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  • MongoMapper won't let me create an object

    - by Jade
    I'm just learning MongoDB and MongoMapper. This is on Rails 3. I created a blog in app/models/blog.rb: class Blog include MongoMapper::Document key :title, String, :required => true key :body, Text timestamps! end I go into the Rails console: rails c Loading development environment (Rails 3.0.0.beta) ruby-1.9.1-p378 > **b = Blog.new** NoMethodError: undefined method `from_mongo' for Text:Module from /Users/jade/.rvm/gems/ruby-1.9.1-p378/gems/mongo_mapper-0.7.2/lib/mongo_mapper/plugins/keys.rb:323:in `get' from /Users/jade/.rvm/gems/ruby-1.9.1-p378/gems/mongo_mapper-0.7.2/lib/mongo_mapper/plugins/keys.rb:269:in `read_key' from /Users/jade/.rvm/gems/ruby-1.9.1-p378/gems/mongo_mapper-0.7.2/lib/mongo_mapper/plugins/keys.rb:224:in `[]' from /Users/jade/.rvm/gems/ruby-1.9.1-p378/gems/mongo_mapper-0.7.2/lib/mongo_mapper/plugins/inspect.rb:7:in `block in inspect' from /Users/jade/.rvm/gems/ruby-1.9.1-p378/gems/mongo_mapper-0.7.2/lib/mongo_mapper/plugins/inspect.rb:6:in `collect' from /Users/jade/.rvm/gems/ruby-1.9.1-p378/gems/mongo_mapper-0.7.2/lib/mongo_mapper/plugins/inspect.rb:6:in `inspect' from /Users/jade/.rvm/gems/ruby-1.9.1-p378/gems/railties-3.0.0.beta/lib/rails/commands/console.rb:47:in `start' from /Users/jade/.rvm/gems/ruby-1.9.1-p378/gems/railties-3.0.0.beta/lib/rails/commands/console.rb:8:in `start' from /Users/jade/.rvm/gems/ruby-1.9.1-p378/gems/railties-3.0.0.beta/lib/rails/commands.rb:34:in `<top (required)>' from /Users/jade/code/farmerjade/script/rails:10:in `require' from /Users/jade/code/farmerjade/script/rails:10:in `<main>' Am I overlooking something really dumb, or is this something in my setup? I'm using the mongo_mapper version you get by adding it to your Gemfile, so I'm wondering if it might be that. I'd appreciate any suggestions!

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  • Using Zend Framework and Doctrine with independend modular structures

    - by stefax
    I've seen a lot of articles about integrating ZF and Doctrine. There is also a proposal for ZF here but they have always two possible structures. Either they put all models into one top level model directory or they put it into a module related model directory. application |-- Bootstrap.php |-- configs |-- controllers |-- models - EITHER HERE |-- modules | -- examplemodule | |-- controllers | |-- models - OR HERE | |-- views |-- views For our projects I see problems for either of the two options: 1. One directory: application/models - in a complex system after a short time there will be hundreds of files, over all when you have the table classes two (e.g. User.php and UserTable.php). 2. Module based model directories: application/modules/examplemodule/models - in many cases we use models in multiple modules at the same time. So the "User" is required e.g. in the modules "game", "administration", ... Is there a way to use some kind of sub directories under the top level directory "models" to get some grouping. It should be completely independent of the module structure. application |-- Bootstrap.php ... |-- models | -- user | |-- User.php | |-- Friend.php | |-- other user related models | -- game | |-- Game.php | |-- Score.php | |-- ... ... Any solution should support autoloading and the class generation from yaml files. Any ideas, links or solutions? Thanks!

