Search Results

Search found 59692 results on 2388 pages for 'legacy data'.

Page 296/2388 | < Previous Page | 292 293 294 295 296 297 298 299 300 301 302 303  | Next Page >

  • php doctrine relational form naming for saving data

    - by neziric
    is it possible to have an html form organized/named in such a way that $foo-fromArray($_POST) would actually save relational data as well? example: html_form_fields: user_name country_name db_table_users: id user_name db_table_countries: id country_name update: forgot to say i'm trying to make this with zend framework forms

    Read the article

  • Sort/Group XML data with PHP?

    - by Volmar
    I'm trying to make a page using data from the discogs.com (XML)-API. i've been parsing it with simpleXML and it's working pretty well but there is some things i'm not sure how to do. Here is part of the XML: <releases> <release id="1468764" status="Accepted" type="Main"> <title>Versions</title> <format>12", EP</format> <label>Not On Label</label> <year>1999</year> </release> <release id="72246" status="Accepted" type="Main"> <title>The M.O.F Blend</title> <format>LP</format> <label>Blenda Records</label> <year>2002</year> </release> <release id="890064" status="Accepted" type="Main"> <title>The M.O.F Blend</title> <format>CD</format> <label>Blenda Records</label> <year>2002</year> </release> <release id="1563561" status="Accepted" type="TrackAppearance"> <title>Ännu En Gång Vol. 3</title> <trackinfo>Backtrack</trackinfo> <format>Cass, Comp, Mix</format> <label>Hemmalaget</label> <year>2001</year> </release> </releases> What i want to achieve is something similair to how discogs presents the releases: http://www.discogs.com/artist/Mics+Of+Fury where diferent versions of the same release are sorted together. (see. The M.O.F Blend in my link) This is done on discogs with having a master release that features the other releases. unfortunately this information isn't present in the API data, so i want to do the same thing by grouping the <release>-nodes with the same <title>-tags, or add a flag to the <releases> that don't have a unique <title>? any good ideas on the best way of doing this? i also like to know if it's possible to count the <release>-nodes (child of releases) that have the same type-attribute? like in this example count the releases with the type "Main"? maybe it's better to do this things with XMLReader or XPath?

    Read the article

  • Problem while adding new Object to CoreData App

    - by elementsense
    Hi Another Day, another CoreData problem,...but hopefully the last one now. Ok here is a copy of what I have : I have a List of Hotel Guests that stay in one Room and have Preferences. Once ready the user should select a guest and see the data and should also be able to add new guest, select the room (maintained also by application) and select their preferences (where the user can also add new preferences). The guest can have no or many preferences. So here is what I have so far. I created 3 Entities : - Rooms with roomnumber - Preferences with name - GuestInfo with name - with these Relationships room (Destination Rooms) and prefs (Destination Preferences with "To-Many Relationship") The prefs is a NSSet when you create a Managed Object Class. Now I created a UITableViewController to display all the data. I also have an edit and add mode. When I add a new Guest and just fill out the name, everything works fine. But when I want to add the prefs or the room number I get this error : Illegal attempt to establish a relationship 'room' between objects in different contexts Now, what confuses me is that when I add a guest and enter just the name, save it, go back and edit it and select the prefs and room number it works ? I have this line in both ViewControllers to select the room or prefs : [editedObject setValue:selectedRoom forKey:editedFieldKey]; with this .h : NSManagedObject *editedObject; NSString *editedFieldKey; NSString *editedFieldName; Again, it works on the editing mode but not when I want to add a fresh object. And to be sure, this is what I do for adding an new Guest : - (IBAction)addNewItem { AddViewController *addViewController = [[AddViewController alloc] initWithStyle:UITableViewStyleGrouped]; addViewController.delegate = self; addViewController.context = _context; // Create a new managed object context for the new book -- set its persistent store coordinator to the same as that from the fetched results controller's context. NSManagedObjectContext *addingContext = [[NSManagedObjectContext alloc] init]; self.addingManagedObjectContext = addingContext; [addingContext release]; [addingManagedObjectContext setPersistentStoreCoordinator:[[_fetchedResultsController managedObjectContext] persistentStoreCoordinator]]; GuestInfo *info = (GuestInfo *)[NSEntityDescription insertNewObjectForEntityForName:@"GuestInfo" inManagedObjectContext:addingContext]; addViewController.info = info; UINavigationController *navController = [[UINavigationController alloc] initWithRootViewController:addViewController]; [self.navigationController presentModalViewController:navController animated:YES]; [addViewController release]; [navController release]; } Anything I have to do to initialize the Room or Prefs ? Hope someone can help me out. Thanks

