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  • Best way to pass image to server?

    - by Chris
    I have an SL3 application that needs to be able to pass an image to the server, and then the server will generate a PDF file with the image in it, and display it to the user. What I already have in place are the following: (1) Code to convert image to byte array (2) Code to generate PDF file with image The main problem that I am running into is the following: In order to bypass the pop-up blocker, which is a requirement for my application, I am using the following code: var button = new NavigationButton(); button.NavigateUri = new Uri("http://localhost:3616/PrintReport.aspx?ReportIndex=11&ActionType=Get&ReportIdentifier=" + reportIdentifier.ToString() + ""); button.TargetName = "_blank"; button.PerformClick(); Initially, I would pass the image to a WCF web service (as a byte array), and then "navigate" to the ASP.NET page that would display the report. However, if I do this, then I can not use my custom HyperlinkButton class, and, certain browsers, including Safari, will block a new window from opening up. Therefore, it appears that the only option is to use the HyperlinkButton class. What I need to be able to do is to somehow pass the image, as a byte array or some other data type, to the server, such that it can temporarily store the image, even if it is in a server variable, and then immediately retrieve it when I navigate to the PrintReport.aspx page. If I upload the image to an ASP.NET form and then use the HyperlinkButton class to navigate to the PrintReport page, it doesn't work, as the app navigates to the PrintReport page before the system has finished uploading the image. I can't pass it to a web service, as that would require that I navigate to the PrintReport.aspx page in the callback code of the web method that I would be passing the image to, and the HyperlinkButton will not allow that, based on security rules. Any help or ideas would be appreciated. Thanks. Chris

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  • Javascript error when attempting to open a modal window in a modal window

    - by The Sheek Geek
    The application is running on a windows server 2003 box using asp.net 2.0 and is an IE specific web app. There is a button that opens a form in an iframe using showModalDialog(...) from a function call located in the javascript. Here is an example of the fucntion: function ShowBusinessHoursSubForm( source ) { var retval = window.showModalDialog("htm/" + locLocaleID + "/SubFormHostFrame.htm", source, "dialogWidth:265px;dialogHeight:261px;help:no;scroll:no;status:no;"); } The host frame is loading an aspx page which contains the actual form that is being used. On the form that is opened there is a button that, when clicked, submits changed to the form. However, if no changed were made before the form was submitted, another modal window pops up stating that there were no changed to the form. This modal window is opened through registration of some javascript in the button click event. The code is as follows (C#): string l_S_ErrorScript = "<script type='text/javascript' language='javascript'>window.showModalDialog('htm/" + l_S_Culture + "/NotChangedErrorDialog.htm', '../../" + l_S_SkinPath + "', 'dialogWidth:310px;dialogHeight:145px;scroll:no;help:no;status:no;');</script>"; if(!m_Page.ClientScript.IsStartupScriptRegistered("ErrorScript")) { m_Page.ClientScript.RegisterStartupScript(this.GetType(), "ErrorScript", l_S_ErrorScript); } When the button is clicked and this dialog needs to appear the following javascript error appears: Error: Object doesn't support this property or method The weird thing is, if I access the application locally and try it everything works fine, but accessing from another computer causes the error. Also, depending on what server (we have many servers for testing all with windows server 2003) the error may not occur on another computer either. These computers are running the same software version using the same version of IE with the same settings. I'm inclined to believe that there is some configuration issue somewhere, but with the settings being the same it is hard to tell. I cannot really change how the app works or the technologies used either. Anyone have any ideas as to what may be causing this?

