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• Getting a RichTextCtrl's default font size in wxPython

  - by Sam

  I have a RichTextCtrl, which I've modified to accept HTML input. The HTML parsing code needs to be able to increase and decrease the font size as it gets tags like <font size="-1">, but I can't work out how to get the control's default font size to adjust. I tried the following (where self is my RichTextCtrl): fred = wx.richtext.RichTextAttr() self.GetStyle(0,fred) print fred.GetFontSize() However, the final instruction fails, because GetStyle turns fred into a TextAttrEx and so I get AttributeError: 'TextAttrEx' object has no attribute 'GetFontSize'. Am I missing a vastly easier way of getting the default font size?

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• Using a member function pointer within a class

  - by neuviemeporte

  Given an example class: class Fred { public: Fred() { func = &Fred::fa; } void run() { int foo, bar; *func(foo,bar); } double fa(int x, int y); double fb(int x, int y); private: double (Fred::*func)(int x, int y); }; I get a compiler error at the line calling the member function through the pointer "*func(foo,bar)", saying: "term does not evaluate to a function taking 2 arguments". What am I doing wrong?

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• Checking data of all same class elements

  - by Tiffani

  I need the code to check the data-name value of all instances of .account-select. Right now it just checks the first .account-select element and not any subsequent ones. The function right now is on click of an element such as John Smith, it checks the data-name of the .account-select lis. If the data-names are the same, it does not create a new li with the John Smith data. If no data-names are equal to John Smith, then it adds an li with John Smith. This is the JS-Fiddle I made for it so you can see what I am referring to: http://jsfiddle.net/rsxavior/vDCNy/22/ Any help would be greatly appreciated. This is the Jquery Code I am using right now. $('.account').click(function () { var acc = $(this).data("name"); var sel = $('.account-select').data("name"); if (acc === sel) { } else { $('.account-hidden-li').append('<li class="account-select" data-name="'+ $(this).data("name") +'">' + $(this).data("name") + '<a class="close bcn-close" data-dismiss="alert" href="#">&times;</a></li>'); } }); And the HTML: <ul> <li><a class="account" data-name="All" href="#">All</a></li> <li><a class="account" data-name="John Smith" href="#">John Smith</a></li> </ul> <ul class="account-hidden-li"> <ul>

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• a little code to allow word substitution depending on user

  - by Fred Quimby

  Can anyone help? I'm creating a demo web app in html in order for people to physically see and comment on the app prior to committing to a proper build. So whilst the proper app will be database driven, my demo is just standard html with some javascript effects. What I do want to demonstrate is that different user group will see different words. For example, imagine I have an html sentence that says 'This will cost £100 to begin'. What I need to some way of identifying that if the user has deemed themselves to be from the US, the sentence says 'This will cost $100 to begin'. This requirement is peppered throughtout the pages but I'm happy to add each one manually. So I envisage some code along the lines of 'first, remove the [boot US] trunk' where the UK version is 'first remove the boot' but the code is saying that the visitor needs the US version. It then looks up boot (in an Access database perhaps) and sees that the table says for boot for US, display 'trunk'. I'm not a programmer but I can normally cobble together scripts so I'm hoping someone may have a relatively easy solution in javascrip, CSS or asp. To recap; I have a number of words or short sentences that need to appear differently and I'm happy to manually insert each one if necessary (but would be even better if the words were automatically changed). And I need a device which allows me to tell the pages to choose the US version, or for example, the New Zealand version. Thanks in advance. Fred

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• Rewriting from headers in Postfix

  - by inxilpro

  I want to configure Postfix to replace the 'From' header in all forwarded/aliased messages with a custom email address, and the 'Reply-To' header with the original sender's address. Is that something that can be done with a simple configuration change, or am I looking at a more complex problem? For example: Original Message: From: "John Smith" <[email protected]> To: "Jane Rice" <[email protected]> Would get translated to: From: "My Email Forwarding Service" <[email protected]> Reply-To: "John Smith" <[email protected]> To: "Jane Rice" <[email protected]> Ideally, I would also have it rewrite the message body (adding something about how the message was forwarded for them), but I know that's much more difficult. We have a number of email aliases, and everytime someone reports spam they received through their alias, our server gets flagged. I'm trying to minimize that damage as much as possible. Any help is greatly appreciated!

