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• De-share third level .name domain

  - by Enzo

  Sometime ago I registered a third level .name domain of the type john.doe.name (this is just an example-my domain is not actually john.doe.name). I just realised that I could have registered the entire second level domain doe.name, which would grant me control of the third level one anyway. Since I already registered the third level, doe.name is now "shared". I have 2 questions: 1) How do I check if I am the only one using the shared second level domain? (normal whois lookup doesn't give any result) 2) Can I "de-share" the domain and buy the entire second level domain? Cheers!

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• "ldap_add: Naming violation (64)" error when configuring OpenLDAP

  - by user3215

  I am following the Ubuntu server guide to configure OpenLDAP on an Ubuntu 10.04 server, but can not get it to work. When I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file: # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: [email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Can anyone help me?

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• How to Configure OpenLDAP on Ubuntu 10.04 Server

  - by user3215

  I am following the Ubuntu server guide to configure OpenLDAP on an Ubuntu 10.04 server, but can not get it to work. When I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file: # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: [email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Can anyone help me?

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• How to configure ldap on ubuntu 10.04 server

  - by user3215

  I am following the link to configure ldap on ubuntu 10.04 server but could not. when I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: [email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Anybody could help me?

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• LINQ-To-SQL and Many-To-Many Relationship Deletions

  - by Jake

  I have a many-to-many relationship between two tables, let's say Friends and Foods. If a friend likes a food I stick a row into the FriendsFoods table, like this: ID Friend Food 1 'Tom' 'Pizza' FriendsFoods has a Primary Key 'ID', and two non-null foreign keys 'Friend' and 'Food' to the 'Friends' and 'Foods' tables, respectively. Now suppose I have a Friend tom .NET object corresponding to 'Tom', and Tom no longer likes pizza (what is wrong with him?) FriendsFoods ff = tom.FriendsFoods.Where(x => x.Food.Name == 'Pizza').Single(); tom.FriendsFoods.Remove(ff); pizza.FriendsFoods.Remove(ff); If I try to SubmitChanges() on the DataContext, I get an exception because it attempts to insert a null into the Friend and Food columns in the FriendsFoods table. I'm sure I can put together some kind of convoluted logic to track changes to the FriendsFoods table, intercept SubmitChanges() calls, etc to try and get this to work the way I want, but is there a nice, clean way to remove a Many-To-Many relationship with LINQ-To-SQL?

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• Finding duplicate values in a SQL table

  - by Alex

  It's easy to find duplicates with one field SELECT name, COUNT(email) FROM users GROUP BY email HAVING ( COUNT(email) > 1 ) So if we have a table ID NAME EMAIL 1 John [email protected] 2 Sam [email protected] 3 Tom [email protected] 4 Bob [email protected] 5 Tom [email protected] This query will give us John, Sam, Tom, Tom because they all have the same e-mails. But what I want, is to get duplicates with the same e-mails and names. I want to get Tom, Tom. I made a mistake, and allowed to insert duplicate name and e-mail values. Now I need to remove/change the duplicates. But I need to find them first.

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• Finding duplicate values in a SQL table - ADVANCED

  - by Alex

  It's easy to find duplicates with one field SELECT name, COUNT(email) FROM users GROUP BY email HAVING ( COUNT(email) > 1 ) So if we have a table ID NAME EMAIL 1 John [email protected] 2 Sam [email protected] 3 Tom [email protected] 4 Bob [email protected] 5 Tom [email protected] This query will give us John, Sam, Tom, Tom because they all have the same e-mails. But what I want, is to get duplicates with the same e-mails and names. I want to get Tom, Tom. I made a mistake, and allowed to insert duplicate name and e-mail values. Now I need to remove/change the duplicates. But I need to find them first.

