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  • Completely remove MySQL from macbook pro

    - by mike
    Im prety sure i completely removed mysql from my system, except for one thing. When i type mysql in the command line i get this bash: /opt/local/bin/mysql5: No such file or directory How is it still recognizing where it thinks mysql should be? I'm trying to build it myself in /usr/local, and when i do install it there, i still get that error message for it looking for it in opt/local.

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  • unix tool to remove duplicate lines from a file

    - by Nathan Fellman
    I have a tool that generates tests and predicts the output. The idea is that if I have a failure I can compare the prediction to the actual output and see where they diverged. The problem is the actual output contains some lines twice, which confuses diff. I want to remove the duplicates, so that I can compare them easily. Basically, something like sort -u but without the sorting. Is there any unix commandline tool that can do this?

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  • php remove button keeps retreiving posted information

    - by Doug
    Hi every1! im quickly finding im quite the beginner to php, so please bare with me! I have a quick problem, I have a remove button for a shopping cart and the code works for it everytime except for the last product thats in the cart. If a person pushes the addtoCart button the URL is reloaded with ?buyproduct=$productNumber and when the remove button is pushed the product is removed. Right so everything is good, but when you try to remove the last item, it keeps reading the product thats in the URL. so the quantity remains 1 for the current $productNumber. i've tried adding the action in the form method tag so that the page reloads without the ?buyproduct=$productNumber, which does work however there are page numbers and sections that were also in the URL and these get reset also. i know the remove is working because once the ?buyproduct=$productNumber is gone from the URL (which can happen for example if they go to another section in the catalog) then the cart can be completely emptied. Thank you so much ahead of time for any1's help, I've used this site before and you guys are genius's!

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  • Jquery Append() and remove() element

    - by BandonRandon
    Hi, I have a form where I'm dynamically adding the ability to upload files with the append function but I would also like to be able to remove unused fields. Here is the html markup <span class="inputname">Project Images: <a href="#" class="add_project_file"><img src="images/add_small.gif" border="0"></a></span> <span class="project_images"> <input name="upload_project_images[]" type="file" /><br/> </span> Right now if they click on the "add" gif a new row is added with this jquery $('a.add_project_file').click(function() { $(".project_images").append('<input name="upload_project_images[]" type="file" class="new_project_image" /> <a href="#" class="remove_project_file" border="2"><img src="images/delete.gif"></a><br/>'); return false; }); To remove the input box i've tried to add the class "remove_project_file" then add this function. $('a.remove_project_file').click(function() { $('.project_images').remove(); return false;}); I think there should be a much easier way to do this. Maybe i need to use the $(this) function for the remove. Another possible solution would be to expand the "add project file" to do both adding and removing fields. Any of you JQuery wizards have any ideas that would be great

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  • remove 2 subviews in one go.

    - by Pavan
    hi, I am trying to remove two viewcontrollers (that have been added on top of each other) with one method. I have made the views in interfacebuilder. they all have their own .h and .m files to go with it. Scenario I am in: I have a main menu which has the view2 header file imported. In a method I add the second view on top of the superview like so view2ViewController * view2 = [[view2ViewController alloc] initWithNibName:@"view2ViewController" bundle:nil]; [self.view addSubview:view2.view]; then in view 2 I have added the view 3 header file so i can add view 3 as a subview ontop of view2. i have another method which is connected again to interface builder to a UIButton so upon button press a method gets called in view2 which adds view 3 on top in exactly the same way like so: view3ViewController * view3 = [[view3ViewController alloc] initWithNibName:@"view3ViewController" bundle:nil]; [self.view addSubview:view3.view]; What im trying to solve: I have a button in view 3 which should remove view 3.... and then it should also remove view 2 aswell so the main screen is visible. How can this be achieved? What I have so far: [self.view removeFromSuperview]; This however only removes View 3... but leaves view 2 in place. What needs to be modified so that i can remove view 2 as well?? Any help is appreciated.

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  • Python beautifulsoup trying to remove html tags 'span'

    - by Michelle Jun Lee
    I am trying to remove [<span class="street-address"> 510 E Airline Way </span>] and I have used this clean function to remove the one that is in between < > def clean(val): if type(val) is not StringType: val = str(val) val = re.sub(r'<.*?>', '',val) val = re.sub("\s+" , " ", val) return val.strip() and it produces [ 510 E Airline Way ]` i am trying to add within "clean" function to remove the char '[' and ']' and basically i just want to get the "510 E Airline Way". anyone has any clue what can i add to clean function? thank you

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  • Remove trailing slash from comment form

    - by Sergio Vargott
    and i really need a code to remove the ending slash when a user put their link. for example i need them to put their url to grab their avatar, but in some cases they put their url ending with a slash (.com/) how can i remove that slash automatically? because when they put their url like that the avatar doesn't show i need them to end like this (.com) in order to show their avatar. I was looking for a remove trailing slash php code, but any solution will be appreciated. i tried to use this code but didn't work $string = rtrim($string, '/');

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  • jquery: remove table row while iterating through table rows

    - by deostroll
    #exceptions is a html table. I try to run the code below, but it doesn't remove the table row. $('#exceptions').find('tr').each(function(){ var flag=false; var val = 'excalibur'; $(this).find('td').each(function(){ if($(this).text().toLowerCase() == val) flag = true; }); if(flag) $(this).parent().remove($(this)); }); What is the correct way to do it?

