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  • gridview commandargument on buttonfield pagination used

    - by ClareBear
    Hello all, I am using c#.net I have a gridview which needs to contain a 'Use' button (appointmentId set as the commandargument). Source Code <asp:GridView ID="resultsReturned" runat="server" AllowPaging="True" AutoGenerateColumns="False" EnableSortingAndPagingCallbacks="True" OnPageIndexChanged="resultsReturned_PageIndexChanged" onrowcommand="resultsReturned_RowCommand"> <Columns> <asp:BoundField DataField="UserAppointmentId" HeaderText="App ID" /> <asp:BoundField DataField="UserBookingName" HeaderText="Booking Name" /> <asp:TemplateField> <ItemTemplate> <asp:Button runat="server" ID="UseButton" Text="Use" CommandName="Use" CommandArgument="UserAppointmentId" /> </ItemTemplate> </asp:TemplateField> </Columns> </asp:GridView> Code-Behind protected void resultsReturned_RowCommand(object sender, GridViewCommandEventArgs e) { if (e.CommandName == "Use") { correctAppointmentID.Value = (e.CommandArgument.ToString()); } } This is used for the pagination: private void BindAppointments() { var results = appointmentRepos.GetBookingIdBySearchCriteria(catgoryid, resultsReturned.PageIndex * resultsReturned.PageSize, -1); resultsReturned.DataSource = results; resultsReturned.DataBind(); } I am binding the appointments to the gridview within the PageLoad/search_Click This is the error I am receiving: Callbacks are not supported on TemplateField because some controls cannot update properly in a callback. Turn callbacks off on 'resultsReturned'. Thanks in advance for any help Clare

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  • Codeigniter Pagination: Run the Query Twice?

    - by Frank
    I'm using codeigniter and the pagination class. This is such a basic question, but I need to make sure I'm not missing something. In order to get the config items necessary to paginate results getting them from a MySQL database it's basically necessary to run the query twice is that right? In other words, you have to run the query to determine the total number of records before you can paginate. So I'm doing it like: Do this query to get number of results $this->db->where('something', $something); $query = $this->db->get('the_table_name'); $num_rows = $query->num_rows(); Then I'll have to do it again to get the results with the limit and offset. Something like: $this->db->where('something', $something); $this->db->limit($limit, $offset); $query = $this->db->get('the_table_name'); if($query->num_rows()){ foreach($query->result_array() as $row){ ## get the results here } } I just wonder if I'm actually doing this right in that the query always needs to be run twice? The queries I'm using are much more complex than what is shown above.

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  • Strategy for locale sensitive sort with pagination

    - by Thom Birkeland
    Hi, I work on an application that is deployed on the web. Part of the app is search functions where the result is presented in a sorted list. The application targets users in several countries using different locales (= sorting rules). I need to find a solution for sorting correctly for all users. I currently sort with ORDER BY in my SQL query, so the sorting is done according to the locale (or LC_LOCATE) set for the database. These rules are incorrect for those users with a locale different than the one set for the database. Also, to further complicate the issue, I use pagination in the application, so when I query the database I ask for rows 1 - 15, 16 - 30, etc. depending on the page I need. However, since the sorting is wrong, each page contains entries that are incorrectly sorted. In a worst case scenario, the entire result set for a given page could be out of order, depending on the locale/sorting rules of the current user. If I were to sort in (server side) code, I need to retrieve all rows from the database and then sort. This results in a tremendous performance hit given the amount of data. Thus I would like to avoid this. Does anyone have a strategy (or even technical solution) for attacking this problem that will result in correctly sorted lists without having to take the performance hit of loading all data? Tech details: The database is PostgreSQL 8.3, the application an EJB3 app using EJB QL for data query, running on JBoss 4.5.