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  • c# Most efficient way to combine two objects

    - by Dested
    I have two objects that can be represented as an int, float, bool, or string. I need to perform an addition on these two objects with the results being the same thing c# would produce as a result. For instance 1+"Foo" would equal the string "1Foo", 2+2.5 would equal the float 5.5, and 3+3 would equal the int 6 . Currently I am using the code below but it seems like incredible overkill. Can anyone simplify or point me to some way to do this efficiently? private object Combine(object o, object o1) { float left = 0; float right = 0; bool isInt = false; string l = null; string r = null; if (o is int) { left = (int)o; isInt = true; } else if (o is float) { left = (float)o; } else if (o is bool) { l = o.ToString(); } else { l = (string)o; } if (o1 is int) { right = (int)o1; } else if (o is float) { right = (float)o1; isInt = false; } else if (o1 is bool) { r = o1.ToString(); isInt = false; } else { r = (string)o1; isInt = false; } object rr; if (l == null) { if (r == null) { rr = left + right; } else { rr = left + r; } } else { if (r == null) { rr = l + right; } else { rr = l + r; } } if (isInt) { return Convert.ToInt32(rr); } return rr; }

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  • Android -Layout Manager not showing buttons

    - by Arun
    The following is my code. I want an interface where I have a single line textbox, a multiline textbox with 2 buttons below. I want the multiline textbox to occupy all the space available after rendering the buttons and textbox. For this I created two LinearLayouts inside the main layout. The first one has vertical orientation with layout_width set to fill_parent. The second one is horizontal with fill_parent again. The first one has a textbox for which I have set the layout_height to fill parent. The second one has two textboxes OK and Cancel. When I run this application I get the UI, but the Buttons are very small. I have to set the button height manually. What am I doing wrong here. I don't want to hard code the button height. <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> <LinearLayout android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:layout_weight="1"> <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="Name"></TextView> <EditText android:layout_width="fill_parent" android:layout_height="wrap_content"></EditText> <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="Contents"></TextView> <EditText android:layout_width="fill_parent" android:layout_height="fill_parent" android:gravity="top" /> </LinearLayout> <LinearLayout android:orientation="horizontal" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_weight="1"> <Button android:id="@+id/okbutt" android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="OK" android:layout_weight="1" /> <Button android:layout_width="fill_parent" android:layout_height="fill_parent" android:text="Cancel" android:layout_weight="1" /> </LinearLayout> Thanks, Arun

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  • how to move and print squares visited by a knight in following order?

    - by josh kant
    Lets say you have a 5/5 board and you place and the knight started moving form the middle square. Every time knight moves it has to follow the following pattern. its easy if you draw what i mean. I am trying to code for the possible moves and print out the no. of moves in the nXn (in this case 5X5) board. The print out should be the no. of order in which the knight moved. { //move 1 //2 squares up and 1 to the left //move 2 //2 squares up and 1 to the right //move 3 //1 square up and 2 to the right //move 4 //1 square down and 2 to the right //move 5 //2 squares down and 1 to the right //move 6 //2 squares down and 1 to the left //move 7 //1 square down and 2 to the left //move 8 //one square up and 2 to the left } Any help would be appreciated. Thank you in advance..

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  • HTML/CSS set div to height of sibling

    - by Paul
    I have 2 div's contained in a third. One of the contained div's is floated left, the other floated right. I would like the 2 sibling div's to always be at the same height, but am having a problem with this. So far I am only viewing the page in Firefox, and figured I'd worry about any cross-browser issues after I get it working in at least one browser. Here is the markup: <div id="main-container" class="border clearfix"> <div id="left-div" class="border"> ... </div> <div id="right-div" class="border"> ... </div> </div> Here is the CSS: #main-container { position: relative; min-height: 500px; } #left-div { position: relative; float: left; width: 700px; min-height: inherit; } #right-div { position: relative; float: right; width: 248px; min-height: inherit; height: inherit; } .clearfix:after { content: " "; display: block; height: 0; clear: both; visibility: hidden; } .clearfix { display: inline-block; _height: 1%; clear: both; } .clearfix { display: block; clear: both; } .border { border: solid 1px #000; } If the content in the #left-div is longer than 500px, the #right-div does not expand to match. In an example I tried, Firefox said the computed style height of the #main-container was 804px, the computed style height of the #left-div was 800px, and the computed style height of the #right-div was 586.2px, as it had expanded to fit it's own content. I understand I might be going about this the wrong way, and if this is a duplicate questions then I apologize, but I wasn't quite sure what to search under.

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  • In JSF How can I understand of multi checkboxes whether all of them is checked or not?

