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  • Display attribute from XML using PHP

    - by user560411
    Hello. I need to display the id attribute of CD from the following XML file. I display correctly everything except the id. Any help would be appreciate. display code <?php $doc = new DOMDocument(); $doc->load( 'insert.xml' ); $CATEGORIES = $doc->getElementsByTagName( "CD" ); foreach( $CATEGORIES as $CD ) { $TITLES = $CD->getElementsByTagName( "TITLE" ); $TITLE = $TITLES->item(0)->nodeValue; $BANDS= $CD->getElementsByTagName( "BAND" ); $BAND= $BANDS->item(0)->nodeValue; $YEARS = $CD->getElementsByTagName( "YEAR" ); $YEAR = $YEARS->item(0)->nodeValue; echo "<b>$TITLE - $BAND - $YEAR\n</b><br>"; } ?> XML <?xml version="1.0" encoding="utf-8"?> <MY_CD> <CATEGORIES> <CD id="3231"> <TITLE>NEVER MIND THE BOLLOCKS</TITLE> <BAND>SEX PISTOLS</BAND> <YEAR>1977</YEAR> </CD> <CD id="2453"> <TITLE>NEVERMIND</TITLE> <BAND>NIRVANA</BAND> <YEAR>1991</YEAR> </CD> </CATEGORIES> </MY_CD>

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  • JavaScript regular expression literal persists between function calls

    - by Charles Anderson
    I have this piece of code: function func1(text) { var pattern = /([\s\S]*?)(\<\?(?:attrib |if |else-if |else|end-if|search |for |end-for)[\s\S]*?\?\>)/g; var result; while (result = pattern.exec(text)) { if (some condition) { throw new Error('failed'); } ... } } This works, unless the throw statement is executed. In that case, the next time I call the function, the exec() call starts where it left off, even though I am supplying it with a new value of 'text'. I can fix it by writing var pattern = new RegExp('.....'); instead, but I don't understand why the first version is failing. How is the regular expression persisting between function calls? (This is happening in the latest versions of Firefox and Chrome.) Edit Complete test case: <!DOCTYPE HTML> <html> <head> <meta http-equiv="Content-type" content="text/html;charset=UTF-8"> <title>Test Page</title> <style type='text/css'> body { font-family: sans-serif; } #log p { margin: 0; padding: 0; } </style> <script type='text/javascript'> function func1(text, count) { var pattern = /(one|two|three|four|five|six|seven|eight)/g; log("func1"); var result; while (result = pattern.exec(text)) { log("result[0] = " + result[0] + ", pattern.index = " + pattern.index); if (--count <= 0) { throw "Error"; } } } function go() { try { func1("one two three four five six seven eight", 3); } catch (e) { } try { func1("one two three four five six seven eight", 2); } catch (e) { } try { func1("one two three four five six seven eight", 99); } catch (e) { } try { func1("one two three four five six seven eight", 2); } catch (e) { } } function log(msg) { var log = document.getElementById('log'); var p = document.createElement('p'); p.innerHTML = msg; log.appendChild(p); } </script> </head> <body><div> <input type='button' id='btnGo' value='Go' onclick='go();'> <hr> <div id='log'></div> </div></body> </html> The regular expression continues with 'four' as of the second call on FF and Chrome, not on IE7 or Opera.

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  • DELETE and EDIT is not working in my python program

