirst()); } }

    Read the article

< Previous Page | 32 33 34 35 36 37 38 39 40 41 42 43  | Next Page >