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  • how to copy a dictionary in python 3.1 and edit ONLY the copy

    - by MadSc13ntist
    can someone please explain this to me??? this doesn't make any sense to me.... I copy a dictionary into another and edit the second and both are changed???? ActivePython 3.1.0.1 (ActiveState Software Inc.) based on Python 3.1 (r31:73572, Jun 28 2009, 19:55:39) [MSC v.1500 32 bit (Intel)] on win32 Type "help", "copyright", "credits" or "license" for more information. dict1 = {"key1":"value1", "key2":"value2"} dict2 = dict1 dict2 {'key2': 'value2', 'key1': 'value1'} dict2["key2"] = "WHY?!?!?!!?!?!?!" dict1 {'key2': 'WHY?!?!?!!?!?!?!', 'key1': 'value1'}

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  • Using `.index()` on repeating letters

    - by Yarden
    I'm building a function that builds a dictionary with words, such as: {'b': ['b', 'bi', 'bir', 'birt', 'birth', 'birthd', 'birthda', 'birthday'], 'bi': ['bi', 'bir', 'birt', 'birth', 'birthd', 'birthda', 'birthday'], 'birt': ['birt', 'birth', 'birthd', 'birthda', 'birthday'], 'birthda': ['birthda', 'birthday'], 'birthday': ['birthday'], 'birth': ['birth', 'birthd', 'birthda', 'birthday'], 'birthd': ['birthd', 'birthda', 'birthday'], 'bir': ['bir', 'birt', 'birth', 'birthd', 'birthda', 'birthday']} This is what it looks like: def add_prefixs(word, prefix_dict): lst=[] for letter in word: n=word.index(letter) if n==0: lst.append(word[0]) else: lst.append(word[0:n]) lst.append(word) lst.remove(lst[0]) for elem in lst: b=lst.index(elem) prefix_dict[elem]=lst[b:] return prefix_dict It works great for words like "birthday", but when I have a letter that repeats itself, I have a problem... for example, "hello". {'h': ['h', 'he', 'he', 'hell', 'hello'], 'hell': ['hell', 'hello'], 'hello': ['hello'], 'he': ['he', 'he', 'hell', 'hello']} I know it's because of the index (python chooses the index of the first time the letter appears) but I do not know how to solve it. Yes, this is my homework and I'm really trying to learn from you guys :)

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  • How to add values accordingly of the first indices of a dictionary of tuples of a list of strings? Python 3x

    - by TheStruggler
    I'm stuck on how to formulate this problem properly and the following is: What if we had the following values: {('A','B','C','D'):3, ('A','C','B','D'):2, ('B','D','C','A'):4, ('D','C','B','A'):3, ('C','B','A','D'):1, ('C','D','A','B'):1} When we sum up the first place values: [5,4,2,3] (5 people picked for A first, 4 people picked for B first, and so on like A = 5, B = 4, C = 2, D = 3) The maximum values for any alphabet is 5, which isn't a majority (5/14 is less than half), where 14 is the sum of total values. So we remove the alphabet with the fewest first place picks. Which in this case is C. I want to return a dictionary where {'A':5, 'B':4, 'C':2, 'D':3} without importing anything. This is my work: def popular(letter): '''(dict of {tuple of (str, str, str, str): int}) -> dict of {str:int} ''' my_dictionary = {} counter = 0 for (alphabet, picks) in letter.items(): if (alphabet[0]): my_dictionary[alphabet[0]] = picks else: my_dictionary[alphabet[0]] = counter return my_dictionary This returns duplicate of keys which I cannot get rid of. Thanks.

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  • python: creating a list inside a dictionary

    - by user1871081
    I just started using python and I'm trying to create a program that will read a file that looks like this: AAA x 111 AAB x 111 AAA x 112 AAC x 123 ... the file is 50 lines long and I'm trying to make the letters into keys in a dictionary and the numbers lists that correspond with the keys. I want the output to look like this: {AAA: ['111', '112'], AAB: ['111'], AAC: [123], ...} This is what I've tried file = open("filename.txt", "r") readline = file.readline().rstrip() while readline!= "": list = [] list = readline.split(" ") j = list.index("x") k = list[0:j] v = list[p + 1:] d = {} if k in d == False d[k] = [] d[k].append(v) else d[k].append(v) readline = file.readline().rstrip() I keep getting syntax errors on my if statement and I can't figure out what I've done wrong.