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  • Error while trying to install Community Engine: NameError - "Undefined local variable or method 'map

    - by floatingfrisbee
    I'm trying to install Community Engine using the instructions here: http://github.com/bborn/communityengine At first I thought it might be because I had Rails 2.3.5 and desert 0.5.3 which were higher versions than what was mentioned on the installation site. However moving to rails 2.3.4 and desert 0.5.2 did not work. Any ideas as to what might be going on? $ script/generate plugin_migration /usr/lib/ruby/gems/1.8/gems/rails-2.3.4/lib/rails/gem_dependency.rb:119:Warning: Gem::Dependency#version_requirements is deprecat ed and will be removed on or after August 2010. Use #requirement /cygdrive/c/users/me/jesse/projects/ceng1/config/routes.rb:2: undefined local variable or method `map' for main:Object (NameError ) from /usr/lib/ruby/gems/1.8/gems/activesupport-2.3.4/lib/active_support/dependencies.rb:147:in `load_without_new_constant _marking' from /usr/lib/ruby/gems/1.8/gems/activesupport-2.3.4/lib/active_support/dependencies.rb:147:in `load_without_desert' from /usr/lib/ruby/gems/1.8/gems/desert-0.5.2/lib/desert/ruby/object.rb:18:in `load' from /usr/lib/ruby/gems/1.8/gems/desert-0.5.2/lib/desert/ruby/object.rb:32:in `__each_matching_file' from /usr/lib/ruby/gems/1.8/gems/desert-0.5.2/lib/desert/ruby/object.rb:17:in `load' from /usr/lib/ruby/gems/1.8/gems/actionpack-2.3.4/lib/action_controller/routing/route_set.rb:286:in `load_routes!' from /usr/lib/ruby/gems/1.8/gems/actionpack-2.3.4/lib/action_controller/routing/route_set.rb:286:in `each' from /usr/lib/ruby/gems/1.8/gems/actionpack-2.3.4/lib/action_controller/routing/route_set.rb:286:in `load_routes!' from /usr/lib/ruby/gems/1.8/gems/actionpack-2.3.4/lib/action_controller/routing/route_set.rb:266:in `reload!' from /usr/lib/ruby/gems/1.8/gems/rails-2.3.4/lib/initializer.rb:537:in `initialize_routing' from /usr/lib/ruby/gems/1.8/gems/rails-2.3.4/lib/initializer.rb:188:in `process' from /usr/lib/ruby/gems/1.8/gems/rails-2.3.4/lib/initializer.rb:113:in `send' from /usr/lib/ruby/gems/1.8/gems/rails-2.3.4/lib/initializer.rb:113:in `run' from /cygdrive/c/users/me/jesse/projects/ceng1/config/environment.rb:6 from /usr/lib/ruby/site_ruby/1.8/rubygems/custom_require.rb:31:in `gem_original_require' from /usr/lib/ruby/site_ruby/1.8/rubygems/custom_require.rb:31:in `require' from /usr/lib/ruby/gems/1.8/gems/rails-2.3.4/lib/commands/generate.rb:1 from /usr/lib/ruby/site_ruby/1.8/rubygems/custom_require.rb:31:in `gem_original_require' from /usr/lib/ruby/site_ruby/1.8/rubygems/custom_require.rb:31:in `require' from script/generate:3

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  • how to handle multiple profiles per user?

    - by Scott Willman
    I'm doing something that doesn't feel very efficient. From my code below, you can probably see that I'm trying to allow for multiple profiles of different types attached to my custom user object (Person). One of those profiles will be considered a default and should have an accessor from the Person class. Can this be done better? from django.db import models from django.contrib.auth.models import User, UserManager class Person(User): public_name = models.CharField(max_length=24, default="Mr. T") objects = UserManager() def save(self): self.set_password(self.password) super(Person, self).save() def _getDefaultProfile(self): def_teacher = self.teacher_set.filter(default=True) if def_teacher: return def_teacher[0] def_student = self.student_set.filter(default=True) if def_student: return def_student[0] def_parent = self.parent_set.filter(default=True) if def_parent: return def_parent[0] return False profile = property(_getDefaultProfile) def _getProfiles(self): # Inefficient use of QuerySet here. Tolerated because the QuerySets should be very small. profiles = [] if self.teacher_set.count(): profiles.append(list(self.teacher_set.all())) if self.student_set.count(): profiles.append(list(self.student_set.all())) if self.parent_set.count(): profiles.append(list(self.parent_set.all())) return profiles profiles = property(_getProfiles) class BaseProfile(models.Model): person = models.ForeignKey(Person) is_default = models.BooleanField(default=False) class Meta: abstract = True class Teacher(BaseProfile): user_type = models.CharField(max_length=7, default="teacher") class Student(BaseProfile): user_type = models.CharField(max_length=7, default="student") class Parent(BaseProfile): user_type = models.CharField(max_length=7, default="parent")

