Search Results

Search found 37414 results on 1497 pages for 'open port'.

Page 291/1497 | < Previous Page | 287 288 289 290 291 292 293 294 295 296 297 298  | Next Page >

• opening a file attachment from an outlook email using clickonce and a file association

  - by MarkGr

  Hi, I have a clickonce application (VS2010, .NET 4). I have registered a file association (.task), and this all works well. If I double click a file with the .task extension on the desktop the clickonce application opens and can open the file. If I email the file however, and double click the file from within outlook, I get the open/save dialog. If I click open nothing appears to happen. If I save the file I can open it by double clicking on it. Any ideas why the file does not open from within outlook ? Thanks, Mark

  Read the article

• Telerik RadEditor working issue under VS2008

  - by Stanislav

  I've a SharePoint portal for tracking questions in a list. When I open an list item in IE8 Telerik Editor works fine. But if I open this page inside VS2008 in browser mode this control starts to do unexpected actions. It's the Telerik RadEditor for Sharepoint v. 5.3.2.0. Is it a bug of VS2008 or a bug of Telerik RadEditor? Steps to reproduce: Install Telerik RadEditor in SharePoint portal Create a List with Rich editing field and create a new item Paste or type a text into Rich editing field and save changes Open VS2008 Click on any link in start page to open browser window Open created list item in VS in editing mode Mark a part of text in Rich editing field Marked text disappears. Undo button of control shows some paste actions

  Read the article

• Python - urllib2 & cookielib

  - by Adrian

  I am trying to open the following website and retrieve the initial cookie and use it for the second url-open BUT if you run the following code it outputs 2 different cookies. How do I use the initial cookie for the second url-open? import cookielib, urllib2 cj = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj)) home = opener.open('https://www.idcourts.us/repository/start.do') print cj search = opener.open('https://www.idcourts.us/repository/partySearch.do') print cj Output shows 2 different cookies every time as you can see: <cookielib.CookieJar[<Cookie JSESSIONID=0DEEE8331DE7D0DFDC22E860E065085F for www.idcourts.us/repository>]> <cookielib.CookieJar[<Cookie JSESSIONID=E01C2BE8323632A32DA467F8A9B22A51 for www.idcourts.us/repository>]>

  Read the article

• Static Javascript files not loaded in Express app

  - by Dave Long

  I have an express app that has a bunch of static javascript files that aren't being loaded even though they are registered in my app.js file. Even public scripts (like jQuery: http://ajax.googleapis.com/ajax/libs/jquery/1.6.3/jquery.min.js) aren't processing. I can see the script tags in the generated html, but none of the functionality runs and I can't see the files loading in the web inspector. Here is the code that I have: app.js var express = require('express') var app = module.exports = express.createServer(); // Configuration var port = process.env.PORT || 3000; app.configure(function(){ app.set('views', __dirname + '/views'); app.set('view engine', 'jade'); app.use(express.bodyParser()); app.use(express.methodOverride()); app.use(app.router); app.use(express.static(__dirname + '/public')); }); app.configure('development', function(){ app.use(express.errorHandler({ dumpExceptions: true, showStack: true })); }); app.configure('production', function(){ app.use(express.errorHandler()); }); // Routes app.get('/manage/new', function(req, res){ res.render('manage/new', { title: 'Create a new widget' }); }) app.listen(port); console.log("Express server listening on port %d in %s mode", app.address().port, app.settings.env); /views/manage/layout.jade !!! 5 html(lang="en") head title= title link(rel="stylesheet", href="/stylesheets/demo.css") link(rel="stylesheet", href="/stylesheets/jquery.qtip.css") script(type="text/javascript", href="http://ajax.googleapis.com/ajax/libs/jquery/1.6.3/jquery.min.js") body!= body script(type="text/javascript", href="/javascripts/jquery.formalize.js") script(type="text/javascript", href="/javascripts/jquery.form.js") script(type="text/javascript", href="/javascripts/jquery.qtip.js") script(type="text/javascript", href="/javascripts/formToWizard.js") script(type="text/javascript", href="/javascripts/widget.js") /views/manage/new.jade h1= title div(style="float:left;") form(action="/manage/generate", method="post", enctype="multipart/form-data", name="create-widget") .errors fieldset legend Band / Album Information fieldset legend Social Networks fieldset legend Download All of my javascript files are stored in /public/javascripts and all of my static CSS files are being served up just fine. I'm not sure what I've done wrong.