    - by Bariscan
    As you understand from the title above, I have a datatable and checkboxes in each row. I want to enable a button when at least one checkbox is selected, and disable it when there is no selected checkboxes (I mean all of them is unselected). I could achieve this as like if one of the checkboxes is selected, the button becomes enable. However, the reversable case I have to do is when the checkboxes is being unselected, when the last selected checbox becomes unselected, the button immediately must become disabled... BTW, I must do it without using a setter method nor a backing bean. Can I perform it by using jquery or a jsfunction, richfaces, etc? As a result, I want to learn how I can disable a button at the moment when all of the checkboxes are unselected? In order to clarify the case, here is my code below; <h:selectBooleanCheckbox id="selectionCheck" onclick="document.getElementById('form1:button1').disabled=false" value="#{_apiV2Product.selectValue}" > </h:selectBooleanCheckbox> Any help would be appreciated, Many thanks, Baris

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  • Table is centering by itself?

    - by user146780
    I have a page here: http://animactions.ca/Animactions/accueil.php and it has a right column. When the right column's content is longer than then the main content, the main content centers rather than start at the top despite I defining it in a style not to do so. From my style sheet: .tbsyles { margin: 0px; text-align: justify; width: 200px; border-left-style: solid; border-left-width: 1px; border-left-color: #A8CFE4; padding-left: 30px; height: 100%; line-height: 100%; vertical-align: top; padding-right: 0px; } .tablestylea { width: 900px; margin: 0px; text-align: justify; height: 100%; line-height: 100%; vertical-align: top; padding-right: 0px; } How can I make it so no matter what the length of my right col content the main content page resizes correctly and starts from the top rather than from the center? Thanks

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  • iphone sdk: finding the direction of scrolling in UIScrollView

    - by Alex1987
    I have a UIScrollView with only horizontal scrolling allowed, and I would like to know which direction (left, right) the user scrolls. What I did was to subclass the UIScrollView and override the touchesMoved method: - (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event { [super touchesMoved:touches withEvent:event]; UITouch *touch = [touches anyObject]; float now = [touch locationInView:self].x; float before = [touch previousLocationInView:self].x; NSLog(@"%f %f", before, now); if (now > before){ right = NO; NSLog(@"LEFT"); } else{ right = YES; NSLog(@"RIGHT"); } } But this method sometimes doesn't get called at all when I move. What do you think?

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  • Custom UIButton for Iphone.

    - by Amal
    I have an view in my App which has a number of buttons based on the number of items returned by the server. So if the server returns say 10 items, there should be 10 buttons and clicking on each button should call a different person. For the above purpose I created a custom button class deriving from UIButton. @implementation HopitalButton @synthesize index; @synthesize button_type; - (id)initWithFrame:(CGRect)frame { if (self = [super initWithFrame:frame]) { UIImage* img = [UIImage imageNamed:@"dr_btn.png"]; [img stretchableImageWithLeftCapWidth:10 topCapHeight:10]; [self setBackgroundImage:img forState:UIControlStateNormal]; [self setTitleColor:[UIColor colorWithRed:0.698 green:0.118 blue:0.376 alpha:1] forState:UIControlStateNormal] ; [self setFont:[UIFont fontWithName:@"Helvetica Bold" size:13]]; self.titleLabel.textColor = [UIColor colorWithRed:178 green:48 blue:95 alpha:1]; self.adjustsImageWhenHighlighted = YES; } return self; } - (void)dealloc { [super dealloc]; } @end Now the problem with the above code is that it does not create buttons that look similar to the buttons created by default in Interface builder. The borders are missing. And I create buttons of the above type by the following code: HopitalButton* hb = [[HopitalButton alloc] init]; hb.button_type = @"call"; hb.frame = CGRectMake(50, 50 + i * 67, 220, 40); [self.scroll_view addSubview:hb]; [hb setTitle:[[[self.office_full_list objectAtIndex:i] objectForKey:@"Staff" ]objectForKey:@"FullName"] forState:UIControlStateNormal]; hb.index = [NSNumber numberWithInt:[self.button_items count]]; [self.button_items insertObject:hb atIndex:[self.button_items count]]; [hb addTarget:self action:@selector(buttonClicked:) forControlEvents:UIControlEventTouchUpInside]; I am not finding a way to set the button type for this custom button. Is there a way i can do it ? Or is there a better way to design the code.

