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  • Tallying records using annotate() not working as should.

    - by 47
    I have two classes: Vehicle and Issues....a Vehicle object can have several issues recorded in the Issues class. What I want to do is to have a list of all issues, with each vehicle appearing only once and the total number of issues shown, plus other details....clicking on the record will then take the user to another page with all those issues for a selected vehicle shown in detail now. I tried this out using annotate, but I could only access the count and vehicle foreign key, but none of the other fields in the Vehicle class. class Issues(models.Model): vehicle = models.ForeignKey(Vehicle) description = models.CharField('Issue Description', max_length=30,) type = models.CharField(max_length=10, default='Other') status = models.CharField(max_length=12, default='Pending') priority = models.IntegerField(default='8', editable=False) date_time_added = models.DateTimeField(default=datetime.today, editable=False) last_updated = models.DateTimeField(default=datetime.today, editable=False) def __unicode__(self): return self.description The code I was using to annotate is: issues = Issues.objects.all().values('vehicle').annotate(count=Count('id')) What could be the problem?

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  • Rails 3 ActiveRecord group_by sort by count

    - by Craig
    The following view code generates a series of links with totals (as expected): <% @jobs.group_by(&:employer_name).sort.each do |employer, jobs| %> <%= link_to employer, jobs_path() %> <%= "(#{jobs.length})" %> <% end %> However, when I refactor the view's code and move the logic to a helper, the code doesn't work as expect. view: <%= employer_filter(@jobs_clone) %> helper: def employer_filter(jobs) jobs.group_by(&:employer_name).sort.each do |employer,jobs| link_to employer, jobs_path() end end The following output is generated: <Job:0x10342e628>#<Job:0x10342e588>#<Job:0x10342e2e0>Employer A#<Job:0x10342e1c8>Employer B#<Job:0x10342e0d8>Employer C#<Job:0x10342ded0>Employer D# What am I not understanding? At first blush, the code seems to be equivalent.

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  • Rails- MiniMagick commands not working

    - by digitalWestie
    I'm running windows xp and I've got MiniMagick and ImageMagick installed (latest versions). I'm now using the console to test out that everything works. Using the ms command prompt image magick works no problem. I'm testing this by using the identify command. Now, when I try to use MiniMagick from the console by entering image = MiniMagick::Image.new('image.jpg') It returns MiniMagickError, "ImageMagick command ("identify \"input.jpg\"") failed: {:status_code = #"'identify' is not recognized as an internal or external command,\noperable program or batch file.\n"} Can anybody help?

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  • Ruby On Rails: Ask for Confirmation When Table Entry Associated With Another Is Destroyed

    - by Train Main
    Hi all, I would like some assistance with the following problem: I have a table of groups that is self-associated with itself, so each group is (optionally) linked to another in a hierarchical fashion. I want to write some code that will somehow check before the destruction of a group entry, if it has any children, and ask the user for confirmation, or whether they wish to delete the child groups as well. I've looked at callbacks, but I don't know how to get the confirmation request to the end user in the view, and then get the response back to the model's callback. Thanks

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  • Rails 3 refactoring issue

    - by Craig
    The following view code generates a series of links with totals (as expected): <% @jobs.group_by(&:employer_name).sort.each do |employer, jobs| %> <%= link_to employer, jobs_path() %> <%= "(#{jobs.length})" %> <% end %> However, when I refactor the view's code and move the logic to a helper, the code doesn't work as expect. view: <%= employer_filter(@jobs_clone) %> helper: def employer_filter(jobs) jobs.group_by(&:employer_name).sort.each do |employer,jobs| link_to employer, jobs_path() end end The following output is generated: <Job:0x10342e628>#<Job:0x10342e588>#<Job:0x10342e2e0>Employer A#<Job:0x10342e1c8>Employer B#<Job:0x10342e0d8>Employer C#<Job:0x10342ded0>Employer D# What am I not understanding? At first blush, the code seems to be equivalent.