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  • jquery: How to completely remove a dialog on close

    - by Svish
    When an ajax operation fails, I create a new div with the errors and then show it as a dialog. When the dialog is closed I would like to completely destroy and remove the div again. How can I do this? My code looks something like this at the moment: $('<div>We failed</div>') .dialog( { title: 'Error', close: function(event, ui) { $(this).destroy().remove(); } }); When I run this the dialog box shows up correctly, but when I close it the dialog is still visible in the html (using FireBug). What am I missing here? Something I have forgotten? Update: Just noticed my code gives me an error in the firebug console. $(this).destroy is not a function Anyone able to help me out? Update: If I do just $(this).remove() instead, the item is removed from the html. But is it completely removed from the DOM? Or do I somehow need to call that destroy function first as well?

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  • Does similar Titles considered duplicates relating to SEO

    - by Uri
    I have built a testing service and I wonder if I should be concerned that search engines will consider similar titles as duplicates. For example: Some URLs title can be differed from others by only one word such as "Senior" and "Junior" Title A: C++ Online Test for Juniors Title B: C++ Online Test for Seniors Another example is with the "+" sign: Title A: C Standard Library Online Test for Seniors Title B: C++ Standard Library Online Test for Seniors Should I assume search engines will understand there is a difference in the titles? And the titles are not duplicated?

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  • How can I remove duplicate nodes in XQuery?

    - by Brabster
    I have an XML document I generate on the fly, and I need a function to eliminate any duplicate nodes from it. My function looks like: declare function local:start2() { let $data := local:scan_books() return <books>{$data}</books> }; Sample output is: <books> <book> <title>XML in 24 hours</title> <author>Some Guy</author> </book> <book> <title>XML in 24 hours</title> <author>Some Guy</author> </book> </books> I want just the one entry in my books root tag, and there are other tags, like say pamphlet in there too that need to have duplicates removed. Any ideas? Updated following comments. By unique nodes, I mean remove multiple occurrences of nodes that have the exact same content and structure.

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  • remove duplicate from string in PHP

    - by Adnan
    Hello, I am looking for the fastest way to remove duplicate values in a string separated by commas. So my string looks like this; $str = 'one,two,one,five,seven,bag,tea'; I can do it be exploding the string to values and then compare, but I think it will be slow. what about preg_replace() will it be faster? Any one did it using this function?

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  • Javascript - remove part of cookie with a split('|') like array

    - by MgS
    I'm abit stuck. I'm using jQuery. I have a cookie which has the value such as : 1,something|2,somethingg|1,something We are treating it as [0] as id and [1] as name. I need to remove ONE where the id == '1' for example, this will leave the cookie like this: 1,something|2,somethingg How do I go about this, it will probally be in a loop, but not sure how to remove one of them. I have this so far: function removeItem(id){ var cookieName = 'myCookie'; var cookie = $.cookie(cookieName); if(cookie){ var cookie = cookie.split('|'); $(cookie).each(function(index){ var thisCookieData = this.split(','); if(thisCookieData[0] == id ){ } }); }

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  • JQuery: Remove duplicate elements?

    - by Keith Donegan
    Say I have a list of links with duplicate values as below: <a href="#">Book</a> <a href="#">Magazine</a> <a href="#">Book</a> <a href="#">Book</a> <a href="#">DVD</a> <a href="#">DVD</a> <a href="#">DVD</a> <a href="#">Book</a> How would I, using JQuery, remove the dups and be left with the following for example: <a href="#">Book</a> <a href="#">Magazine</a> <a href="#">DVD</a> Basically I am looking for a way to remove any duplicate values found and show 1 of each link.

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  • jQuery.remove() - Is there a way to get the object back after you remove it?

    - by Jack Marchetti
    I basically have the same problem in this questions: Flash Video still playing in hidden div I've used the .remove jquery call and this works. However, I have previous/next buttons when a user scrolls through hidden/non-hidden divs. What I need to know is, once I remove the flash object, is there a way to get it back other than refreshing the page? Basically, can this be handled client side or am I going to need to implement some server side handling. detach() won't work because the flash video continues to play. I can't just hide it because the video continues to play as well.