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  • Total row count for pagination using JPA Criteria API

    - by ThinkFloyd
    I am implementing "Advanced Search" kind of functionality for an Entity in my system such that user can search that entity using multiple conditions(eq,ne,gt,lt,like etc) on attributes of this entity. I am using JPA's Criteria API to dynamically generate the Criteria query and then using setFirstResult() & setMaxResults() to support pagination. All was fine till this point but now I want to show total number of results on results grid but I did not see a straight forward way to get total count of Criteria query. This is how my code looks like: CriteriaBuilder builder = em.getCriteriaBuilder(); CriteriaQuery<Brand> cQuery = builder.createQuery(Brand.class); Root<Brand> from = cQuery.from(Brand.class); CriteriaQuery<Brand> select = cQuery.select(from); . . //Created many predicates and added to **Predicate[] pArray** . . select.where(pArray); // Added orderBy clause TypedQuery typedQuery = em.createQuery(select); typedQuery.setFirstResult(startIndex); typedQuery.setMaxResults(pageSize); List resultList = typedQuery.getResultList(); My result set could be big so I don't want to load my entities for count query, so tell me efficient way to get total count like rowCount() method on Criteria (I think its there in Hibernate's Criteria).

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  • wordpress -> showing custom data from child pages + pagination

    - by GaVrA
    Hello! You can see here what i am doing: http://www.arvag.net/otkrijte-svet/leto/ So its pulling 2 custom fields from child pages, one of them is just url for the image on the left, and the other field is that text showing on the right. Now, what i want to do is to add pagination there. The code i have now will just simply show all child pages, but i want to show only 5 child pages, so if user want to see 6th child page he would have to click on link for "Page 2" and so on. The code im using to display these child pages is this: <?php $pages = get_pages('child_of='.$post->ID.'&sort_column=post_title&sort_order=desc'); $count = 0; foreach($pages as $page) { $short_info = get_post_meta($page->ID,'info',true); $image = get_post_meta($page->ID,'slika',true); $count++; ?> <div class='preview_slika left'><img src="<?php echo $image ?>" alt="<?php echo $page->post_title ?>" /></div> <div class='preview_info right'> <h2><?php echo $page->post_title ?></h2> <p><?php echo $short_info ?></p> <a href="<?php echo get_page_link($page->ID) ?>">Više o >></a> </div> <div class='clear'></div> <?php } ?> So any idea what to do to get what i need?

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  • How do I implement Hibernate Pagination using a cursor (so the results stay consistent, despite new

    - by hunterae
    Hey all, Is there any way to maintain a database cursor using Hibernate between web requests? Basically, I'm trying to implement pagination, but the data that is being paged is consistently changing (i.e. new records are added into the database). We are trying to set it up such that when you do your initial search (returning a maximum of 5000 results), and you page through the results, those same records always appear on the same page (i.e. we're not continuously running the query each time next and previous page buttons are clicked). The way we're currently implementing this is by merely selecting 5000 (at most) primary keys from the table we're paging, storing those keys in memory, and then just using 20 primary keys at a time to fetch their details from the database. However, we want to get away from having to store these keys in memory and would much prefer a database cursor that we just keep going back to and moving backwards and forwards over the cursor to generate pages. I tried doing this with Hibernate's ScrollableResults but found that I could not call methods like next() and previous() would cause an exception if you within a different web request / Hibernate session (no surprise there). Is there any way to reattach a ScrollableResults object to a Session, much the same way you would reattach a detached database object to make it persistent? Are there any other approaches to implement this data paging with consistent paging results without caching the primary keys?

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  • why my pagination link doesnt appear ?

    - by udaya
    This is my script which i have used to paginate ,,The datas are restricted to 4 but the pagination link doesn't appear <? require_once ('Pager/Pager.php'); $connection = mysql_connect( "localhost" , "root" , "" ); mysql_select_db( "ssit",$connection); $result=mysql_query("SELECT dFrindName FROM tbl_friendslist", $connection); $row = mysql_fetch_array($result); $totalItems = $row['total']; $pager_options = array( 'mode' => 'Sliding', // Sliding or Jumping mode. See below. 'perPage' => 4, // Total rows to show per page 'delta' => 4, // See below 'totalItems' => $totalItems, ); $pager = Pager::factory($pager_options); echo $pager->links; list($from, $to) = $pager->getOffsetByPageId(); $from = $from - 1; $perPage = $pager_options['perPage']; $result = mysql_query("SELECT * FROM tbl_friendslist LIMIT 5 , $perPage",$connection); while($row = mysql_fetch_array($result)) { echo $row['dFrindName'].'</br>'; } ?>

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  • CakePHP pagination with HABTM models

