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  • How to handle a player's level and its consequent privileges?

    - by Songo
    I'm building a game similar to Mafia Wars where a player can do tasks for his gang and gain experience and thus advancing his level. The game is built using PHP and a Mysql database. In the game I want to limit the resources allowed to player based on his level. For example: ________| (Max gold) | (Max army size) | (Max moves) | ... Level 1 | 1000 | 100 | 10 | ... Level 2 | 1500 | 200 | 20 | ... Level 3 | 3000 | 300 | 25 | ... . . . In addition certain features of the game won't be allowed until a certain level is reached such as players under Level 10 can't trade in the game market, players under Level 20 can't create alliances,...etc. The way I have modeled it is by implementing a very loooong ACL (Access Control List) with about 100 entries (an entry for each level). However, I think there may be a simpler approach to this seeing that this feature have been implemented in many games before.

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  • (GUIDE) How to install and configure Mariadb on Ubuntu 12.10+

    - by Myh Yazid
    First of all open terminal and type this sudo apt-get install python-software-properties I recommend you to use MariaDB version 10.0.4 Alpha because when im installed it i've got no errors compare with 5.5 version. 2: Put this commands in terminal sudo apt-get install software-properties-common sudo apt-key adv --recv-keys --keyserver hkp://keyserver.ubuntu.com:80 0xcbcb082a1bb943db sudo add-apt-repository 'deb http://download.nus.edu.sg/mirror/mariadb/repo/10.0/ubuntu quantal main' If you're using other version please change the "quantal" to your ubuntu version codename eg : 13.10 saucy 13.04 raring 12.10 quantal (im using this version) 12.04 precise` 3: Type in this commands sudo apt-get update sudo apt-get install mariadb-server 4: after finished installed mariadb you need to run this sudo mysql_install_db sudo /usr/bin/mysql_secure_installation If have problem consider look at the end of this post for solution 5: You're done!! Problems solving In step 3 if you get problem, like unmet dependencies, Go to /etc/apt/preferences.d then create new file called "mariadb" Then,Consider to put the below code in the mariadb file that you just created Package: * Pin: origin <mirror-domain> Pin-Priority: 1000 In step 4 you may get 2 errors first occur when you run sudo mysql_install_db Solution : open another terminal and do this killall mysqld 2.second eror may occur when you running sudo /usr/bin/mysql_secure_installationcommand Solution : try doing this cd /etc/init.d and try run ./mysqld start if ./mysqld doesnt exists use ./mysql start as in my case That's All Thank you for reading. I wrote this based on my experience installing this.Any errors you get community here can help you if i cant..tq .

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  • Building Queries Systematically

