Search Results

Search found 8646 results on 346 pages for 'echo flow'.

Page 297/346 | < Previous Page | 293 294 295 296 297 298 299 300 301 302 303 304  | Next Page >

  • PHP: How To Integrate HTML Purifier To Fileter User Submitted Data?

    - by TaG
    I have this script that collects data from users and I wanted to check their data for malicious code like XSS and SQL injections by using HTML Purifier http://htmlpurifier.org/ but how do I add it to my php form submission script? Here is my HTML purifier code require_once '../../htmlpurifier/library/HTMLPurifier.auto.php'; $config = HTMLPurifier_Config::createDefault(); $config->set('Core.Encoding', 'UTF-8'); // replace with your encoding $config->set('HTML.Doctype', 'XHTML 1.0 Strict'); // replace with your doctype $purifier = new HTMLPurifier($config); $clean_html = $purifier->purify($dirty_html); Here is my PHP form submission code. if (isset($_POST['submitted'])) { // Handle the form. $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, profile.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $about_me = mysqli_real_escape_string($mysqli, $_POST['about_me']); $interests = mysqli_real_escape_string($mysqli, $_POST['interests']); if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO profile (user_id, about_me, interests) VALUES ('$user_id', '$about_me', '$interests')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE profile SET about_me = '$about_me', interests = '$interests' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } }

    Read the article

  • Jquery Using Jeditable and activating on click

    - by BandonRandon
    I found this to be almost exactly what I'm trying to do. I'm using Jeditable I can get the default setup to work. I've also been able to get the code in the forum above to work. I believe my problem is that because I'm using a table I need to so something else to select the previous element. Here is my HTML <table> <tr> <td width="5%"><input class="cat_checkbox" type="checkbox" name='delete_cat[]' value='<?php echo("$cat_data[cat_id]");?>' /></td> <td width="90%" class="edit_cat_title" id='unique_id'>Category</td> <td width="5%"><a href="#" class="edit_cat_title_trigger"><img src="images/edit.gif" border="0"></a></td> </tr> </table> and here is my JQuery: //modify title content on the fly $('.edit_cat_title').editable('action.php', { name : 'cat_title', indicator : 'Saving...', submit : 'OK', cancel : 'Cancel', tooltip:'click to edit', event : 'edit' }); //trigger with the click of the edit image $(".edit_cat_title_trigger").bind("click", function() { $(this).prev().trigger("edit_cat_title"); }); I know I probably should be able to figure it out and I know all i have to do is change $(this).prev().trigger("edit_cat_title"); to the right thing but I'm still really new to Jquery. Thanks

    Read the article

  • Zend Framework cleaning default routes when adding other

    - by Renato Aquino
    I have the following problem with Zend Framework. My project has several controllers like Video,Category and Post. The VideoController has an Action called categorylist, so the default URL/Route becomes /video/categorylist Since the action requires 3 parameters I whant to add one simple route: $router->addRoute( 'categorylist', new Zend_Controller_Router_Route('categorylist/:category/:page/:per_page', array('controller' => 'video', 'action' => 'categorylist','page'=>1,'per_page'=>6,'category'=>1)) ); With this I got my URL like www.siteurl.com/categorylist/42/1/6 but, the View Helper URL got crazy, and every url for the other controllers I try to echo it´s redirected to the categorylist route. So when I try this: <?= $this->url(array("controller"=> "video", "action" =>"view",'category'=>1),null,true)?> The expected result its /video/view/category/1, but I got /categorylit only. I tryied to debug the default routes but I got an empty array. print_r($ctrl->getRouter()->getRoutes()); Does anyone have some clue about this wierd behavior? I´m using Zend Framework Version 1.9.7

    Read the article

  • code igniter codeigniter question, making anchor load page containing data from referenced row in DB

    - by thrice801
    Hi, Im trying to learn the code igniter library and object oriented php in general and have a question. Ok so Ive gotten as far as making a page which loads all of the rows from my database and in there, Im echoing an anchor tag which is a link to the following structure. [code]echo anchor("videos/video/$row-video_id", $row-video_title);[/code] So, I have a class called Videos which extends the controller, within that class there is index and video, which is being called correctly (when you click on the video title, it sends you to videos/video/5 for example, 5 being the primary key of the table im working with. So basically all Im trying to do is pass that 5 back to the controller, and then have the particular video page output the particular rows data from the videos table. My function in my controller for video looks like this - [code] function video() { $data['main_content'] = 'video'; $data['video_title'] = 'test'; $this-load-view('includes/template', $data); } [/code] So ya, basically test should be instead of test, a returned value of a query which says get in the table "videos", the row with the video_id of "5", and make $data['video_title'] = value of video_title in database... Should have this figured out by now but dont, any help would be appreciated!