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  • Rails 3 - routing

    - by akam
    I don't know how to make a link_to because I'dont have a nouveau_message_path in rake routes rake routes : GET /nouveau_message/.:id {:action=>"nouveau_message", :controller=>"messages"} routes.rb : controller :messages do get 'nouveau_message/.:id' => :nouveau_message end What is the best way to make a link_to to nouveau_message from another view ? Thanks

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  • cattr_accessor outside of rails

    - by JP
    I'm trying to use the google_search ruby library (code follows) but it complains that 'cattr_accessor is an undefined method' - any ideas why this might be or how I could fix it? require 'rubygems' require 'google_search' GoogleSearch.web :q => "pink floyd"

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  • Rails 3.0 method_missing: undefined method in validator

    - by user567592
    == Schema Information Schema version: 20110111000403 # Table name: places # id :integer not null, primary key name :string(255) latitude :float longitude :float a place can be defined by latitude and longitude or by name # class Place < ActiveRecord::Base validates_precence_of :name, :if = lat_long_not_def? def lat_long_not_def? latitude.blank? || longitude.blank? end end

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  • How to join the results of two tables in django python

    - by user1787524
    I have two models class Weather(model.model): region = models.ForeignKey(Region) district = models.ForeignKey(District) temp_max = models.IntegerField(blank=True, null=True, verbose_name='Max temperature (C)') temp_min = models.IntegerField(blank=True, null=True, verbose_name='Min temperature (C)') and class Plan(model.model): name = tinymce_models.HTMLField(blank=True, null=True) region = models.ForeignKey(Region) district = models.ForeignKey(District) Provided for every region and district have unique row. I want to combine the result so that i can get all the columns of both tables These two Models are not related to each other. ' I need to make the join like join weather w on w.region = A.region and w.distric = A.district so that result contains all the columns in everyobject like obj.temp_max etc

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  • Space (and pipe sign) works on occasion only

    - by Timo Riikonen
    I have an issue that when I try to write pipe sign "|" and space after that, I sometimes get wrong type of space (\240) and my command fails. This issue persists on different shells. How could I fix this? I am using Finnish keyboard layout. timo@timo-i7-ubuntu:~$ ps -ef | grep ruby timo 7169 2633 0 12:12 pts/2 00:00:00 ruby1.9.1 /usr/local/bin/rails new admin4 timo 8736 26515 0 14:22 pts/4 00:00:00 grep --color=auto ruby timo@timo-i7-ubuntu:~$ ps -ef | grep ruby No command ' grep' found, did you mean: Command 'igrep' from package 'openimageio-tools' (universe) Command 'dgrep' from package 'debian-goodies' (main) Command 'rgrep' from package 'grep' (main) Command 'zgrep' from package 'gzip' (main) Command 'zgrep' from package 'zutils' (universe) Command 'sgrep' from package 'sgrep' (universe) Command 'lgrep' from package 'lv' (universe) Command 'egrep' from package 'grep' (main) Command 'ngrep' from package 'ngrep' (universe) Command 'grep' from package 'grep' (main) Command 'agrep' from package 'agrep' (multiverse) Command 'pgrep' from package 'procps' (main) Command 'xgrep' from package 'xgrep' (universe) Command 'vgrep' from package 'atfs' (universe) Command 'fgrep' from package 'grep' (main)  grep: command not found timo@timo-i7-ubuntu:~$ cat pipecom ps -ef | grep rails timo@timo-i7-ubuntu:~$ cat pipecom2 ps -ef | grep rails timo@timo-i7-ubuntu:~$ ./pipecom timo 7169 2633 0 12:12 pts/2 00:00:00 ruby1.9.1 /usr/local/bin/rails new admin4 timo 8777 8775 0 14:26 pts/4 00:00:00 grep rails timo@timo-i7-ubuntu:~$ ./pipecom2 ./pipecom2: line 1: $'\302\240grep': command not found timo@timo-i7-ubuntu:~$ diff -w pipecom pipecom2 1c1 < ps -ef | grep rails --- > ps -ef | grep rails

