Search Results

Search found 8646 results on 346 pages for 'echo flow'.

Page 299/346 | < Previous Page | 295 296 297 298 299 300 301 302 303 304 305 306  | Next Page >

  • help on ejb stateless datagram and message driven beans

    - by Kemmal
    i have a client thats sending a message to the ejbserver using UDP, i want the server(stateless bean) to echo back this message to the client but i cant seem to do this. or can i implement the same logic by using JMS? please help and enlighten. this is just a test, in the end i want a midp to be sending the message to the ejb using datagrams. here is my code. @Stateless public class SessionFacadeBean implements SessionFacadeRemote { public SessionFacadeBean() { } public static void main(String[] args) { DatagramSocket aSocket = null; byte[] buffer = null; try { while(true) { DatagramPacket request = new DatagramPacket(buffer, buffer.length); aSocket.receive(request); DatagramPacket reply = new DatagramPacket(request.getData(), request.getLength(), request.getAddress(), request.getPort()); aSocket.send(reply); } } catch (SocketException e) { System.out.println("Socket: " + e.getMessage()); } catch (IOException e) { System.out.println("IO: " + e.getMessage()); } finally { if(aSocket != null) aSocket.close(); } } } and the client: public static void main(String[] args) { DatagramSocket aSocket = null; try { aSocket = new DatagramSocket(); byte [] m = "Test message!".getBytes(); InetAddress aHost = InetAddress.getByName("localhost"); int serverPort = 6789; DatagramPacket request = new DatagramPacket(m, m.length, aHost, serverPort); aSocket.send(request); byte[] buffer = new byte[1000]; DatagramPacket reply = new DatagramPacket(buffer, buffer.length); aSocket.receive(reply); System.out.println("Reply: " + new String(reply.getData())); } catch (SocketException e) { System.out.println("Socket: " + e.getMessage()); } catch (IOException e) { System.out.println("IO: " + e.getMessage()); } finally { if(aSocket != null) aSocket.close(); } } please help.

    Read the article

  • PHP: Retrieving JSON via jQuery ajax help

    - by iamjonesy
    Hey I have a script that is creating and echoing a JSON encoded array of magento products. I have a script that calls this script using jQuery's ajax function but I'm not getting a proper response. This is the script that creates the array: $collection = Mage::getModel('catalog/product')->getCollection(); $collection->addAttributeToSelect('name'); $collection->addAttributeToSelect('price'); $products = array(); foreach ($collection as $product){ $products[$product->getPrice()] = $product->getName(); } header('Content-Type: application/x-json; charset=utf-8'); echo(json_encode($products)); Here is my jQuery: <select id="products"> <option value="#">Select</option> </select> <script type="text/javascript"> jQuery.noConflict(); jQuery(document).ready(function(){ jQuery.ajax({ type: "GET", url: "http://localhost.com/magento/modules/products/get.php", dataType: "json", success: function(products) { jQuery.each(products,function(price,name) { var opt = jQuery('<option />'); opt.val(name); opt.text(price); jQuery('#products').append(opt); }); } }); }); </script> I'm getting a response from this but I'm not seeing a any JSON. I'm using firebug. I can see there has been a JSON encoded response but the response tab is emtyp and my select boxes have no options. Can anyone see and problems with my code? Here is the response I should get: {"82.9230":"Dummy","177.0098":"Dummy 2","76.0208":"Dummy 3","470.6054":"Dummy 4","357.0083":"Dummy Product 5"} Thanks, Billy

    Read the article

  • OOP 101 - quick question.