    Read the article

  • highlighting search results in php/mysql

    - by fusion
    how do i highlight search results from mysql query using php? this is my code: $search_result = ""; $search_result = $_GET["q"]; $result = mysql_query('SELECT cQuotes, vAuthor, cArabic, vReference FROM thquotes WHERE cQuotes LIKE "%' . $search_result .'%" ORDER BY idQuotes DESC', $conn) or die ('Error: '.mysql_error()); function h($s) { echo htmlspecialchars($s, ENT_QUOTES); } ?> <div class="center_div"> <table> <caption>Search Results</caption> <?php while ($row= mysql_fetch_array($result)) { ?> <tr> <td style="text-align:right; font-size:15px;"><?php h($row['cArabic']) ?></td> <td style="font-size:16px;"><?php h($row['cQuotes']) ?></td> <td style="font-size:12px;"><?php h($row['vAuthor']) ?></td> <td style="font-size:12px; font-style:italic; text-align:right;"><?php h($row['vReference']) ?></td> </tr> <?php } ?> </table> </div>

    Read the article

  • maintaining continuous count in php

    - by LiveEn
    I have a small problem maintain a count for the position. i have written a function function that will select all the users within a page and positions them in the order. Eg: Mike Position 1 Steve Postion 2.............. .... Jacob Position 30 but the problem that i have when i move to the second page, the count is started from first Eg: Jenny should be number 31 but the list goes, Jenny Position 1 Tanya Position 2....... Below is my function function nrk($duty,$page,$position) { $url="http://www.test.com/people.php?q=$duty&start=$page"; $ch=curl_init(); curl_setopt($ch,CURLOPT_URL,$url); $result=curl_exec($ch); $dom = new DOMDocument(); @$dom->loadHTML($result); $xpath=new DOMXPath($dom); $elements = $xpath->evaluate("//div"); foreach ($elements as $element) { $name = $element->getElementsByTagName("name")->item(0)->nodeValue; $position=$position+1; echo $name." Position:".$position."<br>"; } return $position; } Below is the for loop where i try to loop thru the page count for ($page=0;$page<=$pageNumb;$page=$page + 10) { nrk($duty,$page,$position); } I dont want to maintain a array key value in the for each coz i drop certain names...

    Read the article

  • php json jquery and select box

    - by user253530
    I have this php code $jsonArray = array(); $sql = "SELECT ID,CLIENT FROM PLD_SERVERS"; $result = mysql_query($sql); while($row = mysql_fetch_array($result)) { $jsonArray[] = array('id'=>$row['ID'],'client'=>$row['CLIENT']); } echo json_encode($jsonArray); And this js function autosearchLoadServers() { $.post("php/autosearch-load-servers.php",function(data){ var toAppend = ""; for(var i = 0; i < data.length; i++){ toAppend += '<option value = \"' + data[i].id + '\">' + data[i].client + '</option>'; } $("#serverSelect").empty(); $("#serverSelect").html(toAppend); }); } The problem is that i get only undefined values. How can this be? The values are in the JSON, i checked using firebug in mozilla so there has to be something with the data variable but i can't understand what. I tried different ways and no results.

    Read the article

  • Loop XML including all its children using xpath and SimpleXMLElement

    - by Andersson
    Im having a big xml tree with a simple structure. All I want to do is get a node by its attribute using xpath and loop the children. param1 - correct language param1 & param3 - correct node by its id and the parents id. (Need to use parent id when multiplie id appears. The id is not declared as id in DTD) public function getSubmenuNodesRe($language, $id1,$id2) { $result = $this->xml->xpath("//*[@language='$language']//*[@id='$id1']//menuitem[@id='$id2']/*"); return $result; } This works well, I get the node Im expecting. I having no problems looping the array returned by the xpath query. But when i try to loop childnodes all attributes are gone and many of the methods also. Except getName(). function printNodeName($node) { echo $node->getName(). " - \"" . $node['id']. "\"<br>"; if($node->children()->getName() == "menuitem") { $s = $node->children(); printNodeName($s); } } $result = $xmlNode->getSubmenuNodesRe($_GET['language'], 'foo','bar'); if ($result) { while(list( , $node) = each($result)) { if ($node->getName() == "menuitem") { printNodeName($node); } } } Why is that? only the name will be printed for the $s. Really need help to solve this one, any assistance is deeply appreciated! Thanks for your time.