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  • How to Assure an Effective Data Model

    As a general rule in my opinion the effectiveness of a data model can be directly related to the accuracy and complexity of a project’s requirements. For example there is no need to work on very detailed data models when the details surrounding a specific data model have not been defined or even clarified. Developing data models when the clarity of project requirements is limited tends to introduce designed issues because the proper details to create an effective data model are not even known. One way to avoid this issue is to create data models that correspond to the complexity of the existing project requirements so that when requirements are updated then new data models can be created based any new discoveries regarding requirements on a fine grain level.  This allows for data models to be composed of general entities to be created initially when a project’s requirements are very vague and then the entities are refined as new and more substantial requirements are defined or redefined. This promotes communication amongst all stakeholders within a project as they go through the process of defining and finalizing project requirements.In addition, here are some general tips that can be applied to projects in regards to data modeling.Initially model all data generally and slowly reactor the data model as new requirements and business constraints are applied to a project.Ensure that data modelers have the proper tools and training they need to design a data model accurately.Create a common location for all project documents so that everyone will be able to review a project’s data models along with any other project documentation.All data models should follow a clear naming schema that tells readers the intended purpose for the data and how it is going to be applied within a project.

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  • With NVD3.js (nv.models.lineWithFocusChart), how do you set specific ticks on X-axis, when x values are dates?

    - by Panagiotis Panagi
    I'm using nv.models.lineWithFocusChart, where I'm showing some hourly measurements. So the x domain is dates. What I need is to show a tick per hour on X axis: 00:00 01:00 02:00 ... 24:00 I've tried everything I could find but nothing works. It seems that its easy to set specific ticks when values are not dates. But can't figure out how to do it for dates. Here's the code that creates the graph, if it can help: nv.addGraph -> chart = nv.models.lineWithFocusChart(view) chart.yAxis.tickFormat(d3.format(".02f")) d3.select(graphSelector).datum([]).transition().duration(500).call(chart) nv.utils.windowResize -> d3.select(graphSelector).call(chart) chart.xAxis.tickFormat (d) -> d3.time.format(ticksFormat)(new Date(d)) chart.x2Axis.tickFormat (d) -> d3.time.format(ticksFormat)(new Date(d)) chart.xAxis.tickSubdivide(9)

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  • MVVM- How would I go about propagating settings between my main view-model (and other view-models) a

    - by Justin
    I am building a settings dialog for my application and right now all of the settings correspond with settings on the main view-model, but as I add more view's and view-models some may not. I need to know what the best practice is for loading the current settings into the settings dialog and then saving the settings to thier corresponding view-models if the user clicks okay. I will not be using the Properties.Settings.Default system to store settings since I want my application to be as portable as possible and this would store user scoped settings in the directory: C:\Users\ username \Local Settings\Application Data\ ApplicationName Instead of in my application's directory. In case it makes any difference I am using the MVVM Light Toolkit by Laurent Bugnion.

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  • « Le TDD est mort » pour le créateur de Ruby on rails, une position qui divise la communauté agile

    Le TDD est mort ? Non, pas vraiment, peut-être que oui La communauté agile taraudée par un débat autour du TDD« Le TDD est mort ? Ou pas ? » Telle est la question qui taraude l'esprit de la communauté agile en ce moment, vu l'importance du TDD (Test Driven Development ? Développement piloté par les tests) dans l'une des méthodes agiles les plus réputées : la méthode XP.À l'origine de ce débat houleux, David Heinemeier Hansson (DHH) auteur de Ruby on rails et fondateur du Basecamp et ses deux posts...