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  • Remove all rows in duplication (different from distinct row selection)

    - by user1671401
    How can I remove EVERY duplicating row in a DataTable, based on the value of two columns that are in duplication. Unfortunately, I am unable to find the equivalent LINQ Query. (I dont want distinct values even). The table below shall explain my problem I want to delete every row in duplication based on Column_A and Column_B COLUMN_A      COLUMN_B      COLUMN_C     COLUMN_D..... A                       B C                       D E                       F G                       H A                       B E                       F EXPECTED OUTPUT: COLUMN_A      COLUMN_B      COLUMN_C     COLUMN_D..... C                       D G                       H Please help

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  • jquery remove selected element and append to another

    - by KnockKnockWhosThere
    I'm trying to re-append a "removed option" to the appropriate select option menu. I have three select boxes: "Categories", "Variables", and "Target". "Categories" is a chained select, so when the user selects an option from it, the "Variables" select box is populated with options specific to the selected categories option. When the user chooses an option from the "Variables" select box, it's appended to the "Target" select box. I have a "remove selected" feature so that if a user "removes" a selected element from the "Target" select box, it's removed from "Target" and put back into the pool of "Variables" options. The problem I'm having is that it appends the option to the "Variables" items indiscriminately. That is, if the selected category is "Age" the "Variables" options all have a class of "age". But, if the removed option is an "income" item, it will display in the "Age Variables" option list. Here's the HTML markup: <select multiple="" id="categories" name="categories[]"> <option class="category" value="income">income</option> <option class="category" value="gender">gender</option> <option class="category" value="age">age</option> </select> <select multiple="multiple" id="variables" name="variables[]"> <option class="income" value="10">$90,000 - $99,999</option> <option class="income" value="11">$100,000 - $124,999</option> <option class="income" value="12">$125,000 - $149,999</option> <option class="income" value="13">Greater than $149,999</option> <option class="gender" value="14">Male</option> <option class="gender" value="15">Female</option> <option class="gender" value="16">Ungendered</option> <option class="age" value="17">Ages 18-24</option> <option class="age" value="18">Ages 25-34</option> <option class="age" value="19">Ages 35-44</option> </select> <select height="60" multiple="multiple" id="target" name="target[]"> </select> And, here's the js: /* This determines what options are display in the "Variables" select box */ var cat = $('#categories'); var el = $('#variables'); $('#categories option').click(function() { var class = $(this).val(); $('#variables option').each(function() { if($(this).hasClass(class)) { $(this).show(); } else { $(this).hide(); } }); }); /* This adds the option to the target select box if the user clicks "add" */ $('#add').click(function() { return !$('#variables option:selected').appendTo('#target'); }); /* This is the remove function in its current form, but doesn't append correctly */ $('#remove').click(function() { $('#target option:selected').each(function() { var class = $(this).attr('class'); if($('#variables option').hasClass(class)) { $(this).appendTo('#variables'); sortList('variables'); } }); });

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  • In SQL / MySQL, can a Left Outer Join be used to find out the duplicates when there is no Primary ID

    - by Jian Lin
    I would like to try using Outer Join to find out duplicates in a table: If a table has Primary Index ID, then the following outer join can find out the duplicate names: mysql> select * from gifts; +--------+------------+-----------------+---------------------+ | giftID | name | filename | effectiveTime | +--------+------------+-----------------+---------------------+ | 2 | teddy bear | bear.jpg | 2010-04-24 04:36:03 | | 3 | coffee | coffee123.jpg | 2010-04-24 05:10:43 | | 6 | beer | beer_glass.png | 2010-04-24 05:18:12 | | 10 | heart | heart_shape.jpg | 2010-04-24 05:11:29 | | 11 | ice tea | icetea.jpg | 2010-04-24 05:19:53 | | 12 | cash | cash.png | 2010-04-24 05:27:44 | | 13 | chocolate | choco.jpg | 2010-04-25 04:04:31 | | 14 | coffee | latte.jpg | 2010-04-27 05:49:52 | | 15 | coffee | espresso.jpg | 2010-04-27 06:03:03 | +--------+------------+-----------------+---------------------+ 9 rows in set (0.00 sec) mysql> select * from gifts g1 LEFT JOIN (select * from gifts group by name) g2 on g1.giftID = g2.giftID where g2.giftID IS NULL; +--------+--------+--------------+---------------------+--------+------+----------+---------------+ | giftID | name | filename | effectiveTime | giftID | name | filename | effectiveTime | +--------+--------+--------------+---------------------+--------+------+----------+---------------+ | 14 | coffee | latte.jpg | 2010-04-27 05:49:52 | NULL | NULL | NULL | NULL | | 15 | coffee | espresso.jpg | 2010-04-27 06:03:03 | NULL | NULL | NULL | NULL | +--------+--------+--------------+---------------------+--------+------+----------+---------------+ 2 rows in set (0.00 sec) But what if the table doesn't have a Primary Index ID, then can an outer join still be used to find out duplicates?

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  • NSArrayController that is sorted and unique (no duplicates) for use in a pop-up in a core-data app

    - by Douglas Weaver
    I have core data app with an entity OBSERVATION that has as one of its attributes DEALNAME. I want to reference through Interface Builder or by making custom modifications to an NSArrayController a list of unique sorted dealnames so that I can use them in a pop-up. I have attempted to use @distinctUnionOfSets (and @distinctUnionOfArrays) but am unable to locate the proper key sequence. I can sort the ArrayController by providing a sort descriptor, but do not know how to eliminate duplicates. Are the @distinct... keys the right methodology? It would seem to provide the easiest way to optimize the use of IB. Is there a predicate form for removing duplicates? Or do I need to use my custom controller to extract an NSSet of the specific dealnames, put them back in an array and sort it and reference the custom array from IB? Any help would be appreciated. I am astounded that other have not tried to create a sorted-unique pop-up in tableviews.

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