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  • Simple Select Statement on MySQL Database Hanging

    - by AlishahNovin
    I have a very simple sql select statement on a very large table, that is non-normalized. (Not my design at all, I'm just trying to optimize while simultaneously trying to convince the owners of a redesign) Basically, the statement is like this: SELECT FirstName, LastName, FullName, State FROM Activity Where (FirstName=@name OR LastName=@name OR FullName=@name) AND State=@state; Now, FirstName, LastName, FullName and State are all indexed as BTrees, but without prefix - the whole column is indexed. State column is a 2 letter state code. What I'm finding is this: When @name = 'John Smith', and @state = '%' the search is really fast and yields results immediately. When @name = 'John Smith', and @state = 'FL' the search takes 5 minutes (and usually this means the web service times out...) When I remove the FirstName and LastName comparisons, and only use the FullName and State, both cases above work very quickly. When I replace FirstName, LastName, FullName, and State searches, but use LIKE for each search, it works fast for @name='John Smith%' and @state='%', but slow for @name='John Smith%' and @state='FL' When I search against 'John Sm%' and @state='FL' the search finds results immediately When I search against 'John Smi%' and @state='FL' the search takes 5 minutes. Now, just to reiterate - the table is not normalized. The John Smith appears many many times, as do many other users, because there is no reference to some form of users/people table. I'm not sure how many times a single user may appear, but the table itself has 90 Million records. Again, not my design... What I'm wondering is - though there are many many problems with this design, what is causing this specific problem. My guess is that the index trees are just too large that it just takes a very long time traversing the them. (FirstName, LastName, FullName) Anyway, I appreciate anyone's help with this. Like I said, I'm working on convincing them of a redesign, but in the meantime, if I someone could help me figure out what the exact problem is, that'd be fantastic.

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  • Is it possible to use ContainsTable to get results for more than one column?

    - by LockeCJ
    Consider the following table: People FirstName nvarchar(50) LastName nvarchar(50) Let's assume for the moment that this table has a full-text index on it for both columns. Let's suppose that I wanted to find all of the people named "John Smith" in this table. The following query seems like a perfectly rational way to accomplish this: SELECT * from People p INNER JOIN CONTAINSTABLE(People,*,'"John*" AND "Smith*"') Unfortunately, this will return no results, assuming that there is no record in the People table that contains both "John" and "Smith" in either the FirstName or LastName columns. It will not match a record with "John" in the FirstName column, and "Smith" in the LastName column, or vice-versa. My question is this: How does one accomplish what I'm trying to do above? Please consider that the example above is simplified. The real table I'm working with has ten columns and the input I'm receiving is a single string which is split up based on standard word breakers (space, dash, etc.)

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  • Parsing complex string using regex

    - by wojtek_z
    My regex skills are not very good and recently a new data element has thrown my parser into a loop Take the following string "+USER=Bob Smith-GROUP=Admin+FUNCTION=Read/FUNCTION=Write" Previously I had the following for my regex : [+\\-/] Which would turn the result into USER=Bob Smith GROUP=Admin FUNCTION=Read FUNCTION=Write FUNCTION=Read But now I have values with dashes in them which is causing bad output New string looks like "+USER=Bob Smith-GROUP=Admin+FUNCTION=Read/FUNCTION=Write/FUNCTION=Read-Write" Which gives me the following result , and breaks the key = value structure. USER=Bob Smith GROUP=Admin FUNCTION=Read FUNCTION=Write FUNCTION=Read Write Can someone help me formulate a valid regex for handling this or point me to some key / value examples. Basically I need to be able to handle + - / signs in order to get combinations.

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  • Are there any well known algorithms to detect the presence of names?

    - by Rhubarb
    For example, given a string: "Bob went fishing with his friend Jim Smith." Bob and Jim Smith are both names, but bob and smith are both words. Weren't for them being uppercase, there would be less indication of this outside of our knowledge of the sentence. Without doing grammar analysis, are there any well known algorithms for detecting the presence of names, at least Western names?