    - by Jeremy Smyth
    The SQL language is a bit like a toolkit for data. It consists of lots of little fiddly bits of syntax that, taken together, allow you to build complex edifices and return powerful results. For the uninitiated, the many tools can be quite confusing, and it's sometimes difficult to decide how to go about the process of building non-trivial queries, that is, queries that are more than a simple SELECT a, b FROM c; A System for Building Queries When you're building queries, you could use a system like the following:  Decide which fields contain the values you want to use in our output, and how you wish to alias those fields Values you want to see in your output Values you want to use in calculations . For example, to calculate margin on a product, you could calculate price - cost and give it the alias margin. Values you want to filter with. For example, you might only want to see products that weigh more than 2Kg or that are blue. The weight or colour columns could contain that information. Values you want to order by. For example you might want the most expensive products first, and the least last. You could use the price column in descending order to achieve that. Assuming the fields you've picked in point 1 are in multiple tables, find the connections between those tables Look for relationships between tables and identify the columns that implement those relationships. For example, The Orders table could have a CustomerID field referencing the same column in the Customers table. Sometimes the problem doesn't use relationships but rests on a different field; sometimes the query is looking for a coincidence of fact rather than a foreign key constraint. For example you might have sales representatives who live in the same state as a customer; this information is normally not used in relationships, but if your query is for organizing events where sales representatives meet customers, it's useful in that query. In such a case you would record the names of columns at either end of such a connection. Sometimes relationships require a bridge, a junction table that wasn't identified in point 1 above but is needed to connect tables you need; these are used in "many-to-many relationships". In these cases you need to record the columns in each table that connect to similar columns in other tables. Construct a join or series of joins using the fields and tables identified in point 2 above. This becomes your FROM clause. Filter using some of the fields in point 1 above. This becomes your WHERE clause. Construct an ORDER BY clause using values from point 1 above that are relevant to the desired order of the output rows. Project the result using the remainder of the fields in point 1 above. This becomes your SELECT clause. A Worked Example   Let's say you want to query the world database to find a list of countries (with their capitals) and the change in GNP, using the difference between the GNP and GNPOld columns, and that you only want to see results for countries with a population greater than 100,000,000. Using the system described above, we could do the following:  The Country.Name and City.Name columns contain the name of the country and city respectively.  The change in GNP comes from the calculation GNP - GNPOld. Both those columns are in the Country table. This calculation is also used to order the output, in descending order To see only countries with a population greater than 100,000,000, you need the Population field of the Country table. There is also a Population field in the City table, so you'll need to specify the table name to disambiguate. You can also represent a number like 100 million as 100e6 instead of 100000000 to make it easier to read. Because the fields come from the Country and City tables, you'll need to join them. There are two relationships between these tables: Each city is hosted within a country, and the city's CountryCode column identifies that country. Also, each country has a capital city, whose ID is contained within the country's Capital column. This latter relationship is the one to use, so the relevant columns and the condition that uses them is represented by the following FROM clause:  FROM Country JOIN City ON Country.Capital = City.ID The statement should only return countries with a population greater than 100,000,000. Country.Population is the relevant column, so the WHERE clause becomes:  WHERE Country.Population > 100e6  To sort the result set in reverse order of difference in GNP, you could use either the calculation, or the position in the output (it's the third column): ORDER BY GNP - GNPOld or ORDER BY 3 Finally, project the columns you wish to see by constructing the SELECT clause: SELECT Country.Name AS Country, City.Name AS Capital,        GNP - GNPOld AS `Difference in GNP`  The whole statement ends up looking like this:  mysql> SELECT Country.Name AS Country, City.Name AS Capital, -> GNP - GNPOld AS `Difference in GNP` -> FROM Country JOIN City ON Country.Capital = City.ID -> WHERE Country.Population > 100e6 -> ORDER BY 3 DESC; +--------------------+------------+-------------------+ | Country            | Capital    | Difference in GNP | +--------------------+------------+-------------------+ | United States | Washington | 399800.00 | | China | Peking | 64549.00 | | India | New Delhi | 16542.00 | | Nigeria | Abuja | 7084.00 | | Pakistan | Islamabad | 2740.00 | | Bangladesh | Dhaka | 886.00 | | Brazil | Brasília | -27369.00 | | Indonesia | Jakarta | -130020.00 | | Russian Federation | Moscow | -166381.00 | | Japan | Tokyo | -405596.00 | +--------------------+------------+-------------------+ 10 rows in set (0.00 sec) Queries with Aggregates and GROUP BY While this system might work well for many queries, it doesn't cater for situations where you have complex summaries and aggregation. For aggregation, you'd start with choosing which columns to view in the output, but this time you'd construct them as aggregate expressions. For example, you could look at the average population, or the count of distinct regions.You could also perform more complex aggregations, such as the average of GNP per head of population calculated as AVG(GNP/Population). Having chosen the values to appear in the output, you must choose how to aggregate those values. A useful way to think about this is that every aggregate query is of the form X, Y per Z. The SELECT clause contains the expressions for X and Y, as already described, and Z becomes your GROUP BY clause. Ordinarily you would also include Z in the query so you see how you are grouping, so the output becomes Z, X, Y per Z.  As an example, consider the following, which shows a count of  countries and the average population per continent:  mysql> SELECT Continent, COUNT(Name), AVG(Population)     -> FROM Country     -> GROUP BY Continent; +---------------+-------------+-----------------+ | Continent     | COUNT(Name) | AVG(Population) | +---------------+-------------+-----------------+ | Asia          |          51 |   72647562.7451 | | Europe        |          46 |   15871186.9565 | | North America |          37 |   13053864.8649 | | Africa        |          58 |   13525431.0345 | | Oceania       |          28 |    1085755.3571 | | Antarctica    |           5 |          0.0000 | | South America |          14 |   24698571.4286 | +---------------+-------------+-----------------+ 7 rows in set (0.00 sec) In this case, X is the number of countries, Y is the average population, and Z is the continent. Of course, you could have more fields in the SELECT clause, and  more fields in the GROUP BY clause as you require. You would also normally alias columns to make the output more suited to your requirements. More Complex Queries  Queries can get considerably more interesting than this. You could also add joins and other expressions to your aggregate query, as in the earlier part of this post. You could have more complex conditions in the WHERE clause. Similarly, you could use queries such as these in subqueries of yet more complex super-queries. Each technique becomes another tool in your toolbox, until before you know it you're writing queries across 15 tables that take two pages to write out. But that's for another day...

