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  • Tokenizing numbers for a parser

    - by René Nyffenegger
    I am writing my first parser and have a few questions conerning the tokenizer. Basically, my tokenizer exposes a nextToken() function that is supposed to return the next token. These tokens are distinguished by a token-type. I think it would make sense to have the following token-types: SYMBOL (such as <, :=, ( and the like REMARK (or a comment) NUMBER IDENT (such as the name of a function or a variable) STRING (Something enclosed between "....") Now, do you think this makes sense? Also, I am struggling with the NUMBER token-type. Do you think it makes more sense to further split it up into a NUMBER and a FLOAT token-type? Without a FLOAT token-type, I'd receive NUMBER (eg 402), a SYMBOL (.) followed by another NUMBER (eg 203) if I were about to parse a float. Finally, what do you think makes more sense for the tokenizer to return when it encounters a -909? Should it return the SYMBOL - first, followed by the NUMBER 909 or should it return a NUMBER -909 right away?

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  • What does this number mean?

    - by FinalDestiny
    I have one number that has something related to the currentdate : 634101448539930000 634101448627430000 (this information was took 9 seconds later than the first one) I have many codes like this and I need to know what those number means. It's something related to the current time, because the new information has always a bigger number than the older ones. Please if anybody could help me, thanks

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  • Prime Numbers in C?

    - by Ali Azam Rana
    FIRST PROGRAM #include<stdio.h> void main() { int n,c; printf("enter a numb"); scanf("%i",n); for(c=2;c<=n;c++) { if(n%c==0) break; } if(c==n) printf("\nprime\n"); else printf("\nnot prime\n"); getchar(); } SECOND PROGRAM #include <stdio.h> int main() { printf("Enter a Number\n"); int in,loop,rem,chk; scanf("%d",&in); for (loop = 1; loop <=in; loop++) { rem = in % loop; if(rem == 0) chk = chk +1; } if (chk == 2) printf("\nPRIME NUM ENTERED\n"); else printf("\nNUM ENTERED NOT PRIME\n"); getchar(); } the 2nd program works other was the one my friend wrote the program looks fine but on checking it by stepping into we found that the if condition in first program is coming true under every input so whats the logical error here please help me found out......

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  • Optimizing this "Boundarize" method for Numerics in Ruby

    - by mstksg
    I'm extending Numerics with a method I call "Boundarize" for lack of better name; I'm sure there are actually real names for this. But its basic purpose is to reset a given point to be within a boundary. That is, "wrapping" a point around the boundary; if the area is betweeon 0 and 100, if the point goes to -1, -1.boundarize(0,100) = 99 (going one too far to the negative "wraps" the point around to one from the max). 102.boundarize(0,100) = 2 It's a very simple function to implement; when the number is below the minimum, simply add (max-min) until it's in the boundary. If the number is above the maximum, simply subtract (max-min) until it's in the boundary. One thing I also need to account for is that, there are cases where I don't want to include the minimum in the range, and cases where I don't want to include the maximum in the range. This is specified as an argument. However, I fear that my current implementation is horribly, terribly, grossly inefficient. And because every time something moves on the screen, it has to re-run this, this is one of the bottlenecks of my application. Anyone have any ideas? module Boundarizer def boundarize min=0,max=1,allow_min=true,allow_max=false raise "Improper boundaries #{min}/#{max}" if min >= max new_num = self if allow_min while new_num < min new_num += (max-min) end else while new_num <= min new_num += (max-min) end end if allow_max while new_num > max new_num -= (max-min) end else while new_num >= max new_num -= (max-min) end end return new_num end end class Numeric include Boundarizer end

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  • numbers of Parameters in Webservice function