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  • How to remove all that country-specific dictionaries (like En_AU, En_CA, de_CH, etc)?

    - by Ivan
    After I've installed some language packs and spell checking dictionaries (I'd like to use with Firefox and OpenOffice) I've got tons of language variations installed. This makes very inconvenient to maintain dictionary additions, for example. Sometimes Firefox decides to switch to Australian, sometimes to UK dictionary, sometimes to US, etc. For me, a Russian, English is just English, and German is just German. I think every English-speaking will understand me, may I write "color" or "colour", "dialog", or "dialogue" (I usually prefer classic UK spelling though, as a matter of a habit (as I was taught at school)). How to remove all those dialects?

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  • What data-structure/algorithm will allow me to send a list of key/value dictionaries using the least amount of bits?

    - by user12365
    I have server objects that have corresponding client objects. The data to be kept in sync is inside the server object's key/value dictionary. To keep the client objects in sync with the sever objects, I want the server to send the key/value dictionary every frame for each object. What data-structure/algorithm will allow me to send a list of key/value dictionaries using the least amount of bits? Bonus constraint 1: For each type of object, the values of some keys change more often than others. Bonus constraint 2: Memory usage on the server side is relatively expensive.

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  • How to find the maximum value for each key in a List of Dictionaries using LINQ?

    - by Argos
    I have a List of Dictionaries that have keys of type string and values that are ints. Many of the dictionaries have the same keys in them but not all of them. So my question is: using LINQ how would I find the maximum value associated with each distinct key across all of the dictionaries? So for example given the following input: var data = new List<Dictionary<string, int>> { new Dictionary<string, int> {{"alpha", 4}, {"gorilla", 2}, {"gamma", 3}}, new Dictionary<string, int> {{"alpha", 1}, {"beta", 3}, {"gamma", 1}}, new Dictionary<string, int> {{"monkey", 2}, {"beta", 2}, {"gamma", 2}}, }; I would like some kind of collection that contains: {"alpha", 4}, {"gorilla", 2}, {"gamma", 3}, {"beta", 3}, {"monkey", 2} (I'm currently looping through the list and keeping track of things myself, really just wondering if there is a nicer LINQ-esque way of doing it) EDIT: I also don't know what the string keys are in advance

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  • How do I sum values from two dictionaries in C#?

    - by George Stocker
    I have two dictionaries with the same structure: Dictionary<string, int> foo = new Dictionary<string, int>() { {"Table", 5 }, {"Chair", 3 }, {"Couch", 1 } }; Dictionary<string, int> bar = new Dictionary<string, int>() { {"Table", 4 }, {"Chair", 7 }, {"Couch", 8 } }; I'd like to sum the values of the dictionaries together and return a third dictionaries with the keys, and the total values for each key: Table, 9 Chair, 10 Couch, 9 My current solution is to loop through the dictionary and pull them out that way, but I know that solution isn't the most performant or most readable. However, I'm hitting a brick wall trying to come up with a solution in LINQ.

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  • Is there an easy way to "append()" two dictionaries together in Python?

    - by digitaldreamer
    If I have two dictionaries I'd like to combine in Python, i.e. a = {'1': 1, '2': 2} b = {'3': 3, '4': 4} If I run update on them it reorders the list: a.update(b) {'1': 1, '3': 3, '2': 2, '4': 4} when what I really want is attach "b" to the end of "a": {'1': 1, '2': 2, '3': 3, '4': 4} Is there an easy way to attach "b" to the end of "a" without having to manually combine them like so: for key in b: a[key]=b[key] Something like += or append() would be ideal, but of course neither works on dictionaries.

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  • Caching by in-memory dictionaries. Are we doing it all wrong?