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  • Django: Save data from form in DB

    - by Anry
    I have a model: class Cost(models.Model): project = models.ForeignKey(Project) cost = models.FloatField() date = models.DateField() For the model I created a class form: class CostForm(ModelForm): class Meta: model = Cost fields = ['date', 'cost'] view.py: def cost(request, offset): if request.method == 'POST': #HOW save data in DB? return HttpResponseRedirect('/') else: form = CostForm() In the template file determined: <form action="/cost/{{ project }}/" method="post" accept-charset="utf-8"> <label for="date">Date:</label><input type="text" name="date" value={{ current_date }} id="date" /> <label for="cost">Cost:</label><input type="text" name="cost" value="0" id="cost" /> <p><input type="submit" value="Add"></p> </form> How save data from form in DB? P.S. offset = project name Model: class Project(models.Model): title = models.CharField(max_length=150) url = models.URLField() manager = models.ForeignKey(User) timestamp = models.DateTimeField() I tried to write: def cost(request, offset): if request.method == 'POST': form = CostForm(request.POST) if form.is_valid(): instance = form.save(commit=False) instance.project = Project.objects.filter(title=offset) instance.date = request.date instance.cost = request.cost instance.save() return HttpResponseRedirect('/') else: form = CostForm() But it does not work :(

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  • Django ManyToMany Membership errors making associations

    - by jmitchel3
    I'm trying to have a "member admin" in which they have hundreds of members in the group. These members can be in several groups. Admins can remove access for the member ideally in the view. I'm having trouble just creating the group. I used a ManytoManyField to get started. Ideally, the "member admin" would be able to either select existing Users OR it would be able to Add/Invite new ones via email address. Here's what I have: #views.py def membership(request): group = Group.objects.all().filter(user=request.user) GroupFormSet = modelformset_factory(Group, form=MembershipForm) if request.method == 'POST': formset = GroupFormSet(request.POST, request.FILES, queryset=group) if formset.is_valid(): formset.save(commit=False) for form in formset: form.instance.user = request.user formset.save() return render_to_response('formset.html', locals(), context_instance=RequestContext(request)) else: formset= GroupFormSet(queryset=group) return render_to_response('formset.html', locals(), context_instance=RequestContext(request)) #models.py class Group(models.Model): name = models.CharField(max_length=128) members = models.ManyToManyField(User, related_name='community_members', through='Membership') user = models.ForeignKey(User, related_name='community_creator', null=True) def __unicode__(self): return self.name class Membership(models.Model): member = models.ForeignKey(User, related_name='user_membership', blank=True, null=True) group = models.ForeignKey(Group, related_name='community_membership', blank=True, null=True) date_joined = models.DateField(auto_now=True, blank=True, null=True) class Meta: unique_together = ('member', 'group') Any ideas? Thank you for your help.