    - by nickf
    I'm having some problems with creating pagination with a HABTM relationship. First, the tables and relationships: requests (id, to_location_id, from_location_id) locations (id, name) items_locations (id, item_id, location_id) items (id, name) So, a Request has a Location the request is coming from and a Location the Request is going to. For this question, I'm only concerned about the "to" location. Request --belongsTo--> Location* --hasAndBelongsToMany--> Item (* as "ToLocation") In my RequestController, I want to paginate all the Items in a Request's ToLocation. // RequestsController var $paginate = array( 'Item' => array( 'limit' => 5, 'contain' => array( "Location" ) ) ); // RequestController::add() $locationId = 21; $items = $this->paginate('Item', array( "Location.id" => $locationId )); And this is failing, because it is generating this SQL: SELECT COUNT(*) AS count FROM items Item WHERE Location.id = 21 I can't figure out how to make it actually use the "contain" argument of $paginate... Any ideas?

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  • Table sorting & pagination with jQuery and Razor in ASP.NET MVC

    - by hajan
    Introduction jQuery enjoys living inside pages which are built on top of ASP.NET MVC Framework. The ASP.NET MVC is a place where things are organized very well and it is quite hard to make them dirty, especially because the pattern enforces you on purity (you can still make it dirty if you want so ;) ). We all know how easy is to build a HTML table with a header row, footer row and table rows showing some data. With ASP.NET MVC we can do this pretty easy, but, the result will be pure HTML table which only shows data, but does not includes sorting, pagination or some other advanced features that we were used to have in the ASP.NET WebForms GridView. Ok, there is the WebGrid MVC Helper, but what if we want to make something from pure table in our own clean style? In one of my recent projects, I’ve been using the jQuery tablesorter and tablesorter.pager plugins that go along. You don’t need to know jQuery to make this work… You need to know little CSS to create nice design for your table, but of course you can use mine from the demo… So, what you will see in this blog is how to attach this plugin to your pure html table and a div for pagination and make your table with advanced sorting and pagination features.   Demo Project Resources The resources I’m using for this demo project are shown in the following solution explorer window print screen: Content/images – folder that contains all the up/down arrow images, pagination buttons etc. You can freely replace them with your own, but keep the names the same if you don’t want to change anything in the CSS we will built later. Content/Site.css – The main css theme, where we will add the theme for our table too Controllers/HomeController.cs – The controller I’m using for this project Models/Person.cs – For this demo, I’m using Person.cs class Scripts – jquery-1.4.4.min.js, jquery.tablesorter.js, jquery.tablesorter.pager.js – required script to make the magic happens Views/Home/Index.cshtml – Index view (razor view engine) the other items are not important for the demo. ASP.NET MVC 1. Model In this demo I use only one Person class which defines Person entity with several properties. You can use your own model, maybe one which will access data from database or any other resource. Person.cs public class Person {     public string Name { get; set; }     public string Surname { get; set; }     public string Email { get; set; }     public int? Phone { get; set; }     public DateTime? DateAdded { get; set; }     public int? Age { get; set; }     public Person(string name, string surname, string email,         int? phone, DateTime? dateadded, int? age)     {         Name = name;         Surname = surname;         Email = email;         Phone = phone;         DateAdded = dateadded;         Age = age;     } } 2. View In our example, we have only one Index.chtml page where Razor View engine is used. Razor view engine is my favorite for ASP.NET MVC because it’s very intuitive, fluid and keeps your code clean. 