  Read the article

• Form data sent to Node via Post is undefined

  - by user185812

  I know this has been asked countless times on here, however I tried all the solutions and am still having the issue. Most people say to set the content-type (which I did) and to name the inputs that I wish to Post to node. I have done both of these things, yet still get "undefined" when trying to send data from an HTML form to node. JADE Templating HTML Code (Sorry I can't seem to get the indenting to show up here, however I think I should leave the code intact when posting here instead of converting it to normal HTML so that if the error is in here, you are still able to help) Form(action="/registration", method="post", enctype="application/x-www-form-urlencoded") div(class="control-group-Username") label(class="control-group", for="username") Username: div.controls input#Username(id="Username", type="text", placeholder="Username Here", maxlength="23", name="username") //Other divs and stuff here button.btn#submit_button(type="submit") Submit app.js code /** * Module dependencies. */ express = require('express') , routes = require('./routes') , user = require('./routes/user') , http = require('http') , path = require('path'); app = express(); // all environments app.set('port', process.env.PORT || 3000); app.set('views', __dirname + '/views'); app.set('view engine','jade'); app.use(express.favicon()); app.use(express.logger('dev')); app.use(express.bodyParser()); app.use(express.methodOverride()); app.use(express.cookieParser('your secret here')); app.use(express.session()); app.use(app.router); app.use(require('less-middleware')({ src: __dirname + '/public' })); app.use(express.static(path.join(__dirname, 'public'))); // development only if ('development' == app.get('env')) { app.use(express.errorHandler()); } app.use(express.static(__dirname + '/public')); app.get('/', routes.index); app.get('/users', user.list); app.get('/register', routes.register); http.createServer(app).listen(app.get('port'), function(){ console.log('Express server listening on port ' + app.get('port')); }); require('./Register.js'); register.js code app.post('/registration', function(req, res) { var Email=req.body.username console.log(username); });

  Read the article

• How can I concatenate corresponding lines in two files in Perl?

  - by Nano HE

  file1.txt hello tom well file2.txt world jerry done How to merge file1.txt with file2.txt; then create a new file - file3.txt hello world tom jerry well done thank you for reading and reply. Attached the completed code. #!/usr/bin/perl use strict; use warnings; open(F1,"<","1.txt") or die "Cannot open file1:$!\n"; open(F2,"<","2.txt") or die "Cannot open file2:$!\n"; open (MYFILE, '>>3.txt'); while(<F1>){ chomp; chomp(my $f2=<F2>); print MYFILE $_ . $f2 ."\n"; }

  Read the article

• Given a trace of packets, how would you group them into flows?

  - by zxcvbnm

  I've tried it these ways so far: 1) Make a hash with the source IP/port and destination IP/port as keys. Each position in the hash is a list of packets. The hash is then saved in a file, with each flow separated by some special characters/line. Problem: Not enough memory for large traces. 2) Make a hash with the same key as above, but only keep in memory the file handles. Each packet is then put into the hash[key] that points to the right file. Problems: Too many flows/files (~200k) and it might run out of memory as well. 3) Hash the source IP/port and destination IP/port, then put the info inside a file. The difference between 2 and 3 is that here the files are opened and closed for each operation, so I don't have to worry about running out of memory because I opened too many at the same time. Problems: WAY too slow, same number of files as 2 so also impractical. 4) Make a hash of the source IP/port pairs and then iterate over the whole trace for each flow. Take the packets that are part of that flow and place them into the output file. Problem: Suppose I have a 60 MB trace that has 200k flows. This way, I would process, say, a 60 MB file 200k times. Maybe removing the packets as I iterate would make it not so painful, but so far I'm not sure this would be a good solution. 5) Split them by IP source/destination and then create a single file for each one, separating the flows by special characters. Still too many files (+50k). Right now I'm using Ruby to do it, which might've been a bad idea, I guess. Currently I've filtered the traces with tshark so that they only have relevant info, so I can't really make them any smaller. I thought about loading everything in memory as described in 1) using C#/Java/C++, but I was wondering if there wouldn't be a better approach here, especially since I might also run out of memory later on even with a more efficient language if I have to use larger traces. In summary, the problem I'm facing is that I either have too many files or that I run out of memory. I've also tried searching for some tool to filter the info, but I don't think there is one. The ones I've found only return some statistics and wouldn't scan for every flow as I need.

  Read the article

• How to make a thread stay runnig in c#

  - by menachem

  Hello, I have a Windows Form Application (Form1) that allow the user to open another Forms (FormGraph). In order to open the FormGraph App I use a thread that open it. Here is the code that the thread is running: private void ThreadCreateCurvedGraph() { FormGraph myGraph = new FormGraph(); myGraph.CreateCurvedGraph(...); myGraph.Show(); } My problem is that myGraph closed right after it's open. 1) Does anyone know why this is happening and how to make myGraph stay open? 2) After the user closed myGraph, How do I terminate the thread? Many thanks!

  Read the article

• Naming selenium grid nodes. Spawning a specific node

  - by ???? ????