    - by user2968025
    This is a simple python program that ADD, DELETE, EDIT and VIEW student records. The problem is, DELETE and EDIT is not working. I dont know why but when I tried removing one '?' in the DELETE dunction, I had the error that says there are only 8 columns and it needs 10. But originally, there are only 9 columns. I don't know where it got the other one to make it 10. Please help.. :( import sys import sqlite3 import tkinter import tkinter as tk from tkinter import * from tkinter.ttk import * def newRecord(): studentnum="" name="" age="" birthday="" address="" email="" course="" year="" section="" con=sqlite3.connect("Students.db") cur=con.cursor() cur.execute("CREATE TABLE IF NOT EXISTS student(studentnum TEXT, name TEXT, age TEXT, birthday TEXT, address TEXT, email TEXT, course TEXT, year TEXT, section TEXT)") def save(): studentnum=en1.get() name=en2.get() age=en3.get() birthday=en4.get() address=en5.get() email=en6.get() course=en7.get() year=en8.get() section=en9.get() student=(studentnum,name,age,birthday,address,email,course,year,section) cur.execute("INSERT INTO student(studentnum,name,age,birthday,address,email,course,year,section) VALUES(?,?,?,?,?,?,?,?,?)",student) con.commit() win=tkinter.Tk();win.title("Students") lbl=tkinter.Label(win,background="#000",foreground="#ddd",width=30,text="Add Record") lbl.pack() lbl1=tkinter.Label(win,width=30,text="Student Number : ") lbl1.pack() en1=tkinter.Entry(win,width=30) en1.pack() lbl2=tkinter.Label(win,width=30,text="Name : ") lbl2.pack() en2=tkinter.Entry(win,width=30) en2.pack() lbl3=tkinter.Label(win,width=30,text="Age : ") lbl3.pack() en3=tkinter.Entry(win,width=30) en3.pack() lbl4=tkinter.Label(win,width=30,text="Birthday : ") lbl4.pack() en4=tkinter.Entry(win,width=30) en4.pack() lbl5=tkinter.Label(win,width=30,text="Address : ") lbl5.pack() en5=tkinter.Entry(win,width=30) en5.pack() lbl6=tkinter.Label(win,width=30,text="Email : ") lbl6.pack() en6=tkinter.Entry(win,width=30) en6.pack() lbl7=tkinter.Label(win,width=30,text="Course : ") lbl7.pack() en7=tkinter.Entry(win,width=30) en7.pack() lbl8=tkinter.Label(win,width=30,text="Year : ") lbl8.pack() en8=tkinter.Entry(win,width=30) en8.pack() lbl9=tkinter.Label(win,width=30,text="Section : ") lbl9.pack() en9=tkinter.Entry(win,width=30) en9.pack() btn1=tkinter.Button(win,background="#000",foreground="#ddd",width=30,text="Save Student",command=save) btn1.pack() def editRecord(): studentnum1="" def edit(): studentnum1=en10.get() studentnum="" name="" age="" birthday="" address="" email="" course="" year="" section="" con=sqlite3.connect("Students.db") cur=con.cursor() row=cur.fetchone() cur.execute("DELETE FROM student WHERE name = '%s'" % studentnum1) con.commit() def save(): studentnum=en1.get() name=en2.get() age=en3.get() birthday=en4.get() address=en5.get() email=en6.get() course=en7.get() year=en8.get() section=en8.get() student=(studentnum,name,age,email,birthday,address,email,course,year,section) cur.execute("INSERT INTO student(studentnum,name,age,email,birthday,address,email,course,year,section) VALUES(?,?,?,?,?,?,?,?,?)",student) con.commit() win=tkinter.Tk();win.title("Students") lbl=tkinter.Label(win,background="#000",foreground="#ddd",width=30,text="Edit Reocrd :"+'\t'+studentnum1) lbl.pack() lbl1=tkinter.Label(win,width=30,text="Student Number : ") lbl1.pack() en1=tkinter.Entry(win,width=30) en1.pack() lbl2=tkinter.Label(win,width=30,text="Name : ") lbl2.pack() en2=tkinter.Entry(win,width=30) en2.pack() lbl3=tkinter.Label(win,width=30,text="Age : ") lbl3.pack() en3=tkinter.Entry(win,width=30) en3.pack() lbl4=tkinter.Label(win,width=30,text="Birthday : ") lbl4.pack() en4=tkinter.Entry(win,width=30) en4.pack() lbl5=tkinter.Label(win,width=30,text="Address : ") lbl5.pack() en5=tkinter.Entry(win,width=30) en5.pack() lbl6=tkinter.Label(win,width=30,text="Email : ") lbl6.pack() en6=tkinter.Entry(win,width=30) en6.pack() lbl7=tkinter.Label(win,width=30,text="Course : ") lbl7.pack() en7=tkinter.Entry(win,width=30) en7.pack() lbl8=tkinter.Label(win,width=30,text="Year : ") lbl8.pack() en8=tkinter.Entry(win,width=30) en8.pack() lbl9=tkinter.Label(win,width=30,text="Section : ") lbl9.pack() en9=tkinter.Entry(win,width=30) en9.pack() btn1=tkinter.Button(win,background="#000",foreground="#ddd",width=30,text="Save Record",command=save) btn1.pack() win=tkinter.Tk();win.title("Edit Student") lbl=tkinter.Label(win,background="#000",foreground="#ddd",width=30,text="Edit Record") lbl.pack() lbl10=tkinter.Label(win,width=30,text="Student Number : ") lbl10.pack() en10=tkinter.Entry(win) en10.pack() btn2=tkinter.Button(win,background="#000",foreground="#ddd",width=30,text="Edit",command=edit) btn2.pack() def deleteRecord(): studentnum1="" win=tkinter.Tk();win.title("Delete Student Record") lbl=tkinter.Label(win,background="#000",foreground="#ddd",width=30,text="Delete Record") lbl.pack() lbl10=tkinter.Label(win,text="Student Number") lbl10.pack() en10=tkinter.Entry(win) en10.pack() def delete(): studentnum1=en10.get() con=sqlite3.connect("Students.db") cur=con.cursor() row=cur.fetchone() cur.execute("DELETE FROM student WHERE name = '%s';" % studentnum1) con.commit() win=tkinter.Tk();win.title("Record Deleted") lbl=tkinter.Label(win,background="#000",foreground="#ddd",width=30,text="Record Deleted :") lbl.pack() lbl=tkinter.Label(win,width=30,text=studentnum1) lbl.pack() btn=tkinter.Button(win,background="#000",foreground="#ddd",width=30,text="Ok",command=win.destroy) btn.pack() btn2=tkinter.Button(win,background="#000",foreground="#ddd",width=30,text="Delete",command=delete) btn2.pack() def viewRecord(): con=sqlite3.connect("Students.db") cur=con.cursor() win=tkinter.Tk();win.title("View Student Record"); row=cur.fetchall() lbl1=tkinter.Label(win,background="#000",foreground="#ddd",width=300,text="\n\tStudent Number"+"\t\tName"+"\t\tAge"+"\t\tBirthday"+"\t\tAddress"+"\t\tEmail"+"\t\tCourse"+"\t\tYear"+"\t\nSection") lbl1.pack() for row in cur.execute("SELECT * FROM student"): lbl2=tkinter.Label(win,width=300,text= row[0] + '\t\t' + row[1] + '\t' + row[2] + '\t\t' + row[3] + '\t\t' + row[4] + '\t\t' + row[5] + '\t\t' + row[6] + '\t\t' + row[7] + '\t\t' + row[8] + '\n') lbl2.pack() con.close() but1=tkinter.Button(win,background="#000",foreground="#fff", width=150,text="Close",command=win.destroy) but1.pack() root=tkinter.Tk();root.title("Student Records") menubar=tkinter.Menu(root) manage=tkinter.Menu(menubar,tearoff=0) manage.add_command(label='New Record',command=newRecord) manage.add_command(label='Edit Record',command=editRecord) manage.add_command(label='Delete Record',command=deleteRecord) menubar.add_cascade(label='Manage',menu=manage) view=tkinter.Menu(menubar,tearoff=0) view.add_command(label='View Record',command=viewRecord) menubar.add_cascade(label='View',menu=view) root.config(menu=menubar) lbl=tkinter.Label(root,background="#000",foreground="#ddd",font=("Verdana",15),width=30,text="Student Records") lbl.pack() lbl1=tkinter.Label(root,text="\nSubmitted by :") lbl1.pack() lbl2=tkinter.Label(root,text="Chavez, Vissia Nicole P") lbl2.pack() lbl3=tkinter.Label(root,text="BSIT 4-4") lbl3.pack()

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  • UNIX script to convert queries

    - by Harish
    I need a UNIX shell script to convert my queries from Java compatible to Oracle compatible format. ie. I have all the java compatible queries: java: SELECT a, b, c, d, e, f,g "+// "from test where year(timestamp)=year(today) and month(timestamp)=month(today) " +// "and day(timestamp)=2 and h='" + "W" + "'" Oracle SELECT a, b, c,d,e,f,g from test where year(timestamp)=year(today) and month(timestamp)=month(today) and day(timestamp)=2 and h='W' Is it possible using sed or awk?