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  • PHP not working with hosting

    - by Richard
    I have been playing with a php CMS site for someone that I am ready to deploy but am running into a couple problems that I assume to be hosting related. I have been developing and playing with it localy and deploying to a hosting environment friendly towards this specific CMS (joomla). I have recently been trying to deploy to a client's hosting and have been running in to some trouble. Any help would be greatly appreciated. I have been in contact with the clients hosting and have had them set up a mysql DB for me and enable php. Simple php was working but joomla was not able to create the config files it needed to run on this hosting. Therefore I havnt been able to successfully deploy my work. While playing around with some simple php pages I have started getting http 500 errors and now cant seem to get anywhere. This is a smaller hosting company that seems willing to work with me but I dont really know what i need to ask from them to get me working. My questions to you webmaster geniuses would be as follows: Given the situation I have described, is there anything specifically i should do to get my joomla/php site running on this hosting? What specifically should I ask my current hosting providers to do to help me get working? Thanks

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  • Defining work days and work time

    - by user2553268
    I'm working on development of SMS parking software, and I'm stuck at one point for a month... I need to implement periods of payment (or work time, of a work day, if you will). Here's the problem: For an example, traffic wardens work from Monday to Saturday. From Monday to Friday, the work times are from 07:00 to 21:00, and on Saturday, the work time is from 07:00 to 14:00. The project request was, that the customer can pay parking by SMS unlimited, which I did, but didn't implement this logic. I started with making a table for this periods of payment, it consists of: dayofweek (INT, for use with mysql function DAYOFWEEK, to tell me which day in week is the current date), work_start and work_stop (DATETIME, for defining starting and ending the work day), but I'm unsure if I should use DATETIME, beacuse of the date, or should I use only TIME. The idea is this: If you send an SMS, at 20:50, Monday, it should be valid until 07:50, Tuesday (it's payed by the hour). Extending the time of payment, regarding the work time in week. Currently, it works with extending time by the hour without this rule. Really would use some help, or some ideas, I'm stuck with this for quite some time...

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  • Dedicated Servers: Is one better then two for LAMP pseudo HA setup? [closed]

    - by bikedorkseattle
    Possible Duplicate: How to find web hosting that meets my requirements? I know there are zillions of commentary about hosting out there, but I haven't read much about this. Our current well known host is having too many problems, the hardware we are on it subpar, and I'm ready to leave. A day of downtime can cost as much as our monthly hosting bill. A month of bad performance is just killing us right now, user and google wise. I'm wondering about running two dedicated boxes for LAMP, one running as the primary Nginx/Apache (proxy pass), and the other as the MySQL box. Running a single box scares the bejesus out of me because who knows how long it will take anyone to fix a raid card or whatever. The idea is to set this up using some sort of failover system using pacemaker and heartbeat. If one server goes down the other can take over for the other running both web and db. There are some good articles over at Linode about this. I have a few DBs that are 1GB+ and would like to load them into memory. Because of this, I'm shying away from a Linode HA setup because for the price I could do it with two dedicated like I described. Am I mad or an idiot? What are people out there doing for pseodu high availability good performance setups under $400/month? I'm a webmaster; I do a lot of things none of it that well :)

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  • Data Synchronization in mobile apps - multiple devices, multiple users

    - by ProgrammerNewbie
    I'm looking into building my first mobile app. One of the core features of the application is that multiple devices/users will have access to the same data -- and all of them will have CRUD rights. I believe the architecture should involve a central server where all the data is stored. The devices will use an API to interact with the server to perform its data operations (e.g. adding a record, editing a record, deleting a record). I imagine a scenario where synchronizing the data will become a problem. Assume the application should work when it is not connected to the Internet, and thus cannot communicate with this central server. So: User A is offline and edits record #100 User B is offline and edits record #100 User C is offline and deletes record #100 User C goes online (presumably, record #100 should get deleted on the server) User A and B goes online, but the records they edited no longer exist All sorts of scenarios similar to the above can come up. How is this generally handled? I plan to use MySQL, but am wondering if it's not appropriate for such a problem.

