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• Changing JButton background colour temporarily?

  - by sashep

  Hi, I'm super new to Java, and in need of some help. I'm making a little java desktop application where I basically have a grid of 4 JButtons ( 2 x 2 grid), and I need the background colour of individual JButtons to change, and after one second, change back to the original colour (the game I'm trying to make is like Simon, where you have to follow a pattern of buttons that light up). I have a vector that contains randomly generated numbers in the range of 1 to 4, and I want to be able to get each element from the vector and get the corresponding button to change to a different colour for one second (for example, if the vector contains 2 4 1, I would want button 2 to change, then button 4 to change, then button 1 to change). Is this possible or is there a better way to go about doing this with something other than JButtons? How do I implement this? Also, I'm running Mac OS X, which apparently (based on some things I've read on forums) doesn't like JButtons background changing (I think it's because of system look and feel), how can I change this so it works on mac? Thank you in advance for any help :)

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• VB.NET invalid cast exception

  - by user127147

  Hi there, I have a simple application to store address details and edit them. I have been away from VB for a few years now and need to refreash my knowledge while working to a tight deadline. I have a general Sub responsible for displaying a form where user can add contact details (by pressing button add) and edit them (by pressing button edit). This sub is stored in a class Contact. The way it is supposed to work is that there is a list with all the contacts and when new contact is added a new entry is displayed. If user wants to edit given entry he or she selects it and presses edit button Public Sub Display() Dim C As New Contact C.Cont = InputBox("Enter a title for this contact.") C.Fname = frmAddCont.txtFName.Text C.Surname = frmAddCont.txtSName.Text C.Address = frmAddCont.txtAddress.Text frmStart.lstContact.Items.Add(C.Cont.ToString) End Sub I call it from the form responsible for adding new contacts by Dim C As New Contact C.Display() and it works just fine. However when I try to do something similar using the edit button I get errors - "Unable to cast object of type 'System.String' to type 'AddressBook.Contact'." Dim C As Contact If lstContact.SelectedItem IsNot Nothing Then C = lstContact.SelectedItem() C.Display() End If I think it may be something simple however I wasn't able to fix it and given short time I have I decided to ask for help here. Thank you

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• Sizers... - wxPython

  - by Francisco Aleixo

  Ok, so I'm learning about sizers in wxPython and I was wondering if it was possible to do something like: ============================================== |WINDOW TITLE _ [] X| |============================================| |xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx| |xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx| |xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx| |xxxxxxxxxxxxxxxxxxNOTEBOOKxxxxxxxxxxxxxxxxxx| |xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx| |xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx| |xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx| |________ ___________| |IMAGE | |LoginForm | |________| |___________| ============================================== NOTE:Yeah, I literally got this from http://stackoverflow.com/questions/1892110/wxpython-picking-the-right-sizer-to-use-in-an-application With NOTEBOOK expanded to left and bottom, IMAGE to align to left and bottom and loginform align to right and bottom and I managed to do almost everything but now I have a problem.. The problem is that I can't align Loginform and Image separately (im using Box Sizers), and I would like to. This is the code I'm using that is causing the problem at the moment, any help is appreciated. NOTE:The code might be (HUGELY) sloppy as I'm still learning box sizers. sizer = wx.BoxSizer(wx.VERTICAL) sizer1 = wx.BoxSizer(wx.HORIZONTAL) sizer1.Add(self.nb,1, wx.EXPAND) sizer.Add(sizer1,1, wx.LEFT | wx.RIGHT | wx.EXPAND, 10) sizer.Add((-1, 25)) sizer2 = wx.BoxSizer(wx.VERTICAL) sizer2.Add(self.userLabel, 0) sizer2.Add(self.userText, 0) sizer2.Add(self.pwdLabel, 0) sizer2.Add(self.pwdText, 0) sizer2.Add(self.rem, 0) sizer3 = wx.BoxSizer(wx.HORIZONTAL) sizer3.Add(self.login, 0) sizer3.Add(self.sair,0, wx.LEFT, 5) sizer2.Add(sizer3, 0) sizer4 = wx.BoxSizer(wx.HORIZONTAL) sizer4.Add(image, 1, wx.LEFT | wx.BOTTOM) sizer4.Add(sizer2,0, wx.RIGHT | wx.BOTTOM , 5) sizer.Add(sizer4,0, wx.ALIGN_RIGHT | wx.RIGHT, 10)