    - by user73983
    This approach is pretty much the accepted way to do anything in our company. A simple example : when a piece of data for a customer is requested from a service, we fetch all the data for that customer(relevant part to the service) and save it in a in-memory dictionary then serve it from there on following requests(we run singleton services). Any update goes to DB, then updates the in memory dictionary. It seems all simple and harmless but as we implement more complicated business rules the cache gets out of sync and we have to deal with hard to find bugs. Sometimes we defer writing to database, keeping new data in cache till then. There are cases when we store millions of rows in memory because the table has many relations to other tables and we need to show aggregate data quickly. All this cache handling is a big part of our codebase and I sense this is not the right way to do it. All of this juggling adds too much noise to the code and it makes it hard to understand the actual business logic. However I don't think we can serve data in a reasonable amount of time if we have to hit the database every time. I am unhappy about the current situation but I don't have a better alternative. My only solution would be to use NHibernate 2nd level cache but I have nearly no experience with it. I know many campanies use Redis or MemCached heavily to gain performance but I have no idea how I would integrate them into our system. I also don't know if they can perform better than in-memory data structures and queries. Are there any alternative approaches that I should look into?

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  • Implementing "select distinct ... from ..." over a list of Python dictionaries

    - by daveslab
    Hi folks, Here is my problem: I have a list of Python dictionaries of identical form, that are meant to represent the rows of a table in a database, something like this: [ {'ID': 1, 'NAME': 'Joe', 'CLASS': '8th', ... }, {'ID': 1, 'NAME': 'Joe', 'CLASS': '11th', ... }, ...] I have already written a function to get the unique values for a particular field in this list of dictionaries, which was trivial. That function implements something like: select distinct NAME from ... However, I want to be able to get the list of multiple unique fields, similar to: select distinct NAME, CLASS from ... Which I am finding to be non-trivial. Is there an algorithm or Python included function to help me with this quandry? Before you suggest loading the CSV files into a SQLite table or something similar, that is not an option for the environment I'm in, and trust me, that was my first thought.

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  • I Can't Install or Remove Any Application