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  • What to learn after standard C++?

    - by Luca Cerone
    I switched to C++ a few months ago, learning its syntax, the main features of the STL and what you can usually find in a "learn C++" manual. Now I would like to go further. What would be your recommendations? I would like to know what to learn next (not only about the language, but also debugging, frameworks etc. etc.) I know probably the answer depends on the specific needs of each user, so here is a list of mine: Cross Platform development Developing GUI for my programs Develop extendible software, allowing the use of plugins Use of scientific libraries Interact with databases (mainly MySQL) Having server/client functionalities (I'd like users of my programs to interact through internet.. as you might have guessed I am not a programmer by training so I might have used the wrong terms.. if so I apologize for that). Of course I know it takes time, but I would like to have a good list of references and resources to start (both books and websites are ok). Thanks a lot for your help!

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  • Search multiple tables

    - by gilden
    I have developed a web application that is used mainly for archiving all sorts of textual material (documents, references to articles, books, magazines etc.). There can be any given number of archive tables in my system, each with its own schema. The schema can be changed by a moderator through the application (imagine something similar to a really dumbed down version of phpMyAdmin). Users can search for anything from all of the tables. By using FULLTEXT indexes together with substring searching (fields which do not support FULLTEXT indexing) the script inserts the results of a search to a single table and by ordering these results by the similarity measure I can fairly easily return the paginated results. However, this approach has a few problems: substring searching can only count exact results the 50% rule applies to all tables separately and thus, mysql may not return important matches or too naively discards common words. is quite expensive in terms of query numbers and execution time (not an issue right now as there's not a lot of data yet in the tables). normalized data is not even searched for (I have different tables for categories, languages and file attatchments). My planned solution Create a single table having columns similar to id, table_id, row_id, data Every time a new row is created/modified/deleted in any of the data tables this central table also gets updated with the data column containing a concatenation of all the fields in a row. I could then create a single index for Sphinx and use it for doing searches instead. Are there any more efficient solutions or best practises how to approach this? Thanks.

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  • Hard Drive Formatting and Unmounting Errors

    - by Lucas Carther
    I'm trying to format a hard drive using Ubuntu 11.10. Every time that I attempt to format it from the Disk Utility, I get the error saying the device is busy, and under details it says: /dev/sda1 is mounted Then when I try to unmount it from the disk utility, it shows that the operation has failed and says: Error unmounting: umount exited with exit code 1: helper failed with: umount: only root can unmount UUID=70D6-1701 from /boot/efi

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  • Why can't I install Windows 8 in Virtualbox on 12.04? [closed]

    - by The_Ubuntu_Kid
    I recently tried to install Windows 8 RP 32-bit in Virtualbox using Ubuntu 12.04 as the host. I have tried multiple settings for memory, hard drive size, etc. Every single time it has come up with this error Your PC needs to restart. Please hold down the power button Error code: 0x0000005D Parameters: 0x0306170A, 0x756E6547, 0x49656E69, 0x6C65746E I really like windows 8 and I would like to know how to fix this some time soon.

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  • How can i install .deb files from terminal , i tried different ways in askubuntu

    - by krishnamraju
    i am trying to install teamviewer and i am getting the following error and the entire process is as follows kittu@kittu-355V4C-356V4C-3445VC-3545VC:~$ sudo dpkg -i teamviewer_linux_x64.debdpkg: error processing archive teamviewer_linux_x64.deb (--install): cannot access archive: No such file or directory Errors were encountered while processing: teamviewer_linux_x64.deb the file is in home/downloads/teamviewer_linux_x64.deb

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  • Strange jboss console error