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• Problem after dismissing a modal view used in conjunction with a uisplitviewcontroller

  - by user336274

  I'm having a hard time understanding why the following is happening (and how to fix it). I've created an application using the split-view based application. I've added a UiBarButtonItem called showTheModal which calls this method found in RootViewController.m: - (IBAction)showTheModal:(id)sender { theModalController.modalPresentationStyle = UIModalPresentationFullScreen; theModalController.modalTransitionStyle = UIModalTransitionStyleCrossDissolve; [self presentModalViewController:theModalController animated:YES]; if ([detailViewController popoverController] != nil) [[detailViewController popoverController] dismissPopoverAnimated:YES]; The BarButtonItem of course, is shown at the bottom of the Default Root Controller (left side of the of the split view in landscape) or at the bottom of the popup (if in landscape). The modal view is dismissed by a button placed in a toolbar. It calls the following: [self dismissModalViewControllerAnimated: YES]; The problem I'm having is if rotate the screen, while the modal is up. Here is what happens in different scenarios (start refers to the orientation when the showTheModal button is hit, end refers to the orientation when I hit the dismissModal button). 1)Start landscape, end landscape: Everything appears fine. willHideViewController and willShowViewController methods are not called in the RootViewController (as expected) 2) Start landscape, end portrait: UI appears fine. willHideViewController is run TWICE (WHY?) 3) Start portrait, end portrait: UI appears fine. willHideViewController is run once (as expected) 4) Start portrait, end landscape: The 'Root List' button remains in the detail view (right side of the split view. Neither willHideViewController and willShowViewController are invoked (WHY??) Any thoughts as to why #2 and #4 don't behave quite the expected way?

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• UIImagePickerController shows last picture taken instead of camera input

  - by jules

  I'm having a strange behaviour within my app. For taking pictures i'm using the following pretty standard code for displaying the UIImagePickerController: UIImagePickerController *picker = [[UIImagePickerController alloc] init]; picker.delegate = self; picker.allowsEditing = NO; picker.sourceType = UIImagePickerControllerSourceTypeCamera; [self presentViewController:picker animated:YES completion:nil]; It works perfectly fine the first time I tap the button which calls this action. The strange behaviour starts when I tap that button again. The UIImagePickerController starts again BUT it doesnt show the input from the camera anymore. It shows the last picture I've taken. More Details of this state: Tapping on the image shows the yellow square of the auto focus. (which it actually uses to focus the camera correctly) When I tap on the ImageCapture button - the correct image is taken and presented on the screen. If I take a picture and press 'Retake' the regular camera image is presented as input. More weirdness: It has nothing to do with the iPad I'm using. Creating a new example app which only has button which calls the code from above everything works perfectly fine. I assume it has something to do with the configuration of the app. Therefore I checked everything but could not find any differences which may cause this issue. Thanks in advance for any advice! Update: I do implement the UIImagePickerControllerDelegate in order to dismiss the UIImagePickerController.