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  • Rebuilding old (2010) django project in 2012

    - by birgit
    I am trying to make an old Django project run again. After seemingly having solved issues with old sorl.thumbnail versions and deprecated expressions I now get this error when running python manage.py runserver I also tried to copy & paste my old files into a new Django project and get the exactly same error. Maybe someone here has a clue where the problem lies? Unhandled exception in thread started by <bound method Command.inner_run of <django.contrib.staticfiles.management.commands.runserver.Command object at 0x2a80510>> Traceback (most recent call last): File "/usr/lib/python2.7/dist-packages/django/core/management/commands/runserver.py", line 88, in inner_run self.validate(display_num_errors=True) File "/usr/lib/python2.7/dist-packages/django/core/management/base.py", line 249, in validate num_errors = get_validation_errors(s, app) File "/usr/lib/python2.7/dist-packages/django/core/management/validation.py", line 35, in get_validation_errors for (app_name, error) in get_app_errors().items(): File "/usr/lib/python2.7/dist-packages/django/db/models/loading.py", line 146, in get_app_errors self._populate() File "/usr/lib/python2.7/dist-packages/django/db/models/loading.py", line 61, in _populate self.load_app(app_name, True) File "/usr/lib/python2.7/dist-packages/django/db/models/loading.py", line 78, in load_app models = import_module('.models', app_name) File "/usr/lib/python2.7/dist-packages/django/utils/importlib.py", line 35, in import_module __import__(name) File "/home/me/Documents/wdws/wdws/../wdws/cityofwindows/models.py", line 73, in <module> class Image(models.Model): File "/home/me/Documents/wdws/wdws/../wdws/cityofwindows/models.py", line 83, in Image 'large': {'size': (640, 640)}, File "/usr/lib/python2.7/dist-packages/django/db/models/fields/files.py", line 233, in __init__ super(FileField, self).__init__(verbose_name, name, **kwargs) TypeError: __init__() got an unexpected keyword argument 'extra_thumbnails' I need to re-build the project just for visual documentation locally... so also any hints on how to quickly re-run outdated django-projects are very welcome!! Thanks a lot (using Ubuntu 12.04)

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  • Skip subdirectory in python import

    - by jstaab
    Ok, so I'm trying to change this: app/ - lib.py - models.py - blah.py Into this: app/ - __init__.py - lib.py - models/ - __init__.py - user.py - account.py - banana.py - blah.py And still be able to import my models using from app.models import User rather than having to change it to from app.models.user import User all over the place. Basically, I want everything to treat the package as a single module, but be able to navigate the code in separate files for development ease. The reason I can't do something like add for file in __all__: from file import * into init.py is I have circular references between the model files. A fix I don't want is to import those models from within the functions that use them. But that's super ugly. Let me give you an example: user.py ... from app.models import Banana ... banana.py ... from app.models import User ... I wrote a quick pre-processing script that grabs all the files, re-writes them to put imports at the top, and puts it into models.py, but that's hardly an improvement, since now my stack traces don't show the line number I actually need to change. Any ideas? I always though init was probably magical but now that I dig into it, I can't find anything that lets me provide myself this really simple convenience.

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  • O&rsquo;Reilly E-Book of the Day 15/Aug/2014 - Advanced Quantitative Finance with C++

    - by TATWORTH
    Originally posted on: http://geekswithblogs.net/TATWORTH/archive/2014/08/15/orsquoreilly-e-book-of-the-day-15aug2014---advanced-quantitative-finance.aspxToday’s half-price book of the Day offer from O’Reilly at http://shop.oreilly.com/product/9781782167228.do?code=MSDEAL is Advanced Quantitative Finance with C++. “This book will introduce you to the key mathematical models used to price financial derivatives, as well as the implementation of main numerical models used to solve them. In particular, equity, currency, interest rates, and credit derivatives are discussed. In the first part of the book, the main mathematical models used in the world of financial derivatives are discussed. Next, the numerical methods used to solve the mathematical models are presented. Finally, both the mathematical models and the numerical methods are used to solve some concrete problems in equity, forex, interest rate, and credit derivatives.”

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  • In Magento, is it possible to populate your product models from an external API instead of the Magento DB?