    - by c0mrade
    Hello everyone, I'm creating additional module to already multi-module maven project. And for this one I want everything to be like in other modules(meaning dependencies) just to test hello world, then I'll go do some more complex stuff. And it does print hello world as it should when deployed onto jboss server, but I get some strange error on console, had anyone had similar experience? and how can I fix it? Here it is : 15:48:35,789 ERROR [STDERR] log4j:ERROR A "org.jboss.logging.appender.FileAppender" object is not assignable to a "org.apache.log4j.Appender" variable. 15:48:35,789 ERROR [STDERR] log4j:ERROR The class "org.apache.log4j.Appender" was loaded by 15:48:35,790 ERROR [STDERR] log4j:ERROR [BaseClassLoader@9a8d9b{vfszip:/C:/jboss-5.1.0.GA/server/default/deploy/new-module-0.0.1-SNAPSHOT.war/}] whereas object of type 15:48:35,790 ERROR [STDERR] log4j:ERROR "org.jboss.logging.appender.FileAppender" was loaded by [org.jboss.bootstrap.NoAnnotationURLClassLoader@506411]. 15:48:35,790 ERROR [STDERR] log4j:ERROR Could not instantiate appender named "FILE".

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  • Suggest the best options to me to design the dynamic web interface using PHP MYSQL and AJAX

    - by Krishna
    Hello, I am designing a web interface for a company. I am describing the company's profile: company is currently having 5 branches and planning to extend their branches all over the country. it is an insurance surveying company. they are dealing with 6 Categories in the insurance domain, vide .. Engineering Fire Marine Motor Miscellaneous Risk Inspection and branches named as b1, b2, b3, b4, b5 and Extending. and finally they have contract with 22 companies. For each claim they are assign a unique ID. like contractcompany/category/serialno Ex: take a contracted company names as xxx, sss, zzz. xxx/Engineering/001 sss/Engineering/001 . . . xxx/Enginnering/002 sss/Engineering/002 . . . xxx/Fire/001 sss/Fire/001 . . . xxx/Fire/002 . . . xxx/Fire/002 . . . and so on..... by this way they issue the unique ID for each claim. Finally what i want is developing the interface with PHP mysql and ajax auto generating the unique id for each claim. store full details of the claims with reference to unique id. show all claims in one page, and they can view by branch wise and category wise. send monthly Report (All claims they have given and status of claims) to contract companies. give access to contracted companies, but they can view only their respective claims. Each claim has its own documents. So they can be uploaded by own company users or administrator. these files are associated with unique ID. contracted companies can view files. Give access to branches to enter new claims and update old claims. Administrator can create, update and delete all the claims and their details. Only administrator can grant new users (own company branches / contracted companies) Finally the the panel is completely database driven. Could any body can help. Thanks in advance Kindly do the needful and oblige Thanks and Regards Krishna. P [email protected]

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  • Zend Framework Installation

    - by theband
    I get this error after finishing the Zend Installation. Server error! The server encountered an internal error and was unable to complete your request. Either the server is overloaded or there was an error in a CGI script. If you think this is a server error, please contact the webmaster.

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  • How to Display result of subquery rows as one column in MySQL?

    - by SIA
    Hi I have three tables Category, Movies and RelCatMov Category-table categoryid, categoryName 1 thriller 2 supsense 3 romantic 4 action 5 sci-fi Movies-table movieid, movieName 1 Avataar 2 Titanic 3 NinjaAssassin RelCatMov-table categoryid, MovieID 1 1 2 2 3 2 4 2 5 2 Now i Want to display a the record as MovieName Categories Titanic Suspense,Romantic,Sci-fi,action How to do this. I am writing a query select MovieName,(select categoryname from category b,relcatmov c where b.categoryid=c.categoryid and c.movieid=a.movieid) as categories from movies a; Error: Subquery returns more than one row!!! How to display the result of rows in one column? Please help!!!

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  • When does a MySQL Query actually execute in PHP?

    - by MJB
    This sounds like a really simple question, but I am new to PHP. If I have a statement like this: $r =& $db->query("insert into table (col1, col2) values (10, 20)"); Do I have to still execute it, or does it get executed when I reference it? I have another case where I have a select query, which seems logically to run only when I call fetchrow, but the code I am presented with (to fix) does not call execute or fetch.I would have expected it to, so I cannot tell if it is just that I don't get it, or that the missing execute statement is the problem. It also does not insert the record, but it does not throw an error I can find. Also, I am a little confused by the =& notation. I looked it up on google, and found a few mentions of it, but I am still not clear on it. Thanks.