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• DPMS, keep screen off when lid shut

  - by Evan Teran

  I have a laptop running linux. In my xorg configuration, I have DPMS setup so that the screen automatically turns off during several events. In addition to that I have to the following script tied to ACPI lid open/close events: #!/bin/sh for i in $(pidof X); do CMD=$(ps --no-heading $i) XAUTH="$(echo $CMD | sed -n 's/.*-auth \(.*\)/\1/p')" DISPLAY="$(echo $CMD | sed -n 's/.* \(:[0-9]\) .*/\1/p')" # turn the display off or back on export XAUTHORITY=$XAUTH /usr/bin/xset -display $DISPLAY dpms force $1 done Basically, this script takes one parameter ("on" or "off") then iterates through all of my running X sessions and either turns on or turns off the monitor. Here's my issue. When I close the lid of the laptop, the screen goes off as expected, but if a mouse event occurs (like if something bumps into the table...) then the screen turns back on even though it is closed (I can see the light through the side of the laptop). Is there a way to prevent the screen from turning on during a mouse event if the lid is closed?

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• Web user expectations

  - by Ash

  When designing a good Web GUI what expectations can we expect from an end user? I've come up with the following, but I wonder if there are any others which can suggest.. If I click on a hyperlink it will take me to another page/part of this page If I tick/untick a checkbox it might alter the page state (enable/disable elements) If I click on a button I expect it to do something to data. If I click on a button I expect something to happen immediately (either to the current page, or for me to be taken to another page) If I have clicked on a hyperlink and it has taken me to another page, I expect to be able to use the Back button to get back to the previous page in a state similar to that which I left it in If I change something in a form, I can change it back to its previous value if necessary Unless I click on the 'Submit' button nothing should happen to my data. If I bookmark/favourite a page then it should show the same related data each time I visit it If text is underlined and looks like a link, it should be a link and act as one The reasoning behind this question is more a 'UI from hell' one. For example I have come across pages which checking a tickbox next to a record will delete it, straight away, via ajax. To me that just seems wrong, a checkbox is a toggle - something which a delete operation definitely isn't!

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• CSS : How can I add shadow to a label or box

  - by Rachel

  I have an button just as have Ask Question on SO and here is the CSS for it: .rfs .grey_btn{ float: right; margin: 15px 5px; } Now I have to add border shadow to it and I have tried border-radius and box-shadow but it does not give me proper result. Also other question is that I have a label or box say and now I want to increase size of that box so that I have move the text inside that box to right, currently if I move it to right than it reaches the end limit of box and so I want to increase the size of box so that I can push text more towards right. Hope I have made my question clear. Any guidance would be highly appreciated. Thanks.

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• Adding a Layout to bottom of the screen inside a ScrollView in Landscape mode

  - by andreea

  I have the following layout which works in Portrait mode: the Layout with the id LinearLayout02 is placed at the bottom of the screen. The problem appears when flipping to Lanscape mode, when the #LinearLayout02 is placed at the top of the screen. The question is how do I position #LinearLayout02 at the bottom of the screen in both Portrait and Landscape mode? (This happens on G1 and Xperia) Thank you The following code is placed inside a ScrollView android:layout_height="fill_parent" android:layout_width="fill_parent" android:fillViewport="true" <LinearLayout android:id="@+id/sLayout" android:layout_height="wrap_content" android:layout_width="fill_parent" android:orientation="vertical" android:paddingTop="2dip" android:layout_alignParentTop="true" android:gravity="top" > ..... </LinearLayout> <LinearLayout android:id="@+id/LinearLayout02" android:background="@drawable/bottombar_bg" android:layout_width="fill_parent" android:paddingTop="10dip" android:layout_height="56dip" android:layout_alignParentBottom="true" android:gravity="bottom" > <Button android:id="@+id/navigate" style="@style/mainBottomTabsButtonNormal" android:drawableLeft="@drawable/icon_navigation" android:text="@string/navigationSettings" android:layout_gravity="left"> </Button> <Button android:id="@+id/search" style="@style/mainBottomTabsButtonActive" android:drawableLeft="@drawable/icon_search" android:text="@string/search.label" android:layout_gravity="right"> </Button> </LinearLayout> </RelativeLayout>

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• adding nodes to a binary search tree randomly deletes nodes