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  • LLBLGen Pro feature highlights: grouping model elements

    - by FransBouma
    (This post is part of a series of posts about features of the LLBLGen Pro system) When working with an entity model which has more than a few entities, it's often convenient to be able to group entities together if they belong to a semantic sub-model. For example, if your entity model has several entities which are about 'security', it would be practical to group them together under the 'security' moniker. This way, you could easily find them back, yet they can be left inside the complete entity model altogether so their relationships with entities outside the group are kept. In other situations your domain consists of semi-separate entity models which all target tables/views which are located in the same database. It then might be convenient to have a single project to manage the complete target database, yet have the entity models separate of each other and have them result in separate code bases. LLBLGen Pro can do both for you. This blog post will illustrate both situations. The feature is called group usage and is controllable through the project settings. This setting is supported on all supported O/R mapper frameworks. Situation one: grouping entities in a single model. This situation is common for entity models which are dense, so many relationships exist between all sub-models: you can't split them up easily into separate models (nor do you likely want to), however it's convenient to have them grouped together into groups inside the entity model at the project level. A typical example for this is the AdventureWorks example database for SQL Server. This database, which is a single catalog, has for each sub-group a schema, however most of these schemas are tightly connected with each other: adding all schemas together will give a model with entities which indirectly are related to all other entities. LLBLGen Pro's default setting for group usage is AsVisualGroupingMechanism which is what this situation is all about: we group the elements for visual purposes, it has no real meaning for the model nor the code generated. Let's reverse engineer AdventureWorks to an entity model. By default, LLBLGen Pro uses the target schema an element is in which is being reverse engineered, as the group it will be in. This is convenient if you already have categorized tables/views in schemas, like which is the case in AdventureWorks. Of course this can be switched off, or corrected on the fly. When reverse engineering, we'll walk through a wizard which will guide us with the selection of the elements which relational model data should be retrieved, which we can later on use to reverse engineer to an entity model. The first step after specifying which database server connect to is to select these elements. below we can see the AdventureWorks catalog as well as the different schemas it contains. We'll include all of them. After the wizard completes, we have all relational model data nicely in our catalog data, with schemas. So let's reverse engineer entities from the tables in these schemas. We select in the catalog explorer the schemas 'HumanResources', 'Person', 'Production', 'Purchasing' and 'Sales', then right-click one of them and from the context menu, we select Reverse engineer Tables to Entity Definitions.... This will bring up the dialog below. We check all checkboxes in one go by checking the checkbox at the top to mark them all to be added to the project. As you can see LLBLGen Pro has already filled in the group name based on the schema name, as this is the default and we didn't change the setting. If you want, you can select multiple rows at once and set the group name to something else using the controls on the dialog. We're fine with the group names chosen so we'll simply click Add to Project. This gives the following result:   (I collapsed the other groups to keep the picture small ;)). As you can see, the entities are now grouped. Just to see how dense this model is, I've expanded the relationships of Employee: As you can see, it has relationships with entities from three other groups than HumanResources. It's not doable to cut up this project into sub-models without duplicating the Employee entity in all those groups, so this model is better suited to be used as a single model resulting in a single code base, however it benefits greatly from having its entities grouped into separate groups at the project level, to make work done on the model easier. Now let's look at another situation, namely where we work with a single database while we want to have multiple models and for each model a separate code base. Situation two: grouping entities in separate models within the same project. To get rid of the entities to see the second situation in action, simply undo the reverse engineering action in the project. We still have the AdventureWorks relational model data in the catalog. To switch LLBLGen Pro to see each group in the project as a separate project, open the Project Settings, navigate to General and set Group usage to AsSeparateProjects. In the catalog explorer, select Person and Production, right-click them and select again Reverse engineer Tables to Entities.... Again check the checkbox at the top to mark all entities to be added and click Add to Project. We get two groups, as expected, however this time the groups are seen as separate projects. This means that the validation logic inside LLBLGen Pro will see it as an error if there's e.g. a relationship or an inheritance edge linking two groups together, as that would lead to a cyclic reference in the code bases. To see this variant of the grouping feature, seeing the groups as separate projects, in action, we'll generate code from the project with the two groups we just created: select from the main menu: Project -> Generate Source-code... (or press F7 ;)). In the dialog popping up, select the target .NET framework you want to use, the template preset, fill in a destination folder and click Start Generator (normal). This will start the code generator process. As expected the code generator has simply generated two code bases, one for Person and one for Production: The group name is used inside the namespace for the different elements. This allows you to add both code bases to a single solution and use them together in a different project without problems. Below is a snippet from the code file of a generated entity class. //... using System.Xml.Serialization; using AdventureWorks.Person; using AdventureWorks.Person.HelperClasses; using AdventureWorks.Person.FactoryClasses; using AdventureWorks.Person.RelationClasses; using SD.LLBLGen.Pro.ORMSupportClasses; namespace AdventureWorks.Person.EntityClasses { //... /// <summary>Entity class which represents the entity 'Address'.<br/><br/></summary> [Serializable] public partial class AddressEntity : CommonEntityBase //... The advantage of this is that you can have two code bases and work with them separately, yet have a single target database and maintain everything in a single location. If you decide to move to a single code base, you can do so with a change of one setting. It's also useful if you want to keep the groups as separate models (and code bases) yet want to add relationships to elements from another group using a copy of the entity: you can simply reverse engineer the target table to a new entity into a different group, effectively making a copy of the entity. As there's a single target database, changes made to that database are reflected in both models which makes maintenance easier than when you'd have a separate project for each group, with its own relational model data. Conclusion LLBLGen Pro offers a flexible way to work with entities in sub-models and control how the sub-models end up in the generated code.