    - by R Bennett
    I've used procedural for sometime now and trying to get a better understanding of OOP in Php. Starting at square 1 and I have a quick question ot get this to gel. Many of the basic examples show static values ( $bob-name = "Robert";) when assigning a value, but I want to pass values... say from a form ( $name = $_POST['name']; ) class Person { // define properties public $name; public $weight; public $age; public function title() { echo $this->name . " has submitted a request "; } } $bob = new Person; // want to plug the value in here $bob->name = $name; $bob->title(); I guess I'm getting a little hung up in some areas as far as accessing variables from within the class, encapsulation & "rules", etc., can $name = $_POST['name']; reside anywhere outside of the class or am I missing an important point? Thanks

    Read the article

  • save html-formatted text to database

    - by yozhik
    Hi all! I want to save html-formatted text to database, but when I do that it is don't save html-symbols like < / ' and others This is how I read article from database for editing: <p class="Title">??????????? ???????:</p> <textarea name="EN" cols="90" rows="20" value="<?php echo $articleArr['EN']; ?>" ></textarea> And this is how I save it to database: function UpdateArticle($ArticleID, $ParentName, $Title, $RU, $EN, $UKR) { //fetch data from database for dropdown lists //connect to db or die) $db = mysql_connect($GLOBALS["gl_dbName"], $GLOBALS["gl_UserName"], $GLOBALS["gl_Password"] ) or die ("Unable to connect"); //to prevenr ????? symbols in unicode - utf-8 coding mysql_query("SET NAMES 'UTF8'"); mysql_set_charset('utf8'); mysql_query("SET NAMES 'utf8' COLLATE 'utf8_general_ci'"); //select database mysql_select_db($GLOBALS["gl_adminDatabase"], $db); $sql = "UPDATE Articles SET AParentName='".$ParentName."', ATitle='".$Title."', RU='".$RU."', EN='".$EN."', UKR='".$UKR."' WHERE ArticleID='".$ArticleID."';"; //execute SQL-query $result = mysql_query($sql, $db); if (!$result) { die('Invalid query: ' . mysql_error()); } //close database = very inportant mysql_close($db); } Help me please, how can I save such texts properly, Thanx!

    Read the article

  • security deleting a mysql row with jQuery $.post

    - by FFish
    I want to delete a row in my database and found an example on how to do this with jQuery's $.post() Now I am wondering about security though.. Can someone send a POST request to my delete-row.php script from another website? JS function deleterow(id) { // alert(typeof(id)); // number if (confirm('Are you sure want to delete?')) { $.post('delete-row.php', {album_id:+id, ajax:'true'}, function() { $("#row_"+id).fadeOut("slow"); }); } } PHP: delete-row.php <?php require_once("../db.php"); mysql_connect(DB_SERVER, DB_USER, DB_PASSWORD) or die("could not connect to database " . mysql_error()); mysql_select_db(DB_NAME) or die("could not select database " . mysql_error()); if (isset($_POST['album_id'])) { $query = "DELETE FROM albums WHERE album_id = " . $_POST['album_id']; $result = mysql_query($query); if (!$result) die('Invalid query: ' . mysql_error()); echo "album deleted!"; } ?>

    Read the article

  • servlet resopnse data for autocomplete

    - by shams haque
    Hello experts, Following code is in php. i want to do same in java. Please tell me how do i generate this type of array or collection in java. I need this to response to json autocomplete. <?php $q = strtolower($_GET["q"]); if (!$q) return; $items = array( "Peter Pan"=>"[email protected]", "Molly"=>"[email protected]", "Forneria Marconi"=>"[email protected]", "Master Sync"=>"[email protected]", "Dr. Tech de Log"=>"[email protected]", "Don Corleone"=>"[email protected]", "Mc Chick"=>"[email protected]", "Donnie Darko"=>"[email protected]", "Quake The Net"=>"[email protected]", "Dr. Write"=>"[email protected]" ); $result = array(); foreach ($items as $key=>$value) { if (strpos(strtolower($key), $q) !== false) { array_push($result, array( "name" => $key, "to" => $value )); } } echo json_encode($result); ?>