  - by SDLFunTimes

  Hi, stack. I've got a binary tree of type TYPE (TYPE is a typedef of data*) that can add and remove elements. However for some reason certain values added will overwrite previous elements. Here's my code with examples of it inserting without overwriting elements and it not overwriting elements. the data I'm storing: struct data { int number; char *name; }; typedef struct data data; # ifndef TYPE # define TYPE data* # define TYPE_SIZE sizeof(data*) # endif The tree struct: struct Node { TYPE val; struct Node *left; struct Node *rght; }; struct BSTree { struct Node *root; int cnt; }; The comparator for the data. int compare(TYPE left, TYPE right) { int left_len; int right_len; int shortest_string; /* find longest string */ left_len = strlen(left->name); right_len = strlen(right->name); if(right_len < left_len) { shortest_string = right_len; } else { shortest_string = left_len; } /* compare strings */ if(strncmp(left->name, right->name, shortest_string) > 1) { return 1; } else if(strncmp(left->name, right->name, shortest_string) < 1) { return -1; } else { /* strings are equal */ if(left->number > right->number) { return 1; } else if(left->number < right->number) { return -1; } else { return 0; } } } And the add method struct Node* _addNode(struct Node* cur, TYPE val) { if(cur == NULL) { /* no root has been made */ cur = _createNode(val); return cur; } else { int cmp; cmp = compare(cur->val, val); if(cmp == -1) { /* go left */ if(cur->left == NULL) { printf("adding on left node val %d\n", cur->val->number); cur->left = _createNode(val); } else { return _addNode(cur->left, val); } } else if(cmp >= 0) { /* go right */ if(cur->rght == NULL) { printf("adding on right node val %d\n", cur->val->number); cur->rght = _createNode(val); } else { return _addNode(cur->rght, val); } } return cur; } } void addBSTree(struct BSTree *tree, TYPE val) { tree->root = _addNode(tree->root, val); tree->cnt++; } The function to print the tree: void printTree(struct Node *cur) { if (cur == 0) { printf("\n"); } else { printf("("); printTree(cur->left); printf(" %s, %d ", cur->val->name, cur->val->number); printTree(cur->rght); printf(")\n"); } } Here's an example of some data that will overwrite previous elements: struct BSTree myTree; struct data myData1, myData2, myData3; myData1.number = 5; myData1.name = "rooty"; myData2.number = 1; myData2.name = "lefty"; myData3.number = 10; myData3.name = "righty"; initBSTree(&myTree); addBSTree(&myTree, &myData1); addBSTree(&myTree, &myData2); addBSTree(&myTree, &myData3); printTree(myTree.root); Which will print: (( righty, 10 ) lefty, 1 ) Finally here's some test data that will go in the exact same spot as the previous data, but this time no data is overwritten: struct BSTree myTree; struct data myData1, myData2, myData3; myData1.number = 5; myData1.name = "i"; myData2.number = 5; myData2.name = "h"; myData3.number = 5; myData3.name = "j"; initBSTree(&myTree); addBSTree(&myTree, &myData1); addBSTree(&myTree, &myData2); addBSTree(&myTree, &myData3); printTree(myTree.root); Which prints: (( j, 5 ) i, 5 ( h, 5 ) ) Does anyone know what might be going wrong? Sorry if this post was kind of long.

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• Free desktop recording / screencasting on windows

  - by Mercer Traieste

  I'm a newbie in desktop recording and screencasting. I didn't find a suitable free application to do all the things I want it to do, but I did enjoy using jing. I would expect such an application to have these features: choose the whole desktop, a region, a window to record zoom in an area, and camera move save the recorded movie to a compressed format have basic editing tools have the mouse highlighting feature (either a sonar blip or something similar) highlight window/field on the screen, any trick will do display pressed keys/key combinations (like iphone does) So the question is: Which free desktop recording/screencasting software would you recommend on windows? It doesn't have to have all those features, just tell me your favorable experiences. Please suggest tools that would do mouse/keys/areas highlight tricks. I'm open to commercial software too, but I would prefer a free one. Thank you!