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  • PHP Strange error "0:". Possible Object syntax problem?

    - by Michael Stone
    I'm trying to transfer a site from one hosting company to another. I was using 000webhost until the client had hosting and a domain. Now that the client has their domain and hosting, using FatCow.com, I can not for the life of me, debug my PHP code. I'm not getting any errors. I have a successful DB connection. If you procedurally display data, it works, but when I try to use my original objects, something is breaking and just returns "0:". I have all errors on. On old server where the site worked: PHP Version 5.2.11 MySQL Version: 5.0.81 On new server where I get the "0:": PHP Version 5.2.12 MySQL Version 5.0.32 I've setup a test page to test just the output of the variables with the DB connection. Below is my code: <?php error_reporting(E_ALL); ini_set('display_errors', '1'); try { $link = mysql_connect('connectionstring', 'username', 'password'); if (!$link) { die('Could not connect: ' . mysql_error()); } else{ $db = mysql_select_db('a8210422_lit'); } if($db){ include_once('admin/classes/clsPOW.php'); include_once('admin/classes/clsProviders.php'); $pow = new POW(); $prov = new Providers(); $new = $pow->getNew(); $newAr = $new->val(); $get = $prov->getAll($newAr['providerId']); $getAr = $get->val(); $img = $getAr['image']; $name = $getAr['provider']; $desc = $getAr['description']; $zip = $getAr['zip']; $web = $getAr['link']; if($zip==0){ $zip = "Unavailable"; } print $img; print $name; print $desc; print $zip; print $web; } else{ print 'fail!'; } } //catch exception catch(Exception $e) { echo 'Message: ' .$e->getMessage(); } ?>

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  • MSQL upgrade on Ubuntu - any heads ups?

    - by Rob Sedge
    I am needing to upgrade MYSQL on Ubuntu, it is a production server and naturally cautious. My many googles look to be essentially saying that I need to : 1) Backup my current mysql database and tables/data 2) Uninstall current mysql 3) Install new MYSQL 5+ 4) Restore Databases/ tables and data 5) Hope and Pray I got it right ?? Something doesn't seem right, sounds like a lot of down time and risk Am I missing something / or any simple solutions? Upgrading from mSQL 4 to 5 on Ubuntu 10 Many Thanks, Rob

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  • How to check if an SQL query executed without error in ASP?

    - by Sam
    Here's my code: if Request.Form("authorize") <> "" and request.form("delete") <> "true" then post_ids = Request.form("authorize") ids = split(post_ids, ",") For i = LBound(ids) to UBound(ids) sql = "update tbl_comments set authorized = 'true' where comment_id = " & ids(i) pageDB.execute(sql) Next message = "<div id=""succeed""><strong>Updated</strong>: Your comments have been approved.</div>" end if Instead of just setting "message" to the success message i'd like to do something along the lines of... if(pageDB.execute(sql) was succesful) then message = "<div id=""succeed""><strong>Updated</strong>: Your comments have been approved.</div>" else message = "<div id=""error""><strong>Error</strong>: Your comments have not been approved.</div>" end if

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  • Spring Jdbc Template + MySQL = TransientDataAccessResourceException : Invalid Argument Value : Java.

    - by Vanchinathan
    I was using spring jdbc template to insert some data into the database and I was getting this error. Here is my code : JdbcTemplate insert = new JdbcTemplate(dataSource); for(ResultType result : response.getResultSet().getResult()) { Object[] args = new Object[] {result.getAddress(), result.getCity(), result.getState(), result.getPhone(), result.getLatitude(), result.getLongitude(),result.getRating().getAverageRating(), result.getRating().getAverageRating(), result.getRating().getTotalRatings(), result.getRating().getTotalReviews(), result.getRating().getLastReviewDate(), result.getRating().getLastReviewIntro(), result.getDistance(), result.getUrl(), result.getClickUrl(), result.getBusinessUrl(), result.getBusinessClickUrl()}; insert.update("INSERT INTO data.carwashes ( address, city, state, phone, lat, lng, rating, average_rating, total_ratings, total reviews, last_review_date, last_review_intro, distance, url, click_url, business_url, business_click_url, category_id, zipcode_id) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?,96925724,78701)", args); } Quite lengthy code.. but, basically it gets the value from a object and sticks it to a array and passed that array to insert method of jdbc template. Any help will be appreciated.