    Read the article

  • Problem changing Java version using alternatives

    - by Brian Lewis
    I'm not quite sure how I got into this mess, but for some reason I'm not able to change the current version of Java using alternatives. I can run alternatives --config java and type my selection but when I echo the version number for either java or javac, it spits back out 1.5 every time (despite alternatives showing the current version is 1.6). The server I'm working with is running RHEL5, by the way. I have verified that the paths used in alternatives are pointing to the correct directories. Here's some output from my session: [brilewis@myserver]$ sudo /usr/sbin/update-alternatives --config java There are 3 programs which provide 'java'. Selection Command ** 1 /usr/lib/jvm/jre-1.4.2-gcj/bin/java + 2 /usr/java/jdk1.5.0_10/bin/java 3 /usr/java/jdk1.6.0_16/bin/java Enter to keep the current selection[+], or type selection number: 3 [brilewis@myserver]$ java -version java version "1.5.0_10" Java(TM) 2 Runtime Environment, Standard Edition (build 1.5.0_10-b03) Java HotSpot(TM) Server VM (build 1.5.0_10-b03, mixed mode) [brilewis@myserver]$ sudo /usr/sbin/update-alternatives --config java There are 3 programs which provide 'java'. Selection Command ** 1 /usr/lib/jvm/jre-1.4.2-gcj/bin/java 2 /usr/java/jdk1.5.0_10/bin/java + 3 /usr/java/jdk1.6.0_16/bin/java Enter to keep the current selection[+], or type selection number:

    Read the article

  • Getting Started with Ruby & Ruby on Rails

    - by JakeTheSnake
    Some background: I'm a jack-of-all traits, one of which is programming. I learned VB6 through Excel and PHP for creating websites and so far it's worked out just fine for me. I'm not CS major or even mathematically inclined - logic is what interests me. Current status: I'm willing to learn new and more powerful languages; my first foray into such a route is learning Ruby. I went to the main Ruby website and did the interactive intro. (by the way, I'm currently getting redirected to google.com when I try the link...it's happening to other websites as well...is my computer infected?) I liked what I learned and wanted to get started using Ruby to create websites. I downloaded InstantRails and installed it; everything so far has been fine - the program starts up just fine, and I can test some Ruby code in the console. However my troubles begin when I try and view a web page with Ruby code present. Lastly, my problem: As in PHP, I can browse to the .php file directly and through using PHP tags and some simple 'echo' statements I can be on my way in making dynamic web pages. However with the InstantRails app working, accessing a .rb or .rhtml page doesn't produce similar results. I made a simple text file named 'test.rb' and put basic HTML tags in there (html, head, body) and the Ruby tags <%= and % with some ruby code inside. The web page actually shows the tags and the code - as if it's all just plain HTML. I take it Ruby isn't parsing the page before it is displayed to the user, but this is where my lack of understanding of the Ruby environment stops me short. Where do I go from here?

    Read the article

  • I need some help cropping an image in PHP (GD)

    - by evan
    http://i.imgur.com/foT9u.jpg Using that image as an example, here's what I need to do: Crop the blue square to have the same proportional ratio as that of the black square From doing that, I should then be able to resize the blue square to fit into the black square without losing stretching it - It'll retain its proportions. Note: The blue square must be cropped 'from the center'. The original center should remain the center after the crop (it can't be cropped from the top left, for example). Here's what I'm thinking needs to be done (using the, landscape, blue square as the example): Figure out the difference between the black squares width and height Figure out the difference between the blue squares width and height This should tell me how much to crop the blue square by and with how much of a 'top offset' Once it's cropped to fit the black squares proportions, it can then be resized I've been messing around with code similar to: if (BLACK_WIDTH > BLACK_HEIGHT) { $diffHeight = BLACK_WIDTH - BLACK_HEIGHT; $newHeight = $blue_Height - $blue_Height; echo $newHeight; } And using Photoshop to try and get a feel for how this should be done, but it continues to fail .< How should I go about doing this? How can I figure out how much to crop by (depending on if the blue square is landscape or portrait)? How do I then get the offset to retain the blue squares center?

    Read the article

  • highlighting search results in php/mysql

    - by fusion
    how do i highlight search results from mysql query using php? this is my code: $search_result = ""; $search_result = $_GET["q"]; $result = mysql_query('SELECT cQuotes, vAuthor, cArabic, vReference FROM thquotes WHERE cQuotes LIKE "%' . $search_result .'%" ORDER BY idQuotes DESC', $conn) or die ('Error: '.mysql_error()); function h($s) { echo htmlspecialchars($s, ENT_QUOTES); } ?> <div class="center_div"> <table> <caption>Search Results</caption> <?php while ($row= mysql_fetch_array($result)) { ?> <tr> <td style="text-align:right; font-size:15px;"><?php h($row['cArabic']) ?></td> <td style="font-size:16px;"><?php h($row['cQuotes']) ?></td> <td style="font-size:12px;"><?php h($row['vAuthor']) ?></td> <td style="font-size:12px; font-style:italic; text-align:right;"><?php h($row['vReference']) ?></td> </tr> <?php } ?> </table> </div>