3. Controller Since this is simple example with one page, we use one HomeController.cs where we have two methods, one of ActionResult type (Index) and another GetPeople() used to create and return list of people. HomeController.cs public class HomeController : Controller {     //     // GET: /Home/     public ActionResult Index()     {         ViewBag.People = GetPeople();         return View();     }     public List<Person> GetPeople()     {         List<Person> listPeople = new List<Person>();                  listPeople.Add(new Person("Hajan", "Selmani", "[email protected]", 070070070,DateTime.Now, 25));                     listPeople.Add(new Person("Straight", "Dean", "[email protected]", 123456789, DateTime.Now.AddDays(-5), 35));         listPeople.Add(new Person("Karsen", "Livia", "[email protected]", 46874651, DateTime.Now.AddDays(-2), 31));         listPeople.Add(new Person("Ringer", "Anne", "[email protected]", null, DateTime.Now, null));         listPeople.Add(new Person("O'Leary", "Michael", "[email protected]", 32424344, DateTime.Now, 44));         listPeople.Add(new Person("Gringlesby", "Anne", "[email protected]", null, DateTime.Now.AddDays(-9), 18));         listPeople.Add(new Person("Locksley", "Stearns", "[email protected]", 2135345, DateTime.Now, null));         listPeople.Add(new Person("DeFrance", "Michel", "[email protected]", 235325352, DateTime.Now.AddDays(-18), null));         listPeople.Add(new Person("White", "Johnson", null, null, DateTime.Now.AddDays(-22), 55));         listPeople.Add(new Person("Panteley", "Sylvia", null, 23233223, DateTime.Now.AddDays(-1), 32));         listPeople.Add(new Person("Blotchet-Halls", "Reginald", null, 323243423, DateTime.Now, 26));         listPeople.Add(new Person("Merr", "South", "[email protected]", 3232442, DateTime.Now.AddDays(-5), 85));         listPeople.Add(new Person("MacFeather", "Stearns", "[email protected]", null, DateTime.Now, null));         return listPeople;     } }   TABLE CSS/HTML DESIGN Now, lets start with the implementation. First of all, lets create the table structure and the main CSS. 1. HTML Structure @{     Layout = null;     } <!DOCTYPE html> <html> <head>     <title>ASP.NET & jQuery</title>     <!-- referencing styles, scripts and writing custom js scripts will go here --> </head> <body>     <div>         <table class="tablesorter">             <thead>                 <tr>                     <th> value </th>                 </tr>             </thead>             <tbody>                 <tr>                     <td>value</td>                 </tr>             </tbody>             <tfoot>                 <tr>                     <th> value </th>                 </tr>             </tfoot>         </table>         <div id="pager">                      </div>     </div> </body> </html> So, this is the main structure you need to create for each of your tables where you want to apply the functionality we will create. Of course the scripts are referenced once ;). As you see, our table has class tablesorter and also we have a div with id pager. In the next steps we will use both these to create the needed functionalities. The complete Index.cshtml coded to get the data from controller and display in the page is: <body>     <div>         <table class="tablesorter">             <thead>                 <tr>                     <th>Name</th>                     <th>Surname</th>                     <th>Email</th>                     <th>Phone</th>                     <th>Date Added</th>                 </tr>             </thead>             <tbody>                 @{                     foreach (var p in ViewBag.People)                     {                                 <tr>                         <td>@p.Name</td>                         <td>@p.Surname</td>                         <td>@p.Email</td>                         <td>@p.Phone</td>                         <td>@p.DateAdded</td>                     </tr>                     }                 }             </tbody>             <tfoot>                 <tr>                     <th>Name</th>                     <th>Surname</th>                     <th>Email</th>                     <th>Phone</th>                     <th>Date Added</th>                 </tr>             </tfoot>         </table>         <div id="pager" style="position: none;">             <form>             <img src="@Url.Content("~/Content/images/first.png")" class="first" />             <img src="@Url.Content("~/Content/images/prev.png")" class="prev" />             <input type="text" class="pagedisplay" />             <img src="@Url.Content("~/Content/images/next.png")" class="next" />             <img src="@Url.Content("~/Content/images/last.png")" class="last" />             <select class="pagesize">                 <option selected="selected" value="5">5</option>                 <option value="10">10</option>                 <option value="20">20</option>                 <option value="30">30</option>                 <option value="40">40</option>             </select>             </form>         </div>     </div> </body> So, mainly the structure is the same. I have added @Razor code to create table with data retrieved from the ViewBag.People which has been filled with data in the home controller. 