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  • Use regex in awk command in bash script

    - by fmpdmb
    I'm trying to read a file of regexes, looping over them and filtering them out of another file. I'm so close, but I'm having issues with my $regex var substitution I believe. while read regex do awk -vRS= '!/$regex/' ORS="\n\n" $tempOne > $tempTwo mv $tempTwo $tempOne done < $filterFile $tempOne and $tempTwo are temporary files. $filterFile is the file containing the regexes.

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  • sort associative array in awk - help?

    - by Richard
    Hi all, I have an associative array in awk that gets populated like this... chr_count[$3]++ When I try to print my chr_counts I use this: for (i in chr_count) { print i,":",chr_count[i]; } But not surprisingly, the order of i is not sorted in any way. Is there an easy way to iterate over the sorted "keys" of chr_count?

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  • scripting in awk

    - by benjamin button
    I have a text file with contents as below: 1,A,100 2,A,200 3,B,150 4,B,100 5,B,250 i need the output as : A,300 B,500 the logic here is sum of all the 3rd fields whose 2nd field is A and in the same way for B how could we do it using awk?

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  • Getting memory usage from 'ps aux' output with awk

    - by JustB
    Hello everybody, I have to solve an exercise using awk. Basically I need to retrieve from 'ps aux' command the total of memory usage for each user and format like this: User Total%Mem user1 3.4% user2 1.5% and so on. The problem I can't seem to solve is: how do I know how many users are logged in? And how can I make a different sum for each one of them? Thank you :)

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  • awk can and perl cannot

    - by alvin
    somewhere i read about one specific feature present in awk which is absent in perl. failed in locating it again. would appreciate it, if anyone of you could remember. (yep, this might be a useless trivia.) but still curious.

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  • combine 2 files with AWK based last colums

    - by mohammad reshad
    i have two files file1 ------------------------------- 1 a t p b 2 b c f a 3 d y u b 2 b c f a 2 u g t c 2 b j h c file2 -------------------------------- 1 a b 2 p c 3 n a 4 4 a i want combine these 2 files based last columns (column 5 of file1 and column 3 of file2) using awk result ---------------------------------------------- 1 a t p 1 a b 2 b c f 3 n a 2 b c f 4 4 a 3 d y u 1 a b 2 b c f 3 n a 2 b c f 4 4 a 2 u g t 2 p c 2 b j h 2 p c

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  • awk or sed: Best way to grab [this text]

    - by Parand
    I'm trying to parse various info from log files, some of which is placed within square brackets. For example: Tue, 06 Nov 2007 10:04:11 INFO processor:receive: [someuserid], [somemessage] msgtype=[T] What's an elegant way to grab 'someuserid' from these lines, using sed, awk, or other unix utility?

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  • Question about using awk to print all columns great then nth

    - by Andy
    right now I have this line, and it worked until I had whitespace in the second field. svn status | grep '\!' | gawk '{print $2;}' > removedProjs is there a way to have awk print everything in $2 or greater? ($3, $4.. until we don't have anymore columns?) I suppose I should add that I'm doing this in a windows environment with cygwin.

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  • Select a particular column using awk or cut or perl

    - by javed abbas
    Have a requirement to select the 7th column. eg: cat filename | awk '{print $7}' The issue is that the data in the 4th column has multiple values with blank in between. example - The last line in the below output: user \Adminis FL_vol Design 0 - 1 - group 0 FL_vol Design 19324481 - 3014 - user \MAK FL_vol Design 16875161 - 2618 - tree 826 FL_vol Out Global Doc Mark 16875162 - 9618 - /vol/FL_vol/Out Global Doc Mark

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  • AWK -- How to do selective multiple column sorting?

    - by nawesita
    In awk, how can I do this: Input: 1 a f 1 12 v 2 b g 2 10 w 3 c h 3 19 x 4 d i 4 15 y 5 e j 5 11 z Desired output, by sorting numerical value at $5: 1 a f 2 10 w 2 b g 5 11 z 3 c h 1 12 v 4 d i 4 15 y 5 e j 3 19 x Note that the sorting should only affecting $4, $5, and $6 (based on value of $5), in which the previous part of table remains intact.