    Read the article

  • Access/Download server files, not in site root, with PHP

    - by user271619
    Usually I save documents (images, mpegs, excel, word docs, etc...) for my friends or family on my website's root, inside a directory called /files/ or something similar. Nothing too uncommon. But, I have been playing with user session control, and allowing users to upload files to the dedicated /files/ directory. (the file names are saved in a db, with that user's ID) But, that means other people could try to guess and locate other people's files. I do randomize the file names, upon upload. And I stop the apache from displaying the /files/ directory content. However, I'd like to start saving the files outside of the website's root. This way it can't be accessible via the browser. I don't have any code to show, but I didn't want to even start on this endeavor if it's not able to be accomplished. I did find this snippet that shows how to display an image, from outside your website root: $file = $_GET['file']; $fileDir = '/path/to/files/'; if (file_exists($fileDir . $file)) { // Note: You should probably do some more checks // on the filetype, size, etc. $contents = file_get_contents($fileDir . $file); // Note: You should probably implement some kind // of check on filetype header('Content-type: image/jpeg'); echo $contents; } ? Maybe I can use this for any file type, but has anyone heard of a better way to allow users (logged in) to access their files from online, but not letting other users has similar access?

    Read the article

  • PHP script not automatically updating when moved to another server

    - by user32007
    A friend built a ranking system on his site and I am trying to host in on mine via WordPress and Go Daddy. It updates for him but when I load it to my site, it works for 6 hours, but as soon as the reload is supposed to occur, it errors and I get a 500 timeout error. His page is at: jeremynoeljohnson .com/yakezieclub My page is currently at http://sweatingthebigstuff.com/yakezieclub but when you ?reload=1 it will give the error. Any idea why this might be happening? Any settings that I might need to change? Here is the top of the index.php file. I'm not sure which part of any of it is messing up. I literally uploaded the same code as him. Here's the reload part: $cachefile = "rankings.html"; $daycachefile = "rankings_history.xml"; $cachetime = (60 * 60) * 6; // every 6 hours, the cache refreshes $daycachetime = (60 * 60) * 24; // every 24 hours, the history will be written to // - or whenever the page is requested after 24 hours has passed $writenewdata = false; if (!empty($_GET['reload'])) { if ($_GET['reload']== 1) { $cachetime = 1; } } if (!empty($_GET['reloadhistory'])) { if ($_GET['reloadhistory'] == 1) { $daycachetime = 1; $cachetime = 1; } } if (file_exists($daycachefile) && (time() - $daycachetime < filemtime($daycachefile))) { // Do nothing } else { $writenewdata = true; $cachetime = 1; } // Serve from the cache if it is younger than $cachetime if (file_exists($cachefile) && (time() - $cachetime < filemtime($cachefile))) { include($cachefile); echo "<!-- Cached ".date('jS F Y H:i', filemtime($cachefile))." -->"; exit; } ob_start(); // start the output buffer ?>

    Read the article

  • PHP - Select from database the same query

    - by How to PHP
    I created a table that contains the name of the user and his job, and created PHP page that shows me all the users that works doctor, I entered doctor into a variable then I selected from the table where Jobs equal to $doctor, that is great, but I need it to get the same Jobs into a table in the page and the other same jobs into a table in the same page. this is my code that shows only the users works doctor in one table, <html> <h1>Doctors</h1> </html> <?php mysql_connect('localhost','root',''); mysql_select_db('data'); $doctor='doctor'; $query= mysql_query("SELECT * FROM `users` WHERE `job` = '$doctor'")or die(mysql_error()); while ($arr = mysql_fetch_array($query)) $name= $arr['name']; echo $name; } ?> That shows me doctors when I put doctor in a variable I want to show all same Jobs in a table. Is there is a way to do this? Thanks :)

    Read the article

  • How to I pass parameters to Ruby/Python scripts from inside PHP?