  I'm trying to implement a kind of default queues in selenium hub. There is a possibility to specify node's name (actually its environment, smth like "firefox on ubuntu" or "chrome on windows"). Selenium grid itself has a default queue, it works according to 'First In, First Out' principle. But I want to prioritize some of my tasks given to selenium server. I have no possibility to introduce custom queue (seems like there is no API for that), that's why I decided to separate queue's logic from selenium server. I'll only call a specific node with specific name (environment) for example "firefox important node" or smth like that. So, I want to know how to directly tell selenium which node to use for my task? And generally, am I thinking in a right way? Here are my configs: hubConfig.json.erb { "host": null, "port": <%= node[:selenium][:server][:port] %>, "newSessionWaitTimeout": -1, "servlets" : [], "prioritizer": null, "capabilityMatcher": "org.openqa.grid.internal.utils.DefaultCapabilityMatcher", "throwOnCapabilityNotPresent": true, "nodePolling": <%= node[:selenium][:server][:node_polling] %>, "cleanUpCycle": <%= node[:selenium][:server][:cleanup_cycle] %>, "timeout": <%= node[:selenium][:server][:timeout] %>, "browserTimeout": 0, "maxSession": <%= node[:selenium][:server][:max_session] %> } nodeConfig.json.erb { "capabilities": [ { "browserName": "firefox", "maxInstances": 5, "seleniumProtocol": "WebDriver" }, { "browserName": "chrome", "maxInstances": 5, "seleniumProtocol": "WebDriver" }, { "browserName": "phantomjs", "maxInstances": 5, "seleniumProtocol": "WebDriver" } ], "configuration": { "proxy": "org.openqa.grid.selenium.proxy.DefaultRemoteProxy", "maxSession": <%= node[:selenium][:node][:max_session] %>, "port": <%= node[:selenium][:node][:port] %>, "host": "<%= node[:fqdn] %>", "register": true, "registerCycle": <%= node[:selenium][:node][:register_cycle] %>, "hubPort": <%= node[:selenium][:server][:port] %> } } And my Driver class: ... def remote_driver @browser = Watir::Browser.new(:remote, :url => "http://myhub.com:4444/wd/hub", :http_client => client, :desired_capabilities => capabilities ) end def capabilities Selenium::WebDriver::Remote::Capabilities.send( "firefox", :javascript_enabled => true, :css_selectors_enabled => true, :takes_screenshot => true ) end def client client = Selenium::WebDriver::Remote::Http::Default.new client.timeout = 360 client end ... I still don't know how to use specified node for my task. If I try to start a driver adding :name => "firefox important node" and extend nodeConfig.json.erb's configuration with environments: - name: "firefox important node" browser: "*firefox" - name: "Firefox36 on Linux" browser: "*firefox" selenium just starts random firefox browser on a random node. How can I control it?

  Read the article

• declaring constraint to consider prog logic

  - by shantanuo

  I can open a trip only once but can close it multiple times. I can not declare the Trip_no + status as primary key since there can be multiple entries while closing the trip. Is there any way that will assure me that a trip number is opened only once? For e.g. there should not be the second row with "Open" status for trip No. 3 since it is already there in the following table. Trip No | Status 1 Open 1 Close 1 Close 2 Open 2 Close 3 Open 3 Close 3 Close 3 Close 3 Close

  Read the article

• Lines Concatenation between two files.

  - by Nano HE

  file1.txt hello tom well file2.txt world jerry done How to merge file1.txt with file2.txt; then create a new file - file3.txt hello world tom jerry well done thank you for reading and reply. Attached the completed code. #!/usr/bin/perl use strict; use warnings; open(F1,"<","1.txt") or die "Cannot open file1:$!\n"; open(F2,"<","2.txt") or die "Cannot open file2:$!\n"; open (MYFILE, '>>3.txt'); while(<F1>){ chomp; chomp(my $f2=<F2>); print MYFILE $_ . $f2 ."\n"; }

  Read the article

• Check whether Excel file is Password protected

  - by Torben Klein

  I am trying to open an Excel (xlsm) file via VBA. It may or may not be protected with a (known) password. I am using this code: On Error Resume Next Workbooks.Open filename, Password:=user_entered_pw opened = (Err.Number=0) On Error Goto 0 Now, this works fine if the workbook has a password. But if it is unprotected, it can NOT be opened. Apparently this is a bug in XL2007 if there is also workbook structure protection active. (http://vbaadventures.blogspot.com/2009/01/possible-error-in-excel-2007.html). On old XL2003, supplying a password would open both unprotected and password protected file. I tried: Workbooks.Open filename, Password:=user_entered_pw If (Err.Number <> 0) Then workbooks.open filename This works for unprotected and protected file. However if the user enters a wrong password it runs into the second line and pops up the "enter password" prompt, which I do not want. How to get around this?