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  • Are Ruby on Rails / Grails the fastest frameworks for getting sites up quickly?

    - by Jon
    I'm considering using Grails for a new website, but am open to other/new programming languages and frameworks. I have done development using J2EE/JSF2, ASP.NET, and PHP. Is Grails or Ruby on Rails pretty much the best way to get functionality up and running quickly? Some initial thoughts: DJango looks similar to RoR/Grails and I'd consider it GWT is an interesting concept but it doesn't seem like turnaround time is quite as fast Thanks, -Jon

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  • Is it possible to make/translate a 3d engine to ruby on rails?

    - by user20529
    I am looking to make a 3D FPS that runs inside web browsers. I looked into using WebGL, but it didn't seem far enough along into development. I decided on using RoR because Ruby was a language I knew. I realize this may seem like a ridiculous question, but is there any way I can port/rewrite/whatever a game engine(Say for instance IrrLicht) to run inside Rails? Or for that matter, any other language on the web.

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  • Le kit du bon développeur Rails, partie 3. Par l'équipe de Synbioz

    Dernière partie de notre série d'articles sur les gems à connaitre par un développeur Rails. Dans le premier article, nous nous étions attardés sur l'authentification, la recherche et la pagination. Dans la deuxième partie, ce fut au tour de l'internationalisation et de la gestion de fichiers. Dans ce dernier article, les gems concernant les tests et la gestion des tâches annexes seront à leur tour abordées.

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  • How do I add a trailing slash for Django MPTT-based categorization app?