    - by Roger
    Hi, everybody. I need to turn HTML into equivalent Markdown-structured text. From what I could discover, I have only two good choices: Python: Aaron Swartz's html2text.py Ruby: Singpolyma's html2markdown.rb As I am programming in PHP, I need to pass the HTML code, call the Ruby/Python Script and receive the output back. I started creating a simple test just to know if my server was configured to run both languages. PHP code: echo exec('./hi.rb'); Ruby code: #!/usr/bin/ruby puts "Hello World!" It worked fine and I am ready to go to the next step. Unfortunately, all I know is that the function is Ruby works like this: HTML2Markdown.new('<h1>HTMLcode</h1>').to_s I don't know how to make PHP pass the string (with the HTML code) to Ruby nor how to make the ruby script receive the variable and pass it back to PHP (after have parsed it into Markdown). Believe it or not: I know less of Python. A folk made a similar question here ("how to call ruby script from php?") but with no practical information to my case. Any help would be a joy - thanks. Rogério Madureira. atipico.com.br

    Read the article

  • jQuery ajax delete script not actually deleting.

    - by werm
    I have a little personal webapp that I'm working on. I have a link that, when clicked, is supposed to make an ajax call to a php that is supposed to delete that info from a database. For some unknown reason, it won't actually delete the row from the database. I've tried everything I know, but still nothing. I'm sure it's something incredibly easy... Here are the scripts involved. Database output: $sql = "SELECT * FROM bookmark_app"; foreach ($dbh->query($sql) as $row) { echo '<div class="box" id="',$row['id'],'"><img src="images/avatar.jpg" width="75" height="75" border="0" class="avatar"/> <div class="text"><a href="',$row['url'],'">',$row['title'],'</a><br/> </div> /*** Click to delete ***/ <a href="?delete=',$row['id'],'" class="delete">x</a></div> <div class="clear"></div>'; } $dbh = null; Ajax script: $(document).ready(function() { $("a.delete").click(function(){ var element = $(this); var noteid = element.attr("id"); var info = 'id=' + noteid; $.ajax({ type: "GET", url: "includes/delete.php", data: info, success: function(){ element.parent().eq(0).fadeOut("slow"); } }); return false; }); }); Delete code: include('connect.php'); //delete.php?id=IdOfPost if($_GET['id']){ $id = $_GET['id']; //Delete the record of the post $delete = mysql_query("DELETE FROM `db` WHERE `id` = '$id'"); //Redirect the user header("Location:xxxx.php"); }

    Read the article

  • Why am I getting a syntax error after my Json result?

    - by Mike
    I'm using Json to retrieve data from a database, construct some html, and put it to the page, but I'm getting a syntax error after my tag, which is the last tag in the string from my php file. PHP if($QString == ""){ $query = "SELECT * FROM categories"; $result = mysql_query($query); while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $categories="<a href=" . '"' . "?catID=" . $row['catID'] . '"' . ">" . $row['CatName'] . "</a><br>"; echo $_GET['jsoncallback'] . $categories; } } jQuery var jSon = {}; $(function(){ jQuery.jSon.getjSon(); }); jQuery.jSon = { getjSon : function () { $.getJSON('http://host6.spellnet.net/links/list.php?jsoncallback=?', function(json) { eval(json.data); }); } Any Help would be greatly appreciated. I'm getting closer and closer.