    - by sachin
    hi, I am trying to call webservice from python client using SUDS. as per SUDS support, (https://fedorahosted.org/suds/wiki/Documentation#OVERVIEW) I created a webservice with Config: SOAP Binding 1.1 Document/Literal though Document/literal style takes only one parameter, SUDS Document (https://fedorahosted.org/suds/wiki/Documentation#BASICUSAGE) shows: Suds - version: 0.3.3 build: (beta) R397-20081121 Service (WebServiceTestBeanService) tns="http://test.server.enterprise.rhq.org/" Prefixes (1): ns0 = "http://test.server.enterprise.rhq.org/" Ports (1): (Soap) Methods: addPerson(Person person, ) echo(xs:string arg0, ) getList(xs:string str, xs:int length, ) getPercentBodyFat(xs:string name, xs:int height, xs:int weight) getPersonByName(Name name, ) hello() testExceptions() testListArg(xs:string[] list, ) testVoid() updatePerson(AnotherPerson person, name name, ) Types (23): Person Name Phone AnotherPerson Which has functions with several or no parameters. can we have such methods(Exposed) in a webservice with Document/Literal Style? if so how?

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  • Explanation needed for sum of prime below n numbers

    - by Bala Krishnan
    Today I solved a problem given in Project Euler its problem no 10 and it took 7 hrs for my python program to show the result. But in that forum itself a person named lassevk posted solution for this and it took only 4 sec. And its not possible for me to post this question in that forum because its not discussion forum. So, think about this if you want to mark this question as non-constructive. marked = [0] * 2000000 value = 3 s = 2 while value < 2000000: if marked[value] == 0: s += value i = value while i < 2000000: marked[i] = 1 i += value value += 2 print s If any one understand this code please explain it simple as possible. Link to the Problem 10 question.

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  • Sum of even fibonacci numbers

    - by user300484
    This is a Project Euler problem. If you don't want to see candidate solutions don't look here. Hello you all! im developping an application that will find the sum of all even terms of the fibonacci sequence. The last term of this sequence is 4,000,000 . There is something wrong in my code but I cannot find the problem since it makes sense to me. Can you please help me? using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication1 { class Program { static void Main(string[] args) { long[] arr = new long [1000000] ; long i= 2; arr[i-2]=1; arr[i-1]=2; long n= arr[i]; long s=0; for (i=2 ; n <= 4000000; i++) { arr[i] = arr[(i - 1)] + arr[(i - 2)]; } for (long f = 0; f <= arr.Length - 1; f++) { if (arr[f] % 2 == 0) s += arr[f]; } Console.Write(s); Console.Read(); } } }

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  • Invalid quantifer error using Regular Expression (UK Telephone numbers)

    - by Matt
    HI all, as per the title I am getting the error "Invalid Quantifier" Trying to match this reg ex:- ^(((+44\s?\d{4}|(?0\d{4})?)\s?\d{3}\s?\d{3})|((+44\s?\d{3}|(?0\d{3})?)\s?\d{3}\s?\d{4})|((+44\s?\d{2}|(?0\d{2})?)\s?\d{4}\s?\d{4}))(\s?#(\d{4}|\d{3}))?$ Infact ive tried a few UK telephone number regex's from the regex librairy but im getting the same error all the time. If anyone can help id be much appreciative! Just for info, im using the jQuery form validation librairy, and here is my code: - $(document).ready(function(){ //Set Fields to be validated $("#EventForm").validate(); $( "#StartDate" ).datepicker(); $( "#EndDate" ).datepicker(); //Add Postcode Regex Method to Validator Function $.validator.addMethod( "postcode", function(value, element, regexp) { var check = false; var re = new RegExp(regexp); return this.optional(element) || re.test(value); }, "Please enter a valid postcode." ); //Add UK Telephone number Regex Method to Validator Function $.validator.addMethod( "telephone", function(value, element, regexp) { var check = false; var re = new RegExp(regexp); return this.optional(element) || re.test(value); }, "Please enter a valid UK telephone number in the format - 01856 666666." ); //Add Postcode Regular Expression Rule to Postcode Field $("#EventPostcode").rules("add", { postcode: "^([a-zA-Z]){1}([0-9][0-9]|[0-9]|[a-zA-Z][0-9][a-zA-Z]|[a-zA-Z][0-9][0-9]|[a-zA-Z][0-9]){1}([ ])([0-9][a-zA-z][a-zA-z]){1}$"}); $("#EventTelephoneNo").rules("add", { telephone: "^(((\+44\s?\d{4}|\(?0\d{4}\)?)\s?\d{3}\s?\d{3})|((\+44\s?\d{3}|\(?0\d{3}\)?)\s?\d{3}\s?\d{4})|((\+44\s?\d{2}|\(?0\d{2}\)?)\s?\d{4}\s?\d{4}))(\s?\#(\d{4}|\d{3}))?$"}); }); Many thanks