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  • vimperator copy/pasting

    - by hasen j
    I'm trying out vimperator, I mainly wanted it for the hjkl scrolling, I like it's "hint" system for following links, these two features are really all I need; I think. I don't mind the other features, it just sometimes get in my way. The thing that annoys me the most is copy/pasting. I'm used to ctrl-c/ctrl-v, I don't mind using another shortcut, but .. :help yank indicates that copying selected text is done with Y, but the only method mentioned for pasting is the middle mouse button! This is so ridiculously against the spirit of vim! How can I paste in vimperator without using the mouse?

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  • Facebook Connect - Using both FBML and PHP Client

    - by Ryan
    I am doing my second Facebook connect site. On my first site, I used the facebook coonect FBML to sign a user in, then I could access other information via the PHP Client. With this site, using the same exact code, it doesn't seem to be working. I'd like someone to be able to sign in using the Facebook button: <fb:login-button length="long" size="medium" onlogin="facebook_onlogin();"></fb:login-button> After they have logged in, the facebook_onlogin() function makes some AJAX requests to a PHP page which attempts to use the Facebook PHP Client. Here's the code from that page: $facebook = new Facebook('xxxxx API KEY xxxxx', 'xxxxx SECRET KEY xxxxx'); //$facebook->require_login(); ** I DONT WANT THIS LINE!! $userID = $facebook->api_client->users_getLoggedInUser(); if($userID) { $user_details = $facebook->api_client->users_getInfo($userID, 'last_name, first_name'); $firstName = $user_details[0]['first_name']; $lastName = $user_details[0]['last_name']; $this->view->userID = $userID; $this->view->firstName = $firstName; $this->view->lastName = $lastName; } The problem is that the PHP Client thinks I don't have a session key, so the $userID never get set. If I override the $userID with my facebook ID (which I am logged in with) I get this error: exception 'FacebookRestClientException' with message 'A session key is required for calling this method' in C:\wamp\www\mab\application\Facebook\facebookapi_php5_restlib.php:3003 If I uncomment the require_login(), it will get a session ID, but it redirects pages around a lot and breaks my AJAX calls. I am using the same code I successfully did this with on another site. Anyone have any ideas why the PHP client don't know about the session ID after a user has logged in with the connect button? Any ideas would be greatly appreciated. Thanks!

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  • Android - Linear Layout arrangement, not positioning as expected

    - by Arun
    The following is my code. I want an interface where I have a single line textbox, a multiline textbox with 2 buttons below. I want the multiline textbox to occupy all the space available after rendering the buttons and textbox. For this I created two LinearLayouts inside the main layout. The first one has vertical orientation with layout_width set to fill_parent. The second one is horizontal with fill_parent again. The first one has a textbox for which I have set the layout_height to fill parent. The second one has two textboxes OK and Cancel. When I run this application I get the UI, but the Buttons are very small (about 5px in height). I have to set the button height manually. What am I doing wrong here. I don't want to hard code the button height. <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> <LinearLayout android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:layout_weight="1"> <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="Name"></TextView> <EditText android:layout_width="fill_parent" android:layout_height="wrap_content"></EditText> <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="Contents"></TextView> <EditText android:layout_width="fill_parent" android:layout_height="fill_parent" android:gravity="top" /> </LinearLayout> <LinearLayout android:orientation="horizontal" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_weight="1"> <Button android:id="@+id/okbutt" android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="OK" android:layout_weight="1" /> <Button android:layout_width="fill_parent" android:layout_height="fill_parent" android:text="Cancel" android:layout_weight="1" /> </LinearLayout> Thanks, Arun

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  • CSS vertcial centering split background image not overlapping

    - by user295292
    is it possible to split 2 images vertically and when resizing the browser, it wont overlap but stay vertically centered? can the left image stay fixed so the right side of it won't cut off(overlap) this is what i have now, but when resizing the browser smaller, it pushes the left image underneath the right. rather have the images cut off on the outer sides and never overlap each other in the middle, make sense? wrapper { width:1680px; max-width:1680px; height:500px; margin: 0 auto; } left-image { width: 50%; position:absolute; left: auto; height:500px; } right-image { width: 50%; position:absolute; right: 0px; height:500px; }

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  • How can I close a window in Perl/Tk?