    Read the article

  • Batch folder of images into grayscale using php

    - by James
    Can anyone spot where I'm going wrong here. It should be creating grayscale copies of images in one folder and saving them in another folder. Could it be to do with the way im referencing the file locations. Folder permissions on both folders are 777 function grayscalecopy($targetfile, $outputfile){ $size = GetImageSize($targetfile); $width = $size[1]; $height = $size[0]; $canvas = imagecreatetruecolor($width, $height); $sourceimage = imagecreatefromjpeg($targetfile); imagefilter($sourceimage, IMG_FILTER_GRAYSCALE); imagecopy($canvas, $sourceimage, 0, 0, 0, 0, $width, $height); imagejpeg($canvas, $outputfile, 95); imagedestroy($sourceimage); imagedestroy($canvas); echo "Converted ".$targetfile." to grayscale as ".$outputfile." ".$width."x".$height."<br/>"; } $serverfiles = glob("artworkimages/thumbs/*.*"); //$numbertocache = count($serverfiles); $numbertocache = 10; for ($i=0; $i<$numbertocache; $i++) { $serverfilesshort=explode("/",$serverfiles[$i]); $serverfilesshort=$serverfilesshort[count($serverfilesshort)-1]; grayscalecopy($serverfiles[$i], "artworkimages/thumbs/grays/".$serverfilesshort); }

    Read the article

  • MySQL INJECTION Solution...

    - by Val
    I have been bothered for so long by the MySQL injections and was thinking of a way to eliminate this problem all together. I have came up with something below hope that many people will find this useful. The only Draw back I can think of this is the partial search: Jo =returns "John" by using the like %% statement. Here is a php solution: <?php function safeQ(){ $search= array('delete','select');//and every keyword... $replace= array(base64_encode('delete'),base64_encode('select')); foreach($_REQUEST as $k=>$v){ str_replace($search, $replace, $v); } } foo(); function html($str){ $search= array(base64_encode('delete'),base64_encode('select')); $replace= array('delete','select');//and every keyword... str_replace($search, $replace, $str); } //example 1 ... ... $result = mysql_fetch_array($query); echo html($result[0]['field_name']); //example 2 $select = 'SELECT * FROM safeQ($_GET['query']) '; //example 3 $insert = 'INSERT INTO .... value(safeQ($_GET['query']))'; ?> I know, I know that you still could inject using 1=1 or any other type of injections... but this I think could solve half of your problem so the right mysql query is executed. So my question is if anyone can find any draw backs on this then please feel free to comment here. PLEASE GIVE AN ANSWER only if you think that this is a very useful solution and no major drawbacks are found OR you think is a bad idea all together...

    Read the article

  • APC values randomly disappear

    - by Michael
    I'm using APC for storing a map of class names to class file paths. I build the map like this in my autoload function: $class_paths = apc_fetch('class_paths'); // If the class path is stored in application cache - search finished. if (isset($class_paths[$class])) { return require_once $class_paths[$class]; // Otherwise search in known places } else { // List of places to look for class $paths = array( '/src/', '/modules/', '/libs/', ); // Search directories and store path in cache if found. foreach ($paths as $path) { $file = DOC_ROOT . $path . $class . '.php'; if (file_exists($file)) { echo 'File was found in => ' . $file . '<br />'; $class_paths[$class] = $file; apc_store('class_paths', $class_paths); return require_once $file; } } } I can see as more and more classes are loaded, they are added to the map, but at some point the apc_fetch returns NULL in the middle of a page request, instead of returning the map. Getting => class_paths Array ( [MCS\CMS\Helper\LayoutHelper] => /Users/mbl/Documents/Projects/mcs_ibob/core/trunk/src/MCS/CMS/Helper/LayoutHelper.php [MCS\CMS\Model\Spot] => /Users/mbl/Documents/Projects/mcs_ibob/core/trunk/src/MCS/CMS/Model/Spot.php ) Getting => class_paths {null} Many times the cached value will also be gone between page requests. What could be the reason for this? I'm using APC as an extension (PECL) running PHP 5.3.