    - by James Pelton
    I currently have Magento 1.7 CE installed. I want to use the Magento Product Models, except I want to get the price for the product from an external API (our pricing exists outside of Magento). I know what I could use the Magento API to import all the prices from our existing database, but our pricing changes very often, and we would then need to maintain two databases. Basically I'm wondering if there is something in Magento I can overwrite to call our API instead of the DB?

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  • is it possible to store server returned json data in jqgrid to display columnnames models data dynamically for every request?

    - by user1768246
    is it possible to store server returned json data in jqgrid to display columnnames models data dynamically for every request ? $("#grid").jqGrid({ type: "GET", url: "", var columnNames = $("#grid")[0].p.colNames, var columnModel = $("#grid")[0].p.colNames, var columnData = $("#grid")[0].p.colNames, datatype: 'jsonstring', datastr: columnData, colModel: columnModel, jsonReader: { root: 'innerWrapper.rows', page: "result.gridData.outerWrapper.page", total: "result.gridData.outerWrapper.total", records: "result.gridData.outerWrapper.total", repeatitems: false, }, gridview: true, pager: "pager", height: "auto", rowNum: 10, width:"auto", height:"auto", rowList: [10, 20, 30,40], viewrecords: true, caption:"Graph Data", rownumbers: true, });

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  • Error running heroku console. can't update heroku

    - by Omnipresent
    When I try to run heroku console I get the following error: user@omnipresent:~/rails/demo$ heroku console ! This version of the heroku gem has been deprecated. ! Please update it by running: gem update heroku When I do the update..it says there is nothing to update! user@omnipresent:~/rails/demo$ gem update heroku Updating installed gems Nothing to update Following are my versions: user@omnipresent:~/rails/demo$ heroku version heroku-gem/1.5.2 user@omnipresent:~/rails/demo$ ruby -v ruby 1.9.1p0 (2009-01-30 revision 21907) [i686-linux] user@omnipresent:~/rails/demo$ rails -v Rails 2.3.5

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  • Unicode issue in Django

    - by Kave
    I seem to have a unicode problem with the deal_instance_name in the Deal model. It says: coercing to Unicode: need string or buffer, __proxy__ found The exception happens on this line: return smart_unicode(self.deal_type.deal_name) + _(u' - Set No.') + str(self.set) The line works if I remove smart_unicode(self.deal_type.deal_name) but why? Back then in Django 1.1 someone had the same problem on Stackoverflow I have tried both the unicode() as well as the new smart_unicode() without any joy. What could I be missing please? class Deal(models.Model): def __init__(self, *args, **kwargs): super(Deal, self).__init__(*args, **kwargs) self.deal_instance_name = self.__unicode__() deal_type = models.ForeignKey(DealType) deal_instance_name = models.CharField(_(u'Deal Name'), max_length=100) set = models.IntegerField(_(u'Set Number')) def __unicode__(self): return smart_unicode(self.deal_type.deal_name) + _(u' - Set No.') + str(self.set) class Meta: verbose_name = _(u'Deal') verbose_name_plural = _(u'Deals') Dealtype: class DealType(models.Model): deal_name = models.CharField(_(u'Deal Name'), max_length=40) deal_description = models.TextField(_(u'Deal Description'), blank=True) def __unicode__(self): return smart_unicode(self.deal_name) class Meta: verbose_name = _(u'Deal Type') verbose_name_plural = _(u'Deal Types')

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  • How do I flag only one of the formsets in django admin?

    - by azuer88
    I have these (simplified) models: class Question(models.Model): question = models.CharField(max_length=60) class Choices(models.Model): question = models.ForeignKey(Question) text = models.CharField(max_length=60) is_correct = models.BooleanField(default=False) I've made Choices as an inline of Question (in admin). Is there a way to make sure that only one Choice will have is_correct = True? Ideally, is_correct will be displayed as a radio button when it is displayed in the admin formset (TabularInline). my admin.py has: from django.contrib import admin class OptionInline(admin.TabularInline): model = Option extra = 5 max_num = 5 class QuestionAdmin(admin.ModelAdmin): inlines = [OptionInline, ] admin.site.register(QType) admin.site.register(Question, QuestionAdmin)

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  • How do I flag only one of the formsets in django admin ?