2. CSS Design The CSS code I’ve created is: /* DEMO TABLE */ body {     font-size: 75%;     font-family: Verdana, Tahoma, Arial, "Helvetica Neue", Helvetica, Sans-Serif;     color: #232323;     background-color: #fff; } table { border-spacing:0; border:1px solid gray;} table.tablesorter thead tr .header {     background-image: url(images/bg.png);     background-repeat: no-repeat;     background-position: center right;     cursor: pointer; } table.tablesorter tbody td {     color: #3D3D3D;     padding: 4px;     background-color: #FFF;     vertical-align: top; } table.tablesorter tbody tr.odd td {     background-color:#F0F0F6; } table.tablesorter thead tr .headerSortUp {     background-image: url(images/asc.png); } table.tablesorter thead tr .headerSortDown {     background-image: url(images/desc.png); } table th { width:150px;            border:1px outset gray;            background-color:#3C78B5;            color:White;            cursor:pointer; } table thead th:hover { background-color:Yellow; color:Black;} table td { width:150px; border:1px solid gray;} PAGINATION AND SORTING Now, when everything is ready and we have the data, lets make pagination and sorting functionalities 1. jQuery Scripts referencing <link href="@Url.Content("~/Content/Site.css")" rel="stylesheet" type="text/css" /> <script src="@Url.Content("~/Scripts/jquery-1.4.4.min.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/jquery.tablesorter.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/jquery.tablesorter.pager.js")" type="text/javascript"></script> 2. jQuery Sorting and Pagination script   <script type="text/javascript">     $(function () {         $("table.tablesorter").tablesorter({ widthFixed: true, sortList: [[0, 0]] })         .tablesorterPager({ container: $("#pager"), size: $(".pagesize option:selected").val() });     }); </script> So, with only two lines of code, I’m using both tablesorter and tablesorterPager plugins, giving some options to both these. Options added: tablesorter - widthFixed: true – gives fixed width of the columns tablesorter - sortList[[0,0]] – An array of instructions for per-column sorting and direction in the format: [[columnIndex, sortDirection], ... ] where columnIndex is a zero-based index for your columns left-to-right and sortDirection is 0 for Ascending and 1 for Descending. A valid argument that sorts ascending first by column 1 and then column 2 looks like: [[0,0],[1,0]] (source: http://tablesorter.com/docs/) tablesorterPager – container: $(“#pager”) – tells the pager container, the div with id pager in our case. tablesorterPager – size: the default size of each page, where I get the default value selected, so if you put selected to any other of the options in your select list, you will have this number of rows as default per page for the table too. END RESULTS 1. Table once the page is loaded (default results per page is 5 and is automatically sorted by 1st column as sortList is specified) 2. Sorted by Phone Descending 3. Changed pagination to 10 items per page 4. Sorted by Phone and Name (use SHIFT to sort on multiple columns) 5. Sorted by Date Added 6. Page 3, 5 items per page   ADDITIONAL ENHANCEMENTS We can do additional enhancements to the table. We can make search for each column. I will cover this in one of my next blogs. Stay tuned. DEMO PROJECT You can download demo project source code from HERE.CONCLUSION Once you finish with the demo, run your page and open the source code. You will be amazed of the purity of your code.Working with pagination in client side can be very useful. One of the benefits is performance, but if you have thousands of rows in your tables, you will get opposite result when talking about performance. Hence, sometimes it is nice idea to make pagination on back-end. So, the compromise between both approaches would be best to combine both of them. I use at most up to 500 rows on client-side and once the user reach the last page, we can trigger ajax postback which can get the next 500 rows using server-side pagination of the same data. I would like to recommend the following blog post http://weblogs.asp.net/gunnarpeipman/archive/2010/09/14/returning-paged-results-from-repositories-using-pagedresult-lt-t-gt.aspx, which will help you understand how to return page results from repository. I hope this was helpful post for you. Wait for my next posts ;). Please do let me know your feedback. Best Regards, Hajan