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• Directory error when trying to create a new user

  - by Tom Brossman

  I added a second user 'shirley' in Settings - User Accounts, and set a password. The account type is Standard. In 11.04, this worked and I logged in and had a functioning desktop for this user. How is this done in 11.10? When I try to log in as this user I have this error: Nautilus could not create the required folder "/home/shirley/.config/nautilus". Before running Nautilus, please create the following folder, or set permissions such that Nautilus can create it. The only option then is to click OK, this dumps me out to full-screen Nautilus, like this: There is no launcher or visible way to start any programs. Print screen doesn't take a screengrab. The desktop is similar to this question but I get no terminal when I press CTRL+ALT+T. I have to press CTRL+ALT+F2 and restart from the terminal to get out of this. This answer is to install gnome-system-tools. Shouldn't I be able to add a second user with the default install? EDIT: I tried the deluser+adduser suggestion, there was no change after trying it. Here is what I got: tom@desktop:~$ sudo deluser shirley [sudo] password for tom: Removing user `shirley' ... Warning: group `shirley' has no more members. Done tom@desktop:~$ sudo adduser shirley Adding user `shirley' ... Adding new group `shirley' (1001) Adding new user shirley' (1001) with groupshirley' The home directory '/home/shirley' already exists. Not copying from `/etc/skel'. Enter new UNIX password: Retype new UNIX password: passwd: password updated successfully Changing user information for shirley Enter the new value, or press ENTER for the default Full Name []: Room Number []: Work Phone []: Home Phone []: Other []: Is the information correct? [Y/n] y What has gone so wrong with simply adding a second user? Am I the only one having this problem? I'd reinstall if that fixed things, but this is a fresh install only a few days old.

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• Uploading file from file object with PyCurl

  - by Tom

  I'm attempting to upload a file like this: import pycurl c = pycurl.Curl() values = [ ("name", "tom"), ("image", (pycurl.FORM_FILE, "tom.png")) ] c.setopt(c.URL, "http://upload.com/submit") c.setopt(c.HTTPPOST, values) c.perform() c.close() This works fine. However, this only works if the file is local. If I was to fetch the image such that: import urllib2 resp = urllib2.urlopen("http://upload.com/people/tom.png") How would I pass resp.fp as a file object instead of writing it to a file and passing the filename? Is this possible?

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• Python file-io code listing current folder path instead of the specified

  - by Tom Brito

  I have the code: import os import sys fileList = os.listdir(sys.argv[1]) for file in fileList: if os.path.isfile(file): print "File >> " + os.path.abspath(file) else: print "Dir >> " + os.path.abspath(file) Located in my music folder ("/home/tom/Music") When I call it with: python test.py "/tmp" I expected it to list my "/tmp" files and folders with the full path. But it printed lines like: Dir >> /home/tom/Music/seahorse-gw2jNn Dir >> /home/tom/Music/FlashXX9kV847 Dir >> /home/tom/Music/pulse-DcIEoxW5h2gz This is, the correct file names, but the wrong path (and this files are not either in my Music folder).. What's wrong with this code?

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• What could cause these "failed to authenticate" logs other than failed login attempts (OSX)?

  - by Tom

  I've found this in the Console logs: 10/03/10 3:53:58 PM SecurityAgent[156] User info context values set for tom 10/03/10 3:53:58 PM authorizationhost[154] Failed to authenticate user (tDirStatus: -14090). 10/03/10 3:54:00 PM SecurityAgent[156] User info context values set for tom 10/03/10 3:54:00 PM authorizationhost[154] Failed to authenticate user (tDirStatus: -14090). 10/03/10 3:54:03 PM SecurityAgent[156] User info context values set for tom 10/03/10 3:54:03 PM authorizationhost[154] Failed to authenticate user (tDirStatus: -14090). There are about 11 of these "failed to authenticate" messages logged in quick succession. It looks to me like someone is sitting there trying to guess the password. However, when I tried to replicate this I get the same log messages except that this extra message appears after five attempts: 13/03/10 1:18:48 PM DirectoryService[11] Failed Authentication return is being delayed due to over five recent auth failures for username: tom. I don't want to accuse someone of trying to break into an account without being sure that they were actually trying to break in. My question is this: is it almost definitely someone guessing a password, or could the 11 "failed to authenticate" messages be caused by something else?

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• What's the format of Real World Performance Day?

  - by william.hardie

  A question that has cropped a lot of late is "what's the format of Real World Performance Day?" Not an unreasonable question you might think. Sure enough, a quick check of the Independent Oracle User Group's website tells us a bit about the Real World Performance Day event, but no formal agenda? This was one of the questions I posed to Tom Kyte (one of the main presenters) in our recent podcast. Tom tells us that this isn't your traditional event where one speaker follows another with loads of slides. In fact, the Real World Performance Day features Tom and fellow Oracle performance experts - Andrew Holdsworth and Graham Wood - continuously on stage throughout the day. All three will be discussing database performance challenges and solutions from development, architectural design and management perspectives. There's going to be multi-terabyte demos on show, less of the traditional slides, and more interactive debate and discussion going on. Tune-in and hear what else Tom has to say about this fairly unique event!