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  • Date arithmetic using integer values

    - by Dave Jarvis
    Problem String concatenation is slowing down a query: date(extract(YEAR FROM m.taken)||'-1-1') d1, date(extract(YEAR FROM m.taken)||'-1-31') d2 This is realized in code as part of a string, which follows (where the p_ variables are integers): date(extract(YEAR FROM m.taken)||''-'||p_month1||'-'||p_day1||''') d1, date(extract(YEAR FROM m.taken)||''-'||p_month2||'-'||p_day2||''') d2 This part of the query runs in 3.2 seconds with the dates, and 1.5 seconds without, leading me to believe there is ample room for improvement. Question What is a better way to create the date (presumably without concatenation)? Many thanks!

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  • SQL View Creation

    - by george9170
    I have two tables Table FOO FooUniqueID| Year| Name| Worth| --------------------------- 1 2008 Bob 23.00 2 2009 Bob 40200 Table Bar BarUniqueID | Name | Value ----------------------- 1aBc Year 2009 I would like to create a view. That will select everything from FOO where the Year is equal select value from Bar where name = year without using a sub query. thank you

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  • Problem with duplicates in a SQL Join

    - by Chris Ballance
    I have the following result set from a join of three tables, an articles table, a products table, an articles to products mapping table. I would like to have the results with duplicates removed similar to a select distinct on content id. Current result set: [ContendId] [Title] [productId] 1 article one 2 1 article one 3 1 article one 9 4 article four 1 4 article four 10 4 article four 14 5 article five 1 6 article six 8 6 article six 10 6 article six 11 6 article six 13 7 article seven 14 Desired result set: [ContendId] [Title] [productId] 1 article one * 4 article four * 5 article five * 6 article six * 7 article seven * Here is condensed example of the relevant SQL: IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'tempdb.dbo.products') AND type = (N'U')) drop table tempdb.dbo.products go CREATE TABLE tempdb.dbo.products ( productid int, productname varchar(255) ) go IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'articles') AND type = (N'U')) drop table tempdb.dbo.articles go create table tempdb.dbo.articles ( contentid int, title varchar(255) ) IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'articles') AND type = (N'U')) drop table tempdb.dbo.articles go create table tempdb.dbo.articles ( contentid int, title varchar(255) ) IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'articleproducts') AND type = (N'U')) drop table tempdb.dbo.articleproducts go create table tempdb.dbo.articleproducts ( contentid int, productid int ) insert into tempdb.dbo.products values (1,'product one'), (2,'product two'), (3,'product three'), (4,'product four'), (5,'product five'), (6,'product six'), (7,'product seven'), (8,'product eigth'), (9,'product nine'), (10,'product ten'), (11,'product eleven'), (12,'product twelve'), (13,'product thirteen'), (14,'product fourteen') insert into tempdb.dbo.articles VALUES (1,'article one'), (2, 'article two'), (3, 'article three'), (4, 'article four'), (5, 'article five'), (6, 'article six'), (7, 'article seven'), (8, 'article eight'), (9, 'article nine'), (10, 'article ten') INSERT INTO tempdb.dbo.articleproducts VALUES (1,2), (1,3), (1,9), (4,1), (4,10), (4,14), (5,1), (6,8), (6,10), (6,11), (6,13), (7,14) GO select DISTINCT(a.contentid), a.title, p.productid from articles a JOIN articleproducts ap ON a.contentid = ap.contentid JOIN products p ON a.contentid = ap.contentid AND p.productid = ap.productid ORDER BY a.contentid

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  • Execution Plan Optimization when where clause is removed then added back

    - by nmushov
    I have a stored procedure that uses a table valued function which executes in 9 seconds. If I alter the table valued function and remove the where clause, the stored procedure executes in 3 seconds. If I add the where clause back, the query still executes in 3 seconds. I took a look at the execution plans and it appears that after I remove the where clause, the execution plan includes parallelism and the scan count for 2 of my tables drops for 50000 and 65000 down to 5 and 3. After I add the where clause back, the optimized execution plan still runs unless I run DBCC FREEPROCCACHE. Questions 1. Why would SQL Server start using the optimized execution plan for both queries only when I first remove the where clause? Is there a way to force SQL Server to use this execution plan? Also, this is a paramaterized all-in-one query that uses the (Parameter is null or Parameter) in the where clause, which I believe is bad for performance. RETURNS TABLE AS RETURN ( SELECT TOP (@PageNumber * @PageSize) CASE WHEN @SortOrder = 'Expensive' THEN ROW_NUMBER() OVER (ORDER BY SellingPrice DESC) WHEN @SortOrder = 'Inexpensive' THEN ROW_NUMBER() OVER (ORDER BY SellingPrice ASC) WHEN @SortOrder = 'LowMiles' THEN ROW_NUMBER() OVER (ORDER BY Mileage ASC) WHEN @SortOrder = 'HighMiles' THEN ROW_NUMBER() OVER (ORDER BY Mileage DESC) WHEN @SortOrder = 'Closest' THEN ROW_NUMBER() OVER (ORDER BY P1.Distance ASC) WHEN @SortOrder = 'Newest' THEN ROW_NUMBER() OVER (ORDER BY [Year] DESC) WHEN @SortOrder = 'Oldest' THEN ROW_NUMBER() OVER (ORDER BY [Year] ASC) ELSE ROW_NUMBER() OVER (ORDER BY InventoryID ASC) END as rn, P1.InventoryID, P1.SellingPrice, P1.Distance, P1.Mileage, Count(*) OVER () RESULT_COUNT, dimCarStatus.[year] FROM (SELECT InventoryID, SellingPrice, Zip.Distance, Mileage, ColorKey, CarStatusKey, CarKey FROM facInventory JOIN @ZipCodes Zip ON Zip.DealerKey = facInventory.DealerKey) as P1 JOIN dimColor ON dimColor.ColorKey = P1.ColorKey JOIN dimCarStatus ON dimCarStatus.CarStatusKey = P1.CarStatusKey JOIN dimCar ON dimCar.CarKey = P1.CarKey WHERE (@ExteriorColor is NULL OR dimColor.ExteriorColor like @ExteriorColor) AND (@InteriorColor is NULL OR dimColor.InteriorColor like @InteriorColor) AND (@Condition is NULL OR dimCarStatus.Condition like @Condition) AND (@Year is NULL OR dimCarStatus.[Year] like @Year) AND (@Certified is NULL OR dimCarStatus.Certified like @Certified) AND (@Make is NULL OR dimCar.Make like @Make) AND (@ModelCategory is NULL OR dimCar.ModelCategory like @ModelCategory) AND (@Model is NULL OR dimCar.Model like @Model) AND (@Trim is NULL OR dimCar.Trim like @Trim) AND (@BodyType is NULL OR dimCar.BodyType like @BodyType) AND (@VehicleTypeCode is NULL OR dimCar.VehicleTypeCode like @VehicleTypeCode) AND (@MinPrice is NULL OR P1.SellingPrice >= @MinPrice) AND (@MaxPrice is NULL OR P1.SellingPrice < @MaxPrice) AND (@Mileage is NULL OR P1.Mileage < @Mileage) ORDER BY CASE WHEN @SortOrder = 'Expensive' THEN -SellingPrice WHEN @SortOrder = 'Inexpensive' THEN SellingPrice WHEN @SortOrder = 'LowMiles' THEN Mileage WHEN @SortOrder = 'HighMiles' THEN -Mileage WHEN @SortOrder = 'Closest' THEN P1.Distance WHEN @SortOrder = 'Newest' THEN -[YEAR] WHEN @SortOrder = 'Oldest' THEN [YEAR] ELSE InventoryID END )