    - by berkay gürsoy
    when i try to install or remove an application via either software center or apt-get install they both fail and give some debconf errors below is the log please help.Sorry some of the text is not english. sudo apt-get install aptitude Paket listeleri okunuyor... Bitti Bagimlilik agaci insa ediliyor. Durum bilgisi okunuyor... Bitti Asagidaki ek paketler de yüklenecek: aptitude-common libboost-iostreams1.49.0 libcwidget3 Önerilen paketler: aptitude-doc-en aptitude-doc tasksel debtags libcwidget-dev Asagidaki YENI paketler kurulacak: aptitude aptitude-common libboost-iostreams1.49.0 libcwidget3 Yükseltilen: 0, Yeni Kurulan: 4, Kaldirilacak: 0 ve Yükseltilmeyecek: 48. 8 tam olarak kurulmadi veya kaldirilmadi. Indirilmesi gereken dosya boyutu 0 B/2.498 kB Bu islemden sonra 10,4 MB ek disk alani kullanilacak. Devam etmek istiyor musunuz [E/h]? e Use of uninitialized value in concatenation (.) or string at /usr/share/perl5/Debconf/DbDriver/File.pm line 44, <DEBCONF_CONFIG> chunk 3. Use of uninitialized value in -e at /usr/share/perl5/Debconf/DbDriver/File.pm line 46, <DEBCONF_CONFIG> chunk 3. Use of uninitialized value in pattern match (m//) at /usr/share/perl5/Debconf/DbDriver/File.pm line 47, <DEBCONF_CONFIG> chunk 3. Use of uninitialized value $directory in -d at /usr/share/perl5/Debconf/DbDriver/File.pm line 48, <DEBCONF_CONFIG> chunk 3. Use of uninitialized value $directory in concatenation (.) or string at /usr/share/perl5/Debconf/DbDriver/File.pm line 49, <DEBCONF_CONFIG> chunk 3. debconf: DbDriver "config": mkdir :Böyle bir dosya ya da dizin yok Selecting previously unselected package aptitude-common. dpkg: uyari: files list file for package 'aspell' missing; assuming package has no files currently installed dpkg: uyari: files list file for package 'ubuntu-desktop' missing; assuming package has no files currently installed dpkg: uyari: files list file for package 'vuze' missing; assuming package has no files currently installed dpkg: uyari: files list file for package 'java-wrappers' missing; assuming package has no files currently installed (Veritabani okunuyor... 198988 files and directories currently installed.) Unpacking aptitude-common (from .../aptitude-common_0.6.8.1-2ubuntu1_all.deb) ... Selecting previously unselected package libboost-iostreams1.49.0. Unpacking libboost-iostreams1.49.0 (from .../libboost-iostreams1.49.0_1.49.0-3.1ubuntu1_amd64.deb) ... Selecting previously unselected package libcwidget3. Unpacking libcwidget3 (from .../libcwidget3_0.5.16-3.4ubuntu1_amd64.deb) ... Selecting previously unselected package aptitude. Unpacking aptitude (from .../aptitude_0.6.8.1-2ubuntu1_amd64.deb) ... wicd-daemon (1.7.2.4-2ubuntu1) kuruluyor... Use of uninitialized value in concatenation (.) or string at /usr/share/perl5/Debconf/DbDriver/File.pm line 44, <DEBCONF_CONFIG> chunk 3. Use of uninitialized value in -e at /usr/share/perl5/Debconf/DbDriver/File.pm line 46, <DEBCONF_CONFIG> chunk 3. Use of uninitialized value in pattern match (m//) at /usr/share/perl5/Debconf/DbDriver/File.pm line 47, <DEBCONF_CONFIG> chunk 3. Use of uninitialized value $directory in -d at /usr/share/perl5/Debconf/DbDriver/File.pm line 48, <DEBCONF_CONFIG> chunk 3. Use of uninitialized value $directory in concatenation (.) or string at /usr/share/perl5/Debconf/DbDriver/File.pm line 49, <DEBCONF_CONFIG> chunk 3. debconf: DbDriver "config": mkdir :Böyle bir dosya ya da dizin yok dpkg: error processing wicd-daemon (--configure): installed post-installation script alt islemi çikis durumunda hata döndürdü : 1 man-db (2.6.3-1) kuruluyor... Use of uninitialized value in concatenation (.) or string at /usr/share/perl5/Debconf/DbDriver/File.pm line 44, <DEBCONF_CONFIG> chunk 3. Use of uninitialized value in -e at /usr/share/perl5/Debconf/DbDriver/File.pm line 46, <DEBCONF_CONFIG> chunk 3. Use of uninitialized value in pattern match (m//) at /usr/share/perl5/Debconf/DbDriver/File.pm line 47, <DEBCONF_CONFIG> chunk 3. Use of uninitialized value $directory in -d at /usr/share/perl5/Debconf/DbDriver/File.pm line 48, <DEBCONF_CONFIG> chunk 3. Use of uninitialized value $directory in concatenation (.) or string at /usr/share/perl5/Debconf/DbDriver/File.pm line 49, <DEBCONF_CONFIG> chunk 3. debconf: DbDriver "config": mkdir :Böyle bir dosya ya da dizin yok dpkg: error processing man-db (--configure): installed post-installation script alt islemi çikis durumunda hata döndürdü : 1 dictionaries-common (1.12.10) kuruluyor... Use of uninitialized value in concatenation (.) or string at /usr/share/perl5/Debconf/DbDriver/File.pm line 44, <DEBCONF_CONFIG> chunk 3. Use of uninitialized value in -e at /usr/share/perl5/Debconf/DbDriver/File.pm line 46, <DEBCONF_CONFIG> chunk 3. Use of uninitialized value in pattern match (m//) at /usr/share/perl5/Debconf/DbDriver/File.pm line 47, <DEBCONF_CONFIG> chunk 3. Use of uninitialized value $directory in -d at /usr/share/perl5/Debconf/DbDriver/File.pm line 48, <DEBCONF_CONFIG> chunk 3. Use of uninitialized value $directory in concatenation (.) or string at /usr/share/perl5/Debconf/DbDriver/File.pm line 49, <DEBCONF_CONFIG> chunk 3. debconf: DbDriver "config": mkdir :Böyle bir dosya ya da dizin yok dpkg: error processing dictionaries-common (--configure): installed post-installation script alt islemi çikis durumunda hata döndürdü : 1 dpkg: dependency problems prevent configuration of aspell: aspell depends on dictionaries-common (>> 0.40); bununla beraber: Package dictionaries-common is not configured yet. dpkg: error processing aspell (--configure): bagimlilik sorunlari - yapilandirilmadan birakiliyor dpkg: dependency problems prevent configuration of aspell-en: aspell-en depends on aspell (>= 0.60.3-2); bununla beraber: Package aspell is not configured yet. aspell-en depends on dictionaries-common (>= 0.49.2); bununla beraber: Package dictionaries-common is not configured yet. dpkg: error processing aspell-en (--configure): bagimlilik sorunlari - yapilandirilmadan birakiliyor dpkg: dependency problems prevent configuration of hyphen-en-us: hyphen-en-us depends on dictionaries-common (>= 0.10) | openoffice.org-updatedicts; bununla beraber: Package dictionaries-common is not configured yet. openoffice.org-updatedicts paketi yüklenmedi. Package dictionaries-common which provides openoffice.org-updatedicts is not configured yet. dpkg: error processing hyphen-en-us (--configure): bagimlilik sorunlari - yapilandirilmadan birakiliyor dpkg: dependency problems prevent configuration of wicd-gtk: wicd-gtk depends on wicd-daemon (= 1.7.2.4-2ubuntu1); bununla beraber: Package wicd-daemon is not configured yet. dpkg: error processing wicd-gtk (--configure): bagimlilik sorunlari - yapilandirilmadan birakiliyor dpkg: dependency problems prevent configuration of wicd: wicd depends on wicd-daemon (= 1.7.2.4-2ubuntu1); bununla beraber: Package wicd-daemon is not configured yet. wicd depends on wicd-gtk (= 1.7.2.4-2ubuntu1) | wicd-curses (= 1.7.2.4-2ubuntu1) | wicd-cli (= 1.7.2.4-2ubuntu1) | wicd-client; bununla beraber: Package wicd-gtk is not configured yet. wicd-curses paketi yüklenmedi. wicd-cli paketi yüklenmedi. wicd-client paketi yüklenmedi. Package wicd-gtk which provides wicd-client is not configured yet. dpkg: error processing wicd (--configure): bagimlilik sorunlari - yapilandirilmadan birakiliyor aptitude-common (0.6.8.1-2ubuntu1) kuruluyor... libboost-iostreams1.49.0 (1.49.0-3.1ubuntu1) kuruluyor... libcwidget3 (0.5.16-3.4ubuntu1) kuruluyor... aptitude (0.6.8.1-2ubuntu1) kuruluyor... update-alternatives: using /usr/bin/aptitude-curses to provide /usr/bin/aptitude (aptitude) in Otomatik Mod Processing triggers for libc-bin ... ldconfig deferred processing now taking place Islem sirasinda hatalar bulundu: wicd-daemon man-db dictionaries-common aspell aspell-en hyphen-en-us wicd-gtk wicd E: Sub-process /usr/bin/dpkg returned an error code (1)