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• Why did windows change the elevation requirements of my AutoHotKey script, and how can I prevent such in the future?

  - by monsto

  I was working on an AutoHotKey (AHK) script to create prefab mouse movements for a very simple model viewer. I worked on it for a good hour. I zipped the script, posted it to a forum, and thought "oh hey, I should add bla bla bla to the script". When I returned to the program, the AHK script would not work. I could see the mouse movements working in other programs (notepad, chrome, etc), but not where I had been working the previous hour. After several hours of throwing darts at the troubleshooting wall, I discovered that the fix was to set the AHK.exe to Run as Administrator. The question here are multiple Why did Windows 7, in all it's wisdom, suddenly decide that elevation was necessary in the middle of usage? Can these permission requirements somehow be reverted by, say, removing a key from the registry or something? How can this kind of Windows behaviour be avoided in the future?

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• Wrap text around an image in rails and prawn

  - by stevenheidel

  I have a document with dynamic image and dynamic text and would like the text around the image. The image is right aligned on the landscape page. Here is what I have so far: pdf.bounding_box([0,pdf.bounds.top - 50], :width => pdf.bounds.width, :height => pdf.bounds.height-50) do pdf.text @article.title, :size => 30, :style => :bold pdf.text @article.content, :align => :left # image pdf.bounding_box([pdf.bounds.right - 250, pdf.bounds.top], :width => 250, :height => 250) do pdf.image image_path, :width => 250 end end The text goes right underneath the image. I tried doing this http://stackoverflow.com/questions/2085151/ruby-prawn-how-to-wrap-text-around-an-aligned-right-image but it didn't work. Help is appreciated, thanks.

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• How does overlayViewTouched notification work in the MoviePlayer sample code

  - by Jonathan

  Hi, I have a question regarding the MoviePlayer sample code provided by apple. I don't understand how the overlayViewTouch notification works. The NSlog message I added to it does not get sent when I touch the view (not button). // post the "overlayViewTouch" notification and will send // the overlayViewTouches: message - (void)overlayViewTouches:(NSNotification *)notification { NSLog(@"overlay view touched"); // Handle touches to the overlay view (MyOverlayView) here... } I can, however, get the NSlog notification if I place it in -(void)touchesBegan in "MyOverlayView.m". Which makes me think it is recognizing touches but not sending a notification. // Handle any touches to the overlay view - (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event { UITouch* touch = [touches anyObject]; if (touch.phase == UITouchPhaseBegan) { NSLog(@"overlay touched(from touchesBegan") // IMPORTANT: // Touches to the overlay view are being handled using // two different techniques as described here: // // 1. Touches to the overlay view (not in the button) // // On touches to the view we will post a notification // "overlayViewTouch". MyMovieViewController is registered // as an observer for this notification, and the // overlayViewTouches: method in MyMovieViewController // will be called. // // 2. Touches to the button // // Touches to the button in this same view will // trigger the MyMovieViewController overlayViewButtonPress: // action method instead. NSNotificationCenter *nc = [NSNotificationCenter defaultCenter]; [nc postNotificationName:OverlayViewTouchNotification object:nil]; } } Can anyone shed light on what I am missing or doing wrong? Thank you.

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• Moving the Gallery view to the next image on one swipe in Android?

  - by sunil

  Hi All, I have four images in the Gallery View. When we do swipe from left to right or right to left the Gallery View moves all the images i.e if I swipe from left to right from the first image then it will move to all the four images. What I want is that when I swipe it should only move to the next image. Can someone let me know how is this possible? Hope to get a reply soon. Regards Sunil

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• How to figure out what error my Java Eclipse project has?