    - by Patrick Beeson
    I'm using Django-MPTT to develop a categorization app for my Django project. But I can't seem to get the regex pattern for adding a trailing slash that doesn't also break on child categories. Here's an example URL: http://mydjangoapp.com/categories/parentcat/childcat/ I'd like to be able to use http://mydjangoapp.com/categories/parentcat and have it redirect to the trailing slash version. The same should apply to http://mydjangoapp.com/categories/parentcat/childcat (it should redirect to http://mydjangoapp.com/categories/parentcat/childcat/). Here's my urls.py: from django.conf.urls.defaults import patterns, include, url from django.views.decorators.cache import cache_page from storefront.categories.models import Category from storefront.categories.views import SimpleCategoryView urlpatterns = patterns('', url(r'^(?P<full_slug>[-\w/]+)', cache_page(SimpleCategoryView.as_view(), 60 * 15), name='category_view'), ) And here is my view: from django.core.exceptions import ImproperlyConfigured from django.core.urlresolvers import reverse from django.views.generic import TemplateView, DetailView from django.views.generic.detail import SingleObjectTemplateResponseMixin, SingleObjectMixin from django.utils.translation import ugettext as _ from django.contrib.syndication.views import Feed from storefront.categories.models import Category class SimpleCategoryView(TemplateView): def get_category(self): return Category.objects.get(full_slug=self.kwargs['full_slug']) def get_context_data(self, **kwargs): context = super(SimpleCategoryView, self).get_context_data(**kwargs) context["category"] = self.get_category() return context def get_template_names(self): if self.get_category().template_name: return [self.get_category().template_name] else: return ['categories/category_detail.html'] And finally, my model: from django.db import models from mptt.models import MPTTModel from mptt.fields import TreeForeignKey class CategoryManager(models.Manager): def get(self, **kwargs): defaults = {} defaults.update(kwargs) if 'full_slug' in defaults: if defaults['full_slug'] and defaults['full_slug'][-1] != "/": defaults['full_slug'] += "/" return super(CategoryManager, self).get(**defaults) class Category(MPTTModel): title = models.CharField(max_length=255) description = models.TextField(blank=True, help_text='Please use <a href="http://daringfireball.net/projects/markdown/syntax">Markdown syntax</a> for all text-formatting and links. No HTML is allowed.') slug = models.SlugField(help_text='Prepopulates from title field.') full_slug = models.CharField(max_length=255, blank=True) template_name = models.CharField(max_length=70, blank=True, help_text="Example: 'categories/category_parent.html'. If this isn't provided, the system will use 'categories/category_detail.html'. Use 'categories/category_parent.html' for all parent categories and 'categories/category_child.html' for all child categories.") parent = TreeForeignKey('self', null=True, blank=True, related_name='children') objects = CategoryManager() class Meta: verbose_name = 'category' verbose_name_plural = 'categories' def save(self, *args, **kwargs): orig_full_slug = self.full_slug if self.parent: self.full_slug = "%s%s/" % (self.parent.full_slug, self.slug) else: self.full_slug = "%s/" % self.slug obj = super(Category, self).save(*args, **kwargs) if orig_full_slug != self.full_slug: for child in self.get_children(): child.save() return obj def available_product_set(self): """ Returns available, prioritized products for a category """ from storefront.apparel.models import Product return self.product_set.filter(is_available=True).order_by('-priority') def __unicode__(self): return "%s (%s)" % (self.title, self.full_slug) def get_absolute_url(self): return '/categories/%s' % (self.full_slug)

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  • How do you clean Core Data generated models and code from a project?

    - by Hazmit
    I'm having an extremely annoying problem with Core Data in the iPhone SDK. I would say in general Core Data for the most part appears easy to use and nice to implement. I have a sqlite database that is being used as a read only reference to pull data elements out for an iPhone app. It would seem there are really mysterious issues relating to what seems to be migration of the database to the most recent versions of my schema. Why can't you just clean out your stored objects and models and let a project redo all of it when you compile next? You would think if you setup a stored object model there would be a way to just reset it and recompile. I've tried what feels like a thousand 'tips' that have been the results of hours of google searches and documentation prowling to figure out how to do this. My most recent error during compile time is below. 2010-04-07 18:23:51.891 PE[1962:207] * Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Can't merge models with two different entities named 'PElement'' All of this code has been working in the simulator and is only causing me troubles now because I made a change to the schema. I also have the database options for automatically migrating set as below. NSMutableDictionary *optionsDictionary = [NSMutableDictionary dictionary]; [optionsDictionary setObject:[NSNumber numberWithBool:YES] forKey:NSMigratePersistentStoresAutomaticallyOption]; [optionsDictionary setObject:[NSNumber numberWithBool:YES] forKey:NSInferMappingModelAutomaticallyOption];

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  • model not showing up in django admin.