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  • Loading data from a dictionary of dictionaries into an array in Objective C for an iphone app

    - by Kat
    I have a UINavigationController consisting of a tableview I want to load some data into. I have a dictionary plist containing Dictionaries for each Train Line which in turn have dictionaries for each station with the relevant information along with one string lineName. I need to collect the station Names keys and add them to an array to populate my table (This is working). The line names are stored as a string in my lines dictionary with the key being "lineName" Root->| | |->TrainLine1(Dictionary)->| | |-> lineName (String) | |-> Station1 (Dictionary) | |-> Station2 (Dictionary) | | |->TrainLine2(Dictionary)->| | |-> lineName (String) | |-> Station1 (Dictionary) | |-> Station2 (Dictionary) Am I going about this the wrong way? Should I reorganise my plist? The code below crashes the app. - (void)viewDidLoad { self.title = @"Train Lines"; NSString *path = [[NSBundle mainBundle] pathForResource:@"lineDetails" ofType:@"plist"]; NSDictionary *dictionary = [[NSDictionary alloc] initWithContentsOfFile:path]; NSMutableArray *array = [[NSMutableArray alloc] init]; NSMutableArray *lineNameArray = [[NSMutableArray alloc] init]; NSString *key; for (key in dictionary) { NSMutableDictionary *secondDictionary = [NSDictionary dictionaryWithDictionary:[dictionary valueForKey:key]]; [lineNameArray addObject:key]; NSLog(@"Adding this in array:%@", key); [array addObject:[secondDictionary objectForKey:kLineNameKey]]; } self.trainLines = array; self.trainLineKeys = lineNameArray; NSLog(@"Array contents:%@", self.trainLineKeys); [lineNameArray release]; [array release]; [dictionary release]; [super viewDidLoad]; }

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  • How to Declare an Array of Generic Dictionaries in C#?