  - by Greg Mattes

  I've created a Java project from existing source with an Ant build script in Eclipse. I cannot run my project because Eclipse tells me that there is at least one error in it. Now, I know that the project runs fine on the command line, so I suspect an Eclipse configuration error. As far as I can tell, the only feedback that I have from Eclipse is a little red X on my project in the Package Explorer window and dialog window when I try to run the project says there are errors in the project This is all wonderful, but what is the error? Is there a "show me the next error" button somewhere? In the past, on other Eclipse projects, I've notice other little red X's on folders containing source files with errors, the little red X's appear on the source files as well. I scanned (manually) through all of the source files and I haven't found any other red X's (again, where is the "next error" button?). If I select the "Proceed" button I am greeted with a java.lang.NoClassDefFoundError for my main class, which makes me suspect a classpath issue. I've checked the classpath, and I'm fairly certain that it's correct. Is there a way to see the exact jvm command line that Eclipse is invoking? I realize that it might be invoking the JVM programmatically, and not on a "real" command line. In any case, is there a way, other than the run configuration dialog, to see what is actually happening when I hit the "Proceed" button?

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• Counting the number of objects that meets a certain criteria

  - by Candy Chiu

  The title doesn't tell the complete story. Please read the message. I have two objects: Adult and Child. Child has a boolean field isMale, and a reference to Adult. Adult doesn't reference Child. public class Adult { long id; } public class Child { long id; boolean isMale; Adult parent; } I want to create a query to list the number of sons each adult has including adults who don't have any sons. I tried: Query 1 SELECT adult, COUNT(child) FROM Child child RIGHT OUTER JOIN child.parent as adult WHERE child.isMale='true' GROUP BY adult which translates to sql select adult.id as col_0_0_, count(child.id) as col_1_0_, ... {omit properties} from Child child right outer join Adult adult on child.parentId=adult.id where child.isMale = 'true' group by adult.id Query 1 doesn't pick up adults that don't have any sons. Query 2: SELECT adult, COUNT(child.isMale) FROM Child child RIGHT OUTER JOIN child.parent as adult GROUP BY adult translates to sql: select adult.id as col_0_0_, count(child.id) as col_1_0_, ... {omit properties} from Child child right outer join Adult adult on child.parentId=adult.id group by adult.id Query 2 doesn't have the right count of sons. Basically COUNT doesn't evaluate isMale. The where clause in Query 1 filtered out Adults with no sons. How do I build a HQL or a Criteria query for this use case? Thanks.

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• Django Forms - change the render multiple select widget

  - by John

  Hi, In my model I have a manytomany field mentors = models.ManyToManyField(MentorArea, verbose_name='Areas', blank=True) In my form I want to render this as: drop down box with list of all MentorArea objects which has not been associated with the object. Next to that an add button which will call a javascript function which will add it to the object. Then under that a ul list which has each selected MentorArea object with a x next to it which again calls a javascript function which will remove the MentorArea from the object. I know that to change how an field element is rendered you create a custom widget and override the render function and I have done that to create the add button. class AreaWidget(widgets.Select): def render(self, name, value, attrs=None, choices=()): jquery = u''' <input class="button def" type="button" value="Add" id="Add Area" />''' output = super(AreaWidget, self).render(name, value, attrs, choices) return output + mark_safe(jquery) However I don't know how to list the currently selected ones underneath as a list. Can anyone help me? Also what is the best way to filter down the list so that it only shows MentorArea objects which have not been added? I currently have the field as mentors = forms.ModelMultipleChoiceField(queryset=MentorArea.objects.all(), widget = AreaWidget, required=False) but this shows all mentors no matter if they have been added or not. Thanks

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• Looking for a software solution which acts like a hardware KVM

  - by Daisetsu

  I've seen programs like Synergy before which allow a keyboard and mouse to be used across multiple systems. Unfortunately Synergy treats both systems like they are the same thing (when you move the mouse too far to the right it jumps to the other computer, along with keyboard input). I only have 1 monitor so what I need to do here is have a quick way to view my other desktop that is easy to manage. Remote desktop is difficult because you have to take it out of fullscreen, then minimize it and then re-maximize it when you want to use it again. If there were a single button I could hit to switch to the other computer that would be optimal. Both computers are on the same lan.