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  • SOQL Pagination for Salesforce API queries

    - by Daniel Ballinger
    Is there an efficient way to page through results from a SOQL query without bringing all the query results back and then discarding the majority of them? As an example, I'd like to be able to to page through the complete list of contacts showing 10 records at a time. I don't have the need to sort by any particular field.

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  • Using jquery pagination plugin

    - by eddy
    Hi. I want to use this plugin, but I don't know if it'll meet all of my requirements. I know I have to use JSON to fetch the data from the server and then use it at the client side, is that right?. For now, that's fine, because I only have very few records, but when I have thousands of ; will it be convenient to bring all the data at once? What I would like to know is : Is there any way to query the database every time I press the number of an specific page? I ask this cause I don't think is a good idea to load all the data in one go, is it? I used to pass the id of the record I was going to edit like this : <td align="center"> <c:url value="edititem.htm" var="url"> <c:param name="id" value="${item.id}"/> </c:url> <a href="<c:out value="${url}"/>"><img src="images/edit.png" width="14" height="14" alt="edit"/></a> </td> but now I don't know not how to do it. I really hope you can help me out. Thanks in advance.

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  • ASP.NET MVC pagination problem????

    - by MD_Oppenheimer
    OK, This is starting to get mildly irritating. I tried to implement Twitter style paging using ASP.NET MVC and JQuery my problem is that when not using Request.IsAjaxRequest() (for users with javascript turned off) it works fine, obviously posting back the whole page. when I run the code for Request.IsAjaxRequest(), it skips entries, and does not return result in order. this is the code I have: public ActionResult Index(int? startRow) { StatusUpdatesRepository statusUpdatesRepository = new StatusUpdatesRepository(); if (!startRow.HasValue) startRow = Globals.Settings.StatusUpdatesSection.StatusUpdateCount;//5 Default starting row //Retrieve the first page with a page size of entryCount int totalItems; if (Request.IsAjaxRequest()) { IEnumerable<StatusUpdate> PagedEntries = statusUpdatesRepository.GetLastStatusUpdates(startRow.Value,Globals.Settings.StatusUpdatesSection.StatusUpdateCount, out totalItems); if (startRow < totalItems) AddMoreUrlToViewData(startRow.Value); return View("StatusUpdates", PagedEntries); } //Retrieve the first page with a page size of global setting // First run skip 0 take 5 IEnumerable<StatusUpdate> entries = statusUpdatesRepository.GetLastStatusUpdates(0,startRow.Value, out totalItems); if (startRow < totalItems) AddMoreUrlToViewData(startRow.Value); return View(entries); } private void AddMoreUrlToViewData(int entryCount) { ViewData["moreUrl"] = Url.Action("Index", "Home", new { startRow = entryCount + Globals.Settings.StatusUpdatesSection.StatusUpdateCount }); } My GetLastStatusUpdates function: public IQueryable GetLastStatusUpdates(int startRowIndex, int maximumRows,out int statusUpdatesCount ) { statusUpdatesCount = db.StatusUpdates.Count(); return db.StatusUpdates .Skip(startRowIndex) .Take(maximumRows) .OrderByDescending(s = s.AddedDate); } Really fresh out out of ideas as to why this is not working properly when responding to a Request.IsAjaxRequest(), ie when I turn of javascript in the browser, the code works perfectly, except I don't want to repost the whole page????

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  • System.Web.HttpException on asp:gridview pagination

    - by Carlos Muñoz
    I have the following <asp:gridview> with one one TemplateField. En each cell there is an image with a link and a text with a link. It has AllowPaging=True This is the gridview: <asp:GridView ID="gvExperiencias" runat="server" AllowPaging="True" GridLines="None" ShowHeader="False" AutoGenerateColumns="False" Width="650px" PageSize="4" OnDataBinding="gvExperiencias_DataBinding" OnPageIndexChanging="gvExperiencias_PageIndexChanging"> <PagerSettings Mode="NumericFirstLast" FirstPageImageUrl="~/images/fle_pag_izq.gif" LastPageImageUrl="~/images/fle_pag_der.gif" NextPageImageUrl="~/images/fle_pag_der.gif" PreviousPageImageUrl="~/images/fle_pag_izq.gif" Position="TopAndBottom" PageButtonCount="4" FirstPageText="" LastPageText="" NextPageText="" PreviousPageText=""></PagerSettings> <Columns> <asp:TemplateField> <ItemTemplate> <div id="it_0" class="new_solo_exp_ini"> <asp:HyperLink ID="a_0" runat="server" NavigateUrl='<%# "experiencia.aspx?cod_cod=" + Eval("tttb_articulo_relacion_0.ARTCOD_ARTREL") + "&pag=" + pag + "&grp=" + Eval("idiocod_cod_idi_0") + "&cod="+cod %>' Visible='<%# Eval("NotEmpty_0") %>'> <asp:Image ID="Image_0" runat="server" Height="88px" ImageUrl='<%# Eval("arigls_nom_img_0","~/ArchivosUsuario/1/1/Articulos/{0}") %>' Width="88px" CssClass="new_image_exp_ini" /> </asp:HyperLink> <div class="new_vineta_tit_exp_ini"> <asp:HyperLink ID="HyperLink_0" runat="server" NavigateUrl='<%# "experiencia.aspx?cod_cod=" + Eval("tttb_articulo_relacion_0.ARTCOD_ARTREL") + "&pag=" + pag + "&grp=" + Eval("idiocod_cod_idi_0") + "&cod="+cod %>' Text='<%# Bind("arigls_tit_0") %>'> </asp:HyperLink> </div> </div> </ItemTemplate> </asp:TemplateField> </Columns> <PagerStyle CssClass="new_pag_bajo_exp_ini" /> <RowStyle CssClass="new_fila_exp_ini" /> </asp:GridView> When I click the last button or the ... it goes to the corresponding page but when i click on a previous page i get the following errror: An Error Has Occurred Because A Control With Id $ContentPlaceHolder1$gvExperiencias$ctl01$ctl01' Could Not Be Located Or A Different Control Is assigned to the same ID after postback. If the ID is not assigned, explicitly set the ID property of controls that raise postback events to avoid this error. So the pager does not work correctly. I think it's because of the Image's Id that has to be generated dinamically but i don't know how to do it. Can someone help me?