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  • Need help joining tables...

    - by yuudachi
    I am a MySQL newbie, so sorry if this is a dumb question.. These are my tables. student table: SID (primary) student_name advisor (foreign key to faculty.facultyID) requested_advisor (foreign key to faculty.facultyID) faculty table: facultyID (primary key) advisor_name I want to query a table that shows everything in the student table, but I want advisor and requested_advisor to show up as names, not the ID numbers. so like it displays like this on the webpage: Student Name: Jane Smith SID: 860123456 Current Advisor: John Smith Requested advisor: James Smith not like this Student Name: Jane Smith SID: 860123456 Current Advisor: 1 Requested advisor: 2 SELECT student.student_name, SID, student_email, faculty.advisor_name FROM student INNER JOIN faculty ON student.advisor = faculty.facultyID; this comes out close, but I don't know how to get the requested_advisor to show up as a name.

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  • Setting variables in shell script by running commands

    - by rajya vardhan
    >cat /tmp/list1 john jack >cat /tmp/list2 smith taylor It is guaranteed that list1 and list2 will have equal number of lines. f(){ i=1 while read line do var1 = `sed -n '$ip' /tmp/list1` var2 = `sed -n '$ip' /tmp/list2` echo $i,$var1,$var2 i=`expr $i+1` echo $i,$var1,$var2 done < $INFILE } So output of f() should be: 1,john,smith 2,jack,taylor But getting 1,p,p 1+1,p,p If i replace following: var1 = `sed -n '$ip' /tmp/list1` var2 = `sed -n '$ip' /tmp/list2` with this: var1=`head -$i /tmp/vip_list|tail -1` var2=`head -$i /tmp/lb_list|tail -1` Then output: 1,john,smith 1,john,smith Not an expert of shell, so please excuse if sounds childish :)

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  • Creating one row of information in excel using a unique value

    - by user1426513
    This is my first post. I am currently working on a project at work which requires that I work with several different worksheets in order to create one mail master worksheet, as it were, in order to do a mail merge. The worksheet contains information regarding different purchases, and each purchaser is identified with their own ID number. Below is an example of what my spreadsheet looks like now (however I do have more columns): ID Salutation Address ID Name Donation ID Name Tickets 9 Mr. John Doe 123 12 Ms. Jane Smith 100.00 12 Ms.Jane Smith 300.00 12 Ms. Jane Smith 456 22 Mr. Mike Man 500.00 84 Ms. Jo Smith 300.00 What I would like to do is somehow sort my data so that everythign with the same unique identifier (ID) lines up on the same row. For example ID 12 Jane Smith - all the information for her will show up under her name matched by her ID number, and ID 22 will match up with 22 etc... When I merged all of my spreadsheets together, I sorted them all by ID number, however my problem is, not everyone who made a donation bought a ticket or some people just bought tickets and nothing us, so sorting doesn't work. Hopefully this makes sense. Thanks in advance.

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  • Programmatically add/delete users in Exchange

    - by Terry Gamble
    I've got the following set up: ASP.Net site that allows my internal employees to add in new hire information (no secure data, just stuff like name/address/phone) and when they submit this it goes into a database (SQL). Every few minutes a service runs that checks the database and if there are new entries it will add them into Exchange. The issue is I'm not happy with the way the service is doing things, (It's not putting address, etc in it). As I don't have the source code this I'm thinking of recreating it. My issue though is finding a starting point even. I know I'll have to create the scripts through code where the data is retrieved from SQL : Joe Smith 123 Main Street Nowhere, USA 19999 And put that into a powershell cmdlet (not sure exactly the syntax but I can get that figured out unless someone already has it) where the user is created in the Active Directory as a normal user and the mailbox is created simultaneously. From there I just need to fill out fields in Active Directory with the person's address, etc. Finally a deletion routine for when we terminate someone, however I'm sure that it will simply be a cmdlet that is easily shelled out to much like the initial one is, once I can figure out how to start that... Anyone have some good reference points or have already done it and can share?