    - by Zayatzz
    Hi. I have ceated several django apps and stuffs for my own fund and so far everything has been working fine. Now i just created new project (django 1.2.1) and have run into trouble from 1st moments. I created new app - game and new model Game. i created admin.py and put related stuff into it. Ran syncdb and went to check into admin. Model did not show up there. I proceeded to check and doublecheck and read through previous similar threads: http://stackoverflow.com/questions/1839927/registered-models-do-not-show-up-in-admin http://stackoverflow.com/questions/1694259/django-app-not-showing-up-in-admin-interface But as far as i can tell, they dont help me either. Perhaps someone else can point this out for me. models.py in game app: # -*- coding: utf-8 -*- from django.db import models class Game(models.Model): type = models.IntegerField(blank=False, null=False, default=1) teamone = models.CharField(max_length=100, blank=False, null=False) teamtwo = models.CharField(max_length=100, blank=False, null=False) gametime = models.DateTimeField(blank=False, null=False) admin.py in game app: # -*- coding: utf-8 -*- from jalka.game.models import Game from django.contrib import admin class GameAdmin(admin.ModelAdmin): list_display = ['type', 'teamone', 'teamtwo', 'gametime'] admin.site.register(Game, GameAdmin) project settings.py: MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.middleware.csrf.CsrfViewMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.contrib.messages.middleware.MessageMiddleware', ) ROOT_URLCONF = 'jalka.urls' TEMPLATE_DIRS = ( "/home/projects/jalka/templates/" ) INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.messages', 'django.contrib.admin', 'game', ) urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Example: # (r'^jalka/', include('jalka.foo.urls')), (r'^admin/', include(admin.site.urls)), ) Alan.

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  • Limit foreign key choices in select in an inline form in admin

    - by mightyhal
    Edited :-) Hopefully a bit clearer now. The logic is of the model is: A Building has many Rooms A Room may be inside another Room (a closet, for instance--ForeignKey on 'self') A Room can only in inside of another Room in the same building (this is the tricky part) Here's the code I have: #spaces/models.py from django.db import models class Building(models.Model): name=models.CharField(max_length=32) def __unicode__(self): return self.name class Room(models.Model): number=models.CharField(max_length=8) building=models.ForeignKey(Building) inside_room=models.ForeignKey('self',blank=True,null=True) def __unicode__(self): return self.number and: #spaces/admin.py from ex.spaces.models import Building, Room from django.contrib import admin class RoomAdmin(admin.ModelAdmin): pass class RoomInline(admin.TabularInline): model = Room extra = 2 class BuildingAdmin(admin.ModelAdmin): inlines=[RoomInline] admin.site.register(Building, BuildingAdmin) admin.site.register(Room) The inline will display only rooms in the current building (which is what I want). The problem, though, is that for the inside_room drop down, it displays all of the rooms in the Rooms table (including those in other buildings). In the inline of rooms, I need to limit the inside_room choices to only rooms which are in the current building being displayed by the main form. I can't figure out a way to do it with either a limit_choices_to in the model, nor can I figure out how exactly to override the admin's inline formset properly (I feel like I should be somehow create a custom inline form, pass the building_id of the main form to the custom inline, then limit the queryset for the field's choices based on that--but I just can't wrap my head around how to do it). Maybe this is too complex for the admin site, but it seems like something that would be generally useful... Thanks again for your help!