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  • xml dom node children

    - by matt
    Need some help I've got lots of code and i want to make it shorter i know there's a way but I can't remember it this is code example: <?xml version="1.0" encoding="ISO-8859-1"?> <bookstore> <book category="cooking"> <title lang="en">Everyday Italian</title> <author>Giada De Laurentiis</author> <year>2005</year> <price>30.00</price> </book> <book category="children"> <title lang="en">Harry Potter</title> <author>J K. Rowling</author> <year>2005</year> <price>29.99</price> </book> <book category="web"> <title lang="en">XQuery Kick Start</title> <author>James McGovern</author> <author>Per Bothner</author> <author>Kurt Cagle</author> <author>James Linn</author> <author>Vaidyanathan Nagarajan</author> <year>2003</year> <price>49.99</price> </book> <book category="web" cover="paperback"> <title lang="en">Learning XML</title> <author>Erik T. Ray</author> <year>2003</year> <price>39.95</price> </book> </bookstore As you can see the different nodes, children now is there a way to make this code smaller so I don't have to keep writing the nodes and children

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  • Sort/Group XML data with PHP?

    - by Volmar
    I'm trying to make a page using data from the discogs.com (XML)-API. i've been parsing it with simpleXML and it's working pretty well but there is some things i'm not sure how to do. Here is part of the XML: <releases> <release id="1468764" status="Accepted" type="Main"> <title>Versions</title> <format>12", EP</format> <label>Not On Label</label> <year>1999</year> </release> <release id="72246" status="Accepted" type="Main"> <title>The M.O.F Blend</title> <format>LP</format> <label>Blenda Records</label> <year>2002</year> </release> <release id="890064" status="Accepted" type="Main"> <title>The M.O.F Blend</title> <format>CD</format> <label>Blenda Records</label> <year>2002</year> </release> <release id="1563561" status="Accepted" type="TrackAppearance"> <title>Ännu En Gång Vol. 3</title> <trackinfo>Backtrack</trackinfo> <format>Cass, Comp, Mix</format> <label>Hemmalaget</label> <year>2001</year> </release> </releases> What i want to achieve is something similair to how discogs presents the releases: http://www.discogs.com/artist/Mics+Of+Fury where diferent versions of the same release are sorted together. (see. The M.O.F Blend in my link) This is done on discogs with having a master release that features the other releases. unfortunately this information isn't present in the API data, so i want to do the same thing by grouping the <release>-nodes with the same <title>-tags, or add a flag to the <releases> that don't have a unique <title>? any good ideas on the best way of doing this? i also like to know if it's possible to count the <release>-nodes (child of releases) that have the same type-attribute? like in this example count the releases with the type "Main"? maybe it's better to do this things with XMLReader or XPath?

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  • Can someone explain/annotate this Ruby snippet with comments?

    - by Ronnie
    Could someone please add comments to this code? Or, alternatively, what would be the pseudocode equivalent of this Ruby code? It seems simple enough but I just don't know enough Ruby to convert this to PHP. data = Hash.new({}) mysql_results.each { |r| data[r['year']][r['week']] = r['count'] } (year_low..year_high).each do |year| (1..52).each do |week| puts "#{year} #{week} #{data[year][week]}" end end Any help whatsoever would be really appreciated. Thanks!

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  • MySQL error problem

    - by comma
    I keep getting the error listed below but it only says line 1 what does this mean and how do I fix it? Here is the error I keep getting? You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1 here is the code. if (isset($_POST['info_submitted'])) { $user_id = '5'; $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON learned_skills.id = users_skills.skill_id WHERE user_id='$user_id'"); $skill = $_POST['skill']; $experience = $_POST['experience']; $year = $_POST['year']; if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = mysqli_query($mysqli,"INSERT INTO learned_skills (skill, experience, year) VALUES ('" . $skill . "', '" . $experience . "', '" . $year . "')"); } if (!mysqli_query($mysqli, $query1)) { print mysqli_error($mysqli); return; } $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT id FROM learned_skills WHERE id='" . $skill . "' AND experience='" . $experience . "' AND year='" . $year . "'"); if (!$dbc) { print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc)){ $id = $row["id"]; } } $query2 = "INSERT INTO users_skills (skill_id, user_id, date_created) VALUES ('$id', '$user_id', NOW())"; if (!mysqli_query($mysqli, $query2)) { print mysqli_error($mysqli); return; } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE learned_skills JOIN users_skills ON (users_skills.skill_id = learned_skills.id) SET skill = '$skill', experience = '$experience', year = '$year'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } }