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  • PHP & MySQL Pagination

    - by Francesc
    Hi. I have a MySQL query SELECT * FROM 'redirect' WHERE 'user_id'= \''.$_SESSION['user_id'].' \' ORDER BY 'timestamp'` I want to paginate 10 results per page. How Can I do it?

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  • XSLT Pagination

    - by dbomb101
    I have created a xslt document which formats an xml document, but I would like the results from the xslt sheet to be paginated. here is the orginal xlst document <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="/"> <xsl:for-each select="musicInformation/musicdetails"> <label for="artistname{position()}" id="artistnameLabel{position()}">Artist Name:</label> <span id ="artistname{position()}"><xsl:value-of select="artistname" /></span> <br/> <label for="recordname{position()}" id="recordnameLabel{position()}">Record Name:</label> <span id ="recordname{position()}"><xsl:value-of select="recordname" /></span> <br/> <label for="recordtype{position()}" id="recordtypeLabel{position()}">Record Type:</label> <span id ="recordtype{position()}"><xsl:value-of select="recordtype" /></span> <br/> <label for="format{position()}" id="formatLabel{position()}">Format:</label> <span id ="format{position()}"><xsl:value-of select="format" /></span> <br/> <a href="xmlDetail.php?mid={@m_id}" >See Details</a> <br/><br/> </xsl:for-each> </xsl:template> </xsl:stylesheet>

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  • pagination and url encoding help

    - by Sufyan
    <?php $name=$_POST['name']; ?> <form method="POST" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <input type="text" name="name"> <input type="submit" value="GO" name="submit"> </form> <?php include ('db.php'); if(isset($_POST['submit'])) { mysql_query ("INSERT INTO example (name) VALUES('$name')") or die(mysql_error()); } if (!isset($_GET['startrow']) or !is_numeric($_GET['startrow'])) { $startrow = 0; } else { $startrow = (int)$_GET['startrow']; } $query = "SELECT * FROM example ORDER BY id DESC LIMIT $startrow, 20"; $result = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_array($result)){ echo "<li>"; echo $row['name'] ." "." <a href= 'like.php?quote=" . urlencode( $row['name'] ) . "'>Click Here</a>"; echo "</li>"; } echo '<a href="'.$_SERVER['PHP_SELF'].'?startrow='.($startrow+10).'">Next</a>'; ?> I want to make my page links hidden , how can i make then hidden so that a user cant edit it. 2nd question, currently i am showing total 10 records on each page and then a next page button , but the next button is keep showing even when there is no more records...! how to remove a next page button when records ended. ?? line number 28 is the link to pages which can be easyily editable by any user, i wnat to make them secure (using ID) and line 35 is n'next' page link , this link should not be appear when number of records ended

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  • PHP Filesystem Pagination

    - by Byron
    How does one paginate a large listing of files within a folder? I can't see any functions in the PHP documentation that mention any way to specify an 'offset'. Both glob() and scandir() simply return all the files in the folder, and I'm afraid that won't be a good idea for a huge directory. Is there any better way of doing this than simply going through all the files and chopping off the first X number of files?

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  • ASP.NET - extracting from databases and pagination

    - by whitstone86
    I've got basic page templates working in ASP.NET from master pages and can include pages in ASP.NET - however, I'm having difficulty extracting from pages and paginating them. This is the design structure (i.e. the model for my site) I'm trying to base it on: http://library.digiguide.com/lib/programmenextshowing/Medium-319648 I have an SQL Driver installed, my ODBC Advisor says it is MySQL ODBC Driver 5.1. How should I get this project to work, now I have the basics under way?