    Read the article

  • PHP - Retrieve Data From mySQL Server

    - by Kevin
    Hello, Does anyone know how to retrieve a piece of data and display the results in php file? A similar query that I would enter is something like this: SELECT 'email' FROM 'users' WHERE 'username' = 'bob' Thus, the result would be just the email. Thanks, Kevin

    Read the article

  • Populate data and submit on external page

    - by joey m
    Hi, Is is possible to populate data on an external website (example mail.yahoo.com) and subsequently submit the page by using javascript executed from my own webpage? Or is there another way to do this. I am trying to figure out how to do an autologin function into external website. Thanks.

    Read the article

  • MySql.Data.MySqlClient.MySqlException: There is no 'root'@'%' registered

    - by user2963902
    i run web application on iis 6 , windows server 2003 , mysql database. first it was working fine, but when i reconfigured the mysql server with the same password it gave me this message error when i want to enter any page in browser : "MySql.Data.MySqlClient.MySqlException: There is no 'root'@'%' registered". i checked the app connection it's the same, as though the app doesn't see the localhost , because "dbforge" sometimes give me this message: "connection localhost cannot be found" but when i doubleclick the connection it opens as root. any idea to solve this problem

    Read the article

  • How to get the binary data from a download link

    - by jacob
    Hi all, I need to get the binary data of a download link. When I run this link in the browser it always starts download manager. Rather I would like to copy that binary and display it on teh browser. How is this possible in any language. Objective c or c# preferred. Thanks

    Read the article

  • Connecting CoreData to my App on an iPhone Device

    - by Lauren Quantrell
    I apologize ahead of time for what I'm sure is a complete newbie lapse. Running my iPhone app on iPhone simulator - no problem. But I loaded the app on an iPhone device for the first time and it appears as if the SQLite database I'm using (NSManagedObjectContext) isn't connected or didn't upload. The app installs but with no data. How do I get it all to upload and work on the device? I appreciate any help. lq

    Read the article

  • Multi Pivoting on single Source data

    - by Nev_Rahd
    I am trying to mutlipivot source data (as below ) want results as single column (as below) My query so far is SELECT * FROM ( SELECT * FROM ( SELECT NK, DC, VERSION, GEV FROM MULTIPIVOT ) SRC PIVOT ( MAX(GEV) FOR DC IN ( [10], [11], [12], [18] ) ) AS PVT ) SRC PIVOT ( MAX([18]) FOR VERSION IN ( [2006], [2007], [2008],[2009] ) )AS PVT which outputs results as what is the way to get this as single row? Thanks

    Read the article

  • Obtain user activity data in emails after I programmatically mail out emails

    - by John
    If I were to build a newsletter emailing system, I will need to be able to generate reports on how many emails bounced, flagged as spam, unsubscribed, read vs. unread, click through rates etc.... So how do you keep track of user activity after the email has been sent? Am I right in assuming that you CAN NOT embed javascript code into emails to monitor user activity? How else do I gather data for my reports?

    Read the article

  • selecting data from table based on date .

    - by mehdi
    i have database table like this +-------+--------------+----------+ | id | ip | date | +-------+--------------+----------+ | 505 |192.168.100.1 |2010-04-03| | 252 |192.168.100.5 |2010-03-03| | 426 |192.168.100.6 |2010-03-03| | 201 |192.168.100.7 |2010-04-03| | 211 |192.168.100.10|2010-04-03| +-------+--------------+----------+ how can i retirive data from this table where month=03 how to write sql to do that . select * from table where month=03 something like that .

    Read the article

  • In a star schema, are foreign key constraints between facts and dimensions neccessary?

    - by Garett
    I'm getting my first exposure to data warehousing, and I’m wondering is it necessary to have foreign key constraints between facts and dimensions. Are there any major downsides for not having them? I’m currently working with a relational star schema. In traditional applications I’m used to having them, but I started to wonder if they were needed in this case. I’m currently working in a SQL Server 2005 environment.

    Read the article

  • Apple Push Notification with Sending Custom Data

    - by SharmaJI
    I am sending push notifications from php job application to iphone. I am sending push notifications regarding new jobs. Is this possible that when user click on the view of push notification pop up , then user redirect to the particular job in the device. I mean I wanted to know can I send any custom data with push notification like jobId,something else....so that Iphone end Can retrieve and show the particular job ? Thanks.

    Read the article

< Previous Page | 292 293 294 295 296 297 298 299 300 301 302 303  | Next Page >