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  • count number of business that belongs to subcategory in doctrine

    - by Ibrahim Azhar Armar
    this is follow up of this question. count number of foreign keys i am using doctrine 1.2 and i want to count the number of business that belongs to subcategory. following are the mysql tables. 1.fi_category +----+-----------------+-----------------+ | id | name | slug | +----+-----------------+-----------------+ 2.fi_subcategory +----+-----------------+-----------------+-------------+ | id | name | slug | category_id | +----+-----------------+-----------------+-------------+ 3.fi_business_subcategory +----+-------------+----------------+ | id | business_id | subcategory_id | +----+-------------+----------------+ i am using this DQL. $q = Doctrine_Query::create() ->select('c.name, c.slug, sc.name, sc.slug') ->from('Model_Category c') ->leftJoin('c.Subcategory sc') ->leftJoin('sc.BusinessSubcategory bsc'); which gives me something like this. Array ( [0] => Array ( [id] => 1 [name] => Entertainment & Lifestyle [slug] => entertainment-lifestyle [Subcategory] => Array ( [0] => Array ( [id] => 1 [name] => Arts and Crafts [slug] => arts-and-crafts ) [1] => Array ( [id] => 2 [name] => Family [slug] => family ) [2] => Array ( [id] => 3 [name] => Fashion [slug] => fashion ) ) ) ) i am looking to fetch the number of business, i.e the returned result should be something like this depending on the business it belongs. Array ( [0] => Array ( [id] => 1 [name] => Entertainment & Lifestyle [slug] => entertainment-lifestyle [Subcategory] => Array ( [0] => Array ( [id] => 1 [name] => Arts and Crafts [slug] => arts-and-crafts [business_count] => 35 ) [1] => Array ( [id] => 2 [name] => Family [slug] => family [business_count] => 10 ) [2] => Array ( [id] => 3 [name] => Fashion [slug] => fashion [business_count] => 27 ) ) ) ) tried various ways using DQL, but nothing seems to work out. any idea how should i go with what i want?

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  • XML Path needed

    - by user3696029
    I have the following XML file: <?xml version="1.0" encoding="UTF-8"?> <bookstore> <book category="COOKING"> <title lang="en">Everyday Italian</title> <author>Giada De Laurentiis</author> <year>2005</year> <price>30.00</price> </book> <book category="CHILDREN"> <title lang="en">Harry Potter</title> <author>J K. Rowling</author> <year>2005</year> <price>29.99</price> </book> <book category="WEB"> <title lang="en">XQuery Kick Start</title> <author>James McGovern</author> <author>Per Bothner</author> <author>Kurt Cagle</author> <author>James Linn</author> <author>Vaidyanathan Nagarajan</author> <year>2003</year> <price>49.99</price> </book> <book category="WEB"> <title lang="en">Learning XML</title> <author>Erik T. Ray</author> <year>2003</year> <price>39.95</price> </book> </bookstore> I need to write a XML path that returns a book published after 2003, category is children and I just need to display the author and title of the book? What is frustrating is that I have everything in the XPATH that wrote except I am missing the author.

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  • NHibernate and MySql Keywords

    - by jalchr
    Why Nibernate HQL can not handle the following query: from Deal D where (D.ApprovalDate + INTERVAL 1 Year) < current_timestamp() < (D.RenewalDate + INTERVAL -1 Year) knowing that INTERVAL and YEAR are keywords in MySQL, so this is kind of mixing Sql within Hql (unless Hql can handle date functions like so and I don't know) . The dialect is MySQLDialect Its perfectly valid to execute this query SELECT '2005-01-01' + INTERVAL 1 Year;

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  • Doubt in stored procedure in asp.net

    - by Surya sasidhar
    hi, i am writing a sotreprocedure displaying month and year it is working but it is not coming in a order descending order can u help me my procedure like below... ALTER procedure [dbo].[audioblog_getarchivedates] as begin select DateName(Month,a.createddate) + ' ' + DateName(Year,a.createddate) as ArchiveDate from audio_blog a group by DateName(Month,a.createddate) + ' ' + DateName(Year,a.createddate) order by DateName(Month,a.createddate) + ' ' + DateName(Year,a.createddate) desc end result will come like this March 2010 January 2010 February 2010 but it is not in a order (desc) can u help me

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  • C++ class is not recognizing string data type

    - by reallythecrash
    I'm working on a program from my C++ textbook, and this this the first time I've really run into trouble. I just can't seem to see what is wrong here. Visual Studio is telling me Error: identifier "string" is undefined. I separated the program into three files. A header file for the class specification, a .cpp file for the class implementation and the main program file. These are the instructions from my book: Write a class named Car that has the following member variables: year. An int that holds the car's model year. make. A string that holds the make of the car. speed. An int that holds the car's current speed. In addition, the class should have the following member functions. Constructor. The constructor should accept the car's year and make as arguments and assign these values to the object's year and make member variables. The constructor should initialize the speed member variable to 0. Accessors. Appropriate accessor functions should be created to allow values to be retrieved from an object's year, make and speed member variables. There are more instructions, but they are not necessary to get this part to work. Here is my source code: // File Car.h -- Car class specification file #ifndef CAR_H #define CAR_H class Car { private: int year; string make; int speed; public: Car(int, string); int getYear(); string getMake(); int getSpeed(); }; #endif // File Car.cpp -- Car class function implementation file #include "Car.h" // Default Constructor Car::Car(int inputYear, string inputMake) { year = inputYear; make = inputMake; speed = 0; } // Accessors int Car::getYear() { return year; } string Car::getMake() { return make; } int Car::getSpeed() { return speed; } // Main program #include <iostream> #include <string> #include "Car.h" using namespace std; int main() { } I haven't written anything in the main program yet, because I can't get the class to compile. I've only linked the header file to the main program. Thanks in advance to all who take the time to investigate this problem for me.