  Read the article

• Check wether Excel file is Password protected

  - by Torben Klein

  I am trying to open an Excel (xlsm) file via VBA. It may or may not be protected with a (known) password. I am using this code: On Error Resume Next Workbooks.Open filename, Password:=user_entered_pw opened = (Err.Number=0) On Error Goto 0 Now, this works fine if the workbook has a password. But if it is unprotected, it can NOT be opened. Apparently this is a bug in XL2007 if there is also workbook structure protection active. (http://vbaadventures.blogspot.com/2009/01/possible-error-in-excel-2007.html). On old XL2003, supplying a password would open both unprotected and password protected file. I tried: Workbooks.Open filename, Password:=user_entered_pw If (Err.Number <> 0) Then workbooks.open filename This works for unprotected and protected file. However if the user enters a wrong password it runs into the second line and pops up the "enter password" prompt, which I do not want. How to get around this?

  Read the article

• Monitoring UDP socket in glib(mm) eats up CPU time

  - by Gyorgy Szekely

  Hi, I have a GTKmm Windows application (built with MinGW) that receives UDP packets (no sending). The socket is native winsock and I use glibmm IOChannel to connect it to the application main loop. The socket is read with recvfrom. My problem is: this setup eats 25% percent CPU time on a 3GHz workstation. Can somebody tell me why? The application is idle in this case, and if I remove the UDP code, CPU usage drops down to almost zero. As the application has to perform some CPU intensive tasks, I could image better ways to spend that 25% Here are some code excerpts: (sorry for the printf's ;) ) /* bind */ void UDPInterface::bindToPort(unsigned short port) { struct sockaddr_in target; WSADATA wsaData; target.sin_family = AF_INET; target.sin_port = htons(port); target.sin_addr.s_addr = 0; if ( WSAStartup ( 0x0202, &wsaData ) ) { printf("WSAStartup failed!\n"); exit(0); // :) WSACleanup(); } sock = socket( AF_INET, SOCK_DGRAM, 0 ); if (sock == INVALID_SOCKET) { printf("invalid socket!\n"); exit(0); } if (bind(sock,(struct sockaddr*) &target, sizeof(struct sockaddr_in) ) == SOCKET_ERROR) { printf("failed to bind to port!\n"); exit(0); } printf("[UDPInterface::bindToPort] listening on port %i\n", port); } /* read */ bool UDPInterface::UDPEvent(Glib::IOCondition io_condition) { recvfrom(sock, (char*)buf, BUF_SIZE*4, 0, NULL, NULL); /* process packet... */ } /* glibmm connect */ Glib::RefPtr channel = Glib::IOChannel::create_from_win32_socket(udp.sock); Glib::signal_io().connect( sigc::mem_fun(udp, &UDPInterface::UDPEvent), channel, Glib::IO_IN ); I've read here in some other question, and also in glib docs (g_io_channel_win32_new_socket()) that the socket is put into nonblocking mode, and it's "a side-effect of the implementation and unavoidable". Does this explain the CPU effect, it's not clear to me? Whether or not I use glib to access the socket or call recvfrom() directly doesn't seem to make much difference, since CPU is used up before any packet arrives and the read handler gets invoked. Also glibmm docs state that it's ok to call recvfrom() even if the socket is polled (Glib::IOChannel::create_from_win32_socket()) I've tried compiling the program with -pg and created a per function cpu usage report with gprof. This wasn't usefull because the time is not spent in my program, but in some external glib/glibmm dll.