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  • How do I exit a series of If / else conditions in a mysql trigger?

    - by ScArcher2
    I have a trigger that checks to see if certain fields changed during the update. If any of these fields changed I update another table. I'd like to "break" out of the if conditions as soon as I know that something changed. Is there a way to do this within a MySQL Trigger? What I have works, but It seems inefficient. CREATE TRIGGER profile_trigger BEFORE UPDATE ON profile FOR EACH ROW BEGIN DECLARE changed INTEGER; SET changed = 0; IF STRCMP(NEW.first_name, OLD.first_name) <> 0 THEN SET changed = 1; ELSEIF STRCMP(NEW.last_name, OLD.last_name) <> 0 THEN SET changed = 1; ELSEIF STRCMP(NEW.maiden_name, OLD.maiden_name) <> 0 THEN SET changed = 1; ELSEIF STRCMP(NEW.suffix, OLD.suffix) <> 0 THEN SET changed = 1; ELSEIF STRCMP(NEW.title, OLD.title) <> 0 THEN SET changed = 1; ELSEIF STRCMP(NEW.gender, OLD.gender) <> 0 THEN SET changed = 1; ELSEIF STRCMP(NEW.street, OLD.street) <> 0 THEN SET changed = 1; ELSEIF STRCMP(NEW.street2, OLD.street2) <> 0 THEN SET changed = 1; ELSEIF STRCMP(NEW.city, OLD.city) <> 0 THEN SET changed = 1; ELSEIF STRCMP(NEW.state, OLD.state) <> 0 THEN SET changed = 1; ELSEIF STRCMP(NEW.zip, OLD.zip) <> 0 THEN SET changed = 1; ELSEIF STRCMP(NEW.home_phone, OLD.home_phone) <> 0 THEN SET changed = 1; ELSEIF NEW.date_of_birth <> OLD.date_of_birth THEN SET changed = 1; END IF; IF changed > 0 THEN update other_table set updated = CURRENT_TIMESTAMP where id = NEW.id; END IF; END; |

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  • PHP reporting error. DB verify how to?

    - by iamfab
    Error reporting Notice: Undefined variable: random_chars in wamp\www\php_sandbox\idgen.php on line 21 Call Stack: # Time Memory Function Location 1 0.0045 678928 {main}( ) ..\idgen.php:0 GPB7446 How do I fix this error? Using this code like an automatic unique id generator. How do I connect to DB to verify code is truly unique before allowing it to be assigned to a user creating a new account? Thanks <?php $characters = array( "A","B","E","F","G","H","J","K","M","N","P","R","S","T","W","X","Y","Z"); $keys = array(); while(count($keys) < 3) { $x = mt_rand(0, count($characters)-1); if(!in_array($x, $keys)) { $keys[] = $x; } } foreach($keys as $key){ $random_chars .= $characters[$key];} $randNum = rand(2327,9987); $randLet = rand(2327,9987); echo $random_chars . $randNum; ?>

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  • MySQL, PHP, and Apache errors while connecting to DB

    - by cypherdelton
    I'm having two errors when I test the "mysql_connect()" function in php. I just installed PHP and MySQL from scratch. These errors may be related, so I will post them both here: Warning: mysql_connect() [function.mysql-connect]: Headers and client library minor version mismatch. Headers:50158 Library:50518 in /usr/local/apache2/htdocs/index.php on line 6 Warning: mysql_connect() [function.mysql-connect]: Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (2) in /usr/local/apache2/htdocs/index.php on line 6 Many websites say to start the mysql server if you are getting error #2. Whenever I execute the command mysqld start --user=mysql I get the error "mysqld: Too many arguments (first extra is 'start'); Adding the "&" to the end of the command makes no difference (I don't know if it is supposed to). Thanks, Cypher Delton

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  • Setting an empty default value for a char-column in MySQL?

    - by user281434
    Hi In phpMyAdmin I have a char(32) column that has no default value(ie. Default: None). When I try to insert data through a SQL query, it throws out an error saying that the column "doesn't have a default value". I need it to be empty, so instead I've just set it's default value as "As defined: " and then nothing in the value field. Is this a bad idea? And is it any better than simply throwing in an empty value for the column in the SQL query? Thanks for your time.

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