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  • onDateSet does not get called from DatePickerDialog on tablet

    - by cit
    I am using a DatePickerDialog to prompt the user for a date. It works fine in the simulator and on my Samsung Galaxy Nexus, but onDateSet does not get called on my Samsung Galaxy Tab 2. I noticed, that the dialog is bigger and shows a calendar besides the normal spin view. Can that be the problem? Here is some code: import java.util.Calendar; import java.util.Date; import android.app.DatePickerDialog; import android.app.Dialog; import android.content.DialogInterface; import android.content.Intent; import android.os.Bundle; import android.support.v4.app.DialogFragment; import android.widget.DatePicker; import com.cbit.gtbetapp.R; import com.cbit.gtbetapp.gui.racedata.MeetingDataActivity; import com.cbit.gtbetapp.gui.racedata.MeetingListFragment; import com.cbit.gtbetapp.logic.Utility; public class DatePickerFragment extends DialogFragment implements DatePickerDialog.OnDateSetListener { protected Date date = null; @Override public Dialog onCreateDialog(Bundle savedInstanceState) { // Use the current date as the default date in the picker final Calendar c = Utility.getToday(); int year = c.get(Calendar.YEAR); int month = c.get(Calendar.MONTH); int day = c.get(Calendar.DAY_OF_MONTH); date = c.getTime(); // Create a new instance of DatePickerDialog and return it DatePickerDialog dialog = new DatePickerDialog(getActivity(), this, year, month, day) { @Override public void onDateChanged(DatePicker view, int year, int month, int day) { super.onDateChanged(view, year, month, day); setTitle(getString(R.string.date_picker_title)); } }; dialog.setTitle(getString(R.string.date_picker_title)); dialog.setButton(DatePickerDialog.BUTTON_POSITIVE, getString(android.R.string.ok), new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int which) { dialog.cancel(); Intent intent = new Intent(getActivity(), MeetingDataActivity.class); intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP); intent.putExtra(MeetingListFragment.EXTRA_DATE, date.getTime()); startActivity(intent); } }); dialog.setButton(DatePickerDialog.BUTTON_NEGATIVE, getString(R.string.button_cancel), new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int which) { dialog.cancel(); } }); return dialog; } public void onDateSet(DatePicker view, int year, int month, int day) { Calendar c = Calendar.getInstance(); c.clear(); c.set(Calendar.YEAR, year); c.set(Calendar.MONTH, month); c.set(Calendar.DAY_OF_MONTH, day); date = c.getTime(); } } What could cause this? A bug in the tablet? Am I missing something? Can anyone think of a workaround? Thanks a lot!

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  • HTML5 CSS3 layout not working