    Read the article

  • PHP - fgetcsv - Delimiter being ignored?

    - by KnockKnockWhosThere
    I'm trying to output each line in a csv file, and it seems like the delimiter is being ignored... I'm sure my syntax is wrong somewhere, but can't seem to pinpoint it... The CSV file looks like this: ID,Code,Count TM768889,02001,10 TM768889,02002,10 TM768889,02003,10 TM768889,02004,10 TM768889,02005,10 I'm trying to output: 0 - ID,Code,Count 1 - TM768889,02001,10 2 - TM768889,02002,10 3 - TM768889,02003,10 4 - TM768889,02004,10 5 - TM768889,02005,10 But instead, it's outputting this: 0 - ID 1 - Code 2 - Count TM768889 3 - 02001 4 - 10 TM768889 5 - 02002 6 - 10 TM768889 7 - 02003 8 - 10 TM768889 9 - 02004 10 - 10 TM768889 11 - 02005 12 - 10 Here's my code: $row = 0; if(($handle = fopen($_FILES["Filedata"]["tmp_name"], "r")) !== FALSE) { $string = ''; while(($line = fgetcsv($handle,1000,",")) !== FALSE) { $num = count($line); $row++; for($c=0; $c < $num; $c++) { $string .= $c.' - '.$line[$c].'<br />'; } } fclose($handle); echo $string; }

    Read the article

  • Web Hosting URL Length Limit?

    - by Isaac Waller
    Hello, I am designing a web application which is a tie in to my iPhone application. It sends massively large URLs to the web server (15000 about.) I was using NearlyFreeSpeech.net, but they only support URLS up to 2000 characters. I was wondering if anybody knows of web hosting that will support really large URLs? Thanks, Isaac Edit: My program needs to open a picture in Safari. I could do this 2 ways: send it base64 encoded in the URL and just echo the query parameters. first POST it to the server in my application, then the server would send back a unique ID after storing the photo in a database, which I would append to a URL which I would open in Safari which retrieved the photo from the database and delete it from the database. You see, I am lazy, and I know Mobile Safari can support URI's up to 80 000 characters, so I think this is a OK way to do it. If there is something really wrong with this, please tell me. Edit: I ended up doing it the proper POST way. Thanks.

    Read the article

  • PHP and curl for fetching currency rate from Yahoo Finance

    - by gregj
    Hello, I wrote the following php snippet to fetch the currency conversion rate from Yahoo Finance.Im using curl to fetch the data. Suppose, i want to convert from US dollars (USD) to Indian National Rupee (INR),then the url is http://in.finance.yahoo.com/currency/convert?amt=1&from=USD&to=INR&submit= and the Indian Rupee value is shown as 45.225. However,if i run my code, the value im getting is 452.25. Why this discrepancy ? <?php $amount = $_GET['amount']; $from = $_GET['from']; $to = $_GET['to']; $url = "http://in.finance.yahoo.com/currency/convert?amt=".$amount."&from=".$from."&to=".$to; $handle = curl_init($url); curl_setopt ($handle, CURLOPT_RETURNTRANSFER, true); $data = curl_exec($handle); if(preg_match_all('/<td class="yfnc_tabledata1"><b>(?:[1-9]\d+|\d)(?:\.\d\d)?/',$data,$matches)) { print_r($matches[0][1]); } else { echo "Not found !"; } curl_close($handle); ?> Is there something wrong with my regex ? Please help. Thank You.