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• What could cause these "failed to authenticate" logs other than failed login attempts (OSX)?

  - by Tom

  I've found this in the Console logs: 10/03/10 3:53:58 PM SecurityAgent[156] User info context values set for tom 10/03/10 3:53:58 PM authorizationhost[154] Failed to authenticate user (tDirStatus: -14090). 10/03/10 3:54:00 PM SecurityAgent[156] User info context values set for tom 10/03/10 3:54:00 PM authorizationhost[154] Failed to authenticate user (tDirStatus: -14090). 10/03/10 3:54:03 PM SecurityAgent[156] User info context values set for tom 10/03/10 3:54:03 PM authorizationhost[154] Failed to authenticate user (tDirStatus: -14090). There are about 11 of these "failed to authenticate" messages logged in quick succession. It looks to me like someone is sitting there trying to guess the password. However, when I tried to replicate this I get the same log messages except that this extra message appears after five attempts: 13/03/10 1:18:48 PM DirectoryService[11] Failed Authentication return is being delayed due to over five recent auth failures for username: tom. I don't want to accuse someone of trying to break into an account without being sure that they were actually trying to break in. My question is this: is it almost definitely someone guessing a password, or could the 11 "failed to authenticate" messages be caused by something else? EDIT: The actual user wasn't logged in, or using a computer at the time of the log in attempts.

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• Is there an implementation of Tom Kyte's STRAGG function supporting SQL Server?

  - by s_rajasekar

  STRAGG function implemention returns a result as a single column value. Implementation for Oracle seems pretty generic and can be consumed for different tables (and relationships). Could similar behavior be achieved for SQL Server. A search in the web, appears to return only hard coded implementations and not a generic one. Do we have any known solution for Sql server?

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• Using SQL to join spreadsheets in excel

  - by toms

  Based on the explenation here: How do I join two worksheets in Excel as I would in SQL? I tried to join to excel sheets from different files into the same sheet. However, I keep getting this error message when I try to refresh the table: [MICROSOFT][OBDC Excel Driver] Too few parameters. Expected 5. The SQL queries i've put in so far were: SELECT `Sheet1$`.ID, `Sheet1$`.Name, `Sheet1$`.`L Name` FROM `C:\Users\Tom\Book1.xlsx`.`Sheet1$` a LEFT JOIN `C:\Users\Tom\Book2.xlsx`.`Sheet1$` b ON a.col2= b.col2 and SELECT `Sheet1$`.ID, `Sheet1$`.Name, `Sheet1$`.`L Name` FROM `C:\Users\Tom\Book1.xlsx`.`Sheet1$` a LEFT JOIN `C:\Users\Tom\Book2.xlsx`.`Sheet1$` b ON a.`ID`= b.`ID` and SELECT * FROM `C:\Users\Tom\Book1.xlsx`.`Sheet1$` a LEFT JOIN `C:\Users\Tom\Book2.xlsx`.`Sheet1$` b ON a.`ID`= b.`ID` and a few combinations and alterations. I can't seem to find the solution. I've learned that it definitely doesn't like the SELECT *. But I can't fix it. Can anyone suggest any solution?

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• Login without running bash_profile or bashrc

  - by Tom Ritter

  So let's say one typoed something in their .bashrc that prevents him (or her) from logging in via ssh (i.e. the ssh login exits because of the error in the file). Is there any way that person could login without executing it (or .bashrc since the one runs the other), or otherwise delete/rename/invalidate the file? Suppose you don't have physical access to the machine, and this is the only user account with the ability to ssh in. For Reference: .bash_profile includes .bashrc: [[ -f ~/.bashrc ]] && . ~/.bashrc Edit: Things I have tried: ssh user@host "rm ~/.bashrc" scp nothing user@host:/RAID/home/tom/.bashrc ssh user@host "/bin/bash --norc" All give the error: /RAID/home/tom/.bashrc: line 16: /usr/local/bin/file: No such file or directory /RAID/home/tom/.bashrc: line 16: exec: /usr/local/bin/file: cannot execute: No such file or directory