    - by John.Weland
    I have been asked by a local MMA (Mixed Martial Arts) School to help them develop a website. For the life of me I CANNOT get the layout to work correctly. When I get one section set where it should be another moves out of place! here is a pic of the layout: here The header should be a set height as should the footer the entire site at its widest point should be 1250px with the header/content area/footer and the like being 1240px the black in the picture is a scaling background to expand wider as larger resolution systems are viewing them. The full site should be a minimum-height of 100% but scale virtually as content in the target area deems necessary. My biggest issue currently is that my "sticky" footer doesn't stick once the content has stretched the content target area virtually. the Code is not pretty but here it is: HTML5 <!doctype html> <html> <head> <link rel="stylesheet" href="menu.css" type="text/css" media="screen"> <link rel="stylesheet" href="master.css" type="text/css" media="screen"> <meta charset="utf-8"> <title>Untitled Document</title> </head> <body bottommargin="0" leftmargin="0" rightmargin="0" topmargin="0"> <div id="wrap" class="wrap"><div id="logo" class="logo"><img src="images/comalogo.png" width="100" height="150"></div> <div id="header" class="header">College of Martial Arts</div> <div id="nav" class="nav"> <ul id="menu"><b> <li><a href="#">News</a></li> <li>·</li> <li><a href="#">About Us</a> <ul> <li><a href="#">The Instructors</a></li> <li><a href="#">Our Arts</a></li> </li> </ul> <li>·</li> <li><a href="#">Location</a></li> <li>·</li> <li><a href="#">Gallery</a></li> <li>·</li> <li><a href="#">MMA.tv</a></li> <li>·</li> <li><a href="#">Schedule</a></li> <li>·</li> <li><a href="#">Fight Gear</a></li></b> </div> <div id="social" class="social"> <a href="http://www.facebook.com/pages/Canyon-Lake-College-of-Martial-Arts/189432551104674"><img src="images/soc/facebook.png"></a> <a href="https://twitter.com/#!/CanyonLakeMMA"><img src="images/soc/twitter.png"></a> <a href="https://plus.google.com/108252414577423199314/"><img src="images/soc/google+.png"></a> <a href="http://youtube.com/user/clmmatv"><img src="images/soc/youtube.png"></a></div> <div id="mid" class="mid">test <br>test <br>test <br>test <br>test <br>test <br>test <br>test <br>test <br>test <br>test <br>test <br>test <br>test <br>test <br>test <br>test <br>test <br>test <br>test <br>test <br>test <br>test <br>test <br>test <br></div> <div id="footer" class="footer"> <div id="contact" style="left:0px;">tel: (830) 214-4591<br /> e: [email protected]<br /> add: 1273 FM 2673, Sattler, TX 78133<br /> </div> <div id="affiliates" style="right:0px;">Hwa Rang World Tang soo Do</div> <div id="copyright">Copyright © College of Martial Arts</div> </div> </body> </html> CSS3 -Dropdown Menu- @charset "utf-8"; /* CSS Document */ /* Main */ #menu { width: 100%; margin: 0; padding: 10px 0 0 0; list-style: none; background: #444; background: -moz-linear-gradient(#000, #333); background: -webkit-gradient(linear,left bottom,left top,color-stop(0, #444),color-stop(1, #000)); background: -webkit-linear-gradient(#000, #333); background: -o-linear-gradient(#000, #333); background: -ms-linear-gradient(#000, #333); background: linear-gradient(#000, #333); -moz-border-radius: 5px; border-radius: 5px; -moz-box-shadow: 0 2px 1px #9c9c9c; -webkit-box-shadow: 0 2px 1px #9c9c9c; box-shadow: 0 8px 8px #9c9c9c; /* outline:#000 solid thin; */ } #menu li { left:150px; float: left; padding: 0 0 10px 0; position:relative; color: #FC0; font-size:15px; font-family:'freshman' cursive; line-height:15px; } #menu a { float: left; height: 15px; line-height:15px; padding: 0 10px; color: #FC0; font-size:15px; text-decoration: none; text-shadow: 1 1px 0 #000; text-align:center; } #menu li:hover > a { color: #fafafa; } *html #menu li a:hover /* IE6 */ { color: #fafafa; } #menu li:hover > ul { display: block; } /* Sub-menu */ #menu ul { list-style: none; margin: 0; padding: 0; display: none; position: absolute; top: 25px; left: 0; z-index: 99999; background: #444; background: -moz-linear-gradient(#000, #333); background: -webkit-gradient(linear,left bottom,left top,color-stop(0, #111),color-stop(1, #444)); background: -webkit-linear-gradient(#000, #333); background: -o-linear-gradient(#000, #333); background: -ms-linear-gradient(#000, #333); background: linear-gradient(#000, #333); -moz-border-radius: 5px; border-radius: 5px; /* outline:#000 solid thin; */ } #menu ul li { left:0; -moz-box-shadow: none; -webkit-box-shadow: none; box-shadow: none; } #menu ul a { padding: 10px; height: auto; line-height: 1; display: block; white-space: nowrap; float: none; text-transform: none; } *html #menu ul a /* IE6 */ { height: 10px; width: 200px; } *:first-child+html #menu ul a /* IE7 */ { height: 10px; width: 200px; } /*#menu ul a:hover { background: #000; background: -moz-linear-gradient(#000, #333); background: -webkit-gradient(linear, left top, left bottom, from(#04acec), to(#0186ba)); background: -webkit-linear-gradient(#000, #333); background: -o-linear-gradient(#000, #333); background: -ms-linear-gradient(#000, #333); background: linear-gradient(#000, #333); }*/ /* Clear floated elements */ #menu:after { visibility: hidden; display: block; font-size: 0; content: " "; clear: both; height: 0; } * html #menu { zoom: 1; } /* IE6 */ *:first-child+html #menu { zoom: 1; } /* IE7 */ CSS3 -Master Style Sheet- @charset "utf-8"; /* CSS Document */ a:link {color:#FC0; text-decoration:none;} /* unvisited link */ a:visited {color:#FC0; text-decoration:none;} /* visited link */ a:hover {color:#FFF; text-decoration:none;} /* mouse over link */ a:active {color:#FC0; text-decoration:none;} /* selected link */ ul.a {list-style-type:none;} ul.b {list-style-type:inherit} html { } body { /*background-image:url(images/cagebg.jpg);*/ background-repeat:repeat; background-position:top; } div.wrap { margin: 0 auto; min-height: 100%; position: relative; width: 1250px; } div.logo{ top:25px; left:20px; position:absolute; float:top; height:150px; } /*Freshman FONT is on my computer needs to be uploaded to the webhost and rendered host side like a webfont*/ div.header{ background-color:#999; color:#FC0; margin-left:5px; height:80px; width:1240px; line-height:70px; font-family:'freshman' cursive; font-size:50px; text-shadow:8px 8px #9c9c9c; text-outline:1px 1px #000; text-align:center; background-color:#999; clear: both; } div.social{ height:50px; margin-left:5px; width:1240px; font-family:'freshman' cursive; font-size:50px; text-align:right; color:#000; background-color:#999; line-height:30px; box-sizing: border-box; ms-box-sizing: border-box; webkit-box-sizing: border-box; moz-box-sizing: border-box; padding-right:5px; } div.mid{ position:absolute; min-height:100%; margin-left:5px; width:1240px; font-family:'freshman' cursive; font-size:50px; text-align:center; color:#000; background-color:#999; } /*SIDE left and right should be 40px wide and a minimum height (100% the area from nav-footer) to fill between the NAV and the footer yet stretch as displayed content streatches the page longer (scrollable)*/ div #side.sright{ top:96px; right:0; position:absolute; float:right; height:100%; min-height:100%; width:40px; background-image:url(images/border.png); } /*Container should vary in height in acordance to content displayed*/ div #content.container{ } /*Footer should stick at ABSOLUTE BOTTOM of the page*/ div #footer{ font-family:'freshman' cursive; position:fixed; bottom:0; background-color:#000000; margin-left:5px; width:1240px; color:#FC0; clear: both; /*this clear property forces the .container to understand where the columns end and contain them*/ } /*HTML 5 support - Sets new HTML 5 tags to display:block so browsers know how to render the tags properly.*/ header, section, footer, aside, nav, article, figure { display: block; } Eventually once the layout is correct I have to use PHP to make calls for where data should be displayed from what database. If anyone can help me to fix this layout and clean up the crap code, I'd be much appreciated.. I've spent weeks trying to figure this out.

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  • How to convert number(16,10) to date in oracle