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  • C/C++ line number

    - by Betamoo
    In the sake of debugging purposes, can I get the line number in C/C++ compilers? (standard way or specific ways for certain compilers) e.g if(!Logical) printf("Not logical value at line number %d \n",LineNumber); // How to get LineNumber without writing it by my hand?(dynamic compilation) Thanks

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  • List of divisors of an integer n (Haskell)

    - by Code-Guru
    I currently have the following function to get the divisors of an integer: -- All divisors of a number divisors :: Integer -> [Integer] divisors 1 = [1] divisors n = firstHalf ++ secondHalf where firstHalf = filter (divides n) (candidates n) secondHalf = filter (\d -> n `div` d /= d) (map (n `div`) (reverse firstHalf)) candidates n = takeWhile (\d -> d * d <= n) [1..n] I ended up adding the filter to secondHalf because a divisor was repeating when n is a square of a prime number. This seems like a very inefficient way to solve this problem. So I have two questions: How do I measure if this really is a bottle neck in my algorithm? And if it is, how do I go about finding a better way to avoid repetitions when n is a square of a prime?

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  • Simple regular expression for decimal numbers?

    - by finch
    I know this may be the simplest question ever asked on Stack Overflow, but what is the regular expression for a decimal with a precision of 2? Valid examples: 123.12 2 56754 92929292929292.12 0.21 3.1 Invalid examples: 12.1232 2.23332 e666.76 Sorry for the lame question, but for the life of me I haven't been able to find anyone that can help! The decimal place may be option, and that integers may also be included.

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  • Optimizing list comprehension to find pairs of co-prime numbers

    - by user3685422
    Given A,B print the number of pairs (a,b) such that GCD(a,b)=1 and 1<=a<=A and 1<=b<=B. Here is my answer: return len([(x,y) for x in range(1,A+1) for y in range(1,B+1) if gcd(x,y) == 1]) My answer works fine for small ranges but takes enough time if the range is increased. such as 1 <= A <= 10^5 1 <= B <= 10^5 is there a better way to write this or can this be optimized?

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  • Looking for industry numbers on source code management

    - by Dave Duchene
    I'm looking for statistics on SCM usage, in particular I'm trying to find out what percentage of their time developers spend on SCM-related tasks. The more detailed the breakdown, the better. Online and offline resources would both be tremendously useful to me. Can anyone point me towards some industry studies? Preferably recent ones?

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  • Determining the order of a list of numbers (possibly without sorting)

    - by Victor Liu
    I have an array of unique integers (e.g. val[i]), in arbitrary order, and I would like to populate another array (ord[i]) with the the sorted indexes of the integers. In other words, val[ord[i]] is in sorted order for increasing i. Right now, I just fill in ord with 0, ..., N, then sort it based on the value array, but I am wondering if we can be more efficient about it since ord is not populated to begin with. This is more of a question out of curiousity; I don't really care about the extra overhead from having to prepopulate a list and then sort it (it's small, I use insertion sort). This may be a silly question with an obvious answer, but I couldn't find anything online.