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  • UIActivityIndicator on UITableViewCell not displaying while calling a webService

    - by Yoyi Cheika
    Hi coders, I guess my problem is very simple to solve but I haven been able to do so. Here is my problem: I have a custom table view cell that contains a UIActivityIndicator. When a cell is selected I push another view but this second view makes a call to a web service to bring data. Here is my code // Override to support row selection in the table view. - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { // Navigation logic may go here -- for example, create and push another view controller. // AnotherViewController *anotherViewController = [[AnotherViewController alloc] initWithNibName:@"AnotherView" bundle:nil]; // [self.navigationController pushViewController:anotherViewController animated:YES]; // [anotherViewController release]; Models *models = [[Models alloc] initWithNibName:@"Models" bundle:nil]; models.make = ((MakeCell *)[tableView cellForRowAtIndexPath:indexPath]).make.text; models.year = (int)[self.yearLabel.text doubleValue]; models.logo = [makeLogosName objectAtIndex:indexPath.row]; [((MakeCell *)[tableView cellForRowAtIndexPath:indexPath]).activityIndicator startAnimating]; [self.navigationController pushViewController:models animated:YES]; [((MakeCell *)[tableView cellForRowAtIndexPath:indexPath]).activityIndicator stopAnimating]; [models release]; } Where MakeCell is my custom cell. If I comment this line [((MakeCell *)[tableView cellForRowAtIndexPath:indexPath]).activityIndicator stopAnimating]; then the indicator appears as expected when going back to the previous view. I feel like the indicator is not being visually updated until the didSelectRowAtIndexPath returns. Does is works ascyncronically. What can be my problem here. Thank you very much Cheika

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  • Moses v1.0 multi language ini file

    - by Milan Kocic
    I was working with mosesserver 0.91 and everything works fine but now there is version 1.0 and nothing is same as before. Here is my situation: I want to have multi language translation from arabic to english and from english to arabic. All data and configuration file I have works with 0.91 version of mosesserver. Here is my config file: ------------------------------------------------- ######################### ### MOSES CONFIG FILE ### ######################### # D - decoding path, R - reordering model, L - language model [translation-systems] ar-en D 0 R 0 L 0 en-ar D 1 R 1 L 1 # input factors [input-factors] 0 # mapping steps [mapping] 0 T 0 1 T 1 # translation tables: table type (hierarchical(0), textual (0), binary (1)), source-factors, target-factors, number of scores, file # OLD FORMAT is still handled for back-compatibility # OLD FORMAT translation tables: source-factors, target-factors, number of scores, file # OLD FORMAT a binary table type (1) is assumed [ttable-file] 1 0 0 5 /mnt/models/ar-en/phrase-table/phrase-table 1 0 0 5 /mnt/models/en-ar/phrase-table/phrase-table # no generation models, no generation-file section # language models: type(srilm/irstlm), factors, order, file [lmodel-file] 1 0 5 /mnt/models/ar-en/language-model/en.qblm.mm 1 0 5 /mnt/models/en-ar/language-model/ar.lm.d1.blm.mm # limit on how many phrase translations e for each phrase f are loaded # 0 = all elements loaded [ttable-limit] 20 # distortion (reordering) files [distortion-file] 0-0 wbe-msd-bidirectional-fe-allff 6 /mnt/models/ar-en/reordering-table/reordering-table.wbe-msd-bidirectional-fe.gz 0-0 wbe-msd-bidirectional-fe-allff 6 /mnt/models/en-ar/reordering-model/reordering-table.wbe-msd-bidirectional-fe.gz # distortion (reordering) weight [weight-d] 0.3 0.3 # lexicalised distortion weights [weight-lr] 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 # language model weights [weight-l] 0.5000 0.5000 # translation model weights [weight-t] 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 # no generation models, no weight-generation section # word penalty [weight-w] -1 -1 [distortion-limit] 12 --------------------------------------------------------- So please can someone help me and rewrite this config file so it can work in version 1.0. And i need some python sample code of translation. I am using xmlrpc in python and earler I sent http request with: import xmlrpclib client = xmlrpclib.ServerProxy('http://localhost:8080') client.translate({'text': 'some text', 'system': 'en-ar'}) but now seems there is no more 'system' parameter and moses use always default settings.

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