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• Resize Debian in VirtualBox

  - by Poni

  I have a VM with one HD of size 3GB and I'd like to enlarge its HD to 7GB. So I execute this command on the host (while guest is shutdown): VBoxManage modifyhd debian.vdi --resize 7168 Then I run the guest, Debian 6, and then: smith@debian6:~$ df -h Filesystem Size Used Avail Use% Mounted on /dev/sda1 2.8G 2.6G 60M 98% / tmpfs 61M 0 61M 0% /lib/init/rw udev 57M 160K 57M 1% /dev tmpfs 61M 0 61M 0% /dev/shm smith@debian6:~$ sudo parted /dev/sda print Model: ATA VBOX HARDDISK (scsi) Disk /dev/sda: 3221MB Sector size (logical/physical): 512B/512B Partition Table: msdos Number Start End Size Type File system Flags 1 1049kB 3035MB 3034MB primary ext3 boot 2 3036MB 3220MB 185MB extended 5 3036MB 3220MB 185MB logical linux-swap(v1) smith@debian6:~$ cat /proc/partitions major minor #blocks name 8 0 3145728 sda 8 1 2962432 sda1 8 2 1 sda2 8 5 180224 sda5 So, no automatic resizing (detection) of the HD/partition (while VirtualBox, in the host, shows it's 7GB now). Ok... Then I do: smith@debian6:~$ sudo resize2fs /dev/sda1 resize2fs 1.41.12 (17-May-2010) The filesystem is already 740608 blocks long. Nothing to do! smith@debian6:~$ sudo parted GNU Parted 2.3 Using /dev/sda Welcome to GNU Parted! Type 'help' to view a list of commands. (parted) select /dev/sda1 Using /dev/sda1 (parted) resize WARNING: you are attempting to use parted to operate on (resize) a file system. parted's file system manipulation code is not as robust as what you'll find in dedicated, file-system-specific packages like e2fsprogs. We recommend you use parted only to manipulate partition tables, whenever possible. Support for performing most operations on most types of file systems will be removed in an upcoming release. Partition number? 1 Start? 0 End? [3034MB]? Here I'm stuck. At the above parted it asks me to resize to 3GB. No point in that, right.. What should I do in order to enlarge this partition?

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• OpenLDAP Authentication UID vs CN issues

  - by user145457

  I'm having trouble authenticating services using uid for authentication, which I thought was the standard method for authentication on the user. So basically, my users are added in ldap like this: # jsmith, Users, example.com dn: uid=jsmith,ou=Users,dc=example,dc=com uidNumber: 10003 loginShell: /bin/bash sn: Smith mail: [email protected] homeDirectory: /home/jsmith displayName: John Smith givenName: John uid: jsmith gecos: John Smith gidNumber: 10000 cn: John Smith title: System Administrator But when I try to authenticate using typical webapps or services like this: jsmith password I get: ldapsearch -x -h ldap.example.com -D "cn=jsmith,ou=Users,dc=example,dc=com" -W -b "dc=example,dc=com" Enter LDAP Password: ldap_bind: Invalid credentials (49) But if I use: ldapsearch -x -h ldap.example.com -D "uid=jsmith,ou=Users,dc=example,dc=com" -W -b "dc=example,dc=com" It works. HOWEVER...most webapps and authentication methods seem to use another method. So on a webapp I'm using, unless I specify the user as: uid=smith,ou=users,dc=example,dc=com Nothing works. In the webapp I just need users to put: jsmith in the user field. Keep in mind my ldap is using the "new" cn=config method of storing settings. So if someone has an obvious ldif I'm missing please provide. Let me know if you need further info. This is openldap on ubuntu 12.04. Thanks, Dave