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• Can't change current working directory to external drive in Windows

  - by Tom

  I'm trying to run a program located on an external USB disk using the Windows command prompt. I'm running Windows 7 64-bit (running in VMWare Workstation 8.0.) Here's what happens: I plug in the USB disk and it appears as drive letter 'E' in My Computer. I launch cmd from the start menu. I notice the prompt displays C:\Users\Tom> I type cd E:\ I notice the prompt displays C:\Users\Tom> (cd also yields C:\Users\Tom>) I can explore the drive using explorer.exe just fine, and it is connected according to VMWare Workstation. What am I doing wrong?

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• Difference between "machine hardware" and "hardware platform"

  - by Adil

  My Linux machine reports "uname -a" outputs as below:- [root@tom i386]# uname -a Linux tom 2.6.9-89.ELsmp #1 SMP Mon Apr 20 10:34:33 EDT 2009 i686 i686 i386 GNU/Linux [root@tom i386]# As per man page of uname, the entries "i686 i686 i386" denotes:- machine hardware name (i686) processor type (i686) hardware platform (i386) Additional info: [root@tom i386]# cat /proc/cpuinfo <snip> vendor_id : GenuineIntel cpu family : 6 model : 15 model name : Intel(R) Xeon(R) CPU 5148 @ 2.33GHz stepping : 6 cpu MHz : 2328.038 cache size : 4096 KB </snip>

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• Concatenate Gridview Data

  - by zahid mahmood

  I have a gridview with following Data CustomerName item qty tom sugar 1 kg Peter Rice 2 Kg Jhone Sugar .5 kg tom Rice 5 Kg Peter Tea .5 Kg tom Tea 1 kg now I want to display data with the following format: tom sugar 1kg, Rice 5 kg, Tea 1 kg Peter Rice 1kg, Tea .5 kg Jhone Sugar .5kg how to achieve this

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• Excel VBA Text To Column

  - by Pat

  This is what I currently have: H101 John Doe Jane Doe Jack Doe H102 John Smith Jane Smith Katie Smith Jack Smith And here is what I want: H101 John Doe H101 Jane Doe H101 Jack Doe H102 John Smith H102 Jane Smith H102 Katie Smith H102 Jack Smith Obviously I want to do this on a bigger scale. The number of columns is between 1 & 6, so I cant limit it that way. I was able to get a script that allows me to put each individual on one row. However, I am having a hard time getting the first column to copy over to each row. Sub ToOneColumn() Dim i As Long, k As Long, j As Integer Application.ScreenUpdating = False Columns(2).Insert i = 0 k = 1 While Not IsEmpty(Cells(k, 3)) j = 3 While Not IsEmpty(Cells(k, j)) i = i + 1 Cells(i, 1) = Cells(k, 1) //CODE IN QUESTION Cells(i, 2) = Cells(k, j) Cells(k, j).Clear j = j + 1 Wend k = k + 1 Wend Application.ScreenUpdating = True End Sub Like I said, it was working fine to get everyone each on their own row, but can't figure out how to get that first column. It seems like it should be so simple, but it's bugging me. Any help is greatly appreciated.

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• Security Risks of Unsigned ClickOnce Manifests

  - by Tom Tom

  Using signed manifests in ClickOnce deployments, it is not possible to modify files after the deployment package has been published - installation will fail as hash information in the manifest won't match up with the modified files. I recently stumbled upon a situation where this was problematic - customers need to be able to set things like connection strings in app.config before deploying the software to their users. I got round the problem by un-checking the option to "Sign the ClickOnce manifests" in VS2010 and explicitly excluding the app.config file from the list of files to have hashes generated during the publish process. From a related page on MSDN "Unsigned manifests can simplify development and testing of your application. However, unsigned manifests introduce substantial security risks in a production environment. Only consider using unsigned manifests if your ClickOnce application runs on computers within an intranet that is completely isolated from the internet or other sources of malicious code." In my situation, this isn't an immediate problem - the deployment won't be internet-facing. However, I'm curious to learn what the "substantial security risks" of what I've done would be if it was internet-facing (or if things changed and it needed to be in the future). Thanks in advance!