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  • PHP Fatal error on line number that doesn't exist

    - by alexantd
    Fatal error: Allowed memory size of 134217728 bytes exhausted (tried to allocate 523800 bytes) in /Library/WebServer/Documents/XMLDataStore.class.php on line 981 The curious thing about this error is not the memory leak, which would be easy enough to troubleshoot. Rather, it is the fact that XMLDataStore.class.php is only 850 lines long, which I have verified in multiple text editors. This is with the PHP 5.3 bundled with Snow Leopard. I'm not using an opcode cache. Here is my php.ini: allow_url_fopen = Off error_reporting = -1 display_errors = 1 display_startup_errors = 1 date.timezone = 'America/Los_Angeles' output_buffering = Off realpath_cache_size = 0k XMLDataStore.class.php has recently been refactored and it used to be longer than 981 lines. It's almost as if PHP has cached a 2-week-old version and is reading that. I'm positive that the current version at /Library/WebServer/Documents/XMLDataStore.class.php is only 850 lines long, though.

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  • Math Mod Containing Numbers

    - by TheDarkIn1978
    i would like to write a simple line of code, without resorting to if statements, that would evaluate whether a number is within a certain range. i can evaluate from 0 - Max by using the modulus. 30 % 90 = 30 //great however, if the test number is greater than the maximum, using modulus will simply start it at 0 for the remaining, where as i would like to limit it to the maximum if it's past the maximum 94 % 90 = 4 //i would like answer to be 90 it becomes even more complicated, to me anyway, if i introduce a minimum for the range. for example: minimum = 10 maximum = 90 therefore, any number i evaluate should be either within range, or the minimum value if it's below range and the maximum value if it's above range -76 should be 10 2 should be 10 30 should be 30 89 should be 89 98 should be 90 23553 should be 90 is it possible to evaluate this with one line of code without using if statements?

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  • Javascript: find first n prime numbers

    - by bard
    function primeNumbers() { array = []; for (var i = 2; array.length < 100; i++) { for (var count = 2; count < i; count++) { var divisorFound = false; if (i % count === 0) { divisorFound = true; break; } } if (divisorFound == false) {array.push[i];} } return array; } When I run this code, it seems to get stuck in an infinite loop and doesn't return anything... why?

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  • Serial numbers generation without user data

    - by Sphynx
    This is a followup to this question. The accepted answer is generally sufficient, but requires user to supply personal information (e.g. name) for generating the key. I'm wondering if it's possible to generate different keys based on a common seed, in a way that program would be able to validate if those keys belong to particular product, but without making this process obvious to the end user. I mean it could be a hash of product ID plus some random sequence of characters, but that would allow user to guess potential new keys. There should be some sort of algorithm difficult to guess.

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  • ms access negative page numbers

    - by FrustratedWithFormsDesigner
    I have an access report that generates 36505 pages (un filtered, and about half of each page is taken up by group headers and page headers) , though the footer at the bottom of the report page says "36505 of -29031". This looks like an overflow problem maybe, though I'm confused how it got the current page number of the last page OK, but failed to get total page count. Has anyone dealt with this before?

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  • Give a number to return the approximated value of an Enum?

    - by ElektroStudios
    I have this enumeration: Enum Lame_Bitrate kbps_8 = 8 kbps_16 = 16 kbps_24 = 24 kbps_32 = 32 kbps_40 = 40 kbps_48 = 48 kbps_56 = 56 kbps_64 = 64 kbps_80 = 80 kbps_96 = 96 kbps_112 = 112 kbps_128 = 128 kbps_144 = 144 kbps_160 = 160 kbps_192 = 192 kbps_224 = 224 kbps_256 = 256 kbps_320 = 320 End Enum And I would like to return the approximated value of the Enum given a number. For example, if I have the number 190 then I expect to find the more approximated value in the Enum to return the 192 (kbps_192 value of the Enum), if I have the number 196 then again I expect to return the value 192 (not return the next value 224 because is less approximated). Something like this: Private Sub Test() Dim wma_file As String = "C:\windows media audio file.wma" Dim wma_file_Bitrate As Integer = 172 Dim mp3_bitrate_approximated As Integer mp3_bitrate_approximated = Return_Approximated_Value_Of_Enum(wma_file_Bitrate) End Sub private function Return_Approximated_Value_Of_Enum(byval value as integer) as integer return... enum.find(value).approximated... end function Exist any framework method to find the more approximated number given other number in a Enum? I hope you can understand my question, thank you. PS: I prefer a solution using LINQ extensions if can be.

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