    - by guy ergas
    In my Perl/Tk script I have opened two windows. After a specific button click I want to close one of them. How can I do that? Here's what I have so far: $main = new MainWindow; $sidebar = $main->Frame(-relief => "raised", -borderwidth => 2) ->pack (-side=>"left" , -anchor => "nw", -fill => "y"); $Button1 = $sidebar -> Button (-text=>"Open\nNetlist", -command=> \&GUI_OPEN_NETLIST) ->pack(-fill=>"x"); MainLoop; sub GUI_OPEN_NETLIST { $component_dialog = new MainWindow; $Button = $component_dialog -> Button (-text=>"Open\nNetlist", -command=> **close new window**) ->pack(-fill=>"x"); MainLoop; }

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  • Linux and ClickPads

    - by John
    I just got my Arch / Windows 7 dual-boot setup running... except for one thing. I have an HP dv6-3127dx laptop, which is an issue when it comes to Linux because it does not have a traditional touchpad, but a "ClickPad." This means where the left and right buttons exist, it is also sensitive to moving the pointer. The issue comes in when I try to steady the mouse with one finger, while clicking the left click with another, because the mouse freaks out. It's also an issue because it's not recognizing the right click whatsoever. I am currently using the default Synaptics drivers downloaded from pacman on Arch Linux, running Linux v2.6.36. EDIT: The question of course is, how can I fix this?

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  • how to update Sr. No. COLUMN after removing a TR from TABLE

    - by user251336
    i have a table like <table> <tr> <td>Sr. No.</td> <td> Name</td> <td>$nbsp;</td> </tr> <tr> <td>1</td> <td>abc</td> <td>remove button</td> </tr> <tr> <td>2</td> <td>xyz</td> <td>remove button</td> </tr> <tr> <td>3</td> <td>def</td> <td>remove button</td> </tr> onclick of ' remove button ' i send ajax request & after successful response i remove the respective TR using $('#id_of_tr').remove();. till here everything goes fine but now i want to update Sr. No.s of each row. Because Initially order is 1 2 3 , when i remove second row then it becames 1 3 which i want to update it to 1 2. I hope this would help.

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  • What WYSIWYG software can I use to create a web page?

    - by Roman
    I always made web pages by writing HTML code but now I would like to try to use some WYSIWYG approach. Can anybody recommend me a program which I can use for that? I mean a program in which you can move buttons, tables, pictures by mouse. You can change size and shape by mouse. You can use nice templates for "block of text", buttons, background and so on. I am using Windows 7. May be I already have something pre-installed?

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  • Is there a better way to refresh WebView?

    - by cdg
    Hi all. Ok. I have looked EVERYWHERE and my little brain just can't understand a better way to refresh an activity. Any suggestions that I can understand would be great. :) Here is the java code: package com.dge.dges; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.webkit.WebView; import android.widget.Button; public class dgeActivity extends Activity { WebView mWebView; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); mWebView = (WebView) findViewById(R.id.webview); mWebView.getSettings(); mWebView.loadUrl("http://www.websitehere.php"); Button newButton = (Button)findViewById(R.id.new_button); newButton.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { Intent intent = new Intent(dgeActivity.this, dgeActivity.class); startActivity(intent); } }); } } And here is the main.xml <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/RelativeLayout" android:layout_width="fill_parent" android:layout_height="fill_parent" android:background="#000000" > <WebView android:id="@+id/webview" android:layout_width="fill_parent" android:layout_height="wrap_content" android:scrollbars="none" /> <Button android:id="@+id/new_button" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_alignParentBottom="true" android:layout_centerHorizontal="true" android:text="Refresh" /> </RelativeLayout> I don't like the idea of just re-stacking activity after activity. There has to be an easier way to refresh the webview. Please help. :)