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• Tender vs. Requirements vs. Solution Design

  - by Tom Tom

  Conventionally, which of the above documents is deemed to hold the most weight when it comes to system acceptance? I recently had a conversation along these lines: It was argued that the initial requirements / tender documentation should be used to determine system acceptance. It was said that the solution design only serves to describe the way in which the system will solve the problem, not the problem it will solve. Furthermore, it was argued that if requirements are missed during solution design, the requirements should be referenced during system acceptance and that if any requirements were missed then the original tender should be referenced. Conversely, I suggested that - while requirements may be based on the original tender - they supersede it once agreed with the stakeholders. Furthermore, during solution design, analysis is performed to address and refine these initial requirements, translating them into a system capable of meeting the actual requirements. Once signed off by the relevant users, this solution design should absolutely represent the requirements (by virtue of the fact that it's designed upon them) but actually supersedes them as the basis for system acceptance. Is one of the above arguments more valid than the other?

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• Multiple contacts with shared information

  - by Keith Thompson

  Background: I currently have several hundred contacts, synchronized between a Microsoft Exchange server and several mobile devices. I also save exported copies of the contacts in .vcf format. Is there a good way (application, file format, whatever) to maintain contacts with shared information? A very common scenario is that I have contacts for two or more people who live in the same house, for example: John Doe 123 Main Street, Anytown USA Home: 555-555-1111 Work: 555-555-2222 Mobile: 555-555-3333 E-mail: [email protected] Jane Doe 123 Main Street, Anytown USA Home: 555-555-1111 Work: 555-555-4444 Mobile: 555-555-5555 E-mail: [email protected] As you can see, both contacts have the same home address and phone number, but distinct names and work and mobile phone numbers. (Other information might also be either shared or distinct.) The applications and file formats I'm familiar with don't seem to have a good way to deal with this. If I use a single "John & Jane Doe" contact for both, it's difficult to distinguish the distinct information (if I want to call Jane's mobile phone rather than John's). If I use a separate contact for each, I have to remember to update both of them (or all of them for N 2) when they move or change their home phone number. An ideal solution would let me create a record containing information for their household, and have each of their contact records contain a reference to the household record, so that when I view John's contact record I see both shared and distinct information. Is there anything out there that has good support this kind of thing? (I would think there would be, since it's a very common scenario.) (I suppose I could roll my own system that generates merged .vcf files from some extended format, but that wouldn't play well with synchronizing across multiple devices.)

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• How to add LDAP user to existing local group in RHEL?

  - by Highway of Life

  I'm attempting to add some of our LDAP users to a locally defined group on our RHEL server, however I get an error stating that the LDAP user is not found in /etc/passwd. What would be the best way to allow LDAP users to be added to local groups? My feeling is that this must be done manually. I could edit: /etc/group and add the LDAP group to the list. Would that be ideal? [server]# id apache uid=409(apache) gid=409(apache) groups=409(apache) context=user_u:system_r:unconfined_t:s0 [server]# id john.doe uid=11389(john.doe) gid=6097(ABC_Corporate_US) groups=6097(ABC_Corporate_US) context=user_u:system_r:unconfined_t:s0 [server]# /usr/sbin/usermod -a -G apache john.doe usermod: john.doe not found in /etc/passwd OS: RHEL (Red Hat Enterprise Linux Server release 5.3 (Tikanga)) Note: Updating the OS on this machine is not an option.

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• Archiving mails with postfix: how to filter mails?

  - by Tronic

  i wanto to implement the following scenario: we use a postfix mailserver. to archive all old and new mails, i want to setup a second postfix on our fileserver and create a single mailbox "archive". then every mail gets forwarded as bcc to this mailbox automatically. now, i want to create different folders in a maildir structure and let the server move each mail to the right subfolder of the mailbox based on its sender or receiver. e.g. when we get a mail to one of our employees named "John Doe" at [email protected], the mail should be moved to "Inbox/John Doe Incoming". the same applies when john doe sends a mail, folder would be "Inbox/John Doe Outgoing". how can i implement this filter behaviour. i heard of Procmail and Maildrop. Which of the two would you prefer? Which is more easy to configure? Any out-of-box solutions here? thanks in advance!

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