  Read the article

• Contricted A* problem

  - by Ragekit

  I've got a little problem with an A* algorithm that I need to constrict a little bit. Basically : I use an A* to find the shortest path between 2 randomly placed room in 3D space, and then build a corridor between them. The problem I found is that sometimes it makes chimney like corridors that are not ideal, so I constrict the A* so that if the last movement was up or down, you go sideways. Everything is fine, but in some corner cases, it fails to find a path (when there is obviously one). Like here between the blue and red dot : (i'm in unity btw, but i don't think it matters) Here is the code of the actual A* (a bit long, and some redundency) while(current != goal) { //add stair up / stair down foreach(Node<GridUnit> test in current.Neighbors) { if(!test.Data.empty && test != goal) continue; //bug at arrival; if(test == goal && penul !=null) { Vector3 currentDiff = current.Data.bounds.center - test.Data.bounds.center; if(!Mathf.Approximately(currentDiff.y,0)) { //wanna drop on the last if(!coplanar(test.Data.bounds.center,current.Data.bounds.center,current.Data.parentUnit.bounds.center,to.Data.bounds.center)) { continue; } else { if(Mathf.Approximately(to.Data.bounds.center.x, current.Data.parentUnit.bounds.center.x) && Mathf.Approximately(to.Data.bounds.center.z, current.Data.parentUnit.bounds.center.z)) { continue; } } } } if(current.Data.parentUnit != null) { Vector3 previousDiff = current.Data.parentUnit.bounds.center - current.Data.bounds.center; Vector3 currentDiff = current.Data.bounds.center - test.Data.bounds.center; if(!Mathf.Approximately(previousDiff.y,0)) { if(!Mathf.Approximately(currentDiff.y,0)) { //you wanna drop now : continue; } if(current.Data.parentUnit.parentUnit != null) { if(!coplanar(test.Data.bounds.center,current.Data.bounds.center,current.Data.parentUnit.bounds.center,current.Data.parentUnit.parentUnit.bounds.center)) { continue; }else { if(Mathf.Approximately(test.Data.bounds.center.x, current.Data.parentUnit.parentUnit.bounds.center.x) && Mathf.Approximately(test.Data.bounds.center.z, current.Data.parentUnit.parentUnit.bounds.center.z)) { continue; } } } } } g = current.Data.g + HEURISTIC(current.Data,test.Data); h = HEURISTIC(test.Data,goal.Data); f = g + h; if(open.Contains(test) || closed.Contains(test)) { if(test.Data.f > f) { //found a shorter path going passing through that point test.Data.f = f; test.Data.g = g; test.Data.h = h; test.Data.parentUnit = current.Data; } } else { //jamais rencontré test.Data.f = f; test.Data.h = h; test.Data.g = g; test.Data.parentUnit = current.Data; open.Add(test); } } closed.Add (current); if(open.Count == 0) { Debug.Log("nothingfound"); //nothing more to test no path found, stay to from; List<GridUnit> r = new List<GridUnit>(); r.Add(from.Data); return r; } //sort open from small to biggest travel cost open.Sort(delegate(Node<GridUnit> x, Node<GridUnit> y) { return (int)(x.Data.f-y.Data.f); }); //get the smallest travel cost node; Node<GridUnit> smallest = open[0]; current = smallest; open.RemoveAt(0); } //build the path going backward; List<GridUnit> ret = new List<GridUnit>(); if(penul != null) { ret.Insert(0,to.Data); } GridUnit cur = goal.Data; ret.Insert(0,cur); do{ cur = cur.parentUnit; ret.Insert(0,cur); } while(cur != from.Data); return ret; You see at the start of the foreach i constrict the A* like i said. If you have any insight it would be cool. Thanks

  Read the article

• file_operations Question, how do i know if a process that opened a file for writing has decided to c

  - by djTeller

  Hi Kernel Gurus, I'm currently writing a simple "multicaster" module. Only one process can open a proc filesystem file for writing, and the rest can open it for reading. To do so i use the inode_operation .permission callback, I check the operation and when i detect someone open a file for writing I set a flag ON. i need a way to detect if a process that opened a file for writing has decided to close the file so i can set the flag OFF, so someone else can open for writing. Currently in case someone is open for writing i save the current-pid of that process and when the .close callback is called I check if that process is the one I saved earlier. Is there a better way to do that? Without saving the pid, perhaps checking the files that the current process has opened and it's permission... Thanks!

  Read the article

• How can i fix this jquery script for submenu?

  - by Giulio Bambini

  This is the code and this is the result: www.studionews24.com you can see test the menu by clicking inside. $(document).ready(function () { var $links = $('#menu-menu-1 .menu-item a').click(function () { var submenu = $(this).next(); $subs.not(submenu).hide() submenu.toggle(500); $("#menu-2").slideToggle(300); }); var $subs = $links.next(); }); The problem is that if I click on the menu it appears the submenu, but if I don't close the submenu that I have open and I open another voice in the menu it doesn't work properly. If I click another .menu-item a when #menu-2 is open what happens? The script close and open another submenu correctly but my #menu-2 close only close. And then if I close .menu-item a so... #menu-2 open. How can I do to fix?