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  • jQuery menu active link

    - by antosha
    Hello, I am trying to make a jquery menu that when I click on one of the links (without reloading the page), it changes its class to "active" and removes this class when I click on another link. here is my code : <script type="text/javascript"> $(document).ready(function() { $(".buttons").children().("a").click(function() { $(".buttons").children().toggleClass("selected").siblings().removeClass("selected"); }); }); </script> <ul class="buttons"> <li><a class="button" href="#">Link1</a></li> <li><a class="button" href="#">Link2</a></li> <li><a class="button" href="#">Link3</a></li> <li><a class="button" href="#">Link4</a></li> </ul> Can someone tell me why my code is not working and how to fix it? Thanks :)

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  • Extracting table rows with a particular attribute from an HTML File, using HTMLAgilityPack

    - by Soham
    Consider this html snippet: <tr> <td valign=top class="tim_new"><a href="/stocks/company_info/pricechart.php?sc_did=MI42" class="tim_new">3M India</a></td> <td class="tim_new" valign=top><a href='/stocks/marketstats/indcomp.php?optex=NSE&indcode=Diversified' class=tim>Diversified</a></td> <td class="tim_new" align=right valign=top>2,487.25</td> <td class="tim_new" align=right valign=top><font color=#16a903>187.25</font></td> <td class="tim_new" align=right valign=top><font color=#16a903>8.14</font></td> <td class="tim_new" align=right valign=top>2,801.90</td> <td class="tim_new" align=right valign=top>0.06</td> </tr> Realize these three things: The HTML file from which this snippet has been taken, contains multiple number of HTML tables. The table from which this snippet has been extracted doesnt contain only rows of the shown format, but also of other formats like this, for example: <tr><td colspan=7><img src="http://img1.moneycontrol.com/images/blank.gif"height="5"></td></tr>` This same table contains multiple rows of the format which I need to extract. So given this scenario, is it possible to run a code, which extracts, the link with the class name = "tim_new"? Help Appreciated, Soham

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  • How does a trackball reduce pain caused by RSI? [closed]

    - by gunbuster363
    I developed RSI (Repetitive Strain Injury) in my index fingers due excessive mouse clicking. I might consider a trackball as many people suggested. But how does trackball help? I can see it get 2 buttons and a ball which require some fingers to operate on. Will I RSI while I click on the buttons with other healthy fingers? Logitech TrackMan Wheel: I highly doubt this trackball, I assume we are still using the index and middle finger for clicking. Logitech Marble Mouse: I think we will use the thumb to click the left button, will I develop RSI on my thumb? And the right button, which finger should I use? If you know other trackball which might help, please tell me which is the design that help to avoid the stress.

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  • Using repaint() method.