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  • highlight page selected in pagination?

    - by Mahmoud
    Hey There i have a php page, that shows all products that are stored on the database, so everything in fine, but my problem is that i am trying to highlight or give a color when a selected number is clicked, example, let say i all my product are showing and there are 2 pages, so when the user clicks on next the next fade and number 2 is colored yellow this well help the user to on which page he is below is my php code <?php echo"<a style:'color:#FFF;font-style:normal;'> "; include "im/config.php"; include('im/ps_pagination.php'); $result = ("Select * from product "); $pager = new PS_Pagination($conn, $result, 5, 6, "product=product"); $rs = $pager->paginate(); echo"<div id='image_container'>"; echo $pager->renderFullNav(); echo "<br /><br />\n"; while($row = mysql_fetch_array($rs)){ echo" <div class='virtualpage hidepiece'><a href='gal/".$row['pro_image']."' rel='lightbox[roadtrip]' title='".$row['pro_name']." : ".$row['pro_mini_des']."' style='color:#000'><img src='thumb/".$row['pro_thumb']."' /> </a></div>"; } echo"</div>"; echo "<br /><br />\n"; echo $pager->renderFullNav(); echo"</a>"; ?> Thank everyone

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  • Pagination of Date-Based Generic Views in Django

    - by Apreche
    I have a pretty simple question. I want to make some date-based generic views on a Django site, but I also want to paginate them. According to the documentation the object_list view has page and paginate_by arguments, but the archive_month view does not. What's the "right" way to do it?

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  • Recommendation for a Pagination procedure AJAX PHP

    - by Jamex
    Hi, I am not sure the correct terminology for the process that I am trying to describe. I don't even know which platform is underlying the technique. If you understand my description, please give the link to the site(s) and or the keyword name of the process. I think it is done by AJAX, but I am not certain. I use php as the backend code, I just need to find a way to dynamically display the results. Please give suggestions. I forgot the name of the sites that use this, and my link history expired. TIA Description: The page would have a search form and options. After the user submits, the search is initiated, and the results appear inside the dedicated result area. The page does not refresh, just the info inside the result area. The display area will show 20 (or whatever) results (lines). There will be next, and previous buttons. If you hit next, the next set of results will display. I am writing a code that generates 20 results for each display. There is no set number of results, so the results might have a start/first page, but do not have an end page. Each time the user hits 'next', the program would generate/load new results. It would also store previous results, so that when a user hits 'prev', the previous results can instantly come up. What techniques/program are theses?

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  • Pagination in Java

    - by user569125
    I wrote paging logic: My requirement: total elements to display:100 per page,if i click next it should display next 100 records,if i click previous 100 records. Initial varaible values: showFrom:1, showTo:100 max elements:depends on size of data. pageSize:100. Code: if(p*emphasized text*aging.getAction().equalsIgnoreCase("Next")){ paging.setTotalRec(availableList.size()); showFrom = (showTo + 1); showTo = showFrom + 100- 1; if(showTo >= paging.getTotalRec()) showTo = paging.getTotalRec(); paging.setShowFrom(showFrom); paging.setShowTo(showTo); } else if(paging.getAction().equalsIgnoreCase("Previous")){ showTo = showFrom - 1; showFrom = (showFrom - 100); paging.setShowTo(showTo); paging.setShowFrom(showFrom); paging.setTotalRec(availableList.size()); } Here i can remove and add the elements to the existing data.above code works fine if i add and remove few elements.but if i remove or add 100 elements at a time counts are not displaying properly above code works fine if i add and remove few elements.

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  • css pagination for GridView

    - by nCdy
    my css : /* for greed view */ .pagination { font-size: 80%; } .pagination a { text-decoration: none; color: #15B; } .pagination a, .pagination span { display: block; float: left; padding: 0.3em 0.5em; margin-right: 5px; margin-bottom: 5px; } .pagination .current { background: #26B; color: #fff; border: solid 1px #AAE; } .pagination .current.prev, .pagination .current.next{ color:#999; border-color:#999; background:#fff; } but .pagination .current doesn't appears on current page and I can's see the border on it. What am I doing wrong ?

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