    - by Elad
    Hi, I'm trying to read the borland starteam application oracle database and I noticed that they represent their date as a number(16,10) column I think it is not timestamp or epoc. for instance, I have the number: 37137.4347569444, how can I read it as date? I saw that the database has a stored procedure. CONVERT_DATE: CREATE OR REPLACE procedure STARBASE.convert_date ( number_of_days IN integer , nDate OUT number) is nDateOffset number; CurrentDate date; Month integer; Day integer; year number; success boolean := false; bLeapYear boolean:=false; nDaysInMonths number; nLeapDays integer; fDate number (16,10); rgMonthDays number(5,0); begin select sysdate - number_of_days into CurrentDate from dual; nDateOffset := 693959; select to_number(substr((TO_CHAR (CurrentDate, 'MM-DD-YYYY')) , 1, 2), '99') - 1 into month from dual; select to_number(substr((TO_CHAR (CurrentDate, 'MM-DD-YYYY')) , 4, 2), '99') - 1 into day from dual; select to_number(substr((TO_CHAR (CurrentDate, 'MM-DD-YYYY')) , 7, 4), '9999') into year from dual; if ( mod(year , 4) = 0 ) and ( ( mod(year , 400) = 0) or ( mod(year , 100) < 0 )) then bLeapYear :=true; end if; nLeapDays := 0; if ( bLeapYear = true) and ( Day = 28) and ( Month = 1 ) then nLeapDays := 1; end if; select substr(to_char(last_day(CurrentDate) , 'DD-MM-YYYY') , 1 , 2) into nDaysInMonths from dual; if Month = 0 then rgMonthDays := 0; elsif Month = 1 then rgMonthDays := 31; elsif Month = 2 then rgMonthDays := 59; elsif Month = 3 then rgMonthDays := 90; elsif Month = 4 then rgMonthDays := 120; elsif Month = 5 then rgMonthDays := 151; elsif Month = 6 then rgMonthDays := 181; elsif Month = 7 then rgMonthDays := 212; elsif Month = 8 then rgMonthDays := 243; elsif Month = 9 then rgMonthDays := 273; elsif Month = 10 then rgMonthDays := 304; elsif Month = 11 then rgMonthDays := 334; elsif Month = 12 then rgMonthDays := 365; end if; nDate := Year*365 + Year/4 - Year/100 + Year/400 + rgMonthDays + Day + 1; if( Month < 2 ) and ( bLeapYear = true) then nDate := nDate - 1; end if; nDate := nDate - nDateOffset; exception when others then raise; end convert_date; I don't know how to use it. how can i read it anyway? Please help. thank you

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  • Constructor ambiguous quesiton

    - by Crystal
    I'm trying to create a simple date class, but I get an error on my main file that says, "call of overloaded Date() is ambiguous." I'm not sure why since I thought as long as I had different parameters for my constructor, I was ok. Here is my code: header file: #ifndef DATE_H #define DATE_H using std::string; class Date { public: static const int monthsPerYear = 12; // num of months in a yr Date(int = 1, int = 1, int = 1900); // default constructor Date(); // uses system time to create object void print() const; // print date in month/day/year format ~Date(); // provided to confirm destruction order string getMonth(int month) const; // gets month in text format private: int month; // 1 - 12 int day; // 1 - 31 int year; // any year int checkDay(int) const; }; #endif .cpp file #include <iostream> #include <iomanip> #include <string> #include <ctime> #include "Date.h" using namespace std; Date::Date() { time_t seconds = time(NULL); struct tm* t = localtime(&seconds); month = t->tm_mon; day = t->tm_mday; year = t->tm_year; } Date::Date(int mn, int dy, int yr) { if (mn > 0 && mn <= monthsPerYear) month = mn; else { month = 1; // invalid month set to 1 cout << "Invalid month (" << mn << ") set to 1.\n"; } year = yr; // could validate yr day = checkDay(dy); // validate the day // output Date object to show when its constructor is called cout << "Date object constructor for date "; print(); cout << endl; } void Date::print() const { string str; cout << month << '/' << day << '/' << year << '\n'; // new code for HW2 cout << setfill('0') << setw(3) << day; // prints in ddd cout << " " << year << '\n'; // yyyy format str = getMonth(month); // prints in month (full word), day, year cout << str << " " << day << ", " << year << '\n'; } and my main.cpp #include <iostream> #include "Date.h" using std::cout; int main() { Date date1(4, 30, 1980); date1.print(); cout << '\n'; Date date2; date2.print(); }

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  • Ambiguous constructor call

    - by Crystal
    I'm trying to create a simple date class, but I get an error on my main file that says, "call of overloaded Date() is ambiguous." I'm not sure why since I thought as long as I had different parameters for my constructor, I was ok. Here is my code: header file: #ifndef DATE_H #define DATE_H using std::string; class Date { public: static const int monthsPerYear = 12; // num of months in a yr Date(int = 1, int = 1, int = 1900); // default constructor Date(); // uses system time to create object void print() const; // print date in month/day/year format ~Date(); // provided to confirm destruction order string getMonth(int month) const; // gets month in text format private: int month; // 1 - 12 int day; // 1 - 31 int year; // any year int checkDay(int) const; }; #endif .cpp file #include <iostream> #include <iomanip> #include <string> #include <ctime> #include "Date.h" using namespace std; Date::Date() { time_t seconds = time(NULL); struct tm* t = localtime(&seconds); month = t->tm_mon; day = t->tm_mday; year = t->tm_year; } Date::Date(int mn, int dy, int yr) { if (mn > 0 && mn <= monthsPerYear) month = mn; else { month = 1; // invalid month set to 1 cout << "Invalid month (" << mn << ") set to 1.\n"; } year = yr; // could validate yr day = checkDay(dy); // validate the day // output Date object to show when its constructor is called cout << "Date object constructor for date "; print(); cout << endl; } void Date::print() const { string str; cout << month << '/' << day << '/' << year << '\n'; // new code for HW2 cout << setfill('0') << setw(3) << day; // prints in ddd cout << " " << year << '\n'; // yyyy format str = getMonth(month); // prints in month (full word), day, year cout << str << " " << day << ", " << year << '\n'; } and my main.cpp #include <iostream> #include "Date.h" using std::cout; int main() { Date date1(4, 30, 1980); date1.print(); cout << '\n'; Date date2; date2.print(); }

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  • MBA versus MSIS

    - by user794684
    I am considering going back to school for my masters and I've been looking at several avenues I can take. I've been considering either an MBA or an MSIS degree. Overall I know that an MBA is going to give me a solid skill set that can help me become an executive. However they seem to be a dime a dozen these days and the University I can get into is good, but it's not exactly in the top 100 anything. My undergrad MINOR was in Business Information Systems. I'm rusty as hell, considering I haven't touched it, but an MSIS would be more in the direction of my past academic experience and seems to touch both on business management and IT. Question... With an MSIS will I just be a middleman? Will I really be an important person with a real skill set or will I merely be someone who isn't quite cut out to be a manager and who is clueless about the tech side? Is an MSIS degree going to give me a real chance to move up the pay scale quickly or am I better off learning programing, networking through another BS degree? What will give me more upward mobility career wise? An MBA or an MSIS?

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