    Read the article

  • ZIP Numerous Blob Files

    - by Michael
    I have a database table that contains numerous PDF blob files. I am attempting to combine all of the files into a single ZIP file that I can download and then print. Please help! <?php include 'config.php'; include 'connect.php'; $session= $_GET[session]; $query = " SELECT $tbl_uploads.username, $tbl_uploads.description, $tbl_uploads.type, $tbl_uploads.size, $tbl_uploads.content, $tbl_members.session FROM $tbl_uploads LEFT JOIN $tbl_members ON $tbl_uploads.username = $tbl_members.username WHERE $tbl_members.session= '$session'"; $result = mysql_query($query) or die('Error, query failed'); while(list($username, $description, $type, $size, $content) = mysql_fetch_array($result)) { header("Content-length: $size"); header("Content-type: $type"); header("Content-Disposition: inline; filename=$username-$description.pdf"); echo $content; } $files = array('File 1 from database', 'File 2 from database'); $zip = new ZipArchive; $zip->open('file.zip', ZipArchive::CREATE); foreach ($files as $file) { $zip->addFile($file); } $zip->close(); header('Content-Type: application/zip'); header('Content-disposition: attachment; filename=filename.zip'); header('Content-Length: ' . filesize($zipfilename)); readfile($zipname); mysql_close($link); exit; ?>

    Read the article

  • How to add text to email sent from a php contact form

    - by JustStatic
    Hi all this is the PHP im using: <?php $name = $_POST['name']; $email = $_POST['email']; $phone = $_POST['phone']; $message = $_POST['message']; $formcontent=" From: $name \n Phone: $phone \n Message: $message"; $recipient = "[email protected]"; $subject = "Contact Form"; $mailheader = "From: $email \r\n"; mail($recipient, $subject, $formcontent, $mailheader) or die("Error!"); echo "Thank You!" . " -" . "<a href='contact.html' style='text-decoration:none; color:#ff0099;'> Return Home</a>"; ?> Its working perfectly fine but i would like there to be some text sent with this email that says "This is from your website" or something similar to tell the recipient that it isnt spam (my client isn't tech friendly and sees everything plain text as spam). I'm very new to PHP with nearly 0 knowledge and have no idea how to add something like that. I did have a go at making a new variable with the string inside and then include that in the: mail($recipient, $subject, $formcontent, $mailheader) or die("Error!"); line but with no success. Thanks for taking the time any help would be welcome.

    Read the article

  • PHP alternating colors

    - by Jordan Pagaduan
    $dbc = mysql_connect('localhost','root','') or die (mysql_error()); mysql_select_db('payroll') or die (mysql_error()); $sql = "SELECT * FROM employee ORDER BY employee_id DESC"; $result = mysql_query($sql); while($row = mysql_fetch_array($result)) { echo " <tr> <td style=\"padding-left: 20px; border-bottom: 1px solid #999; border-right: 1px solid #999;\">".$row['first_name']." ".$row['last_name']."</td> <td style=\"text-align: center; border-bottom: 1px solid #999; border-right: 1px solid #999; padding-top: 2px ; padding-bottom: 3px ;\"><input type=\"button\" name=\"edit\" value=\"Edit\" class=\"selbtn\">&nbsp;<input type=\"button\" name=\"delete\" value=\"Delete\" class=\"selbtn\"></td> </tr> "; } I wanted to add an alternating color in the loop. what code should I add?

    Read the article

  • php POST response

    - by amit
    I am making a POST to another php file that I want to render in the browser. so clearly, using jquery POST wont work, since it works through AJAX. echo '<div class="showcase_URL"><a class="purl" name="'.$row->num.'" href="#">PROJECT URL</a></div>'; what I have till now in javascript is: $(".showcase_URL a").click(function() { //alert($(this).attr("name")); var number = $(this).attr("name"); $.post( "app-display.php", {app: number}, function(data){ top.location.href = 'app-display.php'; }); }); what I have in app-display.php: $query = 'SELECT num, title, thumb_url, url, type, cat, dated, details FROM app WHERE `num` = "$_POST[app]"'; but it is currently giving me a page without the contents of app-display.php. all the other fragments of the page are loading: header, footer etc. the PHP Response (in Firebug) I am getting is the normal html of the page. how should i do it?

    Read the article

  • Zend/PHP: How to disable webpage behind popup ?