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  • Run script after switching user account "to the same account"

    - by Peter Sivák
    In Ubuntu, when I click on Switch User Account... and then choose the same account to log in (for example if my name is John Smith, I click on switch user account and then log into the John Smith account again), how can I run a script after that? (I know, that I can run a script after "first" login by putting it in /etc/profile file, but this script is not executed again when I choose switch user account and then immediately log in back to the same account.)

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  • GDL Presents: Women Techmakers with JESS3

    GDL Presents: Women Techmakers with JESS3 Join Leslie, COO and Co-founder of JESS3, in conversation with Megan Smith and Betsy Masiello, as they discuss Leslie's experience growing a design business from two employees to a transnational operation. Hosts: Megan Smith - Vice President, Google [x] | Betsy Masiello - Policy Manager Guest: Leslie Bradshaw - President, COO and Co-founder, JESS3 From: GoogleDevelopers Views: 0 3 ratings Time: 01:00:00 More in Science & Technology

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  • Is It Possible To Recover A Partial LVM Logical Volume?

    - by Terry Wang
    Background It is an Ubuntu 12.04 VirtualBox VM with 5 virtual HDDs (VDI), NOTE this is just a test VM, so not well planned ahead: ubuntu.vdi for / (/dev/mapper/ubuntu-root AKA /dev/ubuntu/root) and /home (/dev/mapper/ubuntu-home) weblogic.vdi - /dev/sdb (mounted on /bea for weblogic and other stuff) btrfs1.vdi - /dev/sdc (part of btrfs -m raid1 -d raid1 configuration) btrfs2.vdi - /dev/sdd (part of btrfs -m raid1 -d raid1 configuration) more.vdi - /dev/sde (added this virtual HDD because / ran out of inodes and it wasn't easy to figure out what to delete so as to free up inodes, so I just added the new virtual HDD, created PV, added it to existing volume group ubuntu, grew the root logical volume to work around the inode issue -_-) What happened? Last Friday, before finishing up I wanted to free up some disk space on that box, for some reason I thought the more.vdi was useless and tried to detach it from the VM, I then clicked delete (should have clicked keep files damn!) by mistake when detaching. Unfortunately I didn't have backup for it. All too late. What I have tried Tried to undelete (use testdisk and photorec) the vdi files but it takes too long and recovered heaps of .vdi files that I didn't want (huge, filled the disk, damn!). I finally gave up. Fortunately most of data is on separate ext4 partition and btrfs volumes. Out of curiosity, I still tried to mount the logical volumes and see if it is possible to at least recover the /var and /etc I tried to use system rescue cd to boot and activate the volume groups, I got: Couldn't find device with uuid xxxx. Refusing activation of the partial LV root. Use --partial to override. 1 logical volume(s) in volume group "ubuntu" now active. I was able to mount home LV but not root LV. I am wondering if it is possible to access the root LV any more. Under the bonnet, data (on LV root - /) was striped to more.vdi (PV), I know it's almost impossible to to recover. But I am still curious about how system administrator/DevOps guys deal with this sort of situation;-) Thanks in advance.

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  • Random Monday Thoughs

    - by Terry Goldman
    On this Monday morning my thoughts center on why is it so hard to embrace governance, any form of governance for that matter, be it software development governance, SOA governance, data governance, IT governance, so on a so fourth?Most customers that I meet tend to think that they don't need don't need governance as all is good within the enterprise. The question I generally pose to colleges and customers, is you have to think of governance as an insurance policy. Take of instance, if you just bought a new car, perhaps your "dream" car, would you drive it on the open streets without having the car insured? Probably not.Governance is what insurance is to new cars, be it to SOA, IT transformations and software development. Governance is a insurance policy against risk of failure. Now once I put it in this context, ask yourself, does governance have value to your organization? Most people now get it. Once the seed of governance is planted at the executive level of an organization, it becomes a exercise in planting an that idea into key personnel within the organization. Then the justification for governance grows and grows across the enterprise.Thats my food for though in this Monday morning.FYI, stay tuned for an upcoming multi-part article on using Oracle Enterprise Repository to build a Enterprise Continuum as described in TOGAF v9.0.