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• IPv6 tunnel broker setup

  - by fred basset

  I'm working on a solution to allow remote Linux nodes that are behind firewalls to be accessible for SSH and web server. Can anyone suggest an IPv6 tunnel scheme that would work with NAT firewalls? And what software would be needed on the remote nodes and the central server? Also I do not believe the ISP at either side does native IPv6. A solution where we could have static IPv6 addresses on the remote Linux nodes would be ideal. Thank you, Fred

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• Should be simple: existing laptop with local user and outlook 2007 migrate on same computer to domain user with outlook 2007 emails intact

  - by bifpowell

  I have Dell Laptop with windows 7 64 bit and for the last year it's been just a machine with an account like: machine\john there are files in folders and stuff in c:\users\john and john uses outlook 2007 as a pop3 client and has identifiable local appdata pst files. Now I installed a server and want to have everything be domain-centric so I added this laptop to the domain with admin credentials and then logged in as a domain user as: domain\john.smith Now I want to duplicate machine\john (outlook emails mostly) to domain\john.smith. In the past I used the Files and Settings Xfer Wizard and done. I tried that here and it crunched away for a while, made the file, but the restore had no effect - it ran for a while, had a progress bar, but it's like nothing happened at all afterwards. I've rebooted the machine, logged in as domain administrator as the first user to log on after the restart and tried: c:\users\john xcopy c:\users\john c:\users\john.smith /V /C /F /H /K /Y /E ...and it copies some of it, but when it gets to c:\users\john.smith\appdata\local\application data it chokes "Access denied, unable to create directory" I also tried logging in as domain\john.smith and copying the entire directory that the PSTs are in from machine\john and a lot of the mail was there when I launched outlook after replacing the PSTs, but not all of them??? I got errors about files in use when doing this method, which I figure must be why not all the old emails are in the inbox?... There must be some extremely simple way to do what must be a very common requirement. Any guidance appreciated.

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• Comparing columns in Excel

  - by Regan

  I needed to take columns A, B, and C and compare D, E and F. Here's an example: A B C D E F Jump Smith 5 Jump Smith 8 Run Naylor 2 Swim Fran 4 Swim Fran 7 Jog Dylan 1 Jump Fran 3 Jog Smith 4 So I want to match column A and B with D and E but still have both number related C for 2011 and F for 2012. Can anyone please help with that formula? My data is from A3-C4344 and D3 - D4470.

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• Varnish: User specific pages

  - by jchong0707

  I'm new to Varnish and am interested in using it to speed up my web application I wanted to know if Varnish can handle caching and serving user specific content. For example if I have a page say for example /welcome which is dynamically generated in the backend and is user specific So if User John Smith shows up to /welcome it'll show in the page itself 'Welcome John Smith' and if Bob Smith shows up to /welcome it'll show 'Welcome Bob Smith' Ideally both of those /welcome pages will be cached for each unique User, is this something Varnish can do? (is this even a good Use Case of Varnish?) Thanks!

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• Copying content on webpages in safari. To HTML

  - by Carl Smith

  Hi, is there an easier way to copy and paste website content in html? Want to copy and look like this. Product Information: Length: S / M / L Material: Polyester and Elasthane Brand: Roxana Exclusive Style: Basque But when i paste it into my content box it looks like this- Product Information Length: S / M / L Material: Polyester and Elasthane Brand: Roxana Exclusive Style: Basque Then i need to edit it in the html editor to rearrange it. Is the some sort of app or plugin that i can get so i can turn the text of the page into html so it looks right straight away when i copy it into my content box? If that makes any sense? Thanks Carl Smith :-)

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• Gateway IP Returns to Zero

  - by Robert Smith

  When you set a static IP under Ubuntu 12.04.1, you must supply the desired machine IP and the gateway IP, all using the Network Manager. When I first entered them and rebooted, everything worked great. On the second boot, however, Firefox could find no Web page. Upon checking, I discovered that the gateway IP had returned to zero. Now, no matter how often I resupply it, it returns to zero immediately after NM "saves" it: that is, appears as zero when redisplayed. The only way I can get to the Internet is to restore DHCP operation. I need to use static IP for access to my home network. Would appreciate any suggestion. --Robert Smith

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• Ways to ensure unique instances of a class?