  Read the article

• Constrained A* problem

  - by Ragekit

  I've got a little problem with an A* algorithm that I need to Constrained a little bit. Basically : I use an A* to find the shortest path between 2 randomly placed room in 3D space, and then build a corridor between them. The problem I found is that sometimes it makes chimney like corridors that are not ideal, so I constrict the A* so that if the last movement was up or down, you go sideways. Everything is fine, but in some corner cases, it fails to find a path (when there is obviously one). Like here between the blue and red dot : (i'm in unity btw, but i don't think it matters) Here is the code of the actual A* (a bit long, and some redundency) while(current != goal) { //add stair up / stair down foreach(Node<GridUnit> test in current.Neighbors) { if(!test.Data.empty && test != goal) continue; //bug at arrival; if(test == goal && penul !=null) { Vector3 currentDiff = current.Data.bounds.center - test.Data.bounds.center; if(!Mathf.Approximately(currentDiff.y,0)) { //wanna drop on the last if(!coplanar(test.Data.bounds.center,current.Data.bounds.center,current.Data.parentUnit.bounds.center,to.Data.bounds.center)) { continue; } else { if(Mathf.Approximately(to.Data.bounds.center.x, current.Data.parentUnit.bounds.center.x) && Mathf.Approximately(to.Data.bounds.center.z, current.Data.parentUnit.bounds.center.z)) { continue; } } } } if(current.Data.parentUnit != null) { Vector3 previousDiff = current.Data.parentUnit.bounds.center - current.Data.bounds.center; Vector3 currentDiff = current.Data.bounds.center - test.Data.bounds.center; if(!Mathf.Approximately(previousDiff.y,0)) { if(!Mathf.Approximately(currentDiff.y,0)) { //you wanna drop now : continue; } if(current.Data.parentUnit.parentUnit != null) { if(!coplanar(test.Data.bounds.center,current.Data.bounds.center,current.Data.parentUnit.bounds.center,current.Data.parentUnit.parentUnit.bounds.center)) { continue; }else { if(Mathf.Approximately(test.Data.bounds.center.x, current.Data.parentUnit.parentUnit.bounds.center.x) && Mathf.Approximately(test.Data.bounds.center.z, current.Data.parentUnit.parentUnit.bounds.center.z)) { continue; } } } } } g = current.Data.g + HEURISTIC(current.Data,test.Data); h = HEURISTIC(test.Data,goal.Data); f = g + h; if(open.Contains(test) || closed.Contains(test)) { if(test.Data.f > f) { //found a shorter path going passing through that point test.Data.f = f; test.Data.g = g; test.Data.h = h; test.Data.parentUnit = current.Data; } } else { //jamais rencontré test.Data.f = f; test.Data.h = h; test.Data.g = g; test.Data.parentUnit = current.Data; open.Add(test); } } closed.Add (current); if(open.Count == 0) { Debug.Log("nothingfound"); //nothing more to test no path found, stay to from; List<GridUnit> r = new List<GridUnit>(); r.Add(from.Data); return r; } //sort open from small to biggest travel cost open.Sort(delegate(Node<GridUnit> x, Node<GridUnit> y) { return (int)(x.Data.f-y.Data.f); }); //get the smallest travel cost node; Node<GridUnit> smallest = open[0]; current = smallest; open.RemoveAt(0); } //build the path going backward; List<GridUnit> ret = new List<GridUnit>(); if(penul != null) { ret.Insert(0,to.Data); } GridUnit cur = goal.Data; ret.Insert(0,cur); do{ cur = cur.parentUnit; ret.Insert(0,cur); } while(cur != from.Data); return ret; You see at the start of the foreach i constrict the A* like i said. If you have any insight it would be cool. Thanks

  Read the article

• How can I force the server socket to re-accept a request from a client?

  - by Roman

  For those who does not want to read a long question here is a short version: A server has an opened socket for a client. The server gets a request to open a socket from the same client-IP and client-port. I want to fore the server not to refuse such a request but to close the old socket and open a new one. How can I do ti? And here is a long (original) question: I have the following situation. There is an established connection between a server and client. Then an external software (Bonjour) says to my client the it does not see the server in the local network. Well, client does nothing about that because of the following reasons: If Bonjour does not see the server it does not necessarily means that client cannot see the server. Even if the client trusts the Bonjour and close the socket it does not improve the situation ("to have no open socket" is worser that "to have a potentially bad socket"). So, client do nothing if server becomes invisible to Bonjour. But than the server re-appears in the Bonjour and Bonjour notify the client about that. In this situation the following situations are possible: The server reappears on a new IP address. So, the client needs to open a new socket to be able to communicate with the server. The server reappears on the old IP address. In this case we have two subcases: 2.1. The server was restarted (switched off and then switched on). So, it does not remember the old socket (which is still used by the client). So, client needs to close the old socket and open a new one (on the same server-IP address and the same server-port). 2.2. We had a temporal network problem and the server was running the whole time. So, the old socket is still available for the use. In this case the client does not really need to close the old socket and reopen a new one. But to simplify my life I decide to close and reopen the socket on the client side in any case (in spite on the fact that it is not really needed in the last described situation). But I can have problems with that solution. If I close the socket on the client side and than try to reopen a socket from the same client-IP and client-port, server will not accept the call for a new socket. The server will think that such a socket already exists. Can I write the server in such a way, that it does not refuse such calls. For example, if it (the server) sees that a client send a request for a socket from the same client-IP and client-port, it (server) close the available socket, associated with this client-IP and client-port and than it reopens a new socket.

  Read the article

• Test plans and how best to write them

  - by Karim

  We're trying to figure out the best way to write tests in our test plan. Specifically, when writing a test that is meant to be used by anyone including QA staff, should the steps in the test be very specific or more broad giving the tester more leeway in how the task can be accomplished. As a very simple example, if you're testing opening a document in word processing document, should the test read: Using the mouse, open the file menu Choose "Open File..." in the file menu In the open file dialog that appears, navigate to x and double-click the document called y OR Bring up the file open dialog Open the file y Now I realize one answer is probably going to be "it depends on what you're trying to test" but I'm trying to answer a broader question here: If the test steps are too specific do we risk a) making the testing process to laborious and tedious and more importantly b) do we risk missing something because we wrote down too specific a path to achieve a goal. Alternatively, if we make it broad do we depend too much on the whims of the tester at the time and lose crucial testing of paths that are more common to customers/clients?