    Read the article

  • [Zend YouTubeAPP] failed to upgrade a token

    - by kwokwai
    Hi all, I was testing Zend Gdata 1.10.1 in my localhost. I downloaded Zend Gdate from this link: http://framework.zend.com/download/webservices Inside the Zend Gdata zip file, there was a folder called demos. I extracted it and used the YouTudeVideoApp to upload a sample video to Youtube. But every time after I logged into Youtube, before it redirected me to my localhost, I received a warning message like this warning message: localhost: This website is registered with Google to make authorization requests, but has not been configured to send requests securely. We recommend that you continue the process only if you trust the following destination: localhost:8080/youtube/operations.php So I googled on how to resolve the problem of getting this warning message when I saw some people suggesed changing the value of $secure to True in operation.php. Here is the script mentioned: function generateAuthSubRequestLink($nextUrl = null) { $scope = 'http://gdata.youtube.com'; $secure = true; $session = true; if (!$nextUrl) { generateUrlInformation(); $nextUrl = $_SESSION['operationsUrl']; } $url = Zend_Gdata_AuthSub::getAuthSubTokenUri($nextUrl, $scope, $secure, $session); echo '<a href="' . $url . '"><strong>Click here to authenticate with YouTube</strong></a>'; } After I altered the value of $secure to True, I found that the warning message changed to this: localhost: Registered, secure. This website is registered with Google to make authorization requests The new warning message is somehow shorter and looks better than the previous warning message. But once I pressed the Allow Access button, it turned out to be this: ERROR - Token upgrade for CI3M6_Q3EOGkxoL-___wEYjffToQQ failed : Token upgrade failed. Reason: Invalid AuthSub header. Error 401 ERROR - Unknown search type - '' I don't know why this happened. Could you help me solve the problem please?

    Read the article

  • Get index values for an array to print in value attribute for radio buttons

    - by kexxcream
    Problem: To get the index values of an array to print accordingly in value attribute of radio buttons. The array $_SESSION['items']: Array ( [2] => Array ( [category] => 2 [question] => Array ( [6] => Källorna refereras separat [7] => Vissa försök till sammanbindning [8] => En del sammanfattningar [9] => Olika forskningslinjer jämförs och sammanfattas [10] => Kontraster, jämförelser, sammanfattningar; centrala likheter och skillnader framhävs ) [title] => Integration av källorna ) ) I have a PHP function that looks like this: function itemsLayout ($array) { for ($i = 1; $i <= count($array['question']); $i++) { $form .= '<input type="radio" name="'.$array['category'].'" id="'.$array['category'].'" value="INDEX VALUE FOR QUESTION ARRAY HERE">'; } return $form; } PHP code: I get the index by using the following: $key = key($_SESSION['items']); $current = $_SESSION['items'][$key]; And I print the first index by using: echo itemsLayout($current); Question: How do I get the index values 6, 7, 8, 9, 10 to print in the value attribute for each radio button?

    Read the article

  • How to implement next prev to my blog

    - by lena
    Hi, I have created a basic PHP blog-cms and I'm looking for a easy way to implement prev next. on the blog page. I know there are several Jquery plugins, also some people use PHP to achieve this... I'm looking for the more simple and easy way to do it. I want to display 2 news by page The code: <?php $q = 'SELECT news.user_id,news.date,news.title,news.intro,news.content,news.status,news.visible, CONCAT(users.firstname," ", users.name) AS uname FROM news LEFT JOIN users ON users.id = news.user_id WHERE news.status= 1 AND news.visible=1 AND news.language=1 ORDER BY news.date DESC'; $res = sqlq($q); while ($r = sqlget($res)) { echo '<div> <h5> ' . $r['title'] . '</h5> </div>' . '<div>' . $r['date'] . ' | ' . $r['uname'] .'</div>' . '</br>'. '</br>'. '<p>'. '<div>' . $r['intro'] . '</div>' . '</p>'. '</br>'. '<p>'. '<div>' . $r['content'] . '</div>'. '</p>'. '<hr>' ; } //while ? Thanks for your help

    Read the article

  • Valgrind 'noise', what does it mean?