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  • Wifi won't enter working net after hard reboot

    - by Terry Smith
    I rebooted the hard way after my system jammed again because FF eats all the ram. (that's a different problem) I've always gotten away with it, but not this time. The system came up ok BUT it absolutely refuses to log onto the local house wifi net. I know the net is ok as the Windows box I'm writing this on is on it right now. I deleted the connection and rentered the password but it will not go on. /var/lib/NetworkManager/NetworkManager.state says everything is turned on. I know this is my fault but I'd really like to get back on the net. The machine is a Toshiba Satellite. Any suggestions?

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  • gnome-shell failed to launch when dual monitor detected, nvidia card

    - by Terry Hu
    I installed a clean precise. I like gnome-shell so I installed it. It worked well with single monitor. But It does not work well when I go to office, plug my external monitor onto my laptop. I am using nvidia driver. Another colleague is using the same laptop, he can work well with dual monitors. His laptop is ATI graphic card. When I plug my extended monitor cable, I choose GNOME, but actually it goes to gnome 2 classic desktop environment, not GNOME 3. When I disconnect the extended monitor, restart X, I can login with GNOME3. Do I have to choose between GNOME3 and extended monitor? It's a hard choose.

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  • Eee PC brighness contol with 12.04 release

    - by Terry
    is there a solution to the low screen brightness issue with the Eee PC and release 12.04? When I use the brightness control, the screen goes through three adjustment cycles of dark to semi bright, but never gets to bright. As you index the control up, brightness increases, then suddenly cuts back to dark. use the brightness button to further increase the brightness and the same cycle happens. As though there are three distinct brightness events, each one setting back to low level. Under no circumstances other than initial boot up can you get to a bright screen. I just finished installing 12.04 on two Acer (Gateway netbooks) with no brightness issue. Just on the Eee PC

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  • Networking disabled

    - by Terry Dixon
    Both the Wifi and the ethernet connection to the internet are not working. All had been functioning fine until the Ubuntu suspended itself. On re-starting, the connection to internet failed to function and now I get the message "Network Disabled" whenever I re-boot. nm-tool tells me the state is "asleep". Stopping and starting the NetworkManager has no effect The machine is an Inspiron 9300 and work perfectly with Windows. How do I wake the networking up? Thanks

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  • How do I get brightness controls working properly on an Eee PC 1001P?

    - by Terry
    Is there a solution to the low screen brightness issue with the Eee PC 1001P and release 12.04? When I use the brightness control, the screen goes through three adjustment cycles of dark to semi bright, but never gets to bright. As you index the control up, brightness increases, then suddenly cuts back to dark. use the brightness button to further increase the brightness and the same cycle happens. As though there are three distinct brightness events, each one setting back to low level. Under no circumstances other than initial boot up can you get to a bright screen. I just finished installing 12.04 on two Acer (Gateway netbooks) with no brightness issue. Just on the Eee PC 1001P Eee PC model is 1001P

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  • How Do I Use jQuery/JavaScript To Open A Popup Window/Tab (ASPX Login Page) & Then Pass Values To Op