    - by owca
    I'm still struggling to create this game : http://stackoverflow.com/questions/2844190/choosing-design-method-for-ladder-like-word-game .I've got it almost working but there is a problem though. When I'm inserting a word and it's correct, the whole window should reload, and JButtons containing letters should be repainted with different style. But somehow repaint() method for the game panel (in Main method) doesn't affect it at all. What am I doing wrong ? Here's my code: Main: import java.util.Scanner; import javax.swing.*; import java.awt.*; public class Main { public static void main(String[] args){ final JFrame f = new JFrame("Ladder Game"); Scanner sc = new Scanner(System.in); System.out.println("Creating game data..."); System.out.println("Height: "); //setting height of the grid while (!sc.hasNextInt()) { System.out.println("int, please!"); sc.next(); } final int height = sc.nextInt(); /* * I'm creating Grid[]game. Each row of game contains Grid of Element[]line. * Each row of line contains Elements, which are single letters in the game. */ Grid[]game = new Grid[height]; for(int L = 0; L < height; L++){ Grid row = null; int i = L+1; String s; do { System.out.println("Length "+i+", please!"); s = sc.next(); } while (s.length() != i); Element[] line = new Element[s.length()]; Element single = null; String[] temp = null; String[] temp2 = new String[s.length()]; temp = s.split(""); for( int j = temp2.length; j>0; j--){ temp2[j-1] = temp[j]; } for (int k = 0 ; k < temp2.length ; k++) { if( k == 0 ){ single = new Element(temp2[k], 2); } else{ single = new Element(temp2[k], 1); } line[k] = single; } row = new Grid(line); game[L] = row; } //############################################ //THE GAME STARTS HERE //############################################ //create new game panel with box layout JPanel panel = new JPanel(); panel.setLayout(new BoxLayout(panel, BoxLayout.Y_AXIS)); panel.setBackground(Color.ORANGE); panel.setBorder(BorderFactory.createEmptyBorder(10, 10, 10, 10)); //for each row of the game array add panel containing letters Single panel //is drawn with Grid's paint() method and then returned here to be added for(int i = 0; i < game.length; i++){ panel.add(game[i].paint()); } f.setContentPane(panel); f.pack(); f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); f.setVisible(true); boolean end = false; boolean word = false; String text; /* * Game continues until solved() returns true. First check if given word matches the length, * and then the value of any row. If yes - change state of each letter from EMPTY * to OTHER_LETTER. Then repaint the window. */ while( !end ){ while( !word ){ text = JOptionPane.showInputDialog("Input word: "); for(int i = 1; i< game.length; i++){ if(game[i].equalLength(text)){ if(game[i].equalValue(text)){ game[i].changeState(3); f.repaint(); //simple debug - I'm checking if letter, and //state values for each Element are proper for(int k=0; k<=i; k++){ System.out.print(game[k].e[k].letter()); } System.out.println(); for(int k=0; k<=i; k++){ System.out.print(game[k].e[k].getState()); } System.out.println(); //set word to true and ask for another word word = true; } } } } word = false; //check if the game has ended for(int i = 0; i < game.length; i++){ if(game[i].solved()){ end = true; } else { end = false; } } } } } Element: import javax.swing.*; import java.awt.*; public class Element { final int INVISIBLE = 0; final int EMPTY = 1; final int FIRST_LETTER = 2; final int OTHER_LETTER = 3; private int state; private String letter; public Element(){ } //empty block public Element(int state){ this("", 0); } //filled block public Element(String s, int state){ this.state = state; this.letter = s; } public JButton paint(){ JButton button = null; if( state == EMPTY ){ button = new JButton(" "); button.setBackground(Color.WHITE); } else if ( state == FIRST_LETTER ){ button = new JButton(letter); button.setBackground(Color.red); } else { button = new JButton(letter); button.setBackground(Color.yellow); } return button; } public void changeState(int s){ state = s; } public void setLetter(String s){ letter = s; } public String letter(){ return letter; } public int getState(){ return state; } } Grid: import javax.swing.*; import java.awt.*; public class Grid extends JPanel{ public Element[]e; private Grid[]g; public Grid(){} public Grid( Element[]elements ){ e = new Element[elements.length]; for(int i=0; i< e.length; i++){ e[i] = elements[i]; } } public Grid(Grid[]grid){ g = new Grid[grid.length]; for(int i=0; i<g.length; i++){ g[i] = grid[i]; } Dimension d = new Dimension(600, 600); setMinimumSize(d); setPreferredSize(new Dimension(d)); setMaximumSize(d); } //for Each element in line - change state to i public void changeState(int i){ for(int j=0; j< e.length; j++){ e[j].changeState(3); } } //create panel which will be single row of the game. Add elements to the panel. // return JPanel to be added to grid. public JPanel paint(){ JPanel panel = new JPanel(); panel.setLayout(new GridLayout(1, e.length)); panel.setBorder(BorderFactory.createEmptyBorder(2, 2, 2, 2)); for(int j = 0; j < e.length; j++){ panel.add(e[j].paint()); } return panel; } //check if the length of given string is equal to length of row public boolean equalLength(String s){ int len = s.length(); boolean equal = false; for(int j = 0; j < e.length; j++){ if(e.length == len){ equal = true; } } return equal; } //check if the value of given string is equal to values of elements in row public boolean equalValue(String s){ int len = s.length(); boolean equal = false; String[] temp = null; String[] temp2 = new String[len]; temp = s.split(""); for( int j = len; j>0; j--){ temp2[j-1] = temp[j]; } for(int j = 0; j < e.length; j++){ if( e[j].letter().equals(temp2[j]) ){ equal = true; } else { equal = false; } } if(equal){ for(int i = 0; i < e.length; i++){ e[i].changeState(3); } } return equal; } //check if the game has finished public boolean solved(){ boolean solved = false; for(int j = 0; j < e.length; j++){ if(e[j].getState() == 3){ solved = true; } else { solved = false; } } return solved; } }