    - by NAVEED
    I am working on zend framework, PHP and jQuery. I am working on popups sometimes. When any popup is open on the screen, we can still clicks links on webpage behind popup which causes some unexpected behaviour. How can I disable a webpage behind popup. I have seen some web application in which when popup appears then webpage behind popup become shady. I have read some tutorial about this. In each tutorial a link is used to open a dialog and an special attribute is added in for modal. But I have a different case I have to open dialog on some condition in action. I check a condition in action after post like this: $form = new Edit_Form( ); $this->view->form = $form; $this->view->form->setAction($this->view->url()); $request = $this->getRequest(); if ( $request->isPost() ) { $values = $request->getParams(); if( $values['edit'] ) { $this->view->openEditBox(); } } Now check in view to see that it should open an edit pop or not: if( $this->openEditBox ){ $jsonOutput ['content'] = '<div class="DialogBox" title="Edit">' . $this->form->render() . '</div>'; echo Zend_Json::encode($jsonOutput); } Any Idea? Thanks

    Read the article

  • Getting Started with Ruby & Ruby on Rails

    - by JakeTheSnake
    Some background: I'm a jack-of-all traits, one of which is programming. I learned VB6 through Excel and PHP for creating websites and so far it's worked out just fine for me. I'm not CS major or even mathematically inclined - logic is what interests me. Current status: I'm willing to learn new and more powerful languages; my first foray into such a route is learning Ruby. I went to the main Ruby website and did the interactive intro. (by the way, I'm currently getting redirected to google.com when I try the link...it's happening to other websites as well...is my computer infected?) I liked what I learned and wanted to get started using Ruby to create websites. I downloaded InstantRails and installed it; everything so far has been fine - the program starts up just fine, and I can test some Ruby code in the console. However my troubles begin when I try and view a web page with Ruby code present. Lastly, my problem: As in PHP, I can browse to the .php file directly and through using PHP tags and some simple 'echo' statements I can be on my way in making dynamic web pages. However with the InstantRails app working, accessing a .rb or .rhtml page doesn't produce similar results. I made a simple text file named 'test.rb' and put basic HTML tags in there (html, head, body) and the Ruby tags <%= and % with some ruby code inside. The web page actually shows the tags and the code - as if it's all just plain HTML. I take it Ruby isn't parsing the page before it is displayed to the user, but this is where my lack of understanding of the Ruby environment stops me short. Where do I go from here?

    Read the article

  • Hazelcast Distributed Executor Service KeyOwner

    - by János Veres
    I have problem understanding the concept of Hazelcast Distributed Execution. It is said to be able to perform the execution on the owner instance of a specific key. From Documentation: <T> Future<T> submitToKeyOwner(Callable<T> task, Object key) Submits task to owner of the specified key and returns a Future representing that task. Parameters: task - task key - key Returns: a Future representing pending completion of the task I believe that I'm not alone to have a cluster built with multiple maps which might actually use the same key for different purposes, holding different objects (e.g. something along the following setup): IMap<String, ObjectTypeA> firstMap = HazelcastInstance.getMap("firstMap"); IMap<String, ObjectTypeA_AppendixClass> secondMap = HazelcastInstance.getMap("secondMap"); To me it seems quite confusing what documentation says about the owner of a key. My real frustration is that I don't know WHICH - in which map - key does it refer to? The documentation also gives a "demo" of this approach: import com.hazelcast.core.Member; import com.hazelcast.core.Hazelcast; import com.hazelcast.core.IExecutorService; import java.util.concurrent.Callable; import java.util.concurrent.Future; import java.util.Set; import com.hazelcast.config.Config; public void echoOnTheMemberOwningTheKey(String input, Object key) throws Exception { Callable<String> task = new Echo(input); HazelcastInstance hz = Hazelcast.newHazelcastInstance(); IExecutorService executorService = hz.getExecutorService("default"); Future<String> future = executorService.submitToKeyOwner(task, key); String echoResult = future.get(); } Here's a link to the documentation site: Hazelcast MultiHTML Documentation 3.0 - Distributed Execution Did any of you guys figure out in the past what key does it want?