    - by Terry Robinson
    Hi All, We currently have two asp.net 2.x web applications and we need to perform the following functionality: From one application, we want to auto-login to the other web application automatically in a new tab; using the same browser instance/window. So the process is: Open New Window/Tab With Second System URL/Login Page Wait For Popup Window/Tab Page To Load (DOM Ready?) OnPopupDomReady { Get Usename, Password, PIN Controls (jQuery Selectors) and Populate In Code Then Click Login Button (All Programatically). } I am currently using JavaScript to Open the window as follows: <script type="text/javascript"> $(document).ready(function () { $('a[rel="external"]').click(function () { window.open($(this).attr('href')); return false; }); }); </script> I would like to use jQuery chaining functionality if possible to extent the method above so that I can attach a DOM Ready event to the popped up page and then use that event to call a method on the code behind of the popped up page to automatically login. Something similar to this (Note: The Following Code Sample Does Not Work, It Is Here To Try And Help Illustrate What We Are Trying To Achieve)... <script type="text/javascript"> $(document).ready(function () { $('a[rel="external"]').click(function () { window.open($(this).attr('href').ready(function () { // Use JavaScript (Pref. jQuery Partial Control Name Selectors) To Populate Username/Password TextBoxes & Click Login Button. }) }); }); </script> Our Architecture Is As Follows: We have the source for both products (ASP.NET WebSite[s]) and they are run under different app. pools in IIS. I hope this all makes sense, and if my plan is not going to work, please provide hints ;) Thanks All/Kind Regards, Terry Robinson.

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  • How to count the most recent value based on multiple criteria?

    - by Andrew
    I keep a log of phone calls like the following where the F column is LVM = Left Voice Mail, U = Unsuccessful, S = Successful. A1 1 B1 Smith C1 John D1 11/21/2012 E1 8:00 AM F1 LVM A2 2 B2 Smith C2 John D2 11/22/2012 E1 8:15 AM F2 U A3 3 B3 Harvey C3 Luke D3 11/22/2012 E1 8:30 AM F3 S A4 4 B4 Smith C4 John D4 11/22/2012 E1 9:00 AM F4 S A5 5 B5 Smith C5 John D5 11/23/2012 E5 8:00 AM F5 LVM This is a small sample. I actually have over 700 entries. In my line of work, it is important to know how many unsuccessful (LVM or U) calls I have made since the last Successful one (S). Since values in the F column can repeat, I need to take into consideration both the B and C column. Also, since I can make a successful call with a client and then be trying to contact them again, I need to be able to count from the last successful call. My G column is completely open which is where I would like to put a running total for each client (G5 would = 1 ideally while G4 = 0, G3 = 0, G2 = 2, G1 = 1 but I want these values calculated automatically so that I do not have scroll through 700 names).

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  • MS Word 2010: Hide citation title when 2 publications by same first author from different years are in one citation block

    - by srunni
    I'm trying to hide the display of the titles for two publications by the same first author from different years that are in the same citation block. By default, the title is shown in citations when there are two publications by the same author in a given document. The easiest way to get around this is to right click on the citation, click "Edit Citation", and then suppress the title. However, the issue with this is that if there are 2 citations in 1 citation block (i.e., "(Smith, J., et al. 2010, Smith, J., et al. 2011)" rather than "(Smith, J., et al. 2010) (Smith, J., et al. 2011)"), then using that suppress option only suppresses the title for the first citation (in this case, the 2010 publication). OTOH, if I try to initially insert the publications in separate citation blocks, I can suppress the title in both citations, but I can't cut and paste one into the other's citation block. I can click "Cut" and the citation that was just cut disappears, but the "Paste" option is not available when my cursor is in the second citation block. Any ideas? Thanks!