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• Two virtual computers using one laptop?

  - by JP19

  Hi, I have a laptop and an external display. I am able to use the external display either as extended desktop OR duplicate desktop. I also use a separate keyboard and mouse. So effectively, the laptop acts just as a box without display. I want to know is it possible to use the laptop as 2 virtual PCs. (with separate control). I.E., one person uses the laptop as a laptop, and other person can simultaneously connect a keyboard and mouse and the external display and effectively get a second PC. OS I am using - windows (thought solution for other OSes are welcome). Laptop is a Dell Precision M6300. thanks JP

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• parsing css measures

  - by david

  When i write a jQuery plugin i like to specify options for spacings the CSS way. I wrote a function that returns a CSS String as values in a object. 5px 10px returns top: 5px, right: 10px, bottom: 5px, left: 10px Now i often use the returned values to do some calculations and its not very nice to have to extract the measuring unit every time... I suck in writing regular expressions could someone help me complete this function: this.cssMeasure = function(cssString, separateUnits){ if ( cssString ){ var values = {} }else{ return errorMsg } var spacing = cssString.split(' ') var errorMsg = 'please format your css values correctly dude' if( spacing[4] || (spacing[2] && !spacing[3]) ) { return errorMsg } else if ( spacing[3] ) { values = {top: spacing[0], right:spacing[1], bottom:spacing[2], left:spacing[3]} } else if ( spacing[1] ) { values = {top: spacing[0], right:spacing[1], bottom:spacing[0], left:spacing[1]} } else { values = {top: spacing[0], right:spacing[0], bottom:spacing[0], left:spacing[0]} } if (separateUnits) { $.each(values, function(i, value){ /* at this place i need to extract the measuring unit of each value and return them separately something like top: {value: 10, unit: 'px'}, right: {bla} and so on */ }) } return values } if you have any idea how to improve this function i am open to your comments.

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• CSS vertical centering split background image not overlapping

  - by user295292

  is it possible to split 2 images vertically and when resizing the browser, it wont overlap but stay vertically centered? can the left image stay fixed so the right side of it won't cut off(overlap) this is what i have now, but when resizing the browser smaller, it pushes the left image underneath the right. rather have the images cut off on the outer sides and never overlap each other in the middle, make sense? #wrapper { width:1680px; max-width:1680px; height:500px; margin: 0 auto; } #left-image { width: 50%; position:absolute; left: auto; height:500px; } #right-image { width: 50%; position:absolute; right: 0px; height:500px; }

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• HTML/CSS set div to height of sibling

  - by Paul

  I have 2 div's contained in a third. One of the contained div's is floated left, the other floated right. I would like the 2 sibling div's to always be at the same height, but am having a problem with this. So far I am only viewing the page in Firefox, and figured I'd worry about any cross-browser issues after I get it working in at least one browser. Here is the markup: <div id="main-container" class="border clearfix"> <div id="left-div" class="border"> ... </div> <div id="right-div" class="border"> ... </div> </div> Here is the CSS: #main-container { position: relative; min-height: 500px; } #left-div { position: relative; float: left; width: 700px; min-height: inherit; } #right-div { position: relative; float: right; width: 248px; min-height: inherit; height: inherit; } .clearfix:after { content: " "; display: block; height: 0; clear: both; visibility: hidden; } .clearfix { display: inline-block; _height: 1%; clear: both; } .clearfix { display: block; clear: both; } .border { border: solid 1px #000; } If the content in the #left-div is longer than 500px, the #right-div does not expand to match. In an example I tried, Firefox said the computed style height of the #main-container was 804px, the computed style height of the #left-div was 800px, and the computed style height of the #right-div was 586.2px, as it had expanded to fit it's own content. I understand I might be going about this the wrong way, and if this is a duplicate questions then I apologize, but I wasn't quite sure what to search under.