    Read the article

  • Perl cron job stays running

    - by Dylan
    I'm currently using a cron job to have a Perl script that tells my Arduino to cycle my aquaponics system and all is well, except the Perl script doesn't die as intended. Here is my cron job: */15 * * * * /home/dburke/scripts/hal/bin/main.pl cycle And below is my Perl script: #!/usr/bin/perl -w # Sample Perl script to transmit number # to Arduino then listen for the Arduino # to echo it back use strict; use Device::SerialPort; use Switch; use Time::HiRes qw ( alarm ); $|++; # Set up the serial port # 19200, 81N on the USB ftdi driver my $device = '/dev/arduino0'; # Tomoc has to use a different tty for testing #$device = '/dev/ttyS0'; my $port = new Device::SerialPort ($device) or die('Unable to open connection to device');; $port->databits(8); $port->baudrate(19200); $port->parity("none"); $port->stopbits(1); my $lastChoice = ' '; my $pid = fork(); my $signalOut; my $args = shift(@ARGV); # Parent must wait for child to exit before exiting itself on CTRL+C $SIG{'INT'} = sub { waitpid($pid,0) if $pid != 0; exit(0); }; # What child process should do if($pid == 0) { # Poll to see if any data is coming in print "\nListening...\n\n"; while (1) { my $incmsg = $port->lookfor(9); # If we get data, then print it if ($incmsg) { print "\nFrom arduino: " . $incmsg . "\n\n"; } } } # What parent process should do else { if ($args eq "cycle") { my $stop = 0; sleep(1); $SIG{ALRM} = sub { print "Expecting plant bed to be full; please check.\n"; $signalOut = $port->write('2'); # Signal to set pin 3 low print "Sent cmd: 2\n"; $stop = 1; }; $signalOut = $port->write('1'); # Signal to arduino to set pin 3 High print "Sent cmd: 1\n"; print "Waiting for plant bed to fill...\n"; alarm (420); while ($stop == 0) { sleep(2); } die "Done."; } else { sleep(1); my $choice = ' '; print "Please pick an option you'd like to use:\n"; while(1) { print " [1] Cycle [2] Relay OFF [3] Relay ON [4] Config [$lastChoice]: "; chomp($choice = <STDIN>); switch ($choice) { case /1/ { $SIG{ALRM} = sub { print "Expecting plant bed to be full; please check.\n"; $signalOut = $port->write('2'); # Signal to set pin 3 low print "Sent cmd: 2\n"; }; $signalOut = $port->write('1'); # Signal to arduino to set pin 3 High print "Sent cmd: 1\n"; print "Waiting for plant bed to fill...\n"; alarm (420); $lastChoice = $choice; } case /2/ { $signalOut = $port->write('2'); # Signal to set pin 3 low print "Sent cmd: 2"; $lastChoice = $choice; } case /3/ { $signalOut = $port->write('1'); # Signal to arduino to set pin 3 High print "Sent cmd: 1"; $lastChoice = $choice; } case /4/ { print "There is no configuration available yet. Please stab the developer."; } else { print "Please select a valid option.\n\n"; } } } } } Why wouldn't it die from the statement die "Done.";? It runs fine from the command line and also interprets the 'cycle' argument fine. When it runs in cron it runs fine, however, the process never dies and while each process doesn't continue to cycle the system it does seem to be looping in some way due to the fact that it ups my system load very quickly. If you'd like more information, just ask. EDIT: I have changed to code to: #!/usr/bin/perl -w # Sample Perl script to transmit number # to Arduino then listen for the Arduino # to echo it back use strict; use Device::SerialPort; use Switch; use Time::HiRes qw ( alarm ); $|++; # Set up the serial port # 19200, 81N on the USB ftdi driver my $device = '/dev/arduino0'; # Tomoc has to use a different tty for testing #$device = '/dev/ttyS0'; my $port = new Device::SerialPort ($device) or die('Unable to open connection to device');; $port->databits(8); $port->baudrate(19200); $port->parity("none"); $port->stopbits(1); my $lastChoice = ' '; my $signalOut; my $args = shift(@ARGV); # Parent must wait for child to exit before exiting itself on CTRL+C if ($args eq "cycle") { open (LOG, '>>log.txt'); print LOG "Cycle started.\n"; my $stop = 0; sleep(2); $SIG{ALRM} = sub { print "Expecting plant bed to be full; please check.\n"; $signalOut = $port->write('2'); # Signal to set pin 3 low print "Sent cmd: 2\n"; $stop = 1; }; $signalOut = $port->write('1'); # Signal to arduino to set pin 3 High print "Sent cmd: 1\n"; print "Waiting for plant bed to fill...\n"; print LOG "Alarm is being set.\n"; alarm (420); print LOG "Alarm is set.\n"; while ($stop == 0) { print LOG "In while-sleep loop.\n"; sleep(2); } print LOG "The loop has been escaped.\n"; die "Done."; print LOG "No one should ever see this."; } else { my $pid = fork(); $SIG{'INT'} = sub { waitpid($pid,0) if $pid != 0; exit(0); }; # What child process should do if($pid == 0) { # Poll to see if any data is coming in print "\nListening...\n\n"; while (1) { my $incmsg = $port->lookfor(9); # If we get data, then print it if ($incmsg) { print "\nFrom arduino: " . $incmsg . "\n\n"; } } } # What parent process should do else { sleep(1); my $choice = ' '; print "Please pick an option you'd like to use:\n"; while(1) { print " [1] Cycle [2] Relay OFF [3] Relay ON [4] Config [$lastChoice]: "; chomp($choice = <STDIN>); switch ($choice) { case /1/ { $SIG{ALRM} = sub { print "Expecting plant bed to be full; please check.\n"; $signalOut = $port->write('2'); # Signal to set pin 3 low print "Sent cmd: 2\n"; }; $signalOut = $port->write('1'); # Signal to arduino to set pin 3 High print "Sent cmd: 1\n"; print "Waiting for plant bed to fill...\n"; alarm (420); $lastChoice = $choice; } case /2/ { $signalOut = $port->write('2'); # Signal to set pin 3 low print "Sent cmd: 2"; $lastChoice = $choice; } case /3/ { $signalOut = $port->write('1'); # Signal to arduino to set pin 3 High print "Sent cmd: 1"; $lastChoice = $choice; } case /4/ { print "There is no configuration available yet. Please stab the developer."; } else { print "Please select a valid option.\n\n"; } } } } }