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  • To ref or not to ref

    - by nmarun
    So the question is what is the point of passing a reference type along with the ref keyword? I have an Employee class as below: 1: public class Employee 2: { 3: public string FirstName { get; set; } 4: public string LastName { get; set; } 5:  6: public override string ToString() 7: { 8: return string.Format("{0}-{1}", FirstName, LastName); 9: } 10: } In my calling class, I say: 1: class Program 2: { 3: static void Main() 4: { 5: Employee employee = new Employee 6: { 7: FirstName = "John", 8: LastName = "Doe" 9: }; 10: Console.WriteLine(employee); 11: CallSomeMethod(employee); 12: Console.WriteLine(employee); 13: } 14:  15: private static void CallSomeMethod(Employee employee) 16: { 17: employee.FirstName = "Smith"; 18: employee.LastName = "Doe"; 19: } 20: }   After having a look at the code, you’ll probably say, Well, an instance of a class gets passed as a reference, so any changes to the instance inside the CallSomeMethod, actually modifies the original object. Hence the output will be ‘John-Doe’ on the first call and ‘Smith-Doe’ on the second. And you’re right: So the question is what’s the use of passing this Employee parameter as a ref? 1: class Program 2: { 3: static void Main() 4: { 5: Employee employee = new Employee 6: { 7: FirstName = "John", 8: LastName = "Doe" 9: }; 10: Console.WriteLine(employee); 11: CallSomeMethod(ref employee); 12: Console.WriteLine(employee); 13: } 14:  15: private static void CallSomeMethod(ref Employee employee) 16: { 17: employee.FirstName = "Smith"; 18: employee.LastName = "Doe"; 19: } 20: } The output is still the same: Ok, so is there really a need to pass a reference type using the ref keyword? I’ll remove the ‘ref’ keyword and make one more change to the CallSomeMethod method. 1: class Program 2: { 3: static void Main() 4: { 5: Employee employee = new Employee 6: { 7: FirstName = "John", 8: LastName = "Doe" 9: }; 10: Console.WriteLine(employee); 11: CallSomeMethod(employee); 12: Console.WriteLine(employee); 13: } 14:  15: private static void CallSomeMethod(Employee employee) 16: { 17: employee = new Employee 18: { 19: FirstName = "Smith", 20: LastName = "John" 21: }; 22: } 23: } In line 17 you’ll see I’ve ‘new’d up the incoming Employee parameter and then set its properties to new values. The output tells me that the original instance of the Employee class does not change. Huh? But an instance of a class gets passed by reference, so why did the values not change on the original instance or how do I keep the two instances in-sync all the times? Aah, now here’s the answer. In order to keep the objects in sync, you pass them using the ‘ref’ keyword. 1: class Program 2: { 3: static void Main() 4: { 5: Employee employee = new Employee 6: { 7: FirstName = "John", 8: LastName = "Doe" 9: }; 10: Console.WriteLine(employee); 11: CallSomeMethod(ref employee); 12: Console.WriteLine(employee); 13: } 14:  15: private static void CallSomeMethod(ref Employee employee) 16: { 17: employee = new Employee 18: { 19: FirstName = "Smith", 20: LastName = "John" 21: }; 22: } 23: } Viola! Now, to prove it beyond doubt, I said, let me try with another reference type: string. 1: class Program 2: { 3: static void Main() 4: { 5: string name = "abc"; 6: Console.WriteLine(name); 7: CallSomeMethod(ref name); 8: Console.WriteLine(name); 9: } 10:  11: private static void CallSomeMethod(ref string name) 12: { 13: name = "def"; 14: } 15: } The output was as expected, first ‘abc’ and then ‘def’ - proves the 'ref' keyword works here as well. Now, what if I remove the ‘ref’ keyword? The output should still be the same as the above right, since string is a reference type? 1: class Program 2: { 3: static void Main() 4: { 5: string name = "abc"; 6: Console.WriteLine(name); 7: CallSomeMethod(name); 8: Console.WriteLine(name); 9: } 10:  11: private static void CallSomeMethod(string name) 12: { 13: name = "def"; 14: } 15: } Wrong, the output shows ‘abc’ printed twice. Wait a minute… now how could this be? This is because string is an immutable type. This means that any time you modify an instance of string, new memory address is allocated to the instance. The effect is similar to ‘new’ing up the Employee instance inside the CallSomeMethod in the absence of the ‘ref’ keyword. Verdict: ref key came to the rescue and saved the planet… again!

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  • The Oracle Retail Week Awards - most exciting awards yet?