  - by Peanut

  I'm looking for different ways to ensure that each instance of a given class is a uniquely identifiable instance. For example, I have a Name class with the field name. Once I have a Name object with name initialised to John Smith I don't want to be able to instantiate a different Name object also with the name as John Smith, or if instantiation does take place I want a reference to the orginal object to be passed back rather than a new object. I'm aware that one way of doing this is to have a static factory that holds a Map of all the current Name objects and the factory checks that an object with John Smith as the name doesn't already exist before passing back a reference to a Name object. Another way I could think of off the top of my head is having a static Map in the Name class and when the constructor is called throwing an exception if the value passed in for name is already in use in another object, however I'm aware throwing exceptions in a constructor is generally a bad idea. Are there other ways of achieving this?

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• Summing / Running totals

  - by John

  I have 4 columns: Name, Week, Batch and Units Produced (Cols, A,b,c,d). In column e, I need to keep running totals based on name and week. When the week changes for the same person, restart the total. Fred, 12, 4001, 129.0 Answer in e: 129.0 Fred, 12, 4012, 234.0 Answer in e: 363.0 Fred, 13, 4023, 12.0 Answer in e: 12.0 John, 12, 4003, 420.0 Answer in e: 420.0 John, 13, 4021, 1200.0 Answer in e: 1200.0 John, 13, 4029, 120.0 Answer in e: 1320.0 I need to be able to copy the formula to over 1000 rows.

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• Ping, firewall or DNS problem on Win Server 2008 R2

  - by Fred Kaiser

  Hi there, I've installed windows server 2008 as a VM for the developers here to work on. Installed SQL Server 2008 as well as IIS7. I am not quite sure why, I can remote into that machine using the name I gave to it (winserverdev) but the guys that are supposed to use the bloody thing can't. One very interesting thing is that I can connect but I can't ping... not the name nor the IP address. Is there anything that I should be looking in order to make it work? Any ideas are welcome. Thanks heaps in advance, I really appreciate it. Cheers, Fred Kaiser

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• Inserting a very long Excel table into Word

  - by Fred

  I have a very long excel (2003) s/sheet with in excess of 600 rows that I want to paste into an MS Word document (also 2003). However, I want to ensure that: 1) The header row appears automatically at the top of each page. 2) The s/sheet automatically formats to the correct page width (the one I have is slightly wider than my Word page). This can obviously be done manually by cutting and pasting each page seperately but this is very laborious and time consuming and I once saw somebody achieve this automatically (maybe with a macro) but have been unable to locate them, or the methodology. Can anyone please assist? Thanks in advance, Fred.

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• How to calculate running totals of subsets of data in a table

  - by John

  I have 4 columns: Name, Week, Batch and Units Produced (Cols, A,B,C,D). In column E, I need to keep running totals based on name and week. When the week changes for the same person, restart the total. Fred, 12, 4001, 129.0 Answer in e: 129.0 Fred, 12, 4012, 234.0 Answer in e: 363.0 Fred, 13, 4023, 12.0 Answer in e: 12.0 John, 12, 4003, 420.0 Answer in e: 420.0 John, 13, 4021, 1200.0 Answer in e: 1200.0 John, 13, 4029, 120.0 Answer in e: 1320.0 I need to be able to copy the formula to over 1000 rows.