    - by Nave
    I want to create an array of Dictionaries. But the array size is unknown. For integer, i used List to obtain the integer array of unknown size. But in the case of Dictionary, am not able to create a list of Dictionary. Is thr any wayz by which this can be done? Dictionary(int, String) paramList=null;I am want to create the array of paramList(above). I am using C Sharp.

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  • C#: Get a list of every value for a given key in a set of dictionaries?

    - by Rosarch
    How can I write this code more cleanly/concisely? /// <summary> /// Creates a set of valid URIs. /// </summary> /// <param name="levelVariantURIDicts">A collection of dictionaries of the form: /// dict["filePath"] == theFilePath </param> /// <returns></returns> private ICollection<string> URIsOfDicts(ICollection<IDictionary<string, string>> levelVariantURIDicts) { ICollection<string> result = new HashSet<string>(); foreach (IDictionary<string, string> dict in levelVariantURIDicts) { result.Add(dict["filePath"]); } return result; }

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  • How can I use Linq to create an array of dictionaries from XML?

    - by Duke
    Given the following XML structure: <courses> <course> <title>foo</title> <description>bar</description> </course> ... </courses> How could I create an array of dictionaries such that each dictionary contains all the element/value pairs within a course? What I have right now generates an array whose elements contain a single key/value dictionary for each element/value pair in a course: XElement x = XElement.Parse("...xml string..."); var foo = (from n in x.Elements() select n) .Elements().ToDictionary(y => y.Name, y => y.Value); Produces: [0] => {[course, foo]} [1] => {[description, bar]} What I'd like is this: [0] => {[course, foo], [description, bar]}

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  • Counting entries in a list of dictionaries: for loop vs. list comprehension with map(itemgetter)

    - by Dennis Williamson
    In a Python program I'm writing I've compared using a for loop and increment variables versus list comprehension with map(itemgetter) and len() when counting entries in dictionaries which are in a list. It takes the same time using a each method. Am I doing something wrong or is there a better approach? Here is a greatly simplified and shortened data structure: list = [ {'key1': True, 'dontcare': False, 'ignoreme': False, 'key2': True, 'filenotfound': 'biscuits and gravy'}, {'key1': False, 'dontcare': False, 'ignoreme': False, 'key2': True, 'filenotfound': 'peaches and cream'}, {'key1': True, 'dontcare': False, 'ignoreme': False, 'key2': False, 'filenotfound': 'Abbott and Costello'}, {'key1': False, 'dontcare': False, 'ignoreme': True, 'key2': False, 'filenotfound': 'over and under'}, {'key1': True, 'dontcare': True, 'ignoreme': False, 'key2': True, 'filenotfound': 'Scotch and... well... neat, thanks'} ] Here is the for loop version: #!/usr/bin/env python # Python 2.6 # count the entries where key1 is True # keep a separate count for the subset that also have key2 True key1 = key2 = 0 for dictionary in list: if dictionary["key1"]: key1 += 1 if dictionary["key2"]: key2 += 1 print "Counts: key1: " + str(key1) + ", subset key2: " + str(key2) Output for the data above: Counts: key1: 3, subset key2: 2 Here is the other, perhaps more Pythonic, version: #!/usr/bin/env python # Python 2.6 # count the entries where key1 is True # keep a separate count for the subset that also have key2 True from operator import itemgetter KEY1 = 0 KEY2 = 1 getentries = itemgetter("key1", "key2") entries = map(getentries, list) key1 = len([x for x in entries if x[KEY1]]) key2 = len([x for x in entries if x[KEY1] and x[KEY2]]) print "Counts: key1: " + str(key1) + ", subset key2: " + str(key2) Output for the data above (same as before): Counts: key1: 3, subset key2: 2 I'm a tiny bit surprised these take the same amount of time. I wonder if there's something faster. I'm sure I'm overlooking something simple. One alternative I've considered is loading the data into a database and doing SQL queries, but the data doesn't need to persist and I'd have to profile the overhead of the data transfer, etc., and a database may not always be available. I have no control over the original form of the data. The code above is not going for style points.