    - by sarah.taylor(at)oracle.com
    Last night's annual Oracle Retail Week Awards saw the UK's top retailers come together to celebrate the very best of our industry over the last year.  The Grosvenor House Hotel on Park Lane in London was the setting for an exciting ceremony which this year marked several significant milestones in British - and global - retail.  Check out our videos about the event at our Oracle Retail YouTube channel, and see if you were snapped by our photographer on our Oracle Retail Facebook page. There were some extremely hot contests for many of this year's awards - and all very deserving winners.  The entries have demonstrated beyond doubt that retailers have striven to push their standards up yet again in all areas over the past year.  The judging panel includes some of the most prestigious names in the retail industry - to impress the panel enough to win an award is a substantial achievement.  This year the panel included the likes of Andy Clarke - Chief Executive of ASDA Group; Mark Newton Jones - CEO of Shop Direct Group; Richard Pennycook - the finance director at Morrisons; Rob Templeman - Chief Executive of Debenhams; and Stephen Sunnucks - the president of Gap Europe.  These are retail veterans  who have each helped to shape the British High Street over the last decade.  It was great to chat with many of them in the Oracle VIP area last night.  For me, last night's highlight was honouring both Sir Stuart Rose and Sir Terry Leahy for their contributions to the retail industry.  Both have set the standards in retailing over the last twenty years and taken their respective businesses from strength to strength, demonstrating that there is always a need for innovation even in larger businesses, and that a business has to adapt quickly to new technology in order to stay competitive.  Sir Terry Leahy's retirement this year marks the end of an era of global expansion for the Tesco group and a milestone in the progression of British retail.  Sir Terry has helped steer Tesco through nearly 20 years of change, with 14 years as Chief Executive.  During this time he led the drive for international expansion and an aggressive campaign to increase market share.  He has led the way for High Street retailers in adapting to the rise of internet retailing and nurtured a very successful home delivery service.  More recently he has pioneered the notion of cross-channel retailing with the introduction of Tesco apps for the iPhone and Android mobile phones allowing customers to scan barcodes of items to add to a shopping list which they can then either refer to in store or order for delivery.  John Lewis Partnership was a very deserving winner of The Oracle Retailer of the Year award for their overall dedication to excellent retailing practices.  The business was also named the American Express Marketing/Advertising Campaign of the Year award for their memorable 'Never Knowingly Undersold' advert series, which included a very successful viral video and radio campaign with Fyfe Dangerfield's cover of Billy Joel's 'She's Always a Woman' used for the adverts.  Store Design of the Year was another exciting category with Topshop taking the accolade for its flagship Oxford Street store in London, which combines boutique concession-style stalls with high fashion displays and exclusive collections from leading designers.  The store even has its own hairdressers and food hall, making it a truly all-inclusive fashion retail experience and a global landmark for any self-respecting international fashion shopper. Over the next few weeks we'll be exploring some of the winning entries in more detail here on the blog, so keep an eye out for some unique insights into how the winning retailers have made such remarkable achievements. 

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  • It's Not TV- It's OTN: Top 10 Videos on the OTN YouTube Channel