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  • Slow Jquery Animation

    - by Pyronaut
    I have this webpage : http://miloarc.pyrogenicmedia.com/ Which atm is nothing special. It has a few effects but none that break the bank. If you mouse over a tile, it should change it's opacity to give it a fade effect. This is done through the Jquery Animation, not through CSS (I do this so it can fade, instead of being a straight change). Everything looks nice when the page loads, and the fades look perfect. Infact if you drag your mouse all over the place, if gives you a "trail" almost like a snake. Anyway, My next problem is that you will see there is a box in the top left, which is going to tell you information about the tile you are hovering over. This seems to work fine. When you mouse over that information box, it switches it's position (So that you can reach the tiles that were previously hidden underneath it). From my understanding, this is all working fine, and to the letter. However, After one move of the info box (One hover). Viewing the page in Firefox turns slugish. As in, after a successful move of the info box, the fade effects become very stuttered, and it doesn't pick up events as fast meaning you can't draw a "trail" on the screen. Chrome doesn't have this issue. It seems to work fine no matter what. Safari also seems ok. Although I do notice if I move my mouse really fast, it does jump a bit but not as much as firefox. Internet explorer doesn't work at all. Seems to crash the browser... And there is an error with the rounded corner plugin im using (Not sure why...). All in all, I think whatever I'm doing inside my code must be heavily sluggish. But I don't know where it is happening. Here is the full code, but I would advise go to the link to view everything. <script type="text/javascript"> $(document).ready(function() { var WindowWidth = $(window).width(); var WindowMod = WindowWidth % 20; var WindowWidth = WindowWidth - WindowMod; var BoxDimension = WindowWidth / 20; var BoxDimensionFixed = BoxDimension - 12; var dimensions = BoxDimensionFixed + 'px'; $('.gamebutton').each(function(i) { $(this).css('width', dimensions); $(this).css('height', dimensions); }); var OuterDivHeight = BoxDimension * 10; var TopMargin = ($(window).height() - OuterDivHeight) / 2; var OuterDivWidth = BoxDimension * 20; var LeftMargin = ($(window).width() - OuterDivWidth) / 2; $('#gamePort').css('margin-top', TopMargin).css('margin-left', LeftMargin).css('margin-right', LeftMargin); $('.gamebutton img').each(function(i) { $(this).hover( function () { $(this).animate({'opacity': 0.65}); }, function () { $(this).animate({'opacity': 1}); } ); }); $('.rounded').corners(); $('.gamebutton').each(function(i) { $(this).hover(function() { $('.gameTitlePopup').html($(this).attr('title')); FadeActive(); }); }); function FadeActive() { $('.activeInfo').fadeIn('slow'); } $('#gameInfoLeft').hover(function() { $(this).removeClass('activeInfo'); $(this).fadeOut('slow', function() { $('#gameInfoRight').addClass('activeInfo'); FadeActive(); }); }); $('#gameInfoRight').hover(function() { $(this).removeClass('activeInfo'); $(this).fadeOut('slow', function() { $('#gameInfoLeft').addClass('activeInfo'); FadeActive(); }); }); }); </script> Thanks for any help :).

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  • USB drivers installed twice

    - by stupid-phil
    Hello, I have a problem with usb drivers on Windows 7 64bit When I start up my laptop, the mouse I have plugged into a usb port does not work. I have to open the device manager, where there are two "Standard Enhanced PCI to USB Host Controller" entries. One is marked as faulty (yellow triangle). I uninstall this. Scan for changes. Then it re-appears, but not marked as faulty. And the mouse works. I have to do this every time I reboot. A colleague has the same problem. Both DELL laptops, but different models. I've tried uninstalling all USB controllers, but after a reboot, they are all reinstalled with the faulty entry. This only started happening in the last few weeks. Any help appreciated. It's driving me nuts. Thanks Phil

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