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  • How would I merged nested dictionaries in a list in python?

    - by Kevin
    for example if i had the result [{'Germany': {"Luge - Men's Singles": 'Gold'}}, {'Germany': {"Luge - Men's Singles": 'Silver'}}, {'Italy': {"Luge - Men's Singles": 'Bronze'}}] [{'Germany': {"Luge - Women's Singles": 'Gold'}}, {'Austria': {"Luge - Women's Singles": 'Silver'}}, {'Germany': {"Luge - Women's Singles": 'Bronze'}}] [{'Austria': {'Luge - Doubles': 'Gold'}}, {'Latvia': {'Luge - Doubles': 'Silver'}}, {'Germany': {'Luge - Doubles': 'Bronze'}}] how would I sort this so that all of the events germany and so on had won could be under one single title. i.e germany would be germany:Luge - Men's Singles: Gold, Silver, Luge - Women's Singles: Gold, Bronze, Luge - Doubles: Bronze. thanks for any help

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  • Why can't I find DataTemplates in merged resource dictionaries?

    - by dthrasher
    In my MainWindow.xaml, I have the following reference to a ResourceDictionary: <Window.Resources> <ResourceDictionary> <ResourceDictionary.MergedDictionaries> <ResourceDictionary Source="MainSkin.xaml" /> </ResourceDictionary.MergedDictionaries> </ResourceDictionary> </Window.Resources> In MainSkin.xaml, I define a datatemplate: <DataTemplate x:Key="TagTemplate"> ... </DataTemplate> Deeper within my application, I attempt to use this data template: <ContentControl DataContext="{Binding Tag}" ContentTemplate="{StaticResource TagTemplate}"/> The code compiles successfully, but when I attempt to load a Page or UserControl that contains this StaticResource, I get an exception saying that the TagTemplate can't be found. What am I doing wrong?

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  • How to make firefox to spellcheck in multiple languages simultaneously?

    - by Vi
    I want to it to assume that text may be in mixture of languages and words should be looked up in multiple dictionaries. (E.g. everything in en-GB, en-US, ru, be and be-classic should be consider as good, everything else should be underlined and corrections from all dictionaries should be offered). Is there an add-on for "multi-language spell-check"? Alternatively, can I merge all dictionaries into one big combined dictionary?

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  • Force apt to remove all emacs*

    - by wishi
    Hi! I have a bug-problem with the apt-packages of emacs: >>Error occurred processing debian-ispell.el: File error (("Opening input file" "no such file or directory" "/usr/share/emacs23/site-lisp/dictionaries-common/debian-ispell.el")) >>Error occurred processing ispell.el: File error (("Opening input file" "no such file or directory" "/usr/share/emacs23/site-lisp/dictionaries-common/ispell.el")) >>Error occurred processing flyspell.el: File error (("Opening input file" "no such file or directory" "/usr/share/emacs23/site-lisp/dictionaries-common/flyspell.el")) emacs-install: /usr/lib/emacsen-common/packages/install/dictionaries-common emacs23 failed at /usr/lib/emacsen-common/emacs-install line 28, <TSORT> line 30. dpkg: error processing emacs23-lucid (--configure): subprocess installed post-installation script returned error exit status 1 dpkg: dependency problems prevent configuration of emacs: emacs depends on emacs23 | emacs23-lucid | emacs23-nox; however: Package emacs23 is not installed. Package emacs23-lucid which provides emacs23 is not configured yet. Package emacs23-nox which provides emacs23 is not installed. Package emacs23-lucid is not configured yet. Package emacs23-nox is not installed. dpkg: error processing emacs (--configure): dependency problems - leaving unconfigured No apport report written because the error message indicates its a followup error from a previous failure. Errors were encountered while processing: emacs23-lucid emacs E: Sub-process /usr/bin/dpkg returned an error code (1) In fact I would be satisfied with just emacs23-nox, a couple of plugins - from apt. But I can neither --purge nor --purge reinstall, nor remove the packages. It always processes until this certain bug. I did some google-searching, found some stuff on Launchpad suggesting: sudo apt-get install --reinstall --purge emacsen-common But this is the same... so I hope there a way to tell app to just remove everything releated to emacs, and to start from scratch again? Thanks, Marius

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