    - by Bob Rhubart
    It's been a while since we checked in on what people are watching on the Oracle Technology Network YouTube Channel. Here are the Top 10 video for the last 30 days. Tom Kyte: Keeping Up with the Latest in Database Technology Tom Kyte expands on his keynote presentation at the Great Lakes Oracle Conference with tips for developers, DBAs and others who want to make sure they are prepared to work with the latest database technologies. That Jeff Smith: Oracle SQL Developer Oracle SQL Developer product manager Jeff Smith (yeah, that Jeff Smith) talks about his presentations at the Great Lakes Oracle Conference and shares his reaction to keynote speaker C.J. Date's claim that "SQL dropped the ball." Gwen Shapira: Hadoop and Oracle Database Oracle ACE Director Gwen Shapira @gwenshap talks about the fit between Hadoop and Oracle Database and dives into the details of why Oracle Loader for Hadoop is 5x faster. Kai Yu: Virtualization and Cloud Oracle ACE Director Kai Yu talks about the questions he is most frequently asked when he does presentations on cloud computing and virtualization. Mark Sewtz: APEX 4.2 Mobile App Development Application Express developer Marc Sewtz demos the new features he built into APEX4.2 to support Mobile App Development. Jeremy Schneider: RAC Attack Oracle ACE Jeremy Schneider @jer_s describes what you can expect when you come to a RAC (Real Application Cluster) Attack. Frits Hoogland: Exadata Under the Hood Oracle ACE Director Frits Hoogland (@fritshoogland) talks about the secret sauce under Exadata's hood. David Peake: APEX 4.2 New Features David Peake, PM for Oracle Application Express, gives a quick overview of some of the new APEX features. Greg Marsden: Hugepages = Huge Performance on Linux Greg Marsden of Oracle's Linux Kernel Engineering Team talks about some common customer performance questions and making the most of Oracle Linux 6 and Transparent HugePages. John Hurley: NEOOUG and GLOC 2013 Northeast Ohio Oracle User Group president John Hurley talks about the background and success of the 2013 Great Lakes Oracle Conference.

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  • Aggregating Excel cell contents that match a label [migrated]

    - by Josh
    I'm sure this isn't a terribly difficult thing, but it's not the type of question that easily lends itself to internet searches. I've been assigned a project for work involving a complex spreadsheet. I've done the usual =SUM and other basic Excel formulas, and I've got enough coding background that I'm able to at least fudge my way through VBA, but I'm not certain how to proceed with one part of the task. Simple version: On Sheet 1 I have a list of people (one on each row, person's name in column A), on sheet 2 I have a list of groups (one on each row, group name in column A). Each name in Sheet 1 has its own row, and I have a "Data Validation" dropdown menu where you choose the group each person belongs to. That dropdown is sourced from Sheet 2, where each group has a row. So essentially the data validation source for Sheet 1's "Group" column is just "=Sheet2!$a1:a100" or whatever. The problem is this: I want each group row in Sheet 2 to have a formula which results in a list of all the users which have been assigned to that group on Sheet 1. What I mean is something the equivalent of "select * from PeopleTab where GROUP = ThisGroup". The resulting cell would just stick the names together like "Bob Smith, Joe Jones, Sally Sanderson" I've been Googling for hours but I can't think of a way to phrase my search query to get the results I want. Here's an example of desired result (Dash-delimited. Can't find a way to make it look nice, table tags don't seem to work here): (Sheet 1) Bob Smith - Group 1 (selected from dropdown) Joe Jones - Group 2 (selected from dropdown) Sally Sanderson - Group 1 (selected from dropdown) (Sheet 2) Group 1 - Bob Smith, Sally Sanderson (result of formula) Group 2 - Joe Jones (result of formula) What formula (or even what function) do I use on that second column of sheet 2 to make a flat list out of the members of that group?

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  • Junit test bluej [closed]

    - by user1721929
    Can someone make a junit test of this? public class PersonName { int NumberNames(String wholename) { // store the name passed in to the method String testname=wholename; // initialize number of names found int numnames=0; // on each iteration remove one name while(testname.length()>numnames) { // take the "white space" from the beginning and end testname = testname.trim(); // determine the position of the first blank // .. end of the first word int posBlank= testname.indexOf(' '); // cut off word /** * it continues to the stop sign because that is where you commanded it to end */ testname=testname.substring(posBlank+1,testname.length()); // System.out.println(numnames); // System.out.println(testname); numnames++; System.out.println(testname); } return numnames; } public static void main(String args[]) { PersonName One= new PersonName(); System.out.println(One.NumberNames("Bobby")); System.out.println(One.NumberNames("Bobby Smith")); System.out.println(One.NumberNames("Bobby L. Smith")); System.out.println(One.NumberNames(" Bobby Paul Smith Jr. ")); } }

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