  Read the article

• Interconnecting Emulator Instances Android

  - by blah01

  Hi all I want to communicate two emulators via DatagramSocket in Android. Each of them is a Node in a P2P system. Thus each of them has a server Thread and client Thread (created per GUI event). This is how I create server public static final String SERVERIP = "10.0.2.15"; //... run() { InetAddress serverAddr = InetAddress.getByName(SERVERIP); DatagramSocket socket = new DatagramSocket(SERVERPORT,serverAddr); while(true) { byte[] buf = new byte[29]; DatagramPacket packet = new DatagramPacket(buf, buf.length); socket.receive(packet); //... } } The port is given by the user during initializing application. The client part (requesting some data) InetAddress serverAddr = InetAddress.getByName("10.0.2.2"); //... Log.i("Requester", "Trying to connect to device port = "+target); DatagramSocket socketJ = new DatagramSocket(); byte[] bufJ = Adaptor.createStringMsg(Adaptor.createJoingMsg(id, Location.getX(), Location.getY())).getBytes(); DatagramPacket packetJ = new DatagramPacket(bufJ, bufJ.length, serverAddr, target); Log.i("Requester", "Sending: '" + new String(bufJ) + "'"); socketJ.send(packetJ); Log.i("Requester", "Done."); Some additional info. The Node1 (emulatorA) has a server on port 8000 and Node2 (emulatorB) has a server on port 8001. The target port for "client part" is read properly. What tried to do is to set the redirection as such: //emulatorA redir add tcp:8000:8000 //emulatorB redir add tcp:8001:8001 However I can not get any communication beetwen those 2 emulators. As far as I understood the android tutorial about it should work like this redir add tcp:localhostPort:emulatorPort. I'm stuck with it :/. Can anyone point me the mistake or give some good advice. For the record while I was testing communication on a single device (client faking other node) everything worked, so I don't think there is a bug in the code. Btw does any one knows how can I get 2 set of logs for those 2 emulators (logA, logB)? It would help me a lot.

  Read the article

• Python text file processing speed issues

  - by Anonymouslemming

  Hi all, I'm having a problem with processing a largeish file in Python. All I'm doing is f = gzip.open(pathToLog, 'r') for line in f: counter = counter + 1 if (counter % 1000000 == 0): print counter f.close This takes around 10m25s just to open the file, read the lines and increment this counter. In perl, dealing with the same file and doing quite a bit more (some regular expression stuff), the whole process takes around 1m17s. Perl Code: open(LOG, "/bin/zcat $logfile |") or die "Cannot read $logfile: $!\n"; while (<LOG>) { if (m/.*\[svc-\w+\].*login result: Successful\.$/) { $_ =~ s/some regex here/$1,$2,$3,$4/; push @an_array, $_ } } close LOG; Can anyone advise what I can do to make the Python solution run at a similar speed to the Perl solution? I've tried just uncompressing the file and dealing with it using open instead of gzip.open, but that made a very small difference to the overall time.

  Read the article

• MySqlConnection really not close

  - by stighy

  Hi guys, i've a huge problem. Take a look to this sample code private sub FUNCTION1() dim conn as new mysqlconnection(myconnstring) conn.open ---- do something FUNCTION2() ---- conn.close end sub private sub FUNCTION2() dim conn as new mysqlconnection(myconnstring) .... conn.open -- do something conn.close end sub Despite i close regulary all my connection, they remains "open" on the mysql server. I know this because i'm using MySQL Administration tool to check how many connection i open "line by line" of my source code. In fact i get a lot of time "user has exceeded the 'max_user_connections' resource (current value: 5)" My hoster permit ONLY 5 connection, but i think that if i write GOOD source code, this cannot be a problem. So my question is: why that "damn" connections remain open ?? Thank you in advance!