    - by azuer88
    I have these (simplified) models: class Question(models.Model): question = models.CharField(max_length=60) class Choices(models.Model): question = models.ForeignKey(Question) text = models.CharField(max_length=60) is_correct = models.BooleanField(default=False) I've made Choices as an inline of Question (in admin). Is there a way to make sure that only one Choice will have is_correct = True? Ideally, is_correct will be displayed as a radio button when it is displayed in the admin formset (TabularInline). My first solution was to override the validation of the formset but did understand how to do this. (is_correct is displayed as checkbox, and I'd display an error that only one is_correct should be selected.)

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  • Django and conditional aggregates

    - by piquadrat
    I have two models, authors and articles: class Author(models.Model): name = models.CharField('name', max_length=100) class Article(models.Model) title = models.CharField('title', max_length=100) pubdate = models.DateTimeField('publication date') authors = models.ManyToManyField(Author) Now I want to select all authors and annotate them with their respective article count. That's a piece of cake with Django's aggregates. Problem is, it should only count the articles that are already published. According to ticket 11305 in the Django ticket tracker, this is not yet possible. I tried to use the CountIf annotation mentioned in that ticket, but it doesn't quote the datetime string and doesn't make all the joins it would need. So, what's the best solution, other than writing custom SQL?

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  • group inlines in django admin

    - by pablo
    Hi I have a two models, Model1 and Model2. Model2 has a FK to Model1 and FK to iteself. In the admin I show Model2 as inlines in Model1 change_form. I want to modify the way the inlines are shown in the admin. I need to group all the instances that have the same parent_model2 and display them as a readonly field with a string of 'childs' in the parent Model2 instance. I know how to use itertools.groupby (or the django version) but don't know how to do it in the admin. What should I override to be able to iterate over all the Model2 instances, group them by parent, add children to the parent and remove children from the inlines? class Model1(models.Model): name = models.CharField() class Model2(models.Model): name = models.CharField() fk_model1 = models.ForeignKey('self', blank=True, null=True) parent_model2 = models.ForeignKey('self', blank=True, null=True) Thanks

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  • Editting ForeignKey from "child" table

    - by profuel
    I'm programming on py with django. I have models: class Product(mymodels.Base): title = models.CharField() price = models.ForeignKey(Price) promoPrice = models.ForeignKey(Price, related_name="promo_price") class Price(mymodels.Base): value = models.DecimalField(max_digits=10, decimal_places=3) taxValue = models.DecimalField("Tax Value", max_digits=10, decimal_places=3) valueWithTax = models.DecimalField("Value with Tax", max_digits=10, decimal_places=3) I want to see INPUTs for both prices when editing product, but cannot find any possibility to do that. inlines = [...] works only from Price to Product, which is stupid in this case. Thanx for adnvance.

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  • Django finding which field matched in a multiple OR query

    - by Greg Hinch
    I've got a couple models which are set up something like this: class Bar(models.Model): baz = models.CharField() class Foo(models.Model): bar1 = models.ForeignKey(Bar) bar2 = models.ForeignKey(Bar) bar3 = models.ForeignKey(Bar) And elsewhere in the code, I end up with an instance of Bar, and need to find the Foo it is attached to in some capacity. Right now I came up with doing a multiple OR query using Q, something like this: foo_inst = Foo.objects.get(Q(bar1=bar_inst) | Q(bar2=bar_inst) | Q(bar3=bar_inst)) What I need to figure out is, which of the 3 cases actually hit, at least the name of the member (bar1, bar2, or bar3). Is there a good way to do this? Is there a better way to structure the query to glean that information?

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