    Read the article

  • Send POSTs to a PHP script on a server

    - by Sam Jarman
    I have a PHP script on a server <?php // retrieve POST vars $comment = $_POST['comment']; $email = $_POST['email']; // remove trailing whitespace etc $comment = trim($comment); $email = trim($email); // format date accoring to http://www.w3schools.com/php/func_date_date.asp $date_time = date("Y-m-d-H-i-s"); // i.e. 2010-04-15-09-45-23 // prepare message $to = "(removed my email addy)"; //who to send the mail to $subject = "Feedback from iPhone app"; //what to put in the subject line $message = "Name/Email: $email \r\n Comment: $comment"; mail($to, $subject,$message) or "bad"; echo "ok"; ?> How do I now send a POST request from my iPhone app... ive tried this sort of thing... NSURL *url = [NSURL URLWithString:@"mysite.com/script.php"]; NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url]; [request setHTTPMethod:@"POST"]; NSString *message = boxForSuggestion.text; NSString *userEmailString = usersEmail.text; NSString *requestBodyString = [NSString stringWithFormat:@"comment:%@&email%@", message , userEmailString]; NSData *requestBody = [requestBodyString dataUsingEncoding:NSUTF8StringEncoding]; [request setHTTPMethod:@"POST" [request setHTTPBody:requestBody]; NSURLResponse *response = NULL; NSError *requestError = NULL; NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&requestError]; NSString *responseString = [[[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding] autorelease]; NSLog(@"%@", responseString); Any ideas? Thanks guys Sam

    Read the article

  • Error handling in PHP

    - by Industrial
    Hi guys, We're building a PHP app based on Good old MVC (codeigniter framework) and have run into trouble with a massive chained action that consists of multiple model calls, that together is a part of a big transaction to the database. We want to be able to do a list of actions and get a status report of each one back from the function, whatever the outcome is. Our first initial idea was to utilize the exceptions of PHP5, but since we want to also need status messages that doesnt break the execution of the script, this was our solution that we came up with. It goes a little something like this: $sku = $this->addSku( $name ); if ($sku === false) { $status[] = 'Something gone terrible wrong'; $this->db->trans_rollback(); return $status; } $image= $this->addImage( $filename); if ($image=== false) { $error[] = 'Image could not be uploaded, check filesize'; $this->db->trans_rollback(); return $status; } Our controller looks like this: $var = $this->products->addProductGroup($array); if (is_array($var)) { foreach ($var as $error) { echo $error . '<br />'; } } It appears to be a very fragile solution to do what we need, but it's neither scalable, neither effective when compared to pure PHP exceptions for instance. Is this really the way that this kind of stuff generally is handled in MVC based apps? Thanks!