  Read the article

• Using Juniper EX3300 as a router

  - by Richard Whitman

  So I have a Juniper EX3300 Switch. One of its uplink ports (ge-0/1/0) is connected to my ISP's router. ISP router's port address is xx.xx.xx.109. My switch's IP address is xx.xx.xx.110. From the switch, I can ping to xx.xx.xx.109 and any other IP in the world. I mean its connected to the Internet. I connected the port eth0 of a computer (running Ubuntu) to the port ge-0/0/0 of the switch (which in the same VLAN as ge-0/1/0). I configured the port eth0 as follows: iface eth0 inet static address yy.yy.yy.208 netmask 255.255.255.240 gateway xx.xx.xx.110 yy.yy.yy.208 is assigned to me by the ISP. So, now I can ping to the switch (xx.xx.xx.110) from this computer. But I can not ping to either xx.xx.xx.109 (ISP router) or any other IP. I want this computer to be connected to the Internet. What am I doing wrong? Here are some of the configurations on my switch: interfaces { ge-0/0/0 { unit 0 { family ethernet-switching; } } . . . ge-0/1/0 { ether-options { no-auto-negotiation; link-mode full-duplex; speed { 1g; } } unit 0 { family ethernet-switching { port-mode access; } } } . . . vlan { unit 0 { family inet { address 10.0.1.1/24; } } unit 1 { family inet { address xx.xx.xx.110/30; } } } } . . . routing-options { static { route 0.0.0.0/0 { next-hop xx.xx.xx.109; retain; } } } vlans { Cogent { vlan-id 3; interface { ge-0/1/0.0; ge-0/0/0.0; ge-0/0/1.0; ge-0/0/2.0; ge-0/0/3.0; } l3-interface vlan.1; } TFLan { vlan-id 2; interface { ge-0/0/5.0; ge-0/0/6.0; ge-0/0/7.0; ge-0/0/8.0; ge-0/0/9.0; ge-0/0/10.0; ge-0/0/11.0; ge-0/0/12.0; ge-0/0/13.0; ge-0/0/14.0; ge-0/0/15.0; ge-0/0/16.0; ge-0/0/17.0; ge-0/0/18.0; ge-0/0/19.0; ge-0/0/20.0; ge-0/0/21.0; ge-0/0/22.0; ge-0/0/23.0; ge-0/0/4.0; } l3-interface vlan.0; } }

  Read the article

• Cannot read status the monit daemon, even with allowed group

  - by jefflunt

  I cannot seem to get monit status or other CLI commands to work. I've built monit v5.8 to run on a Raspberry Pi. I'm able to add services to be monitored, and the web interface can be accessed just fine, as I've set it up for public read-only access (it's a test server, not my final production setup, so not a big deal right now). Problem is, when I run monit status while logged in as root I get: # monit status monit: cannot read status from the monit daemon I also have monit started on boot via this /etc/inittab file entry: mo:2345:respawn:/usr/local/bin/monit -Ic /etc/monitrc I've verified that monit is running, and I'm getting email alerts anytime I either kill the monit process manually, or reboot my raspberry pi. So, next I check my monitrc file permissions to see which group is allowed access. # ls -al /etc/monitrc -rw------- 1 root root 2359 Aug 24 14:48 /etc/monitrc Here's my relevant allow section of the control file. set httpd port 80 allow [omitted] readonly allow @root allow localhost allow 0.0.0.0/0.0.0.0 Also tried setting permissions on this file to 640 to allow group read permissions, but no matter what I try I either get the same error as noted above, or when the permissions are set to 640 I get: # monit status monit: The control file '/etc/monitrc' must have permissions no more than -rwx------ (0700); right now permissions are -rw-r----- (0640). What am I missing here? I know that the httpd must be enabled, as that's the interface that the CLI uses to get information (or so I've read), so I've done that. And in terms of monit doing its monitoring job and sending email alerts, that's all working as well. Here's my entire monitrc file - again, this is version v5.8, and it was build with both PAM and SSL support. The process runs under the root user: # Global settings set daemon 300 with start delay 5 set logfile /var/log/monit.log set pidfile /var/run/monit.pid set idfile /var/run/.monit.id set statefile /var/run/.monit.state # Mail alerts ## Set the list of mail servers for alert delivery. Multiple servers may be ## specified using a comma separator. If the first mail server fails, Monit # will use the second mail server in the list and so on. By default Monit uses # port 25 - it is possible to override this with the PORT option. # set mailserver smtp.gmail.com port 587 username [omitted] password [omitted] using tlsv1 ## Send status and events to M/Monit (for more informations about M/Monit ## see http://mmonit.com/). By default Monit registers credentials with ## M/Monit so M/Monit can smoothly communicate back to Monit and you don't ## have to register Monit credentials manually in M/Monit. It is possible to ## disable credential registration using the commented out option below. ## Though, if safety is a concern we recommend instead using https when ## communicating with M/Monit and send credentials encrypted. # # set mmonit http://monit:[email protected]:8080/collector # # and register without credentials # Don't register credentials # # ## Monit by default uses the following format for alerts if the the mail-format ## statement is missing:: set mail-format { from: [email protected] subject: $SERVICE $DESCRIPTION message: $EVENT Service: $SERVICE Date: $DATE Action: $ACTION Host: $HOST Description: $DESCRIPTION Monit instance provided by chicagomeshnet.com } # Web status page set httpd port 80 allow [omitted] readonly allow @root allow localhost allow 0.0.0.0/0.0.0.0 ## You can set alert recipients whom will receive alerts if/when a ## service defined in this file has errors. Alerts may be restricted on ## events by using a filter as in the second example below.

  Read the article

< Previous Page | 287 288 289 290 291 292 293 294 295 296 297 298  | Next Page >