    - by Chris Huang-Leaver
    When I used valgrind to help debug an app I was working on I notice a huge about of noise which seems to be complaining about standard libraries. As a test I did this; echo 'int main() {return 0;}' | gcc -x c -o test - Then I did this; valgrind ./test ==1096== Use of uninitialised value of size 8 ==1096== at 0x400A202: _dl_new_object (in /lib64/ld-2.10.1.so) ==1096== by 0x400607F: _dl_map_object_from_fd (in /lib64/ld-2.10.1.so) ==1096== by 0x4007A2C: _dl_map_object (in /lib64/ld-2.10.1.so) ==1096== by 0x400199A: map_doit (in /lib64/ld-2.10.1.so) ==1096== by 0x400D495: _dl_catch_error (in /lib64/ld-2.10.1.so) ==1096== by 0x400189E: do_preload (in /lib64/ld-2.10.1.so) ==1096== by 0x4003CCD: dl_main (in /lib64/ld-2.10.1.so) ==1096== by 0x401404B: _dl_sysdep_start (in /lib64/ld-2.10.1.so) ==1096== by 0x4001471: _dl_start (in /lib64/ld-2.10.1.so) ==1096== by 0x4000BA7: (within /lib64/ld-2.10.1.so) * large block of similar snipped * ==1096== Use of uninitialised value of size 8 ==1096== at 0x4F35FDD: (within /lib64/libc-2.10.1.so) ==1096== by 0x4F35B11: (within /lib64/libc-2.10.1.so) ==1096== by 0x4A1E61C: _vgnU_freeres (vg_preloaded.c:60) ==1096== by 0x4E5F2E4: __run_exit_handlers (in /lib64/libc-2.10.1.so) ==1096== by 0x4E5F354: exit (in /lib64/libc-2.10.1.so) ==1096== by 0x4E48A2C: (below main) (in /lib64/libc-2.10.1.so) ==1096== ==1096== ERROR SUMMARY: 3819 errors from 298 contexts (suppressed: 876 from 4) ==1096== malloc/free: in use at exit: 0 bytes in 0 blocks. ==1096== malloc/free: 0 allocs, 0 frees, 0 bytes allocated. ==1096== For counts of detected errors, rerun with: -v ==1096== Use --track-origins=yes to see where uninitialised values come from ==1096== All heap blocks were freed -- no leaks are possible. You can see the full result here: http://pastebin.com/gcTN8xGp I have two questions; firstly is there a way to suppress all the noise? --show-below-main is set to no by default, but there doesn't appear to be a --show-after-main equivalent.

    Read the article

  • (HARD)Remove accents from a JSON response using the raw content

    - by Pentium10
    This is a follow up of this question: Remove accents from a JSON response. The accepted answer there works for a single item/string of a raw JSON content. But I would like to run a full transformation over the entire raw content of the JSON without parsing each object/array/item. What I've tried is this function removeAccents($jsoncontent) { $obj=json_decode($jsoncontent); // use decode to transform the unicode chars to utf $content=serialize($obj); // serialize into string, so the whole obj structure can be used string as a whole $a = 'ÀÁÂÃÄÅÆÇÈÉÊËÌÍÎÏÐÑÒÓÔÕÖØÙÚÛÜÝÞßàáâãäåæçèéêëìíîïðñòóôõöøùúûýýþÿRr'; $b = 'aaaaaaaceeeeiiiidnoooooouuuuybsaaaaaaaceeeeiiiidnoooooouuuyybyRr'; $content=utf8_decode($content); $jsoncontent = strtr($content, $a, $b); // at this point the accents are removed, and everything is good echo $jsoncontent; $obj=unserialize($jsoncontent); // this unserialization is returning false, probably because we messed up with the serialized string return json_encode($obj); } As you see after I decoded JSON content, I serialized the object to have a string of it, than I remove the accents from that string, but this way I have problem building back the object, as the unserialize stuff returns false. How can I fix this?

    Read the article

  • How can I set up an editor to work with Git on Windows?

    - by Patrick McElhaney
    I'm trying out Git on Windows. I got to the point of trying "git commit" and I got this error: Terminal is dumb but no VISUAL nor EDITOR defined. Please supply the message using either -m or -F option. So I figured out I need to have an environment variable called EDITOR. No problem. I set it to point to Notepad. That worked, almost. The default commit message opens in Notepad. But Notepad doesn't support bare line feeds. I went out and got Notepad++. But I can't figure out how to get Notepad++ set up as the %EDITOR% in such a way that it works with Git as expected. I'm not married to Notepad++. At this point I couldn't care less what editor I use. I just want to be able to type my commit messages without using -m. So, for those of you using Git on Windows: What (free) tool do you use to edit your commit message, and what do you get when you type echo %EDITOR% at the command prompt?

    Read the article

< Previous Page | 295 296 297 298 299 300 301 302 303 304 305 306  | Next Page >