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  • Optimizing grep (or using AWK) in a shell script

    - by Ode
    Hi - In my shell script, I am trying to search using terms found in a $sourcefile against the same $targetfile over and over. My $sourcefile is formatted as such: pattern1 pattern2 etc... The inefficient loop I have to search with is: for line in $(< $sourcefile);do fgrep $line $targetfile | fgrep "RID" >> $outputfile done I understand it would be possible to improve this by either loading the whole $targetfile into memory, or perhaps by using AWK? Thanks

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  • how to use sed/awk to remove words with multiple pattern count

    - by user1461112
    I have a file of string records where one of the fields - delimited by "," - can contain one or more "-" inside it. The goal is to delete the field value if it contains more than two "-". i am trying to recoup my past knowledge of sed/awk but can't make much headway ========== info,whitepaper,Data-Centers,yes-the-6-top-problems-in-your-data-center-lane info,whitepaper,Data-Centers,the-evolution-center info,whitepaper,Data-Centers,the-evolution-of-lan-technology-lanner ========== expected outcome: info,whitepaper,Data-Centers info,whitepaper,Data-Centers,the-evolution-center info,whitepaper,Data-Centers thanks

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  • Converting FASTQ to FASTA with SED/AWK

    - by neversaint
    I have a data in that always comes in block of four in the following format (called FASTQ): @SRR018006.2016 GA2:6:1:20:650 length=36 NNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNGN +SRR018006.2016 GA2:6:1:20:650 length=36 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!+! @SRR018006.19405469 GA2:6:100:1793:611 length=36 ACCCGCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC +SRR018006.19405469 GA2:6:100:1793:611 length=36 7);;).;);;/;*.2>/@@7;@77<..;)58)5/>/ Is there a simple sed/awk/bash way to convert them into this format (called FASTA): >SRR018006.2016 GA2:6:1:20:650 length=36 NNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNGN >SRR018006.19405469 GA2:6:100:1793:611 length=36 ACCCGCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC In principle we want to extract the first two lines in each block-of-4 and replace @ with >.

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  • awk output to a file

    - by Harish
    I need help in moving the contents printed by awk to a text file. THis is a continuation of previous quesion I have to move all the contents into the same file so it is appending. To be specific nawk -v file="$FILE" 'BEGIN{RS=";"} /select/{ gsub(/.*select/,"select");gsub(/\n+/,"");print file,$0;} /update/{ gsub(/.*update/,"update");gsub(/\n+/,"");print file,$0;} /insert/{ gsub(/.*insert/,"insert");gsub(/\n+/,"");print file,$0;} ' "$FILE" How to get the print results to a text file appended one after the other in the same file?

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  • Using AWK, treate files

    - by Mat
    Hi all, I have something to do that it must be finished before 4.00PM. I want create a batch file with awk, grep or sed that keep all lines beginning with 'INSERT' and delete the other lines. After this, i want replace a string "change)" by "servicechange)" when the 3rd word in the treated line is "donextsit". I don't know how to do this before my deadline (4.00 PM). Please HELP ME!! Thx for your answers. And Sorry for my english ;)

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  • Substring extraction using bash shell scripting and awk

    - by rohanbk
    So, I have a file called 'dummy' which contains the string: "There is 100% packet loss at node 1". I also have a small script that I want to use to grab the percentage from this file. The script is below. result=`grep 'packet loss' dummy` | awk '{ first=match($0,"[0-9]+%") last=match($0," packet loss") s=substr($0,first,last-first) print s}' echo $result I want the value of $result to basically be 100% in this case. But for some reason, it just prints out a blank string. Can anyone help me?

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  • awk / sed script to remove text

    - by radman
    Hi, I am currently needed of way to programmatically remove some text from Makefiles that I am dealing with. Now the problem is that (for whatever reason) the makefiles are being generated with link commands of -l<full_path_to_library>/<library_name> when they should be generated with -l<library_name>. So what I need is a script to find all occurrences of -l/ and then remove up to and including the next /. Example of what I'm dealing with -l/home/user/path/to/boost/lib/boost_filesystem I need it to be -lboost_filesystem As could be imagined this is a stop gap measure until I fix the real problem (on the generation side) but in the meantime it would be a great help to me if this could work and I am not too good with my awk and sed. Thanks for any help.

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  • awk + sorting file according to values in the file and write two diffrent files

    - by yael
    hi I have in file file_test values of right eye and left eye How to separate the file_test to file1 and file2 by awk in order to write the equal values on file1 and different values on file2 as the following example down THX file_test: NAME: jim LAST NAME: bakker right eye: |5|< left eye VALUE: |5|< NAME: Jorg LAST NAME: mitchel right eye: |3|< left eye VALUE: |5|< NAME: jimmy LAST NAME: kartter right eye: |6|< left eye VALUE: |5|< NAME: david LAST NAME: kann right eye: |9|< left eye VALUE: |9|< file1: NAME: jim LAST NAME: bakker right eye: |5|< left eye VALUE: |5|< NAME: david LAST NAME: kann right eye: |9|< left eye VALUE: |9|< file2: NAME: Jorg LAST NAME: mitchel right eye: |3|< left eye VALUE: |5|< NAME: jimmy LAST NAME: kartter right eye: |6|< left eye VALUE: |5|<

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