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• rsync server, uploaded files permissions incorrect

  - by fred basset

  I'm trying to setup an rsync server on my Ubuntu machine. Transfer from a local PC to the server via rsync does work, but the resultant uploaded files have no r,w or x bits set, e.g. ---------- 1 fredb fredb 0 Aug 30 20:50 sk_upgrade_20120830_033450.txt ---------- 1 fredb fredb 0 Aug 30 20:50 sk_user_20120827_184534.txt ---------- 1 fredb fredb 0 Aug 30 20:50 sk_user_20120830_033450.txt My rsyncd.conf file is: motd file = /etc/rsyncd.motd [workspace] path = /tmp comment = rsync server uid = nobody gid = nobody read only = false auth users = fredb secrets file = /etc/rsyncd.scrt How can I get the target files permissions correct? Also once I've solved this problem how can I transfer without a password? TY, Fred

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• What is the effect of this order_by clause?

  - by bread

  I don't understand what this order_by clause is doing and whether I need it or not: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date order by i.order_date desc; This produces this data: 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10101 John Gray 30-Jun-1999 Raft 58.00 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10101 John Gray 02-Jan-2000 Lantern 16.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 While if I remove the order_by clause completely, as in this query: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date; I get these results: 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10101 John Gray 02-Jan-2000 Lantern 16.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10101 John Gray 30-Jun-1999 Raft 58.00 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 I'm not sure what the order_by is doing here and if it's having the intended effects.

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• Attempting to extract a pattern within a string

  - by Brian

  I'm attempting to extract a given pattern within a text file, however, the results are not 100% what I want. Here's my code: import java.util.regex.Matcher; import java.util.regex.Pattern; public class ParseText1 { public static void main(String[] args) { String content = "<p>Yada yada yada <code> foo ddd</code>yada yada ...\n" + "more here <2004-08-24> bar<Bob Joe> etc etc\n" + "more here again <2004-09-24> bar<Bob Joe> <Fred Kej> etc etc\n" + "more here again <2004-08-24> bar<Bob Joe><Fred Kej> etc etc\n" + "and still more <2004-08-21><2004-08-21> baz <John Doe> and now <code>the end</code> </p>\n"; Pattern p = Pattern .compile("<[1234567890]{4}-[1234567890]{2}-[1234567890]{2}>.*?<[^%0-9/]*>", Pattern.MULTILINE); Matcher m = p.matcher(content); // print all the matches that we find while (m.find()) { System.out.println(m.group()); } } } The output I'm getting is: <2004-08-24> bar<Bob Joe> <2004-09-24> bar<Bob Joe> <Fred Kej> <2004-08-24> bar<Bob Joe><Fred Kej> <2004-08-21><2004-08-21> baz <John Doe> and now <code> The output I want is: <2004-08-24> bar<Bob Joe> <2004-08-24> bar<Bob Joe> <2004-08-24> bar<Bob Joe> <2004-08-21> baz <John Doe> In short, the sequence of "date", "text (or blank)", and "name" must be extracted. Everything else should be avoided. For example the tag "Fred Kej" did not have any "date" tag before it, therefore, it should be flagged as invalid. Also, as a side question, is there a way to store or track the text snippets that were skipped/rejected as were the valid texts. Thanks, Brian

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• Tricky SQL query involving consecutive values