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• Javascript error when attempting to open a modal window in a modal window

  - by The Sheek Geek

  The application is running on a windows server 2003 box using asp.net 2.0 and is an IE specific web app. There is a button that opens a form in an iframe using showModalDialog(...) from a function call located in the javascript. Here is an example of the fucntion: function ShowBusinessHoursSubForm( source ) { var retval = window.showModalDialog("htm/" + locLocaleID + "/SubFormHostFrame.htm", source, "dialogWidth:265px;dialogHeight:261px;help:no;scroll:no;status:no;"); } The host frame is loading an aspx page which contains the actual form that is being used. On the form that is opened there is a button that, when clicked, submits changed to the form. However, if no changed were made before the form was submitted, another modal window pops up stating that there were no changed to the form. This modal window is opened through registration of some javascript in the button click event. The code is as follows (C#): string l_S_ErrorScript = "<script type='text/javascript' language='javascript'>window.showModalDialog('htm/" + l_S_Culture + "/NotChangedErrorDialog.htm', '../../" + l_S_SkinPath + "', 'dialogWidth:310px;dialogHeight:145px;scroll:no;help:no;status:no;');</script>"; if(!m_Page.ClientScript.IsStartupScriptRegistered("ErrorScript")) { m_Page.ClientScript.RegisterStartupScript(this.GetType(), "ErrorScript", l_S_ErrorScript); } When the button is clicked and this dialog needs to appear the following javascript error appears: Error: Object doesn't support this property or method The weird thing is, if I access the application locally and try it everything works fine, but accessing from another computer causes the error. Also, depending on what server (we have many servers for testing all with windows server 2003) the error may not occur on another computer either. These computers are running the same software version using the same version of IE with the same settings. I'm inclined to believe that there is some configuration issue somewhere, but with the settings being the same it is hard to tell. I cannot really change how the app works or the technologies used either. Anyone have any ideas as to what may be causing this?

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• Custom UIButton for Iphone.

  - by Amal

  I have an view in my App which has a number of buttons based on the number of items returned by the server. So if the server returns say 10 items, there should be 10 buttons and clicking on each button should call a different person. For the above purpose I created a custom button class deriving from UIButton. @implementation HopitalButton @synthesize index; @synthesize button_type; - (id)initWithFrame:(CGRect)frame { if (self = [super initWithFrame:frame]) { UIImage* img = [UIImage imageNamed:@"dr_btn.png"]; [img stretchableImageWithLeftCapWidth:10 topCapHeight:10]; [self setBackgroundImage:img forState:UIControlStateNormal]; [self setTitleColor:[UIColor colorWithRed:0.698 green:0.118 blue:0.376 alpha:1] forState:UIControlStateNormal] ; [self setFont:[UIFont fontWithName:@"Helvetica Bold" size:13]]; self.titleLabel.textColor = [UIColor colorWithRed:178 green:48 blue:95 alpha:1]; self.adjustsImageWhenHighlighted = YES; } return self; } - (void)dealloc { [super dealloc]; } @end Now the problem with the above code is that it does not create buttons that look similar to the buttons created by default in Interface builder. The borders are missing. And I create buttons of the above type by the following code: HopitalButton* hb = [[HopitalButton alloc] init]; hb.button_type = @"call"; hb.frame = CGRectMake(50, 50 + i * 67, 220, 40); [self.scroll_view addSubview:hb]; [hb setTitle:[[[self.office_full_list objectAtIndex:i] objectForKey:@"Staff" ]objectForKey:@"FullName"] forState:UIControlStateNormal]; hb.index = [NSNumber numberWithInt:[self.button_items count]]; [self.button_items insertObject:hb atIndex:[self.button_items count]]; [hb addTarget:self action:@selector(buttonClicked:) forControlEvents:UIControlEventTouchUpInside]; I am not finding a way to set the button type for this custom button. Is there a way i can do it ? Or is there a better way to design the code.

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