    Read the article

  • Moving a large number of files in one directory to multiple directories

    - by Axsuul
    I am looking to create a Windows batch script to move about 2,000 files and splitting them up so that there are 10 files per folder. I have attempted creating a batch script but the syntax really boggles my mind. Here is what I have so far @echo off :: Config parameters set /a groupsize = 10 :: initial counter, everytime counter is 1, we create new folder set /a n = 1 :: folder counter set /a nf = 1 for %%f in (*.txt) do ( :: if counter is 1, create new folder if %n% == 1 ( md folder%nf% set /a n += 1 ) :: move file into folder mv -Y %%f folder%nf%\%%f :: reset counter if larger than group size if %n% == %groupsize% ( set /a n = 1 ) else ( set /a n += 1 ) ) pause Basically what this script does is loop through each .txt file in the directory. It creates a new directory in the beginning and moves 10 files into that directory, then creates a new folder again and moves another 10 files into that directory, and so on. However, I'm having problems where the n variable is not being incremented in the loop? I'm sure there's other errors too since the CMD window closes on me even with pause. Any help or guidance is appreciated, thanks for your time!

    Read the article

  • How can I protect this code from SQL Injection? A bit confused.

    - by Craig Whitley
    I've read various sources but I'm unsure how to implement them into my code. I was wondering if somebody could give me a quick hand with it? Once I've been shown how to do it once in my code I'll be able to pick it up I think! This is from an AJAX autocomplete I found on the net, although I saw something to do with it being vulnerable to SQL Injection due to the '%$queryString%' or something? Any help really appreciated! if ( isset( $_POST['queryString'] ) ) { $queryString = $_POST['queryString']; if ( strlen( $queryString ) > 0 ) { $query = "SELECT game_title, game_id FROM games WHERE game_title LIKE '%$queryString%' || alt LIKE '%$queryString%' LIMIT 10"; $result = mysql_query( $query, $db ) or die( "There is an error in database please contact [email protected]" ); while ( $row = mysql_fetch_array( $result ) ) { $game_id = $row['game_id']; echo '<li onClick="fill(\'' . $row['game_title'] . '\',' . $game_id . ');">' . $row['game_title'] . '</li>'; } } }

    Read the article

  • Enter ID instead of name on submit (form)

    - by Derek
    In my activities table, I have a user ID and a project ID. When a user (of admin level) creates an activity they select from a drop down menu a project. Here is the select query to draw up appropriate values: $sql = "SELECT usersprojects_tb.projectid, projects.projectname FROM projects INNER JOIN usersprojects on projects.projectid = usersprojects.projectid WHERE usersprojects.userid = '".$_SESSION['SESS_USERID']."'"; And for the tag with the dropdown menu, I have this: <?php echo $row['projectname']?> I have tried submitting the form with 'projectid' here instead and the project ID is stored successfully in my activies table. However, the user needs to see the project names (IDs arent exactly user-friendly!) And with 'projectname' as displayed, they can select the names of the available projects (to associate an activity with) but the project ID is not stored, how I link this up, so that when the project name is sent, the ID for this project is stored properly in my activities table. I'm also having the exact same problem with the users drop down. As the admin user selects a user from the drop down to assign the task to. I exactly what I want, but I think I may be using the wrong syntax! Any help is much appreciated. Thanks.

    Read the article

  • How to parse rss from a php page, using jQuery/jFeed?

    - by ricebowl
    I'm trying to fumble my way through parsing rss sensibly, using jQuery and jFeed. Because of the same origin policy I'm pulling the BBC's health news feed into a local page (http://www.davidrhysthomas.co.uk/play/proxy.php). Originally this was just the same proxy.php script as available in the jFeed download package, but due to my host's disabling allow_url_fopen() I've amended the php to the following: $url = "http://newsrss.bbc.co.uk/rss/newsonline_uk_edition/health/rss.xml"; $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $data = curl_exec($ch); echo "$data"; curl_close($ch); Which seems to generate the same/comparable contents as the original fopen on my local machine. Now that seems to be working, I'm looking at setting the jFeed script up to work with the page and, to my embarrassment, don't see how. I understand that, at the least, this should work: jQuery.getFeed({ url: 'http://www.davidrhysthomas.co.uk/play/proxy.php', success: function(feed) { alert(feed.title); } }); ...but, as I'm sure you anticipate, it doesn't. What non-output there is, is available for your perusal here: http://www.davidrhysthomas.co.uk/play/exampleTest.html. And I honestly don't have a clue what to do about it. If anyone could offer some pointers, tips, hints, or, at a pinch, a quick slap around the cheeks and a 'pull yourself together!' it'd be much appreciated... Thanks in advance =)

    Read the article

< Previous Page | 293 294 295 296 297 298 299 300 301 302 303 304  | Next Page >