  - by Gabriel

  I need to perform a relatively easy to explain but (given my somewhat limited skills) hard to write SQL query. Assume we have a table similar to this one: exam_no | name | surname | result | date ---------+------+---------+--------+------------ 1 | John | Doe | PASS | 2012-01-01 1 | Ryan | Smith | FAIL | 2012-01-02 <-- 1 | Ann | Evans | PASS | 2012-01-03 1 | Mary | Lee | FAIL | 2012-01-04 ... | ... | ... | ... | ... 2 | John | Doe | FAIL | 2012-02-01 <-- 2 | Ryan | Smith | FAIL | 2012-02-02 2 | Ann | Evans | FAIL | 2012-02-03 2 | Mary | Lee | PASS | 2012-02-04 ... | ... | ... | ... | ... 3 | John | Doe | FAIL | 2012-03-01 3 | Ryan | Smith | FAIL | 2012-03-02 3 | Ann | Evans | PASS | 2012-03-03 3 | Mary | Lee | FAIL | 2012-03-04 <-- Note that exam_no and date aren't necessarily related as one might expect from the kind of example I chose. Now, the query that I need to do is as follows: From the latest exam (exam_no = 3) find all the students that have failed (John Doe, Ryan Smith and Mary Lee). For each of these students find the date of the first of the batch of consecutively failing exams. Another way to put it would be: for each of these students find the date of the first failing exam that comes after their last passing exam. (Look at the arrows in the table). The resulting table should be something like this: name | surname | date_since_failing ------+---------+-------------------- John | Doe | 2012-02-01 Ryan | Smith | 2012-01-02 Mary | Lee | 2012-01-04 Ann | Evans | 2012-02-03 How can I perform such a query? Thank you for your time.

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• Odd SQL Results

  - by Ryan Burnham

  So i have the following query Select id, [First], [Last] , [Business] as contactbusiness, (Case When ([Business] != '' or [Business] is not null) Then [Business] Else 'No Phone Number' END) from contacts The results look like id First Last contactbusiness (No column name) 2 John Smith 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number I'd expect record 2 to also show No Phone Number If i change the "[Business] is not null" to [Business] != null then i get the correct results id First Last contactbusiness (No column name) 2 John Smith No Phone Number 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number Normally you need to use is not null rather than != null. whats going on here?

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• Creating an excel macro to sum lines with duplicate values

  - by john

  I need a macro to look at the list of data below, provide a number of instances it appears and sum the value of each of them. I know a pivot table or series of forumlas could work but i'm doing this for a coworker and it has to be a 'one click here' kinda deal. The data is as follows. A B Smith 200.00 Dean 100.00 Smith 100.00 Smith 50.00 Wilson 25.00 Dean 25.00 Barry 100.00 The end result would look like this Smith 3 350.00 Dean 2 125.00 Wilson 1 25.00 Barry 1 100.00 Thanks in advance for any help you can offer!

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• Simple Select Statement on MySQL Database Hanging

  - by AlishahNovin

  I have a very simple sql select statement on a very large table, that is non-normalized. (Not my design at all, I'm just trying to optimize while simultaneously trying to convince the owners of a redesign) Basically, the statement is like this: SELECT FirstName, LastName, FullName, State FROM Activity Where (FirstName=@name OR LastName=@name OR FullName=@name) AND State=@state; Now, FirstName, LastName, FullName and State are all indexed as BTrees, but without prefix - the whole column is indexed. State column is a 2 letter state code. What I'm finding is this: When @name = 'John Smith', and @state = '%' the search is really fast and yields results immediately. When @name = 'John Smith', and @state = 'FL' the search takes 5 minutes (and usually this means the web service times out...) When I remove the FirstName and LastName comparisons, and only use the FullName and State, both cases above work very quickly. When I replace FirstName, LastName, FullName, and State searches, but use LIKE for each search, it works fast for @name='John Smith%' and @state='%', but slow for @name='John Smith%' and @state='FL' When I search against 'John Sm%' and @state='FL' the search finds results immediately When I search against 'John Smi%' and @state='FL' the search takes 5 minutes. Now, just to reiterate - the table is not normalized. The John Smith appears many many times, as do many other users, because there is no reference to some form of users/people table. I'm not sure how many times a single user may appear, but the table itself has 90 Million records. Again, not my design... What I'm wondering is - though there are many many problems with this design, what is causing this specific problem. My guess is that the index trees are just too large that it just takes a very long time traversing the them. (FirstName, LastName, FullName) Anyway, I appreciate anyone's help with this. Like I said, I'm working on convincing them of a redesign, but in the meantime, if I someone could help me figure out what the exact problem is, that'd be fantastic.

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